Answer:
Number of moles of water = 210 mol
Explanation:
Given data:
Mass of water = 3780 g
Number of moles of water = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of water = 18 g/mol
Number of moles = 3780 g/ 18 g/mol
Number of moles of water = 210 mol
Ashley is preparing for a speech about the tentacular feeding pattern of the corals. Help her complete the sentences. Corals have tentacles near the oral opening. The tentacles comprise cells called . These cells contain used by corals to sting the prey and stun them using the tentacles.
Answer:
Stinging cell, nematocysts.
Explanation:
Corals have tentacles present near the oral opening. The tentacles comprise cells called stinging cells. These cells contain nematocysts used by corals to sting the prey and stun them using the tentacles. These stinging cells present near the mouth which contains nematocysts that is an organelle that produces toxic substances used by the coral to catch their prey.
the question in the picture
plz help
and give me an explanation
Answer:
B. CH3CH2CH2CH2CH2C1Explanation:
I HOPE IT HELPS :)
2
3 of 6 - SCH4U
Date: Name(s):
4. HCl is a corrosive colourless gas that dissolves readily in water.
Aqueous HCl reacts with NaOH to form water and NaCl. In a simple
calorimeter, a 100.00 mL sample of 0.415 mol/L HCl(aq) is mixed
with 50.00 mL of excess NaOH(aq). During the reaction, there is a
rise in temperature by 4.83 °C. Calculate the molar enthalpy change
(in kJ/mol) for the above reaction. SHOW ALL YOUR WORK.
Answer: The molar enthalpy change is 73.04 kJ/mol
Explanation:
[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]
moles of HCl= [tex]molarity\times {\text {vol in L}}=0.415mol/L\times 0.1=0.0415mol[/tex]
As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.
volume of water = 100.0 ml + 50.0 ml = 150.0 ml
density of water = 1.0 g/ml
mass of water = [tex]volume \times density=150.0ml\times 1.0g/ml=150.0g[/tex]
[tex]q=m\times c\times \Delta T[/tex]
q = heat released
m = mass = 150.0 g
c = specific heat = [tex]4.184J/g^0C[/tex]
[tex]\Delta T[/tex] = change in temperature = [tex]4.83^0C[/tex]
[tex]q=150.0\times 4.184\times 4.83[/tex]
[tex]q=3031.3J[/tex]
Thus 0.0415 mol of HCl produces heat = 3031.3 J
1 mol of HCL produces heat = [tex]\frac{3031.3}{0.0415}\times 1=73043.3J=73.04kJ[/tex]
Thus molar enthalpy change is 73.04 kJ/mol
How many calories of energy are required to heat an 87 g piece of iron from 30*C to 40*C?.
ses
(The is the specific heat of iron is 0.110 cal/g x *C)
Answer:
95.7 cal
Explanation:
The heat required can be calculated as follows:
heat = m x Cp x ΔT
Where:
m = mass of iron = 87 g
Cp = specific heat of iron = 0.110 cal/g.°C
ΔT = change in temperature = final T - initial T = 40°C - 30°C = 10°C
Thus, we introduce the data in the mathematical equation to calculate the heat in calories:
heat = 87 g x 0.110 cal/g.°C x 10°C = 95.7 cal
Your friend uses a wire coil to model how a sound wave moves. What is an advantage to using
the spring coil as a model?
(10 Points)
A. The model increases the complexity of the wave.
B. The model shows the wave more quickly.
C. The model can be measured much more accurately.
D. The model can be observed from the classroom more easily.
Answer:
D. The model can be observed from the classroom more easily
Explanation:
From the concept of using wire coil to model and the concept of using spring coil to measure, we can come to the conclusion that the correct answer is Option D.
A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum chloride the chemist has added to the flask. Round your answer to 2 significant digits.
Answer:
2000 millimoles of AlCl₃
Explanation:
From the question given above, the following data were obtained:
Volume of solution = 1.8 L
Molarity of solution = 1.1 mol /L
Millmole of AlCl₃ =?
Next, we shall determine the number of mole of AlCl₃ in the solution.
This can be obtained as follow:
Volume of solution = 1.8 L
Molarity of AlCl₃ solution = 1.1 mol /L
Number of mole of AlCl₃ =?
Molarity = mole /Volume
1.1 = Number of mole of AlCl₃ / 1.8
Cross multiply
Number of mole of AlCl₃ = 1.1 × 1.8
Number of mole of AlCl₃ = 1.98 moles
Finally, we shall convert 1.98 moles to millimoles. This can be obtained as follow:
1 mole = 1000 millimoles
Therefore,
1.98 mole = 1.98 mole × 1000 millimoles / 1 mole
1.98 mole = 1980 millimoles
1.98 mole ≈ 2000 millimoles
Thus, the chemist added 2000 millimoles of AlCl₃
Do any water molecules become gas particles when the vapor pressure is lower than atmospheric pressure? Why or why not?
Answer:
Yes, water molecules becomes gas particles when the vapor pressure is lower than the external atmospheric temperature.
Explanation:
Vapor pressure is defined as the pressure of the vapor that lies above its surface. In other words, it is the pressure of the vapor which results from the evaporation of a liquid which is above a liquid in a closed or open container.
The liquid starts boiling or evaporation takes place when the vapor pressure of the liquid becomes equal to the external or atmospheric pressure. Now when the vapor pressure is less than the atmospheric pressure, the liquid boils at a higher temperature while when vapor pressure is more than the atmospheric temperature, the liquid starts boiling a lower temperature.
No water molecule is converted into gas when the atmospheric pressure is higher than vapour pressure.
No, water molecules will not become gas particles when the vapor pressure is lower than atmospheric pressure because of the higher pressure of surrounding environment on the water molecules. The water in liquid form is converted into gas form and evaporated when the vapour pressure is equal or higher than atmospheric pressure.
So if the vapour pressure is lower than the atmospheric pressure than the water molecules will not become gas particle so we can conclude that no water molecule is converted into gas when the atmospheric pressure is higher than vapour pressure.
Learn more: https://brainly.com/question/20503287
what does dissocation of hydrogen mean ?
Answer:
dissociation, in chemistry, separation of a substance into atoms or ions. ... For example, hydrogen molecules (H2) dissociate into atoms (H) at very high temperatures; at 5,000°K about 95% of the molecules in a sample of hydrogen are dissociated into atoms.
Explanation:
Considering this balanced chemical equation, how many grams of HgO will be produced when 44 g of Hg react with excess O2?
2Hg (l) + O2 (g) --> 2HgO (s)
A 28 g
B 44 g
C 48 g
D 96 g
Also, how would you go to solve this problem? Thanks!
Answer:
48g
Explanation:
2Hg(l) + O₂(g) => 2HgO
44g excess ?
44g/200.59g·mol⁻¹ = 0.219 mole Hg(l) = 0.219 mole HgO(s) produced.*
*Since coefficients are equal for Hg and HgO then the moles of HgO produced is the same as moles Hg used.
Convert 0.219 mole HgO to grams => 0.219mol x 216.95g/mol = 47.512g HgO ≅ 48g (2 sig figs)
To calculate the atoms of an element in a given molecule, we need to multiply stoichiometry by the number that is written on the foot of that element. The correct option is option C.
What is Balanced equation?Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, displacement reaction.
The other characteristic of balanced reaction is that physical state should be written with each compound or molecule on reactant and product side. Physical state should be written in brackets. s means solid, l means liquid, g means gas.
2Hg(l) + O₂(g) [tex]\rightarrow[/tex] 2HgO
44g excess ?
The mole ratio between Hg and HgO is 1:1.
44g÷200.59g/mol= 0.219 mole of Hg= 0.219 mole of HgO
mass of HgO=0.219mol x 216.95g/mol
= 47.512g
Therefore, the correct option is option C.
Learn more about the balanced equation, here:
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I need the answer today!
_____________________________________________
Solution 3 Is The Most ConcentratedS1:M = m/v
= 100ml ÷ 2 spoons × 100%
= - 5,000 μg/ppb³
= 50% Diluted
S2:M = m/v
= 200ml ÷ 5 spoons × 100%
= - 4,000 μg/ppb³
= 40% Diluted
S3:M = m/v
= 300ml ÷ 6 spoons × 100%
= - 5,000 μg/ppb³
= 50% Diluted
S4:M = m/v
= 600ml ÷ 8 spoons × 100%
= - 75,000 μg/ppb³
= 75% Diluted
_____________________________________________
Reaction: 2 Ag2CO3 --> 4 Ag + 2 CO2 + O2, how many moles of silver will
be produced when 97.4g of silver carbonate decomposes?
Answer:
0.7 moles of Ag are produced
Explanation:
Given data:
Mass of silver carbonate = 97.4 g
Moles of silver produced = ?
Solution:
Chemical equation:
2Ag₂CO₃ → 4Ag + 3CO₂
Number of moles of Ag₂CO₃ :
Number of moles = mass/molar mass
Number of moles = 97.4 g/ 275.75 g/mol
Number of moles = 0.35 mol
Now we will compare the moles of Ag and Ag₂CO₃.
Ag₂CO₃ : Ag
2 : 4
0.35 : 4/2×0.35 = 0.7
0.7 moles of Ag are produced.
The formula mass of HC2H302 is
1.
59
2.
60
3.
72
4.
80
Answer:
60
Explanation:
The formula of the compound is given as:
HC₂H₃O₂
To find the formula mass we sum up the atomic masses of the component elements;
Atomic mass:
H = 1
C = 12
O = 16
HC₂H₃O₂ = 1 + 2(12) + 3(1) + 2(16)
= 1 + 24 + 3 + 32
= 60
When writing a chemical name, what is written first?
A diamond contains 5.0 x 10^(21) atoms of carbon. What amount (moles) of carbon and what mass (grams) of carbon are in this diamond
Answer:
Amount (Mole) of carbon = 0.008303 mole
Mass (gramm)of Carbon = 0.0997 g.
Explanation:
From Avogadro's law, we know that 1 mole of carbon contains 6.022×10²³ atoms.
Then the mole of carbon that contains 5.0×10²¹ atoms can be computed as (5.0×10²¹ / 6.022×10²³)
=0.008303 mole
5.0×10²¹ atoms is contained in 0.008303 mole
Hence, Amount (Mole) of carbon = 0.008303 mole
the mass of carbon can be computed , we know that
Mole = mass /Molar mass
Where Molar mass of carbon = 12.01 g/mol
n=0.008303 mol
Making " mass" subject of the formula,
mass=Mole ,× Molar mass
=0.008303 x 12.01
= 0.0997 g.
I need help with science question. Picture attached
Answer:
C
cell wall only in plants
chloroplast only in plants
enlarged vacuoles only in plants
cell membrane in both
hope this helps :)
Explanation:
Answer:
a. cell wall b. membrane
Which of the following is true for the theoretical yield of a reaction? (1 point)
It is always calculated as a ratio.
It is the yield from the excess reactant.
It is the yield from the limiting reactant.
It is always twice the value of the actual yield.
Answer:
It is always twice the value of the actual yield.
Explanation:
iodid ion is oxidized to hypoiodite ion by permanganate what is the ratio of hydroxide ions to iodide ions in balanced equation
Answer: The ratio of number of hydroxide ions to iodide ions is 2 : 1.
Explanation:
The chemical equation for the oxidation of iodide ion is oxidized to hypoiodite ion by permanganate follows:
[tex]2MnO_4^-+I^-+H_2O\rightarrow 2MnO_2(s)+IO_3^{-}+2OH^{-}[/tex]
According to mole concept:
1 mole of a substance contains [tex]6.022\times 10^{23}[/tex] number of particles
Moles of iodide ions = 1 mole
Number of iodide ions = [tex](1\times 6.022\times 10^{23}[/tex]
Moles of hydroxide ions = 2 mole
Number of hydroxide ions = [tex](2\times 6.022\times 10^{23}[/tex]
Taking the ratio of number of hydroxide ions and number of iodide ions are as follows:
[tex]\frac{\text{Number of hydroxide ions}}{\text{Number of iodide ions}}=\frac{(2\times 6.022\times 10^{23})}{(1\times 6.022\times 10^{23})}\\\\\frac{\text{Number of hydroxide ions}}{\text{Number of iodide ions}}=\frac{2}{1}[/tex]
Hence, the ratio of number of hydroxide ions to iodide ions is 2 : 1.
Predict the Product
C6H12O6 → ______ + ___________
C6H12 + O2 → _______ + __________
Answer:
Answers with detail are given below.
Explanation:
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
Anaerobic respiration in plants produced ethanol which if accumulate then cause the harmful effect in plants. It is also occur in some microorganisms such as yeast.
C₆H₁₂O₆ → 2C₃H₆O₃
Anaerobic respiration in animals pyruvate converted into lactic acid and it is not as harmful as ethanol in plant if accumulate. It is produced during exercise. It can produce the cramps which can be cured with massage.
C₆H₁₂ + O₂ → CO₂ + H₂O
This reaction is the combustion reaction of cyclohexane. Cyclohexane burnt in the presence of oxygen and form water and carbon dioxide.
energy from the sun provides fuel for entire ecosystems true or false
Answer: True
Explanation:
interconic attraction theory states what
Explanation:
Interionic Attractions are when an ion is surrounded by an ionic atmosphere which has a net charge opposite for its own. ... The ionic atmosphere cannot created nor destroyed. In solutions with weak electrolytes the number of ions is not large, therefore the effect of the interionic attraction is small.
Hope this is fine for youWhat causes your vocal cords to vibrate a)mucas b)air c)chemicals
Answer:
air
Explanation:
Vocal folds vibrate when excited by aerodynamic phenomena; they are not plucked like a guitar string. Air pressure from the lungs controls the open phase. The passing air column creates a trailing “Bernoulli effect,” which controls the close phase.
Isopropyl alcohol (c3h7OH) burns in air according to this equation:
2C3H7OH + 9O2 -> 6CO2 + 8H2O
a) calculate the moles of oxygen needed to react with 3.40 mol C3H7OH
b) find the moles of each product formed when 3.40 mol C3H7OH reacts with oxygen
Answer:
a) 15.3 mol O₂
b) 10.2 mol CO₂; 13.6 mol H₂O
Explanation:
Step 1: Write the balanced equation
2 C₃H₇OH + 9 O₂ ⇒ 6 CO₂ + 8 H₂O
Step 2: Calculate the moles of O₂ that react with 3.40 moles of C₃H₇OH
The molar ratio of C₃H₇OH to O₂ is 2:9. The moles of O₂ required are 9/2 × 3.40 mol = 15.3 mol
Step 3: Calculate the moles of CO₂ produced from 3.40 moles of C₃H₇OH
The molar ratio of C₃H₇OH to CO₂ is 2:6. The moles of CO₂ produced are 6/2 × 3.40 mol = 10.2 mol
Step 4: Calculate the moles of H₂O produced from 3.40 moles of C₃H₇OH
The molar ratio of C₃H₇OH to H₂O is 2:8. The moles of H₂O produced are 8/2 × 3.40 mol = 13.6 mol
what is the emperical formula of a compound containing 40.1% carbon and 6.6% hydrogen
Answer:
CH₂
Explanation:
Given parameters:
Percentage composition:
Carbon = 40.1%
Hydrogen = 6.6%
Unknown:
Empirical formula of the compound = ?
Solution:
The empirical formula of a substance is its simplest formula.
Elements Carbon Hydrogen
Percentage
Composition 40.1 6.6
Molecular mass 12 1
Number of moles 40.1/12 6.6/1
3.342 6.6
Divide through by
the smallest 3.342/3.342 6.6/3.342
1 2
So the empirical formula of the compound is CH₂
10.
(05.05 MC)
Read the chemical equation.
Fe2O3 + CO → Fe + CO2
If 1.8 moles of Fe2O3 react with 2.7 moles of CO, how many moles of each product are formed? (3 points)
5.4 moles Fe and 1.8 moles CO2
2.7 moles Fe and 0.9 moles CO2
3.6 moles Fe and 5.4 moles CO2
1.8 moles Fe and 2.7 moles CO2
Answer: 1.8 moles Fe and 2.7 moles [tex]CO_2[/tex] are produced.
Explanation:
The balanced chemical reaction is:
[tex]Fe_2O_3+3CO\rightarrow 2Fe+3CO_2[/tex]
According to stoichiometry :
3 moles of [tex]CO[/tex] require 1 mole of [tex]Fe_2O_3[/tex]
Thus 2.7 moles of [tex]CO[/tex] will require=[tex]\frac{1}{3}\times 2.7=0.9moles[/tex] of [tex]Fe_2O_3[/tex]
Thus [tex]CO[/tex] is the limiting reagent as it limits the formation of product and [tex]Fe_2O_3[/tex] is the excess reagent.
As 3 moles of [tex]CO[/tex] give = 2 moles of [tex]Fe[/tex] and 3 moles of [tex]CO_2[/tex]
Thus 2.7 moles of [tex]CO[/tex] will give =[tex]\frac{2}{3}\times 2.7=1.8moles[/tex] of [tex]Fe[/tex] and [tex]\frac{3}{3}\times 2.7=2.7moles[/tex] of [tex]CO_2[/tex]
Thus 1.8 moles Fe and 2.7 moles [tex]CO_2[/tex] are produced.
When 1.0 g of gasoline burns, it released 11 kcal of heat. The density of gasoline is 0.74 g/mL. How many Joules of heat is released when 1.5 gallons of gasoline burns?
Answer:
[tex]Q=1.9x10^8J[/tex]
Explanation:
Hello!
In this case, since we first know the heat and mass of the first experiment, we are able to compute enthalpy of vaporization of gasoline as shown below:
[tex]Q=m\Delta _{vap} H\\\\\Delta _{vap} H=\frac{11kcal}{1.0g} =11\frac{kcal}{g}[/tex]
Next, we need to the compute the grams in 1.5 gallons of gasoline via its density with the proper units:
[tex]m_{gasoline}=1.5gal*\frac{3785.41mL}{1gal}*\frac{0.74g}{1mL} =4202g[/tex]
Therefore, the new joules are computed via:
[tex]Q=4202g*11\frac{kcal}{g}*\frac{1000cal}{1kcal}*\frac{4.184J}{1cal}\\\\Q=1.9x10^8J[/tex]
Best regards!
What are the relationships between temperature and viscosity of water?
Explanation:
Both cohesion and molecular interchange contribute to liquid viscosity. The impact of increasing the temperature of a liquid is to reduce the cohesive forces while simultaneously increasing the rate of molecular interchange. The former effect causes a decrease in the shear stress while the latter causes it to increase.
temperature?
The viscosity of liquids decreases rapidly with an increase in temperature, and the viscosity of gases increases with an increase in temperature. Thus, upon heating, liquids flow more easily, whereas gases flow more sluggishly.
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Lila is a track and field athlete. She must complete four laps around a circular track. The track itself measures 400 meters from start to finish and the race took her 6 minutes to complete.
Which best describes her speed and velocity?
Her speed is 4.4 m/s, and her velocity is 0 m/s.
Her speed is 1.1 m/s, and her velocity is 0 m/s.
Her speed is 0 m/s, and her velocity is 2400 m/s.
Her speed is 4.4 m/s, and her velocity is 4.4 m/s.
Answer:
Her speed is 1.1 m/s, and her velocity is 0 m/s.
Explanation:
Hello!
In this case, since the speed is the defined as the distance traveled over the elapsed time:
[tex]s=\frac{d}{t}[/tex]
And the velocity is defined as the change in displacement over the time interval:
[tex]v=\frac{\Delta d}{\Delta t}[/tex]
Thus, since the total distance traveled was 400 m and the total time 6 mins (360 s), we compute the speed as:
[tex]s=\frac{400m}{360s}=1.1m/s[/tex]
And the velocity is 0 m/s because the initial point is the very same final point as the track was circular. Therefore the answer is Her speed is 1.1 m/s, and her velocity is 0 m/s.
Best regards!
explain what happens to the concentrations of the reactants and products during a chemical reaction
Change 32°C to degree °F
Answer:
89.6 F
Explanation:
Brain-List?
write the formula to iron (III) oxide and iron (III) carbonate
Answer:
iron (III) oxide =Fe2O3
iron(III) carbonate =Fe2(CO3)3