Table is in the picture. and will mark brainstest.
Here is the question
Based on the information in the table, which combination of materials would make the most conductive and best insulated wire?
A) A zinc wire with glass insulation
B) A copper wire with rubber insulation
C) A plastic wire with plastic insulation
D) An aluminum wire with plastic insulation​

Answer:

V = 411.43 V

Explanation:

The two forces as a result of each of the 2 charges are;

F1 = kq1•q/r

F2 = kq2.q/r

Where r = r/2 since we are dealing with potential difference at a point midway between the charges.

q1 = 5 nC = 5 × 10^(-9) C

q2 = 3 nC = 3 × 10^(-9) C

k = 9 × 10^(9) N.m²/C²

r = 35 cm = 0.35m

r/2 = 0.35/2

Thus;

F1 = (9 × 10^(9) × 5 × 10^(-9) × q)/(0.35/2)²

F1 = 1469.39q

F2 = (9 × 10^(9) × 3 × 10^(-9) × q)/(0.35/2)²

F2 = 881.63q

Net force acting midway is;

F_net = F1 + F2

F_net = 1469.39q + 881.63q

F_net = 2351.02q

Now, we know that formula for electric potential is;

V = kq/r

Thus ;

V = Fr/q derived from the earlier equation for force we used.

Where F is F_net.

V = 2351.02q × r/q

V = 2351.02r

Recall that we are dealing with midpoint and r = r/2

Thus;

V = 2351.02 × 0.35/2

V = 411.43 V

Answer:

дангггггггггггггггггггггггггггггггггггггггггггггг

Answer: D.

Explanation: I took the test

Answer:

Breathing and cellular respiration are complementary processes that enable the body to produce energy by taken in oxygen which is required for the chemicals contained in food to be broken down there by producing, energy, water and carbon dioxide. The breathing and cellular respiration process also enables the removal of the produced carbon dioxide finally through nose and/or mouth

Explanation:

In cellular respiration, glucose molecules in the presence of oxygen gas are broken down into carbon dioxide and water aerobically in living cells, to release energy and produce ATP as follows;

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

During breathing, oxygen is inhaled into the lungs from the atmosphere  and carbon dioxide is exhaled from the longs into the atmosphere, such that the carbon dioxide produced during cellular respiration is transported out of the body through the veins respiratory system, from where is passes out through the nose, while oxygen used in cellular respiration comes from breathing in oxygen into the respiratory system

The oxygen is then transported to the cells through by blood in the blood vessels of the circulatory system to the cells, where the cells use the oxygen for cellular respiration to release energy.

Answer:

Geomagnetic Field

Explanation:

Answer:

because they are underaged and prob dont care and also the gov thinks that the youth cant make a reasonable decision for them selves for sum like that and the media influnces them to by saying whats going on and who supports who

Answer:

The SI unit of time is second (s) and temperature is Kelvin (K)

Explanation:

hope it is helpful to you

According to the equations of motion, the time taken to reach the ground is 5 seconds.

Using;

s = ut + 1/2gt^2

s = distance

u = initial velocity

t = time taken

g = acceleration due to gravity

Note that u = 0 m/s since the object was dropped from a height

Substituting values;

125 = 1/2 × 10  × t^2

125 = 5t^2

t^2 = 125/5

t^2 = 25

t = 5 secs

Velocity on reaching the ground is obtained from

v = u + gt

Where u = 0 m/s

v = gt

v = 10 × 5

v = 50 m/s

At half the time it takes to reach the ground;

s =  ut + 1/2gt^2

Where u = 0 m/s

s =  1/2gt^2

s = 1/2  × 10  × (2.5)^2

s = 31.25 m

Learn more about equation of motion: https://brainly.com/question/8898885

Answer:

(i) time taken by the ball to reach the

ground is 5 sec.

(ii) velocity of the ball on reaching the

ground is 50 m/s.

(iii) the height of the ball at half the time it

takes to reach the ground is 31.25 m.

Step-by-step explanation:

(i) time taken by the ball to reach the

ground

[tex]\longrightarrow{\sf{ \: \: s= ut + \dfrac{1}{2} a{(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: 125= 0 \times t + \dfrac{1}{2} \times 10 \times {(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: 125= 0 + \dfrac{10}{2} \times {(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: 125= 0 + 5\times {(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: 125= 5\times {(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = \dfrac{125}{5}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = \dfrac{ \cancel{125}}{\cancel{5}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = 25}}[/tex]

[tex]\longrightarrow{\sf{ \: \: t = \sqrt{25} }}[/tex]

[tex]\longrightarrow \: \: {\sf{\underline{\underline{\red{ t = 5 \: sec}}}}}[/tex]

Hence, the ball taken 5 sec to reach the ground.

[tex]\begin{gathered}\end{gathered}[/tex]

(ii) velocity of the ball on reaching the

ground

[tex]\longrightarrow{\sf{ \: \: {v}^{2} - {u}^{2} = 2as}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {v}^{2} - {0}^{2} = 2 \times 10 \times 125}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {v}^{2} = 20 \times 125}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {v}^{2} = 2500}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {v} = \sqrt{2500} }}[/tex]

[tex]\longrightarrow{\sf{ \: \: \underline{\underline{ \red{{v} = 50 \: m/s }}}}}[/tex]

Hence, the velocity of ball is 50 m/s.

[tex]\begin{gathered}\end{gathered}[/tex]

(iii) the height of the ball at half the time it

takes to reach the ground.

[tex]\longrightarrow{\sf{ \: \: s= ut + \dfrac{1}{2} a{(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= 0 \times \dfrac{5}{2} + \dfrac{1}{2} \times 10 \times { \left( \dfrac{5}{2} \right)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= 0 + \dfrac{10}{2} \times { \left( \dfrac{5}{2} \times \dfrac{5}{2} \right)}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times { \left( \dfrac{5 \times 5}{2 \times 2} \right)}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times { \left( \dfrac{25}{4} \right)}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times \dfrac{25}{4}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10 \times 25}{2 \times 4}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{250}{8}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{\cancel{250}}{\cancel{8}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {\underline{\underline{\red{s= 31.25 \: m}}}}}}[/tex]

Hence, the height of the ball to reach the ground is 31.25 m.

[tex]\underline{\rule{220pt}{3.5pt}}[/tex]

Answer:

When the image distance is positive, the image is on the same side of the mirror as the object, and it is real and inverted. When the image distance is negative, the image is behind the mirror, so the image is virtual and upright.

Explanation:

Answer:

26.02 ml

Explanation:

0.055(473.0) = 26.02 ml

Answer:223.46 MJ

Explanation:

Given

The thermal conductivity of brick wall is [tex]k=1.16\ W/m.^{\circ}C[/tex]

Cross-section of Wall [tex]A=5\m \times 7\ m[/tex]

time period [tex]t=17.2\ h=17.2\times 60\times 60=61,920\ s[/tex]

Inside temperature [tex]T_i=24^{\circ}C[/tex]

Outside temperature [tex]T_o=8^{\circ}C[/tex]

Heat transfer through the bricks

[tex]\dot{Q}=kA\dfrac{dT}{dx}[/tex]

[tex]\dot{Q}=1.16\times 35\times \dfrac{16}{0.18}\\\\\dot{Q}=3608.88\ W[/tex]

Heat flow for 17.2 h

[tex]Q=3608.88\times 61,920=223.46\ MJ[/tex]

Solution :

As the charge is stationary, hence

[tex]$F_m= qvB \sin \theta$[/tex]

[tex]$F_m=0$[/tex]

Hence, no torque at all.

When the charge is moving in positive x direction and the field will be in the negative y direction outside the bar, then :

[tex]$F = q(V \hat i \times B(- \hat j))$[/tex]

    [tex]$= -qV B (\hat i \times \hat j)$[/tex]

    [tex]$=qVB(- \hat k)$[/tex]

Hence, the force have direction [tex]$(- \hat k)$[/tex].

When instead of charge, an iron nail is used, then there will be induced magnetic field in the soft iron. The nature of the pole induced will be opposite near tot he bar. That is the north pole will be induced near the south pole and vice versa. That is why whichever be the pole of magnet closest to iron will be attracted by iron.

Answer:

C

Explanation:

Copper is a conductor because its valence electrons can move freely from atom to atom.

Answer:

Two possibities: Increase in pressure or decrease in temperature.

Explanation:

There are two possibilities under the assumption that mass of the gas is conserved and, consquently, the amount of moles is also conserved, a reduction in the volume of the gas leads to an increase in pressure (Boyle's Law) and a decrease in temperature (Gay-Lussac's Law)

Answer:

he word that musicians use for frequency is pitch. The shorter the wavelength, the higher the frequency, and the higher the pitch, of the sound. In other words, short waves sound high; long waves sound low. ... In other words, it sounds higher

Explanation:

Measuring the heat of chemical reactions or physical changes.

Answer:

1st: Radiation

2nd: Conduction

3rd: Convection

Explanation:

I actually learned this before in school. Yay

Answer:

35

Explanation:

angle of incidence equals angle of reflection

Answer:

1. sand and water

2. suspension

mark me as brainliest plz

Answer: Medial rotation

Lateral rotation

Supination

Pronation

Opposition

Explanation:

Medial rotation can be defined as the rotation of any of the body part towards the middle axis of the body. For example, movement of leg bones so that the toes are pointed towards inward.

Lateral rotation is the movement of the body parts or bones away from the middle axis of the body. For example. outward circle created by the upper limbs directed outwards.

Supination is the rotation of the forearm in such a way so that the palm is directed upwards so that hand can receive money or hand can slap a person.

Pronation is the downward motion of hand to put things down.

Opposition is the movement of the bones of the fingers the metacarpals which allow the thumb to touch the fingertips.

Answer:

Answer is B.

Because the wavelength of infrared is shorter than microwave radiation

Answer:

this one is for your egg drop question

first question -

Use this worksheet to design your device and record your data. You can then use this form to help you  write your lab report.  

Height of egg drop: _5ft._

__________________________________________________________

Q2:

Ideas for Prototype Design

Teepee, large cube , small cube

__________________________________________________________

Q3:

Preliminary Sketches (attach separate paper if needed)

Option A: teepee

__________________________________________________________

Q4:

Advantages:                                           Disadvantages:  

● fully covered                  ● egg might crack

●  could stand higher distances    ●egg will most likely bounce around    around but not crack  but most likely to crack

__________________________________________________________

Q5:

Option B: large cube

Option C: smaller cube

__________________________________________________________

Q6:

more advantages and disadvantages

Advantages: Disadvantages:  

● egg will be tightly secured so nothing bounces around

●  egg might crack depending on the impact to the floor

__________________________________________________________

Q7:

Which of the three designs will you move forward with? Explain your reasoning for selecting this design.

I think i'm going to be moving forward with the teepee design

__________________________________________________________

Q8:

Building the Prototype  

What modifications, if any, did you make to the basic design during the construction process?

I made it a little smaller than the original design

__________________________________________________________

Q9:

Predictions  

Will your device cushion the egg? How will your device do this?

I think it will cushion the design if i put the plastic bag in with the egg it should prevent it from moving around to much

__________________________________________________________

Q10:

Will your device increase the time it takes for the egg to impact the ground? How will your device do this?

I think the extra weight added to the design might affect it by speeding up the process down to the floor

__________________________________________________________

Q11:

Observations  

Record your observations and the results of the experimental tests of your device below.

First i tried the egg without the plastic bag and it cracked so i made the design smaller and added the plastic bag this time

__________________________________________________________

Q12:

Evaluating Your Prototype  

What worked well? I would say definitely the plastic bag keeping the egg in place

__________________________________________________________

Q13:

Which features can be improved upon? The structure itself as in where the string and tape were

__________________________________________________________

Q14:

Suggestions  

How could the design of this device be improved? More balance i guess because the egg would move alot without the bag

__________________________________________________________

Q15:

Why would this change be an improvement? What force or momentum principle is this improvement  based on? If the egg had more balance then it would have a less chance of cracking i think this is a type of impulse toward the ground bc of the egg’s weight

__________________________________________________________

Q16:

Sketch of Final Design  

Draw a well-labeled sketch of the final design.

( i provided it :) )

okie peace!

Answer

slope

Explanation:

Answer:

6544.07 J

Explanation:

From the question given above, the following data were obtained:

Distance (d) = 15 m

Force (F) = 628 N

Angle (θ) = 46°

Workdone (Wd) =?

The work done can be obtained by using the following formula:

Wd = Fd × Cos θ

Wd = 628 × 15 × Cos 46

Wd = 9420 × 0.6947

Wd = 6544.07 J

Therefore, the workdone is 6544.07 J

Answer:

[tex]55.64\ \text{nm}[/tex]

Explanation:

[tex]\lambda[/tex] = Wavelength falling on film = 520 nm

n = Refractive index of film = 2.62

T = Thickness of film

m = Order

We have the relation

[tex]2T=\dfrac{m\lambda}{n}\\\Rightarrow T=\dfrac{m\lambda}{2n}\\\Rightarrow T=\dfrac{m\times 520}{2\times 2.62}\\\Rightarrow T=99.24m[/tex]

The thickness should be greater than 1036 nm. This means [tex]m=11[/tex]

[tex]T=99.24\times 11=1091.64\ \text{nm}[/tex]

Thickness of the film to be added would be

[tex]\Delta T=1091.64-1036=55.64\ \text{nm}[/tex]

Thickness of the film to be added is [tex]55.64\ \text{nm}[/tex].

Answer:

Explanation:

The ray of light is passing from high refractive index medium to low refractive index medium so condition for cancellation of reflected light is as follows .

2μt = (2n+1) λ/2

where μ is refractive index of the medium , t is thickness , λ is wavelength of light and n is a integer .

Putting n = 10

2x 2.62 x t = 21 x 520 / 2 nm

5.24 t = 5460 nm

t = 1042 nm

Thickness required to be added

= 1042 - 1036 = 6 nm .

Answer: The seismic waves are useful for the oil and gas exploration beneath the earth crust.

Explanation:

The seismic waves are sent beneath the earth crust to determine the location of fossil fuels like petrol, and natural gas. These seismic waves bound back and their pattern of reflection and refraction is recorded by using a receiver that is a geophone or can be a hydrophone (in water). The seismic waves bounce back indicating towards the reservoir of fossil fuel exhibit a characteristic pattern that can help in tracing the location of the fossil fuel.

Answer:

1. Amplitude Modulation

Explanation:

AM is an acronym for Amplitude Modulation and it's refers to a process that is typically used for coding sounds such as voices and music for transmission from one point to another.

On the other hand, FM is an acronym for frequency modulation used for the propagation and transmission of sound waves.

Basically, the two forms of modulation are used for broadcasting in radio transmission.

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.

Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.

Answer:

the image can be rather real or virtual