The time,
T
(seconds), it takes for a pot of water to boil is proportional to the amount,
A
(litres), of water.
It takes 180 seconds to boil 2.8 litres of water.
Work out how long it takes (to the nearest second) to boil 2.2 litres.

Answer:

The time it takes to boil 2.2 litres of water is approximately 141 seconds

Step-by-step explanation:

The given parameters are;

The relationship of the variables, T and A is a proportional, therefore, we have;

T ∝ A, or T/A = k = Constant of proportionality

The time it takes to boil 2.8 liters of water = 180 seconds

∴ When A = 2.8 litres, T = 180 seconds, from which we have;

k = T/A = 180 s/(2.8 L) = 450/7 s/L

k = 450/7 s/L

When A = 2.2 litres, we have;

T/A = k

∴ T = k × A

Plugging in the value for both 'k', and 'A' when A = 2.2 litres, gives;

T = k × A = 450/7 s/L × 2.2 L = 990/7 s = 141.[tex]\overline{428571}[/tex] s

The time it takes to boil 2.2 litres of water, given a direct proportionality relation is, T = 141.[tex]\overline{428571}[/tex] seconds ≈ 141 seconds given to the nearest second.

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