Answer:
51 miles/hour
Explanation:
Talia is on a road trip with some friends. in the first 2 hours, they travel 100 miles. then they hit traffic and go only 30 miles in the next hour. the last hour of their trip, they drive 75 miles. calculate the average speed of talia’s car during the trip. give your answer to the nearest whole number.
The average speed would be 51 miles/hour.
The average speed of a moving object is defined as the total distance traveled relative to the total time taken fro the journey. Mathematically, it is given as:
total distance traveled/total time taken.
In this case;
Total distance traveled = 100 + 30 + 75 = 205 miles
Total time taken = 2 + 1 + 1 = 4 hours
Therefore;
Average speed = 205/4 = 51.25 miles/hour
To the nearest whole number = 51 miles/hour
A car accelerates from 10m/s to 20m/s over a distance of 80m. What is its acceleration?
Answer:
0.125m/s^2
Explanation:
20-10=10
10 divided by 80=0.125m/s^2
The average velocity of the car is 15 m/s. The time taken to travel over the distance with this velocity is 5.3 seconds. Then the acceleration of the car is 1.8 m/s².
Wat is acceleration ?Acceleration is a physical quantity measuring the rate of change in velocity of a moving object. Like velocity, acceleration is a vector quantity having magnitude and direction.
Acceleration is the ratio of change in velocity to the change in time.
a = Δv/Δt
Given, the car is accelerating from 10 to 20 m/s. Hence, it travelled with average velocity of 15 m/s over the distance of 80 m.
Then , time taken = distance/velocity
t = 80 m/15 m/s = 5.3 s
Acceleration = Δv/t = (20 -10 m/s) /5.3 s = 1.8 m/s².
Therefore, the acceleration of the car is about 1.8 m/s².
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Wil-E-Coyote drops a bowling ball off a cliff to try to catch the Roadrunner. The cliff is
132 m high. How many seconds does it take the ball to fall to the ground?
Answer:
t = 5.19 s
Explanation:
We have,
Height of the cliff is 132 m
It is required to find the time taken by the ball to fall to the ground. Let t is the time taken. So, using equation of kinematics as :
[tex]y=ut+\dfrac{1}{2}gt^2\\\\\text{since}\ u=0\\\\y=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2y}{g}}\\\\t=\sqrt{\dfrac{2\times 132}{9.8}}\\\\t=5.19\ s[/tex]
So, it will take 5.19 seconds to fall to the ground.
What observation about light supported Einstein’s theory?
Answer:
Explanation:
Do you mean the theory that space-time is defined by what's in it? And that mass warps space-time?
There are many instances where his observation turned out to be correct. The most popular one is the phenomena of gravitational lensing. We can see the light from stars that are actually behind the sun. The huge gravity of the sun bends space-time and this also bends light. We use gravitational lensing alllll the time when trying to see very distant stars or galaxies.
Answer:
The Sun bent the light from a star. This bending made the star appear in a slightly different position from its actual position. This observation supported Einstein’s theory.
Explanation:
This is the answer on Edmentum! :)
If kinetic energy of a body is increased by 125%, the percentage increase in Momentum is?
Answer:
50 %
Explanation:
It's Fifty percent
what is the defination o
f temperature
Answer: The degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.
Which two laws were discovered by Antoine Lavoisier and Joseph Proust
Answer:
Joseph proust's law of difinite composition
Law of conservation of mass
Explanation:
Dalton's law of multiple proportions is part of the basis for modern atomic theory, along with Joseph Proust's law of definite composition (which states that compounds are formed by defined mass ratios of reacting elements) and the law of conservation of mass that was proposed by Antoine Lavoisier.
Answer:
law of conservation of mass
law of definite proportions
Explanation:
A 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees. Ignoring friction, how fast is it going when it reaches the bottom of the hill?
Answer:
10.2 m/s
Explanation:
Using conservation of energy:
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)
v = 10.2 m/s
The velocity when car reaches the bottom of the hill is 10.2 m/s.
What is mechanical energy?The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.
M.E = KE +PE
M.E = ½ mv² + mgh
where g is the acceleration due to gravity, v is the velocity, m is the mass and h is the height of the object.
Given is a 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees.
Using conservation of energy principle, we have
PE = KE
mgh = ½ mv²
v = √(2gh)
Substitute the values, we get
v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)
v = 10.2 m/s
Thus, the velocity when car reaches the bottom of the hill is 10.2 m/s.
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Use the worked example above to help you solve this problem. An Alaskan rescue plane drops a package of emergency rations to stranded hikers, as shown in the figure. The plane is traveling horizontally at 39.0 m/s at a height of 1.50 102 m above the ground. (a) Where does the package strike the ground relative to the point at which it was released? (b) What are the horizontal and vertical components of the velocity of the package just before it hits the ground? horizontal and vertical (c) Find the angle of the impact.
Answer:
(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane
(b) The horizontal component = 39.0 m/s
The vertical component = 171.55 m/s
(c) The angle of impact is 77.19°
Explanation:
The parameters given are;
Velocity of the plane, vₓ = 39.0 m/s
Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m
(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;
h = u·t + 1/2×g×t²
Where:
g = Acceleration due to gravity = 9.81 m/s²
u = Initial vertical velocity = 0 m/s
Hence;
1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²
∴ t = √(1500/4.905) = 17.49 s
The horizontal distance the package travels before landing = 17.49 × 39 ≈ 682 m
The package lands 682 meters horizontally ahead from the point the package was dropped from the plane
(b) The vertical velocity, [tex]v_y[/tex], of the package just before landing is given by the relation;
[tex]v_y[/tex]² = u² + 2·g·h
u = 0 m/s
∴ [tex]v_y[/tex]² = 0 + 2×9.81×1500 = 29430 m²/s²
[tex]v_y[/tex] = √29430 = 171.55 m/s
Hence the horizontal component = 39.0 m/s
The vertical component = 171.55 m/s
(c) The angle of impact, θ, is given as follows;
[tex]tan \theta = \dfrac{v_y}{v_x} = \dfrac{171.55}{39.0 } = 4.4[/tex]
∴ θ = tan⁻¹(4.4) = 77.19°.
if the resistance of a car headlight is 15 ohm and the current through it is 0.60, what is the voltage across the headlight?
Answer:
9 volts (assuming 0.60 is in Amperes)
Explanation:
Recall that Ohms law can be expressed as
V = IR, where
V = voltage,
I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)
R = resistance (given as 15 ohm)
substituting the above values into the formula
V = IR
V = (0.6)(15)
V = 9 Volts
Mass is the amount of what
Answer:
Mass is the amount of matter in a substance.
Explanation:
The basic SI unit for mass is the kilogram (kg).
how many chromosomes does an elephant's egg cell have ?
Answer:
Diploid is often noted as 2N where N is the number of chromosomes. So in humans 2N=46. During sexual reproduction, the sex cells of parent organisms unite with one another and form a fertilized egg cell. In this situation, each sex cell is a gamete.
Explanation:
How can one find the mechanical advantage of a pulley?
Answer:
To calculate the mechanical advantage of a pulley you simply have to count the number of rope sections that support whatever object you are lifting (not counting the rope that is attached to the effort)
Example:
For example, in a one pulley system the MA is 1. In a two pulley system the MA is 2. The more compound the pulley is the easier the load is to lift. If you were lifting a 600kg object with 2 pulleys you would have to use enough effort to pull 300kg to lift the 600kg object! Therefore your mechanical advantage would be 2 (600/300).
MA= load/effort OR number of rope sections
How did Einstein’s and Newton’s theories differ in terms of explaining the cause of gravity?
Newton's law of universal gravitation doesn't say anything about the cause of gravity.
Einstein's theory of relativity does.
What is the force experienced when a 5.0 kg mass is accelerated at 7.5 m/s??
Answer:
F = 37.5 N
Explanation:
It is given that,
Mass of the object is 5 kg
Acceleration of the object is 7.5 m/s²
We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,
F = m
[tex]F=5\times 7.5\\\\F=37.5\ N[/tex]
So, the force acting on the object is 37.5 N.
Question 3 of 5
2 Points
Which term refers to a transfer of thermal energy between objects?
A. Potential energy
B. Kinetic energy
C. Heat
D. Temperature
SUSMIT
Answer:
Explanation:
Kinetic energy
A horse runs for 15 seconds to the south at a speed of 12 m/s. What is the
displacement of the horse in this time?
A. 180 m south
B. 150 m south
C. 150 m
D. 180 m
Answer: 180 m south
Explanation:
The displacement of the horse in this time is 180 m south. The correct option is A.
What is displacement?The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.
Velocity is the time rate of change of displacement with time.
Given is a horse runs for 15 seconds to the south at a speed of 12 m/s. So, the displacement is
Displacement = Speed x Time
Put the values, we get
Displacement = 12 m/s x 15s
= 180 m
Thus, the displacement of the horse in this time is 180 m south.
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can someone help what are the common branches of physics
Answer: Dear Buddy ,the common brnches os physics are given below:
Explanation:
Mechanics
Classical physics
Modern physics
Thermodynamics
Electricity
Magnetism
Geo physics
Plasma physics
Optics
Sound and oscillation
Electronics
Chemical physics
Engineering physics
Solid state physics
Quantum physics
Nuclear physics
Particle physics
Bio physics
Astrophysics
Condensed matter physics
hope it helps
Answer:
Engineering is one of branches that uses physics mainly the most
Explanation:
as for engineering requires mathematics and physics principles in their everyday routine to calculate and measure accordingly to manufactur a product.
4 answers. Anyone know?
Answer:
lift
weight
thrust
air resistance
Explanation:
plz mark me as brainliest
Answer: Upthrust, lift, air resistance, and thrust
Explanation:
All of these 4 elements are taken into account during the design and creation of a plane.
GENTE ME AJUDEM NESTA QUESTÃO POR FAVOR, TENHO PROVA ONLINE AMANHÃ! "Um sonar de um navio de pesca localizou um cardume de sardinhas a 300 m de profundidade. Sabendo que a velocidade de propagação do som na água tem o valor de 1500 m/s, calcula o tempo que decorre desde a emissão dos ultra-sons e a sua receção no navio." Por favor!
Answer:
The time between the emission of the wave and it's reception was 0.4 seconds.
Explanation:
The sound wave emitted by the sonar traveled from the boat to the fishes and came back, therefore the distance of it's total route is twice the distance from the boat to the fishes. We can apply the average speed formula in order to solve this problem, this is done below:
[tex]\text{speed} = \frac{\text{distance}}{\text{time}}[/tex]
We were given the distance traveled by the wave and it's speed, therefore we can solve for the time:
[tex]\text{time} = \frac{\text{distance}}{\text{speed}}\\\\\text{time} = \frac{(2*300)}{1500}\\\\\text{time} = \frac{600}{1500} = 0.4 \text{ s}[/tex]
The time between the emission of the wave and it's reception was 0.4 seconds.
describe three factors that influence the location of rural settlement
Explanation:
presence of food, water ,etc
Explanation:
here is five all you have to do is just pick
At what wavelength would a star radiate the greatest amount of energy if the star has a surface temperature of 60,000 K?
Answer:
[tex]\lambda=4.81\times 10^{-8}\ m[/tex]
Explanation:
We have,
The surface temperature of the star is 60,000 K
It is required to find the wavelength of a star that radiated greatest amount of energy. Wein's displacement law gives the relation between wavelength and temperature such that :
[tex]\lambda T=2.89\times 10^{-3}[/tex]
Here,
[tex]\lambda[/tex] = wavelength
[tex]\lambda=\dfrac{2.89\times 10^{-3}}{60000}\\\\\lambda=4.81\times 10^{-8}\ m[/tex]
So, the wavelength of the star is [tex]4.81\times 10^{-8}\ m[/tex].
tree
5. A carge pinnore camera has a magnification of 0.050 for a
located 5.on from the camera. Klhat is the size of the image
screen?
son
the
Solution
Answer:
Explanation:
Size of the image: 2 cmIn order to calculate the size of the image, we can use the following proportion:wherep = 80 m is the distance of the tree from the pinholeq = 20 cm = 0.2 m is the distance of the image from the pinhole = 8 m is the heigth of the object is the height of the imageBy re-arranging the proportion, we find2) Magnification: 0.0025The magnification of a camera is given by the ratio between the size of the image and the size of the real object:so, in this problem we have
Which of the following machines most likely has the greatest efficiency?
a
A. Airplane
B. Automobile
C. Bicycle
D. Human body
Please give me concept to solve this.
Answer:
The difference in tension, between adjacent sections of the pull cable at the given conditions is 17.701 kN
Explanation:
We take the cars as moving upwards such that the resultant pulling force on the car, F, along the cable is given by the relation
[tex]F_{car}[/tex] = Upward tension force, [tex]Tension_{(upwards)}[/tex] - Downward tension force, [tex]Tension_{(downwards)}[/tex] - Component of the weight of the car along the taut cable
The parameters given are;
Mass of car, m = 2750 kg
Angle of inclination of taut cables, θ = 35°
The upward acceleration of the car, a = 0.81 m/s²
Given that the weight is acting vertically downwards, we have;
Component of the weight of the car along the taut cable = m × g × sin(θ)
∴ Component of the weight of the car along the taut cable = 2750 × 9.81 × sin (35°) = 15473.66 N
We therefore have;
[tex]F_{car}[/tex] = [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] - 15473.66 N
[tex]F_{car}[/tex] = m × a = 2750 × 0.81 = [tex]T_{upwards}[/tex] - [tex]T_{downwards}[/tex] - 15473.66
∴ [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] = 2750 × 0.81 + 15473.66 = 17701.16 N
Hence the difference in tension, [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] between adjacent sections of the pull cable if the cars are at the maximum permissible mass and are being accelerated up the incline = 17701.16 N or 17.701 kN.
A car starts from rest and develops an acceleration of 2 m/s2. If the distance covered by the car during its motion is 100m, what is the final velocity attained by the car?
Answer:
20
Explanation:
because I am always right yo bro be like me
An object rotates describing a horizontal circumference when subjected to a centripetal force F. What centripetal force will act on the object if the radius of the circle is doubled and the kinetic energy of the object is halved? A) F/4 B) F/2 C) F D) 4F please explain this to me : (
Answer:
Option A: F/4
Explanation:
Centripetal force, [tex]F = \frac{mv^{2} }{r}[/tex]
Where v = speed
r = radius
Since Kinetic Energy, [tex]E_{k} = 0.5 mv^{2}[/tex]
Writing centripetal force in terms of kinetic energy, [tex]F = \frac{2 E_k}{r}[/tex]
If the initial radius of the circle, r₁ =r
The doubled radius, r₂ = 2r
If the initial kinetic energy, [tex]KE_1 = E_{k}[/tex]
The halved kinetic energy, [tex]KE_2 = 0.5E_{k}[/tex]
Therefore, the new Centripetal force becomes:
[tex]F_{2} = \frac{2(0.5 E_k)}{2r} \\F_{2} = \frac{0.5 E_k}{r}\\F_{2} =\frac{1}{4} * \frac{2 E_k}{r}\\Since, F = \frac{2 E_k}{r} \\F_{2} =\frac{1}{4} * F\\F_{2} =\frac{F}{4}[/tex]
A wire is placed between the poles of a horseshoe magnet. There is a current in the wire in the direction shown, and this causes a force to act on the wire.
suppose that g (x) equals f (x + 1) - 3 which statement best compares the graph of g (x) with the graph of f (x)
Answer:
The graph of G(x) is the graph of F(x) shifted 1 unit to the left and 3 units down.
Explanation:
f(x + q) which is left q units
f(x - q) which is right q units
f(x) + q which is up q units
f(x) - q which down q nits
and
G(x) = F(x + 1) - 3
So,
f(x + 1) shifts to left 1 unit
f(x) - 3 shifts to down 3 units
So, the correct answer is B.
The graph of G(x) is the graph of F(x) shifted 1 unit to the left and 3 units down.
drawing is a form of
Answer:
visual art in which one uses to mark drawing and express feelings
Explanation:
In my own opinion. Hope it helps.
The gravitational force between two students sitting beside each other on Earth is
Answer:
Fgrav. = GM1×M2/R2
Explanation:
Gravitational force is mostly related
to planetary bodies by Newton's law of gravitation which states that the gravitional force is proportional to the product of the mass of the object and inversely proportional to the square of the distance between them.
Hence in this case the Gravitational force,
Fgrav. = GM1×M2/R2
M1 and M2 are the mass of the two students and R is their distance apart
G is a constant known as gravitational constant.6.67408 × 10-11 m3/kgs2