Squid use jet propulsion for rapid escapes. A squid pulls water into its body and then rapidly ejects the water backward to propel itself forward. A 1.5 kg squid (not including water mass) can accelerate at 20 m/s2 by ejecting 0.15 kg of water. Part A What is the magnitude of the thrust force on the squid

Answer:

Answer:

The correct answer is C

Explanation:

Change is momentum can be described as the change in the product of mass and velocity of a body. Every moving object as a momentum and the higher the momentum of this object, the harder it is to stop. Impulse (a force), which is sometimes used to describe change in momentum can be described as the product as force multiplied by time.

From the description above, it can be deduced that an increase in impulse can lead to a greater change in momentum. And an increase in impulse can be brought about by an increase in the time it takes a body to be brought to rest after collision. And since the car that hit the water barrels was brought to rest at a longer time, it has a greater change in momentum

Answer:

a

[tex]H =212.6 \ J[/tex]

b

[tex]v = 7.647 \ m/s[/tex]

Explanation:

From the question we are told that

   The child's weight is  [tex]W_c = 287 \ N[/tex]

    The length of the sliding surface of the playground is  [tex]L = 7.20 \ m[/tex]

    The coefficient of friction is  [tex]\mu = 0.120[/tex]

      The angle is [tex]\theta = 31.0 ^o[/tex]

      The initial  speed is  [tex]u = 0.559 \ m/s[/tex]

Generally the normal force acting on the child is mathematically represented as

=>    [tex]N = mg * cos \theta[/tex]

Note  [tex]m * g = W_c[/tex]

Generally the frictional force between the slide and the child is    

         [tex]F_f = \mu * mg * cos \theta[/tex]

Generally the resultant force acting on the child due to her weight and the frictional  force is mathematically represented as

      [tex]F =m* g sin(\theta) - F_f[/tex]

Here  F is the resultant force and it is represented as  [tex]F = ma[/tex]

=>   [tex]ma = m* g sin(31.0) - \mu * mg * cos (31.0)[/tex]

=>   [tex]a = g sin(31.0)- \mu * g * cos (31.0)[/tex]

=>  [tex]a = 9.8 * sin(31.0) - 0.120 * 9.8 * cos (31.0)[/tex]

=>[tex]a = 4.039 \ m/s^2[/tex]

So

   [tex]F_f = 0.120 * 287 * cos (31.0)[/tex]

=> [tex]F_f = 29.52 \ N[/tex]

Generally the heat energy generated by the frictional  force which equivalent tot the workdone by the frictional force  is mathematically represented as

     [tex]H = F_f * L[/tex]

=>  [tex]H = 29.52 * 7.2[/tex]

=>  [tex]H =212.6 \ J[/tex]

Generally from kinematic equation we have that

    [tex]v^2 = u^2 + 2as[/tex]

=>  [tex]v^2 = 0.559^2 + 2 * 4.039 * 7.2[/tex]

=>  [tex]v = \sqrt{0.559^2 + 2 * 4.039 * 7.2}[/tex]

=>  [tex]v = 7.647 \ m/s[/tex]

Answer:

the object's mass is 50 kg

Explanation:

We use Newton's second law to solve for the mass:

F = m * a , then   m = F / a

In our case, the acceleration is the gravitational acceleration on the planet, and the force is the weight of the object on the planet. So we get:

m = w / a = 650 N / 13 m/s^2 = 50 kg

Then, the object's mass is 50 kg.

Answer:

yes

Explanation:

Answer:

x = 704 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} ^{2} =v_{o} ^{2} +2*a*x[/tex]

where:

Vf = final velocity = 65 [m/s]

Vo = initial velocity = 0 (starts from rest)

a = acceleration = 3 [m/s²]

x = distance [m]

Now replacing we have:

65² = 0 + 2*3*x

4225 = 6*x

x = 704 [m]

Answer:

d.music comes out from a television speaker

Explanation:

because television use electricity (electrical energy) and produce sound (sound energy) that we hear while watching tv

Answer:

The answer would be (D) Music comes out from a television speaker.

Explanation:

This is because the TV uses electrical energy from where its plugged in. And the speaker is the sound energy which is caused by the TV to go with the show you are watching.

Hope this helps!

Answer:

B. 10000 J

Explanation:

The possible answers are not related to the statement at all. The correct statement is:

If a 100 kg person walks up two floors in the Physics building (about 10 meters up), this person's potential energy has increased by:

From definitions of work and gravitational potential, we get the following formula to calculate the change experimented in the person's potential energy after walking up two floors in the Physics building:

[tex]\Delta U_{g} = m\cdot g \cdot \Delta z[/tex] (1)

Where:

[tex]\Delta U_{g}[/tex] - Change in the gravitational potential energy, measured in joules.

[tex]m[/tex] - Mass of the person, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]\Delta z[/tex] - Change in height, measured in meters.

If we know that [tex]m = 46\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta z = 10\,m[/tex], then the change in the gravitational potential energy is:

[tex]\Delta U_{g} = (100\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (10\,m)[/tex]

[tex]\Delta U_{g} = 9807\,J[/tex]

The choice that best approximates this answer is B.

Answer:it’s A

Explanation:

because i took the quiz

Answer:

D is the correct answer, not A

Explanation:

Complete question:

Two parallel 3.0-meter long wires conduct current. The current in the top wire is 12.5 A and flows to the right. The top wire feels a repulsive force of 2.4 x 10^-4 N created by the interaction of the 12.5 A current and the magnetic field created by the bottom current (I). Find the magnitude and direction of the bottom current, if the distance between the two wires is 40cm.

Answer:

The bottom current is 12.8 A to the right.

Explanation:

Given;

length of the wires, L = 3.0 m

current in the top wire, I₁ = 12.5 A

repulsive force between the two wires, F = 2.4 x 10⁻⁴ N

distance between the two wires, r = 40 cm = 0.4 m

The repulsive force between the two wires is given by;

[tex]F = \frac{\mu_oI_1I_2L}{2\pi r}\\\\I_{2} = \frac{2F\pi r}{\mu_oI_1L}[/tex]

Where;

I₂ is the bottom current

The direction of the bottom current must be in the same direction as the top current since the force between the two wires is repulsive.

[tex]I_{2} = \frac{2F\pi r}{\mu_oI_1L}\\\\I_{2} = \frac{2(2.4*10^{-4})(\pi)(0.4)}{(4\pi*10^{-7})(12.5)(3)}\\\\I_{2} = 12.8 \ A[/tex]

Therefore, the bottom current is 12.8 A to the right.

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{6}{12} = \frac{1}{2} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:A

Explanation:

Answer:

A. -2.83 x 10-7N

Explanation:

Answer:

Explanation:

Force = mass * acceleration

Given

Mass = 1500kg

Get the acceleration using the equation of motion;

v² = u²+2aS

20² = 0+2s(200)

400 = 400a

a = 400/400

a = 1m/s²

Get the upward force required

F = 1500 * 1

F = 1500N

Hence the upward force required if the elevator moves upward 200.0 meters before reaching 20.0 m/s is 1500N

Answer:

The ratio is  [tex]R_c:R_e = 4 : 1[/tex]

Explanation:

From the question we are told that

   The period of the satellite is  [tex]T_c = 8 \ years[/tex]

Generally the period of earth around the sun is [tex]T_e = 1 \ year[/tex]

Generally from Kepler's third law , which is mathematically represented as

      [tex]\frac{T_c ^2}{T_e^2} = \frac{R_c^3}{R_e^3}[/tex]

Here  [tex]R_c[/tex] is the radius of the orbit which the satellite rotate around the sun

         [tex]R_e[/tex] is the radius of the orbit which the earth rotate around the sun

=>  [tex]\frac{R_c^3}{R_e^3} = [\frac{8}{1} ]^2[/tex]

=>   [tex]\frac{R_c}{R_e} = \sqrt[3]{[\frac{8}{1} ]^2}[/tex]      

=>   [tex]\frac{R_c}{R_e} = \frac{4}{1 }[/tex]      

=>   [tex]R_c:R_e = 4 : 1[/tex]

Answer:

  C = A - B

Explanation:

The addition of vectors takes into account the magnitude of each vector and its direction, so when adding two vectors, the result depends on the direction of the vectors.

* If the vectors have the same direction the result is maximum

            C = A + A

* if the vectors have 90 between them, the magnitude of the result is given by the Pythagorean Theorem

            C = √(A² + B²)

* if the vectors have 180º between them the result is minimal

            C = A - B

We can also perform this sum graphically, where the resulting vector goes from the origin of the first vector to the tip of the last one, it can clearly be seen that when the vectors are antiparallel (180º angle) the magnitude is minimal

Answer:

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Answer:

The amplitude of the motion is 0.0286 m.

Explanation:

Given;

mass of the object, m = 0.2 kg

spring constant, k = 120 N/m

maximum speed of the simple harmonic motion, [tex]V_m[/tex] = 0.70 m/s

The amplitude A of the motion is given by;

[tex]V_m = \omega A\\\\[/tex]

where;

ω is the angular velocity given as;

[tex]\omega = \sqrt{\frac{k}{m} }\\\\\omega = \sqrt{\frac{120}{0.2} }\\\\\omega =24.5 \ rad/s[/tex]

Now, substitute the value of angular velocity and solve the amplitude;

[tex]V_m = \omega A\\\\A = \frac{V_m}{\omega}\\\\A = \frac{0.7}{24.5}\\\\A = 0.0286 \ m[/tex]

Therefore, the amplitude of the motion is 0.0286 m.

Answer:

b. 29.2 rev/min

Explanation:

       [tex]L_{0} = L_{f} (1)[/tex]

        [tex]L_{0} = I_{0} * \omega_{0} (2)[/tex]

        where I₀ = initial moment of inertia = moment of inertia of the disk +

        moment of inertia of the cylinder and ω₀ = initial angular velocity  =

       30.0 rev/min.

       [tex]L_{f} = I_{f} * \omega_{f} (4)[/tex]

       where If = final moment of inertia = moment of the inertia of the solid

      disk + moment of  inertia of the clay flattened on a disk, and ωf = final

      angular velocity.

   [tex]I_{f} = \frac{1}{2} * m_{d} *r_{d} ^{2} + \frac{1}{2}* m_{fd} *r_{fd} ^{2} = 0.2 kg*m2 +6.4e-3 kg*m2 = 0.2064 kg*m2 (5)[/tex]

       ⇒ Lo =Lf = If*ωf

        [tex]\omega_{f} = \frac{L_{o}}{I_{f} } = \frac{6.027kg*m2*rev/min}{0.2064kg*m2} = 29.2 rev/min (6)[/tex]

The rate of change of angular displacement is defined as angular speed. The final angular speed of the wheel will be 29.2 rev/min.

The rate of change of angular displacement is defined as angular speed.  is stated as follows:

ω = θ t

Where,

θ is the angle of rotation,

t is the time

ω is the angular speed

The given data in the problem is

m is the mass of wheel = 10.0 kg

r₁ is the radius of disk = 20.0 cm=0.2

M is the mass of clay= 2.0 kg

R is the radius of cylinder =  3.0cm

[tex]\rm \omega_i[/tex] is the initial rotational speed =30.0 rev/min

r₂ is the final radius of disk=  8.0 cm.

[tex]\rm \omega_f[/tex] is the initial rotational speed=?

When the external torques act on the body is zero the total angular momentum must be conserved, as follows:

Initial momentum = Final momentum

[tex]\rm L_0=L_f[/tex]

The value of the initial angular momentum L₀ is found by

I₀ = initial moment of inertia = moment of inertia of the disk +moment of inertia of the cylinder

[tex]\rm I_0= \frac{1}{2}m_dr_d^2+ \frac{1}{2}m_cr_c^2\\\\ \rm I_0= \frac{1}{2}\times 10\times (0.2)^2+ \frac{1}{2}\times m_2(0.03)^2[/tex]

[tex]\rm L_0 = I_0\times \omega_0\\\\ L_0 = 2009\times 30\\\\ \rm L_0 =6.027 \;kgm^2rev/min[/tex]

The value of the final angular momentum [tex]I_f[/tex] is found by

[tex]\rm I_f= \frac{1}{2}m_dr_d^2+ \frac{1}{2}m_fr_fd^2\\\\ \rm I_0= 0.2064 m_2[/tex]

[tex]\rm I_f[/tex] is the final moment of inertia = moment of the inertia of the solid disk + moment of inertia of the clay flattened on a disk.

[tex]L_0 =L_f = I_f \times \omega_f[/tex]

[tex]\rm \omega_f=\frac{L_0}{I_f} \\\\ \rm \omega_f=\frac{6.027 m_2}{0.2064 m_2} \\\\ \rm \omega_f= 29.2\; rev/min[/tex]

Hence the final angular speed of the wheel will be 29.2 rev/min.

To learn more about the angular speed refer to the link;

https://brainly.com/question/9684

Answer:

true

Explanation:

Answer:

true

Explanation:

Answer:

a. E = 86.36 x 10⁻³ V/m = 86.36 mV/m

b. ρ = 3.6 x 10⁻⁷ Ωm

Explanation:

a.

The electric field in terms of the voltage is given by the following formula:

E = V/d

where,

E = Electric Field in the Wire = ?

V = Potential Difference = 3.8 V

d = distance between the points = 44 m

Therefore,

E = 3.8 V/44 m

E = 86.36 x 10⁻³ V/m = 86.36 mV/m

b.

Now, from Ohm's Law:

V = IR

R = V/I

where,

R = Resistance of wire = ?

I = Current = 3 A

Therefore,

R = 3.8 V/3 A

R = 1.27 Ω

Now, the resistance of a wire can be given as:

R = ρL/A

where,

ρ = resistivity of material = ?

L = Length = 44 m

A = Cross-sectional area = πr² = π(0.002 m)² =  1.25 x 10⁻⁵ m²

Therefore,

1.27 Ω = ρ*44 m/1.25 x 10⁻⁵ m²

(1.27 Ω)(1.25 x 10⁻⁵ m²)/44 m = ρ

ρ = 3.6 x 10⁻⁷ Ωm

Explanation:

One common property with all halogens in group 7 is that they are all non-metals.

Fluorine, chlorine, Bromine and Iodine are classified as non-metallic elements and they have a high electronegativity.

The most prominent observation from halogens is that they all non-metallic in nature.

Answer:

The correct option is a

Explanation:

From the question we are told that

   The mass of the block is  [tex]m = 4.84 \ kg[/tex]

    The height of the vertical  drop is [tex]h = 19.6 \ m[/tex]

Generally from the law of energy conservation , the potential energy at the top  of the slide is equal to the kinetic energy at the point after sliding this can be mathematically represented as

        [tex]PE = KE[/tex]

i.e     [tex]m * g * h = \frac{1}{2} * m * v^2[/tex]

=>    [tex]gh = 0.5 v^2[/tex]

=>   [tex]v = \sqrt{\frac{9.8 * 19.6}{0.5 } }[/tex]

=>    [tex]v = 19.6 \ m/s[/tex]

The iron has, because it's displacing more water than the wood is.

Answer:

X = 69.1 x 10⁻⁶ m = 69.1 μm

Explanation:

The relationship between the motion of the moveable mirror and the fringe count of the Michelson's Interferometer is given by the following formula:

d = mλ/2

where,

d = distance moved by the mirror = X = ?

m = No. of Fringes counted = 246

λ = wavelength of light entering interferometer = 562 nm = 5.62 x 10⁻⁷ m

Therefore,

X = (246)(5.62 x 10⁻⁷ m)/2

Therefore,

X = 69.1 x 10⁻⁶ m = 69.1 μm

Answer:

The length of the pendulum cord is approximately 114.592 centimeters.

Explanation:

We include a representation of the motion of the pendulum in the image attached below. The trajectory described by the pendulum is represented by the following geometrical expression:

[tex]s = \theta \cdot r[/tex] (1)

Where:

[tex]\theta[/tex] - Angular change with the vertical, measured in radians.

[tex]r[/tex] - Length of the pendulum cord, measured in centimeters.

[tex]s[/tex] - Arc, measured in centimeters.

If we know that [tex]\theta = \frac{\pi}{9}[/tex] and [tex]s = 40\,cm[/tex], then the length of the pendulum cord is.

[tex]r = \frac{s}{\theta}[/tex]

[tex]r = \frac{40\,cm}{\frac{\pi}{9} }[/tex]

[tex]r \approx 114.592\,cm[/tex]

The length of the pendulum cord is approximately 114.592 centimeters.

Answer:

true

Explanation:

Im in k12 and I got an 100%

We know, by conservation of energy :

[tex]\dfrac{kx^2}{2}=mgh[/tex]

Therefore,

[tex]\dfrac{x_1^2}{x_2^2}=\dfrac{h_1}{h_2}[/tex]

Putting given values, we get :

[tex]\dfrac{x_1^2}{x_2^2}=\dfrac{h_1}{h_2}\\\\\dfrac{4.9^2}{x_2^2}=\dfrac{50.2}{2\times 50.2}\\\\x_2^2=2\times 4.9^2\\\\x_2 = 4.9\times \sqrt{2}\\\\x_2=6.93\ cm[/tex]

Therefore, the spring be compressed to 6.93 cm to send the ball twice as high.

Hence, this is the required solution.

Answer:

no they different

Explanation:

because hen lives on land and eagle flies in sky it doesnt walk often just it aearch for its prey and it eats there only

Answer:

eheisjsnsndndj

Explanation:

sjdjdj

a. Nitrogen, Oxygen,and Carbon Dioxide

hope im right but I dont really know