The speed of light u is equal to c.
Given,
The motion of a transparent medium influences the speed of light.
The water moves with speed v in a horizontal pipe.
Assume the light travels in the same direction as the water moves.
The speed of light with respect to the water is c /n.
The index of refraction of water, n = 1.33
Let us assume u' be the speed of light in water.
u' is related to the refractive index of water,as u' = c/n
where, c is the speed of light.
Let, u be the speed of light in water in the lab frame.
Now, u and u' are related as : u = ( u'+v) /(1+u'v/c^2)
Here, v is the speed of water in the horizontal pipe.
We know the value of u'. so by substituting the value, we will get ,
u = (c/n+v) /(1+cv/nc^2)
u = c/n (1+nv/c) /(1+v/nc)
u in the limit as the speed of the water approaches c.
Thus,
u = lim v-->c [c/n (1+nv/c) /(1+v/nc) ]
u= c/n (1+n) /(1+1/n)
u= c .
Hence, the speed of light u is equal to c.
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Disclaimer: incomplete question. here is the complete question.
Question:The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n = 1.33 is the index of refraction of water.
(a) Use the velocity transformation equation to show that the speed of the light measured in the laboratory frame isu = c/n (1 + nv/c / 1+ v/nc).
(d) Evaluate u in the limit as the speed of the water approaches c .
it's possible to transfer electric charge to an object so that its net electric charge is 6.5 times the fundamental electric charge, e.
It's possible to transfer electric charge to an object so that its net electric charge is 6.5 times the fundamental electric charge e. it is a false statement. because any charge can only be integral multiple of the fundamental charge e.
What is electric charge?A neutral body gets charged if it gains or losses some electrons.
There are two types of charges: positive charge and negative charge.
It is the property of substances due to which a body produce and experience electric effect.
S.I. unit of charge is coulomb.
Q = It
Where, Q = charge,
I = electric current,
t = time
Quantisation of charge :charge is quantised. it means that charge on a body is always equal to the integral multiple of basic unit of charge i.e. charge of one electron.
Q = ne
e = 1.6 ×10^-19 C .
A charge of magnitude 1C contains about 6×10^18 electrons.
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Pressure is a derived quantity with a formula suxh as Force per unit area what do you think which base quantities will be involved to form this derived quantity.
Answer:
you can find answer in this
Explanation:
https://physics.nist.gov/cuu/Units/units.html
A ball is thrown up in the air and then caught 10 seconds later. How high did it go and what was the initial speed up? (6)
Answer:
high=125m
speed up=50m s-¹
Explanation:
consider acceleration due to gravity = 10m s-²
upward as positive
in t=5s
ball rest momentarily velocity=0
you can know this by drawing s-t graph
consider the upward movement t=0-5s
we now have v=0 t=5 a= -10 and need find u
so use a=[v-u]/t
-10=[0-u]/5
-50=-u
u=50 ms-¹
then let find the displacement
s = (v+u)t*1/2
s= 50*5*1/2
s=125m
10 pts the classic millikan oil drop experiment was the first to obtain an accurate measurement of the charge on an electron. in it, oil drops were suspended against the gravitational force by a vertical electric field. consider an oil drop with a weight of 1.2 x 10-14n, if the drop has a single excess electron, find the magnitude (in n/c) of the electric field needed to balance its weight. your should round your answer to an integer, indicate only the number, do not include the unit.
the magnitude of the electric field needed to balance its weight is
0.75 ×10⁵N/C
The oil drop method was performed by Robert A Millikan in 1909.
It is used to determine the size of the charge on an atom.
Millikan used vacuum pump oil for this his experiment.
to find out the magnitude of electric field
W = q E,
W = weight (W = mg)
q = charge (1.6×10⁻¹⁴C)
E = Electric field
→ oil drops were suspended against the gravitational force by a vertical electric field such that its weight is balanced by the electron force i.e.
W = 1.2× 10⁻¹⁴
1.2× 10⁻¹⁴ = q × E
E = 1.2× 10⁻¹⁴N/ 1.6×10⁻¹⁹C
E = 0.75 ×10⁵N/C
the magnitude of the electric field needed to balance its weight is
0.75 ×10⁵N/C
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A karate expert executes a swift blow and breaks a cement block with her bare hand. The magnitude of the force on her hand is.
3.141592653589793238
Explanation:
3.141592653589793238
A ray of light is incident at an angle of 30° on the angle through which the ray is minimally a glass prism of refractive index 1.5. Calculate deviated in the prism. (The medium surrounding the prism is air)
Typically, the "refracted angle" is used to refer to the "angle of deviation."
Snell's Law is simply applied in this case.
Since n1sin1 = n2sin2,
The incidence angle is 1
The refracted angle is 2
The appropriate indices of refraction are n1 and n2.
the standard value for air, n1, is 1.
n2 = 1.5
What is the first rule of Snell?As a result, the refractive indices of the two media may be related through the angle associated with incidence and refraction. The incident ray, the refracted ray, and the normal ray are all said to be on the same plane.
Snell's Law is particularly significant for optical technologies like fibre optics. According to Snell's Law, the refractive indices of the materials at the contact are proportional to the ratio of the sine of the angles of incidence and transmission.
The extension is obeyed by the e-ray Because the refractive index of an e-ray changes with the angle between the wave vector and optical axis, Snell's law applies. It is important to consider e-ray propagation in the uniaxial crystal.
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to determine your line of , you would need to know the angle your location (line) makes with the equatorial plane at earth's center.
To determine your line of latitude , you would need to know the angle your location (line) makes with the equatorial plane at earth's center.
What is Line of latitude?This is also referred to as parallels and it is defined as the imaginary lines that divide the Earth. They run from east to west and are used to specify the north and south sides of the Earth.
To determine the line of latitude , it is imperative to know the angle your location (line) makes with the equatorial plane at earth's center which is therefore the reason why it was chosen as the most appropriate choice.
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One pole of a magnet attracts a nail. Will the other pole of the magnet attract the nail? Explain. Also explain how a magnet sticks to a refrigerator door.
Yes, either pole generates a field that causes atoms within the iron to rotate in order to align their magnetic moments with the exterior field.
A magnet has a significant normal force acting on the door. The magnet is then held in place by frictional force.
What is a magnet?A magnet is defined as a magnetic field-producing item capable of attracting unlike poles and repelling similar poles.
Magnets are manufactured from a class of metals known as ferromagnetic metals. These metals include nickel and iron. These metals are unusual in their ability to magnetize consistently. When we ask how a magnet works, we mean how the magnetic field of a magnet affects the thing.
There are many different sizes and shapes of magnets.
Magnets can be found in a variety of objects and settings, including toys, cabinet hardware, ornamental pieces placed on refrigerators, and other objects and sites.
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A car increases its speed from 30 km/h to 60 km/h in 5 seconds. Its acceleration s (a) 1.66 m/s² (b) 5 km/h² (c) 16.6 km/h² (d) 5m/s²
Answer: 6 km/h²
Explanation:
Final Speed= 60 km/h
Initial Speed= 30 km/h
Time= 5 sec
Now,
60= 30 + Acceleration*5
⇒Acceleration = 6 km/h²
A bicyclist traveling at 5 m/s hits a fence, the bicyclist files over the fence. Which
of Newton's Laws does this BEST describe?
1.Newton’s 1st Law
2.Newton's 2nd Law
3.Newton's 3rd Law
The Newton's Laws that BEST describe the situation is Newton's second law of motion.
What is Newton's second law of motion?
Newton's second law of motion states, the force exerted by an object is directly proportional to the product of mass and acceleration of the object.
Also, the law can also be states as force is equal to the rate of change of momentum.
F ∝ Δp
Ft = m(v2 - v1)
The force exerted on the bicyclist by the fence is equal to the change in momentum of the bicyclist. The bicyclist was able to fly over the fence because there is a change in his momentum.
Thus, the Newton's Laws that BEST describe the situation is Newton's second law of motion.
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which truth did isaac newton’s investigations of gravity explain? jupiter has more moons than earth. jupiter has more moons than earth. the sun is more massive than earth. the sun is more massive than earth. gravity acts on all objects in the universe. gravity acts on all objects in the universe. earth is not the center of the universe. earth is not the center of the universe.
Newton's investigations of gravity explain the truth that Jupiter has more moons than Earth.
The fact that Jupiter has more moons than Earth was first discovered by Galileo Galilei in 1610, and it was later confirmed by Newton. In addition to having more moons, it is also thought that Jupiter may be home to some of the most powerful magnetic fields in the solar system.
What was explained by Isaac Newton's law of gravity?Every particle in the cosmos attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers, according to Newton's law of universal gravitation.
Thus, the equation for universal gravity has the following structure:
[tex]{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}}{\displaystyle[/tex]
where r is the distance between the centers of the two objects' masses, m1 and m2 are their respective masses, G is the gravitational constant, and F is the gravitational force acting between them.
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The correct answer is; Gravity acts on all objects in the universe.
The answer above is incorrect…
Find the net electric flux through (c) What can you conclude about the charges, if any, inside the cylindrical surface?
The net flux is positive so the charge in the cylinder is positive To be a uniform field, the field lines mug originate from a plane of charge The net charge inside the cylinder is positive and is distributed on a plane parallel to the ends of the cylinder.
Electric flux, property of an electric field that may be thought of as the number of electric lines of force (or electric field lines) that intersect a given area. Electric field lines are considered to originate on positive electric charges and to terminate on negative charges.
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The furniture was designed to go a top speed of 87.0mph. How far would this sofa travel to the mall 1.00 hour away?
The sofa with a top speed of 87 mph would travel a distance of 43.5 miles to the mall 1 hour away.
Considering the sofa accelerates constantly throughout the motion,
s = ( u + v ) t / 2
s = Distance
u = Initial velocity
v = Final velocity
t = Time
v = 87 mph
t = 1 hr
u = 0
s = ( u + v ) t / 2
s = ( 0 + 87 ) 1 / 2
s = 43.5 mi
This is an equation of motion.
Therefore, the sofa would travel a distance of 43.5 miles
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if you run off the pavement, you should: steer straight ahead and speed up steer straight and slow down before attempting to return to the pavement turn the steering wheel quickly toward the road apply the brakes hard submit answer
If you run off the pavement, you should turn the steering wheel quickly toward the road and is denoted as option C.
What is Pavement?This is a path which is found in almost all roads and is designed to enhance foot traffic in most climes. This is the path where individuals walk so as not to get hit down by a vehicle.
In a situation where a car runs into the pavement, the best choice is to turn the steering wheel quickly toward the road as braking hard could damage the brakes of the car and cause accident in subsequent trips.
This is therefore why option C was chosen as the correct choice.
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Answer: Steer straight and slow down before attempting
Explanation:
A nonconducting ring of radius 10.0 cm is uniformly charged with a total positive charge 10.0μC. The ring rotates at a constant angular speed 20.0 rad/ s about an axis through its center, perpendicular to the plane of the ring. What is the magnitude of the magnetic field on the axis of the ring 5.00 cm from its center?
The magnitude of the magnetic field on the axis of the ring 5 cm from its center is 143 pT.
The radius of the nonconducting ring is R = 10 cm.
The ring is uniformly charged q = 10 μC.
The angular speed of the ring, ω = 20 rad/s
The ring is x = 5 cm from the center of the ring.
Now,
R = 10 cm = 0.1 m
q = 10.0 μC = 10 × 10⁻⁶ C
x = 5 cm = 0.05 m
The magnetic field on the axis of a current loop is given as:
[tex]B =\frac{\mu_{0}IR^{2}}{4 \pi(x^{2}+R^{2})^{\frac{3}{2} }}[/tex]
Now, [tex]I = \frac{q}{\frac{2 \pi}{\omega} }[/tex]
So, the magnitude of the magnetic field which is directed away from the center is:
[tex]B =\frac{\mu_{0} \omega qR^{2}}{4 \pi(x^{2}+R^{2})^{\frac{3}{2} }}[/tex]
[tex]B = \frac{\mu_{0} \times(200) \times (10 \times 10^{-6}) \times (0.1)^{2}}{4 \pi((0.05)^{2}+(0.1)^{2})^\frac{3}{2} }[/tex]
B = 1.43 × 10⁻¹⁰ T
B = 143 pT
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The power output of a certain public-address speaker is 6.00W . Suppose it broadcasts equally in all directions.(b) At what distance from the speaker would the sound be barely audible?
The distance from the speaker would the sound be barely audible is 477.46km.
What is distance?It's how far away two objects or locations are measured numerically as distance. Distance in physics or common language can refer to a physical length or an assumption based on other factors (e.g. "two counties over"). Sometimes the symbol |AB| is used to indicate how far apart two points are. "Distance from A to B" and "Distance from B to A" are typically equivalent terms. A distance function or metric in mathematics is an extension of the idea of physical distance; it defines what it means for components in a space to be "near to" or "far away" from one another. Distance is a non-numerical unit of measurement in the social sciences and psychology.
Explanation:
Sound audible(barely) = 0dB
I= 10.709*I/[tex]10^{-10}[/tex]=0
I= [tex]10^{-12}[/tex]*[tex]10^{0}[/tex]=[tex]10^{-12}[/tex]w/[tex]m^{2}[/tex]
[tex]distance(r)=\sqrt[]{\frac{P}{4\pi I} } =\sqrt[]{\frac{6}{4\pi * 10^{-12} } } =477.46 km[/tex]
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a total charge of 300 c flows past a given cross section of a conductor in 30 seconds. what is the value of the current?
Explanation:
Q = charge in C(coulombs)
I = current in A(amps)
t = time in s(seconds)
Q = I × t
I = Q / t
Substitute in given values.
I = 300C / 30s
= 10A
Hope this helped! ^^
The electric current generated by a charge of 300 coulombs passing through the cross section of a conductor in a time of 30 seconds is: 10 A
To solve this exercise the formula for electric current and the procedure we will use is:
I= q/t
Where:
I = intensity of the electric currentq= electric charget = timeInformation about the problem:
q= 300 Ct = 30 sI=?1 C/s = 1 AApplying the electric current intensity formula we have:
I= q/t
I= 300 C / 30 s
I= 10 A
What is electric current intensity?In physics the intensity of the electric current is the magnitude that expresses the amount of electric charge or electric current in coulomb (c) that passes through an electrical conductor in a given time in seconds (s). Its unit of measurement in the international system is the Ampere (A).
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Plasma is one of the fundamental states of matter and consists of a:
A) liquid at high temperature
B) totally or partially ionized gas, electrically neutral
C) partially ionized gas, with electric charge
D) partially ionized liquid
E) partially ionized liquid, electrically neutral
Answer:
a
Explanation:
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A cubical surface surrounds a point charge q . Describe what happens to the total flux through the surface if (e) the charge is moved outside the surface.
Gauss law explains that the electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field.
Mathematically,
Φ=Q ϵo
Where;
Q is enclosed charge
ϵo is the permittivity of the free space
In the case where the charge is moved outside the surface, the flux in the electric field becomes zero because the enclosed charge becomes zero. Thus, the electric field will change due to the movement outside the surface. The only instances where flux is kept constant are when it is moved within the surface or the enclosing object is changed.
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Q|C The speed of a one-dimensional compressional wave traveling along a thin copper rod is 3.56 km/s . The rod is given a sharp hammer blow at one end. A listener at the far end of the rod hears the sound twice, transmitted through the metal and through air, with a time interval Δt between the two pulses.(d) Imagine that the copper rod is replaced by another material through which the speed of sound is v_r . What is the length of the rod in terms of t and v_r ?
The length of rod in terms v(r) and t is L = [ Δt / (1/343) - (1/v(r)) ].
3.56 km/s is the speed of a one-dimensional compressional wave moving along a thin copper rod.
At one end of the rod, a hard hammer strike is delivered. With a time interval of Δt between the two pulses, a listener at the other end of the rod hears the sound twice as it travels through the metal and the air.
The time interval is given by t = L/v.
We know, The speed of air, v(air) = 343 m/s
Now,
When the copper rod is swapped out for a different substance and the sound speed is measured as v(r).
The delay between pulses arrivals is:
Δt = L [(1/v(air)) - (1/v(copper))]
Then,
L = [ Δt / (1/v(air)) - (1/v(r)) ]
L = [ Δt / (1/343) - (1/v(r)) ]
Here L is the length of the rod, Δt is in seconds and v(r) is the speed of sound in the rod.
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an object of mass m is traveling at constant speed v in a circular path of radius r. how much work is done by the centripetal force on mass m during an angular displacement of 2π revolutions?: *
The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J
Centripetal force - a force acts on an moving object in circular path.
the centripetal force is given by
F= mv²/r (equation1)
Work done is given by
W = Fd (equation 2)
d = 2π
work is done by the centripetal force on mass m during an angular displacement of 2π revolutions is given by:
to calculate work done using equation 1 in 2 we get
W = mv² d/r
W = mv² × 2π /r J
The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J
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A small car weighs 10168.25 N. What is its mass?
Answer:
1036.5kg
...................
Consider cyclic processes completely characterized by each of the following net energy inputs and outputs. In each case, the energy transfers listed are the only ones occurring. Classify each process as (a) possible, (b) impossible according to the first law of thermodynamics, (c) impossible according to the second law of thermodynamics, or (d) impossible according to both the first and second laws.(vi) Input is 5J of energy transferred by heat, and output is 3J of work plus 2J of energy transferred b
The situation is possible based on the first law of thermodynamics.
What is thermodynamics?The term thermodynamics has to do with the study of heat. Heat is that which causes the temperature of a body to change. We know that according to the first law of thermodynamics, energy could neither be created nor destroyed but can be converted from one form to another.
The second law of thermodynamics states that, the conversion of energy is not 100% efficient as some of the energy could be lost as heat. We can now fit in the scenario described into the laws of thermodynamics.
We can see that, if we input is 5J of energy transferred by heat, and output is 3J of work plus 2J of energy transferred by heat, then the situation is possible based on the first law of thermodynamics.
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Help please ;((((((((
Answer:
42- electromagnetic force
Explanation:
electrons keep orbiting around the nucleus thanks to electromagnetic force :)
hope this helped!
Happens at the start of the game and after every touchdown. in flag football you may throw or punt the ball.
The correct answer is punt/kickoff
In gridiron football, a drive is started with a kickoff. The "kicking team" often kicks the ball to the "receiving team" of the opposite team during a kickoff. Until the player with the ball is tackled by the kicking team, goes out of bounds, scores a touchdown, or the play is otherwise deemed dead, the receiving team is then allowed to return the ball, i.e., attempt to move it towards the kicking team's end zone. Every half of play, the start of various overtime forms, and after scoring plays all feature kickoffs. At the beginning of each half, following a try, and following a successful field goal, the ball is sent into play through a kickoff.
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Complete question
Happens at the start of the game and after every touchdown. in flag football you may throw or punt the ball. options 1. Interception 2. Fumble
3. Punt/Kickoff 4. Down
special clothes needed or worn in church
Answer: If you want to know how to dress for church, something modest and comfortable should be fine. Generally, graphic tees that show off sports team logos or bands should never be worn to church. Solid-colored tops are fine, and even something with a pattern should be OK to wear.
Explanation:
Review. For a certain type of steel, stress is always proportional to strain with Young's modulus 20 × 10¹⁰ N/m² . The steel has density 7.86× 10³kg / m³. It will fail by bending permanently if subjected to compressive stress greater than its yield strength бy = 400MPa. A .rod 80.0cm long, made
of this steel, is fired at 12.0 m/s straight at a very hard wall.(b) After the front end of the rod hits the wall and stops, the back end of the rod keeps moving as described by Newton's first law until it is stopped by excess pressure in a sound wave moving back through the rod. What time interval elapses before the back end of the rod receives the message that it should stop?
[tex]1.58\times 10^{-4}\ \mathrm{s}$[/tex] is the time interval elapses before the back end of the rod receives the message that it should stop.
Given:
Length of the rod, L = 80 cm = 0.800 m
Young's modulus, Y = [tex]20 \times 10^{10}\;N/m^{2}[/tex]
steel density, [tex]\rho = 7.86 \times 10^{3}\;kg/m^{3}[/tex]
The speed of the wave in the rod is,
[tex]$v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$[/tex]
Consequently, the length of the rod's end is traveled by the wave in at
[tex]$t=\frac{L}{v} = \frac{0.800\ \mathrm{m}}{5044\ \mathrm{m/s}} = 1.58\times 10^{-4}\ \mathrm{s}$[/tex]
Hence, [tex]1.58\times 10^{-4}\ \mathrm{s}$[/tex] is the time interval elapses before the back end of the rod receives the message that it should stop.
What are Newtons Laws?The three fundamental laws of classical mechanics known as Newton's laws of motion describe how an object's motion and the forces acting on it interact. The following paraphrase of these statutes is available
Unless a force acts upon a body, it remains at rest or in continual straight-line motion.
When a force acts on a body, the force is equal to the time rate at which the body's momentum changes.
When two bodies exert force on one another, the direction and amount of the force are opposed.
Isaac Newton first identified the three laws of motion in his 1687 book Philosophize Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy).
They served as the cornerstone for classical mechanics as Newton used them to examine and explain the motion of numerous physical objects and systems. The conceptual foundations of classical physics have been reconstructed in several ways since Newton, utilizing various mathematical techniques that have revealed insights that were hidden in the original, Newtonian formulation.
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a rocket was launched into the air from a podium 6 feet off the ground. the rocket path is represented by the equation h(t)
The average rate of change of height from the initial launch to the maximum height is 180 feet.
The given function is
[tex]h(t) = -16t^{2} +120t+6[/tex]
The average rate of change of h(t) from t=a to t=b is given by:
[tex]\frac{h(b)-h(a)}{b-a}[/tex]
Vertical Velocity will be zero at maximum height. To find maximum height we differentiate the equation to get an equation for the velocity and set it to zero.
On differentiating we get,
h'(t) = -16(2)t + 120
h'(t) = -32t + 120
now equating to zero we get
t = 3.75 s
This is the time at which the rocket reaches maximum height.
The initial launch occurs at t = 0
substituting it in the original equation we get
[tex]h(t)[/tex] = [tex]-16(0)^{2}+120(0)+6[/tex]
[tex]h(t) = 6[/tex]
The average rate of change from the initial launch to the maximum height is:
[tex]\frac{h(3.75)-h(0)}{3.75-0}[/tex]
= [tex]\frac{681-6}{3.75}[/tex]
= 180
Hence the average rate of change from the initial launch to the maximum height is 180 feet.
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A tank for compressed gas has a maximum safe pressure limit of 850 kPa. The pressure
gauge reads 425 kPa when the temperature is 28°C. What is the highest temp in degrees
Celsius the tank can withstand safely?
Which question would best determine how electromagnetic and mechanical waves are similar?
The question 'How do electromagnetic and mechanical waves compare?'
There are many similarities between electromagnetic waves and mechanical waves.
In Physics, both electromagnetic and mechanical waves have amplitude, wavelength, and frequency.
Electromagnetic waves can travel through empty spaces as well such as vacuums, gases, liquids, and solids.
While mechanical waves can not propagate through space they can only travel through liquids, solids, and gases.
water waves and ripples in a pool are examples of mechanical waves.
Examples of EM waves are radio signals and light waves, microwaves, and X-rays.
To put it simply, EM waves do not require a medium to travel whereas mechanical waves require a medium to propagate.
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