The indefinite integral of ((6e^4x)(e^arctan(3e^4x)))/(1+9e^8x)

Answers

Answer 1

Answer:

[tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{e^\big{arctan(3e^{4x})}}{2} + C[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Property [Multiplied Constant]:                                                           [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Integration

Integrals[Indefinite Integrals] Integration Constant C

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

U-Substitution

U-Solve

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx[/tex]

Step 2: Integrate Pt. 1

[Integrand] Rewrite:                                                                                       [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \int {\frac{6e^\big{arctan(3e^{4x}) + 4x}}{1 + 9e^\big{8x}}} \, dx[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]:                 [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = 6\int {\frac{e^\big{arctan(3e^{4x}) + 4x}}{1 + 9e^\big{8x}}} \, dx[/tex]

Step 3: integrate Pt. 2

Set variables for u-substitution.

Set u:                                                                                                             [tex]\displaystyle u = 4x[/tex][u] Differentiate [Basic Power Rule, Multiplied Constant]:                         [tex]\displaystyle du = 4 \ dx[/tex]

Step 4: Integrate Pt. 3

[Integral] Rewrite [Integration Property - Multiplied Constant]:                 [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{4e^\big{arctan(3e^{4x}) + 4x}}{1 + 9e^\big{8x}}} \, dx[/tex][Integral] U-Substitution:                                                                               [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{e^\big{arctan(3e^u) + u}}{1 + 9e^\big{2u}}} \, du[/tex]

Step 5: Integrate Pt. 4

Set variables for u-substitution #2.

Set v:                                                                                                               [tex]\displaystyle v = 9e^{2u} + 1[/tex] [v] Differentiate [Exponential Differentiation, Chain Rule]:                       [tex]\displaystyle dv = 18e^{2u} \ du[/tex][v] U-Solve:                                                                                                    [tex]\displaystyle u = ln \Big( \frac{\sqrt{v - 1}}{3} \Big)[/tex][dv] U-Solve:                                                                                                   [tex]\displaystyle du = \frac{e^{-2u}}{18} \ dv[/tex][U-Solve] Rewrite u:                                                                                       [tex]\displaystyle e^u = \frac{\sqrt{v - 1}}{3}[/tex]

Step 6: Integrate Pt. 5

[Integral] U-Solve:                                                                                              [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{e^\big{arctan(3(\frac{\sqrt{v - 1}}{3})) + ln(\frac{\sqrt{v - 1}}{3})}}{1 + 9(\frac{\sqrt{v - 1}}{3})^2} \frac{1}{18e^{2u}}\, dv[/tex][Integral] Simplify:                                                                                              [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{\sqrt{v - 1}e^\big{arctan(\sqrt{v - 1})}}{3[1 + v - 1]} \frac{1}{18(\frac{\sqrt{v - 1}}{3})^2}\, dv[/tex][Integral] Simplify:                                                                                         [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{\sqrt{v - 1}e^\big{arctan(\sqrt{v - 1})}}{3v} \frac{1}{2(v - 1)}\, dv[/tex][Integral] Simplify:                                                                                         [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{3}{2}\int {\frac{e^\big{arctan(\sqrt{v - 1})}}{6v\sqrt{v - 1}} \, dv[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]:                 [tex]\displaystyle \int {\bigg( 6e^\big{4x} \cdot \frac{e^\big{arctan(3e^{4x})}}{1 + 9e^\big{8x}} \bigg)} \, dx = \frac{1}{4}\int {\frac{e^\big{arctan(\sqrt{v - 1})}}{v\sqrt{v - 1}} \, dv[/tex]

Step 7: Integrate Pt. 6

Set variables for u-substitution #3.

Set z:                                                                                                               [tex]\displaystyle z = arctan(\sqrt{v - 1})[/tex][z] Differentiate [Arctrig Differentiation, Chain Rule]:                                 [tex]\displaystyle dz = \frac{1}{2v\sqrt{v - 1}} \ dv[/tex]

See attachment for rest of work (would not fit entire answer in answering box).

The Indefinite Integral Of ((6e^4x)(e^arctan(3e^4x)))/(1+9e^8x)

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The horizontal asymptote of the rational function y = (8 · x² + 7 · x - 5) / (5 · x² + 2 · x + 6) is y = 8 / 5.

How to determine the equation of a horizontal asymptote

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

The greatest common factor is 3 for 27n + 66p and 12x + 75y + 21.

What are Factors?

Factors of a number or an algebraic expression are the numbers or expressions which divides the given number evenly.

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So we can say that 2 and 5 are factors of 10.

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Step-by-step explanation:

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Answer:

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Answers

Answer:

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Step-by-step explanation:

its hard to tell but i think it dilated 5 units

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Answer:

i'm pretty sure its 30%.

Step-by-step explanation:

because 70% are in heath. so 30% of the students arent. i think... hope this helped.

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Answer:

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Step-by-step explanation:

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The given compound inequality is conveniently written with the "arrows" pointing to the left. This means the lower limit of the variable is on the left side of the inequality, just as it is on the left end of the number line graph.

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Answers

Answer: least value - 22

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Step-by-step explanation:


Juanita makes $26 an hour at work. She has to take time off work to purchase her skirt, so each hour away from work costs her $26 in lost income. Assume that returning to work takes Juanita the same amount of time as getting to a store and that it takes her 30 minutes to shop. As you answer
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Answer: Local Department Store: $6.5, $118.5

Across Town: $13, $102

Neighboring City: $26, $96

Step-by-step explanation:

Local Department Store: 1 hr=60 min.

60/15=4

26/4=$6.5

112+6.5=$118.5

Across Town: 60/30=2

26/2=$13

89+13=$102

Neighboring City: 60/60=1

26/1=$26

70+26=$96

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Answers

Answer:

60%

Step-by-step explanation: i hope this heple

\

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Answers

Answer:

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Step-by-step explanation:

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Answer:

(appx) 4.3

Step-by-step explanation:

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its 256.............................


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Answer:

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Step-by-step explanation:

The circumference is 72 inches.


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Answers

It should be noted that 24 percent of 60 is 14.4.

How to calculate the percentage?

The question is to calculate 24% of 60.

This will go thus:

= 24% × 60

= 24/100 × 60

= 0.24 × 60

= 14.4

Therefore, 24% of 60 is 14.4.

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Step-by-step explanation:

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(04.01 MC) A candle burns down at the rate of 0.5 inches per hour. The original height of the candle was 10 inches. Part A: Write a list of 6 ordered pairs to show the height of the candle in inches (y) as a function of time in hours (x) from the first hour after it started burning. For example, the point (0, 10) would represent a height of 10 inches after 0 hours. Explain how you obtained the ordered pairs. (5 points) Part B: Is this relation a function? Justify your answer using the list of ordered pairs you created in Part A. (2 points) Part C: If the rate at which the candle burned was 0.75 inches per hour instead of 0.5 inches per hour, would the relation be a function? Explain your answer using input and output values. (3 points)

Answers

The ordered pairs, justification of the function with different order pairs is required.

The ordered pairs are [tex](0,10),(1,9.5),(2,9),(3,8.5),(4,8),(5,7.5)[/tex]

All values of [tex]x[/tex] has a unique value in [tex]y[/tex] so, it is a function.

y = Height of candle

x = Number of hours

m = Rate = 0.5 inches per hour

c = y intercept = Initial height = 10 inches

The required function is

[tex]y=-0.5x+10[/tex]

Six ordered pairs would be

[tex]x=0,1,2,3,4,5[/tex]

[tex]y=-0.5\times 0+10=10[/tex]

[tex]y=-0.5\times 1+10=9.5[/tex]

[tex]y=-0.5\times 2+10=9[/tex]

[tex]y=-0.5\times 3+10=8.5[/tex]

[tex]y=-0.5\times 4+10=8[/tex]

[tex]y=-0.5\times 5+10=7.5[/tex]

The ordered pairs are

[tex](0,10),(1,9.5),(2,9),(3,8.5),(4,8),(5,7.5)[/tex]

It can be seen that all values of [tex]x[/tex] has a unique value in [tex]y[/tex] so, it is a function.

If m = 0.75 inches per hour

The function would change to

[tex]y=-0.75x+10[/tex]

Some ordered pairs would be

[tex]y=-0.75\times 0+10[/tex]

[tex]y=-0.75\times 1+10[/tex]

[tex](0,10),(1,9.25)[/tex]

The same is seen in this function, all values of [tex]x[/tex] has a unique value in [tex]y[/tex] so, it is a function.

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WILL GIVE BRAINLIEST!!

Ignore the $

Meyer rolls two fair, ordinary dice with the numbers $1,2,3,4,5,6$ on their sides. What is the probability that at least one of the dice shows a square number?

Answers

Two numbers on each die are squares: 1 and 4. 4 numbers on each die are not squares: 2 , 3, 5, and 6. there are 16 ways for him to roll a non-square die, out of 36 outcomes for the pair of dice. The other 20 options each have a square number showing on one or both dice. So, the probability is 5/9. hope this helps please pick my answer as brainliest, have a good day!

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