The laws of reflection holds for__
a) plane mirrors. b) spherical mirrors.
c)both. d) None of them.​

Answers

Answer 1

Answer:

c)both

Explanation:

The laws of reflection hold true for all the reflecting surfaces either spherical or plane. Therefore, the plane mirror, concave mirror and the convex mirror all will follow the laws of reflection.

Answer 2

Answer:

It holds for only plane mirrors

It states that the angle of incidence is equal to the angle of reflection.

This is only possible in plane mirrors only


Related Questions

Din Djarin pushes on a crate of frog eggs (with a mass of 88) with a force of 240 N, if µs= .4 and µk= .133 what is the net force acting on the crate?

I'll give brainliest to anyone who can answer this, too.

Answers

Answer:

R = mg

F = µsR

Fs= 0.4 × ( 88 × 10)

Fs = 772 N

Fk= µk R

Fs= 1.33 × 880 N

Net force = (772+(1.33×880))-240 N

How did the leaning tower of Pisa start leaning?

Answers

Answer:

The foundation was somewhat bad

Explanation:

The leaning was caused by the uneven settling of the building's foundations in the soft ground. Three of its eight stories had been completed when the uneven settling of the building’s foundations in the soft ground became noticeable. At that time, war broke out between the Italian city-states, and construction was halted for almost a century. This pause allowed the tower’s foundation to settle and likely prevented its early collapse.

hope this helps:)

And tell me I was holding a 1 pound bag of apples and his left hand and a 2 pound bag of apples in his right hand which sentences about this situation are true

Answers

Answer:

B. Antonio is applying a 1-pound force to hold the 1-pound bag. E. The mass of the bag in his left hand is less than the mass of the bag in his right hand.

Explanation:

In order for one to carry something, they need to be exerting a force that is equal to the weight of the object. For Antonio therefore to hold the 1-pound bag, he needs to apply a 1-pound force.

Pounds measure the mass of an object. On his left hand Antonio has 1 pound and on the right he has 2. He is therefore carrying more mass on his right hand than on his left.

For the lever below calculate the position of the fulcrum if mass "A" = 25
kg and mass "B" = 100 kg and the leaver is 25 meters in length.

Answers

67.126792&4&484 because step step by step explains the double

What temperature will the hot plate reach when set to 300 degrees celsius?

Answers

300 degrees celsius

I’m pretty sure the temperature carries to the object.

How many different genera are represented?

The subject is in SCIENCE

Answers

Explanation:

Numbers of accepted genera

The numbers of either accepted, or all published genus names is not known precisely; Rees et al., 2020 estimate that approximately 310,000 accepted names (valid taxa) may exist, out of a total of c.

Soccer is technically know as what ?

a - Futbol

b - Association football

c - Association soccer

Answers

Answer:

c - Association soccer

because there is football in form of American football, hence it's soccer

Answer:

B.

Explanation:

Soccer was the only football-type game in the United States until American-style football became popular in the 1870s

a person who drives under the influence of alcohol or drugs blank?

Answers

Answer:

alcohol

Explanation:

alcohol is drives under the influence

Answer:

Has lost the ability to make wise decisions

sort the facts into the category that they best describe sound waves and electromagnetic waves

Answers

Answer:

Sound waves have a low speed of 330 m/s

Sound waves are mechanical waves

Electromagnetic waves have a greater speed of 3.0×10^8 m/s

Electromagnetic waves are due to disturbance of electromagnetic objects.

it regulates the amount of light passing through the spicemen. A. arm B. base C. body tube D. diaphragm

Answers

Answer:

D. diaphragm

Explanation:

The question above is related to the different parts of the microscope. Among the choices above, it is the diaphragm that regulates the amount of light passing through the specimen. This is located below the stage (the platform where the slide of specimen is placed). With the help of the diaphragm, the intensity of light is controlled, which allows the observer to see the specimen in the best contrast.

Additional Information:

The arm links the base of the microscope to its head.

The base simply supports the microscope.

The body tube links the objective lenses to the eyepiece.

A weight of 6 kg increases the speed of its force from 2 m / s to 4 m / s. By how many joules does the kinetic energy of the body increase?​

Answers

Answer:

36 J

Explanation:

Let's start off with the Kinetic Energy formula: 1/2m[tex]v^{2}[/tex]

So to find the change in Kinetic Energy, you would first have to find the Kinetic Energy in the beginning and in the end.

*Note: Mass: you incorrectly wrote weight = 6 kg- because weight is a force you have to write 6 Newtons. If you are talking about the mass, you would write 6 kg. If you are talking about weight, you would write 6 Newtons. The difference will make significant changes to the answer, so I will give you the answer for both.

If 6 kg is the MASS:

Beginning: find the kinetic energy.

Plug in all parts of the formula: 1/2mv^2 = [tex]\frac{1}{2}[/tex](6)(2 squared)= [tex]\frac{1}{2}[/tex](6)(4)= 12 J

End: find the kinetic energy.

Plug in all parts of the formula: 1/2mv^2=[tex]\frac{1}{2}[/tex](6)(4 squared)=[tex]\frac{1}{2}[/tex](6)(16)= 48 J

Answer:

36 J

If 6 kg is the WEIGHT:

We know that the weight formula is mg, or mass times acceleration due to gravity (which is always 9.8 m/s^2). Plug in the numbers:

Weight = mass x acceleration due to gravity

6 = mass x 9.8

6 = 9.8m

*Divide both sides*

mass = 0.6 kg

Now, we can use the mass to find the kinetic energy.

Beginning: find the Kinetic Energy

Plug in all parts of the formula: 1/2mv^2 = [tex]\frac{1}{2}[/tex](0.6)(2 squared)= [tex]\frac{1}{2}[/tex](0.6)(4)= 1.2 J

End: find the Kinetic Energy

Plug in all parts of the formula: 1/2mv^2=[tex]\frac{1}{2}[/tex](0.6)(4 squared)=[tex]\frac{1}{2}[/tex](0.6)(16)= 4.8 J

Answer:

3.6 J

(this answer is not very feasible, so 36 J is the way to go. But just remember, don't mix up weight and mass again- as you can see, they lead to different answers!)

Given that both liquid A and B exert the same amount of pressure .What would be the height of column of liquid A if the density of liquid A is twice the density of liquid B and the height of column of liquid B is 10cm ?show you are work?​

Answers

Answer:

ans 5

Explanation:

hope it's help It seems to me

Which of the following is an example of an unbalanced force?

A. Book sitting on a table
B. Car sitting in the garage
C. Person on an elevator going down
D. Person leaning on a wall

Answers

I think it’s d don’t go by mine tho

The world's largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds. What is the velocity for one of the blades? (THIS IS PHYSICS, CIRCULAR MOTION)

Answers

Answer:

The velocity of the blades is 88.185 m/s.

Explanation:

Given;

length of the blade, r = 80 m

angular speed, ω = 1 rev per 5.7 seconds

The velocity of the blades is calculated by applying the following circular motion equation that relates linear velocity (V) and angular speed (ω);

[tex]V = \omega r\\\\V = (\frac{1 \ rev}{5.7 \ s} \times \frac{2 \pi \ rad}{ 1 \ rev} )(80 \ m)\\\\V = 88.185 \ m/s[/tex]

Therefore, the velocity of the blades is 88.185 m/s.

Can someone help me :(

Answers

Stored water is gravitational potential energy
Power lines is electrical energy
Turbine is mechanical energy
The 2nd box is kinetic energy

Hope this helps

Have a great day/night

The blades of a metal cutter are shorter than the blades of paper cutter scissor. Give reason​

Answers

Answer:

Metal is a tougher material to cut though, so the blades must be shorter to create more pressure to break through the metal. Paper on the other hand is easier to cut through so the blades can be longer in order to cut more in each snip.

Which of the following is not a product of a complete combustion reaction of a hydrocarbon?
A. energy
B. carbon dioxide
C. carbon
D. water

Answers

Answer:

I think the answer might be C

C. Carbon is not a product of a complete combustion reaction of a hydrocarbon.

What is complete combustion?

Complete combustion is a process in which all carbon contained in a fuel or gas stream is converted to carbon dioxide.

The generic equation for the complete combustion of a hydrocarbon is:

CxHy + O₂ ⇒ CO₂ + H₂O + Energy

Let's consider which of the following is a product of a complete combustion reaction of a hydrocarbon.

A. energy. YES.

B. carbon dioxide. YES.

C. carbon. NO.

D. water. YES.

C. Carbon is not a product of a complete combustion reaction of a hydrocarbon.

Learn more about complete combustion here: https://brainly.com/question/9913173

A merry-go-round of radius 2 m is rotating at one revolution every 5 s. A
child is located at 1 m from the axis. A teenager is located at 2 m from the
axis.
What is the angular speed of the child?
What is the angular speed of the teenager?
What is tangential speed of the child?
What is the tangential speed of the teenager?

Answers

Answer:

a) The angular speed of the child is approximately 1.257 rad/s

b) The angular speed of the teenager is approximately 1.257 rad/s

c) The tangential speed of the child is approximately 1.257 m/s

d) For the child, r = 2 m

The tangential speed of the teenager is approximately 2.513 m/s

Explanation:

The revolutions per minute, r.p.m. of the merry-go-round = 1 revolution/(5 s)

The radius of the merry-go-round = 2 m

The location of the child = 1 m from the axis

The location of the teenager = 2 m from the axis

1 revolution = 2·π radians

Therefore, we have;

The angular speed, ω = (Angle turned)/(Time elapsed) = (2·π radians)/(5 s)

∴ The angular speed of the merry-go-round, ω = 2·π/5 radians/second

a) The angular speed of the child = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s

b) The angular speed of the teenager = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s

c) The tangential speed, v = r × The angular speed, ω

Where;

r = The radius of rotation of the object

For the child, r = 1 m

The tangential speed of the child = 1 m × 2·π/5 radians/second = 2·π/5 m/s ≈ 1.257 m/s

d) For the child, r = 2 m

The tangential speed of the teenager = 2 m × 2·π/5 radians/second = 4·π/5 m/s ≈ 2.513 m/s

A 1.00 kg object moving in the + x direction at 10.0 m/s collides with a 1.50 kg object traveling at 5.00 m/s in the - x direction. After the collision, the 1.00 kg object moves with a velocity of 4.00 m/s in the - x direction. How much kinetic energy was lost during the collision?

Answers

Answer:

The amount of kinetic energy lost during the collision is 60.75 J

Explanation:

The given parameters are;

The mass of the object moving in the +x direction, m₁ = 1.00 kg

The velocity of the object moving in the +x direction, v₁ = 10.0 m/s

The mass of the object moving in the -x direction, m₂ = 1.50 kg

The velocity of the object moving in the +x direction, v₂ = 5.00 m/s

The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s

The direction of motion of the 1.00 kg mass after collision = -x direction

The total initial kinetic energy of the system, [tex]K.E._{total \ initial}[/tex] = 1/2·m₁·v₁² + 1/2·m₂·v₂²

∴ [tex]K.E._{total \ initial}[/tex]  = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J

The final kinetic energy of the system, [tex]K.E._{final}[/tex]  = 1/2·m₁·v₃²

[tex]K.E._{final}[/tex] = 1/2×1.00×4² = 8 J

The amount of kinetic energy lost during the collision, [tex]\Delta K.E._{system}[/tex] is given as follows;

[tex]\Delta K.E._{system}[/tex] =  [tex]K.E._{final}[/tex] -[tex]K.E._{total \ initial}[/tex] = 8 J - 68.75 J = -60.75 J

The amount of kinetic energy lost during the collision = 60.75 J.

When comparing mass and size data for the planets Earth and Jupiter, it is observed that Jupiter is about 300 times more massive than Earth. One might quickly conclude that an object on the surface of Jupiter would weigh 300 times more than on the surface of the Earth. For instance, one might expect a person who weighs 500 N on Earth would weigh 150000 N on the surface of Jupiter. Yet this is not the case. In fact, a 500 N person on Earth weighs about 1500 N on the surface of Jupiter. Explain how this can be.

Answers

Answer:

This situation happens because radius of Jupiter is 10 times greater than radius of the Earth.

Explanation:

According to Newton's Law of Gravitation, weight is directly proportional to the mass of the planet ([tex]M[/tex]), measured in kilograms, and inversely proportional to the square of the radius of the planet ([tex]R[/tex]), measured in meters. That is:

[tex]W \propto \frac{M}{R^{2}}[/tex]

[tex]W = \frac{k\cdot M}{R^{2}}[/tex](1)

Where [tex]k[/tex] is proportionality constant, measured in Newton-square meters per kilogram.

Then, we eliminate the proportionality constant by constructing this relationship:

[tex]\frac{W_{J}}{W_{E}} = \left(\frac{M_{J}}{M_{E}}\right)\cdot \left(\frac{R_{E}}{R_{J}} \right)^{2}[/tex]

Where subindices J and E mean "Jupiter" and "Earth", respectively. If we know that [tex]\frac{M_{J}}{M_{E}} = 300[/tex], [tex]W_{E} = 500\,N[/tex]and [tex]W_{J} = 1500\,N[/tex], then the ratio of radii is:

[tex]\frac{R_{E}}{R_{J}} = \sqrt{\left(\frac{W_{J}}{W_{E}} \right)\cdot \left(\frac{M_{E}}{M_{J}} \right)}[/tex]

[tex]\frac{R_{E}}{R_{J}} = \sqrt{3\cdot \left(\frac{1}{300} \right)}[/tex]

[tex]\frac{R_{E}}{R_{J}} = \frac{1}{10}[/tex]

Therefore, this situation happens because radius of Jupiter is 10 times greater than radius of the Earth.

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