Define the following Vocabulary words
1. Archae Bacteria
2. Bacteria
3. Eukarya Kingdom
4. Domain
It’s a test and only need 2 more problems!!!! Thank you and Appreciate it!!!
Answer:
the molar mass of propane (c3H8) is
12*3+1*8
=36+8=44
Define
wheel and axel
Answer:
A wheel and axle is a simple lifting machine that consists if rope that unwind a wheel onto a cylindrical drum/ shaft to provide mechanical advantage.
wheel and axle is a simple machine having two co-axial cylinder of different radii fitted to a common axies.
1. What is the molar mass of Al2S3?
Answer:
150.17 g/mol
Explanation:
5.6 g of Iron reacts with excess fluorine gas.
The mass of iron fluoride produced is 11.3 g
What is the formula of the iron fluoride?
Answer: FeF3 Iron(III) fluoride
Explanation: 5.6 g = 1/10 mole Fe
11.3-5.6g F = 5.7 = 3/10 mole F
To measure the amount of nickel in some industrial waste fluid, an analytical chemist adds sodium hydroxide solution to a sample of the fluid and collects the solid nickel(II) hydroxide product. When no more is produced, he filters, washes and weighs it, and finds that has been produced. The balanced chemical equation for the reaction is:
Answer:
The final balanced equation is
Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+
Explanation:
It is given that sodium hydroxide is added to collect the solid nickel(II) hydroxide product
The empirical equation for this statement is
Ni2+ + NaOH --> Ni (OH)2 + Na+
We will first balance the hydroxide molecule. On the right side there are two OH molecules.
Thus, on the left side we will take 2 sodium hydroxide
Ni2+ + 2NaOH --> Ni (OH)2 + Na+
Now we will balance the sodium ion which are 2 in numbers on the left side and 1 on the right side
Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+
So, the final balanced equation is
Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+
Choose the correct statement regarding the behavior of water.Group of answer choicesThe heat capacity of liquid water is greater than the heat capacity of solid ice.The water phase with the smallest temperature increase when adding 10 kcal of heat is solid ice.Ice has a higher density than liquid water and therefore sinks.The water phase with the smallest temperature increase when adding 10 kcal of heat is gas vapor.The heat capacity of gas vapor is greater than the heat capacity of liquid water.
Answer:
The water phase with the smallest temperature increase when adding 10 kcal of heat is solid ice.
Explanation:
The rest of the statements are incorrect. The density of ice is lower than the density of water. The heat capacity of solid ice is greater almost twice the heat capacity of the liquid water. The heat capacity of vapors is less than heat capacity of liquid.
Which individual elements make up the following common
compounds?
CaCO 3
CaCl 2
C H O 3 6
HCl
Ca(OH) 2
Answer:
I think it will carbon hope it helps
Menstruation occurs on a ______ interval from puberty until menopause
A. Three months
B. Two months
C. Half month
D. One month
I'll give brainliest to whoever gives me the answer to all of this.
Is the study of matter and energy complete, or do you think there’s still new information to discover?
Answer:
Physical science, in turn, can be divided into chemistry and physics. Chemistry is the study of matter and energy at the scale of atoms and molecules. ... Physics is the study of matter and energy at all scales—from the tiniest particles of matter to the entire universe but i dont really know if there is new information to discover
Explanation:
hope it help and if it doesnt sorry ;)
Give the formula of the alkanes his molecule contains 28 hydrogen atoms
Answer:
jayfeather friend me
Explanation:
Table 1. Summary of the Straight-Chain Alkanes
Name Formula Number of Structural Isomers
Octadecane C18H38
Nonadecane C19H40
Eicosane C20H42 366,319 (!)
29 more rows
The formula of the alkanes the molecule contains 28 hydrogen atoms is [tex]C_1_3H_2_8[/tex], i.e., tridecane.
What are alkanes?Alkanes are organic compounds made up entirely of single-bonded carbon and hydrogen atoms with no other functional groups.
Alkanes have the general formula CnH2n+2 and are classified into three types: linear straight-chain alkanes, branched alkanes, and cycloalkanes.
Alkanes are important raw materials in the chemical industry and the main component of gasoline and lubricants.
Natural gas is primarily composed of methane and ethane and is used for heating, cooking, and power generation (gas turbines).
Natural gas and petroleum are separated from the alkanes. Natural gas is primarily composed of methane, with trace amounts of other low molecular weight alkanes.
All other alkanes are derived from petroleum, which is a complex mixture of many compounds.
Here, the formula for 28 hydrogen atom containing alkane is
[tex]C_1_3H_2_8[/tex]
Thus, this given formula is of tridecane.
For more details regarding alkanes, visit:
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2. Methyl dichloroacetate (Cl2CHCO2CH3) decays into methanol (CH3OH) and dichloroacetic acid (Cl2CHCO2H) on reaction with water. Given a rate constant of 2.7 x 10-4/sec and an initial concentration of 1-ppm methyl dichloroacetate in the water, how much methanol will be present in the water after 30 min
Answer:
2.69 * 10^-6 Mol/L
Explanation:
The equation of the reaction is;
Cl2CHCO2CH3 -------------------> Cl2CHCO2H + CH3OH
To convert from ppm concentration to Mol/L, we have
M = ppm/MM * 1000
Where;
M = mol/l
MM= Molar mass
M = 1/142.97 g/mol * 1000 =
M= 6.99 * 10^-6 Mol/L
For first order reaction;
ln[A] = ln[A]o -kt
Given that
[A]o = 6.99 * 10^-6 Mol/L
[A]=??
k= 2.7 x 10-4/sec
t= 30 mins * 60 = 1800 s
ln[A] = ln[6.99 * 10^-6] - (2.7 x 10-4 * 1800)
ln[A] = -11.87 - 0.486
ln[A] = -12.356
[A] = e^(-12.356)
[A] = 4.3 * 10^-6 Mol/L
Concentration of methanol present after 30 mins= 6.99 * 10^-6 - 4.3 * 10^-6 = 2.69 * 10^-6 Mol/L
Helppppp pleaseeee xxxxxx
Answer:
2812.6 g of H₂SO₄
Explanation:
From the question given above, the following data were obtained:
Mole of H₂SO₄ = 28.7 moles
Mass of H₂SO₄ =?
Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:
Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)
= 2 + 32 + 64
= 98 g/mol
Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:
Mole of H₂SO₄ = 28.7 moles
Molar mass of H₂SO₄ =
Mass of H₂SO₄ =?
Mole = mass / Molar mass
28.7 = Mass of H₂SO₄ / 98
Cross multiply
Mass of H₂SO₄ = 28.7 × 98
Mass of H₂SO₄ = 2812.6 g
Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄
When going down a slope on a roller
coaster, does your stomach actually
move up?
Answer:
yes
Explanation:
due to gravity &hggggggggg%ggghhbvvvghh
14.86 ml + 15.0 ml + 14.980 ml =
Answer:
44.84 ml
Explanation:
14.86
+
15.0
+
14.980
_______
44.84
What is the mass in grams of 2.5 mol of O2?
Answer:
80grams
Explanation:
RAM of O=16
molar mass of O2= 16×2=32g/mol
mass= mole × molar mass
= 2.5×32= 80g
what does the roman numeral stand for in copper(1) oxide should it not be copper(II) oxide
Answer:
The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.
Explanation:
Roman numeral is used to indicate the oxidation number of an element in a compound.
The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.
This can be seen from the following illustration:
copper(I) oxide => Cu₂O
Oxidation number of O = –2
Oxidation number of Cu₂O = 0
Oxidation number of Cu =?
Cu₂O = 0
2Cu + O = 0
2Cu – 2 = 0
Collect like terms
2Cu = 0 + 2
2Cu = 2
Divide both side by 2
Cu = 2/2
Cu = 1
Thus, we can see that the oxidation number of Cu in Cu₂O is 1. Hence the name of Cu₂O is copper(I) oxide indicating that the oxidation number of of copper (Cu) in the compound is 1.
For copper(II) oxide, we shall determine the oxidation number of Cu. This can be obtained as follow:
copper(II) oxide, CuO => CuO
Oxidation number of O = –2
Oxidation number of CuO = 0
Oxidation number of Cu =?
CuO = 0
Cu + O = 0
Cu – 2 = 0
Collect like terms
Cu = 0 + 2
Cu = 2
Thus, the oxidation number of Cu in CuO is 2. Hence the name of CuO is copper(II) oxide indicating that the oxidation number of of copper (Cu) in the compound is 2.
From the above illustrations,
We can see that the roman numeral in both copper(I) oxide, Cu₂O and copper(II) oxide, CuO are different because the oxidation number of Cu in both cases are different.
Which of these substances would be an alkali?
A substance which turns universal indicator orangeA substance with a pH of 1A substance which turns universal indicator blueA substance with a pH of 7
One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal
and one mole of water. 5.00 g of the metallic oxide produces 2.32 g of the metal. What is the metallic
oxide?
Answer:
Lithium oxide, Li₂O.
Explanation:
Hello!
In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:
[tex]M_2O+H_2 \rightarrow 2M+H_2O[/tex]
Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:
[tex]5.00gM_2O*\frac{1molM_2O}{(2x+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{xgM}{1molM} = 2.32gM[/tex]
Thus, we perform the operations in order to obtain:
[tex]\frac{10x}{2x+16}=2.32[/tex]
So we solve for x as shown below:
[tex]10x = 2.32(2x+16)\\\\10x = 4.64x+37.12\\\\x = \frac{37.12}{10-4.64}\\\\x= 6.93 g/mol[/tex]
Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.
Best regards!
After looking at the schematics of the bubble, he finds that it holds 0.750 moles of gas at Standard Temperature and Pressure. Unfortunately for Rooster, helium gas is not sold by the mole, only by the liter. He needs to know how many liters of gas 0.750 moles of helium is.
Answer:
16.8 L
Explanation:
From the question given above, the following data were obtained:
Number of mole of He = 0.750 mole
Volume of He =?
Recall:
1 mole of any gas occupy 22.4 L at STP. This also implies that 1 mole of He occupies 22.4 L at STP.
Finally, we shall determine the volume occupied by 0.750 mole of He. This can be obtained as follow:
1 mole of He occupied 22.4 L at STP.
Therefore, 0.750 mole of He will occupy = 0.750 × 22.4 = 16.8 L at STP.
Thus, 0.750 mole of He is equivalent to 16.8 L
what is the substance? cdH) (Η) (Η
(H)C
cco
Ή) (Η
Η
Η
Answer:
A substance is a pure single form of matter. It cannot be separated into other kinds of matter by any physical process.
235U92 + 1N0 + 135Cs55 + 99Rb37 + x1n0
Label one of the test tubes Fe2+. Add 4 milliliters of iron(II) sulfate to the test tube.
Label the other test tube Fe3+. Add 4 milliliters of iron(III) nitrate to the test tube.
Add 4 milliliters of potassium thiocyanate to each test tube.
Observe the contents of the test tubes, noting any evidence of a chemical reaction. Record your observations in the table. If there is no evidence of a reaction, write “no reaction.”
Answer: A: Has little to no reaction; might turn slightly red in color. B: The liquid grows darker in color to a more reddish tone.
Explanation: I didn’t have the necessary materials to complete the experiment so the teacher told me and I put it in my own words.
A banana has 0.42 g of potassium. How many moles of potassium are in a banana ?
Answer:
0.011mole
Explanation:
Given parameters:
Mass of potassium in the banana = 0.42g
Unknown:
Number of moles of potassium in the banana = ?
Solution:
To solve this problem, we use the expression below:
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of K = 39g/mol
Number of moles = [tex]\frac{0.42}{39}[/tex] = 0.011mole
Write the molecular equation for the reaction that occurs, if any, when solutions of the following substances are mixed: nitric acid and potassium carbonate. Make sure that you have properly identified all of the phases in your answer.
Answer:
The balanced molecular equation for the reaction is:
[tex]2HNO_{3_{(aq)} }[/tex] + [tex]K_{2} CO_{3} _{(s)}[/tex] → [tex]2KNO_{3} _{(s)}[/tex] + [tex]H_{2} O_{(l)[/tex] + [tex]CO_{2} _{(g)}[/tex]↑
Explanation:
The weak nitric acid reacts with the strong potassium base to produce salt, water and carbon dioxide which is given off.
Molecular ratio of reactants is 2 : 1.
All phases are represented in the equation: aq for aqueous, l for liquid and g for gas (notice how they are written in subscript).
I hope this was helpful.
Lithium diorganocopper (Gilman) reagents are prepared by treatment of an organolithium compound with copper(I) iodide. Decide what lithium diorganocopper (Gilman) reagent is needed to convert 1-bromopropane into propylcyclohexane. Draw the structure of the organolithium compound that is used to prepare Gilman.
Answer:
See explanation and image attached
Explanation:
The Gilman reagent is a lithium and copper (diorganocopper) reagent with a general formula R2CuLi. R is an alkyl or aryl group.
They are useful in the synthesis of alkanes because they react with organic halides to replace the halide group with an R group.
In this particular instance, we intend to synthesize propylcyclohexane. The structure of the lithium diorganocopper (Gilman) reagent required is shown in the image attached to this answer.
As human populations grow, it becomes more important to use renewable sources of energy Which of the following objects uses energy from a renewable source?
a stove that is powered by natural gas
a refrigerator that runs on solar power
a lantern that burns oil from beneath Earth's surface
a foaster that uses electricity from a coal-burning power plant
Explanation:
Moreover, increasing use of fossil fuels also causes serious environmental problems. Hence, there is a pressing need to use renewable energy sources like solar energy, wind, tide, biomass and energy from waste material. (i) it reduces the dependence on fossil fuels for energy. (ii) they donot produces pollution.
Help solve please, it’s due in less than an hour or so.
sorry i can only figure out 1 but the answer is
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124
hope you do good on your test :D
Fill in the coefficient needed to make the equation balanced.
1. _______ Na + Cl2 → ______NaCl
a. 2, 2
b. 2, 3
c. 2, 1
d. 2, 4
2. _______Al + _______S → Al2S3
a. 2, 2
b. 2, 3
c. 2, 4
d. 2, 6
3. ______ H2 + O2 → ______H2O
A. 2, 2
b. 2, 3
c. 2, 4
d. 2, 8
4. _______Fe + ______O2 → ______Fe2O3
a. 4, 2, 2
b. 4, 2, 1
c. 4, 3, 2
d. 4, 3, 1
Answer:
1 a
2 b
3 a
4. c
Explanation: