Answer:
1. The solution to question 1 is as follows;
srand(seedVal);
cout<<rand()%10<<endl;
cout<<rand()%10<<endl;
2. The solution to question 2 is as follows
cout<<100+rand()%50 <<endl;
cout<<100+rand()%50 <<endl;
Explanation:
The general syntax to generate random number between interval is
Random Number = Lower Limit + rand() % (Upper Limit - Lower Limit + 1)
In 1;
The solution starts by calling srand(seedVal);
The next two statements is explained as follows
To print two random integers between intervals of 0 and 9 using rand()"
Here, the lower limit = 0
the upper limit = 9
By substituting these values in the formula above; the random number will be generated as thus;
Random Number = 0 + rand() % (9 - 0 + 1)
Random Number = 0 + rand() % (10)
Random Number = rand() % (10)
So, the instruction to generate the two random variables is rand() % (10)
2.
Similar to 1 above
To print two random integers between intervals of 100 and 149 using rand()"
Here, the lower limit = 100
upper limit = 149
By substituting these values in the formula above; the random number will be generated as thus;
Random Number = 100 + rand() % (149 - 100 + 1)
Random Number = 100 + rand() % (50)
So, the instruction to generate the two random variables is 100 + rand() % (50)
Write a Python program that can compare the unit (perlb) cost of sugar sold in packages with different weights and prices. The program prompts the user to enter the weight and price of package 1, then does the same for package 2, and displays the results to indicate sugar in which package has a better price. It is assumed that the weight of all packages is measured in lb. The program should check to be sure that both the inputs of weight and price are both positive values.
Answer:
This program is written using python
It uses less comments (See explanation section for more explanation)
Also, see attachments for proper view of the source code
Program starts here
#Prompt user for price of package 1
price1 = int(input("Enter Price 1: "))
while(price1 <= 0):
price1 = int(input("Enter Price 1: "))
#Prompt user for weight of package 1
weight1 = int(input("Enter Weight 1: "))
while(weight1 <= 0):
weight1 = int(input("Enter Weight 1: "))
#Calculate Unit of Package 1
unit1 = float(price1/weight1)
print("Unit cost of Package 1: "+str(unit1))
#Prompt user for price of package 2
price2 = int(input("Enter Price 2: "))
while(price2 <= 0):
price2 = int(input("Enter Price 2: "))
#Prompt user for weight of package 2
weight2 = int(input("Enter Weight 2: "))
while(weight2 <= 0):
weight2 = int(input("Enter Weight 2: "))
#Calculate Unit of Package 2
unit2 = float(price2/weight2)
print("Unit cost of Package 2: "+str(unit2))
#Compare units
if unit1 > unit2:
print("Package 1 has a better price")
elif unit1 == unit2:
print("Both Packages have the same price")
else:
print("Package 2 has a better price")
Explanation:
price1 = int(input("Enter Price 1: ")) -> This line prompts the user for price of package 1
The following while statement is executed until user inputs a value greater than 1 for price
while(price1 <= 0):
price1 = int(input("Enter Price 1: "))
weight1 = int(input("Enter Weight 1: ")) -> This line prompts the user for weight of package 1
The following while statement is executed until user inputs a value greater than 1 for weight
while(weight1 <= 0):
weight1 = int(input("Enter Weight 1: "))
unit1 = float(price1/weight1) -> This line calculates the unit cost (per weight) of package 1
print("Unit cost of Package 1: "+str(unit1)) -> The unit cost of package 1 is printed using this print statement
price2 = int(input("Enter Price 2: ")) -> This line prompts the user for price of package 2
The following while statement is executed until user inputs a value greater than 1 for price
while(price2 <= 0):
price2 = int(input("Enter Price 2: "))
weight2 = int(input("Enter Weight 2: ")) -> This line prompts the user for weight of package 2
The following while statement is executed until user inputs a value greater than 1 for weight
while(weight2 <= 0):
weight2 = int(input("Enter Weight 2: "))
unit2 = float(price2/weight) -> This line calculates the unit cost (per weight) of package 2
print("Unit cost of Package 2: "+str(unit2)) -> The unit cost of package 2 is printed using this print statement
The following if statements compares and prints which package has a better unit cost
If unit cost of package 1 is greater than that of package 2, then package 1 has a better priceIf unit cost of both packages are equal then they both have the same priceIf unit cost of package 2 is greater than that of package 1, then package 2 has a better priceif unit1 > unit2:
print("Package 1 has a better price")
elif unit1 == unit2:
print("Both Packages have the same price")
else:
print("Package 2 has a better price")
Someone help me with this
Answer:
(b) public String doMath(int value){
return " " + (value * 3);
}
Explanation:
Two of the answers doesn't even have a variable to pass into. In order, to return a String the return " " in b will do this. Therefore, I think the answer is b.
Write a function to_pig_latin that converts a word into pig latin, by: Removing the first character from the start of the string, Adding the first character to the end of the string, Adding "ay" to the end of the string. So, for example, this function converts "hello"to "ellohay". Call the function twice to demonstrate the behavior. There is a worked example for this kind of problem.
Answer:
def to_pig_latin(word):
new_word = word[1:] + word[0] + "ay"
return new_word
print(to_pig_latin("hello"))
print(to_pig_latin("latin"))
Explanation:
Create a function called to_pig_latin that takes one parameter, word
Inside the function, create a new_word variable and set it to the characters that are between the second character and the last character (both included) of the word (use slicing) + first character of the word + "ay". Then, return the new_word.
Call the to_pig_latin function twice, first pass the "hello" as parameter, and then pass the "latin" as parameter
Answer:
...huh?
Explanation:
#Write a function called "scramble" that accepts a string #as an argument and returns a new string. The new string #should start with the last half of the original string #and end with the first half. # #If the length of the string is odd, split the string #at the floor of the length / 2 (in other words, the second #half is the longer half). # #For example: # scramble("abcd") -> "cdab" # screamble("abcde") -> "cdeab" # scramble("railroad")) -> "roadrail" # scramble("fireworks")) -> "worksfire"
Answer:
def scramble(s):
if len(s) % 2 == 1:
index = int(len(s)//2)
else:
index = int(len(s)/2)
return s[index:] + s[:index]
Explanation:
Create a function called scramble that takes one parameter, s
Check the length of the s using len function. If the length is odd, set the index as the floor of the length/2. Otherwise, set the index as length/2. Use index value to slice the s as two halves
Return the second half of the s and the second half of the s using slice notation (s[index:] represents the characters from half of the s to the end, s[:index] represents the characters from begining to the half of the s)
The IBM 370 mainframe computer was introduced in 1970. The 370 Model 145 could hold up to 524,288 bytes of data (512 Kbytes). It cost $1,783,000.00 to buy (or $37,330/month to rent). A notebook computer today holds 16 Gbytes of memory and costs $2,500 to buy. If you assume that 100% of the price is just the memory, for both computers:
• how much did 1 Kbyte of memory in the IBM computer cost?
• how much does 1 Kbyte of memory in the laptop cost?
• how many times cheaper is the memory in the laptop than memory in the mainframe?
• what factor is today’s computer cheaper than the IBM 370?
Answer:
a) $3482.4 per Kbyte
b) $0.000149 per Kbyte
c) The laptop is 23369991 times cheaper than the mainframe computer
d) Today's computer is 23369991 times cheaper than IBM 370
Explanation:
a) The 370 Model 145 could hold up to 524,288 bytes of data
one Kb = 1024 bytes, therefore 524,288 bytes = 524288/1024 Kbytes= 512 Kbytes. It cost $1,783,000.00 to buy (or $37,330/month to rent).
Since 100% of the price is just the memory
Cost per 1 Kb = cost of computer / memory
Cost per 1 Kb = $1,783,000 / 512 Kb = $3482.4 per Kbyte
b) A notebook computer today holds 16 Gbytes of memory
one Kb = 1024 bytes, 1024 Kb = 1 Mbyte, 1024 Mbytes = 1 Gbyte.
Therefore 16 Gbytes = (16 * 1024 * 1024) Kbytes = 16777216 Kbytes. It cost $2500 to buy
Since 100% of the price is just the memory
Cost per 1 Kb = cost of computer / memory
Cost per 1 Kb = $2500 /16777216 Kb = $0.000149 per Kbyte
c) Cost per 1 Kb for mainframe/ Cost per 1 Kb for laptop = $3482.4 per Kbyte / $0.000149 per Kbyte = 23369991
The laptop is 23369991 times cheaper than the mainframe computer
d) Today's computer is 23369991 times cheaper than IBM 370
You have decided that the complexity of the corporate network facility and satellite offices warrants the hiring of a dedicated physical security and facilities protection manager. You are preparing to write the job requisition to get this critical function addressed and have solicited some ideas from the PCS working group members regarding physical and environmental security risks. Discuss the operational security functions that the physical security and facilities protection manager would be responsible for. Discuss how these functions would inform the development and implementation of system related incident response plans. Further discuss how these incident response plans fit into business continuity planning. Include at least one research reference and associated in-text citation using APA standards. In yourreplies to your peers further discuss how the concepts improve the security posture of PCS.
Answer:
All organizational security functions are as follows:
i) Classify any vital data
ii) Analyze of the hazard
iii) Analyze vulnerability
iv) Assess the risk
v) Take the appropriate risk prevention measures.
Explanation:
These methods described the incident that will fit into this business model was its ongoing support and control of its system that involves the improvements and fix bugs. For above-mentioned mechanisms aid in evaluating potential events/attacks and help reduce the risk involved with these, as well as promote network security by reducing the likelihood of any harm. In this case, appropriate monitoring and monitoring should be a must.Max magnitude Write a method maxMagnitude() with two integer input parameters that returns the largest magnitude value. Use the method in a program that takes two integer inputs, and outputs the largest magnitude value. Ex: If the inputs are: 5 7 the method returns: 7 Ex: If the inputs are: -8 -2 the method returns: -8 Note: The method does not just return the largest value, which for -8 -2 would be -2. Though not necessary, you may use the absolute-value built-in math method. Your program must define and call a method: public static int maxMagnitude(int userVal1, int userVal2)
Answer:
The java program is as follows.
import java.lang.*;
public class Numbers
{
//variables to hold two numbers
static int num1=-8, num2=-2;
//method to return integer with higher magnitude
public static int maxMagnitude(int userVal1, int userVal2)
{
if(Math.abs(userVal1) > Math.abs(userVal2))
return userVal1;
else
return userVal2;
}
public static void main(String[] args) {
int max = maxMagnitude(num1, num2);
System.out.println("The number with higher magnitude among "+num1+ " and "+num2+ " is "+max);
}
}
OUTPUT
The number with higher magnitude among -8 and -2 is -8
Explanation:
1. Two integer variables are declared to hold the two numbers. The variables are declared at class level (outside main()) and declared static.
2. The variables are initialized with any random value.
3. The method, maxMagnitude(), takes the two integer parameters and returns the number with higher magnitude. Hence, return type of the method is int.
public static int maxMagnitude(int userVal1, int userVal2)
4. This method finds the number with higher magnitude using the Math.abs() method inside if-else statement.
if(Math.abs(userVal1) > Math.abs(userVal2))
return userVal1;
else
return userVal2;
5. Inside main(), the method, maxMagnitude(), is called. This method takes the two variables as input parameters.
6. The integer returned by the method, maxMagnitude() is assigned to a local integer variable, max, as shown.
int max = maxMagnitude(num1, num2);
7. The result is displayed to the user as shown.
System.out.println("The number with higher magnitude among "+num1+ " and "+num2+ " is "+max);
8. The class variables and the method, maxMagnitude(), are declared static so that they can be used and called inside main().
9. The variable, max, is called local variable since it can be used only within the main() where it is declared. It is not declared static.
10. The class is declared public since it has the main() method and execution begins with main().
11. The program is saved with the same name as the name of the public class having main(). In this case, the program is saved as Numbers.java.
12. No user input is taken for the two input parameter values. The static variables can be assigned any integer value and the program can be tested accordingly.
Translate each statement into a logical expression. Then negate the expression by adding a negation operation to the beginning of the expression. Apply De Morgan's law until each negation operation applies directly to a predicate and then translate the logical expression back into English.
Sample question: Some patient was given the placebo and the medication. ∃x (P(x) ∧ D(x)) Negation: ¬∃x (P(x) ∧ D(x)) Applying De Morgan's law: ∀x (¬P(x) ∨ ¬D(x)) English: Every patient was either not given the placebo or not given the medication (or both).(a) Every patient was given the medication.(b) Every patient was given the medication or the placebo or both.(c) There is a patient who took the medication and had migraines.(d) Every patient who took the placebo had migraines. (Hint: you will need to apply the conditional identity, p → q ≡ ¬p ∨ q.)
Answer:
Explanation:
To begin, i will like to break this down to its simplest form to make this as simple as possible.
Let us begin !
Here statement can be translated as: ∃x (P(x) ∧ M(x))
we require the Negation: ¬∃x (P(x) ∧ M(x))
De morgan's law can be stated as:
1) ¬(a ∧ b) = (¬a ∨ ¬b)
2) ¬(a v b) = (¬a ∧ ¬b)
Also, quantifiers are swapped.
Applying De Morgan's law, we have: ∀x (¬P(x) ∨ ¬M(x)) (∃ i swapped with ∀ and intersecion is replaced with union.)
This is the translation of above
English: Every patient was either not given the placebo or did not have migrane(or both).
cheers i hope this helped !!
What did Aristotle teach?
Philosophy, I beleive. He tought Sikander liturature and eloquence, but his most famous teachings were of philosophy.
Aristotle taught the world science. He was considered the best scientists of his time.
Look at attachment.
Answer: Choice 1
Explanation:
The turtle will loop around 9 times since each time we are subtracting 10 until it hits 10 from 100. Only the first one seems to be like that.
Hope that helped,
-sirswagger21
Answer:
Explanation:
I switch.my acounntt it got hacked
2) An algorithm that takes in as input an array with n rows and m columns has a run time of O(nlgm). The algorithm takes 173 ms to run in an input array with 1000 rows and 512 columns. How long will the algorithm take to run on an input array with 1500 rows and 4096 columns? (Note: For ease of calculation, please use a base of 2 for your logarithm.)
Answer:
The algorithm takes 346 ms to run on an input array with 1500 rows and 4096 columns.
Explanation:
For an input array with 1000 rows and 512 columns, the algorithm takes 173 ms.
We want to find out how long will the algorithm take to run on an input array with 1500 rows and 4096 columns?
Let the algorithm take x ms to run 1500 rows and 4096 columns.
For an input of n rows and m columns, it takes
[tex]n \: log_{2} \:m[/tex]
So,
[tex]1000 \: log_{2} \:512 = 173 \\\\1000 \: log_{2} \:2^{9} = 173 \:\:\: ( 2^{9} = 512) \\\\1000 \times 9 = 173 \:\:\:\:\: \: \: eg. 1[/tex]
and
[tex]1500 \: log_{2} \:4096 = x \\\\1500 \: log_{2} \:2^{12} = x \:\:\: ( 2^{12} = 4096) \\\\1500 \times 12 = x \:\:\:\:\: \: \: eg. 2[/tex]
Now divide the eq. 2 by eq. 1 to find the value of x
[tex]\frac{1500 \times 12}{1000 \times 9} = \frac{x}{173} \\\\\frac{18000 }{9000} = \frac{x}{173} \\\\2 = \frac{x}{173} \\\\x = 2 \times 173 \\\\x = 346 \: ms[/tex]
Therefore, the algorithm takes 346 ms to run on an input array with 1500 rows and 4096 columns.
Consider that a large online company that provides a widely used search engine, social network, and/or news service is considering banning ads for the following products and services from its site: e-cigarettes, abortion clinics, ice cream, and sugared soft drinks. Which, if any, do you think they should ban? Give reasons. In particular, if you select some but not all, explain the criteria for distinguishing.
Answer:
I think that they should ban ads for all four products. These products, e-cigarettes, abortion clinics, ice cream, and sugared soft drinks, are all discreet adult products that should not be advertised because of their health hazards. Since the "large online company provides a widely used search engine, social network, and/or news service, which are mainly patronized by younger people, such ads that promote products injurious to individual health should be banned. Those who really need or want these products know where they could get them. Therefore, the products should not be made easily accessible to all people. Nor, should ads promote their patronage among the general population.
Explanation:
Advertisements create lasting and powerful images which glamourize some products, thereby causing the general population, especially children, to want to consume them without any discrimination of their health implications. If online banning is then contemplated, there should not be any distinguishing among the four products: e-cigarettes, abortion clinics, ice cream, and sugared soft drinks.
Alcatel-Lucent's High Leverage Network (HLN) increases bandwidth and network capabilities while reducing the negative impact on the environment. This works because the HLN:_____________.
a. Reduces or eliminates use of finite (non-renewable) radio frequencies utilized by wireless devices.
b. Reduces Radio Frequency Interference (RFI) - overcrowding of specific areas of the electromagnetic spectrum.
c. Limits the number of people who can access the network at any one time —particularly during times of peak energy demand.
d. Delivers increased bandwidth using fewer devices and energy.
Answer:
d. Delivers increased bandwidth using fewer devices and energy.
Explanation:
Alcatel-Lucent, formed in 1919 was a French global telecommunications equipment manufacturing company with its headquarter in Paris, France.
They provide services such as telecommunications and hybrid networking solutions deployed both in the cloud and properties.
Alcatel-Lucent's High Leverage Network (HLN) increases bandwidth and network capabilities while reducing the negative impact on the environment. This works because the High Leverage Network (HLN) delivers increased bandwidth using fewer devices and energy on Internet Protocol (IP) networks.
The Alcatel-Lucent's High Leverage Network (HLN) provides reduced cost of transmitting data as fewer network equipments are used with less adverse effects on the environment.
The High Leverage Network (HLN) when successfully implemented helps telecom firms to improve their operational efficiency, maintenance costs, and enhance network performance and capacity to meet the bandwidth demands of their end users.
What is a large public computer network through which computers can exchange information at high speed?
Answer:
Server
Explanation:
The Question is vauge, but I believe a Server is the word you're looking for. Computer Network could mean various things, in this case im going to assume that by Network, its saying Server. As a server is what allows for high speed interactions between a host computer and a client computer.
a. A programmer wrote a software delay loop that counts the variable (unsigned int counter) from 0 up to 40,000 to create a small delay. If the user wishes to double the delay, can they simply increase the upperbound to 80,000?
b. If the code contains a delay loop and we noticed that no delay is being created at run-time. What should we suspect during debugging?
Answer:
Explanation:
The objective here is to determine if the programmer can simply increase the upperbound to 80,000.
Of course Yes, The programmer can simply increase the delay by doubling the upperbound by 80000. The representation can be illustrated as:
( int : i = 0; i < 40,000; i ++ )
{
// delay code
}
Which can be modified as:
( int : i = 0; i < 80,000; i ++ )
{
// delay code
}
b) If the code contains a delay loop and we noticed that no delay is being created at run-time. What should we suspect during debugging?
Assuming there is no delay being created at the run-time,
The code is illustrated as:
For ( int : i = 0 ; i < 0 ; i ++ )
{
// delay code which wont
//execute since code delay is zero
}
we ought to check whether the loop is being satisfied or not. At the Initial value of loop variable, is there any break or exit statement is being executed in between loop. Thus, the aforementioned delay loop wont be executed since the loop wont be executed for any value of i.
Next, Su wants to explain how the cotton gin separated seeds from cotton. At first, she considers using star bullets for
the steps in this process. But then, she determines that is not the right approach. Which action would most clearly
show the steps in the process in her presentation?
Su should change the type of bullet.
Su should change the size of the bullets.
Su should change the bullets to numbers.
Su should change the color of the bullets.
Answer:
change bullets to numbers
Explanation:
100%
Given main(), define the Team class (in file Team.java). For class method getWinPercentage(), the formula is:teamWins / (teamWins + teamLosses)Note: Use casting to prevent integer division.Ex: If the input is:Ravens133 where Ravens is the team's name, 13 is number of team wins, and 3 is the number of team losses, the output is:Congratulations, Team Ravens has a winning average!If the input is Angels 80 82, the output is:Team Angels has a losing average.Here is class WinningTeam:import java.util.Scanner;public class WinningTeam {public static void main(String[] args) {Scanner scnr = new Scanner(System.in);Team team = new Team();String name = scnr.next();int wins = scnr.nextInt();int losses = scnr.nextInt();team.setTeamName(name);team.setTeamWins(wins);team.setTeamLosses(losses);if (team.getWinPercentage() >= 0.5) {System.out.println("Congratulations, Team " + team.getTeamName() +" has a winning average!");}else {System.out.println("Team " + team.getTeamName() +" has a losing average.");}}}
Answer:
Explanation:
public class Team {
private String teamName;
private int teamWins;
private int teamLosses;
public String getTeamName() {
return teamName;
}
public void setTeamName(String teamName) {
this.teamName = teamName;
}
public int getTeamWins() {
return teamWins;
}
public void setTeamWins(int teamWins) {
this.teamWins = teamWins;
}
public int getTeamLosses() {
return teamLosses;
}
public void setTeamLosses(int teamLosses) {
this.teamLosses = teamLosses;
}
public double getWinPercentage() {
return teamWins / (double) (teamWins + teamLosses);
}
}
Following are the Java program to define the Team class and calculate its value:
Class Definition:class Team //defining the class Team
{
private String teamName;//defining String variable
private int teamWins, teamLosses;//defining integer variable
//defining the set method to set value the input value
public void setTeamName(String teamName)//defining setTeamName method that takes one String parameter
{
this.teamName = teamName;//using this keyword that sets value in teamName
}
public void setTeamWins(int teamWins) //defining setTeamWins method that takes one integer parameter
{
this.teamWins = teamWins;//using this keyword that sets value in teamWins
}
public void setTeamLosses(int teamLosses)//defining setTeamLosses method that takes one integer parameter
{
this.teamLosses = teamLosses;//using this keyword that sets value in teamLosses
}
//defining the get method that returns the input value
public String getTeamName() //defining getTeamName method
{
return teamName;//return teamName value
}
public int getTeamWins() //defining getTeamWins method
{
return teamWins;//return teamWins value
}
public int getTeamLosses() //defining getTeamLosses method
{
return teamLosses;//return teamLosses value
}
public double getWinPercentage()//defining getWinPercentage method
{
return ((teamWins * 1.0) / (teamWins + teamLosses));//using the return keyword that returns percentage value
}
}
Please find the complete code in the attached file and its output file in the attached file.
Class definition:
Defining the class "Team".Inside the class two integer variable "teamWins, teamLosses" and one string variable "teamName" is declared.In the next step, the get and set method is defined, in which the set method is used to set the value, and the get method is used to return the value.Find out more about the Class here:
brainly.com/question/17001900
Assume that you have a list of n home maintenance/repair tasks (numbered from 1 to n ) that must be done in numeric order on your house. You can either do each task i yourself at a positive cost (that includes your time and effort) of c[i] . Alternatively, you could hire a handyman who will do the next 4 tasks for the fixed cost h (regardless of how much time and effort those 4 tasks would cost you). The handyman always does 4 tasks and cannot be used if fewer than four tasks remain. Create a dynamic programming algorithm that finds a minimum cost way of completing the tasks. The inputs to the problem are h and the array of costs c[1],...,c[n] .
a) Find and justify a recurrence (without boundary conditions) giving the optimal cost for completing the tasks. Use M(j) for the minimum cost required to do the first j tasks.
b) Give an O(n) -time recursive algorithm with memoization for calculating the M(j) values.
c) Give an O(n) -time bottom-up algorithm for filling in the array.
d) Describe how to determine which tasks to do yourself, and which tasks to hire the handyman for in an optimal solution.
Answer:
Explanation:
(a) The recurrence relation for the given problem is :
T(n) = T(n-1) + T(n-4) + 1
(b) The O(n) time recursive algorithm with memoization for the above recurrence is given below :
Create a 1-d array 'memo' of size, n (1-based indexing) and initialize its elements with -1.
func : a recursive function that accepts the cost array and startingJobNo and returns the minimum cost for doing the jobs from startingJobNo to n.
Algorithm :
func(costArr[], startingJobNo){
if(startingJobNo>n)
then return 0
END if
if(memo[startingJobNo] != -1)
then return memo[startingJobNo];
END if
int ans1 = func(costArr, startingJobNo+1) + costArr[startingJobNo]
int ans2 = func(costArr, startingJobNo+4) + h
memo[startingJobNo] = min(ans1,ans2);
return memo[startingJobNo];
}
(c)
First, Create a 1-d array 'dp' of size, N+1.
dp[0] = 0
bottomUp(int c[]){
for i=1 till i = n
DO
dp[i] = min(dp[i-1] + c[i], dp[max(0,i-4)] + h);
END FOR
return dp[n];
}
(d)
Modifying the algorithm given in part (b) as follows to know which job to do yourself and in which jobs we need to hire a handyman.
First, Create a 1-d array 'memo' of size, n (1-based indexing) and initialize its elements with -1.
Next, Create another 1-d array 'worker' of size,n (1-based indexing) and initialize its elements with character 'y' representing yourself.
Algorithm :
func(costArr[], startingJobNo){
if(startingJobNo>n)
then return 0
END if
if(memo[startingJobNo] != -1)
then return memo[startingJobNo];
END if
int ans1 = func(costArr, startingJobNo+1) + costArr[startingJobNo]
int ans2 = func(costArr, startingJobNo+4) + h
if(ans2 < ans1)
THEN
for (i = startingJobNo; i<startingJobNo+4 and i<=n; i++)
DO
// mark worker[i] with 'h' representing that we need to hire a mechanic for that job
worker[i] = 'h';
END for
END if
memo[startingJobNo] = min(ans1,ans2);
return memo[startingJobNo];
}
//the worker array will contain 'y' or 'h' representing whether the ith job is to be done 'yourself' or by 'hired man' respectively.
A small publishing company that you work for would like to develop a database that keeps track of the contracts that authors and publishers sign before starting a book. What fields do you anticipate needing for this database
Answer:
The database can include the fields related to the Author such as name and address, related to Publisher such as publisher's name and address, related to book such as title and ISBN of the book and related to contract such as payment schedule, contract start and end.
Explanation:
The following fields can be needed for this database:
Author First_NameAuthor's Last_NameAuthors_addressPublisher_namePublisher_addressBook_titleBook ISBNcontract date : this can be start_date (for starting of contract) and end_date ( when the contract ends) payment_made: for payment schedule.C++ Problem: In the bin packing problem, items of different weights (or sizes) must be packed into a finite number of bins each with the capacity C in a way that minimizes the number of bins used. The decision version of the bin packing problem (deciding if objects will fit into <= k bins) is NPcomplete. There is no known polynomial time algorithm to solve the optimization version of the bin packing problem. In this homework you will be examining three greedy approximation algorithms to solve the bin packing problem.
- First-Fit: Put each item as you come to it into the first (earliest opened) bin into which it fits. If there is no available bin then open a new bin.
- First-Fit-Decreasing: First sort the items in decreasing order by size, then use First-Fit on the resulting list.
- Best Fit: Place the items in the order in which they arrive. Place the next item into the bin which will leave the least room left over after the item is placed in the bin. If it does not fit in any bin, start a new bin.
Implement the algorithms in C++. Your program named bins.cpp should read in a text file named bin.txt with multiple test cases as explained below and output to the terminal the number of bins each algorithm calculated for each test case. Example bin.txt: The first line is the number of test cases, followed by the capacity of bins for that test case, the number of items and then the weight of each item. You can assume that the weight of an item does not exceed the capacity of a bin for that problem.
3
10
6
5 10 2 5 4 4
10
20
4 4 4 4 4 4 4 4 4 4 6 6 6 6 6 6 6 6 6 6
10
4
3 8 2 7
Sample output: Test Case 1 First Fit: 4, First Fit Decreasing: 3, Best Fit: 4
Test Case 2 First Fit: 15, First Fit Decreasing: 10, Best Fit: 15
Test Case 3 First Fit: 3, First Fit Decreasing: 2, Best Fit: 2
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You can add additional design elements to a picture by adding a color background, which is accomplished by using what Paint feature?
Pencil tool
Shapes tool
Color Picker tool
Fill with Color tool
Answer:
Fill with Color tool
How are a members details be checked and verified when they return to log back in to the website ?
Answer:
When you sign into a website, you have to enter a password and username most of the time, which will allow the website to know that you have checked in and it is you, who is using your account.
What’s the best way to figure out what wires what and goes where?
Write a basic program that performs simple file and mathematical operations.
a. Write a program that reads dates from input, one date per line. Each date's format must be as follows: March 1, 1990. Any date not following that format is incorrect and should be ignored. Use the find() method to parse the string and extract the date. The input ends with -1 on a line alone. Output each correct date as: 3/1/1990.
b. After the program is working as above, modify the program so that it reads all dates from an input file "inputDates.txt" (an Example file is attached).
c. Modify your program further so that after parsing all dates from the input file "inputDates.txt", it writes out the correct ones into an output file called: "parsedDates.txt".
Ex: If the input is:
March 1, 1990
April 2 1995
7/15/20
December 13, 2003
-1
then the output is:
3/1/1990
12/13/2003
Answer:
Explanation:
I have written the Python program based on your requirements.
Just give the path of the input file and the path for the output file correctly where you want to place the output file.
In, my code - I have given my computer's path to the input and output file.
You just change the path correctly
My code works perfectly and I have tested the code with your inputs.
It gives the exact output that you need.
I have attached the Output that I got by running the below program.
Code:
month_list={ "january":"1","february":"2", "march":"3","april":"4", "may":"5", "june":"6","july":"7", "august":"8", "september":"9","october":"10", "november":"11", "december":"12"} input_file=open('C:\\Users\\Desktop\\inputDates.txt', 'r') output_file=open('C:\\Users\\Desktop\\parsedDates.txt','w') for each in input_file: if each!="-1": lis=each.split() if len (lis) >=3: month=lis [0] day=lis[1] year=lis [2] if month.lower() in month_list: comma=day[-1] if comma==',': day=day[:len (day)-1] month_number=month_list[month.lower()] ans-month_number+"/"+day+"/"+year output_file.write (ans) output_file.write("\n") output_file.close() input_file.close()
- O X parsedDates - Notepad File Edit Format View Help 3/1/1990 12/13/2003
- X inputDates - Notepad File Edit Format View Help March 1, 1990 April 2 1995 7/15/20 December 13, 2003 -1
cheers i hope this helped !!
In this exercise we have to use the knowledge in computer language to write a code in python, like this:
the code can be found in the attached image
to make it simpler we have that the code will be given by:
month_list ={"january": "1", "february": "2", "march": "3", "april": "4", "may": "5", "june": "6", "july": "7", "august": "8", "september": "9", "october": "10", "november": "11", "december":"12"}
input_file = open ('C:\\Users\\Desktop\\inputDates.txt', 'r') output_file =
open ('C:\\Users\\Desktop\\parsedDates.txt', 'w') for each
in input_file:if each
!="-1":lis = each.split ()if len
(lis) >= 3:month = lis[0] day = lis[1] year = lis[2] if month
.lower ()in month_list:comma = day[-1] if comma
== ',': day = day[:len (day) - 1] month_number =
month_list[month.lower ()]ans - month_number + "/" + day + "/" +
year output_file.write (ans) output_file.write ("\n") output_file.
close ()input_file.close ()
See more about python at brainly.com/question/26104476
Write a program in C# : Pig Latin is a nonsense language. To create a word in pig Latin, you remove the first letter and then add the first letter and "ay" at the end of the word. For example, "dog" becomes "ogday" and "cat" becomes "atcay". Write a GUI program named PigLatinGUI that allows the user to enter a word and displays the pig Latin version.
Answer:
The csharp program is as follows.
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
string word = textBox1.Text;
string ch = word.Substring(0, 1);
string str = word.Substring(1, word.Length-1);
string s = str.Insert(str.Length, ch);
textBox2.Text = s.Insert(s.Length, "ay");
}
private void button3_Click(object sender, EventArgs e)
{
Close();
}
private void button2_Click(object sender, EventArgs e)
{
textBox1.Text = "";
textBox2.Text = "";
}
}
}
Explanation:
1. A string variable to hold the user input is declared and initialized accordingly. The user inputted string is taken from textbox1.
string word = textBox1.Text;
2. A string variable to hold the first character of the user inputted string is declared and initialized.
string ch = word.Substring(0, 1);
3. A string variable to hold the user inputted string without the first character is declared and initialized accordingly.
string str = word.Substring(1, word.Length-1);
4. A string variable to hold the substring from step 3 along with the inserted characters at the end, is declared and initialized accordingly.
string s = str.Insert(str.Length, ch);
5. The final string is assigned to the textbox 2, which is the PigLatin conversion of the user inputted string.
textBox2.Text = s.Insert(s.Length, "ay");
6. All the above take place when the user clicks Convert to PigLatin button.
7. Two additional buttons, clear and exit are also included in the form.
8. When the user clicks clear button, both the textboxes are initialized to empty string thus clearing both the textboxes.
textBox1.Text = "";
textBox2.Text = "";
9. When the user clicks the exit button, the application closes using the Close() method.
10. The program is done in Visual Studio.
11. The output of the program is attached.
12. The program can be tested for any type of string and any length of the string.
Chris wants to view a travel blog her friend just created. Which tool will she use?
HTML
Web browser
Text editor
Application software
Answer:
i think html
Explanation:
Answer:
Web browser
Explanation:
Can you please at least give me some part of the code. At least how to start it in C++. Thank you!
Project 5: You will design and implement various classes and write a program to manage one of the following a bank, a hospital, a library, a business, an organization, etc.) The program must do the following:
1. Allow the initialization of the different attributes of the objects from the keyboard.
2. Allow the initialization of the different attributes from a file
3. Perform calculations on one (or more) of the attributes (e.g. calculateInterest, generateHospitalBill, calculateCheckedBooks, etc.)
4. Output a report of all objects created. The report called for by requirement 4 should output all information about each object. You will need to take advantage of the capabilities of C++ classes, inheritance and overriding.
Program Design:
1. Create at least one base class. All data members have to be private. Your main function and any function that it calls should use the member functions of this class for all transactions.
2. Create at least two derived class of the base class described in the previous point.
3. The program will maintain arrays of objects that interacts with each other to manage the designated establishment (bank, hospital, library, etc.). Please do not use anything more sophisticated than an array.
4. Keep the program simple. I am interested in whether you can demonstrate basic competence in the use of classes, inheritance, and good design.
5. All data members in the classes must be private. This is to assure that you use the C++ capabilities that this assignment is all about. Do not use any global variables.
6. When the user decides to quit the updated information is saved back to the secondary storage to give the user the option to either start fresh or continue where he/she left off at the beginning of the next execution
Answer:
Explanation:
The objective of this question is to compute a program that involve using a C++ code for designing and implementing a Bank Account Management Simulator with integrated file storage for saving details to secondary storage.
When writing this code I notice the words are more than 5000 maximum number of characters the text editor can contain, so i created a word document for it. The attached file to the word document can be found below.
Two of the most fundamental functions for dealing with interprocess communication are read() and write(). Consider the following otherwise valid C program:int r, pipeFDs[2];
char message[512];
pid_t spawnpid;
pipe(pipeFDs);
spawnpid = fork();
switch (spawnpid)
{
case 0:
close(pipeFDs[0]); // close the input file descriptor
write(pipeFDs[1], "hi process, this is the STUFF!!", 21);
break;
default:
close(pipeFDs[1]); // close output file descriptor
r = read(pipeFDs[0], message, sizeof(message));
printf("Message received from other: %s\n", message);
break;
}
Select each of the following answers that is correct. CAN BE MULTIPLE CHOICES...
(1) The read() call may block until data becomes available
(2) When the read() call returns, this one call will return all of the data that was sent through the pipe, which is different behavior than if this was a socket
(3) If the read() call blocks, the process will be suspended until data arrives
(4) The write() call will return before all of the data has been written, if the corresponding read() call blocks mid-transfer
(5) Pipes can fill, which will cause the write() call to block until the read() call is able to read data from the pipe
Answer: Provided in the explanation section
Explanation:
int r, pipeFDs[2];
char message[512];
pid_t spawnpid;
pipe(pipeFDs);
spawnpid = fork();
switch (spawnpid)
{
case 0:
close(pipeFDs[0]); // close the input file descriptor
write(pipeFDs[1], "hi process, this is the STUFF!!", 21);
break;
default:
close(pipeFDs[1]); // close output file descriptor
r = read(pipeFDs[0], message, sizeof(message));
printf("Message received from other: %s\n", message);
break;
}
Observation of the program:
The read() call may block until data becomes available If the read() call blocks, the process will be suspended until data arrives Pipes can fill, which will cause the write() call to block until the read() call is able to read data from the pipe⇒ Therefore,Option 1,3 and 5 correct
Cheers i hope this helped !!!
Write a C++ program to find if a given array of integers is sorted in a descending order. The program should print "SORTED" if the array is sorted in a descending order and "UNSORTED" otherwise. Keep in mind that the program should print "SORTED" or "UNSORTED" only once.
Answer:
The cpp program for the given scenario is as follows.
#include <iostream>
#include <iterator>
using namespace std;
int main()
{
//boolean variable declared and initialized
bool sorted=true;
//integer array declared and initialized
int arr[] = {1, 2, 3, 4, 5};
//integer variables declared and initialized to length of the array, arr
int len = std::end(arr) - std::begin(arr);
//array tested for being sorted
for(int idx=0; idx<len-1; idx++)
{
if(arr[idx] < arr[idx+1])
{
sorted=false;
break;
}
}
//message displayed
if(sorted == false)
cout<< "UNSORTED" <<endl;
else
cout<< "UNSORTED" <<endl;
return 0;
}
OUTPUT
UNSORTED
Explanation:
1. An integer array, arr, is declared and initialized as shown.
int arr[] = {1, 2, 3, 4, 5};
2. An integer variable, len, is declared and initialized to the size of the array created above.
int len = std::end(arr) - std::begin(arr);
3. A Boolean variable, sorted, is declared and initialized to true.
bool sorted=true;
4. All the variables and array are declared inside main().
5. Inside for loop, the array, arr, is tested for being sorted or unsorted. The for loop executes over an integer variable, idx, which ranges from 0 till the length of the array, arr.
6. The array is assumed to be sorted if all the elements of the array are in descending order.
7. If the elements of the array are in ascending order, the Boolean variable, sorted, is assigned the value false and for loop is exited using break keyword. The testing is done using if statement.
8. Based on the value of the Boolean variable, sorted, a message is displayed to the user.
9. The program can be tested for any size of the array and for any order of the elements, ascending or descending. The program can also be tested for array of other numeric data type including float and double.
10. All the code is written inside the main().
11. The length of the array is found using begin() and end() methods as shown previously. For this, the iterator header file is included in the program.
In the lab, you defined the information systems security responsibility for each of the seven domains of a typical IT infrastructure. In which domain are you most likely to find service provider service level agreements (SLAs), managed security services, monitoring, and reporting?
Answer:
LAN/WAN domain
Explanation:
This is the boundary between trusted adn untrusted zones. All SLA's, managed security services, their monitoring and reporting is done by this domain.