Some cruise ship passengers are given magnetic​ bracelets, which they agree to wear in an attempt to eliminate or diminish the effects of motion sickness. Others are given similar bracelets that have no magnetism. What type of study is​ this? What are the variables of​ interest?
Choose the correct answer below.
A. Observational study. The variable of interest is whether the passenger experienced motion sickness.
B. Observational study. The variable of interest is whether a passenger's bracelet is magnetized or not.
C. Experiment. The variable of interest is whether the passenger experienced motion sickness.
D. Experiment. The variable of interest is whether a passenger's bracelet is magnetized or not.

Answers

Answer 1

Answer:

Option c

Step-by-step explanation:

This is an experiment because the researcher wants to test efficiency of the magnetic bracelets in the elimination of motion sickness i.e. whether they experienced motion sickness even after wearing the magnetic bracelets.


Related Questions

please answer this correctly

Answers

Answer:

557

Step-by-step explanation:

l x w

13x24

13x7

22x7

557

Write down five numbers with a mode of 6.

Answers

Answer:

6 4 5 6 7

Step-by-step explanation:

The mode would be 5. The first 2 letters of MODE are MO, which can be an abbreviation for MOST OFTEN.

Listed below are head injury measurements from small cars that were tested in crashes. The measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion," (lower ​ "hic" values correspond to safer​ cars). The listed values correspond to cars​ A, B,​ C, D,​ E, F, and​ G, respectively. Find the
a.​ mean,
b.​ median,
c.​ midrange,
d. mode for the data.
Also complete parts e. and f. 514 541 302 400 507 406 369

Answers

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Listed below are head injury measurements from small cars that were tested in crashes. The measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion," (lower ​ "hic" values correspond to safer​ cars). The listed values correspond to cars​ A, B,​ C, D,​ E, F, and​ G, respectively.

514 541 302 400 507 406 369

Find the

a.​ mean,

b.​ median,

c.​ midrange,

d. mode for the data.

Also complete parts e. and f.

e. Which car appears to be the safest?

f. Based on these limited results, do small cars appear to have about the same risk of head injury in a crash?

Answer:

a) Mean = 434.14

b) Median = 406

c) Midrange = 421.5

d) Mode = 0

e) Car C appears to be the safest

f) The small cars does not appear to have about the same risk of head injury in a crash.

Step-by-step explanation:

We are given the head injury measurements from small cars that were tested in crashes.

The measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion.

The listed values are;

A = 514

B = 541

​C = 302

D = 400

​E = 507

F = 406

G = 369

a)​ Mean

The mean of the measurements is given by

Mean = Sum of measurements/ Number of measurements

Mean = (514 + 541 + 302 + 400 + 507 + 406 + 369)/7

Mean = 3039/7

Mean = 434.14

b)​ Median

Arrange the measurements in ascending order (low to high)

302, 369, 400, 406, 507, 514, 541

The median is given by

Median = (n + 1)/2

Median = (7 + 1)/2

Median = 8/2

Median = 4th

Therefore, the 4th measurement is the median that is 406

Median = 406

c)​ Mid-range

The midrange is given by

Midrange = (Max + Min)/2

The maximum measurement in the data set is 541

The minimum measurement in the data set is 302

Midrange = (541 + 302)/2

Midrange = 843/2

Midrange = 421.5

d)​ Mode for the data

The mode of the data set is the most repeated measurement.

302, 369, 400, 406, 507, 514, 541

In the given data set we don't have any repeated measurement therefore, there is no mode or we can say the mode of this data set is 0.

Mode = 0

e) Which car appears to be the safest?

Since we are given that the measurements are in​ "hic," which is a measurement of a standard​ "head injury​ criterion," (lower ​ "hic" values correspond to safer​ cars)

The lowest hic value corresponds to car C that is 302

Therefore, car C appears to be the safest among other cars.

f) Based on these limited results, do small cars appear to have about the same risk of head injury in a crash?

302, 369, 400, 406, 507, 514, 541

As you can notice, the hic values differ a lot from each other therefore, we can conclude that the small cars does not appear to have about the same risk of head injury in a crash.

Find the area of a regular hexagon with a side length of 5cm, Round to the nearest tenth.

Answers

Answer:

i think its 64.95cm

Step-by-step explanation:

Please answer this correctly

Answers

Answer:

Area of the figure = 254.5 cm²

Step-by-step explanation:

Area of rectangle = Length × Width

Area of triangle = 1/2(base × Height)

Dividing the figure into parts for convenience

So,

Rectangle 1  (the uppermost):

4 × 6 = 24 cm²

Rectangle 2 (below rectangle 1):

15 × 8 = 120 cm²

Rectangle 3 (with rectangle 2):

11 × 4 = 44 cm²

Triangle 1 :

1/2(7 × 19) = 133/2 = 66.5 cm²

Now adding up all to get the area of the figure:

Area of the figure = 24 + 120 + 44 + 66.5

Area of the figure = 254.5 cm²

Erin has previously recorded all credit card activity manually using the Expense transaction screen and reconciled the account using the Reconciliation Tool. After connecting her credit card in the Banking Center, she doesn’t see any matches for the transactions she previously entered and reconciled.

Answers

Answer:

The steps Erin has to take for the reconciliation of her account and activities is as follows: Select the reconciled transactions, Select Batch actions, and Modify the selected ones.

Step-by-step explanation:

Solution

Since Erin could not detect any matches for the transactions she has entered before and enrolled, she needs to take the following processes to reconcile back all her credit activities which is stated below:

Process 1 :Select the reconciled transactions

Process 2 :Batch Actions

Process 3: Modify Selected

From the process stated above Erin can first of all choose the reconciled transactions, after that she can select the batch actions and lastly modify the ones that was selected with the aim of putting or adding them back in the account reconciliation.

The length of a rectangle is increasing at a rate of 8 cmys and its width is increasing at a rate of 3 cmys. When the length is 20 cm and the width is 10 cm, how fast is the area of the rectangle increasing?

Answers

Answer:

The area of the rectangle increasing at the rate of 140 cm²/s

Step-by-step explanation:

Rectangle area:

A rectangle has two dimensions, length l and width w.

It's area is:

A = l*w.

When the length is 20 cm and the width is 10 cm, how fast is the area of the rectangle increasing?

We apply implicit differentiation to solve this question:

[tex]A = l*w[/tex]

So

[tex]\frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}[/tex]

Length is 20, so [tex]l = 20[/tex].

Width is 10, so [tex]w = 10[/tex]

The length of a rectangle is increasing at a rate of 8 cm/s and its width is increasing at a rate of 3 cm/s.

This means that [tex]\frac{dl}{dt} = 8, \frac{dw}{dt} = 3[/tex]

So

[tex]\frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}[/tex]

[tex]\frac{dA}{dt} = 20*3 + 10*8 = 140[/tex]

Area in cm².

So

The area of the rectangle increasing at the rate of 140 cm²/s

g Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 6 ft high

Answers

Answer:

0.3537 feet per minute.

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

[tex]\dfrac{dV}{dt}=10$ ft^3/min[/tex]

[tex]\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h[/tex]

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

[tex]\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}[/tex]

[tex]\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}[/tex]

Therefore: [tex]\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10[/tex]

We want to determine how fast is the height of the pile is increasing when the pile is 6 feet high.

[tex]When h=6$ feet$\\\dfrac{3\pi *6^2}{12}\dfrac{dh}{dt}=10\\9\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{9\pi}\\ \dfrac{dh}{dt}=0.3537$ feet per minute[/tex]

When the pile is 6 feet high, the height of the pile is increasing at a rate of 0.3537 feet per minute.

Please answer this correctly

Answers

Answer:

Band: 30%

Chorus: 18%

Painting: 21%

Robotics: 14%

Coding: 17%




Determine the number of ways three trumpet players out of 6 are chosen for 1st chair, 2nd chair, and 3rd chair.

Answers

Answer:

120 ways

Step-by-step explanation:

There are 3 spots and 6 options

_ _ _

1  2 3

6 ways for 1st chair to be chosen

5 ways for 2nd chair to be chosen (1st chair is chosen already, so there are 5 players left)

4 ways for 3rd chair to be chosen (1st and 2nd are already chosen, only 4 players left)

Multiply 6*5*4 to find the total number of ways (120)

If f(3x − 1) = 6x − 1, find f(x) and f(0)

Answers

f(3x - 1) = 6x - 1

Rewrite 6x - 1 as a function of 3x - 1:

6x - 1 = 6x - 2 + 1 = 2(3x - 1) + 1

That is,

f(3x - 1) = 2(3x - 1) + 1

which means

f(x) = 2x + 1

and so

f(0) = 2*0 + 1 = 1

Bonita said that the product of 5/6 x 1 2/3 is 7/3.

How can you tell that her answer is wrong.

Answers

Answer:

  Bonita's product is too large

Step-by-step explanation:

The two factors in the problem are (5/6) and (5/3). The factor 5/6 is less than 1, ensuring that the product will be less than 5/3.

Bonita's result of 7/3 is more than 5/3, so is too large to be the product.

??!!!?!?
.....
....
...

Answers

Answer:

A) (3,2)

Step-by-step explanation:

Conditions:

x+y ≤ 6x ≥ 0y ≥ 0

A) (3,2)

yes, as all 3 conditions are met3+2≤6, 3≥0, 2≥0

B) (0,7)

no, as the first condition is not met0+7 > 6

Five people ​(Aaron ​, Byron ​, Carina ​, Duncan ​, and Evelyn ​) form a​ club, Nequals ​{A, ​B, C,​ D, E}. Carina and Evelyn are​ women, and the others are men. If they choose a treasurer ​randomly, find the odds in favor of Evelyn becoming treasurer . The odds in favor of Evelyn becoming treasurer are

Answers

Answer is   1:4

================================================

Explanation:

When we talk about "odds in favor", we will use a colon to separate two whole numbers. The first number represents the number of ways for Evelyn to be chosen treasurer (just one way) and the second number represents all the ways she doesn't get chosen (the four other people)

Put another way, writing "odds in favor are 1:4" basically means "there's 1 way to get Evelyn elected and 4 ways for her to not get elected"

Instead of writing 1:4 you could write "1 to 4"

-----------

Side note: Contrast this with "odds against" and the ratio would flip from 1:4 to 4:1. Same idea, but the number of failures is listed first because we're focusing on the "against" (instead of "favor") portion. We read "4:1" as "4 to 1".

The odds in favor of Evelyn becoming treasurer are 1:5 or 1/5.

To determine the odds in favor of Evelyn becoming treasurer, we need to know the total number of possible outcomes and the number of favorable outcomes.

There are five members in the club, so there are five possible outcomes for the treasurer position, one for each member. Since Evelyn is one of the five members, she has one favorable outcome.

Therefore, the odds in favor of Evelyn becoming treasurer are 1:5 or 1/5.

Learn more about odds in favor here:

https://brainly.com/question/32587212

#SPJ4

The percent, X , of shrinkage o n drying for a certain type of plastic clay has an average shrinkage percentage :, where parameter : is unknown. A random sample of 45 specimens from this clay showed an average shrinking percentage of 18.4 and a standard deviation of 2.2.

Required:
a. Estimate at 5% level of significance whether the true average shrinkage percentage U: is greater than 17.5 and write your conclusion.
b. Report the p-value.

Answers

Answer:

a) [tex]t=\frac{18.4-17.5}{\frac{2.2}{\sqrt{45}}}=2.744[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=45-1=44[/tex]  

The critical value for this case is [tex]t_{\alpha}=1.68[/tex] since the calculated value is higher than the critical we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 18.4

b) [tex]p_v =P(t_{(44)}>2.744)=0.0044[/tex]  

Step-by-step explanation:

Information given

[tex]\bar X=18.4[/tex] represent the sample mean

[tex]s=2.2[/tex] represent the sample standard deviation

[tex]n=45[/tex] sample size  

[tex]\mu_o =17.5[/tex] represent the value to verify

[tex]\alpha=0.05[/tex] represent the significance level

t would represent the statistic

[tex]p_v[/tex] represent the p value

Part a

We want to test if the true mean is higher than 17.5, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 17.5[/tex]  

Alternative hypothesis:[tex]\mu > 17.5[/tex]  

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

And replacing we got:

[tex]t=\frac{18.4-17.5}{\frac{2.2}{\sqrt{45}}}=2.744[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=45-1=44[/tex]  

The critical value for this case is [tex]t_{\alpha}=1.68[/tex] since the calculated value is higher than the critical we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 18.4

Part b

The p value would be given by:

[tex]p_v =P(t_{(44)}>2.744)=0.0044[/tex]  

A supermarket is redesigning it’s checkout lanes. Design A has a sample size of 50, sample mean of 4.1 minutes, and sample standard deviation of 2.2 minutes. Design B has a sample size of 50, sample mean of 3.5 minutes, and sample standard deviation of 1.5 minutes. At the 0.05 level of significance, determine if their is evidence that the checkout times of the two systems differ.

Answers

Answer:

The calculated value t = 1.57736 < 1.9845 at 5 % level of significance

Null hypothesis is accepted at 5 % level of significance

There is no significance difference between Design A and Design B

Step-by-step explanation:

Given  sample size of design A

                                            n₁ = 50

sample mean of design A x⁻₁ = 4.1 minutes

Sample standard deviation S₁ = 2.2 minutes

Given  sample size of design B

                                            n₂ = 50

sample mean of design A x⁻₂ = 3.5 minutes

Sample standard deviation S₂ = 1.5 minutes

Null Hypothesis : H₀ : There is no significance difference between Design A and Design B

Alternative Hypothesis : H₁:There is  significance difference between Design A and Design B

Level of significance ∝ = 0.05

Test statistic

[tex]t = \frac{x^{-} _{1}- x^{-} _{2} }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} }) } }[/tex]

where

[tex]S^{2} = \frac{n_{1} S_{1} ^{2} +n_{2} S^2_{2} }{n_{1} +n_{2} -2}[/tex]

[tex]S^{2} = \frac{50 (2.2)^{2} +50(1.5)^2}{50+50-2}[/tex]

On calculation , we get

S² = 3.6173

Test statistic

                   [tex]t = \frac{4.1-3.5}{\sqrt{3.617(\frac{1}{50} +\frac{1}{50} }) }[/tex]

On calculation , we get

   t = 1.57736

Degrees of freedom

ν = n₁ + n₂ -2 = 50 +50 -2 =98

t₀.₀₂₅ ,₉₈ = 1.9845

The calculated value t = 1.57736 < 1.9845 at 5 % level of significance

null hypothesis is accepted

Please answer this correctly

Answers

Answer:

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Step-by-step explanation:

Answer:

The quarter circle's area is 38.47 yard²

Step-by-step explanation:

The area of a full circle is pi * r ²

The area of a quarter circle is 1/4 * pi * r ²

Given:

Use 3.14 for pi

Round to the nearest hundredths.

Perimeter of quarter circle is 24.99 yards

For r you must leave it as 'r' because we do not know it for now...

1. Circumference of a full circle = 2* pi * r

2. 1/4 * ( 2 * pi * r )

1/4 * ( 2 * 3.14 * r )

1/2 * 3.14 * r

1.57 * r

3 Since r = 'r'

We have to 2 sides running from the centre of the 'pie' to the left and right of the quarter circle which both have a length of exactly 'r'. So you just add 2 * r.

4. The outcome of step 2 + step 3 is the perimeter of quarter circle, which was given as 24.99 inch

1.57 * r + 2 * r = 24.99

( 1.57 + 2 ) * r = 24.99

3.57 * r = 24.99

Divide left and right of the = sign by 3.57

3.57 / 3.57 * r = 24.99 / 3.57

1 * r = 24.99 / 3.57

r = 7

The area of a quarter circle is 1/4 * pi * r ²

1/4 * pi * 7²

1/4 * 49 * pi

49/4 * pi

49/4 * 3.14

38.465

Round to the nearest hundredths gives 38.47 yard²

The quarter circle's area is 38.47 yard²

Which of the following represents "two times the sum of a number and fifteen is equal to six times the number?"

A. 2(6N + 15) = N
B. 2N + 15 = 6N
C. 2(N + 15) = 6N

Answers

Two times the sum of a number and fifteen is equal to six times the number.

times - multiply
number- variable (N)

C. 2(N + 15) = 6N

Please answer this correctly

Answers

Answer:

40 - 59 ⇒ 6

60 - 79 ⇒ 5

Answer:

40-59: 6

60-79: 5

Step-by-step explanation:

If you just added up, you can find all the values.

I need help with this one

Answers

Answer:

Top right

Step-by-step explanation:

The solution to a system of equation is where the two graphs cross

The top right lines cross at (5,-3)

A shareholders' group, in lodging a protest, claimed that the mean tenure for a chief executive office (CEO) was at least eight years. A survey of companies reported in the Wall Street Journal found a sample mean tenure x = 7.56 of years for CEOs with a standard deviation of years s = 6.67 years.
A. Formulate hypotheses that can be used to challenge the validity of the claim made by the shareholders' group.
B. Assume 70 companies were included in the sample. What is the p-value for your hypothesis test?
C. At α = 0.02, what is your conclusion?

Answers

Answer:

could be c might be a also

Step-by-step explanation:

as a last-minute deal Don and Mary booked a 7 day cruise for a total of $670 if the normal price for a couple is $1340, what discount percent did Don and Mary recieve?​

Answers

Answer:

Don and Mary received a discount of 50%.

Step-by-step explanation:

Initially, we use a rule of three to find the percentage of the initial price that they paid.

The discount is 100% subtracted by the percentage they paid.

Percentage they paid:

The normal price for a couple is $1340, which is 100%.

They paid $670, which is x%. We have to find x.

$1340 - 100%

$670 - x%

[tex]1340x = 100*670[/tex]

[tex]x = \frac{100*670}{1340}[/tex]

[tex]x = 50[/tex]

They paid 50% of the original price.

What discount percent did Don and Mary recieve?​

100 - 50% = 50%

Don and Mary received a discount of 50%.

3. Which of the following values is not possible in probability?
A. P(x) = 1
B. x P(x) = 3 C. P(x) = 0.5
D. P(x) = -0.5​

Answers

Answer:

D . P(x)=-0.5

Step-by-step explanation:

i think please mark my answer as a brainliest answer and follow me.

The answer is D.P(x)=-0.5


Please help me i need the answer if i knew it i will complete all of them by my self (: .

Answers

For area you would times the two sides you have together
10 x 10 = 100

The right answer is 100 units^2

please see the attached picture for full solution

Hope it helps

Good luck on your assignment,

9. The mean is defined as the
A. number that shows up most often in a data set.
B. average of a data set.
C. middle of the data set.
D. range of the data set.

Answers

Answer:

B. Average of the data set

Step-by-step explanation:

The mean is defined as the average of a data set and it's formula is

Mean = [tex]\frac{sum of observations}{number of observations}[/tex]

A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/cubic meter with a standard deviation of 0.0783. Determine the 80% confidence interval for the population mean nitrate concentration. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

Answers

Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=25-1=24[/tex]

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=1.318 \cdot 0.016=0.021[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186[/tex]

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).

A swimming pool is to be drained. The pool is shaped like a Rectangular prism with length 12m , with 10 m, and depth 3m. Suppose water is pumped out of the pool at a rate of 18 m3 per hour.if the pool starts completely full , how many hours does it take to empty the pool ?

Answers

Answer:

20 hours

Step-by-step explanation:

first calculate volume:

12x10x3=360

then divide by 18

360/18=20

So 20 hours in total

During the worst periods of inflation in America, the price of food increased at a rate of 12 % per month. If your food bill was $300 one month during this period, what was it two months later?
Exponential; $337.08
Linear; $672.00
Exponential; $376.32
Linear; $372.00

Answers

Answer:

  Exponential; $376.32

Step-by-step explanation:

Generally, an increase of 12% in a month means the prices are 12% more than they were in the previous month. That is, the value has been multiplied by 1.12.

The same would be true for the second month, so the overall multiplier for the two months is ...

  (1.12)(1.12) = 1.12^2 = 1.2544

This makes the food bill for the second month amount to ...

  1.2544 × $300 = $376.32

_____

As with all percentages, you need to be clear about what base is being used. Here, we have assumed the base for a monthly increase is the value at the beginning of the month.

If, instead, it is the value at the beginning of the year, then the increase is linear, not exponential. 12% of the value at the beginning of the year is the same throughout the year.

A tank contains 180 liters of fluid in which 50 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min; the well-mixed solution is pumped out at the same rate. Find the number A(t) of grams of salt in the tank at time t.

Answers

Answer:

[tex]\mathbf{A(t) = 180 - 130e ^{-\dfrac{t}{30}}}[/tex]

Step-by-step explanation:

Given that:

A tank contains 180 liters of fluid in which 50 grams dissolved inside.

Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min

The salt pumped out[tex]= \dfrac{6 L}{180 L} = \dfrac{1}{30}[/tex] of initial amount added salt

At (t = 0) = 50

To determine the number A (t)

[tex]\dfrac{dA}{dt}=Rate_{in} - Rate _{out}[/tex]

[tex]A' = 6 - \dfrac{1}{30}A[/tex]

[tex]A' + \dfrac{1}{30}A = 6[/tex]

Integrating factor  [tex]y = e^{\int\limits pdt[/tex]

[tex]y = e^{\int\limits \dfrac{1}{30}dt}[/tex]

[tex]y = e^{\dfrac{t}{30}}[/tex]

[tex](e^{ \frac{t}{30}}A)' =4 e ^{\dfrac{t}{30}}+c[/tex]

Taking integral on the both sides;

[tex]Ae ^{\dfrac{t}{30}}= 6 * 30 e^{\dfrac{t}{30}} + c[/tex]

[tex]A = 180+ ce^ {-\dfrac{t}{30}}[/tex]

At  A(t = 0) = 50

50 = 180  + C            (assuming C = [tex]ce ^{-\dfrac{t}{30}}[/tex])

C = 50 - 180

C = 130

[tex]\mathbf{A(t) = 180 - 130e ^{-\dfrac{t}{30}}}[/tex]


Pls help me with this

Answers

Answer:

x = 1.5

Step-by-step explanation:

Given

[tex]\frac{x}{2} \geq 0.75[/tex]

[tex]\frac{x}{2} < 2.5[/tex]

Required

Find the value of x.

First, the inequalities need to be rewritten and merged;

if [tex]\frac{x}{2} \geq 0.75[/tex], then

[tex]0.75 \leq \frac{x}{2}[/tex]

Multiply both sides by 2

[tex]2 * 0.75 \leq \frac{x}{2} * 2[/tex]

[tex]1.5 \leq x[/tex]

Similarly;

[tex]\frac{x}{2} < 2.5[/tex]

Multiply both sides by 2

[tex]2 * \frac{x}{2} < 2.5 * 2[/tex]

[tex]x < 5[/tex]

Merging these results together; to give

[tex]1.5 \leq x < 5[/tex]

This means that the range of values of x is from 1.5 to 4.9999....

From the question, x is the smallest rational number; from the range above ([tex]1.5 \leq x < 5[/tex]), the minimum value of x is 1.5 and 1.5 is a rational number;

Hence, x  = 1.5

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