state the principle of conservation of energy​

Answers

Answer 1

Answer:

Principal of Conservation of Energy states that " Energy is neither created nor destroyed. However, It is just converted to other forms of energy"


Related Questions

If kinetic energy of a body is increased by 125%, the percentage increase in Momentum is?

Answers

Answer:

50 %

Explanation:

It's Fifty percent

What observation about light supported Einstein’s theory?

Answers

Answer:

Explanation:

Do you mean the theory that space-time is defined by what's in it? And that mass warps space-time?

There are many instances where his observation turned out to be correct. The most popular one is the phenomena of gravitational lensing. We can see the light from stars that are actually behind the sun. The huge gravity of the sun bends space-time and this also bends light. We use gravitational lensing alllll the time when trying to see very distant stars or galaxies.

Answer:

The Sun bent the light from a star. This bending made the star appear in a slightly different position from its actual position. This observation supported Einstein’s theory.

Explanation:

This is the answer on Edmentum! :)

4 answers. Anyone know?​

Answers

Answer:

lift

weight

thrust

air resistance

Explanation:

plz mark me as brainliest

Answer: Upthrust, lift, air resistance,  and thrust

Explanation:

All of these 4 elements are taken into account during the design and creation of a plane.

The graph shows the motion of a cyclist.



Calculate;

a) The acceleration in the first 20 s.

b) The acceleration between 20 and 30s.

c) The acceleration in the last 10 s.

d) The distance travelled by the cyclist when he was moving at a constant speed?
Show working.

Answers

Answer:

A. 0.5m/s².

B. –0.5m/s².

C. –0.5m/s².

D. 100m.

Explanation:

A. Determination of the acceleration in the first 20s.

Initial velocity (u) = 0

Final Velocity (v) = 10m/s

Time (t) = 20secs.

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (10 – 0)/20 = 10/20

a = 0.5m/s²

Therefore, the acceleration of the cyclist in the first 20secs is 0.5m/s²

B. Determination of the acceleration between 20 and 30s. This can be obtained as follow:

Initial velocity (u) = 10m/s

Final Velocity (v) = 5m/s

Time (t) = 30 – 20 = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (5 – 10)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the 20 and 30secs is

–0.5m/s².

C. Determination of the acceleration in the last 10s.

Initial velocity (u) = 5m/s

Final Velocity (v) = 0

Time (t) = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (0 – 5)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the last 10secs is

–0.5m/s².

D. Determination of the distance travelled by the cyclist when he was moving at a constant speed.

Velocity (v) = 5m/s

Time (t) = 50 – 30 = 20secs

Displacement (d) =?

Velocity = Displacement /Time

v = d/t

5 = d/20

Cross multiply

d = 5 x 20

d = 100m

Therefore, the distance travelled by the cyclist at constant speed is 100m

A wire is placed between the poles of a horseshoe magnet. There is a current in the wire in the direction shown, and this causes a force to act on the wire.

Answers

The answer in the picture

Mass is the amount of what​

Answers

Answer:

Mass is the amount of matter in a substance.

Explanation:

The basic SI unit for mass is the kilogram (kg).

How can one find the mechanical advantage of a pulley?

Answers

Answer:

To calculate the mechanical advantage of a pulley you simply have to count the number of rope sections that support whatever object you are lifting (not counting the rope that is attached to the effort)

Example:

For example, in a one pulley system the MA is 1. In a two pulley system the MA is 2. The more compound the pulley is the easier the load is to lift. If you were lifting a 600kg object with 2 pulleys you would have to use enough effort to pull 300kg to lift the 600kg object! Therefore your mechanical advantage would be 2 (600/300).

               MA= load/effort OR number of rope sections

Count the numbers and then support whatever you are lifting (object)

A ball hits a wall horizontally at 6m/s and rebounces at 4.4m/s the ball is in contact with wall for 0.04 sec. what is the acceleration.

Answers

Answer:

Acceleration (a) = 40 m/s²

Explanation:

Given:

Initial velocity (u) = 6 m/s

Final velocity (v) = 4.4 m/s

Time taken (t) = 0.04sec

Find:

Acceleration (a) = ?

Computation:

We know that,

⇒ v = u + at

a = (v - u) / t

⇒ Acceleration (a) = (4.4 - 6) / 0.04

⇒ Acceleration (a) = (-1.6) / 0.04

Acceleration (a) = 40 m/s²

can someone help what are the common branches of physics

Answers

Answer: Dear Buddy ,the common brnches os physics are given below:

Explanation:

Mechanics

Classical physics

Modern physics

Thermodynamics

Electricity

Magnetism

Geo physics

Plasma physics

Optics

Sound and oscillation

Electronics

Chemical physics

Engineering physics

Solid state physics

Quantum physics

Nuclear physics

Particle physics

Bio physics

Astrophysics

Condensed matter physics

hope it helps

Answer:

Engineering is one of branches that uses physics mainly the most

Explanation:

as for engineering requires mathematics and physics principles in their everyday routine to calculate and measure accordingly to manufactur a product.

suppose that g (x) equals f (x + 1) - 3 which statement best compares the graph of g (x) with the graph of f (x)​

Answers

Answer:

The graph of G(x) is the graph of F(x) shifted 1 unit to the left and 3 units down.

Explanation:

f(x + q) which is left q units

f(x - q) which is right q units

f(x) + q which is up q units

f(x) - q which down q nits

and

G(x) = F(x + 1) - 3

So,

f(x + 1) shifts to left 1 unit

f(x) - 3 shifts to down 3 units

So, the correct answer is B.

The graph of G(x) is the graph of F(x) shifted 1 unit to the left and 3 units down.

What is the unit of work? Explain whether the unit of work is a fundamental uint
or derived unit
1.
What do you mean by a unit?
2.
unit or a derived unit.
are the fundamental units used in physics?
al Bureau of Weights and Me​

Answers

Answer:

1)the unit of work is joule. 2)it is derived unit because it is made by two different unit force and displacement .3)

How did Einstein’s and Newton’s theories differ in terms of explaining the cause of gravity?


Answers

Newton”s theory says this can occur because of gravity, a force attracting those objects to one another or to a single, third object. Einstein also says this occurs due to gravity- but in his theory, gravity is not a force. It is a curve in space-time.

Newton's law of universal gravitation doesn't say anything about the cause of gravity.

Einstein's theory of relativity does.

Question 3 of 5
2 Points
Which term refers to a transfer of thermal energy between objects?
A. Potential energy
B. Kinetic energy
C. Heat
D. Temperature
SUSMIT

Answers

Answer:

Explanation:

Kinetic energy

Answer is kinetic energy

drawing is a form of

Answers

Answer:

visual art in which one uses to mark drawing and express feelings

Explanation:

In my own opinion. Hope it helps.

A sheet of paper 3.0 cm by 4.0 cm is lying on the desk. If the atmospheric pressure is 1.013105 Pa, what is the total force exerted on the top side of the paper by the atmosphere?

Answers

Answer:

132.56N

Explanation:

Pressure is defined as force per unit area.

Expressed mathematically as;

P = F/A

Where P-pressure

F-force

A-area

From the above formula,

F= P×A

= 1.1013 × 10^5 × (3×4/10000)

= 11.013×12 =132.56N

Note: the unit of measure in cm is converted to m and since 100cm makes 1m for each sides 3cm and 4cm we convert to 'm' by dividing by 100 twice giving division by 10000)

The unit of measure Pa means Pascal and is the same as N/m2

describe three factors that influence the location of rural settlement​

Answers

Explanation:

presence of food, water ,etc

Explanation:

here is five all you have to do is just pick

What’s the When the temperature increases the viscosity of the liquids ??? Hurry someone plz help

Answers

Answer:

Decreases

Explanation:

Viscosity is inversely proportional to temperature

i.e. η ∝ [tex]\frac{1}{T}[/tex]

Where η is coefficient of viscosity and T is temperature,

Which means that when temperature increases, viscosity decreases and vice versa.

A car accelerates from 10m/s to 20m/s over a distance of 80m. What is its acceleration?

Answers

Answer:

0.125m/s^2

Explanation:

20-10=10

10 divided by 80=0.125m/s^2

The average velocity of the car is 15 m/s. The time taken to travel over the distance with this velocity is 5.3 seconds. Then the acceleration of the car is 1.8 m/s².

Wat is acceleration ?

Acceleration is a physical quantity measuring the rate  of change in velocity of a moving object. Like velocity, acceleration is a vector quantity having magnitude and direction.

Acceleration is the ratio of change in velocity to the change in time.

a = Δv/Δt

Given, the car is accelerating from 10 to 20 m/s. Hence, it travelled with average velocity of 15 m/s over the distance of 80 m.

Then , time taken  = distance/velocity

t = 80 m/15 m/s = 5.3 s

Acceleration = Δv/t = (20 -10 m/s) /5.3 s = 1.8 m/s².

Therefore, the acceleration of the car is about  1.8 m/s².

Find more on acceleration:

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Please give me concept to solve this.

Answers

Answer:

The difference in tension,  between adjacent sections of the pull cable at the given conditions is 17.701 kN

Explanation:

We take the cars as moving upwards such that the resultant pulling force on the car, F, along the cable is given by the relation

[tex]F_{car}[/tex] = Upward tension force,  [tex]Tension_{(upwards)}[/tex] - Downward tension force, [tex]Tension_{(downwards)}[/tex] - Component of the weight of the car along the taut cable

The parameters given are;

Mass of car, m = 2750 kg

Angle of inclination of taut cables, θ = 35°

The upward acceleration of the car, a = 0.81 m/s²

Given that the weight is acting vertically downwards, we have;

Component of the weight of the car along the taut cable = m × g × sin(θ)

∴ Component of the weight of the car along the taut cable = 2750 × 9.81 × sin (35°) = 15473.66 N

We therefore have;

[tex]F_{car}[/tex] =  [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] - 15473.66 N

[tex]F_{car}[/tex]  = m × a = 2750 × 0.81 =  [tex]T_{upwards}[/tex] - [tex]T_{downwards}[/tex] - 15473.66

∴  [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] = 2750 × 0.81 + 15473.66 = 17701.16 N

Hence the difference in tension,  [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] between adjacent sections of the pull cable if the cars are at the maximum permissible mass and are being accelerated up the incline = 17701.16 N or 17.701 kN.

At what wavelength would a star radiate the greatest amount of energy if the star has a surface temperature of 60,000 K?

Answers

Answer:

[tex]\lambda=4.81\times 10^{-8}\ m[/tex]

Explanation:

We have,

The surface temperature of the star is 60,000 K

It is required to find the wavelength of a star that radiated greatest amount of energy. Wein's displacement law gives the relation between wavelength and temperature such that :

[tex]\lambda T=2.89\times 10^{-3}[/tex]

Here,

[tex]\lambda[/tex] = wavelength

[tex]\lambda=\dfrac{2.89\times 10^{-3}}{60000}\\\\\lambda=4.81\times 10^{-8}\ m[/tex]

So, the wavelength of the star is [tex]4.81\times 10^{-8}\ m[/tex].

Which of the following machines most likely has the greatest efficiency?
a
A. Airplane
B. Automobile
C. Bicycle
D. Human body

Answers

Im guessing airplane

The gravitational force between two students sitting beside each other on Earth is

Answers

Answer:

Fgrav. = GM1×M2/R2

Explanation:

Gravitational force is mostly related

to planetary bodies by Newton's law of gravitation which states that the gravitional force is proportional to the product of the mass of the object and inversely proportional to the square of the distance between them.

Hence in this case the Gravitational force,

Fgrav. = GM1×M2/R2

M1 and M2 are the mass of the two students and R is their distance apart

G is a constant known as gravitational constant.6.67408 × 10-11 m3/kgs2


A rubber band that has been stretched has gained ____ energy
OA) heat
OB) kinetic
OC) potential
D) chemical​

Answers

Answer: potential

Explanation:

A car starts from rest and develops an acceleration of 2 m/s2. If the distance covered by the car during its motion is 100m, what is the final velocity attained by the car?

Answers

Answer:

20

Explanation:

because I am always right yo bro be like me

What is the force experienced when a 5.0 kg mass is accelerated at 7.5 m/s??

Answers

Answer:

F = 37.5 N

Explanation:

It is given that,

Mass of the object is 5 kg

Acceleration of the object is 7.5 m/s²

We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,

F = m

[tex]F=5\times 7.5\\\\F=37.5\ N[/tex]

So, the force acting on the object is 37.5 N.    

how many chromosomes does an elephant's egg cell have ?

Answers

Answer:

Diploid is often noted as 2N where N is the number of chromosomes. So in humans 2N=46. During sexual reproduction, the sex cells of parent organisms unite with one another and form a fertilized egg cell. In this situation, each sex cell is a gamete.

Explanation:

A 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees. Ignoring friction, how fast is it going when it reaches the bottom of the hill?​

Answers

Answer:

10.2 m/s

Explanation:

Using conservation of energy:

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)

v = 10.2 m/s

The velocity when car reaches the bottom of the hill is 10.2 m/s.

What is mechanical energy?

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

M.E = ½ mv² + mgh

where g is the acceleration due to gravity, v is the velocity, m is the mass and h is the height of the object.

Given is a 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees.

Using conservation of energy principle, we have

PE = KE

mgh = ½ mv²

v = √(2gh)

Substitute the values, we get

v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)

v = 10.2 m/s

Thus, the velocity when car reaches the bottom of the hill is 10.2 m/s.

Learn more about mechanical energy.

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When heat is converted into another form of energy, the total amount of energy is constant. Which law best illustrates this statement?
A.
the first law of thermodynamics
B.
the second law of thermodynamics
C.
the third law of thermodynamics
D.
none of the above

Answers

Answer:

A

Explanation:

This is the first law of thermodynamics and it's called the law of conservation of energy

Answer : A


explanation :



if the resistance of a car headlight is 15 ohm and the current through it is 0.60, what is the voltage across the headlight?

Answers

Answer:

9 volts (assuming 0.60 is in Amperes)

Explanation:

Recall that Ohms law can be expressed as

V = IR, where

V = voltage,

I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)

R = resistance (given as 15 ohm)

substituting the above values into the formula

V = IR

V = (0.6)(15)

V = 9 Volts

Answer is 9 V you use Ohm’s Law to solve the problem

GENTE ME AJUDEM NESTA QUESTÃO POR FAVOR, TENHO PROVA ONLINE AMANHÃ! "Um sonar de um navio de pesca localizou um cardume de sardinhas a 300 m de profundidade. Sabendo que a velocidade de propagação do som na água tem o valor de 1500 m/s, calcula o tempo que decorre desde a emissão dos ultra-sons e a sua receção no navio." Por favor!

Answers

Answer:

The time between the emission of the wave and it's reception was 0.4 seconds.

Explanation:

The sound wave emitted by the sonar traveled from the boat to the fishes and came back, therefore the distance of it's total route is twice the distance from the boat to the fishes. We can apply the average speed formula in order to solve this problem, this is done below:

[tex]\text{speed} = \frac{\text{distance}}{\text{time}}[/tex]

We were given the distance traveled by the wave and it's speed, therefore we can solve for the time:

[tex]\text{time} = \frac{\text{distance}}{\text{speed}}\\\\\text{time} = \frac{(2*300)}{1500}\\\\\text{time} = \frac{600}{1500} = 0.4 \text{ s}[/tex]

The time between the emission of the wave and it's reception was 0.4 seconds.

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