Triangles E F G and K L M are shown. Angles E F G and K L M are congruent. The length of side K L is 6, the length of side M L is 5, and the length of K M is 8. The length of E G is 24, the length of G F is 15, and the length of E F is 18. Can the triangles be proven similar using the SSS or SAS similarity theorems? Yes, △EFG ~ △KLM only by SSS. Yes, △EFG ~ △KLM only by SAS. Yes, △EFG ~ △KLM by SSS or SAS. No, they cannot be proven similar by SSS or SAS.?

Answer:

4(xy + 3w + 3z)

Step-by-step explanation:

The GCF is 4, so you can take that out and put it in front of the parentheses. Then you just divide all of the terms by 4 (4xy / 4 = xy; 12w / 4 = 3w; 12z / 4 = 3z), etc.

Answer:

  24.2

Step-by-step explanation:

You are given the hypotenuse and angle, and you want to find the length of the adjacent side.

The mnemonic SOH CAH TOA reminds you that the relation between angle and sides is ...

  Cos = Adjacent/Hypotenuse

  cos(41°) = x/32

  x = 32·cos(41°)

  x ≈ 24.2

5×4=20 is closer to 24.9344.

[tex]487 \times 512=24.9344[/tex]

Let's try placing the decimals after the hundreds place.

[tex]4.87 \times 5.12=24.9344[/tex]

It works.

There is more than one possibility.

[tex].487 \times 51.2=24.9344[/tex]

[tex]48.7 \times .512=24.9344[/tex]

Answer:

[tex] E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8[/tex]

Now we can find the second moment with this formula:

[tex] E(X^2) = \sum_{i=1}^n X^2_i P(X_i)[/tex]

And replacing we got:

[tex] E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4[/tex]

The variance would be given by:

[tex] Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96[/tex]

And the deviation would be:

[tex] Sd(X) =\sqrt{6.96}= 2.638[/tex]

Step-by-step explanation:

For this case we have the following distribution given:

X      1      2      7

P(X) 1/5  2/5   2/5

We need to begin finding the mean with this formula:

[tex] E(X) = \sum_{i=1}^n X_i P(X_i)[/tex]

And replacing we got:

[tex] E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8[/tex]

Now we can find the second moment with this formula:

[tex] E(X^2) = \sum_{i=1}^n X^2_i P(X_i)[/tex]

And replacing we got:

[tex] E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4[/tex]

The variance would be given by:

[tex] Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96[/tex]

And the deviation would be:

[tex] Sd(X) =\sqrt{6.96}= 2.638[/tex]

Answer:both sides will be equal

Step-by-step explanation:

Answer:

After 1st year, the age distribution will be

[tex]x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right][/tex]

After 2nd year, the age distribution will be

[tex]x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right][/tex]

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

[tex]A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right][/tex]

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

[tex]x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right][/tex]

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

[tex]x_1 = A \cdot x[/tex]

[tex]x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right][/tex]

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

[tex]x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right][/tex]

After 2nd year, the age distribution will be

[tex]x_2 = A \cdot x_1[/tex]

[tex]x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right][/tex]

[tex]x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right][/tex]

Answer:

sorry i meant c

Step-by-step explanation:

Answer:

-17

Step-by-step explanation:

-6-11=-17

Answer:

the answer is -17

Step-by-step explanation:

Suppose 43% of the population has a retirement account. If a random sample of size 774 is selected, what is the probability that the proportion of persons with a retirement account will differ from the population proportion by less than 3%?

Answer:

the probability that the proportion of persons with a retirement account will differ from the population proportion by less than 3% is 0.9082

Step-by-step explanation:

Given that:

sample size n = 774

Let P be the population proportion for having a retirement account  = 0.43

Also

Let consider [tex]\hat p[/tex] be the sample proportion of having a retirement account.

However; as n is > 30 ; we can say:

[tex]\mathbf{\mu_{\hat p} = 0.43}[/tex]  ;  

 [tex]\mathbf{\sigma_{\hat p^2} = \dfrac{p(1-p)}{n}}[/tex]  

⇒   [tex]\mathbf{\sigma_{\hat p^2} = \dfrac{0.43(1-0.43)}{774}}[/tex]

⇒ [tex]\mathbf{\sigma_{\hat p^2} = \dfrac{0.43(0.57)}{774}}[/tex]

So; we need  P( the sample proportion will differ from 'p' by less than 3% i.e 0.03)

[tex]=P(| \hat p- p|< 0.03)[/tex]

[tex]=P(| \hat p- \mu _p|< 0.03)[/tex]

[tex]= P ( |\dfrac{\hat P - \mu_p}{\sigma_{\hat p}}|< \dfrac{0.03}{\sqrt{ \dfrac{0.43*0.57}{774} }})[/tex]

[tex]= P(|Z|<1.6859)\ \ \ \ [Z=(\dfrac{\hat P - \mu_{\hat P}}{\sigma_{\hat P}}) \sim N(0,1)][/tex]

[tex]= P(-1.6859 <Z<1.6859) \\ \\ = \Phi(1.6859)- \Phi (-1.6859) \\ \\ = \Phi (1.6859) - (1- \Phi(1.6859) \\ \\ = 2 \Phi (1.6859)-1[/tex]

From Normal Cumulative Distribution Function Table

[tex]= 2*0.9541 -1[/tex]

= 1.9082 - 1

= 0.9082

Thus; the probability that the proportion of persons with a retirement account will differ from the population proportion by less than 3% is 0.9082

Answer:

3+6i

Step-by-step explanation:

I did it

Answer:3+6i

Step-by-step explanation:

Answer:

The total weight of his purchase is 1.08 pounds

Step-by-step explanation:

To find the total weight of his purchase, we sum the weight of each of his purchases.

He purchased:

4/9 pound of peanut.

7/11 pounds of raisins

Total:

The least common multiple between 9 and 11 is 99.

Then

[tex]\frac{4}{9} + \frac{7}{11} = \frac{11*4 + 9*7}{99} = \frac{107}{99} = 1.08[/tex]

The total weight of his purchase is 1.08 pounds

Answer:

Option c

Step-by-step explanation:

The study is an observational study. An observational study is made when the researchers collect data based on what they see, hear or observe without any form of manipulation or treatment plan from the researchers. Thus, in this case, the study is an observational study because the study examines individuals in a sample, but does not try to influence the response variable/influence their responses.

Answer:

180 or 1260

Step-by-step explanation:

4*5=20

8*2=16

20+16=36

36*5=180

180*7=1260

sorry it took so long im only in 8th grade but im doing 11th grade classes because im smart i guess

Answer:

Option c

Step-by-step explanation:

This is an experiment because the researcher wants to test efficiency of the magnetic bracelets in the elimination of motion sickness i.e. whether they experienced motion sickness even after wearing the magnetic bracelets.

Answer:

0.0062

Step-by-step explanation:

Find the standard error.

σ = 20 / √100

σ = 2

Find the z-score.

z = (x − μ) / σ

z = (70 − 65) / 2

z = 2.5

Find the probability.

P(Z > 2.5) = 1 − 0.9938

P(Z > 2.5) = 0.0062

Answer:

Step-by-step explanation:

a circle will satisfy the conditions of Green's Theorem since it is closed and simple.

Let's identify P and Q from the integral

[tex]P=x^2 y[/tex], and [tex]Q= xy^2[/tex]

Now, using Green's theorem on the line integral gives,

[tex]\oint\limits_C {x^2ydx-xy^2dy } =\iint\limits_D {y^2-x^2} \, dA\\\\[/tex]

Answer:

y + 7 = -2/3 (x - 1)

Step-by-step explanation:

Point-slope form is y - y1 = m (x - x1)

-7 is y1, -2/3 is m, and 1 is x1

When you plug the values in, you get y + 7 = -2/3 (x - 1)

Answer:

a=5

b=15

Step-by-step explanation:

By following the pattern on the table we can see that the x is increasing by 1 and the y is increasing by 3 each time. Therefore, the next set of numbers would be (5,15).

Answer:

Step-by-step explanation:

the complex number and its conjugate

Answer:

(1+3i)(1-3i)

Step-by-step explanation:

Answer:

x = 1/2 , y = 6

Explanation:

Step 1 - Align the equations and multiply the second row by 2

4x + 3y = 20

2x + y = 7

4x + 3y = 20

4x + 2y = 14

Step 2 - Subtract them both

4x + 3y = 20

4x + 2y = 14

y = 6

So, y = 6

Step 3 - Substitute y into the first equation

4x + 3y = 20

4x + 3(6) = 20

4x + 18 = 20

Step 4 - Subtract 18 from both sides

4x + 18 = 20

4x + 18 - 18 = 20 - 18

4x = 2

Step 5 - Divide both sides by 4

4x = 2

4x / 4 = 2 / 4

x = 2/4

So, x = 1/2

Answer:

a

Step-by-step explanation:

because as absolute value gets smaller the line gets steeper

r

Answer:

-2 is an output of the function.

Step-by-step explanation:

The given table is as follows:

[tex]\left[\begin{array}{cc}{x}&f(x)\\-6&8\\7&3\\4&-5\\3&-2\\-5&12\end{array}\right][/tex]

Here, the values written on the left side of table i.e. values of [tex]x[/tex] are known as the domain values or input values to a function.

The values written on the right side of table i.e. values of [tex]f(x)[/tex] are known as the range values or output values of the function [tex]f(x)[/tex].

Let us consider the pairs of values:

(-6,8) then left side value is of [tex]x[/tex] and right side value is of [tex]f(x)[/tex]

i.e. when [tex]x=-6[/tex], the output value [tex]f(x) =8[/tex].

The same thing applies for all the pairs of values.

similarly for the pair (3,-2):

Left side value is of [tex]x[/tex] and right side value is of [tex]f(x)[/tex]

i.e. when [tex]x=3[/tex], the output value [tex]f(x) =-2[/tex].

So, the answer is:

-2 is an output of the function.

Answer:

-2

Step-by-step explanation:

Answer:

[tex] P(A) = 0.21[/tex]

We want to find the probability that a randomly selected freshman from this college does not take an introductory statistics class, so then we can use the complement rule given by:

[tex] P(A') = 1-P(A)[/tex]

Where A is the event of interest (a freshman at a certain college takes an introductory statistics class) and A' the complement (a freshman at a certain college NOT takes an introductory statistics class) and then replacing we got:

[tex] P(A')=1-0.21= 0.79[/tex]

Step-by-step explanation:

For this problem we know that the probability that a freshman at a certain college takes an introductory statistics class is 0.21, let's define of interest as A and we can set the probability like this:

[tex] P(A) = 0.21[/tex]

We want to find the probability that a randomly selected freshman from this college does not take an introductory statistics class, so then we can use the complement rule given by:

[tex] P(A') = 1-P(A)[/tex]

Where A is the event of interest (a freshman at a certain college takes an introductory statistics class) and A' the complement (a freshman at a certain college NOT takes an introductory statistics class) and then replacing we got:

[tex] P(A')=1-0.21= 0.79[/tex]

Answer: axiom

Step-by-step explanation:

Answer:

efdm3rndne

Step-by-step explanation:

nenejej4ree2wiwiwwi3ieiej

Answer:

-8/5

Step-by-step explanation:

x/3+1= 7/15

x/3= 7/15-1

x/3=  -8/15

x= - 8/5

if percent of 1 year was 5%:

meaning time between accidents must be atleast 1 week

The mean waiting time that exists between the accidents would be:

- 1 week

'Mean waiting time' is determined through the contemplated value of an odd(random/casual) variable.

Given that,

Probability(P) of no accident taking place in 1 year = 5%

Assuming T be the accidents' number that takes place during a year,

Since 5% is the probability or chance of no accident to take place,

The mean waiting time between accidents = 1 week at least via Poisson process.

Thus, 1 week would be the correct answer.

Learn more about 'Mean' here:

brainly.com/question/521501

Answer:

C. The given function is continuous at x=4 because the limit is 2.

Step-by-step explanation:

Given the function:

[tex]f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right[/tex]

We are to determine if the function is continuous at x=4.

For a function to be continuous  at some value c in its domain:

Now: at x=4

Since the two values are the same, we say that f(x) is continuous at x=4.

The correct option is C.

Answer:

C.

Step-by-step explanation:

1/2r = 2π/Cb

Answer:

f(x)= 4x or y=4x

Step-by-step explanation:

X represents minutes and the 4 is how many dishes she can wash.