Stoplight parrotfish:

Answer:

A. Air

Explanation:

Answer:

C. Horizontal component of velocity

Explanation:

Object in motion stays in motion,

nothing works against its motion in the horizontal direction, unlike in the vertical direction, gravity pulls object down.

Answer:

B) 0.3Hz

Explanation:

I just took the test i hope i helped and i hope you pass the test

Answer:.5

Explanation:

I took the quiz

Answer: conductors are substances that allow heat or electricity to pass through . It deals with only the flow of electrons.

Eg. water, copper wire, iron rod, some ceramic materials, metallic nail.

Insulators are materials that do not allow heat or electricity to pass through.

Eg. Book, plastic, rubber, glass, paper

Explanation:

Answer:

d = 6105 m

Explanation:

For this exercise we must use trigonometry to find the diameter of the has. The most common definition in optics of the angle of divergence is measured between the two ends of the beam, therefore to use this angle in trigonometry where the angle is measured with respect to the normal we must take half of this angle

          θ = 1.65 10⁻⁵ / 2 = 0.825 10⁻⁵ rad

let's use the tangent

          tan θ = y / L

          y = L tan θ

          y = 370000 103 tan (0.825 10⁻⁵)

let's be careful since the angles are in radians

          y = 3025.5 m

This is the distance from the normal that corresponds to the radius of the circle, the diameter is twice the radius

          d = 2 y

          d = 2 3025.5

          d = 6105 m

Answer:

5 x 10⁻⁷N

Explanation:

Given parameters:

Mass of object 1  = 100kg

Mass of object 2 = 300kg

Distance  = 2m

Unknown:

Force of gravitational attraction between the objects  = ?

Solution:

From Newton's law of universal gravitation we derive an expression:

        Fg  = [tex]\frac{G m_{1} m_{2} }{r^{2} }[/tex]

G is the universal gravitation constant = 6.67 x 10⁻¹¹

m is the mass

r is the distance between the bodies

 Now insert the parameters and solve;

     Fg  = 6.67 x 10⁻¹¹ x [tex]\frac{100 x 300}{2^{2} }[/tex]   = 5 x 10⁻⁷N

Answer : The weight of the car is 9800 N

Explanation :

It is given that,

The mass of the car, m = 1000 kg

We have to find the weight of the car. The weight of an object is defined as the force acting on it under the action of gravity. The mass of an object is the amount of matter present in it.

Using second law of motion :

W = m g

Where

m is the mass of the car

g is the acceleration due to gravity g = 9.8 N/kg

W = 1000 kg × 9.8 N/kg

W = 9800 N

So, the weight of the car is 9800 N.

Hence, this is the required solution.

Answer: The weight of the car in newtons is 9800N/kg

Explanation:

Answer:

The answer is true

Explanation:

could you brainliest again they said I plagarized when I didn't

Answer:

2239

Explanation: Stack addition

Answer: 2,239

Explanation: do 2OOO + 1OO + 5O + 89, that will give you 2,239.

Answer:

[tex]y = - 2.7876 * 10^{28}[/tex]

[tex]x= 3.0199 * 10^{28}[/tex]

Explanation:

Given

[tex]12x+13y=12.01[/tex]

[tex]x+y=2.323 * 10^{27}[/tex]

Required:

Solve

Make x the subject in [tex]x+y=2.323 * 10^{27}[/tex]

[tex]x=2.323 * 10^{27} - y[/tex]

Substitute the above expression for y in [tex]12x+13y=12.01[/tex]

[tex]12(2.323 * 10^{27} - y) + 13y = 12.01[/tex]

Open brackets

[tex]12*2.323 * 10^{27} - 12y + 13y = 12.01[/tex]

[tex]12*2.323 * 10^{27} + y = 12.01[/tex]

Collect Like Terms

[tex]y = 12.01 - 12*2.323 * 10^{27}[/tex]

[tex]y = 12.01 - 2.7876 * 10^{28}[/tex]

12.01 is negligible compared to [tex]2.7876 * 10^{28}[/tex]

So:

[tex]y = - 2.7876 * 10^{28}[/tex]

Substitute the above expression for y in [tex]x=2.323 * 10^{27} - y[/tex]

[tex]x=2.323 * 10^{27} - (- 2.7876 * 10^{28})[/tex]

[tex]x=2.323 * 10^{27} + 2.7876 * 10^{28}[/tex]

[tex]x= 0.2323 * 10^{28} + 2.7876 * 10^{28}[/tex]

[tex]x= 3.0199 * 10^{28}[/tex]

Answer:

8

10th classpepar2021

Answer:

y ≤ 1x-1

Explanation:

line is not dotted = ___ than or equal to

shaded area below line = less than

so: ≤

--

y=mx+b

y intercept -1 (line intersects y line on -1)

y=mx-1

points (1,0) (0, -1)

find slope

---

in conclusion, y ≤ 1x - 1

hope this helped ya :-)

To avoid splashing, rain gauges are positioned 30 cm above the surface of the ground.

The rainfall may be precisely measured by a rain gauge without any loss from evaporation. It is a tool for measuring the amount of precipitation that falls over a certain area. As a result, it gauges rainfall. A millimeter of measured precipitation is equal to one liter of rainfall per square meter.

Standard rain gauges have a 150–170 cm channeled aperture. They are made to be a straightforward passive collector. For measuring the amount of precipitation, use a graduated measuring glass. To avoid rainwater splashing while measuring rainfall, the rain gauze should be positioned 30 cm above the ground.

Learn more about rain gauge here:

https://brainly.com/question/19820977

#SPJ2

Answer:

Lateral inversion is a phenomenon in which left appears to be right and vice versa. It is due to direction that light follows when it strikes a reflecting surface, generally a mirror.

Answer:

they are closer!!

Explanation:

Hope this helped!! :D

Answer:

Current drawn = 0.417 A (rounded to 3 significant figures)

Resistance = 576Ω (rounded to 3 significant figures)

Explanation:

Current = Power ÷ Voltage

Current = 100W / 240V

∴ Current = 0.416666666.... = 0.417A

Resistance = Voltage ÷ Current

Resistance = 240 ÷ 0.417

∴ Resistance = 575.539 = 576Ω

Answer:

The weight of the water is 37.14 N.

Explanation:

Given;

density of water, ρ = 62.4 lbm/ft³

volume of water, V = 1 gallon = 0.1338 ft³

The mass of the water is calculated as;

m = ρV

[tex]m = 62.4 \ \frac{lbm}{ft^3} \ \times \ 0.1338 \ ft^3\\\\m = 8.349 \ lbm[/tex]

1 lbm = 0.454 kg

8.349 lbm = ?

= 3.79 kg

The weight of the water is calculated as;

W = mg

where;

g is acceleration due to gravity = 9.8 m/s²

W = (3.79)(9.8)

W = 37.14 N.

Therefore, the weight of the water is 37.14 N.

Answer:

the impulse imparted to the ball is 4.158 kg.m/s

Explanation:

Please find attached image for diagram.

Given;

initial speed of the ball from point A, u = 54km/h = 15 m/s

angle of deflection of the ball along BOP, θ = 45⁰/2 = 22.5⁰

mass of the ball, m = 0.15 kg

the final speed of the ball along B,  = u (in reverse direction)

The initial momentum of the ball, P₁ = mucosθ

The final momentum of the ball is P₂ in reverse direction to P₁.

the impulse imparted to the ball = change in momentum of the ball

J = ΔP = P₂ - P₁

J = mucosθ - (-mucosθ)

J = mucosθ + mucosθ

J = 2mucosθ

J = 2(0.15)15cos(22.5⁰)

J = 4.158 kg.m/s

Thus, the impulse imparted to the ball is 4.158 kg.m/s

Answer:

C. 2.5

Explanation:

It said it was right, so that's cool.

Answer:

A.

Explanation:

Answer:

Speed of ball as it leaves ramp is 2 m/s

Explanation:

From the question it is given that the average distance traveled by ball from point A to B is 2.0 m and the time taken is 1sec

one student is using stopwatch to calculate the time taken by ball and another student is using meter stick to calculate the distance traveled

since speed of ball is given by v = [tex]\frac{distance}{time}[/tex]  thus,

the speed = 2 m/s

now for minimizing the error of speed it is necessary to record the readings by single students at-least 5 times and take average

by doing this, the error of speed calculation will be minimum as the it decreases the error due to random error of system caused by taking the reading  by different students

Answer:

C. The sum of the momentum gained by both pins will equal the amount of momentum lost by the ball.

Explanation:

The law of conservation of momentum states that total momentum before collision must be equal to the total momentum after collision.

Momentum could be transferred from one object to another during collision. When the ball hits the stationary pins, momentum is transferred from the ball to the pins.

Since the collision is elastic, momentum is conserved hence total momentum gained by the pins equals the total momentum lost by the ball.

Answer:

Someone might think the answer is 30 m when the person cannot distinguish between absolute pressure and gauge pressure.

Explanation:

Given absolute pressure at a depth of 20 m = 3 atm.

When you drive down 30 m in water, the gauge pressure experienced is calculated as;

P = ρgh

Where;

ρ is density of water = 1000 kg/m³

g is acceleration due to gravity, = 9.8 m/s²

h is the depth of water = 30 m

P = (1000)(9.8)(30)

P = 294000 Pa

in atm = [tex]\frac{294000}{101325} = 2.9 \ atm[/tex] ≅ 3 atm.

Thus, someone might think the answer is 30 m when the person cannot distinguish between absolute pressure and gauge pressure.

Someone  might think the height (depth) is 30 meters, if he or she is unable to distinguish between gauge pressure and absolute pressure.

Given the following data:

Scientific data:

To calculate the gauge pressure at a depth below the surface of a water:

Mathematically, gauge pressure is given by this formula:

[tex]P = \rho gh[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]P = 1000 \times 9.8 \times 30[/tex]

Gauge pressure = 294000 Pa

Next, we would convert the value in Pascals to atmosphere.

Conversion:

1 atm = 101325 Pa

X atm = 294000 Pa

Cross-multiplying, we have:

[tex]X = \frac{294000}{101325}[/tex]

X = 2.90 ≈ 3.0 atm.

Read more on absolute pressure here: https://brainly.com/question/10013312

Answer:

Answer:

Mechanical advantage of the machine is 1.5

Explanation:

The formula for mechanical advantage is:

MA = OutputForce/InputForce

To calculate this, we need the force of input and the force of output.

The formula to calculate the force given the work (W) and the distance (d) is:

F = W/d

Calculating the input force Fi:

Fi = 200Nm/20m = 10 N

Calculating the output force Fo:

Fo = 150Nm/10m = 15 N

Thus, the mechanical advantage MA is:

MA = 15N / 10N = 1.5

Answer:

300 Nm ; 300 J

Explanation:

Given that:

Force (F) = 20 N

Distance (d) = 15 m

The kinetic energy (Workdone) = Force * Distance

Kinetic Energy = 20N * 15m

Kinetic Energy = 300Nm

K. E = 1/2

Answer:

77.0k/M

Explanation:

Answer:

Total Mass = 18 kg 900 gram

Explanation:

Given:

Mass of sugar buy = 6 kg 500 gram

Mass of rice buy = 12 kg 400 gram

Find:

Total Mass

Computation:

Total Mass = Mass of sugar buy + Mass of rice buy

Total Mass = 6 kg 500 gram + 12 kg 400 gram

Total Mass = 18 kg 900 gram

Answer:

6.1 × 10^9 Nm-1

Explanation:

The electric field is given by

E= Kq/d^2

Where;

K= Coulombs constant = 9.0 × 10^9 C

q = magnitude of charge = 1.62×10−6 C

d = distance of separation = 1.53 mm = 1.55 × 10^-3 m

E= 9.0 × 10^9 × 1.62×10−6/(1.55 × 10^-3 )^2

E= 14.58 × 10^3/2.4 × 10^-6

E= 6.1 × 10^9 Nm-1

This question is not complete, the complete question is;

An electron remains suspended between the surface of the Earth (assumed neutral) and a fixed positive point charge, at a distance of 5.3 m from the point charge. Determine the charge required for this to happen.  The acceleration due to gravity is 9.8 m/s² and the Coulomb constant is 8.98755 x 10⁹ N.m²/C².  Answer in units of C.

Answer: the charge required for this to happen is 1.7415 × 10¹⁹ C

Explanation:

Given the data in the question;

we know that gravitational force on electro = M×g

mass of electron m = 9.10938356 × 10⁻³¹ kilograms

charge of electron e = 1.60217662 × 10⁻¹⁹ coulombs

given that distance r = 5.3m and the Coulomb constant = 8.98755 x 10⁹ N.m²/C²

g = 9.8 m/s²

Now for the electron to be suspended, This will happen only if the electrostatic force is equal to weight of electron;

[ (1/4πε0) × q × e] / r²   =   m × g

so we substitute

8.98755 x 10⁹ × q × 1.60217662 × 10⁻¹⁹/[5.3]² = 9.10938356 × 10⁻³¹ × 9.8

q =  8.9271 × 10⁻³⁰ / 5.1262 × 10⁻¹¹

q = 1.7415 × 10¹⁹ C

Therefore the charge required for this to happen is 1.7415 × 10¹⁹ C

[1.43996 × 10⁹ × q] / 29.09 =  8.92719 x 10⁻³⁰

1.43996 × 10⁹ × q  = 2.5969 × 10⁻²⁶

q = 2.5969 × 10⁻²⁶ / 1.43996 × 10⁹

q =  

This question is incomplete, the complete question is;

A parallel-plate capacitor is made from two aluminum-foil sheets, each 3.0 cm wide and 5.00 m long. Between the sheets is a mica strip of the same width and length that is 0.0225 mm thick. What is the maximum charge?

(The dielectric constant of mica is 5.4, and its dielectric strength is 1.00×10⁸ V/m)

Answer: the maximum charge q is 716.85 μF

Explanation:

Given data;

with = 3.0 cm = 0.03

breathe = 5.0 m

Area = 0.03 × 5 = 0.15 m²

dielectric strength E = 1.00 × 10⁸

∈₀ = 8.85 × 10⁻¹²

constant K = 5.4

maximum charge = ?

the capacitor C = KA∈₀ / d

q = cv so c = q/v

now

q/v = KA∈₀ / d

q =  vKA∈₀/d = EKA∈₀

we substitute

q = (1.00 × 10⁸) × 5.4 × 0.15 ×  8.85 × 10⁻¹²    

q = 716.85 × 10⁻⁶ F

q = 716.85 μF

the maximum charge q is 716.85 μF

Answer:

3. is made of nucleotides