The electric field for 100 cm is 1.62 MN/C
Length of the straight filament = (100cm) (1m/100cm) = 1m
Electric field for the straight conductor = [tex]E = \frac{2k_{e} \lambda}{r}[/tex]
E = [2(8.99 × 10^9 N·m^2/C^2)(90.0 × 10^-6 C/m)] / 1 m
E = 1.62 MN/C
The electric field is directed radially inward, toward the filament.
The electric field is a force produced by a charge near its surroundings. This force is exerted on other charges when brought in the vicinity of this field. SI unit of the electric field is N/C (Force/Charge).
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Calculate the wavelength of an orange light wave with a frequency of 5.085 x 10^14 Hz. The speed of light is 3.0 x 10^8 m/s.
^ meaning a power
Answer:
5.9 x 10⁻⁷m
Explanation:
Given parameters:
Frequency = 5.085 x 10¹⁴Hz
Speed of light = 3.0 x 10⁸m/s
Unknown:
Wavelength of the orange light = ?
Solution:
The wavelength can be derived using the expression below;
wavelength = [tex]\frac{v}{f}[/tex]
v is the speed of light
f is the frequency
wavelength = [tex]\frac{3 x 10^{8} }{5.085 x 10^{14} }[/tex] = 5.9 x 10⁻⁷m
24. A soccer ball is kicked straight up into the air with a velocity of 10 m/s. How much time does it take the ball to reach its maximum height? (g = 10 m/s^2)
A 2 sec
B 100 sec
C 1.4 sec
D 1 sec
Answer:
D. Time t = 1 [s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}=v_{o}-g*t[/tex]
where:
Vf = final velocity = 0 (when the ball reaches the maximum height its elevation won't be increased since the velocity is zero)
vi = initial velocity = 10 [m/s]
g = gravity acceleration = 10 [m/s²]
t = time [s]
Now replacing:
[tex]0 = 10-10*t\\10 = 10*t\\t = 1 [s][/tex]
All battery powered devices, run off of what type of power?
Answer:
Electrical energy
Explanation:
electrical energy Essentials. A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.
energy released in a chemical reaction comes from ?
A ford F-250 pulls a 1000-kg car with a net force of 2000 N. What is the acceleration of the car A=F/m
Answer:
2ms^2
Explanation:
A = 2000 divided by 1000
A= 2
what is work please give ans
physical properties of light, such as its amplitude and wavelength, and the human perception of color
The study of the physical properties of light, such as its wavelength and amplitude, and the human perception of color is called psychophysics. It comprises two major areas: discrimination and absolute.
The study of wavelength and amplitude, interaction between physical stimuli and their consequential effects such as perceptions and sensations is called psychophysics.
This concept is applied in psychophysics tasks where extensive research and studies are performed on sensory and other visual information.
To put it in simple words, psychophysics is vital for measuring the perception of a subject through stimulus detection experiments.
Stimuli detection is done either through the method of limits, adjustment technique, or constant stimuli method.
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Newton’s laws of motion
Mendeleev recognized the periodic law. True or False
Answer: True
Explanation:
A 33 kg box sits at rest on a tabletop.
Draw and clearly label all the forces acting on the box;
Calculate the normal force.
Answer:
323.4N
Explanation:
Given parameters:
Mass of the box = 33kg
Unknown:
Normal force on the body = ?
Solution:
The normal force of a body is the vertical force the body exerts on another body.
It is expressed as;
Normal force = mass x acceleration due to gravity
Acceleration due to gravity = 9.8m/s²
Normal force = 33 x 9.8 = 323.4N
A student exerts a force of 35 newtons to move a cart loaded with lab equipment to the prep room 20 meters. If it takes the student 10 seconds to push the cart to the prep room, how much power did the student use?
a) 700 W
b) 2.5 Nm
c) 62.5 J/s
d) 70 W
huhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
A man applies a force of 500 N to push a truck 10 m down the street. How much work has been done? Please answer!
Answer:
5000 J
Explanation:
W=F*D
W=500N*10m
w=5000 J
When a man applies a force of 500 N to push a truck 10 m down the street. Then the work of 5000 J has been done.
What is Work ?Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J). i.e. Work(W) is force(F) times displacement(s). W=F× s When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule.
Writing for it's dimension, W=F× s
Force has dimension [L¹ M¹ T²]
Displacement has dimension [L¹]
multiplying both the dimensions Force and Displacement we get, dimension of Work [L² M¹ T²].
Given,
F = 500 N
s = 10 m
Work = Fs = 500×10 = 5000 J
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What limits the amplitude of motion of a real vibrating system that is driven at one of its resonant frequencies?
To find limits of the amplitude of motion of real vibrating system that is driven at one of its resonant frequencies, Here the damping of vibrations turns the energy of vibration into internal energy.
A football is kicked at
a 51.0° angle, and hits the
ground 38.7 m away. What
was its initial velocity?
(Unit = m/s)
The correct answer is 19.7 m/s.
Range is the height of the projectile when it reaches a vertical velocity of zero; after that, gravity will take over and quicken the object's descent. The projectile range, which is determined by the object's initial velocity, is the horizontal displacement of the object projected.
Only when one force is applied at the start of the trajectory does projectile motion occur; thereafter, gravity is the only resistance. A projectile launched under specified beginning circumstances will have a range in physics. Assuming a flat Earth with a consistent gravity field and no air resistance may make it more predictable.
Range R = 38.7 m
Acceleration due to gravity g =9.8 m/s
Launch angle θ = 51
Range of the projectile is given by
R = [tex]u^2[/tex] Sin2θ / g
[tex]u^2[/tex] = gR/ Sin 2θ
u = √gR/ Sin 2θ
u = √ 9.8 × 38.7 / Sin ( 2 × 51)
u = 19.7 m/s.
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Two cats jump off a roof that is 23m off the ground. Cat A jumps directly up with a velocity of 7m/s, and cat B jumps directly down with a velocity of 7m/s. How far up does cat A go? How fast does cat A go just before it hits the ground? How fast does cat B go just before it hits the ground? How much longer is cat A in the air than cat B?
(a) The height reached by cat A is 2.5 m.
(b) The speed of cat A before it hits the ground is 36.4 m/s.
(c) The speed of cat B before it hits the ground is 22.39 m/s.
(d) The time spent in air by cat A than cat B is 1.43 seconds.
Time of motion of cat AThe time of motion of cat A is calculated as follows;
h = vt - ¹/₂gt
-23 = 7t - 4.9t²
4.9t² - 7t - 23 = 0
solve the quadratic equation using formula method;
a = 4.9, b = -7, c = - 23
t = 3.0 seconds
Time of motion of cat BThe time of motion of cat B is calculated as follows;
h = vt - ¹/₂gt
23 = 7t + 4.9t²
4.9t² + 7t - 23 = 0
solve the quadratic equation using formula method;
a = 4.9, b = 7, c = -23
t = 1.57 seconds
Height reached by cat Ah = u²/2g
h = (7²)/(2 x 9.8)
h = 2.5 m
Speed of cat A before it hits the groundv = u + gt
v = 7 + 3(9.8)
v = 36.4 m/s
Speed of cat B before it hits the groundv = u + gt
v = 7 + 1.57(9.8)
v = 22.39 m/s
Time spent in air by cat A than cat B
Time difference = 3 s - 1.57 s = 1.43 seconds
Thus, the height reached by cat A is 2.5 m.
The speed of cat A before it hits the ground is 36.4 m/s.
The speed of cat B before it hits the ground is 22.39 m/s.
The time spent in air by cat A than cat B is 1.43 seconds.
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Question 24 (2 points)
What is power? (2 points)
O a
O b
O c
Od
The magnitude of a force needed to move an object
How much work can be done in a given time
The distance over time that an object moves
The energy needed to create work
A rectangular tank is filled with water to a depth of 4m. Calculate the pressure at the bottom of the tank. PLEASEEE HELP!! IM BEGGING!!!! PLEASEEEEE
For this we have the hidrostatic equation:
[tex]\boxed{P = \rho gh}[/tex]
Being:
P = Pressure
ρ = Density of liquid (water) = 1000 kg/m
g = Gravity = 9,81 m/s²
h = Height = 4 m
Replacing acording formula:
[tex]\boxed{P = 1000 \ kg/m ^{3} * 9,81 \ m/s^{2} * 4 \ m}[/tex]
Resolving:
[tex]\boxed{P = 39240 \ Pa}[/tex]
Result:
The pression at the bottom is 39240 Pa.
In this illustration, the magnetic field is strongest
HELP ME PLS PLS PLS
1. Which is one characteristic of a SMART fitness goal?
A. Endurance
B. Intensity
C. Attainable
D. Believable
Answer:
I would say D. Believable. Sorry if its wrong.
Explanation:
Why does surface water disperse when touched with soap?
The end of the detergent molecule which attaches to fat (grease) repels water molecules. It is known as hydrophobic, meaning "water fearing." By attempting to move away from the water molecules, the hydrophobic ends of the detergent molecules push up to the surface. This weakens the hydrogen bonds holding the water molecules together at the surface. The result is a break in the surface tension of the water.
Answer:
In a soap-and-water solution the hydrophobic (greasy) ends of the soap molecule do not want to be in the liquid at all. Those that find their way to the surface squeeze their way between the surface water molecules, pushing their hydrophobic ends out of the water. This separates the water molecules from each other.
Explanation:
Radioisotopes often emit one or more types of radiation, including alpha particles, beta particles, and gamma rays. The distance the radiation travels through matter before being absorbed increases in order from alpha to gamma. Which statement describes the best radioisotope that can be used for radioisotope imaging and for radionuclide therapy?
A.It emits only gamma rays.
B.It emits only alpha particles.
C.It emits alpha and beta particles.
D.It emits beta particles and gamma rays.
The best radioisotope that can be used for radioisotope imaging and for radionuclide therapy is It emits beta particles and gamma rays.
What is and how does radiotherapy work?It is a treatment in which ionizing radiation (X-ray, for example) is used to destroy a tumor or prevent its cells from increasing. These radiations are not seen and during the application the patient does not feel anything. Radiation therapy can be used in combination with chemotherapy or other treatments.
in this case, the best radioisotope that can be used for imaging is radionuclide because It emits beta particles and gamma rays.
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Answer:
It emits beta particles and gamma rays.
Explanation:
What is one result of warming up your bod'y muscles before exercising
Which model correctly represents the product or products of the chemical reaction?
The model that correctly represents the product or products of the chemical reaction is the first one. Thus, the correct option for this question is A.
What is a Chemical reaction?A chemical reaction may be defined as a type of reaction in which one or more substances that are known as the reactants are considerably converted to one or more different substances that are known as the products.
In a chemical reaction, the molecules or atoms of the substance may always remain the same in the reactant or product. That is the mass of the chemical substance may always remain the same. While model 2 and 4 increases the mass of compound A in the given reaction. So, they are eliminated.
Option 3 is incorrect because when you get a product of any chemical reaction, it may never be separated automatically as described in option C.
Therefore, the model that correctly represents the product or products of the chemical reaction is the first one. Thus, the correct option for this question is A.
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A Smart Car, which has a mass of 1000 kg, is going 20 m/s. When it hits the barrier, it stops at a time of 0.5 seconds. What is the impulse on the car?
Answer:
Imp = 20000 [kg*m/s]
Explanation:
In order to solve this problem we must divide it into two parts. In the first part we must use the following equation of kinematics.
[tex]V_{f}=v_{i}-a*t[/tex]
where:
Vf = final velocity = 0 (the car stops)
Vi = initial velocity = 20 [m/s]
a = acceleration [m/s²]
t = time = 0.5 [s]
Acceleration is negative as the cart slows down as it stops.
[tex]0=20-a*0.5\\20=0.5*a\\a=40 [m/s^{2}][/tex]
The second part is the determination of momentum, which is defined as the product of force over a given time. But to determine the force we must use Newton's second law which tells us that the sum of the forces of a body is equal to the product of mass by acceleration.
∑F = m*a
[tex]F = 1000*40\\F = 40000[N][/tex]
Now the impulse or momentum
[tex]Imp = F*t\\Imp = 40000*0.5\\Imp=20000[kg*m/s][/tex]
Bonus: What is the velocity of an 8 kg lead shot-put if it has 484 J of energy? Type here to search e
Answer:
11m/s
Explanation:
Given parameters:
Mass of the lead shot = 8kg
Energy of the shot = 484J
Unknown:
Velocity of the shot = ?
Solution:
To solve this problem, we apply the kinetic energy formula;
K.E = [tex]\frac{1}{2}[/tex] m v²
m is the mass
v is the unknown
Now, insert the parameters and solve;
484 = [tex]\frac{1}{2}[/tex] x 8 x v²
484 = 4v²
v² = 121
v = 11m/s
Need quick response
Are my answers for 1-8 correct and if not what is the correct answer for the ones that are wrong and why?
Also need answers for 9 and 10 since I’m not sure what the answers are and I want an explanation for both of those.
Answer:
I'll give you all the answers, I know them all, I just did this. I need $1 via cas ap tho since it's hard
If a persons skin is dry she will experience more of a shock
Answer:
add lotion
Explanation:
What is the displacement of the object from 12 seconds to 16 seconds
Answer:
The displacement of the object is -8 m
Explanation:
Displacement
The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.
If the area is below the y-axis, then the displacement is negative. Otherwise is positive.
It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.
From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.
The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:
[tex]\displaystyle D = \frac{4*(-4)}{2}=-\frac{16}{2}=-8\ m[/tex]
The displacement of the object is -8 m
Three solid plastic cylinders all have radius 2.50cm and length 6.00cm. Find the charge of each cylinder given the following additional information about each one. Cylinder (b) carries charge with uniform density 15.0 nC/m² on its curved lateral surface only. Cylinder
By the charge density, the curved surface area of the cylinder charge is 0.141 nC.
We need to know about charge density to solve this problem. The charge density can be determined as
λ = Q / A
where λ is charge density, Q is charge and A is surface area.
The parameter given is the charge density and the solid cylinder shape which are :
λ = 15 nC/m²
r = 2.5 cm = 0.025 m
L = 6.0 cm = 0.06 m
Find the curved surface area of cylinder
A = 2πrL
A = 2π. 0.025. 0.06
A = 9.43 x 10¯³ m²
Find the charges
Q = λ x A
Q = 15 x 9.43 x 10¯³
Q = 0.141 nC
Hence, the curved surface area of the cylinder charge is 0.141 nC.
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Which requires more work: lifting a 70 kg sack vertically 2 m or lifting a 35 kg sack vertically 4 meters?
Answer:
ADD ANSWER 5 PTS?
Explanation:
ME : Seriously
BRAINLY: 5 PTS!
Answer:
they require the same amount of work
Explanation:
the formula for work is
W=Fnet*Displacement
and Fnet =m*a
a=9.81 m/s^2
Which gives us
W=ma*d
The set up would be;
(35kg*9.81m/s^2)*4 m=W
(70kg*9.81m/s^2)*2m=W
W= 1373.4 J
Both are the same therefore the correcr answer is *both require the same amount of work*