The composite bar chart Messages received shows the number of messages Tim received each day for five days.
a) How many texts did Tim receive on Monday?
b) How many emails did Tim receive on Thursday?
c) In total, what fraction of the messages were emails?
Give your answer in its simplest form.

The larger integer number is 18 and the smaller integer number is -14.

Integers are the subset of Rational numbers which contains all numbers except fraction and decimals

Numbers are the building blocks of mathematics. Numbers are used to count ,measure or label quantities.

The different types of numbers are:

Let the smaller number be x. The sum of the numbers is 4 .

So the larger number is 4 - x

Again given that sum of three times the larger number and 2 times the smaller number is 26.

∴3 ( 4-x )+ 2x = 26

or, 12 -3x +2 x = 26

or, -x = 26-12

or, x = -14

Therefore the larger number is 4-(-14)= 18

Hence the larger integer number is 18 and the smaller number is -14 .

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Abby should write her equation as k = 1.61m.

The correct option is B.

A pair of algebraic equations with the equal symbol (=) in the center and the same value are referred to as an equation.

Given:

Abby knows that 1 mile is about 1.61 kilometers.

To write an equation, which she can use to convert any given distance in miles (m) to kilometers (k):

Let m be the total number of miles and k be the kilometers.

So, the equation is,

k = 1.61m

Where 1.61 is multiplied by m.

Therefore, the equation is k = 1.61m.

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Answer:

120

Step-by-step explanation:

the difference = 24×41-864=120

Part (a)

The middle values were nitially 266 and 269, but now they are 255 and 266. Thus, the median changes from 267.5 to 260.5, meaning it decreases by 7.

Part (b)

The sum before the change is 2264, but after, it is 2120. This means the sum decreased by 144, and thus the mean decreased by 16.

The sequence starting with 0 but each number is two times three less than the previous number is as follows:

0, -6, -12, -18, -22

A sequence is defined as an arrangement of numbers in a particular order.

The most common sequence are the arithmetic and the geometric sequence.

The sequence starts with 0 but each number is two times three less than the previous number.

This means the first term of the sequence is 3.

Hence,

2 times 3 less than the previous number means:

Aₙ = Aₙ₋₁ - 2(3)

where,

Let's use the formula to find the other numbers in the sequence,

A₂ = A₂₋₁ - 2(3) = 0 - 6 = -6

A₃ = A₃₋₁ - 2(3) = -6 - 6 = -12

A₄ = A₄₋₁ - 2(3) = -12 - 6 = - 18

A₅ = A₅₋₁ - 2(3) = -18 - 6 = - 22

Therefore, the sequence starting with 0 but each number is two times three less than the previous number is as follows:

0, -6, -12, -18, -22

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Using the Pythagorean Theorem and implicit differentiation, it is found that the distance between them is increasing at a rate of 2050 km/h when they are 0.5 hours away from the harbor.

The Pythagorean Theorem relates the length of the legs [tex]l_1[/tex] and [tex]l_2[/tex] of a right triangle with the length of the hypotenuse h, according to the following equation:

[tex]h^2 = l_1^2 + l_2^2[/tex]

For this problem, we have that since the ships are moving west and north, the distance between them as a function of the time will be given by the hypotenuse of a right triangle, as follows:

d² = x² + y².

In which;

Applying implicit differentiation, the rate of change of the position is given as follows:

[tex]2\frac{dd}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}[/tex]

[tex]\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}[/tex]

From the velocities, we have that:

[tex]\frac{dx}{dt} = 40, \frac{dy}{dt} = 50[/tex]

From the velocities, and the time of half an hour, the positions are given as follows:

x = 0.5 x 40 = 20, y = 0.5 x 50 = 25.

Hence:

[tex]\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}[/tex]

[tex]\frac{dd}{dt} = 20(40) + 25(50)[/tex]

dd/dt = 2050.

The distance between them is increasing at a rate of 2050 km/h when they are 0.5 hours away from the harbor.

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Answer is 140

According to the question,

Given that,

111 + 10 + 25 - 2 × 3

calculate the term

121 + 25 - 6

121 + 19

140

Una solicitud de licencia de manejar comercial

(DL 44C). Al firmar este formulario significa

que usted se compromete a hacerse un análisis

químico para determinar el contenido de alcohol

o drogas en su sangre. Si se niega a firmarlo, el

Departmento de Vehículos Motorizados (DMV)

no expedirá o renovará su licencia de manejar.

• Su nombre verdadero y completo.

• Un reporte de examen médico aprobado Medical Examination Report (MER). El formulario

federal válido (orginal o copia) del reporte del

examen médico Medical Examination Report

(MER) (MCSA-5875) y el formulario del certificado del examinador médico Medical Examiner’s Certificate Form (MEC) MCSA-5876

al solicitar la licencia de manejar o el permiso;

tal reporte debe ser expedido por un doctor en

los Estados Unidos que esté licenciado en medicina (M.D.), un doctor licenciado en osteopatía

(D.O.), un médico asistente con licencia (P.A.),

un enfermero practicante avanzado y registrado

(APN) o un doctor quiropráctico autorizado. Los

conductores que tengan certificados para manejar autobuses escolares, autobuses de actividades

estudiantiles School Pupil Activity Bus Certificate (SPAB), autobuses de jóvenes, vehículos

paratránsito para el público en general General

Public Paratransit Vehicle (GPPV) o co certificados para manejar vehículos de labores agrícolas

deben tener un examen médico expedido por

un doctor en medicina, un médico asistente con

licencia, un enfermero practicante avanzado y

registrado o un quiropráctico que esté autorizado en el registro nacional de examinadores médicos certificados National Registry of Certified

Medical Examiners (§12517.2 del CVC).

Se requiere un reporte médico fechado en los 2

últimos años para cualquier tipo de solicitud de

licencia CDL y luego cada 2 años.

Nota: No envíe por correo su reporte médico

a la patrulla de caminos California Highway

Patrol (CHP). El formulario MER y el formulario

del certificado MEC pueden presentarse en una

oficina del DMV o ser enviados por correo directamente al DMV para actualizarlos. Envíe por

correo sus formularios MER y MEC a la siguientedirección por lo menos 4 semanas antes que se

venza su reporte médico anterior o su privilegio

para manejar vehículos CMV puede invalidarse.

Envíe el reporte médico a:

Department of Motor Vehicles

CDL/PDPS Unit, MS G204

PO Box 942890

Sacramento, CA 94290-0001

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Answer:

=sqrt of 30

Step-by-step explanation:

=sqrt of 3×2×5

=sqrt 30

The number of hours Hector worked this week is 32 hours.

444 = 15(4) + 12(x)

444 = 60 + 12x

444 - 60 = 12x

384 = 12x

x = 384/12

x = 32 hours

check:

444 = 60 + 12x

444 = 60 + 12(32)

444 = 60 + 384

444 = 444

Therefore, the number of hours Hector worked this week is 32 hours.

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The measure of segment DF from the given question is 21

In line geometry, a line is the distance between two points while an angle is the point where two lines intersect.

Given the following parameters

DE = 4x + 10, EF = 2x-1, and DF = 9x-15,

Required

DF

Using the addition postulate

DE + EF = DF

Substitute

4x+10 + 2x -1= 9x - 15

6x + 11 = 9x - 1

6x - 9x =  -1 - 1

-3x = -12

x = 12/3

x = 4

For DF

DF =  9(4) - 15

DF = 21

Hence the measure of segment DF from the given question is 21

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answer:

1,120,504

Step-by-step explanation:

I don't really have one but I'm sure

2(6k+2)=64

12k+4=64

12k=60

k=5

Answer:

$1

Step-by-step explanation:

If you have x dimes, you have 8x nickels.

So, this means x + 8x = 18.

This means you have 2 dimes and 16 nickels, which have a combined value of 2(0.10)+16(0.05)=$1.

The equation of circle is [tex]x^2+y^2=100[/tex]

The standard equation of a circle with center (h, k) and radius r is given by:

[tex](x-h)^2+(y-k)^2=r^2[/tex] ........(1)

This is the equation needed for the circle with a center at A(h, k) and a radius equal to r since it describes the relationship between the coordinates of any point on the circumference.

Now according to the question, it is given that the circle has the center at origin and length of its radius is 10.

Center = (h, k)=(0, 0)

Radius(r) = 10 units

Now, substituting the given values in (1) we get;

⇒[tex]x^2+y^2=100[/tex]

Therefore, the equation of circle centered at origin with radius 10 is [tex]x^2+y^2=100[/tex]

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The possible values of x will belong to the set A = [9, ∞).

We have the following inequality -

1 - 2x/3 ≤ -3

We have to determine all values of x.

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

According to the question, we have the following inequality -

1 - 2x/3 ≤ -3

Subtract 1 from both sides -

-2x/3 ≤ -4

Multiply by -1 on both sides -

2x/3 ≥ 4

Multiply by 3/2 on both sides -

x ≥ 9

Hence, the possible values of x will belong to the set A = [9, ∞).

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Answer:

450g

450,000mg

450,000,000,000ng

Explaination:

Kg to g (x1,000)

Kg to mg (x1,000,000)

kg to ng (x1,000,000,000,000)

Answer:

6(5)3(5)² + (3)³

Step-by-step explanation:

Put this into your calculator just like this

Step-by-step explanation:

[tex](3 \sqrt{3 - 2 \sqrt{2)(3 \sqrt{3 - 2 \sqrt{2)} } } } [/tex]

Answer:

(−∞, 31/5) or x <31/5 (the graph will start a little bit past 6 and will be a open circle and head to the left)

Answer:

x< 6[tex]\frac{1}{5}[/tex]

Step-by-step explanation:

7<-5(x -8) - 2  Distribute the 5

7<-5x + 40 - 2

7<-5x +38  Subtract 38 from both sides

-31<-5x  Divide both sides by -5

[tex]\frac{31}{5}[/tex] >x  When you divide both sides by a negative number, you must flip the sign.

or

x < 6 [tex]\frac{1}{5}[/tex]

To get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.

Given that we have to get 1 by dividing 60 by something and multiply 60 by something to get 25.

We are required to find those numbers.

Take first result:

Suppose the number which divides 60 be x.

So,

60/x=1

x=60

Number will be 60.

Take second result:

Suppose the number which multiplied with 60 to get 25 be y.

So,

60*y=25

y=25/60

y=0.41

Number will be 0.41.

Hence to get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.

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The value of x associated with the point P on a number line is 0.5.

In accordance with the statement, the condition SP = PT means that the locations of points S, T and P on the number line are 0, 1, x, so that S < P < T and that point P is equidistant of points S and T. Then, the location of the missing point is determined by the midpoint formula:

P = 0.5 · S + 0.5 · T

P = 0.5 · 0 + 0.5 · 1

P = x = 0.5

The value of x associated with the point P on a number line is 0.5.

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Answer:

GA =34

Y = 61

Step-by-step explanation:

GA= GENERAL ADMISSION =$10

Y= YOUTH =$8

GA+Y= 95

GA=95-Y

10GA+8Y=828

10(95-Y)+8Y=828

950-10Y+8Y=828

-2Y= 122 MULTIPLY BY (-1)

2Y= 122

Y= 61

GA= 34

There were 61 youth tickets sold and 34 general admission tickets

Answer: The car was not speeding. It went 27.6 mi/h.

Step-by-step explanation: The equation v=2/5L is given where v is measured in mi/h. L is measured in ft. Since we have the value 69 for L, we sub it into the equation. We end up getting 27.6 mi/h after evaluating.

Answer: 1. {a, b, c, d, e}

2. {a, b, d}

3. {c, f, g, h}

4. {a, c}

Step-by-step explanation:

1. AUC ==> Means take all parameters from A and C.

A+C=

{a, b, c, d}+{a, e}={a, b, c, d, e}

2. B∩A ==> Means take the common parameters from B and A

B: {b, e, a, d}

A: {a, b, c, d}

Both B and A have a, b, and d.

So answer is {a, b, d}.

3. B' is every parameter that isn't in B

Reminder: B={b, e, a, d}.

All parameters: {a, b, c, d, e, f, g, h}

Remaining Parameters(B'): {c, f, g, h}

4. A-B∩C'

First, let's find C'.

C' is every parameter that isn't in C.

Reminder: C={a, e}

All parameters: {a, b, c, d, e, f, g, h}

Remaining Parameters(C'): {b, c, d, f, g, h}

Then lets find B∩C'

B: {b, e, a, d}

C': {b, c, d, f, g, h}

Both B and C' have b and d, so B∩C' is {b, d}

A-{b, d}=

{a, b, c, d}-{b, d}={a, c} ==> Answer for 4

Answer:

[tex]\sf 1) \quad \sf A \cup C = \{a, b, c, d, e\}[/tex]

[tex]\sf 2) \quad B \cap A = \{a, b, d\}[/tex]

[tex]\sf 3) \quad B' = \{c, f, g, h \}[/tex]

[tex]\sf 4) \quad A -(B \cap C') = \{a, c \}[/tex]

Step-by-step explanation:

Set Notation

[tex]\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}[/tex]

Given sets:

Therefore:

Question 1

[tex]\begin{aligned}\sf A \cup C & = \sf \{a, b, c, d\} \cup \{a,e\}\\& = \sf \{a, b, c, d, e\}\end{aligned}[/tex]

Question 2

[tex]\begin{aligned}\sf B \cap A & = \sf \{b, e, a, d\} \cap \{a, b, c, d\}\\& = \sf \{a, b, d\}\end{aligned}[/tex]

Question 3

[tex]\begin{aligned}\sf B' & = \rm U - \sf B\\& = \sf \{a, b, c, d, e, f, g, h \}-\{b, e, a, d\}\\& = \sf \{c, f, g, h \}\end{aligned}[/tex]

Question 4

[tex]\begin{aligned}\sf A -(B \cap C') & = \sf \{a, b, c, d \}- \left( \{b, e, a, d \} \cap \{b, c, d, f, g, h \} \right)\\& = \sf \{a, b, c, d \}- \{b, d \} \\& = \sf \{a, c \}\end{aligned}[/tex]

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Answer:

[tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]

Step-by-step explanation:

Here, m is the slope and b is the y-intercept.

( -1, 3) ;  x₁ = -1  & y₁ = 3

(7, -8) ; x₂ = 7 & y₂ = -8

Slope can be obtained by the formula:

    [tex]\sf \boxed{\bf Slope = \dfrac{y_2-y_1}{x_2-x_1}}[/tex]

                [tex]\sf =\dfrac{-8-3}{7-[-1]}\\\\\\=\dfrac{-8-3}{7+1}\\\\\\=\dfrac{-11}{8}[/tex]

Now, we can find the y-intercept,

[tex]\sf y = \dfrac{-11}{8}x + b\\\\Substitute \ any \ one \ of \ the \ point \ in \ the \ above \ equation.\\\\\text{Here, we are substituting (-1 ,3)}\\\\3 = \dfrac{-11}{8}*(-1) + b\\\\3 = \dfrac{11}{8}+b\\\\b = 3 - \dfrac{11}{8}\\\\b = \dfrac{3*8}{1*8}-\dfrac{11}{8}\\\\b= \dfrac{24-11}{8}\\\\b= \dfrac{13}{8}[/tex]

Slope-intercept form:

          [tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]

Answer:

So what you have to do is go back to you lesson and read till you find an answer just like this one and read how to do it when u do that go back and to the quick check and find an answer that is similar. the reason why I'm telling you this is cause I cant calculate it right. or what you can do is calculate it right on here.

Step-by-step explanation:

https://www.inchcalculator.com/cubic-footage-calculator/

Answer:

  5.2 g/cm³

Step-by-step explanation:

Given a sculpture consisting of 2 cm³ at 4 g/cm³, 7 cm³ at 5 g/cm³, and 5 cm³ at 6 g/cm³, you want its average density.

The total mass of the sculpture is the sum of the masses of the components. Each of those is the product of its volume and density.

  red sand: (2 cm³)(4 g/cm³) = 8 g

  yellow sand: (7 cm³)(5 g/cm³) = 35 g

  brown sand: (5 cm³)(6 g/cm³) = 30 g

The total mass of the sculpture is ...

  total mass = 8 g + 35 g + 30 g = 73 g

The total volume of the sculpture is the sum of the volumes of its parts:

  total volume = 2 cm³ +7 cm³ +5 cm³ = 14 cm³

The density is the ratio of mass to volume:

  ρ = (total mass)/(total volume) = (73 g)/(14 cm³) = 73/14 g/cm³

  = 5 3/14 g/cm³ ≈ 5.2 g/cm³

The average density of the sculpture is about 5.2 g/cm³.

The value of x and y is y=29, X=21.

180-60=120

4y+4=120 get y by itself and remember that what ever you do to one side you do to the other.

Alternate interior angles are congruent so 3x-3=60

What is an angle ?

Angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle. Angles formed by two rays lie in the plane that contains the rays. Angles are also formed by the intersection of two planes. These are called dihedral angles.

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