The gravitational field strength on the moon is 1.63 N/kg. If a rock on the moon weighs 2000N, how
much does the same rock weigh on the earth?

Answer:

I'm not that busy solving but I'll tell you the formula that Force x distance is equal to work done

The work is done on a pumpkin when we lift it by 15 m with 24 N is 360 J

Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J).  

i.e. Work(W) is force(F) times displacement(s).

W=F× s

When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule.

Writing for it's dimension,

W=F× s

Force has dimension [L¹ M¹ T²]

Displacement has dimension [L¹]

multiplying both the dimensions Force and Displacement  

we get,

dimension of Work [L² M¹ T²]

According to newton's second law of motion,

Force(F) is mass(M) times acceleration(a).

i.e. F=ma

Given,

Force = 24 N

Displacement = 15 m

W=F.s= 24*15 = 360 J

Hence work done on pumpkin is 360 J

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Answer:

[tex]fe = \frac{9 \times 10 {}^{9} \times 1.6 \times 10 {}^{ - 19} \times 1.6 \times 10 { - 19}^{?} }{(1 \times 10 { }^{ - 8}) {}^{2} } \\ fe = 23.04 \times 10 {}^{ - 13} n[/tex]

Answer:The Dead Sea water has a density of 1.24 kg/litre

Explanation:

which makes swimming similar to floating.

Answer:

Se obtienen 2,27 gramos de metanol.

Explanation:

La reacción entre monóxido de carbono e hidrógeno para producir metanol es la siguiente:

CO + 2H₂ → CH₃OH  

Para encontrar el reactivo limitante y el reactivo en exceso, debemos calcular el número de moles de CO y H₂:

[tex]\eta_{CO} = \frac{m}{M} [/tex]              

En donde:    

m: es la masa

M: es el peso molecular  

[tex]\eta_{CO} = \frac{m}{M_{CO}} = \frac{2,0 g}{28,01 g/mol} = 0,071 moles [/tex]

[tex]\eta_{H_{2}} = \frac{2,0 g}{2,02 g/mol} = 0,99 moles [/tex]

Dado que la relación estequiométrica entre CO y H₂ es 1:2, el número de moles de hidrógeno gaseoso que reaccionan con el monóxido de carbono es:

[tex] \eta_{H_{2}} = \frac{2}{1}*0,071 = 0,142 moles [/tex]      

Entonces, se necesitan 0,142 moles de H₂ para reaccionar con 0,071 moles de CO y debido a que se tienen más moles de H₂ (0,99 moles) entonces el reactivo limitante es CO y el reactivo en exceso es H₂.

Ahora podemos encontar la masa de metanol obtenida usando el reactivo limitante (CO) y sabiendo que la realcion estequiométrica entre CO y CH₃OH es 1:1.    

[tex] \eta_{CH_{3}OH} = \eta_{CO} = 0,071 moles [/tex]

[tex] m = 0,071 moles*32,04 g/mol = 2,27 g [/tex]

Por lo tanto, se obtienen 2,27 gramos de metanol.

Espero que te sea de utilidad!      

Answer:

The kinetic energy of a moving object is directly proportional to its mass and directly proportional to the square of its velocity. This means that an object with twice the mass and equal speed will have twice the kinetic energy while an object with equal mass and twice the speed will have quadruple the kinetic energy.

Answer:

[tex]Pressure = 29723.1\ N/m^2[/tex]

Explanation:

Given

[tex]Force = 8694N[/tex]

[tex]Length = 0.45m[/tex]

[tex]Width = 0.65m[/tex]

Required

The force exerted on the floor by the box

First, calculate the area covered by the box (i.e. the base area)

[tex]Base\ Area = Length * Width[/tex]

[tex]Base\ Area = 0.45m * 0.65m[/tex]

[tex]Base\ Area = 0.2925m^2[/tex]

Pressure is calculated as:

[tex]Pressure = \frac{Force}{Area}[/tex]

[tex]Pressure = \frac{8694N}{0.2925m^2}[/tex]

[tex]Pressure = 29723.0769231\ N/m^2[/tex]

[tex]Pressure = 29723.1\ N/m^2[/tex] --- approximated

Answer:

Explanation:

This is a missile throwing exercise, let's find the distance

         x = v₀ₓ / t

         t = v₀ₓ / x

let's calculate

         t = 2.5 / 12

         t = 0.2083 s

as time is a scalar this is the same value for descends to the ground

         y = v_{oy} t  - 1/2 g t²    

we calculate

         v_y = 0 - 9.8 0,2083  

         v_y = - 2.04 m / s

the negative sign indicates that the speed is down

A pumpkin is thrown horizontally off of a building at a speed of 2.5 m/s and travels a horizontal distance of 12 m before hitting the ground. We can ignore air resistance.

What is the pumpkin's vertical velocity when it hits the ground?

Answer: -47.04

Answer:

13,308 MAYBE IF IT ISN'T IM SO SORRY

Explanation:

Answer:

P=F/A where F is the weight of the water and A is the area on which it is resting. The weight of the water is mg. The mass of the water is dv where d is the density and v is the volume. Finally, the volume of the water in a vessel is equal to the area of the base of the vessel times the height of the vessel. (v=Ah)

Plugging everything in we get:

P = dAhg/A

So

P=dhg

So we have shown that liquid pressure is directly  proportional to height of liquid in a vessel.​

Answer:

so we don't drown and die.

Explanation:

Answer: NO.

Explanation: Oxygen is not a compound. It has only one element in it.

chemical reaction for fossil fuels:combustion of fuels.

Difference between biomass and fossil fuels:how much carbon dioxide is produced

Comparing biomass with other renewable energy sources:does not have as much energy potential as fossil fuels.

Making energy choices locally: biomass

Answer:

D

Explanation:

Answer:

[tex]5.2\ \text{m/s}[/tex]

[tex]70^{\circ}[/tex] south of east

Explanation:

[tex]v_a[/tex] = 3 m/s

[tex]\theta_a[/tex] = [tex]20^{\circ}[/tex] north of east

[tex]v_b[/tex] = 6 m/s

[tex]\theta_b[/tex] = [tex]40^{\circ}[/tex] south of east = [tex]360-40=320^{\circ}[/tex] north of east

x and y component of [tex]v_a[/tex]

[tex]v_{ax}=v_a\cos \theta\\\Rightarrow v_{ax}=3\times \cos 20^{\circ}\\\Rightarrow v_{ax}=2.82\ \text{m/s}[/tex]

[tex]v_{ay}=v_a\sin\theta\\\Rightarrow v_{ay}=3\times \sin20^{\circ}\\\Rightarrow v_{ay}=1.03\ \text{m/s}[/tex]

x and y component of [tex]v_b[/tex]

[tex]v_{bx}=v_b\cos \theta\\\Rightarrow v_{bx}=6\times \cos 320^{\circ}\\\Rightarrow v_{bx}=4.6\ \text{m/s}[/tex]

[tex]v_{by}=v_b\sin\theta\\\Rightarrow v_{by}=6\times \sin320^{\circ}\\\Rightarrow v_{by}=-3.86\ \text{m/s}[/tex]

[tex]\Delta v=v_b-v_a\\\Rightarrow \Delta v=(4.6-2.82)\hat{i}+(-3.86-1.03)\hat{j}\\\Rightarrow \Delta v=1.78\hat[i}-4.89\hat{j}[/tex]

Magnitude

[tex]|\Delta v|=\sqrt{(-4.89)^2+1.78^2}\\\Rightarrow \Delta v=5.2\ \text{m/s}[/tex]

Direction

[tex]\theta=\tan{-1}|\dfrac{-4.89}{1.78}|\\\Rightarrow \theta=70^{\circ}[/tex]

The magnitude of the change in velocity vector is [tex]5.2\ \text{m/s}[/tex] and the direction is [tex]70^{\circ}[/tex] south of east.

The change in velocity will be  [tex]\Delta V=5.2\ \frac{m}{s}[/tex] and the direction will be [tex]70^o[/tex] South to east.

Any quantity which is defined by its magnitude and direction both are called as the vector quantities.

Now the data given in the question will be given as:

[tex]V_a[/tex] = 3 m/s

[tex]\theta[/tex] = [tex]20^o[/tex] north of east

[tex]V_b[/tex] = 6 m/s

[tex]\theta[/tex] =  [tex]40^o[/tex]south of east =  360-40=320 north of east

Now we will find the x and y component of [tex]V_a[/tex]

[tex]V_{ax}=V_acos\theta[/tex]

[tex]V_{ax}=3\times Cos20[/tex]

[tex]V_{ax}=2.82\ \frac{m}{s}[/tex]

[tex]V_{ay}=V_aSin\theta[/tex]

[tex]V_{ay}=3\times Sin20[/tex]

[tex]V_{ay}=1.03\ \frac{m}{s}[/tex]

Now we will find the x and y component of [tex]V_b[/tex]

[tex]V_{bx}=V_bcos\theta[/tex]

[tex]V_{bx}=6\times cos\320[/tex]

[tex]V_{bx}=4.6\ \frac{m}{s}[/tex]

[tex]V_{by}=V_bSin\theta[/tex]

[tex]V_{by}=6\times Sin320[/tex]

[tex]V_{by}=-3.86\ \frac{m}{s}[/tex]

Now change in velocity will be

[tex]\Delta V=V_b-V_a[/tex]

[tex]\Delta V=(4.6-2.82)i+(-3.86-1.03)j[/tex]

[tex]\Delta V=1.78i-4.89j[/tex]

The magnitude can be find out as follows:

[tex]\Delta V=\sqrt{(-4.89^2+(1.78^2)}[/tex]

[tex]\Delta V=5.2\ \frac{m}{s}[/tex]

The direction of the vector will be

[tex]\theta= tan^{-1}(\dfrac{-4.89}{1.78})[/tex]

[tex]\theta=70^o[/tex]

Thus the change in velocity will be  [tex]\Delta V=5.2\ \frac{m}{s}[/tex] and the direction will be [tex]70^o[/tex] South to east.

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Answer:

3. converging lens

Explanation:

When the rays of light coming parallel to principle axis after refraction through the lens passes through a point called focus, since it converge all the ray at one point, that is why it is said to be converging lens.

Answer & Explanation:

In science, rationality and creativity work together. Creativity allows us to view and solve problems with innovation and openness. Scientific theories often came from sparks of creative thinking and bold yet logical processes.

Answer:

7.35..kg

Explanation:

Hope this will help you

Please,Mark me as Brainllist .

Answer:

Cool.

Explanation:

What's the question..? :|

Answer: 4276.2 calories

Explanation:

Given

mass of steam is 6 gm at [tex]100^{\circ}C[/tex]

Conversion of steam to ice involves

Calories released during the conversion of steam to water at [tex]100^{\circ}C[/tex]

[tex]E_1=mL_v\quad [L_v=\text{latent heat of vaporisation}]\\E_1=6\times 533=3198\ cal.[/tex]

Calories released during the conversion of water at [tex]100^{\circ}C[/tex] to water at [tex]0^{\circ}C[/tex]

[tex]E_2=mc(\Delta T)\quad [c=\text{specific heat of water,}1\ cal./gm.^{\circ}C]\\E_2=6\times 1\times 100=600\ cal.[/tex]

Calories released during the conversion of water to the ice at [tex]0^{\circ}C[/tex]

[tex]E_3=mL_f\quad [L_f=\text{latent heat of fusion}]\\E_3=6\times 79.7=478.2\ cal.[/tex]

The total energy released is

[tex]E=E_1+E_2+E_3\\E=3198+600+478.2=4276.2\ cal.[/tex]

Answer:

it depends on the medium :D

Answer:

the correct one is 2

Explanation:

The emission and arcion spectra are similar, in the emission spectra a heated material emits photons for the internal transitions of the electrons, in the absorption spectrum the continuous emission of a lamp is absorbed at the energies that the material has transitions.

In our case the material is low early, so all the electrons are in their base states.

As the light beam has all wavelengths, those corresponding to the first emission of the material will be observed.

When reviewing the answers, the correct one is 2

Answer:

25 seconds

Explanation:

500/20

Answer:

Δx is the path difference between the two waves.

...

Phase Difference And Path Difference Equation.

Formula Unit

Phase Difference \Delta \phi=\frac{2\pi\Delta x}{\lambda } Radian or degree

Path Difference \Delta x=\frac{\lambda }{2\pi }\Delta \phi meter

Answer:

22

Explanation:

bc it just is

Answer:

P since without a host the parasite won't be able to survive they would start decreasing as well but if the hosts were no more then they would go extinct. But since it is just decreasing then it should be P

Answer:

3kWx(3/60)h=0.15kwh

Answer:

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

Explanation:

El mango experimenta un movimiento de caída libre, es decir, un movimiento uniformemente acelerado debido a la gravedad terrestre, despreciando los efectos de la viscosidad del aire y la rotación planetaria. Entonces, la velocidad final del mango, es decir, la velocidad con la que llega al suelo, se puede determinar mediante la siguiente fórmula cinemática:

[tex]v = v_{o}+g\cdot t[/tex] (1)

Donde:

[tex]v_{o}[/tex] - Velocidad inicial, en metros por segundo.

[tex]v[/tex] - Velocidad final, en metros por segundo.

[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.

[tex]t[/tex] - Tiempo, en segundos.

Si sabemos que [tex]v_{o} = -75\,\frac{m}{s}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] y [tex]t = 26\,s[/tex], entonces la velocidad final del mango es:

[tex]v = v_{o}+g\cdot t[/tex]

[tex]v = -75\,\frac{m}{s}+\left(-9.807\,\frac{m}{s} \right)\cdot (26\,s)[/tex]

[tex]v = -329.982\,\frac{m}{s}[/tex]

El mango llega al suelo a una velocidad de 329.982 metros por segundo.