Answer:
Static, sliding, and rolling friction occur between solid surfaces. Static friction is strongest, followed by sliding friction, and then rolling friction, which is weakest. Fluid friction occurs in fluids, which are liquids or gases.
Explanation:
When a current of 2.0A flows in the 100-turn primary of an ideal transformer, this causes 14 A to flow in the secondary. How many turns are in the secondary?A) 700B) 356C) 114D) 14E) 4
Answer: The correct option is D) 14
Explanation:
A transformer is a device used for stepping- up or stepping- down an alternating voltage. It has both primary and secondary windings. Energy is usually supplied through the primary coil and delivered through the secondary coil in a transformer. Using the equation:
Ns= lp
Np= Is
Where Ns--> number of turns in secondary coil
Np--> number of turns in primary coil
Is--> current flow in secondary coil
Ip--> current flow in primary coil.
Therefore Ns= Np Ip/Is
Substituting from the question
Ns= 100×2/14
Ns= 200/14
Ns = 14.28 which is approximately 14 turns in the secondary coil.
A satellite of 2,140 kg travels around the earth, of 5.97 - 1024
kg. How long will it take the satellite to complete one full orbit if
the distance between them is 9,325 km?
Answer:
8,961
Explanation:
A river flows due east at 1.50 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant velocity of 10 m/s due north relative to the water.(a) What is the velocity of the boat relative to the shore?(b) If the river is 300 m wide, how far downstream has the boat moved by the time it reaches the north shore?
Answer:
a
[tex]u = 10.11 \ m/s[/tex]
b
[tex]x = 44.996 \ m[/tex]
Explanation:
From the question we are told that
The velocity of the river due east is [tex]v = 1.150i \ m /s[/tex]
The velocity of the boat due north is [tex]v_1 = 10j \ m/ s[/tex]
The width of the river is [tex]d = 300 \ m[/tex]
Generally the velocity of the boat relative to the shore
[tex]u = \sqrt{v^2 + v_1^2}[/tex]
=> [tex]u = \sqrt{1.50 ^2 + 10^2}[/tex]
=> [tex]u = 10.11 \ m/s[/tex]
Generally direction of the boat relative to the shore is mathematically represented as
[tex]tan \theta = \frac{v}{v_1}[/tex]
=> [tex]\theta = tan^{-1}[ \frac{v}{v_1}][/tex]
=> [tex]\theta = tan^{-1}[ \frac{1.5}{10}][/tex]
=> [tex]\theta = 8.53^o[/tex]
Generally the distance covered by the boat in the direction of flow of the river before reaching the north shore is mathematically represented as
[tex]x = d* tan(\theta )[/tex]
=> [tex]x = 300 * tan(8.53)[/tex]
=> [tex]x = 44.996 \ m[/tex]
(a) The velocity of the boat relative to the shore is 10.11 m/s.
(b) The distance traveled by the boat when it reaches the north shore is 303.3 m.
The given parameters;
initial velocity of the river, = 1.5 m/s due eastvelocity of the boat, = 10 m/s due north(a) The velocity of the boat relative to the shore is calculated by applying Pythagoras theorem as shown below;
[tex]v = \sqrt{1.5^2 + 10^2} \\\\v = 10 .11 \ m/s[/tex]
(b) Let the time taken for the boat to reach the north shore = t
[tex]distance = speed \times time \\\\c^2 = a^2 + b^2\\\\[/tex]
the width of the river is the height of the right-trianglethe displacement of the river after time "t" is the base of the right-trianglethe displacement of the boat after time "t" is the hypotenuse side[tex](10.11t)^2 = (300)^2 + (1.5t)^2\\\\102.21t^2 = 90,000 + 2.25t^2\\\\99.96t^2 = 90,000\\\\t^2 = \frac{90,000}{99.96} \\\\t^2 = 900\\\\t = \sqrt{900} \\\\t = 30 \ s[/tex]
The distance traveled by the boat when it reaches the north shore;
[tex]d = 10.11t\\\\d = 10.11 \times 30\\\\d = 303.3 \ m[/tex]
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Newton's Law of Universal Gravitation states that every object in the universe
Answer: Newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
Explanation:
What is the mass of a pet cat that weighs 75N?
Answer:
7.64787 kilograms
Explanation:
75 Newton = 7.64787 Kilograms
hope this helps
pls mark brainliest :D
Answer:
Explanation:
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Which has more momentum, a 2000 lb car moving at 100 km/hr or a 4000 lb truck moving at 50 km/hr ?
Answer:
The truck and car have the same momentum.
Explanation:
[tex]m_1[/tex] = Mass of car = [tex]2000\ \text{lb}=2000\times0.45359237\ \text{kg}[/tex]
[tex]v_1[/tex] = Velocity of car = [tex]\dfrac{100}{3.6}\ \text{m/s}[/tex]
[tex]m_2[/tex] = Mass of truck = [tex]4000\times0.45359237\ \text{kg}[/tex]
[tex]v_2[/tex] = Velocity of truck = [tex]\dfrac{50}{3.6}\ \text{m/s}[/tex]
Momentum of car
[tex]p_1=m_1v_1\\\Rightarrow p_1=2000\times0.45359237\times \dfrac{100}{3.6}\\\Rightarrow p_1=25199.58\ \text{kg m/s}[/tex]
Momentum of the truck
[tex]p_2=m_2v_2\\\Rightarrow p_2=4000\times0.45359237\times \dfrac{50}{3.6}\\\Rightarrow p_2=25199.58\ \text{kg m/s}[/tex]
Both the truck and car have the same momentum of [tex]25199.58\ \text{kg m/s}[/tex].
What is the relationship between elastic collision and 1:1 ratio?
An elastic collision is an come across between two bodies wherein the overall kinetic electricity of the two bodies stays the same.
In a super, perfectly elastic collision, there's no internet conversion of kinetic strength into other kinds inclusive of heat, noise, or capacity strength. An elastic collision is a collision wherein there is no internet loss in kinetic strength within the gadget due to the collision. each momentum and kinetic energy are conserved portions in elastic collisions.
An elastic collision is a collision wherein there is no internet loss in kinetic electricity in the gadget because of the collision. In the elastic collision, in which the kinetic energy is conserved, the kinetic electricity in an inelastic collision isn't always conserved. In an inelastic collision, the kinetic energy among the colliding bodies is exceptional at the start and the quit of the collision.
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A 15.0kg block is resting on a 2.5 m long board with a coefficient of static friction of 0.45. If one end of the board is slowly raised, at what angle will the block slip?
As the board is raised by an angle θ, the block will be held in place by 3 forces:
• its weight, pointing downward (magnitude w )
• the normal force of the board pushing up on the block, pointing in the direction perpendicular to the board (mag. n)
• static friction, pointing in the direction parallel to the board, opposite the direction the block would slip (mag. f )
Decompose the vectors into components that are parallel and perpendicular to the board (taking the direction of n to be the positive direction perpendicular to the board, and the direction of f to be the negative directoin parallel to it), so that by Newton's second law, we have
• net parallel force:
∑ F = w (//) + f
∑ F = m g sin(θ) - µ n = 0
where µ = 0.45 is the coefficient of static friction, g = 9.80 m/s² is the mag. of the acceleration due to gravity, and m = 15.0 kg is the mass of the block.
• net perpendicular force:
∑ F = n + w (⟂)
∑ F = n - m g cos(θ) = 0
Solve for n in the equation for net perpendicular force:
n = m g cos(θ)
Substitute this into the equation for net parallel force:
m g sin(θ) - 0.45 m g cos(θ) = 0
Solve for θ :
sin(θ) - 0.45 cos(θ) = 0
sin(θ) = 0.45 cos(θ)
tan(θ) = 0.45
θ = tan⁻¹(0.45)
θ ≈ 24.2°
So the maximum angle the board can be lifted before the block starts to slide is about 24.2°, since the coefficient of static friction µ is such that
f = µ n
where f is the maximum magnitude of the static friction force.
A nearsighted person has a far point of 40cm. What power spectacle lens is needed if the lens is 2cm from the eye
Answer:
The value is [tex]p = - 2.63 \ Diopters[/tex]
Explanation:
From the question we are told that
The value of the far point is [tex]a = 40 \ cm = 0.4 \ m[/tex]
The distance of the lens to the eye is [tex]b = 2 \ cm = 0.02[/tex]
Generally
[tex]1 Diopter = > 1 m^{-1}[/tex]
Generally the power spectacle lens needed is mathematically represented as
[tex]p = \frac{1}{d_o } + \frac{1}{d_i}[/tex]
Here [tex]d_o[/tex] is the object distance which for a near sighted person is [tex]d_o = \infty[/tex]
And [tex]d_i[/tex] is the image distance which is evaluated as
[tex]d_i = b - a[/tex]
=> [tex]d_i = 0.02 - 0.4[/tex]
=> [tex]d_i = -0.38 \ m[/tex]
So
[tex]p = \frac{1}{\infty } + \frac{1}{-0.38}[/tex]
=> [tex]p = 0 - 2.63[/tex]
=> [tex]p = - 2.63 \ Diopters[/tex]
Why is the term negative acceleration used instead of deceleration
Answer:
See Explanation
Explanation:
Whenever a force is applied in an object in the opposite direction of its motion. It tends to slow down the speed of the object. Therefore, this force is called the decelerating force and the acceleration produced by it is called deceleration.
The deceleration produced in this case by this decelerating force has a direction opposite to the direction of motion or velocity of the object. Therefore, this deceleration is defined with a negative sign along with its magnitude.
Due to this opposite direction, term negative acceleration is also used instead of deceleration.
A diver 50 m deep in 10∘C fresh water exhales a 1.0-cm-diameter bubble. What is the bubble's diameter just as it reaches the surface of the lake, where the water temperature is 20∘C?
Answer:
18.2mm
Explanation:
D = 50m
T1 = 10+273 = 283K
T2 = 20+273 = 293K
R1 = 5x10^-3
Absolute pressure at 50m
P1 = pA + pwateer x g x d
= 101000+ 1000x9.81x50
= 591500pa
New volume of bubble
= P1v1/T1 = p2v2/T2
= 125x10^-9 x 591500x293/101000*283
= 757.9x10^-9m³
R2 = 9.2x10^-3
D2 = 18.2mm
Or 1.82cm
Mark takes a 45 minute bike ride through the canyon a total of 4 kilometers what is his speed
Answer:
5.33 km /hr
Explanation:
45 minutes is 3/4 or .75 hr
4 km / .75 hr = 5 1/3 or 5.33 km/hr
When a falling meteoroid is at a distance above the Earth's surface of 3.40 times the Earth's radius, what is its acceleration due to the Earth's gravitation
Answer:
g = 0.85 m[tex]s^{-2}[/tex]
Explanation:
g = [tex]\frac{GM}{h^{2} }[/tex]
were; g is the acceleration due to Earth's gravity, G is Newton's gravitation constant (6.674 x [tex]10^{-11}[/tex] N[tex]m^{2}[/tex][tex]kg^{-2}[/tex]), M is the mass of the earth (5.972 x [tex]10^{24}[/tex] kg), and h is the distance of meteoroid to the earth.
h = 3.40 x R
= 3.40 x 6371 km
h = 21661.4 km
= 21661400 m
Thus,
g = [tex]\frac{6.674*10^{-11}*5.972*10^{24} }{(21661400)^{2} }[/tex]
= [tex]\frac{3.9857 *10^{14} }{4.6922*10^{14} }[/tex]
= 0.84944
g = 0.85 m[tex]s^{-2}[/tex]
The acceleration due to the Earth's gravitation is 0.85 m[tex]s^{-2}[/tex].
if a man travels 10m north in 4s, stops for 20s, then travels 20 meters east in 15s, what is the man's average velocity for the trip?
Answer:
The average velocity from 1 to 3 seconds is 20 m/s l. X/T = 0 m/1s = zero.
Explanation:
I hope that helped!
Electric circuits provide energy for light bulbs. Which of these prevents the flow of electrons?
O a circuit that is closed
O a series circuit
O a circuit that is open
O a parallel circuit
A circuit that is closed prevents the flow of electrons. So, the correct option is A.
What is an Electric circuit?An electrical circuit is defined as an interconnection of electrical components or a model of such interconnection, consisting of electrical elements. An electrical circuit is described as a network consisting of a closed loop, which provides a return path for current.
A closed circuit is required to carry current. When there is a break anywhere in the path, the circuit will open and no current will flow, and the metal atoms in the wire will quickly become cool and electrically neutral.
Thus, a circuit that is closed prevents the flow of electrons. So, the correct option is A.
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If the IMA of a machine Is 3 and the resistance arm Is 6 meters, then the effort arm is? 2 meters, 3 meters, 9 meters, 18 meters.
Answer:
18 newtons
Explanation: I'm taking that class
how much work is produced when a 350N object is used to move a car 5 m?
Answer:w= 1,750 J
Explanation: w=f x d
w=350 N x 5 m
w= 1,750 J
(pretty sure that’s right)
The work produced by the object to move the car is of 1750 J.
Given data:
The magnitude of force applied on the object is, F = 350 N.
The distance moved by the car is, s = 5 m.
When some magnitude of force is applied on any object to displace it, then the output of the applied force is known as work done. The mathematical expression for the work done is given as,
[tex]W = F \times s[/tex]
Solving as,
[tex]W = 350 \times 5\\\\W = 1750 \;\rm J[/tex]
Thus, we can conclude that the work produced by the object to move the car is of 1750 J.
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define electric potential at a point and find expression for it.
Answer:
Recall that the electric potential is defined as the potential energy per unit charge, i.e. V=PEq V = PE q . ... The equation for the electric potential due to a point charge is V=kQr V = kQ r , where k is a constant equal to 9.0×109 N⋅m2/C2.
Explanation:
How long would it take a boat that started at rest to get to a velocity of 56 m/s if it was accelerating at 17 m/s/s?
Answer:
3.29 s
Explanation:
Using v = u + at where u = initial velocity of boat = 0 m/s since it starts at rest, v = final velocity of boat = 56 m/s, a = acceleration of boat = 17 m/s² and t = time taken to accelerate to 56 m/s.
So, v -= u + at
t = (v - u)/a
substituting the values of the variables, we have
t = (56 m/s - 0 m/s)/17 m/s²
= 56 m/s ÷ 17 m/s²
= 3.29 s
It will take the boat 3.29 s to accelerate to 56 m/s at an acceleration of 17 m/s²
Please help me on this with a full explanation
Answer:
a = 5 [m/s²]
Explanation:
We must perform a sum of forces on both axes (vertical axis and horizontal axis).
We see that the forces on the vertical axis are the same but in the opposite direction. In this way, there is no movement on the vertical axis y. and we can find the mass of the body.
∑Fy = 0
Fnorm - Fgrav = 0
We know that the force of gravity is equal to the product of mass by gravitational acceleration.
[tex]F_{grav}=m*g[/tex]
where:
m = mass [kg]
g = gravity acceleration = 10 [m/s²]
[tex]100=m*10\\m=100/10\\m=10[kg][/tex]
Since there is only one force on the horizontal axis, this force generates accelerated motion. This force is equal to the product of mass by acceleration, as stipulated by Newton's second law.
∑F = m*a
where:
F = force = 50 [N]
a = acceleration of the body [m/s²]
[tex]F=m*a\\50*10*a\\a=5[m/s^{2} ][/tex]
What is the distance traveled
The projectile will travel 6053.13 m in the horizontal direction
Data obtained from the questionThe following data were obtained from the question:
Initial velocity (u) = 342 m/sAngle of projection (θ) = 66.3 degreesAcceleration due to gravity (g) = 9.8 m/s²Air resistance = 31.1%Range (R) =?How to determine the range of the projectileThe range the projectile will attain can be obtained as follow:
R = u²Sine(2θ) / g
R = 342² × Sine (2×66.3) / 9.8
R = 8785.39 m
Air resistance is 31.1%. Thus, we have
R = 8785.39 - (8785.39 × 31.1%)
R = 8785.39 - 2732.26
R = 6053.13 m
Thus, the projectile will travel 6053.13 m in the horizontal direction
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A person walks 5 meters north, which is vector 1. Then he walks 4 meters east, which is vector 2. The displacement vector is vector 3. Draw the vectors and calculate displacement and the angle between vectors 1 and 3
Explanation:
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1. If an object does not change its position, then we say that it is at _________?
2. According to the video, can an object ALWAYS seem at rest to everyone?
3. What else did the person need in the video to find their friend's house BESIDES a REFERENCE POINT?
4. So according to the video, in order to find an object or place, you need what 3 things?
5. Using the number system to determine motion, what was the starting position of the car in the problem?
6. What was the final position of the car?
7. How far in total did the car actually travel?
Answer:
ᏌᎳᏆᎿᏌᎭ ᎭᏆᎳ ᎷᎭᏌ Ꭽ
Explanation:
Answer:
rest
Explanation:
if an object is not in it's position, then we say it is at rest.
the question is in a picture
Answer:
same for all objects
Explanation:
earth pulls every object by same force of gravity
If earth squeezed to the size of moon.Calculate the weight of 100kg mass in the squeezed earth.
Answer:
833.9kg that's the answer
According to Newton's second law, if you increase the mass but the force is the same, what happens to the acceleration?
Audio Recording 50 KB
acceleration decreases
Оа
Ob
Ос
acceleration increases
acceleration remains the same
Simple Answer. Mass cannot change.
Force=Acceleration
How does light move?
Answer:
Light travels as a wave. But unlike sound waves or water waves, it does not need any matter or material to carry its energy along. This means that light can travel through a vacuum—a completely airless space. It speeds through the vacuum of space at 186,400 miles (300,000 km) per second.
Explanation:
Hope this helps :))
Alex, parked by the side of an east-west road, is watching car P, which is moving in a westerly direction. Barbara, driving east at a speed 52 km/h, watches the same car. Take the easterly direction as positive. If Alex measures a speed of 78 km/h for car P, what velocity will Barbara measure?
Answer:
[tex]v_{PB} = 130\ km/h[/tex]
Explanation:
Since, Alex is at rest. Therefore, the speed measured by him will be the absolute speed of car P. Therefore, taking easterly direction as positive:
[tex]Absolute\ Velocity\ of\ Car\ P = v_{P} = -78\ km/h[/tex]
And the absolute velocity of Barbara's Car is given as:[tex]Absolute\ Velocity\ of\ Barbara's\ Car = v_{B} = 52\ km/h[/tex]
Now, for the velocity of Car p with respect to the velocity of Barbara's Car can be given s follows:
[tex]Velocity\ of\ Car\ P\ measured\ by\ Barbara = v_{PB} = v_{B}-v_{P}\\\\v_{PB} = 52\ km/h-(-78\ km/h)[/tex]
[tex]v_{PB} = 130\ km/h[/tex]
Question 12 of 20
To produce a magnetic field, what does an electromagnet require?
A. A solenoid with no current flowing through it
B. A current flowing through a coil of wire
C. A core made from a magnetic material
D. A copper core
Answer:
B a current flowing through a coil of wire :)
Explanation:
Hypoventilation dramatically increases carbonic acid concentration and involves________?
extremely fast breathing
extremely slow breathing
irregular breathing
intermittent breathing
extremely deep breathing