Solve for x in the diagram below.
120°
3x
0
2=

Solve For X In The Diagram Below.1203x02=

Answers

Answer 1

Answer:

x=40

Step-by-step explanation:

The 2 angles are opposite each other. Therefore, they are vertical angles. This means the 2 angles are equal. So, we can set them equal to each other.

120=3x

We want to find out what n is. In order to do this, we have to get n by itself. Perform the opposite of what is being done to the equation. Keep in mind, everything done to one side, has to be done to the other.

x is being multiplied by 3. The opposite of multiplication is division. Divide both sides by 3.

120/3=3x/3

120/3=x

40=x

x is equal to 40.

Answer 2

Answer:

40

Step-by-step explanation:

i had this a while ago


Related Questions

(6x^2+5x-3)+(x^2-9) find the sum please

Answers

Answer:

7x^2+5x-12

Step-by-step explanation:

(6x^2+5x-3)+(x^2-9)

Combine like terms

(6x^2+ x^2+5x-3-9)

7x^2+5x-12

I need help please!! Identify the solution for the system of equations graphed here.

A. (1,1)

B. (-1,1)

C. (1,-1)

D. (-1,-1)

Answers

Answer:

C. (1,-1)

Step-by-step explanation:

Lines are intersecting each other at point (1, - 1).

Hence, the system of equations graphed here would be (1, - 1)

If you expand and simplify. -(y+2)(y-8)

Answers

Answer:

[tex]-y^2+6y+16[/tex]

Step-by-step explanation:

[tex]-(y+2)(y-8)[/tex]

[tex]-1(y+2) \times (y-8)[/tex]

[tex](-y-2)\times (y-8)[/tex]

[tex]-y(y-8)-2(y-8)[/tex]

[tex]-y^2+8y-2y+16[/tex]

[tex]-y^2+6y+16[/tex]

find the initial value of the function x + 3y = 18

Answers

x+3y=18
x+3y-18=18-18
x+3y-18=0
x+3y-18=0 ( << that’s your answer) hope it helps

If a polynomial function f(x) has roots 0, 4, and 3+ sqrt 11, what must also be a root of f(x)?

a. 3+i sqrt 11
b. -3+i sqrt 11
c. 3- sqrt 11
d. -3- sqrt 11

Answers

Answer:

The answer is C 3- sqrt 11

Step-by-step explanation:

Solve the inequality.
2(4+2x)>5x+5
O x5-2
O X2-2
x33
O X23

Answers

Step-by-step explanation:

8 + 4x > 5x + 5

8 - 5 > 5x - 4x

3 > x

The solution to the system of equation is x < 3

Inequality expression

Given the inequality expression 2(4+2x)>5x+5

Expand the inequality

2(4+2x)>5x+5

8 + 4x > 5x + 5

Collect the like terms

4x - 5x > 5 -8

-x > -3

x < 3

Hence the solution to the system of equation is x < 3

Learn more on inequality here: https://brainly.com/question/24372553

Find the slope of the line that passes through (5, 9) and (2, 2). will mark brain

Simplify your answer and write it as a proper fraction, improper fraction, or integer.

Answers

The right answer is 7/3

please see the attached picture for full solution

hope it helps..

Good luck on your assignment

Answer:

[tex]slope = \frac{7}{3} [/tex]

Step-by-step explanation:

[tex](5 \: \: , \: \: 9) = > (x1 \: \: \:, \: y1) \\ (2 \: \: , \: \: 2) = > (x2 \: \: \:, \: \: y2)[/tex]

[tex] slope \\ = \frac{y1 - y2}{x1 - x2} \\ = \frac{9 - 2}{5 - 2} \\ = \frac{7}{3} [/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

A weather station reports that there is a 40% chance of rain today. What is the probability that it will not rain today?

Answers

Answer:

Since the full percentage of something is 100% thats because 1*100 = 100.

So since it has 40% chance of rain what would 100-40 be? Well it would be 60. So the probability that it will not rain is

60%

None because it will not

[tex]R = \sqrt{ \frac{ax - P}{Q + bx} } [/tex]
solve for x. Please can someone help me ASAP. I need to hand it on today.​

Answers

Step-by-step explanation:

[tex]r = \sqrt{ \frac{ax - p}{q + bx} } \\ {r}^{2} = \frac{ax - p}{q + bx} [/tex]

r² (q + bx) = ax - p

qr² + bxr² = ax - p

qr² + p = ax - bxr²

qr² + p = x (a - br²)

[tex]x = \frac{q {r}^{2} + p}{a - b {r}^{2} } [/tex]

Answer:

[tex]\displaystyle x=\frac{-P-\math{R}^2Q}{\math{R}^2b-a}[/tex]

Step-by-step explanation:

[tex]R=\sqrt{\frac{ax-P}{Q+bx}}[/tex]

[tex]\mathrm{Square\:both\:sides}[/tex]

[tex]R^2=\left(\sqrt{\frac{ax-P}{Q+bx}}\right)^2[/tex]

[tex]R^2=\frac{ax-P}{Q+bx}[/tex]

[tex]\mathrm{Multiply\:both\:sides\:by\:}Q+bx[/tex]

[tex]\math{R}^2\left(Q+bx\right)=\frac{ax-P}{Q+bx}\left(Q+bx\right)[/tex]

[tex]\math{R}^2\left(Q+bx\right)=ax-P[/tex]

[tex]\math{R}^2Q+\math{R}^2bx=ax-P[/tex]

[tex]\mathrm{Subtract\:}\math{R}^2Q\mathrm{\:from\:both\:sides}[/tex]

[tex]\math{R}^2Q+\math{R}^2bx-\math{R}^2Q=ax-P-\math{R}^2Q[/tex]

[tex]\math{R}^2bx=ax-P-\math{R}^2Q[/tex]

[tex]\mathrm{Subtract\:}ax\mathrm{\:from\:both\:sides}[/tex]

[tex]\math{R}^2bx-ax=ax-P-\math{R}^2Q-ax[/tex]

[tex]\math{R}^2bx-ax=-P-\math{R}^2Q[/tex]

[tex]\mathrm{Factor}\:\math{R}^2bx-ax[/tex]

[tex]x\left(\math{R}^2b-a\right)=-P-\math{R}^2Q[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}\math{R}^2b-a[/tex]

[tex]\frac{x\left(\math{R}^2b-a\right)}{\math{R}^2b-a}=-\frac{P}{\math{R}^2b-a}-\frac{\math{R}^2Q}{\math{R}^2b-a}[/tex]

[tex]x=\frac{-P-\math{R}^2Q}{\math{R}^2b-a}[/tex]

2/3 - 4x + 7/2 = -9x + 5/6 apply the properties.. step by step

Answers

Answer:

x=5/13

Step-by-step explanation:

2/3+7/2=9x+5/6+4x

2/3+7/2-5/6=9x+4x

lcm of 2,3,6=6

2/3=4/6      7/2=21/6       5/6=5/6

4/6+21/6-5/6=9x+4x

30/6=13x

5=13x

x=5/13

Steps:

Step 1: Simplify both sides of the equation.

2/3−4x+7/2=−9x+5/6

2/3+−4x+7/2=−9x+5/6

(−4x)+( 2/3 + 7/2 )=−9x+ 5/6 (Combine Like Terms)

−4x+25/6=−9x+5/6

−4x+25/6=−9x+5/6

Step 2: Add 9x to both sides.

−4x+25/6+9x=−9x+5/6+9x

5x+25/6=5/6

Step 3: Subtract 25/6 from both sides.

5x+25/6−25/6=5/6−25/6

5x=−10/3

Step 4: Divide both sides by 5.

5x/5=−10/3/5

=  x=-2/3

Answer:  x=-2/3

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Hope this helps.

Solve the following equation 4×6x−7=1 x= log8log6 x= log2log6 x= log6log8 x= log6log2

Answers

Answer:

The value of x is [tex]x=\frac{\log(2)}{\log(6)}[/tex].

Step-by-step explanation:

Solve the equation as follows:

[tex]4\times 6^{x}-7=1[/tex]

     [tex]4\times 6^{x}=7+1[/tex]

           [tex]6^{x}=\frac{8}{4}[/tex]

           [tex]6^{x}=2[/tex]

Take log on both sides.

[tex]\log(6^{x})=\log(2)[/tex]

[tex]x\log (6)=\log(2)[/tex]

        [tex]x=\frac{\log(2)}{\log(6)}[/tex]

Thus, the value of x is [tex]x=\frac{\log(2)}{\log(6)}[/tex].

Help please!
How does the function f(x)=x^2−4x−21 illustrate the Fundamental Theorem of Algebra?

Fill in the blanks. (Hint: Your answers are numbers.)

The degree of f(x) is _____. The Fundamental Theorem of Algebra guarantees that a polynomial equation has the same number of complex roots as its degree. This means that f(x) has exactly _____ zeros. Those zeros are 7 and _____.

Answers

f(x)=x²−4x−21

The degree is the biggest power of x.  That's a polynomial of degree 2, also called a quadratic function.  Let's find its zeros.

0 = x²−4x−21 = (x - 7)(x+3)

x=7 or x=-3

The fundamental theorem guarantees every non-constant polynomial with complex coefficients has a complex zero, let's call it r.  If we divide the polynomial by x-r there won't be any remainder and we'll get a new polynomial, one degree less.  The fundamental theorem again applies and (if it's not a constant polynomial) we are assured of another zero, s.  We divide by x-s and get a new polynomial of degree one less.  We repeat all this until we get a constant polynomial (degree zero).    So we get a zero for every degree. They're not necessarily all different.

Answer:

The degree of f(x) is 2. The Fundamental Theorem of Algebra guarantees that a polynomial equation has the same number of complex roots as its degree. This means that f(x) has exactly 2 zeros. Those zeros are 7 and -3.

Mateo's wage is £420 per week.
He spends 1/3 of his wage on food.
35% goes on the household bills and the rest is saved.
How much does Mateo save each week?

Answers

Answer:

He saves £133 every week

Need help ASAP! Need help ASAP will mark you as brainiest!

Answers

Answer:

[tex]r=\frac{44}{\pi }[/tex]

Step-by-step explanation:

[tex]88=2\pi r[/tex]

[tex]\mathrm{Switch\:sides}\\2\pi r=88\\\frac{2\pi r}{2\pi }=\frac{88}{2\pi }\\r=\frac{44}{\pi }\\or\\r=14.00563[/tex]

Answer:

2 metres

Step-by-step explanation:

Circumference = 2 × π × r

→ Substitute in the values

88 = 2 ×  [tex]\frac{22}{7}[/tex]  × r

→ Divide both sides by 2 to isolate  [tex]\frac{22}{7}[/tex]  and r

44 =  [tex]\frac{22}{7}[/tex]  × r

→ Multiply everything by 7 to get rid of the fraction

308 = 22 × 7r

→ Divide the equation by 22 to isolate 7r

14 = 7r

→ Divide the equation by 7 to isolate r

2 = r

The radius of the circle with a circumference of 88 meters is 2 metres

(PLZ NEED HELP) The doubling time of a bacterial population is 10 minutes. After 80 minutes, the bacterial population was 80000. _____
Using your rounded answer for the initial population above (do not round your growth rate), find the size of the bacterial population after 5 hours.____

Answers

Answer:

Initial population = 313

Population after 5 hours = [tex]3.36 \times 10^{11}[/tex]

Step-by-step explanation:

Let initial population = [tex]x[/tex]

It is given that population gets doubled every 10 minutes.

Population after 10 minutes = [tex]2x[/tex]

Population after 20 minutes = [tex]2^{2} x[/tex]

:

:

Population after 80 minutes = [tex]2^{8} x[/tex] and it is given as 80000.

[tex]\Rightarrow 2^{8} x = 80000\\\Rightarrow x = \dfrac{80000}{256}\\\Rightarrow x = 313[/tex]

So, initial population is 312.5 = ~313

To find, population after 5 hours i.e. 5 [tex]\times[/tex] 60 = 300 minutes

Population after 300 minutes =

[tex]2^{30} x\\\Rightarrow 2^{30} \times 313\\\Rightarrow 3.36 \times 10^{11}[/tex]

So, the answers are:

Initial population = 313

Population after 5 hours = [tex]3.36 \times 10^{11}[/tex]

(3x+8) (4x+10) what is the length

Answers

12x^2+62x+80
Do you want a step by step?

Let f(x) = .............

Answers

Answer:

4

Step-by-step explanation:

g(3) = -2(3)^2 -4 = 2(9) -4 = 18-4 = 14

|f(2)| = | 2^2 -3| = | 4-3| = 1

(g(3) +2) = (14+2) = 16

4*  |f(2)|  = 4*1 = 4

16/4 = 4

The area of a circle is 18pi square inches. If the area of a sector of this circle is 6pi square inches, then which of the following must be the sector's central angle?
Please help I’ll give you brainliest promise !

Answers

Answer:

240 degrees

Step-by-step explanation:

Mathematically, the area of a circle is

A = 2 * pi * r^2

we need to calculate the radius of the circle first

18pi = 2pi * r^2

divide both sides by 2pi

r^2 = 9

r = 3 inches

Area of sector = angle/360 * pi * r^2

6pi = angle/360 * pi * 3^2

6pi = angle/360 * 9pi

(360 * 6pi)/9pi = angle

40 * 6 = 240 degrees

HELP MARK AS BRAINLIST

Answers

Answer:

12 square units

Step-by-step explanation:

formula= a+b/2×h

a=2

b=6

h=3

the answer will be = 2+6/2×3

=8/2×3

=4×3

=12

Answer:

17 square units i think

A car travels 0.75 miles every minute.explain how you could use proportional reasoning too find how far the car travels in a hour

Answers

Answer:

The car travels 45 miles in one hour.

Step-by-step explanation:

Knowing that one hour is 60 minutes and that the car travels 0.75 miles every minute, you can multiply 60 and 0.75 which gives you 45 miles per hour meaning in one hour the car travels 45 miles.

solve tan x - cot x = -2cos 2x cosec 2x​

Answers

Answer:

Step-by-step explanation:

tan x-cot x

[tex]=\frac{sin~x}{cos~x} -\frac{cos~x}{sin ~x} \\=\frac{sin^2x-cos^2 x}{sin ~x~cos~x} \\=\frac{-2(cos^2x-sin^2x)}{2 sin ~x~cos~x} \\=\frac{-2 cos~2x}{sin~2x} \\=-2 cos ~2x~cosec~2x[/tex]

A coordinate plane showing Nina's run. The x-axis shows Time in seconds and the y-axis shows Distance in meters. Four points plotted and labeled. The points are (4, 32), (6, 48), (8, 64), (10, 80). A two column table with four rows. The first column, Time in seconds, has the entries, 4, 6, 8. The second column, Distance in meters, has the entries, 35, 47.5, 60. Nina and Ryan each ran at a constant speed for a 100-meter race. Each runner’s distance for the same section of the race is displayed on the left. Who had a head start, and how big was the head start? had a head start of meters

Answers

Answer:

Ryan had a head start of 10 meters

Answer:

Ryan had a head start of 10 meters.

Have a great day!

Step-by-step explanation:

Please mark me brainliest!

HELP ASAP!!

Determine the surface area of the figure built out of blocks.

A) 30 sq. Units
B) 26 sq. Units
C) 22 sq. Units
D) 19 sq. Units

Answers

Answer:

i think it's s d because that's how many sq. there are

In the diagram of circle O, what is the measure of ? 27° 54° 108° 120°

Answers

Answer:

Option (2).

Step-by-step explanation:

This question is incomplete; here is the complete question and find the figure attached.

In the diagram of a circle O, what is the measure of ∠ABC?

27°

54°

108°

120°

m(minor arc [tex]\widehat {AC}[/tex]) = 126°

m(major arc [tex]\widehat {AC}[/tex]) = 234°

By the intersecting tangents theorem,

If the two tangents of a circle intersect each other outside the circle, measure of angle formed between them is half the difference of the measures of the intercepted arcs.

m∠ABC = [tex]\frac{1}{2}[m(\text {major arc{AC})}-m(\text{minor arc} {AC})][/tex]

             = [tex]\frac{1}{2}(234-126)[/tex]

             = 54°

Therefore, Option (2) will be the answer.

Answer:

B.

Step-by-step explanation:

The diameter of a sphere is 4 centimeters. Which represents the volume of the sphere? StartFraction 32 Over 3 EndFractionπ cm3 8π cm3 StartFraction 64 Over 3 EndFractionπ cm3 16π cm3

Answers

Answer:

The volume of the sphere is 32 π /3 cm^3

Step-by-step explanation:

Mathematically, the volume of a sphere can be calculated using the formula below;

V = 4/3 * pi * r^3

Now since we have the radius and diameter = 2 * radius

radius = diameter/2 = 4/2 = 2

Substituting this value into the volume equation;

V = 4/3 * pi * 2^3 = 32pi/3

Answer:

The correct answer is A

Step-by-step explanation:

Which expressions have a positive product? *




–(5)(–0.2)(–1.9)(9)



–(2.14)(1.6)(14)



(6.3)(–8.7)(0.7)



(8.5)(–0.4)(–2.7)

Answers

Answer:

The fourth choice is the correct one.

Step-by-step explanation:

If the count of negative signs is even, the product is even (positive).

This does not apply to the first choice; this expression is odd.

Same for the second choice.

Same for the third choice.  The expression is odd.

The fourth choice is POSITIVE because there are an even number (2) of negative signs.

To eliminate the y-terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before
adding the equations together?
First Equation: 5x - 4y = 28
Second equation: 3x - 3y = 30
The first equation should be multiplied by 3 and the second equation by 5.
The first equation should be multiplied by 3 and the Second equation by -5.
The first equation should be multiplied by 9 and the second equation by 4
The first equation should be multiplied by 9 and the second equation by -4.
Mark this and retum
Save and Exit
Next
Submit

Answers

Answer:

To eliminate y- terms

Multiply equ(1) by 3 and equ(2) by -4

To eliminate y- terms

Multiply (1) by 3 and (2) by -5

Step-by-step explanation:

5x - 4y = 28 (1)

3x - 3y = 30 (2)

To eliminate y- terms

Multiply equ(1) by 3 and equ(2) by -4

15x-12y=84

-12x+12y= -120

Add equ (3) and (4)

3x=84-120

3x=-36

x=-36/3

= -12

x=-12

To eliminate x- terms

5x-4y=28

3x-3y=30

Multiply (1) by 3 and (2) by -5

15x-12y=84

-15x+15y=-150

Add the new equation

3y= -66

y= -22

Given: 3x < -6. Choose the solution set.
A. {x | x < -2}
B. {x | x > -2}
C. {x | x < 2}
D. {x | x > 2}

Answers

Answer:

When we divide the inequality by 3 we get x < -2 so the answer is A.

I WILL MARK AS BRAINLIST

Answers

Answer:

18 square meters

Step-by-step explanation:

Answer:

7.5 square meters

solution,

The given figure if a Trapezium whose parallel sides are of 3 m and 2 m respectively.

Distance between the parallels sides

i.e. height is 3 m

Now,

[tex]area = \frac{1}{2} \times sum \: of \: parallel \: sides \times height \\ = \frac{1}{2} \times (3 + 2) \times 3 \\ = \frac{1}{2} \times 5 \times 3 \\ = \frac{15}{2} \\ = 7.5 \: {m}^{2} [/tex]

Hope this helps...

Good luck on your assignment...

simplify (a+b)^3 + (a-b)^3 + 6a(a^2-b^2)

Answers

Answer:

8a^3.

Step-by-step explanation:

(a+b)^3=a^3+b^3+3a^2b+3ab^2

(a-b)^3=a^3-b^3-3a^2b+3ab^2

(a+b)^3+(a-b)^3=2a^3+6ab^2

According to the question

(a+b)^3+(a-b)^3+6a(a^2-b^2)

Put in the value

=2a^3+6ab^2 +6a^3–6ab^2

=8a^3

In the simplest form expression (a + b)³ + (a - b)³ + 6a(a² - b²) can be written as,  8a³

What are algebraic identities?

Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.

Given that,

A algebraic identity,

(a + b)³ + (a - b)³ + 6a(a² - b²)

It is known that,

(a + b)³  = a³ + b³ + 3ab(a + b)

(a - b)³  =  a³ - b³ - 3ab(a - b)

So, now we can substitute expressions

(a + b)³ + (a - b)³ + 6a(a² - b²)

a³ + b³ + 3ab(a + b) + a³ - b³ - 3ab(a - b) +  6a(a² - b²)

a³ + b³ +  3a²b + 3ab² + a³ - b³ -3a²b + 3ab² + 6a³ - 6ab²

8a³

Hence, the simplest form is 8a³

To know more about algebraic expressions check:

https://brainly.com/question/24875240

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