Answer:
Since, 113 is on the confidence interval obtained (97.502, 114.098), so, we can suggest that is plausible that the true average IQ score for all seventh-grade female students at this school is 113.
Step-by-step explanation:
The question isn't complete, the missing part asked us to obtain a 99.5% confidence interval for the true average IQ score
Finding the confidence interval using the sample data provided, we can answer the question of plausibility.
Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.
Mathematically,
Confidence Interval = (Sample mean) ± (Margin of error)
Sample Mean = 105.8
Margin of Error is the width of the confidence interval about the mean.
It is given mathematically as,
Margin of Error = (Critical value) × (standard Error of the mean)
Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.
To find the critical value from the t-tables, we first find the degree of freedom and the significance level.
Degree of freedom = df = n - 1 = 31 - 1 = 30
Significance level for 99.5% confidence interval
(100% - 99.5%)/2 = 0.25% = 0.0025
t (0.0025, 30) = 3.03 (from the t-tables)
Standard error of the mean = σₓ = (σ/√n)
σ = standard deviation of the sample = 15
n = sample size = 30
σₓ = (15/√30) = 2.739
99.5% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]
CI = 105.8 ± (3.03 × 2.739)
CI = 105.8 ± 8.298
99.5% CI = (97.502, 111.387)
99.5% Confidence interval = (97.502, 114.098)
Since, 113 is on the confidence interval obtained, so, we can suggest that is plausible that the true average IQ score for all seventh-grade female students at this school is 113.
Hope this Helps!!!
Which of the following real-world problems can be modeled with the inequality 384+2x<6x? Marta charges a flat fee of $384 plus $2 per linear foot to decorate tables for a quinceanera. Carla charges $6 per linear foot to do the same. For what number of linear feet, x, will the cost of both decorators be the same? Shawna has made 384 campaign buttons for the student council election. She plans to make 2 more buttons each hour. Marguerite plans to make 6 campaign buttons per hour. For what number of hours, x, will Shawna have the same amount of campaign buttons as Marguerite? Super Clean house cleaning company charges $384 to power wash a house plus $2 per linear foot. Power Bright charges $6 per linear foot and no flat fee. For what number of linear feet, x, will the cost of Super Clean be more expensive than Power Bright? Mega Gym charges a $384 registration fee and $2 each time the gym is used. Super Gym charges a fee of $6 every time the gym is used. What number of times, x, will Super Gym need to be used to exceed the cost of Mega Gym?
Answer:
Mega Gym charges a $384 registration fee and $2 each time the gym is used. Super Gym charges a fee of $6 every time the gym is used. What number of times, x, will Super Gym need to be used to exceed the cost of Mega Gym?
Step-by-step explanation:
Given: the inequality is [tex]384+2x<6x[/tex]
To find: the correct option
Solution:
Let x denotes number of times gym is used.
As Mega Gym charges a $384 registration fee and $2 each time the gym is used,
Total amount charged by Mega Gym = [tex]\$(384+2x)[/tex]
As Super Gym charges a fee of $6 every time the gym is used,
Total amount charged by Super Gym = [tex]\$\,6x[/tex]
In order to find number of times, x Super Gym is used such that cost of Super Gym exceeds the cost of Mega Gym,
Solve the inequality:
cost of Super Gym > cost of Mega Gym
[tex]6x>384+2x\\384+2x<6x[/tex]
So, the correct option is '' Mega Gym charges a $384 registration fee and $2 each time the gym is used. Super Gym charges a fee of $6 every time the gym is used. What number of times, x, will Super Gym need to be used to exceed the cost of Mega Gym? ''
Help on this question please!!!
Answer:
Hello! Here is your answer
Step-by-step explanation:
112=4(28)
a=4b
You can only have one variable so:
Combine b to a:
a-b=84
4b-b=84
Divide both sides by 3:
3b/3=84/3
b=28
But that is not it:
Sum of both cards:
a+b
a=112
b=28
112+28=140
= 140
I hope I was of help. If not please let me know! Thank you! Good luck!
A student takes a multiple-choice test that has 11 questions. Each question has five choices. The student guesses randomly at each answer. Let X be the number of questions answered correctly. (a) Find P (6). (b) Find P (More than 3). Round the answers to at least four decimal places.
Answer:
a) P(6) = 0.0097
b) P(More than 3) = 0.1611
Step-by-step explanation:
For each question, there are only two possible outcomes. Either it is guessed correctly, or it is not. Questions are independent of each other. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
A student takes a multiple-choice test that has 11 questions.
This means that [tex]n = 11[/tex]
Each question has five choices.
This means that [tex]p = \frac{1}{5} = 0.2[/tex]
(a) Find P (6)
This is P(X = 6).
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 6) = C_{11,6}.(0.2)^{6}.(0.8)^{5} = 0.0097[/tex]
P(6) = 0.0097
(b) Find P (More than 3).
Either P is 3 or less, or it is more than three. The sum of the probabilities of these outcomes is 1. So
[tex]P(X \leq 3) + P(X > 3) = 1[/tex]
We want P(X > 3). So
[tex]P(X > 3) = 1 - P(X \leq 3)[/tex]
In which
[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{11,0}.(0.2)^{0}.(0.8)^{11} = 0.0859[/tex]
[tex]P(X = 1) = C_{11,1}.(0.2)^{1}.(0.8)^{10} = 0.2362[/tex]
[tex]P(X = 2) = C_{11,2}.(0.2)^{2}.(0.8)^{9} = 0.2953[/tex]
[tex]P(X = 3) = C_{11,3}.(0.2)^{3}.(0.8)^{8} = 0.2215[/tex]
[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0859 + 0.2362 + 0.2953 + 0.2215 = 0.8389[/tex]
Then
[tex]P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8389 = 0.1611[/tex]
P(More than 3) = 0.1611
The office needs 8 new devices worth $8000. The order consists of new computers (C ) which cost $925 each and printers (P) which cost $1125 each. How many of the new devices are computers and how many are printers?
Answer:
The number of computer is 5 and printer is 3
A standard deck of cards contains 52 cards. One card is selected from the deck. (a) Compute the probability of randomly selecting a seven or king. (b) Compute the probability of randomly selecting a seven or king or jack. (c) Compute the probability of randomly selecting a queen or spade.
Answer:
(a)[tex]\dfrac{2}{13}[/tex]
(b)[tex]\dfrac{3}{13}[/tex]
(c)[tex]\dfrac{4}{13}[/tex]
Step-by-step explanation:
In a standard deck, there are 52 cards which are divided into 4 suits.
(a)
Number of Seven Cards =4
Number of King cards =4
Probability of randomly selecting a seven or king
=P(Seven)+P(King)
[tex]=\dfrac{4}{52} +\dfrac{4}{52} \\=\dfrac{8}{52}\\=\dfrac{2}{13}[/tex]
(b)
Number of Seven Cards =4
Number of King cards =4
Number of Jack(J) cards =4
Probability of randomly selecting a seven or king
=P(Seven)+P(King)+P(Jack)
[tex]=\dfrac{4}{52} +\dfrac{4}{52}+\dfrac{4}{52} \\=\dfrac{12}{52}\\=\dfrac{3}{13}[/tex]
(c)
Number of Queen Cards =4
Number of Spade cards =13
Number of Queen and Spade cards =1
Probability of randomly selecting a seven or king
[tex]=P$(Queen)+P(Spade)-P(Queen and Spade Card)\\=\dfrac{4}{52} +\dfrac{13}{52} -\dfrac{1}{52} \\=\dfrac{16}{52} \\=\dfrac{4}{13}[/tex]
Can anybody help me with this one?
Answer:
12 cm
Step-by-step explanation:
The rule regarding secants and/or tangents is that the product of distances from their common point to the two intersection points with the circle is the same.
For the tangent the "two" intersection points with the circle are the same point, so ...
product of tangent lengths = product of secant lengths
(8 cm)(8 cm) = (4 cm)(4 cm +x)
Dividing by 4 cm gives ...
16 cm = 4 cm + x
12 cm = x
A car travelled 80km in 48minutes. find the speed of the car in km/hr
80km / 48 min = 1 2/3 km per minute.
1 2/3 km per minute x 60 minutes(1 hour) = 100 km per hour
Any help would be greatly appreciated.
There are 300 raffle tickets.
The prizes are as follows:
First prize - voucher for meal at local restaurant
Second prize - food hamper
Third prize - chocolate cake
4x homemade jams
3x homemade pickles
A prize is won after the first raffle ticket is drawn.
What is the probability of winning a prize when the next ticket is drawn?
Answer: 0.007
Step-by-step explanation:
Suppose that you have a ticket.
We have 3 prizes, and 300 tickets.
After the first tiket is drawn, someone win a prize, so now we have 299 tikets left and 2 prizes left.
Then, for the next draw, you have p = 1/299 of wining a prize.
If you did not win there, the probability for the third price is p = 1/298 (because there are 2 less tickets now)
Then the probability of winning at least one prize is:
P = 1/299 + 1/298 = 0.007
what is the radius of the circle that has an area of [tex]81*x*pi[/tex] degrees
Answer:
R=9
Step-by-step explanation:
the formula for area of a circle is pi r squared
where r denotes the radius of the circle
equating the formula for area with the area of the circle provided
p\i r squared = 81 p\i
r squared = 81
r = radical 81
r =9 inches
Which numbers are solutions of the inequality below? (Select all that apply.)
x − 2 < −8
a) 6
b) −6
c) 4
d) −8
Answer:
d) −8
Step-by-step explanation:
x − 2+2 < −8+2
x < -6
The only number less than -6 is -8
An unevenly heated plate has temperature T(x, y) in °C at the point (x, y). If T(2, 1) = 130, and Tx(2, 1) = 16, and Ty(2, 1) = −13, estimate the temperature at the point (2.03, 0.96). (Round your answer to 2 decimal places.)
Answer:
The estimated temperature at the point (2.03, 0.96) is 131
Step-by-step explanation:
In this question, we are to estimate the temperature at the given point using the temperature of the unevenly heated plate.
We proceed as follows;
In the question, we identify that the temperature at the point T(2,1) = 130 degrees celcius
Now, let’s look at how the temperature changes. There is a positive change of 16 units when we move across the x-axis and a negative decrease when we move up the y-axis to a tune of 16 units(negative)
Now, how does the problem wants us to move using the notation of change?
Look at the point (2.03, 0.96), since movement across the x-axis is positive, the motion here in terms of x i.e Δx is 0.03 while the corresponding motion in terms of y(albeit negative) is Δy = -0.04
Mathematically, the change in temperature is proportional to the distance traveled. What this means is that we need to multiply the changes in direction by the corresponding temperature. This is shown below;
ΔTx =Δx*Tx(2,1) => ΔTx = (0.03)*(16) = 0.48
ΔTy = Δy*Ty(2,1) => ΔTy = (-0.04)*(-13) = 0.52
We can now combine the equations above to form a single one as follows; which is an approximation;
ΔT = Δx*Tx(2,1) + Δy*Ty(2,1) => ΔT = (0.03)*(16) + (-0.04)*(-13) = 1
To arrive at the final answer, we add the change in temperature to the staring temperature which is ;
T(2.03,0.96) = T(2,1) + ΔT = 130 + 1= 131
Given that d is the midpoint of line segment ab and k is the midpoint of line segment bc, which statement must be true? (May give brainliest)
Answer:
B is the midpoint of line segment AC
In the western region of the state the times of all boys running in this event are normally distributed with standard deviation 12 seconds, but with mean 5 minutes 22 seconds. Find the proportion of boys from this region who qualify to run in this event in the state meet. (Hint: normalcdf)
Here is the full question.
The average finishing time among all high school boys in a particular track event in a certain state is 5 minutes 17 seconds. Times are normally distributed with standard deviation 12 seconds.
A. The qualifying time in this event for participation in the state meet is to be set so that only the fastest 5% of all runners qualify. Find the qualifying time in seconds (round it to the closest second). (Hint: Convert minutes to seconds.)
B. In the western region of the state the times of all boys running in this event are normally distributed with standard deviation 12 seconds, but with mean 5 minutes 22 seconds. Find the proportion of boys from this region who qualify to run in this event in the state meet. (Hint: normalcdf)
Answer:
a. x ≅ 337 seconds.
b. P(x > 337 ) = 0.1056
Step-by-step explanation:
A.
Given that ;
Mean [tex]\mu =[/tex] 5 minutes 17 seconds =( (60× 5)+17 ) seconds = 317 seconds ( since 60 seconds make 1 minute.
Standard deviation: [tex]\sigma[/tex] = 12 seconds.
Only the fastest 5% of all runners qualify
The objective is to determine the qualifying time in seconds
Let's look for the Z-score of 0.95;
The Z-score is 1.645 from the tables
[tex]x= ( \sigma * z ) + \mu[/tex]
[tex]x = ( 12 * 1.645 ) + 317 \\ \\x = 336.74[/tex]
x ≅ 337 seconds.
B. Given that the standard deviation = 12 seconds
Mean = 5 minutes 22 seconds = (5 × 60 + 22 )seconds = 322 seconds
he objective is to find P(x > 337 ) i.e the proportion of boys from this region who qualify to run in this event in the state meet.
we are using command normalcdf (SEE THE ATTACHED FILE BELOW FOR THE COMPUTATION)
we have P(x > 337 ) = 0.1056
An inverted conical tank starts the day with 250 ft^3 of crayon wax in it. As the factory commences work, the tank is filled with an additional 40 ft^3 of wax per minute. The height of the wax is modeled by H(V)=3 piV/25. A. Write a function , V(t) to model the volume of wax in the tank after t minutes. B. Find an expression for the composition (HoV)(t) C. The composition in B (above) can be described as the ________ of the wax in terms of _______
Answer:
A. V(t) = 40t + 250 B. (HoV)(t) = 24πt/5 + 30π C. The composition in B (above) can be described as the height of the wax in terms of time.
Step-by-step explanation:
A. Let the rate of change of volume V with respect to time be dV/dt = 40 ft³/min
Solving this, V = 40t + C. At the start of the day, that is t = 0, V = 250 ft³
Substituting these values, we have
250 ft³ = 40(0) + C
C = 250 ft³
So, V(t) = 40t + 250
B. Since H(V) = 3πV/25
(HoV)(t) = 3π(40t + 250)/25
= 24πt/5 + 30π
C. The composition in B (above) can be described as the height of the wax in terms of time.
The length of the sides of a square are initially 0 cm and increase at a constant rate of 8 cm per second. Write a formula that expresses the side length of the square, s (in cm), in terms of the number of seconds, t , since the square's side lengths began growing. s
Answer:
s(t)=8t
Step-by-step explanation:
The length of the sides of a square are initially 0 cm and increase at a constant rate of 8 cm per second.
Let the length of the Square = s
[tex]\dfrac{ds}{dt}=8 $cm/seconds, s_0=0 cm[/tex]
We solve the differential equation above subject to the given initial condition.
[tex]\dfrac{ds}{dt}=8\\ds=8$ dt\\Take the integral of both sides\\\int ds=\int 8$ dt\\s(t)=8t+C, where C is the constant of integration\\When t=0, s=0cm\\s(0)=0=8(0)+C\\C=0\\Therefore, s(t)=8t[/tex]
The formula that expresses the side length of the square, s (in cm), in terms of the number of seconds, t , since the square's side lengths began growing is:
s(t)=8t (in cm)
In ΔEFG, ∠E \cong≅∠G, GE = 7 and FG = 15. Find the length of EF.
Answer: EF = 15
Step-by-step explanation:
The given description is that of an isosceles triangle. The base angles are congruent, therefore the sides opposite of those angles are also congruent.
The base angles are ∠E and ∠G and the vertex angle is ∠F.
The sides opposite to the base angles are EF and FG.
Thus, EF ≡ FG.
Since FG = 15 and FG = EF, then 15 = EF.
Based on the definition of an isosceles triangle, the length of EF in the triangle is: 15 units.
What is an Isosceles Triangle?An isosceles triangle has two sides that are congruent. The angles opposite these congruent sides are also congruent.
ΔEFG is an isosceles triangle. The congruent sides are, FG and EF.
Therefore, EF = FG = 15 units.
Learn more about isosceles triangle on:
https://brainly.com/question/11884412
please help!! Select the two reasons which fit best in lines 1 and 2 of the proof (given and details in photo)
A: 1.) Vertical Angles are congruent
2.) SSS Congruence Postulate
B: 1.) Definition of Angle Bisectors
2.) SAS Congruence Postulate
C: 1.) Vertical Angles are congruent
2.) AAS Congruence Postulate
D. 1.) Vertical Angles are congruent
2.) SAS Congruence Postulate
Answer:
D
Step-by-step explanation:
Line 1: Since these angles are vertical, they are congruent
Line 2: We have 2 sides and an angle in between them so it is SAS
This means the answer is D.
Answer: The correct answer is this set:
1.) Vertical Angles are congruent
2.) SAS Congruence Postulate
Very confused, need help quick! (see attachment) Simplify and show your work.
Answer:
27/(4x^6y^8)
Step-by-step explanation:
Target the variables first. (x^a)^b is the same as x^(a x b).
In the numerator, it is x^(2 x 3) , which is x^6, and y^(4 x 3), which is y^12.
Same principle on the bottom. the denominator is x^12 and y^20.
In the numerator, the number 4 is alone so don't do anything to it. Cube 3. The coefficient of the numerator is 4 x 3^3 . The coefficient of the denominator is 2^4. Cancel like terms. when you divide same terms' exponents, you subtract the exponent on top by the exponent on the bottom. Remember that you can only simplify LIKE terms. (x with x, y with y, number with number.)
What is 1.036 that add up to 4
Answer:
2.964
Step-by-step explanation:
A random sample of 1141 men and 1212 women aged 25-64 y (response rate 76%) completed a questionnaire and underwent a short examination in a clinic. Intake of beer, wine and spirits during a typical week, frequency of drinking, and a number of other factors were measured by a questionnaire. The present analyses are based on 891 men and 1098 women who were either nondrinkers or 'exclusive' beer drinkers (they did not drink any wine or spirits in a typical week). 500 men are beer drinkers and 325 men from this group have the obesity. 80 non-drinkers men are obese.
Required:
a. What type of study desing?
b. Which parameters can be calculated?
c. Determine it and explain the results.
Answer:
(a) A cross sectional study (b) The parameter can be computed as follows: Non-drinkers who agree exposed to obesity, Drinkers who are exposed or vulnerable to obesity (c) A postie relationship is established from the experiment between drinkers who are exposed to obesity and non drinkers who are exposed to obesity
Step-by-step explanation:
(a) The type of design is refereed to as a cross sectional study
(b) Now, because 50 men are beer drinkers out of 891 men.
Hence we can deduce form this that 500/891 gives us 0.56%.
This suggest that 0.56% men are beer drinkers out of which 325 have obesity, lets take for example 235/500 = 0.65% are exposed to obesity in which 80/ (89-500) = 80/491 = 0.16%
The non drinkers are 0.16% and are not exposed to obesity
Thus,
The parameters to be calculated is stated below:
Non-drinkers who agree exposed to obesityDrinkers who are exposed or vulnerable to obesity(c) The next step is to determine and explain the results.
In this case we can say there is a positive relationship between drinkers and non drinkers, since from the experiment 0.65% are exposed to obesity and 0.16$ non drinkers are exposed to obesity.
Classify the triangle by its sides, and then by its angles.
60 degrees
60 degrees
60 degrees
4 ft
4 ft
4 ft
Classified by its sides, the triangle is a(n)
▼
equilateral
scalene
isosceles
triangle.
Classified by its angles, the triangle is a(n)
▼
obtuse
acute
right
triangle.
Answer:
Equilateral, acute
Step-by-step explanation:
Equilateral triangles have all sides the same length (all sides are 4 ft in this triangle, so it is equilateral).
Acute triangles have no angles that are greater than or equal to 90 degrees (all angles are 60, which is less than 90, so it is acute).
Drag each description to the model and equation it matches.
Tell me if it is right
Answer:
213, 123
Step-by-step explanation:
The probability that an event will happen is Upper P (Upper E )equalsStartFraction 13 Over 17 EndFraction . Find the probability that the event will not happen. The probability that the event will not happen is nothing.
Answer:
The probability that the event will not happen is [tex]\frac{4}{17}[/tex]
Step-by-step explanation:
The occurrence of an event can be divided into two parts, the event would occur or the event would not occur. But the probability of an event is 1.
From the given question;
The probability of the event = 1
The probability that the event will happen, P = [tex]\frac{13}{17}[/tex]
Thus,
The probability that the event will not happen = probability of the event - probability that the event will happen
= 1 - P
= 1 - [tex]\frac{13}{17}[/tex]
= [tex]\frac{17 - 13}{17}[/tex]
= [tex]\frac{4}{17}[/tex]
Thus, the probability that the event will not happen is [tex]\frac{4}{17}[/tex].
1 adult and 6 children went swimming. How much did they pay together
Answer:
[tex]x+6y[/tex] where x is the cost of one adult ticket and y is the cost of one child ticket.
Step-by-step explanation:
This is an incomplete question since we would need to know the cost of the adult ticket and the cost of the children ticket.
However, let's say that the price is x dollars per adult and y dollars per child.
Now, we need to find out how much one adult and 6 children paid.
Thus, we would have to multiply the cost per adult by the number of adults and the cost per child per number of children and then sum up these two results.
Writing this in an algebraic way we would have:
[tex]1(x)+6y\\x+6y[/tex]
Thus, 1 adult and 6 children would have paid x + 6y dollars where x is the cost of the adult ticket and y is the cost of the children ticket.
(For example, if an adult ticket is 6 dollars and a child ticket is 4 dollars we would have that they paid 6 + 6(4) = 6 + 24 = 30 dollars)
Write an equation of a line that contains the following two points in slope intercept form
(-2,4) (3,-1)
Answer:
y = -x + 2
Step-by-step explanation:
The slope intercept form equation of this line can be written like this :
y = my + p ; where m is the slope and p is the y intercept.
[tex]m = \frac{-1-4}{3-(-2)} = \frac{-5}{5} =-1[/tex]
then the equation becomes y = -x + p
(-2,4) is a point of the line means 4 = -(-2) + p
then p = 4 - 2 = 2
finally, y = -x + 2
g It is known that 20% of products on a production line are defective. Products are inspected until first defective is encountered. a) What is the probability that the experimenter must inspect six products
Question:
It is known that 20% of products on a production line are defective. Products are inspected until first defective is encountered. a) What is the probability that the experimenter must inspect six products to find a defective product?
Answer:
P(x = 6) = 0.0655
P(x = 6) = 6.55%
Step-by-step explanation:
It is given that 20% of products on a production line are defective.
p = 0.20
Then
q = 1 - p = 1 - 0.20 = 0.80
Which means that 80% of products on the production line are not defective.
We want to find out the probability that the experimenter must inspect six products to find a defective product.
Let x is the number of inspections to get a defective product.
P(x = 6) = ?
If out of 6 inspections 1 is defective then it means 5 are not defective
so the probability is
P(x = 6) = p¹ × q⁵
P(x = 6) = 0.20¹ × 0.80⁵
P(x = 6) = 0.20 × 0.32768
P(x = 6) = 0.0655
P(x = 6) = 6.55%
Therefore, there is 6.55% chance that the experimenter finds a defetive product in 6 inspections.
Jack uses triangles in the construction of bridges, such as the one shown below. A triangle has angles G, 72 degrees, and blank. The exterior angle to the blank angle is 133 degrees. What is the measure of Angle?
Answer: The answer is 61
Step-by-step explanation: did it on 2020 edg pls mark me brainliest
Answer:
61
Step-by-step explanation:
Find the value of z Subscript alpha divided by 2 that corresponds to a confidence level of 89.48%.
Answer:
For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]
Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:
[tex] z_{\alpha/2}= \pm 1.62015[/tex]
And we can use the following excel code for example:
"=NORM.INV(0.0526,0,1)"
Step-by-step explanation:
For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]
Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:
[tex] z_{\alpha/2}= \pm 1.62015[/tex]
And we can use the following excel code for example:
"=NORM.INV(0.0526,0,1)"
If an arrow is shot upward on Mars with a speed of 52 m/s, its height in meters t seconds later is given by y = 52t − 1.86t2. (Round your answers to two decimal places.) (a) Find the average speed over the given time intervals.
Answer:
A. (I) v = 46.42 m/s; (ii) v = 47.35 m/s; (III) v = 48.09 m/s; (iv) v = 48.26 m/s; (v) v = 58.28 m/s
B. v = 48.28 m/s
Note: the question is missing some values. The full Question is provided below:
If an arrow is shot upward on Mars with a speed of 52 m/s, its height in meters t seconds later is given by y = 52t − 1.86t2. (Round your answers to two decimal places.)
(a) Find the average speed over the given time intervals. (i) [1, 2] m/s (ii) [1, 1.5] m/s (iii) [1, 1.1] m/s (iv) [1, 1.01] m/s (v) [1, 1.001] m/s
(b) Estimate the speed when t = 1. m/s
Step-by-step explanation:
Height, y = 52t - 1.86t²
Velocity = ∆y/∆t = 52 - 1.86 * 2t = 52- 3.72t
A. Average velocity = (v1 + v2)/2
(i) At t = 1, 2
Average velocity = (52 - 3.72*1 + 52 -3.72*2)/2 = 46.42 m/s
(ii) At t = 1,1.5
Average velocity = (52 - 3.72*1 + 52 - 3.72*1.5)/2 = 47.35 m/s
(iii) At t = 1,1.1
Average velocity = (52 - 3.72*1 + 52 -3.72*1.1)/2 = 48.09m/s
(iv) At to = 1, 1.01
Average velocity = (52 - 3.72*1 + 52 - 3.72*1.01)/2 = 48.26 m/s
(iv) At t = (1, 1.001)s
Average velocity = (52 - 3.72*1 + 52 - 3.72*1.001)/2 = 48.28 m/s
B. Speed at t = 1s
Velocity = 52 - 3.72 * 1 = 48.28 m/s
Please help. I’ll mark you as brainliest if correct!
answer is g(x)=|x+2|-1
[tex]answer \\ g(x) = - |x + 2| - 1\\ as \: we \: can \: see \: from \: the \: given \: graph \\ above \: that \: the \: graph \: of \: absolute \\ function \: has \: been \: reflected \: over \: the \\ x \: axis \: \: shifted \: 2 \: units \: left \: and \: 1 \: \\ units \: down. \\ due \: to \: reflection \: there \: is \: a \: negative \\ sign \: shift \: of \: 2 \: units \: left \: is \: given \\ by \: x + 2 \: and \: 1 \: units \: down \: is \: given \\ by \: - 1 \\ hope \: it \: helps[/tex]