the table below shows the effect conditions on a car stopping distance. in witch condition was the car travelling most slowly​

Answer:

Answer:

Acceleration

Explanation:

plato

Answer:

Using the orbital velocity as deg/time  or the angular speed:

1 rev / sec = 2 * pi rad / sec   since there are 2 pi rad in a revolution

2 rad/sec = 1 / pi rev/sec  = f   from above

P = 1 / f = pi sec/rev = 3.14 sec/rev

Answer:

Hope I can help you.

Explanation:

Here u go here are some that you can choose from! :)

1) Air bags are activated by a chemical reaction inside the bag. A sensor turns on an electrical circuit, and then sodium azide is ignited. The reaction that occurs generates nitrogen gas, which fills the bag at an extremely rapid rate.

2) Baking soda and vinegar produce carbon dioxide gas when mixed. As this gas grows in volume, it puts pressure on whatever container it is in, and will erupt out of an opening in the container, creating a volcano effect. This chemical reaction is safe, making it a great science activity for kids.

3) Batteries have two terminals: the anode and the cathode. They're separated by an electrolyte, a chemical that allows the anode and cathode to transmit a charge. When something's connected to a battery, chemical reactions take place along the electrodes to produce electricity. Of course, you can't see the energy in the battery when the battery is just sitting around; it is when the electricity is produced that the energy is seen.

4) Explosives: when an explosive goes off, chemical energy that was stored in it is changed and transferred into sound energy, kinetic energy, and thermal energy. Just because chemical energy is being released, it doesn't mean an explosion will occur. But, when a solid material quickly changes into a hot, expanding gas, you may be looking at an explosion. Take TNT, for example. Two units of solid TNT can instantly change into 15 units of hot gas, creating a dark and sooty explosion.

5) Food: chemical energy in food is released when the food is digested and the molecules of food are broken down into smaller pieces. Our bodies digest food by mixing it with acids and enzymes in the stomach. This process turns carbohydrates into glucose. The stomach (and small intestine) then release that glucose into the bloodstream, serving as energy for our bodies.

6) Heating packs (used to warm up cold hands or soothe sore muscles) have chemicals inside them. A lot of them function by "cracking" (or bending) them. This is because they're filled with iron. Once you crack the heating pack, the iron is exposed to the air. As the iron reacts to the oxygen, it transforms into iron oxide, a chemical that can produce heat.

7) Wood, when dry, stores chemical energy. This chemical energy is released as the wood burns, and it is converted into heat, or thermal energy. This also produces light energy. As a result of burning, the wood turns into an entirely new substance - ashes.

Answer:

Explanation:

Mechanical energy is the sum of all potential energy and kinetic energy .

The word "gravity" belongs between "of" and "on".

Answer:

12mA

Explanation:

Answer:

it binds the negatively charged electrons to the positively charged atomic nucleus.

Explanation:

its called Electromagnetic Force

Answer:

Electric

Explanation:

Because they are charged objects

Answer: its B

Explanation:

Answer:

The amount of heat energy that must be removed from the mixture to cool it to its freezing point, of -16°C is 45,360 J

Explanation:

The given parameters for the refrigeration unit and the ice cream are;

The power of the refrigeration unit = 120 J/s

The mass of the liquid ice cream, m = 0.6 kg

The initial temperature of the liquid ice cream, T₁ = 20°C

The freezing point temperature of the ice cream, T₂ = -16°C

The specific heat capacity of the ice cream, c = 2,100 J/kg⁻¹·°C⁻¹

The amount of heat energy that must be removed from the mixture to cool it to its freezing point, ΔQ, is given as follows;

ΔQ = m × c × ΔT

Where;

ΔT = T₁ - T₂

∴ ΔQ = m × c × (T₁ - T₂)

Therefore, by substituting the known values, we have;

ΔQ = 0.6 × 2,100 × (20 - (-16)) = 45,360

The amount of heat energy that must be removed from the mixture to cool it to its freezing point, of -16°C = ΔQ = 45,360 J.

a. 13.23 N

b. 13.2

What you need to do is use this equation:

(m1 + m2) x g

hope it helps!

Answer:

the quantity which has both magnitude and direction is called vector quantity

Answer:

Sophie gained 1,599.36 J of GPE

Explanation:

Gravitational Potential Energy  (GPE)

Gravitational potential energy is the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=mgh

Where:

m = mass of the object

h  = height with respect to a fixed reference

g  = acceleration of gravity ([tex]9.8 m/s^2[/tex])

Sophie has a mass of m=48 Kg and climbs a ladder that takes her to a height of h=3.4 m.

Calculate the GPE she gained:

U = 48 * 9.8 * 3.4

U = 1,599.36 J

Sophie gained 1,599.36 J of GPE

Answer:

The position x, is ± 0.4 m.

Explanation:

The total mechanical energy of the oscillatory motion is given as;

[tex]E_T = U +K.E\\\\E_T = \frac{1}{2} kA^2\\\\ \frac{1}{2} kA^2 = U +K.E\\\\K.E = \frac{1}{2} kA^2 - U ----equation(1)[/tex]

When the kinetic energy (E) is half of the elastic potential energy (U);

[tex]K.E = \frac{U}{2} ----equation(2)[/tex]

Equate (1) and (2)

[tex]\frac{U}{2} = \frac{1}{2} kA^2 - U\\\\U = kA^2 -2U\\\\U+2U = kA^2\\\\3 U = kA^2\\\\3(\frac{1}{2} kx^2) = kA^2\\\\\frac{3}{2} x^2=A^2\\\\x^2 = \frac{2}{3} A^2\\\\x = \sqrt{\frac{2}{3} A^2} \\\\x = A\sqrt{\frac{2}{3} } \\\\x = 0.49\sqrt{\frac{2}{3} }\\\\x = + /- (0.4 \ m)[/tex]

Thus, the position x, is ± 0.4 m.

Answer: NOT B) Electric potential energy is the charge divided by the electric potential difference.

Explanation:

just missed it on edg

Answer: Choice C

Explanation:

Answer:

Its a fuse.

Explanation:

Answer:

Up AND Down

Explanation:

a transverse wave goes up and Down

Answer:

B) interval training

Explanation:

Interval training is a type of training in which the period of intense activity alternates with the period of active recovery. The duration and intensity of the work interval together with the duration and intensity of the recovery interval make up one series.

When planning interval training, it is necessary to determine: 1. the duration and intensity of the working interval, 2. the duration and intensity of the recovery interval, and 3. the total number of series.

Precisely because of the larger number of variables and the unlimited possibility of combinations, interval training is more efficient and interesting than continuous training.

Answer:

thermosphere...........

Answer:

Approximately [tex]0.8\; \rm s[/tex] (assuming that air resistance is negligible.)

Explanation:

Let [tex]v_0[/tex] denote the initial velocity of this ball. Let [tex]\theta[/tex] denote the angle of elevation of that velocity.

The initial velocity of this ball could be decomposed into two parts:

If air resistance on this ball is negligible, [tex]v_0(\text{vertical})[/tex] alone would be sufficient for finding the time of flight of this ball.

Calculate [tex]v_0(\text{vertical})[/tex] given that [tex]v_0 = 8 \; \rm m \cdot s^{-1}[/tex] and [tex]\theta = 30^\circ[/tex]:

[tex]\begin{aligned}& v_0(\text{vertical}) \\ &= v_0 \cdot \sin(\theta) \\ &= \left(8 \; \rm m \cdot s^{-1} \right) \cdot \sin\left(30^{\circ}\right) \\ &= 4\;\rm m \cdot s^{-1} \end{aligned}[/tex].

Assume that air resistance on this ball is zero. Right before the ball hits the ground, the vertical velocity of this ball would be exactly the opposite of the value when the ball was launched.

Since [tex]v_0(\text{vertical}) = 4\; \rm m \cdot s^{-1}[/tex], the vertical velocity of this ball right before landing would be [tex]v_1(\text{vertical}) = -4\; \rm m \cdot s^{-1}[/tex].

Calculate the change to the vertical velocity of this ball:

[tex]\begin{aligned}& \Delta v(\text{vertical}) \\ & = v_1(\text{vertical}) - v_0(\text{vertical}) \\ &= -8\; \rm m \cdot s^{-1}\end{aligned}[/tex].

In other words, the vertical velocity of this ball should have change by [tex]8\; \rm m \cdot s^{-1}[/tex] during the entire flight (from the launch to the landing.)

The question states that the gravitational field strength on this ball is [tex]g = 10\; \rm m \cdot s^{-2}[/tex]. In other words, the (vertical) downward gravitational pull on this ball could change the vertical velocity of the ball by [tex]10\; \rm m\cdot s^{-1}[/tex] each second. What fraction of a second would it take to change the vertical velocity of this ball by [tex]8\; \rm m \cdot s^{-1}[/tex]?

[tex]\begin{aligned}t &= \frac{\Delta v(\text{initial})}{g} \\ &= \frac{8\; \rm m \cdot s^{-1}}{10\; \rm m \cdot s^{-2}} = 0.8\; \rm s\end{aligned}[/tex].

In other words, it would take [tex]0.8\; \rm s[/tex] to change the velocity of this ball from the initial velocity at launch to the final velocity at landing. Therefore, the time of the flight of this ball would be [tex]0.8\; \rm s\![/tex].

Answer:

Ok

Explanation:

The question mentions an illustration that is not provided, but I can solve the problem anyway.

Answer:

Ua - Ub = 5,390 J regardless of the reference height

Explanation:

Gravitational Potential Energy

Gravitational potential energy is the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or [tex]9.8 m/s^2[/tex].

The problem is about proving the difference in potential energy does not depend on the reference used to calculate them.

a. Let's set the zero level for gravitational potential energy at B, i.e., h=0 at B.

The m=55 kg skier is at the top of the slope (point A) at a height of h=10 m.

The gravitational potential energy Ua is:

Ua = 55 * 9.8 * 10 = 5,390 J

The gravitational potential energy Ub (h=0) is:

Ub = 55 * 9.8 * 0 = 0 J

The difference is:

Ua - Ub = 5,390 J - 0 J = 5,390 J

b. Now fix the zero level at point A (h=0).

The gravitational potential energy Ua (h=0) is:

Ua = 55 * 9.8 * 0 = 0 J

Point B is at a height h=-10 m since it's below the reference.

The gravitational potential energy Ub (h=-10) is:

Ub = 55 * 9.8 * (-10) = -5,390 J

The difference is:

Ua - Ub = 0 J - (-5,390 J) = 5,390 J

We get the same value.

c. Finally, fix the reference at the midpoint between A and B.

Point A is at a height h=5 m since it's 5 m above the reference.

The gravitational potential energy Ua is:

Ua = 55 * 9.8 * 5 = 2695 J

Point B is at a height h=-5 m since it's 5 m below the reference.

The gravitational potential energy Ub is:

Ub = 55 * 9.8 * (-5) = -2695 J

The difference is:

Ua - Ub = 2695 J - (-2695 J) = 5,390 J

Again, we get the same value.

Conclusion:

Ua - Ub = 5,390 J regardless of the reference height

Answer:

Nobody knows...

Explanation:

Answer:

3. 1.8A

Explanation:

Given the following data;

Quantity of charge, Q = 650C

Time = 6 minutes to seconds = 6 * 60 = 360 seconds.

To find the current l;

Quantity of charge = current * time

Substituting into the equation, we have;

650 = current * 360

Current = 650/360

Current = 1.8 Amperes

Answer:

i think yes, because the sand together with the filters catches all the impurities of the water that will pass through them. (btw sorry for my English, this is translated from my language in translator, so don't mind my English pls)

Answer:

Newton's third law of motion.

Explanation:

We are told the force needed to throw the full soda can was more than that needed to throw the empty can.

Now, the weight of the full soda can will be more than that of the empty can. Therefore, the full can will demand more force than that of the empty can due to Newton's third law of motion which states that to every action, there is an equal and opposite reaction.

Answer:

C. 90°

Explanation:

The critical angle is that angle of incidence in the dense medium where the angle of refraction is 90°.

In this case, light travels from the more optically dense medium to the less optically dense medium.

When the angle of incidence in the dense medium is equal to the critical angle, the angle of refraction is 90°.

Answer:

The answer is False

Explanation:

Hope this helps :)

Mars is the focus of much scientific study about possible human colonization. Its surface conditions and the presence of water on Mars make it arguably the most hospitable of the planets in the Solar System, other than Earth. Mars requires less energy per unit mass (delta-v) to reach from Earth than any planet except Venus.

Permanent human habitation on a planetary body other than the Earth is one of science fiction's most prevalent themes. As technology has advanced, and concerns about the future of humanity on Earth have increased, the argument that space colonization is an achievable and worthwhile goal has gained momentum. Other reasons for colonizing space include economic interests, long-term scientific research best carried out by humans as opposed to robotic probes, and sheer curiosity.

One of Elon Musk's stated goals through his company SpaceX is to make such colonization possible by providing transport, and to "help humanity establish a permanent, self-sustaining colony on Mars within the next 50 to 100 years".

Many organizations support the colonization of Mars. They have also given different reasons and ways humans can live on Mars. One of the oldest organizations is the Mars Society. They promote a NASA program that supports human colonies on Mars. The Mars Society have set up Mars analog research stations in Canada and the United States. All other organizations include MarsDrive, who wants to help fund settlements on Mars, and Mars to Stay. Mars to Stay advocates settlements on Mars. In June 2012, Mars One released a statement that they believe could help start a colony on Mars by 2023.