The radius of the spherical ball is 4.32_+0.01m.what does it mean?​

The component that Chang could leave out and still be able to light up the bub is the switch.

The electric circuit refers to a path that is created for the flow of current. We know that current is the movement of electrons. When we connect a circuit, a proper conduit has been set up so that electrons can pass through.

In this case, we have been told that Chang wants to build a circuit that will light up a bulb from a flashlight, and has a battery, switch, wire, and a light bulb.

The component that Chang could leave out and still be able to light up the bub is the switch.

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Missing parts;

Chang wants to build a circuit that will light up the bulb from a flashlight. Which component could Chang leave out and still light up the bulb? the switch the battery the wire the light bulb

Answer:

A) the battery

Explanation:

The range of potential energies of the wire-field system for different orientations of the circle are -

θ                  U

0°             375 π x [tex]10^{-7}[/tex]

90°              0

180°        - 375 π x [tex]10^{-7}[/tex]

We have current carrying wire in a form of a circle placed in a uniform magnetic field.

We have to the range of potential energies of the wire-field system for different orientations of the circle.

The formula to calculate the magnetic potential energy is -

U = M.B = MB cos [tex]$\theta[/tex]

where -

M is the Dipole Moment.

B is the Magnetic Field Intensity.

According to the question, we have -

U = M.B = MB cos [tex]$\theta[/tex]

We can write M = IA (I is current and A is cross sectional Area)

U = IAB cos [tex]$\theta[/tex]

U = Iπ[tex]r^{2}[/tex]B cos [tex]$\theta[/tex]

For [tex]$\theta[/tex] = 0° →

U(Max) = MB cos(0) = MB =  Iπ[tex]r^{2}[/tex]B = 5 × π × [tex]( 0.05 ) ^{2}[/tex] × 3 × [tex]10^{-3}[/tex] =

375 π x [tex]10^{-7}[/tex].

For [tex]$\theta[/tex] = 90° →

U = MB cos (90) = 0

For [tex]$\theta[/tex] = 180° →

U(Min) = MB cos(0) = - MB =  - Iπ[tex]r^{2}[/tex]B = - 5 × π × [tex]( 0.05 ) ^{2}[/tex] × 3 × [tex]10^{-3}[/tex] =

- 375 π x [tex]10^{-7}[/tex].

Hence, the range of potential energies of the wire-field system for different orientations of the circle are -

θ                  U

0°             375 π x [tex]10^{-7}[/tex]

90°              0

180°        - 375 π x [tex]10^{-7}[/tex]

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Answer:

your answer is D

Explanation:

..........

Answer:

d

Explanation:

UsaTestPrep

The bat's observation of the echo's frequency is 41.2 kHz

A bat flies speedily in this problem [tex]$$v_{\text {bat }}=5.0 \mathrm{~m} / \mathrm{s}$$[/tex] .

It makes a frequency chirp [tex]$$f_S=40 \mathrm{kHz}=4.0 \times$$10^{4} Hz.[/tex]

An adjacent wall reflects the sound. We determine the echo's frequency based on the bat's observations.

(b) Sound propagates at a speed of [tex]v=345 \mathrm{~m} / \mathrm{s}[/tex]

The sound will undergo two Doppler shifts. The first Doppler change occurs when the sound travels toward the wall, and the second Doppler shift occurs as the sound returns to the bat.

     [tex]\begin{aligned}f_{O, 1} &=f_S\left(\frac{v+v_O}{v-v_S}\right) \\&=f_S\left(\frac{v+0}{v-\left(+v_{\mathrm{bat}}\right)}\right) \\f_{O, 1} &=f_S\left(\frac{v}{v-v_{\mathrm{bat}}}\right)\end{aligned}[/tex]

The moving bat, which moves in the direction of the source, serves as the observer in the second Doppler shift. The wall that isn't moving is the source. The bat's frequency observations must be

[tex]\begin{aligned}f_{\text {echo }} &=f_{O, 1}\left(\frac{v+v_O}{v-v_S}\right) \\&=f_{O, 1}\left(\frac{v+\left(+v_{\text {bat }}\right)}{v-0}\right) \\&=f_{O, 1}\left(\frac{v+v_{\text {bat }}}{v}\right) \\&=f_S\left(\frac{v}{v-v_{\mathrm{bat}}}\right)\left(\frac{v+v_{\text {bat }}}{v}\right) \\\Rightarrow f_{\text {echo }} &=f_S\left(\frac{v+v_{\mathrm{bat}}}{v-v_{\mathrm{bat}}}\right)\end{aligned}[/tex]

By substituting values in the equation, we get

   [tex]\begin{aligned}f_{\text {echo }} &=f_S\left(\frac{v+v_{\text {bat }}}{v-v_{\text {bat }}}\right) \\&=\left(4.0 \times 10^4 \mathrm{~Hz}\right)\left(\frac{345+5.0}{345-5.0}\right) \\&=4.11765 \times 10^4 \mathrm{~Hz} \\f_{\text {echo }} &=41.2 \mathrm{kHz}\end{aligned}[/tex]

Hence, The bat's observation of the echo's frequency is 41.2 kHz.

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Considering the conversion between Celsius degree and Fahrenheit degree, the correct answer is option (e): -25°C is equivalent to -13 Fahrenheit temperature.

The Celsius degree, represented as °C, is the unit created by Anders Celsius. This scale is also called the "Centigrade scale" and in it the temperature is divided into 100 degrees, with 0º C being the freezing point of water and 100º C the boiling point of water.

The Fahrenheit degree is the unit of temperature proposed by Gabriel Fahrenheit in 1724, whose scale sets zero and one hundred in the freezing and evaporation temperatures of ammonium chloride in water. On this temperature scale, unlike the Celsius scale, the freezing point of water is 32º F while the boiling point of water is 212º F.

To perform the conversion, the expression must be applied:

°F= °C× 9/5 + 32

On a very cold day in upstate New York, the temperature is -25°C. Fahrenheit temperature is calculated as:

°F= (-25°C)× 9/5 + 32

Solving:

°F= -13

In summary, the correct answer is option (e): -25°C is equivalent to -13 Fahrenheit temperature.

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Two motorcycles start at the same point, one motorcycle travels 15 km due north and stops, the second motorcycle travels 32 km due west and stops, value closest to the distance between the motorcycles when they stop is 35.3 km.

In general, kilometers to miles is the conversion of distance from the kilometers to miles. kilometers and miles are used to measure length from one point to the other. In metric system, kilometer is the unit of length and it is considered as the International System of Units, whereas miles are used in the imperial and US customary units. The kilometer is abbreviated as “km”, and mile is abbreviated as “mi”. These two measures are mostly used to measure the geographical land areas.

You are aware that hypotenuse of a right triangle is shorter than the total of the legs and longer than the longest leg.

The relevant distance in this geometry is greater than the 32 km and less than 15+32 = 47 km. The only option that falls within acceptable range is 35.3 kilometers.

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Answer:

happy holidays

Explanation:

Answer:

The water cycles energy source comes from the sun

Explanation:

The sun's solar energy helps evaporate water from several bodies of water which causes the process of transportation

Answer:

5600 + 6650 = 12250

Explanation:

Answer:

C. 25.0%

Explanation:

Radioactive decay of an atom follows the equation:

ln[A] = -kt + ln[A]₀

Where [A] could be taken as an amount of radioactive atom after time t,

k is rate constant = ln 2 / Half-Life = ln 2 / 6hours = 0.1155hours⁻¹

[A]₀ is initial amount of the isotope = 100%

Replacing:

ln[A] = -0.1155hours⁻¹ *12hours+ ln[100%]

ln[A] = 3.2192

[A] = 25.0%

Right solution is:

C. 25.0%

Answer:

How we know, the equation is:

W = mg

Replacing according our data:

W = 53 kg × 9,8 m/s^2

Resolving:

W = 519,4 N

The weight of the object is of 519,4 Newtons.

The oxygen gas has  root mean square velocity of 1651.67 m/s.

What is specific heat capacity ?

Scientifically, specific heat capacity is the quantity of heat (J) absorbed by a material when its temperature increases 1 K (or 1 °C) per unit mass, expressed as J/(kg K) or J/(kg °C).

Q = mCΔT

Calculation of temperature of oxygen gas is done below using formulae :

V(rms) = √3RT/M

where;

M is molar mass of oxygen gas = 32 g/mol = 0.032 kg/mol

value of gas constant R = 8.314 J/K.mol

T is temperature of the oxygen gas = 77+273 = 350 k

V(rms) = √3RT/M

V(rms) = √(3x8.314x350)/0.032

V(rms) = √87297/0.032

V(rms) = √2728031.25

V(rms) = 1651.67 m/s

Thus, The oxygen gas has root mean square velocity of 1651.67 m/s.

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Answer:

Making the lumber thick will make it stiff, which seems good. On the other hand, with thicker lumber, differences in expansion on the two faces have more leverage to make the lumber move.

Answer: The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.

Explanation:

The energy transfer to the kinetic store of the motor will be less than 800 J because some of the energy is dissipated in the surrounding.

A piece of electrical equipment that is used to supply power to the electrical load is called an electric power supply.

The basic objective of this device is to transfer power from the source to the consumer with the correct amount of voltage, frequency, and current.

Furthermore, this device transforms alternative current (AC) into low voltage direct current (DC).

It consists of four major elements: filter, transformer, regulator circuits, and rectifier.

To put it simply, a power supply transforms Ac voltage to DC voltage.

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Answer:

kinetic energy is the answer

Explanation:

kinetic energy is movement

The tension in the rod when the ratio of speed is 8 is 1.34 × 10⁴ N.

The longitudinal waves speed is determined using the density of the material and the Youngs modulus with the expression:

v = √(Y/rho)

A wave in a stretched string can be used to represent the transverse wave.

The length of the metal rod is 150 cm and the radius of the rod is  cm.

The mass of the rod is 50.9 g.

Now, the Youngs modulus for the material is 6.80× 10¹⁰ N/m².

For the longitudinal wave

v(l) = (Y/ρ)^{1/2}

For the transverse wave :

v(T) = (Y/μ)^{3/2}

Now, we need

v(L) / v(T) = 8

And we know,

T = (μY) / (64ρ) where μ= m /L

And the density, ρ = mass / volume = (m) / (πr²L)

Therefore,

T = (πr²Y) / 64

T =  (π)(2 × 10⁻³)² × (6.8 × 10¹⁰) / 64

T = 1.34 × 10⁴ N

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Answer:

d

Explanation:

because ik igvddhh56yfdsaw66 u77rfgtd gyy f music nutren

Answer:

The object's velocity would increase due to the change in force.

Explanation:

Answer:

9.3e-8 Meters

Answer:

D. Validity group

Explanation:

A validity group is not necessarily a component of a normal experiment.

A normal experiment is made up of the dependent variables, independent variables, and most times the control group.

The electric force on a due to b in component form = [tex]\bold{0\vec i+72\times10^{-9}\vec j\ N}[/tex]

Charge of A = 4 nC = [tex]4\times 10^{-9}[/tex] C

Charge of B = -8 nC = [tex]-8\times 10^{-9}[/tex] C

A is on the origin, (0,0) and B is at the point (0 cm,2cm).

Therefore, distance between charges A and B, r = [tex]\sqrt{(0-0^2)+(0-2)^2} =2[/tex]

Using Coulomb's law, the electric force is directly proportional to the product of charges and inversely proportional to the square of distance between charges.

i.e., [tex]F_{A\ on\ B}=\frac{kq_1q_2}{r^2}[/tex], where k = [tex]9\times 10^9 Nm^2C^{-2}[/tex], the Coulomb constant.

So [tex]F_{A\ on\ B}=\frac{9\times 10^9\times 4\times 10^{-9}\times 8\times 10^{-9}}{2^2} = \bold{72\times 10^{-9} N}[/tex]

Since there is no x-component for this force,

the electric force on a due to b in component form = [tex]\bold{0\vec i+72\times10^{-9}\vec j\ N}[/tex]

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Object A, which has been charged to +4.0 nC is at the origin. Object B, which has been charged to -8.0 nC, is at (x, y)=(0.0 cm, 2.0 cm).  What is the electric force on A due to B in component form? Express your answer in terms of the unit vectors i and j. Use the 'unit vector button to denote unit vectors in your answer.

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The total time taken by the ball to reach Dina is  7.5 × 10³ s.

A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.

If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.

In the frame S', Dina and Owen are at rest.

The speed of the ball with respect to Owen, u =0.800c

The speed of the frame S' with respect to frame S,  v = 0.600c

Distance between Dina and Owen, L(p) = 1.8 × 10¹² m

Speed of light, c = 3 × 10⁸ m/s

Therefore, the ball reaches Dina in time:

t = L(p) / u

t = 1.8 × 10¹² m / 0.8c

t = 1.8 × 10¹² m /(0.8)(3 × 10⁸ m/s)

t = 7.5 × 10³ s

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The two forces that act on the orbit of a planet are velocity of planet and gravity between sun and planet.

The force that pulls items toward the center of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity. Gravity applies to everything that has mass. Gravity is stronger for objects with higher mass. Along with distance, gravity weakens as well. Therefore, the gravitational pull of two things becomes stronger the closer they are to one another.

The mass of the Earth is what creates gravity. The combined gravitational force of all of its mass acts on the mass in your body.

Velocity of the planet is also related to its gravity.

Forces that acts on the orbit of a planet is force due to velocity and gravity.

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