Starting at rest, A car accelerated to 20m/s in 4s. How far did the car travel as it sped up. Assume constant acceleration?

Answers

Answer 1

Answer:

40 m

Explanation:

displacement = 1/2 a t^2

                        = 1/2 ( 20/4) (4^2)

40 m


Related Questions

How many grams are in 2 kg

Answers

There are 2000g in 2kg
There are 2000g in 2kg

Helium balloons pop in a hot car because

Answers

Answer:

This is because helium molecules get bigger when they heat up , so if your balloons keep getting hotter , they will eventually pop

Answer:

the helium molecules within the ballon expand as they heat up, resulting in the eventually resulting in popping.

Explanation:

^^^^^

Polio is a disease that can cause paralysis. Doctors treated patients with casts and braces, but the work of Elizabeth Kenny led to the use of hot baths and exercise to treat polio victims. These patients had less incidence of paralysis. Kenny’s ideas and their acceptance were due to

Answers

Kenny’s ideas and their acceptance were due to open-mindedness because she led to the use of hot baths and exercise to treat polio victims.

Who was Elizabeth Kenny?

Elizabeth Kenny was a world-renowned nurse from Australia who develop a treatment for poliomyelitis, a very serious viral disease caused by poliovirus.

Elizabeth Kenny's ideas were controversial because they may be considered to be against conventional medical treatments.

In conclusion, Kenny’s ideas and their acceptance were due to open-mindedness because she led to the use of hot baths and exercise to treat polio victims.

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What does an electromagnet in an electric motor do? I need help asap

Answers

Answer:the Correct Answer is

It transforms electrical energy into mechanical energy.

Explanation:

I got the answer right

The Universal Gravitational constant
gives the mass and value a direction
converts the ratio of mass and distance to Newtons
gives the mass and distance a value
converts the ratio of mass and distance to kilograms

Answers

According to the given question, mBg- mAg = a(mA + mB)  is the equation that will be used to determine acceleration.  

The gravitational constant, represented by the capital G, is an empirical physical constant used in the calculation of gravitational effects in both Albert Einstein's theory of general relativity and Sir Isaac Newton's law of universal gravitation.

It is the proportionality constant in Newton's law that links the gravitational force between two bodies to the sum of their respective masses and the square root of their distance. It quantifies the relationship between the energy-momentum tensor and the spacetime geometry in the Einstein field equations.

The measured value of the constant is known to four significant digits with some certainty. Its value is approximately 6.674×10−11 m3⋅kg−1⋅s−2 in SI units.

Given in the qusetion

T -  WA = mAa         --------------1

WB - T = mBa            --------------2

We know that, WA = mAg and WB = mBg

T = mAa + WA

T = mAa + mAg           --------------3

Similarly, T = WB - mBa

T = mBg- mBa            --------------4

From equation 3 and 4

mAa + mAg = mBg- mBa

mAa + mBa = mBg- mAg

a(mA + mB) =  mBg- mAg

So, mBg- mAg = a(mA + mB)  is the equation that will be used to determine the acceleration.  

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Your question is incomplete. Please check the full content below.
The Universal Gravitational constant converts the ratio of mass and distance to Newton

gives the mass and distance a value

converts the ratio of mass and distance to kilograms

gives the mass and value a direction

The following equations are for two connected objects in the axis of motion

T-WA=mAa

WB-T=mBa

Which of the following equations would be used to determine the acceleration

T+mBg-mAg=(mA+mB)a

-T+mBg-mAg=(mA+mB)a

mBg-mAg=(mA+mB)a

mBg-mAg=mAa

7. A tennis ball thrown horizontally from the top of a water tower lands 20.0 m from the base of the tower. If the tennis ball is initially thrown at a velocity of 10.0 m/s: (a) how long does it take the tennis ball to reach the ground? (b) how high is the water tower? (b) how far away was the golfer from the hole when he hit the ball? A championship goffer uses a nine iron to chip a shot right into the cup. If the golf ball is launched at a velocity of 20m / s at an angle of 60 deg above the horizontal: (a) how long was the ball in the air? (c) what maximum height did the ball reach?​

Answers

Time taken by the tennis ball to reach the ground is 1.23 second, if the initial velocity is  10.0 m/s.

Velocity is the time price at which an object is transferring alongside a route, even as the pace is the fee and path of an item's motion. put some other manner, velocity is a scalar price, at the same time as velocity is a vector.

Speed is the speed at which something moves in a particular direction. for instance as the rate of a car traveling north on a motorway, or the rate a rocket travels after launching. In a scalar way, absolutely the value magnitude of the velocity vector is continually the velocity of the motion.

Speed is a vector expression of the displacement that an item or particle undergoes with appreciation to time. the standard unit of speed magnitude (also known as velocity ) is the meter consistent with 2nd (m/s).

The top of a water tower lands 20.0 m

initial velocity = 10.0 m/s

time required to reach the ground  =

S = ut + 1/2 at²

20 = 10t + 5t²

t = 1.23 second

The water is at a height of 20 m.

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As a ladder leans against a wall it exerts a force on both the wall and ground. What are the two reactant forces on the ladder?
Responses

−Fwall on ladder and −Fground on ladder
−Fwall on ladder and −Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline

Fwall on ladder and −Fground on ladder
Fwall on ladder and −Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline

Fwall on ladder and Fground on ladder
Fwall on ladder and Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline

−Fwall on ladder and Fground on ladder
−Fwall on ladder and Fground on ladder

Its -Fwallonladdy and -fgroundonladder just made sure to add this since no one else did yet

Answers

The two reactant forces on the ladder are -Fwall on Ladder and -Fground on Ladder

What are the two reactant forces on the ladder?

To know the reactant forces on the ladder, we use Newton's third law of motion.

What is Newton's third law of motion?

Newton's third law of motion states that for every action, there is an equal and opposite reaction.

So, for the ladder, as the ladder leans against a wall it exerts a force on both the wall and ground.

Now, since the ladder exerts a force on the wall, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the wall is Fladder on wall, then the reaction force of wall on the ladder is Fwall on ladder.

So, Fladder on wall = -Fwall on Ladder

Also, since the ladder exerts a force on the ground, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the ground is Fladder on ground, then the reaction force of ground on the ladder is Fground on ladder.

So, Fladder on ground = -Fground on Ladder

So, the two reactant forces on the ladder are -Fwall on Ladder and -Fground on Ladder

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Convert 1.54 mg/cm³ to kg/dm³.

Answers

The converted unit 1.54 (mg / (cm^3)) is :

=0.00154 kg / (dm^3.)

What does unit conversion mean?

A unit conversion is used to express the same property in a distinct unit of measurement. Minutes can be used to measure time instead of hours, and feet, kilometres, or any other measure can be used to measure distance in place of miles.

Why is conversion of units required?

Showing someone the precise amount you have will be helpful. help with a mathematical problem, especially one involving chemistry where the solution can be found by following the units. Indicate the person's preferred system of measurement (i.e. metric or standard).

Briefing:

1.54 mg/ cm³ x 1g/1000mg

Continue likewise until you have achieved kg:

1.54 mg/ cm³ x 1g/1000mg x 1 kg/ 10000g

Now, work on cm³

1.54 mg/ cm³ x 1g/1000mg x 1 kg/ 1000g x 10³ cm/1dm³  = ?

= .00154 kg/dm³

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Find the force exerted by a pressure of 40N/m² acting over an area of 0.0025 cm ​

Answers

Answer:

[tex]1.0*10^{-5} N[/tex]

Explanation:

To answer this question we can use the formula: [tex]P=\frac{F}{A}[/tex]

Pressure (Pascals) = Force (Newtons) divided by Area (Square Meters)

We are given pressure and area in the question and are trying to find force so we can rearrange the equation to suit our needs by multiplying both sides by Area:

[tex]P(A) = \frac{F}{A} (A)\\ \\F =PA[/tex]

The next step is to ensure all given information is in the correct units. Because we are given pressure in the units [tex]N/m^{2}[/tex], we need to convert 0.0025[tex]cm^{2}[/tex] into [tex]m^{2}[/tex].

There are 10,000 [tex]cm^{2}[/tex] in 1 [tex]m^{2}[/tex], therefore to convert between them, we need to divide 0.0025 by 10,000.

[tex]0.0025/10000 = 0.00000025m^{2}[/tex]

OR [tex]2.5*10^{-7} m^{2}[/tex]

Now we just need to multiply them together to get force:

[tex]F=PA\\F=40*2.5*10^{-7}\\F=1.0*10^{-5} N[/tex]

Hope this helped!

006 (part 1 of 4) 3.0 points

Both car A and car B leave school at the same time, traveling in the same direction. Car A travels at a constant speed of 74 km/h, while car B travels at a constant speed of 93 km/h. How far is Car A from school 2.7 h later? Answer in units of km.

007 (part 2 of 4) 3.0 points

How far is car B from school 2.7 h later? Answer in units of km.

008 (part 3 of 4) 3.0 points

How long does it take car A to reach a gas station a distance 189 km from the school? Answer in units of h.

009 (part 4 of 4) 3.0 points

How long does it take car B to reach the gas station? Answer in units of h.​

Answers

1. The distance of car A from the school is 199.8 Km

2. The distance of car B from the school is 251.1 Km

3. The time taken for car A to reach the station is 2.55 hours

4. The time taken for car B to reach the station is 2.03 hours

What is speed?

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

1. How to determine the distance of car A from the schoolSpeed = 74 Km/hTime = 2.7 hoursDistance of car A =?

Speed = Distance / time

Cross multiply

Distance = speed × time

Distance of car A = 74 × 2.7

Distance of car A = 199.8 Km

2. How to determine the distance of car B from the schoolSpeed = 93 Km/hTime = 2.7 hoursDistance of car B =?

Speed = Distance / time

Cross multiply

Distance = speed × time

Distance of car B = 93 × 2.7

Distance of car B = 251.1 Km

3. How to determine the time taken for car A to reach the gas stationSpeed = 74 Km/hDistance = 189 KmTime for car A =?

Speed = distance / time

74 = 189 / time

Cross multiply

74 × time = 189

Divide both side by 14

Time = 189 / 74

Time for car A = 2.55 hours

4. How to determine the time taken for car B to reach the gas stationSpeed = 93 Km/hDistance = 189 KmDistance = 189 KmTime for car B =?

Speed = distance / time

93 = 189 / time

Cross multiply

93 × time = 189

Divide both side by 93

Time = 189 / 93

Time for car B = 2.03 hours

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Britney is on the starting line to run a track race. The distance around the track is 400m.
She starts the race and runs 400m around the track. She ends up in the same place where
she started. What distance did she cover? What was her displacement?

Answers

So she started from the finish line , she ran the track 400m so she only cover 400 m so your answer is 400m

What is the mass of a block accelerating at 2 m/s2 and pushed by a 9 N force?

Answers

Answer:

1 Newton (N) 1 kg*m/s²

Acceleration is measured in m/s², so combine your starting figures in such a way as to get m/s² (you have to divide away the kg):

9N/2kg = 4.5 m/s²

Explanation:

What is measurement ?...​

Answers

Answer:

the size, length, or amount of something, as established by measuring.

the determination of the size or magnitude of something. By comparing that unknown quantity with some standard quantity of equal nature, known as measurement unit.

Wil-E-Coyote drops a bowling ball off a cliff to try to catch the Roadrunner. The cliff is 128 m high. How long does it take the ball to hit the ground?

Answers

The time has taken the ball to hit the ground is (t)= 5.11 Seconds.

What is time?

The best example that would help us understand and know what time are the clock and the calendar. This clock gives us the exact hour, minutes and seconds. The calendar tells us the exact day, month and year.

How can we calculate time?

To calculate the time has taken the ball to hit the ground, we are using the formula,

S=ut+(1/2)gt²

Here we are given,

u= The initial velocity of the ball= 0 m/s

g= The acceleration due to gravity is= 9.8 m/s²

S= The height of the cliff = 128m.

We have to calculate the time has taken the ball to hit the ground = t

Now, we put the known values in the above equation we get,

S=ut+(1/2)gt²

Or, 128=0*t+(1/2)*9.8*t²

Or, t= √((2*128)/9.8)

Or, t=5.11 Seconds

Thus from the above calculation we can conclude that, the time has taken the ball to hit the ground is (t)= 5.11 Seconds

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What become v if we use 2 risistors of 4w in parallel

Answers

the voltage across two resistors of 4w in parallel is the same.

A student drops a ball from the top of a 37-meter tall building. The ball leaves the student's hand with a zero speed. What is the speed of the ball at the moment just before it hits the ground?

Answers

Answer:

The ball accelerates because of gravity which is constant. So we can apply one of the equations of uniformly accelerated motion to solve the problem.

[tex]Vf^2=Vo^2+2aS\\[/tex] is compatible since [tex]S, Vo, a[/tex] are given enabling us to calculate [tex]Vf[/tex] .

[tex]Vf^2=(0m/s)^2+2*10m/s^2*37m\\Vf^2=20m/s^2*37m\\Vf^2=740m^2/s^2\\Vf=\sqrt{740} m/s\\ Vf=27.202941017 m/s\\[/tex]

HELP URGENT- will give brainliest if correct

Answers

Answer:

6 km is the right answer

hope it helps you

Explanation:

please mark me as brainliest

Velocity in x direction
Initial velocity in y direction

Answers

Answer: Vx= 86.6 m/s & Vy= 50 m/s

Explanation:

Vx= 100*cos30° = 86.6 m/s

Vy= 100*sin30° = 50 m/s


needdd helppppppppp

Answers

Answer:

divide 223 by 74 and you'll get your answer

A cheetah can run at a maximum speed
106 km/h and a gazelle can run at a maxi-
mum speed of 75.6 km/h.
If both animals are running at full speed,
with the gazelle 63.4 m ahead, how long before
the cheetah catches its prey?
Answer in units of s.

Answers

Answer:

Explanation:

We find the difference in speeds between the 2 animals

106 - 75.6 = 29.4 km/h

then we convert it to m/s by dividing it with 3.6

29.4 / 3.6 = 8.2 m/s

distance divided by speed equals time

63.4 / 8.2 = 7.7 seconds

A man runs at 7.5 m s-1 due east across the deck of a ship which moves at 10.0 m s-' due
north. Determine the resultant velocity of the man (his velocity relative to the water).

Answers

The resultant velocity of the man is 12.5 m/s N of E.

Velocity of the man, Vm = 7.5 m/s

Velocity of Ship, Vs= 10 m/s

Since, velocity is a vector quantity, it will have both the magnitude and the direction.

So the magnitude for the resultant vector can be calculated by using the formula

[tex]\sqrt{x^{2} +y^{2} }[/tex] ; where x is the magnitude of the x-axis component and y is the magnitude of the y-axis component

i.e.

= [tex]\sqrt{Vm^{2} +Vs^{2} }[/tex]

= [tex]\sqrt{7.5^{2} + 10^{2} }[/tex]

= [tex]\sqrt{156.25}[/tex]

= 12.5 m/s

Also the direction can be calculated by Tan[tex]\alpha[/tex]

Tan[tex]\alpha[/tex] = [tex]\frac{10}{7.5}[/tex]

= Tan⁻(1.33)

= 58.9°

The angle between the resultant velocity and the horizontal axis is 58.9°.

Therefore the resultant velocity of the man relative to the water is 12.5 m/s towards NORTH-EAST direction.

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Soil erosion is the wearing down of soil. This map provides data on the rate of soil erosion in the united states for a given year. What trend does the mad show? A. Soil erosion rates are high across the united states B. Soil erosion rates are low across the united states C. Siol erosion rates are uniform across the united states D. Soil erosion rates vary across the united states

Answers

Soil erosion is the wearing down of soil. The trend that the map shows is that soil erosion rates vary across the united states.

Hence, option (D) is correct.

What is Soil Erosion?

The removal of the top layer of soil by the action of wind, water, or human activities is known as soil erosion.Sometimes, soil erosion is good for the environment, especially in depositing fertile soil.Soil erosion is a geological action of moving soil.The areas with the highest agricultural activities have the highest rate of erosion.

As shown on the map, soil erosion vary across the United States.

Therefore, option (D) is correct.

Soil erosion is a slow method that happens while the impact of water or wind detaches and gets rid of soil particles, inflicting the soil to go to pot. Soil deterioration and low water excellent because of erosion and surface runoff have turn out to be intense troubles international.

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If a container, with a fixed number of molecules inside, is
reduced in volume, less molecules will hit the sides of the
container per unit time, causing less pressure.
TRUE
FALSE
Check it

Answers

Answer:

FALSE

FALSE

FALSE

FALSE

To pass a vehicle inspection, your Must be heard from 200 feet away.
Ohorn
Omuffler
windshield wipers
stereo

Answers

A I think sorry if I'm wrong

A: In a second contest, the three displacements given are 90.9 m , 30.0 ∘ west of north; 15.5 m straight north; and 80.9 m , 45.0 ∘ south of east. What magnitude does the winner calculate for the displacement to find the keys to the Porsche?

B: What direction does the winner calculate for the displacement to find the keys to the Porsche?

Answers

A. Magnitude that the winner calculates for the displacement to find the keys to the Porsche is 38.83m.

B. The direction that the winner calculates for the displacement to find the key to the Porsche is 72.38° East of North.

When a particle moves from position A to point B, its displacement cannot be expressed using scalars. Always represented as a vector.

If an object's beginning and final positions are the same, its displacement is zero. That is, if a person begins a voyage at one location, walks some distance, and then returns to that location, his mobility will be zero.

The distance to the item will be 0 in this situation. Furthermore, there is no direction of zero displacements.

Given,

S1 = 90.9m, 30.0° west of north

S1 = 90.9 sin 30°( - î) + cos 30° j

∴ S1 = -45.45î + 78.72j

S2 = 15.5 m straight north

S2= 15.5 j

S3 = 80.9m, 45° south of east

S3 = 80.9 cos 45° î + 80.9 sin 45° j

S3 = 57.21 î - 57.21 j

Now,

Total displacement, S = S1 + S2 + S3

S = (-45.45î + 78.72j) + ( 15.5 j) + (57.21 î - 57.21 j)

  = ( -45.45 + 57.21) î + ( 78.72 + 15.5 -57.21) j

S  = 11.76 î + 37.01 j

|S| = 38.38m

tan α = y / x

tan α = 37.01 / 11.76

tan α = 3.15

α = 72.38°   from East of North

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7. What is the acceleration of a 24.00 kg mass pushed by an 8.0 N force?

Answers

Answer:

3 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question we have

[tex]a = \frac{24}{8} \\ [/tex]

We have the final answer as

3 m/s²

Hope this helps you

How can you categorize the hazard in the hospitality industry?

Answers

Falls and Falling Objects.
Chemical Exposure.
Fire Hazards.
Electrical Hazards.
Repetitive Motion Injury.

Suppose, that you are measuring the length of a wood block and the edge of your block appears to be lined up exactly with a millimeter mark. How would you express the estimate part of a millimeter when you record the block’s length?

Answers

When taking the measurement, the estimate part of a millimeter when recording the block’s length can be expressed as ± 0.5 mm.

What are measurements?

Measurements are the processes by which the attributes and properties of a given object or substance is quantified.

There are two types of measurements that can be obtained from any given object and they are:

quantitative measurementsqualitative measurements

Quantitative measurements measures the properties of objects in terms of numbers. Some examples of quantitative measurements are length, temperature, time, mass, etc.

Qualitative measurements describe the non-numerical features of objects such as color, texture, etc.

The measurement of length of a block of wood is a quantitative measurement.

The uncertainty or estimate of a measurement is half plus or minus the smallest division in the measurement.

The uncertainty or estimate of the millimeter block = ¹/₂ * 1 mm

The uncertainty or estimate of the millimeter block = ±0.5 mm

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.Which term is described as a shelf of undersea land reaching a depth of about 200 meters (656 feet) and extending out from the shoreline?

A. guyots

B. deep-sea trenches

C. abyssal plains

D. continental shelf

Answers

Option D. continental shelf

Continental shelf is a part of a continent that is submerged under an area of ​​relatively shallow water known as a shelf sea.

It is given in the question, that the shelf of undersea land reaches 200 meters and it also extends out from the shoreline. This condition is only possible when a structure is submerged, and such submerged region can only be called as continental shelf.

On the other hand guyots is a underwater volcanic mountain and deep-sea trenches are the the long narrow lowerings in the ocean floor with the depth upto 6000 meters. And abyssal plains are the underwater ocean floors which cannot be found at the depth of 200 meters.

Therefore continental shelf is used to described as a shelf of undersea land reaching a depth of about 200 meters (656 feet) and extending out from the shoreline.

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when does a circuit is said to be over loaded?​

Answers

Answer:

Every electric circuit in a wiring system must be protected against overloads. A circuit overload occurs when the amount of current flowing through the circuit exceeds the rating of the protective devices. The amount of current flowing in a circuit is determined by the load -- or the "demand" -- for current.

Explanation:

Hope this helps :)

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