The enthalpy of combustion of naphthalene (MW = 128.17 g/mol) is -5139.6 kJ/mol. How much energy is produced by burning 0.8210 g of naphthalene?

Answer:

Barium chloride + Sodium phosphate    →   barium phosphate + sodium chloride

Explanation:

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

Chemical equation:

BaCl₂ + Na₃PO₄         →     Ba₃(PO₄)₂ + NaCl

Balanced chemical equation:

3BaCl₂ + 2Na₃PO₄         →     Ba₃(PO₄)₂ + 6NaCl

The cation and anion of both reactants are exchanged with each other.

Ba²⁺ react with PO₄³⁻ and form Ba₃(PO₄)₂ while Cl⁻ react with Na⁺ and form sodium chloride.  

Molecular equation:

Barium chloride + Sodium phosphate    →   barium phosphate + sodium chloride

Answer:

"a chemical reaction in which acid and a base react quantitatively with each other"

Explanation:

The highest boiling point : A) 0.10 M lithium sulfate, Li₂SO4

Solutions from volatile substances have a higher boiling point and lower freezing points than the solvent  

ΔTb = Tb solution - Tb solvent  

ΔTb = boiling point elevation  

[tex] \large {\boxed {\boxed {\bold {\Delta Tb \: = \: Kb.m}}} [/tex]  

Kb = molal boiling point increase  

m = molal solution  

For electrolyte solutions there is a van't Hoff factor = i  

i = 1 + (n-1) α  

n = number of ions from the electrolyte  

α = degree of ionization, strong electrolyte α = 1, for non electrolytes i = 1  

So ΔTb   ≈ i(van't Hoff), the greater i, the greater ΔTb

α = 1 ,  strong electrolyte

A) 0.10 M lithium sulfate, Li₂SO4

Li₂SO4 ⇒2Li⁺+SO₄²⁻ ⇒n=3

B) 0.10 M hydrochloric acid, HCI

HCl⇒H⁺+Cl⁻⇒n=2

C) 0.10 M lithium nitrate, LINO₃

LINO₃ ⇒ Li⁺+NO₃⁻ ⇒n=2

D) 0.10 M magnesium sulfate, MgSO4​

MgSO4​ ⇒ Mg²⁺ + SO₄²⁻ ⇒ n=2

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question we have

[tex]a = \frac{500}{50} = \frac{50}{5} = 10 \\ [/tex]

We have the final answer as

Hope this helps you

London Dispersion force or Van de Waals force is a temporary attractive force which are the weakest and occur between nonpolar noble gases and same charges. This force is weaker because they have more electrons that are farther from the nucleus and are able to move around easier.

Example: [tex]N_2[/tex], [tex]F_2, \ I_2[/tex]

[tex]\huge\textbf{Dipole - Dipole Forces}[/tex]

Dipole force is present between the polar molecules. Polar molecules are those molecules which have slightly negative and slightly positive charge. Dipole-dipole forces are attractive forces between the positive end of one polar molecule and the negative end of another polar molecule.

Example: HCl, HF, [tex]CHCl_3[/tex]

[tex]\huge\textbf{Hydrogen Bonding}[/tex]

It is a special type of dipole force present between polar molecules, it is formed between Hydrogen atom which forms positive ion, and the other negative ion. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom. The hydrogen bond is one of the strongest intermolecular attractions, but weaker than a covalent or an ionic bond.

Example: Every polar molecule which has hydrogen has hydrogen bonding i.e. [tex]H_2O, NH_3[/tex]

Answer:

See explanation and image attached

Explanation:

The  acid-catalyzed hydration of alkenes is an ionic reaction. Being an ionic reaction, a carbocation is formed in the process. This carbocation is capable of rearrangement to yield different products based on thermodynamic stability.

Remember that the order of stability of carbocations is; methyl< primary<secondary< tertiary. The rearrangement of carbocations leads to the formation of more stable intermediates and consequently more stable products.

However, the alkene in the image shown yields 1-methylcyclohexanol  without carbocation rearrangement.

Answer: calcium

Explanation: a periodic table can tell you how many protons have, and from this we can see that the answer is calcium

So there are two aluminum atoms, three sulfur atoms, and 12 oxygen atoms in a single unit of the compound Al2(SO4)3.

Chemical element aluminum has the atomic number 13 and the letter Al assigned to it. The density of aluminum is around one third that of steel, which is less than that of most common metals. When exposed to air, it generates an oxidized layer that protects the surface because to its strong affinity for oxygen. With regard to color and light-reflecting properties, aluminum has a striking visual similarity to silver. It has a soft, ductile, and non-magnetic texture.

Aluminum is the twelfth most frequent element in the universe and has only one stable isotope, 27Al, which is also quite abundant. Radiodating employs the radioactivity of 26Al.

Chemically, aluminum belongs to the boron group and is a post-transition metal.

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Answer:

distillation of a mixture

Explanation:

Answer:

A.) Distillation of mixture.

Explanation:

edge 2021

The energy of the waves is 6.5 * 10^-19 J.

The energy of the wave could be obtained from the wavelength of the wave by by the use of the formula shown below;

E = hc/λ

h = Plank's constant

c = speed of light

λ = wavelength

Now we have;

h = 6.6 * 10^-34 Js

c = 3 * 10^8 m/s

λ =  305 * 10^-9

E =  6.6 * 10^-34 Js * 3 * 10^8 m/s/ 305 * 10^-9

E = 6.5 * 10^-19 J

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Answer:

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

47.7 g Mg

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

Step 3: Convert

[tex]47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} )[/tex] = 1.18161 × 10²⁴ particles Mg

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

Answer:

The correct answer is - 1. oxaloacetate.

Explanation:

During the electron transport chain, the oxaloacetate is converted to aspartate by the reduction of NADH and accepting electrons in the mitochondria. Aspartate is then moved through the inner membrane to the cytosol.

This is the reaction also known as the synthesis of the aspartate. Aspartate either again converted to OAA (oxaloacetate) or move to the biosynthesis of proteins and biosynthesis of purine and pyrimidines.

Answer:

c

Explanation:

energy does not have volume

Answer:

Explanation:

Answer:

[Al³⁺] = 1.62 M

[SO₄²⁻] = 2.43 M

Explanation:

Step 1: Given data

Molar concentration of Al₂(SO₄)₃: 0.811 M

Step 2: Write the reaction for the ionization of Al₂(SO₄)₃

Al₂(SO₄)₃(aq) ⇒ 2 Al³⁺(aq) + 3 SO₄²⁻(aq)

Step 3: Calculate the molar concentration of Al³⁺

The molar ratio of Al₂(SO₄)₃ to Al³⁺ is 1:2. The molarity of Al³⁺ is 2/1 × 0.811 M = 1.62 M.

Step 4: Calculate the molar concentration of SO₄²⁻

The molar ratio of Al₂(SO₄)₃ to SO₄²⁻ is 1:3. The molarity of SO₄²⁻ is 3/1 × 0.811 M = 2.43 M

The concentration of the aluminium ion is 0.4055 M while the concentration of the sulfate ion is 0.270  M.

We know that the following reaction occurs for the dissolution of Al2(SO4)3 in water;

Al2(SO4)3(s) ----> 2Al^3+(aq) + 3SO4^2-(aq)

To find the concentration of each of the ions;

So using the square bracket notation to indicate concentration;

[Al^3+] = 0.4055 M

So using the square bracket notation to indicate concentration;

[SO4^2−] =0.270  M

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Answer:

Explanation:

The essential though process is to ask oneself when converting grams to moles=>  'How many formula weights are in the given mass?' This directs one to divide the substance's formula weight into the given mass (in grams) on order to determine number of moles. That is ...

moles = Given Mass of Substance in grams / formula weight of substance in grams

= 1578 grams / 791 grams-mol.⁻¹ =1.995 mole ≅ 2 moles

A. The period of a pendulum can b defined as the time it takes the pendulum to make one full back-and-forth swing.

The period of a pendulum is defined as the time taken by the pendulum to finish one full oscillation and is denoted by letter "T".

The period of oscillation of a pendulum is calculated as follows;

T = 2π√(L/g)

where;

The period of a pendulum does not depend on the mass of the ball, but only on the length of the string.

Thus, we can conclude that, the period of a pendulum can b defined as the time it takes the pendulum to make one full back-and-forth swing.

A full back ad forth swing makes one complete oscillation.

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The number of vum the man can trade for is = 108 vum

The number of sop the man has = 4 sop.

But the exchange rates are as follows:

1 fot = 5 vum,

2 sop = 3 tuz,

4 bef = 5 tuz,

9 fot = 2 bef

Using,

2 sop = 3 tuz,

4sop = X tuz

X tuz = 4×3/2 = 13/2 = 6 tuz.

Using,

4 bef = 5 tuz,

X bef = 6 tuz

X bef = 6×4/5

X bef =24/5 = 4.8 bef

Using,

9 fot = 2 bef

X fot = 4.8 bef

X fot = 9 × 4.8/2

X fot = 21.6 fot.

Using,

1 fot = 5 vum,

21.6 fot = X vum

X vum = 5 × 21.6/1

X vum = 108 vum

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Answer:

[tex] \huge 9[/tex]

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ { H_3O}^{+}][/tex]

From the question we have

[tex]pH = - log(1 \times {10}^{ - 9} ) [/tex]

We have the final answer as

Hope this helps you

Answer:

3x10 16hz 16 small above 10

Explanation:the frequency of any wave is (wave speed)/(wavelength)

The speed of light is 3x10 m/s. that's 30 million quartz

Answer:

See explanation

Explanation:

The mole refers to the amount of substance contained in 12 g of carbon-12. It was arbitrarily related to the number of elementary entities in 12 g of carbon -12 by Prof. Avogadro.

The number of moles of a substance is obtained as the mass of the substance divided by the mass of one mole of the substance (molar mass). Hence when the number of moles is known, the mass is now;

number of moles * molar mass

The density : 21.63 g/L

The gas equation can be written  

[tex]\large {\boxed {\bold {PV = nRT}}}[/tex]

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

T = 65+273=338 K

P=2.36 atm

MW Iodine gas (I₂)=254

The density :

[tex]\tt \rho=\dfrac{P\times MW}{RT}\\\\\rho=\dfrac{2.36\times 254}{0.082\times 338}=21.63~g/L[/tex]

Answer:

Geosphere

Explanation:

Geosphere sometimes called as lithosphere starts from the surface of the earth and lies till crust. This part of the earth contains rocks and minerals.

This portion of the earth includes sediments,mountains and rock. The natural resources that is available to the human brings lies in geosphere.

Answer:

Before I answer I feel that I should provide some scientific background as to how you would go about determining the answer.

First point that’s important for you to understand is the following formula

F =  G∗(M1∗M2)/d2

Where G is your gravitational constant, which means that comparing the two weights it won’t change and we don’t really have to worry ourselves too much about it.

Secondly we have the masses of the two individual objects, M1 and M2, in this case M1 is going to be 120 pounds.

Then you have d which is the distance between the centres of the two objects.

The second thing you need to understand is the fine print in the question. You asked how much you would weigh given that you weigh 120 pounds on Earth. The question from a pure science view is flawed as you don’t infact weigh 120 pounds, rather you have a mass of 120 pounds which will remain a constant. Your weight on Earth is actually 530 Newtons

(120lb=54,4311kg)

(54,4311kg*9.8) = approximately 530N

Now assuming you are right and the moon has a sixth of the earths mass, that would mean that you would weigh a sixth of it.

But wait theres more, because the radius of the moon is smaller it will have an impact. the radius of the moon infact is a sixth of the earths, which means that you will be multiplying by 36(because you are making the divisor a sixth smaller, but also squaring it)

this would mean that you would weigh six times as much on the moon as on Earth, which we know is not true. This implies you made a mistake with the mass of the moon compared to that of the Earth. So upon googling it.

Mass of Earth

5.972 × 10^24 kg

Mass of Moon

7.34767309 × 10^22

kilograms

Just looking at it the difference is about 200 times, which means that you probably misinterpreted the data, the gravitational attraction of the moon is a sixth of the Earths, which means you would weigh about 530/6N or to the casual viewer about 88 N

Note : I rounded and abstracted a lot because I feel its the gist of the answer and the understanding that’s important, you are welcome to contact me if you feel anything is incomplete or unclear. I did most of the math quickly and am liable to mistakes but the science is right(unless ofc you feel like bringing relativity in, but that’s a whole other can of worms

Explanation:

Yess

Answer:

19.92 pounds :)