Answer:
The potential of energy availability at all locations where there is Sunlight
Explanation:
One advantage in owning a solar car is the potential of energy availability
The solar car source of energy is from the Sun which is readily available during the daytime where there is a clear sky. The energy from sunlight is converted to to electrical energy by the photovoltaic cells on solar panels installed on the roof area of solar powered cars
The energy from the Sunlight is a form of renewable energy and therefore allows for better stability as well as the possibility of reuse of the energy
There are no emissions from the use of solar cars including noise, making the solar car very environmentally friendly.
Which of the following atoms has the largest atomic radius? Provide an explanation
a Hydrogen
b. Sodium
C Lithium
d Rubidium
Answer:
Rubidium 265 pm
Explanation:
As can be seen in the figures below, the atomic radius increases from top to bottom in a group, and decreases from left to right across a period
Hydrogen 53 pm
Lithium 167 pm
Sodium 190 pm
The English system is used as the International System of Measurement. Please select the best answer from the choices provided T F
Need help please: How many mL of 0.150 Molarity CaBr2 solution must be used to react with 50 mL of 0.115 Molarity AgNO3?
CaBr2 + 2AgNO3 --> Ca(No3)2 + 2AgBr
Answer:
0.019 L or 19.1 mL
Explanation:
Given the equation of the reaction; we have:
CaBr2 + 2AgNO3 --> Ca(No3)2 + 2AgBr
We must first obtain the number of moles of AgNO3 reacted. This can be obtained from;
Concentration of AgNO3 reacted= 0.115 M
Volume of AgNO3 reacted= 50 ml
Since
Number of moles of AgNO3= concentration of AgNO3 × volume of AgNO3
Number of moles = 0.115 M × 50/1000 = 5.75 ×10^-3 moles
From the reaction equation;
2 moles of AgNO3 reacts with 1 mole of CaBr2
5.75 ×10^-3 moles of AgNO3 reacts with 5.75 ×10^-3 moles × 1 /2 = 2.875×10^-3 moles of CaBr2
Now;
Number of moles of CaBr2= concentration of CaBr2 × volume of CaBr2
Number of moles of CaBr2= 2.875×10^-3 moles
Volume of CaBr2= ????
Concentration of CaBr2= 0.150 M
Hence;
Volume of CaBr2= number of moles of CaBr2/ concentration of CaBr2
Volume of CaBr2= 2.875×10^-3 moles / 0.150
Volume of CaBr2= 0.019 L or 19.1 mL
Answer:
19 mL of CaBr₂ solution should be used to react with AgNO₃
Explanation:
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react:
AgNO₃: 2 molesCaBr₂: 1 mole50 ml of 0.115 M AgNO₃ react. Since molarity is the number of moles of solute per liter of solution, then you can do the following rule of three: if there are 0.115 moles of AgNO₃ in 1 L, in 0.05 L (being 1 L = 1000 mL, then 50 mL = 0.05 L How many moles are there?
[tex]moles of AgNO_{3}=\frac{0.05L*0.115 moles}{1 L}[/tex]
moles of AgNO₃=5.75*10⁻³
Now we can make a new rule of three to calculate the amount of moles necessary for CaBr₂ to react with moles of AgNO₂: if stoichiometry 2 moles of AgNO₃ react with 1 mole of CaBr₂, 5.75*10⁻³ moles of AgNO₃ with how many moles of CaBr₂ react ?
[tex]moles of CaBr_{2} =\frac{5.75*10^{-3}moles of AgNO_{3}*1 mole of CaBr_{2} }{2moles of AgNO_{3}}[/tex]
moles of CaBr₂=2.875*10⁻³ moles
Being 0.150 the molarity of the CaBr₂ compound, you can apply the following rule of three: if by definition of molarity 0.150 moles are in 1 L, 2.875 * 10⁻³ moles in how much volume is it present?
[tex]volume=\frac{2.875*10^{-3} moles*1L}{0.150 moles}[/tex]
volume=0.019 L
Being 1 L = 1000 mL, then 0.019 L = 19 mL
19 mL of CaBr₂ solution should be used to react with AgNO₃
PLS HELP!! Need help with this asap.
Answer:
22.6881 Grams of CO
Explanation:
Fe2O3 + 3CO = 3CO2 + 2Fe
Ratio
1:3 = 3:2
How many grams of CO are needed to produce 30.2 grams of Fe
Fe2O3 Molar mass: 159.69 g/mol
CO Molar mass: 28.01 g/mol
Fe Atomic mass: 55.845
Ok so our end result is 30.2 Grams of Fe, we have 2 Fe so we have 15.1 Grams per Fe
15.1/55.845 = 0.27
So then we multiply this by 3 as we we know the ratio and get get 0.81 required as this is 3CO.
So we need 0.81 Moles of CO so we need 22.6881 Grams of CO.
How does the size of the atoms relate to how reactive it is?
Answer: nucleus
Explanation: the bigger the nucleus there more reactive the atom is
Answer:
The larger an atom is, the more reactive it will be.
It helps to think about the size of an atom with the location of the electrons and nucleus in mind. You know that protons are positively charged and electrons are negatively charged, therefore there is a level of attraction between these two oppositely charged subatomic particles. This attraction helps stabilize the atom.
Now, in a larger atom, with more electrons are those electrons (specifically the valence electrons) going to be closer or further from the nucleus than in a smaller atom?
They will of course be further from the nucleus and therefore further from the positively charged nucleus. This makes it easier for the valence electrons to leave the atom and form an ionic bond or to interact with another atom to form a covalent bond.
If electrons can leave more easily, then the atom is more likely to react.
Cracking of octane please help! Show the chemical formula and the diagrams
Answer:
Fuels made from oil mixtures containing large hydrocarbon molecules are not efficient as they do not flow easily and are difficult to ignite. Crude oil often contains too many large hydrocarbon molecules and not enough small hydrocarbon molecules to meet demand. This is where cracking comes in
Explanation:
What happens at the particle level during a chemical reaction?
Answer:
Reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.RT
Explanation:
Nonrenewable resources are ?
Answer:
limited resources
Explanation:
nonrenewable resources are those resources found inside the earth that are in a fixed amount. They are being used at a faster rate, and cannot be renewed. These resources include fossil fuels,natural gas, and coal.
// have a great day //
In a undisturbed layer, how do we know which layer was deposited first ?
Answer:
It's the bottom layer.
Explanation:
Scientists use the Law of Superposition to determine the relative age of a layer of sedimentary rock:
The oldest rock layer is at the bottom of an undisturbed bed.
Thus, Layer A in the figure below was deposited first.
How is a muscle mutation potentially linked to the size of our brain?
Answer:
I found on internet may be it helps
Explanation:
Here, we provide a general review of recent studies into the genetic basis of human brain evolution. The insights gleaned from these studies can be broadly divided into three categories: (i) positive selection on protein-coding regions of the genome that lead to changes in the sequences of existing proteins; (ii) duplication and deletion of genes; and (iii) evolutionary changes in non-coding regions of the genome, especially those in cis-regulatory sequences that lead to altered gene expression .
What’s the answer to this question?
Answer:
“The answer to this question” is more general. The preposition to denotes assignment - that the answer is being “applied” to the question, whether the answer is right or wrong. Conceptually, that makes a lot more sense than the previous one. This is also the more common usage.
Determine the power of 900 joules of work done in 4 seconds
A) 3600 W
B) 225 W
C) 904 W
D) 450 W
Answer:
B. 225 W
Explanation:
Power is the measure of the amount of work done in a certain time frame. It can be found using the following formula.
p=w/t
where w is the amount of work done in joules and t is the amount of time in seconds.
We know that 900 joules of work was done in 4 seconds.
w=900 J
t= 4 s
Substitute these values into the formula.
p=900 J/ 4 s
Divide 900 by 4
900/4=225
p= 225 J/s
1 Joules of work per second (J/s) is equal to 1 Watt (W). Therefore, we can substitute Watts for Joules per second.
p= 225 Watts
The power is 225 Watts, and the correct answer is B.
Which type of reaction is described by the following equation? Na2O (s) + 2CO2 (g) + H2O (g) produces 2NaHCO3 (s)
Answer:
If the reaction is going from left to right it would be synthesis, if going right to left it would be decomposition.
Explanation:
Na2O (s) + 2CO2 (g) + H2O (g) = 2 NaHCO3 (s)
Left Side
Na = 2
O = 6
C = 2
H = 2
Right Side
Na = 2
O = 6
C = 2
H = 2
Ok so is balanced already, though initial equation in question had an error in regards to the left hand side the ) should have been an O.
Hmm
Na2O (s) + 2CO2 (g) + H2O (g) = 2 NaHCO3 (s)
If it was going from right to left would be decomposition
But going from left to right it would be synthesis
The following half-reaction can be balanced in acidic solution:
N2O5 --> NH4+
How many electrons appear in the balanced equation?
A. 13e-
B. 14e-
C. 16e-
D. 18e-
Answer:
None of them, answer seems to be 24 unless I messed up
Explanation:
How many electrons appear in the balanced equation
What the heck do they mean, do they mean transferred?
N2O5 --> NH4+
Left Side
N 5+ Electrons 2 in central shell, 5 in outer
O 2- Electrons 2 in central shell, 6 in outer
Right Side
H 1+ Electrons 1 in central shell
N 3- Electrons 2 in central shell, 5 in outer
Hmm, ok so need to balance the half equation first, this is a redox reaction.
Hmm, so it's going to be something like
H2 + N2O5 → NH + O3
Step 1. Write down the unbalanced equation ('skeleton equation') of the chemical reaction. All reactants and products must be known. For a better result write the reaction in ionic form.
H2 + N2O5 → NH + O3
Step 2. Separate the process into half reactions. A redox reaction is nothing but both oxidation and reduction reactions taking place simultaneously.
a) Assign oxidation numbers for each atom in the equation. Oxidation number (also called oxidation state) is a measure of the degree of oxidation of an atom in a substance (see: Rules for assigning oxidation numbers).
H02 + N+52O-25 → N-1H+1 + O03
b) Identify and write out all redox couples in reaction. Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). Write down the transfer of electrons. Carefully, insert coefficients, if necessary, to make the numbers of oxidized and reduced atoms equal on the two sides of each redox couples.
When one member of the redox couple is oxygen with an oxidation state of -2 or hydrogen with an oxidation state of +1, it is best to replace it with a water molecule.
O:3H+12O-2 → O03 + 6e-(O)
H02 → H+12O-2 + 2e-(H)
R:N+52O-25 + 12e- → 2N-1H+1(N)
c) Combine these redox couples into two half-reactions: one for the oxidation, and one for the reduction (see: Divide the redox reaction into two half-reactions).
O:3H+12O-2 + H02 → O03 + H+12O-2 + 8e-
R:N+52O-25 + 12e- → 2N-1H+1
Step 3. Balance the atoms in each half reaction. A chemical equation must have the same number of atoms of each element on both sides of the equation. Add appropriate coefficients (stoichiometric coefficients) in front of the chemical formulas to balance the number of atoms. Never change any formulas.
a) Balance all other atoms except hydrogen and oxygen. We can use any of the species that appear in the skeleton equations for this purpose. Keep in mind that reactants should be added only to the left side of the equation and products to the right.
O:3H+12O-2 + H02 → O03 + H+12O-2 + 8e-
R:N+52O-25 + 12e- → 2N-1H+1
b) Balance the charge. For reactions in an acidic solution, balance the charge so that both sides have the same total charge by adding a H+ ion to the side deficient in positive charge.
O:3H+12O-2 + H02 → O03 + H+12O-2 + 8e- + 8H+
R:N+52O-25 + 12e- + 12H+ → 2N-1H+1
c) Balance the oxygen atoms. Check if there are the same numbers of oxygen atoms on the left and right side, if they aren't equilibrate these atoms by adding water molecules.
O:3H+12O-2 + H02 + H2O → O03 + H+12O-2 + 8e- + 8H+
R:N+52O-25 + 12e- + 12H+ → 2N-1H+1 + 5H2O
Balanced half-reactions are well tabulated in handbooks and on the web in a 'Tables of standard electrode potentials'. These tables, by convention, contain the half-cell potentials for reduction. To make the oxidation reaction, simply reverse the reduction reaction and change the sign on the E1/2 value.
Step 4. Make electron gain equivalent to electron lost. The electrons lost in the oxidation half-reaction must be equal the electrons gained in the reduction half-reaction. To make the two equal, multiply the coefficients of all species by integers producing the lowest common multiple between the half-reactions.
O:3H+12O-2 + H02 + H2O → O03 + H+12O-2 + 8e- + 8H+| *3
R:N+52O-25 + 12e- + 12H+ → 2N-1H+1 + 5H2O| *2
O:9H+12O-2 + 3H02 + 3H2O → 3O03 + 3H+12O-2 + 24e- + 24H+
R:2N+52O-25 + 24e- + 24H+ → 4N-1H+1 + 10H2O
Step 5. Add the half-reactions together. The two half-reactions can be combined just like two algebraic equations, with the arrow serving as the equals sign. Recombine the two half-reactions by adding all the reactants together on one side and all of the products together on the other side.
9H+12O-2 + 2N+52O-25 + 3H02 + 24e- + 3H2O + 24H+ → 3O03 + 4N-1H+1 + 13H2O + 24e- + 24H+
Step 6. Simplify the equation. The same species on opposite sides of the arrow can be canceled. Write the equation so that the coefficients are the smallest set of integers possible.
2N+52O-25 + 3H02 → 3O03 + 4N-1H+1 + H2O
22.00 g of CO2 has a volume of 50.00 L and a pressure of 0.8210 atm. What must be the
temperature of the gas?
Answer:
T = 9.875K
Explanation:
The ideal gas Law is PV = nRT.
P = Pressure
V = Volume
n = amount of substance
R = 8.314 J/(K. mol)
T = Temperature in Kelvin
22g CO2
CO2 Molar Mass = 44g/mol
C = 12g/mol
O = 16g/mol
P = 0.8210atm
V = 50L
PV = nRT
0.8210 x 50 = 8.314 x 0.5 x T
41.05 = 4.157T
T = 41.05/4.157
T = 9.875K
PLZ HELP QUICKLY!!!!!!!!
Portfolio: Reflection
Review everything from your portfolio thoughtfully. Answer the following questions carefully and specifically. Use your answers as a guide to prepare for your presentation. Your presentation will focus on your goals and your development and improvements this semester. As you answer these questions, evaluate your strengths as a student. Consider how your growth this semester has prepared you for advancement. Use complete sentences or a paragraph to respond to each item.
WHAT DOES THIS QUESTION MEAN: When you look through your portfolio, what improvements do you notice in your work?
What do they mean by WORK?
Answer:
they meen like what youve learned or like what youve been tonight....all that is work stuff you did for example school work.
hi:)) how to do 5? I’m not sure if it’s hydrogen carbonate or carbonate
Answer:
copper(ll) carbonate
Explanation:
Since the product is a salt which is copper(II) carbonate, water and carbon dioxide, this reaction is an acid + metal carbonate reaction.
Looking at the salt, Cu²⁺ has to be part of the reactants.
Hence, the missing compound there has to be copper(ll) carbonate, CuCO₃.
The balanced chemical equation would be:
CuCO₃ + 2HNO₃➙ Cu(NO₃)₂ +H₂O +CO₂
P.s. You left out CO₂ as a product in Q2 ;)
Just a recap of the main reactions you would've learnt:
1) Acid + base/ alkali ➙ salt + water
2) Acid + metal ➙ salt + hydrogen gas
3) Acid + metal carbonate ➙ salt + H₂O + CO₂
how can the hemlock woolly upset natural ecosystem?
Answer:
The HWA attacks eastern hemlock trees in forests and ornamental hemlock trees found in our residential landscaping. It feeds on the hemlock trees' young twigs by sucking the sap, causing their buds to die and needles to dry out and drop from the plant prematurely i think
hope i helped!!
Is Raisin Bran cereal with milk homogeneous
Answer:
no
Explanation:
Homogeneous means that the substance looks uniform throughout. This means that all of it looks the same (ex. juice or water). Because you can see the different parts of raisin bran cereal with milk it is not homogeneous, it is heterogeneous.
Which state of matter is by high density and definite shape?
A. Solid
B. Liquid
C. Both Liquid and Solid
D. Gas
Answer:
Solid
Explanation:
Solid has a definite shape and its molecules have high density.
Hope this will help you.
An ice freezer behind a restaurant has a freon leak, releasing 41.60 g of C2H2F3Cl into the air every week. If the leak is not fixed, how many kilograms of fluorine will be released into the air over 6 months? Assume there are 4 weeks in a month. mass of fluorine leaked over 6 months:
A scuba tank contains air at 2975 psi and 25°C. The tank is left in a car in the
hot sun and the temperature increases to 44°C. What will be the pressure (psi)
in the tank?
Answer:
The new pressure is 3164.58 psi.
Explanation:
We have,
Initial pressure, [tex]P_1= 2975\ psi[/tex]
Initial temperature, [tex]T_1=25^{\circ}=298.15\ K[/tex]
The tank is left in a car in the hot sun and the temperature increases to 44°C, [tex]T_2=44^{\circ} =317.15\ K[/tex]
Let [tex]P_2[/tex] is the final pressure in the tank. Gay Lussac's law,
[tex]P\propto T\\\\\dfrac{P_1}{P_2}=\dfrac{T_1}{T_2}\\\\P_2=\dfrac{P_1T_2}{T_1}[/tex]
Plugging all the values,
[tex]P_2=\dfrac{2975\times 317.15}{298.15}\\\\P_2=3164.58\ psi[/tex]
So, the new pressure is 3164.58 psi.
Is the answer B? Help
Answer:
A
Explanation:
Hmm, so we have the following in the diagram
Pt(s)
Cl2(g)
Ag(s)
NaCl(aq)
AgNO3(aq)
Pt 2+, 4+, 6+ Though it states Pt is inert
Cl 2-
Ag 1+
Na 1+
NO3-
Anode definition: the positively charged electrode by which the electrons leave an electrical device.
Electrode definition: a conductor through which electricity enters or leaves an object, substance, or region.
Cations attracted to cathode pick up electrons
Anions attracted to anode release electrodes+
Reduction at Cathode (red cat gain of e)
Oxidation at Anode (ox anode loss of e)
So from the diagram we can see that the charge is being generated through the 2 metal plates.
So the answer is A, the anode material is Pt and the half reaction is 2Cl- = Cl2 + 2e-
What is the percent by mass in a solution with 10.0 grams of solute and 25.0 grams of solvent?
Answer:
Percent by mass of solute is (10/35) x 100 = 28.57%
Percent by mass of solvent is (25/35) x 100 = 71.43%
Explanation:
10.0 grams of solute
25.0 grams of solvent
Total Mass = 35 grams
percent by mass = (Mass A / Total Mass) x 100
Percent by mass of solute is (10/35) x 100 = 28.57%
Percent by mass of solvent is (25/35) x 100 = 71.43%
Iodine-131 has a half-life of 8 days. How long would it take for the number of unstable nuclei in the sample to be reduced from 1,000 to 125?
Answer:
After one-half life: 16 mg
After 2-half lives: 8 mg
After 3-half lives: 4 mg
After 4-half lives: 2 mg
After 5-half lives: 1 mg
(5 half-lives) x (8 days/half-life) = 40 days
or doing it the mathematical way: Let z be the number of days to be found:
1 mg = 32 mg x (1/2)^(z / 8 days)
1/32 = (1/2)^(z / 8 days)
log (1/32) = (z / 8 days) x log (1/2)
z / 8 days = log (1/32) / log (1/2)
z = 8 days x log (1/32) / log (1/2) = 40 days
Explanation:
Iodine-131 has a half-life of 8 days, then it would it take for the number of unstable nuclei in the sample to be reduced from 1,000 to 125 is 512 days.
How do we calculate total time?Total time of the reduction of any substance from an initial concentration to a particular concentration will be calculated as:
T = (t)ⁿ, where
n = number of half lives
t = half life time = 8 days
1st half life: 1000 → 500
2nd half life: 500 → 250
3rd half life: 250 → 125
So number of half life times is 3. On putting values we get,
T = (8)³
T = 512 days
Hence total duration of time is 512 days.
To know more about half life time, visit the below link:
https://brainly.com/question/25750315
What's the sequence of a single complete engine cycle?
Intake, compression, power, exhaust
Intake, power, compression, exhaust
Compression, power, intake, exhaust
Intake, exhaust, compression, power
Answer:
Intake, compression, power, and exhaust
Explanation:
A four-stroke cycle engine is an internal combustion engine that utilizes four distinct piston strokes (intake, compression, power, and exhaust) to complete one operating cycle. The piston make two complete passes in the cylinder to complete one operating cycle.
The sequence of a single complete engine cycle is Intake, compression, power, exhaust. Therefore option 1 is correct.
1. Intake: In this step, the intake valve opens, allowing a mixture of air and fuel to enter the combustion chamber.
2. Compression: After the intake stroke, the intake valve closes, and the piston moves back up, compressing the air-fuel mixture. This compression increases the pressure and temperature inside the cylinder, preparing it for combustion.
3. Power: Once the air-fuel mixture is compressed, the spark plug ignites it. The burning mixture rapidly expands, generating a high-pressure force that pushes the piston down.
4. Exhaust: After the power stroke, the exhaust valve opens, and the piston moves back up, pushing the burned gases out of the cylinder and into the exhaust system.
Know more about engine cycle:
https://brainly.com/question/32297821
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Calculate the theoretical yield for the amount of sodium carbonate produced as a result of this chemical reaction. Record your final answer in the above data table.
Calculate the percent yield using your theoretical yield and the amount of sodium carbonate that was actually recovered. Record your final answer in the above data table.
How did your calculated mass of sodium carbonate compare with the actual mass you obtained from the experiment? If the two masses are different, suggest reasons for the difference.
Predict the amount of water and carbon dioxide that was produced as a result of this reaction.
1.
Mass of crucible
5.26 g
2.
Mass of crucible & NaHCO3
8.27 g
3.
Mass of NaHCO3 (2-1)
3.01g
4.
Theoretical Yield of Na2CO3
(Use the amount calculated in #3 as your starting amount)
g
5.
Mass of crucible & Na2CO3
7.13 g
6.
Mass of Na2CO3 – Actual Yield (5-1)
1.87 g
7.
% Yield = actual yield x 100
theoretical yield
%
Answer:
98.6%
Explanation:
First we put down the equation representing the decomposition of sodium bicarbonate.
2NaHCO3(s) ----> Na2CO3(s) + H2O(l) + CO2(g)
We can see from the data provided that the mass of sodium bicarbonate reacted is 3.01 g.
The number of moles of sodium bicarbonate reacted= mass of sodium bicarbonate/ molar mass of sodium bicarbonate
Molar mass of sodium bicarbonate= 84.007 g/mol
Number of moles of sodium bicarbonate=3.01 g/ 84.007 g/mol
Number of moles of sodium bicarbonate= 0.0358 moles
From the balanced reaction equation,
2 moles of sodium bicarbonate yields 1 mole of sodium carbonate
Hence 0.0358 moles of sodium bicarbonate yields 0.0358/2 = 0.0179 moles of sodium carbonate
Theoretical yield of sodium carbonate = number of moles of sodium carbonate × molar mass of sodium carbonate
Molar mass of sodium carbonate= 105.9888 g/mol
Theoretical yield of sodium carbonate= 0.0179 moles × 105.9888 g/mol
Theoretical yield of sodium carbonate= 1.897 g
Actual yield of sodium carbonate= 1.87 g
%yield of sodium carbonate= 1.87/1.897 ×100
%yield of sodium carbonate= 98.6%
Ammonia (NH3) Is base.
How best do you describe Ammonia when dissolved in water
B. Ammonia forms a neutral solution.
C. Ammonia forms a buffered solution.
d. Ammonia acts as base because has OH- and makes water accepts hydrogen.
Answer:
Ammonia accepts a proton from water
Explanation:
Let us quickly remind ourselves of the Brownstead-Lowry definition of an acid. According to Brownstd-Lowry, an acid is any substance that donates hydrogen ions while a base is any substance that accepts hydrogen ions. The hydrogen ion is also known as a proton.
If we look at the behaviour of ammonia in water;
NH3(g) + H2O(l) ----> NH4^+(aq) + OH^-(aq)
We can easily see that ammonia accepts a proton from water (this makes it a Brownstd-Lowry base) and the hydroxide ion is formed in the process. Water functions as the proton donor here.
Will a battery with magnesium (Mg) as the anode and aluminum (Al) work to power a flashlight? Why or why not?
Answer:
Yes because magnesium has a more negative reduction potential than aluminum.
Explanation:
The single factor that will determine whether a battery with magnesium as anode and aluminium as cathode will work or not is the respective electrode potentials of the two elements.
Recall that in a battery, oxidation occur at the anode and reduction occurs that the cathode. The reduction potential shows the ease with which a metal is reduced or oxidized. The substance with the most negative reduction potential will function as the anode while the substance with the less negative electrode potential will function as the anode.
The reduction potential of Magnesium is -2.37 V while that of aluminum is -1.66 V. This implies that magnesium must function as the anode and aluminum as the cathode in order to have a spontaneous electrochemical process in the cell.
What is the Log(10^-4)
Answer:
-4
Explanation:
[tex]log 10^{-4} = -4 log 10[/tex]
log 10 = 1
Therefore -4 log 10 = -4 x 1 = -4