Answer: experimental design
the accuracy of data-collecting devices
human error
bias in selecting samples
incorrect data analysis
incorrect treatment of the control group
Explanation:
Instrumental, environmental, procedural, and human errors are frequent causes. Depending on how they affect the outcomes, each of these errors can either be random or systematic.
What are Experimental Error?The discrepancy between a measured value and its true value is known as experimental error. In other words, the error or inaccuracies are what prevent us from perceiving a measurement that is 100 percent accurate.
Every measurement has some degree of experimental error, which is fairly common. Due to the widespread belief that some degree of error is inherent to the scientific method, it is not typically seen as a "mistake" in the classic sense.
However, scientists can reduce error and obtain results that are more accurate by embracing and comprehending the ways that experimental error can affect any scientific operation.
The potential sources of error in experiment are Instrumental, environmental, procedural, and human errors.
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Benda setinggi 3 cm diletakkan pada jarak 10 cm di depan cermin cekung yang berjari-jari
kelengkungan 10 cm. Tentukan:
Jarak bayangan
Perbesaran bayangan
Sifat bayangan
Answer:
a) Shadow distance
10 cm in front of the mirror.
b) Zoom in the shadow
The shadow formed is the same height as the object and is placed also at the centre of curvature of the mirror as shown in the attached image to this solution.
c) The nature of the shadow
The shadow formed is real, inverted, same size as the object and formed at the centre of curvature.
Explanation:
English Translation
Objects as high as 3 cm are placed at a distance of 10 cm in front of a concave mirror with 10 cm curvature. Determine:
a) Shadow distance
b) Zoom in the shadow
c) The nature of the shadow
Solution
The mirror equation is given as
(1/f) = (1/v) + (1/u)
f = focal length of the mirror = (radius of curvature)/2 = 10/2 = 5 cm
v = image distance = ?
u = object distance = 10 cm
We can then calculate the shadow' s distance from the mirror thus
(1/5) = (1/v) + (1/10)
(1/v) = 0.2 - 0.1 = 0.1
v = (1/0.1) = 10 cm
b) Zoom in the shadow
Since the object is placed at the centre of curvature, as shown in the attached image, the image is formed at a point of intersection of rays. The image formed is the same height as the object and is placed also at the centre of curvature of the mirror.
c) The nature of the shadow
Since the mirror is a concave mirror, the image is real and formed in front of the mirror. The image is also inverted and formed at the centre of curvature of the mirror.
Hope this Helps!!!
Just need the answer to D please
The boat has to pull with MORE force. Don't forget about the force of friction with the water, pulling the skier in the backwards direction. The force that accelerates him is the NET force ... boat force minus water resistance. So the boat force has to be greater than the net accelerating force.
3.
If you are part of a center or network, you can use program-level data to
A. change the way you record and maintain information.
B. identify professional development needs.
C. improve the management systems to support child learning.
D. change the way you speak with families
Answer:
A
Explanation:
Answer: A
Explanation:
A) Is it possible for an object that, object with zero acceleration have velocity? If yes give an example if not give its proof.
Answer:
Yes, in case of uniform velocity
Explanation:
This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.
Since, acceleration is defined as the rate of change of velocity.
Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.
a = ΔV/t = 0/t
a = 0 m/s²
So, the acceleration of the body is 0 m/s², but it has a uniform velocity
Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.
a care starting from rest has an acceleration 0.3 m/s square, calculate the velocity and distance travelled by this car after 2 minutes?
Answer:
Final velocity (v) = 36 m/s
Distance traveled (s) = 2,160 m
Explanation:
Given:
Initial velocity (u) = 0
Acceleration (a) = 0.3 m/s
Time travel (t) = 2 minutes = 120 seconds
Find:
Final velocity (v) = ?
Distance traveled (s) = ?
Computation:
v = u + at
v = 0 + 0.3(120)
v = 0.3(120)
v = 36 m/s
Final velocity (v) = 36 m/s
Distance traveled (s) = ut + (1/2)at²
Distance traveled (s) = (0.5)(0.3 × 120 × 120)
Distance traveled (s) = 2,160 m
Ahoy starting from rest moves with a distance of 200m in 10 seconds...Find the magnitude of acceleration
Answer:
The magnitude of acceleration is 2m/s² .
Explanation:
First, you have to find the velocity as it starts to travel 200m in 10s. The formula of velocity is V = Distance/Time, then you have to substitute the values into the formula :
[tex]v = d \div t[/tex]
[tex]let \: d = 200 \\ let \: t = 10[/tex]
[tex]v = 200 \div 10[/tex]
[tex]v = 20m/s[/tex]
Next, you have to substitute the values into the acceleration formula, a = (v-u)/t where v represents final velocity, u is initial velocity and t is time taken :
[tex]a = \frac{v - u}{t} [/tex]
[tex]let \: v = 20 \\ let \: u = 0 \\ let \: t = 10[/tex]
[tex]a = \frac{20 - 0}{10} [/tex]
[tex]a = \frac{20}{10} [/tex]
[tex]a = 2m/ {s}^{2} [/tex]
PLEASE HELP. Really important
Explanation:
2) C would need the least effort, because the longer the effort distance, the least the effort applied.
what are two things that are infinite?
Answer:
Infinity = Never ending
Explanation:
The universe could be infinite, both in terms of space and time, but there is currently no way to test whether it goes on forever or is just very big. The part of the universe we are able to observe is finite, measuring about 46 billion light years in diameter.
The set of natural numbers is an infinite set. This kind of infinity is, by definition, called countable infinity. All sets that can be put into a bijective relation to the natural numbers are said to have this kind of infinity. This is also expressed by saying that the cardinal number of the set is aleph-naught (ℵ0).
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STARS ARE INFINITE , NUMBERS ARE INFINITE
Explanation:
How much energy (in Joules) is released when 12.0 g of water cools from 20.0 °C to 11.0 °C? This is a grade 10 question from the Climate unit (from Canada)
Answer: - 452.088joule
Explanation:
Given the following :
Mass of water = 12g
Change in temperature(Dt) = (11 - 20)°C = - 9°C
Specific heats capacity of water(c) = 4.186j/g°C
Q = mcDt
Where Q = quantity of heat
Q = 12g × 4.186j/g°C × - 9°C
Q = - 452.088joule
potential energy is frequintly converted into kenetic energey. kenetic energey
Answer:
When an object falls, its gravitational potential energy is changed to kinetic energy. ... Gravitational potential energy for a mass m at height h near the surface of the Earth is mgh more than the potential energy would be at height 0. (It's up to you where you choose height 0.)
Explanation:
Answer:
Qwertyujiknb vcdxrftyhbvcdxrft6y7uij
Explanation:
a motorcar is moving with a velocity of 108 km / h and it takes 4s to stop after the brakes are applied calculate the force exerted by the brakes on the motorcar if it's mass along with the passengers is 1000 kg
Answer: - 7500N
Explanation:
Given the following :
Initial Velocity of car = 108km/hr
Time taken to stop after applying brakes = 4s
Mass of passengers in car = 1000kg
Force exerted by the brakes on the car =?
After 4s, then final Velocity (V) = 0
Initial Velocity (u) of the car = 108km/hr
108km/hr = (108 × 1000)m ÷ (3600)s = 30m/s
Force exerted = mass(m) × acceleration(a)
Acceleration of car = Change in Velocity with time
a = (v - u) / t
a = (0 - 30) / 4
a = - 30/ 4
a = - 7.5m/s^2
Therefore,
Force exerted = mass(m) × acceleration(a)
Force exerted = 1000kg × (-7.5)m/s^2
Force exerted = - 7500N
Answer:
The force exerted by the brakes on the motor car is -7500 N.
Explanation:
Given :-
Mass of the motor car along with passengers (m)= 1000 kgInitial velocity (u) = 108 km/hTime taken (t) = 4 sTo find :-
The force exerted by the brakes on the motor car.Solution :-
Since the car stops, the final velocity (v) will be 0 m/s.
• Initial velocity (u) = 108 km/h.
Converting initial velocity into m/s.
We know that,[tex] \sf{1\:km/h=\dfrac{5}{18}\:m/s}[/tex]
Then initial velocity,
= [108 × 5/18 ] m/s
= 30 m/s
Now find the force exerted by the brakes.
★ Formula used :
[tex]{\boxed{\sf{F=\dfrac{m(v-u)}{t}}}}[/tex]
[put values][tex]:\implies \sf \: F= \dfrac{1000(0 - 30)}{ 4} \\ \\ : \implies \sf \: F \: = \dfrac{ - 30000}{4} \\ \\ : \implies \sf \: F \: = - 7500[/tex]
The force exerted by the brakes on the motor car = -7500 N.
•The negative sign of force(F) means that the force was applied in opposite direction of motion.
__________________a motorcar is moving with a velocity of 108 km / h and it takes 4s to stop after the brakes are applied calculate the force exerted by the brakes on the motorcar if it's mass along with the passengers is 1000 kg
Answer:
-7500 N
Explanation:
v₀ = 108 km/h = 30 m/s
v = 0 m/s
t = 4 s
a = Δv / Δt
a = (0 m/s − 30 m/s) / 4 s
a = -7.5 m/s²
F = ma
F = (1000 kg) (-7.5 m/s²)
F = -7500 N
Answer:-7500
Explanation v₀ = 108 km/h = 30 m/s
v = 0 m/s
t = 4 s
a = Δv / Δt
a = (0 m/s − 30 m/s) / 4 s
a = -7.5 m/s²
F = ma
F = (1000 kg) (-7.5 m/s²)
F = -7500 N
Ethan pushes a wooden box across a carpeted floor. Then he pushes the same box across a smooth marble floor. Why does Ethan find it easier to push the box on the marble floor than on the carpeted floor?
A. The box experiences more friction on the marble floor.
B.The box experiences less friction on the marble floor.
C.The box experiences more applied force on the marble floor.
D.The box experiences less normal force on the marble floor.
Answer:
B.The box experiences less friction on the marble floor
Explanation:
Answer:
B. The Box experiences less friction on the marble floor
Explanation:
This is because the the carpet is not a flat surface and the marble is smooth
right auricale is bigger then left aurical, why?
Explanation:
Veins carry deoxygenated blood from different parts of the body to our heart. ... Since a larger volume of blood is collected in the right auricle than that of the left auricle, right auricle is larger than the left auricle.
A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65 m/s in 5 seconds. What
is the acceleration?
-13 m/s
-6 m/s²
6mis?
13 m/s2
Acceleration = (change in speed) / (time for the change)
Change in speed = (speed after the change) - (speed before the change)
Change in speed = (65 m/s) - (35 m/s) = 30 m/s
Acceleration = (30 m/s) / (5 s)
Acceleration = 6 m/s²
Consider a cylindrical crew module with a diameter of 5 meters, a length of 15 meters, and a crew of 6 people. The module contains air that is at
standard sea-level atmospheric pressure and temperature. The sea level density of air at 20 degrees Celsius is 1.204 kg/m3.
What is the volume of the crew module? Provide your answer in m' with at least 2 decimal places.
Answer:
294.524 m^3
Explanation:
The volume of a cylinder is given by the formula ...
V = πr^2h
For a radius of 2.5 m and a length of 15 m, the volume is ...
V = π(2.5 m)^2(15 m) = 93.75π m^3 ≈ 294.524 m^3
The volume is about 294.52 cubic meters.
I NEED ANSWER RN OR ILL BE DED
Answer:
i) O m/s² as velocity is constant
ii) 20m/s
iii)Hint:Calculate the area of the graph,that is;below the line, for the first 15 seconds only
Hope this helps.
a vector points 12.0 units along the x-axis and 9.00 units along the y-axis. find the magnitude of the vector
Explanation:
R = [tex]\sqrt{(12.0)^{2} + (9.00)^{2}}[/tex] = 15 UNIDADES
What is the wavelength of a 1.28 x 10^17 Hz wave?
Answer:
The wavelength of the wave is 2.34 nm.
Explanation:
It is required to find the wavelength of a [tex]1.28\times 10^{17}\ Hz[/tex] wave. A wave moves with a speed of light. Speed of a wave is given in terms of wavelength and frequency. So,
[tex]v=f\lambda[/tex]
[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{1.28\times 10^{17}}\\\\\lambda=2.34\times 10^{-9}\ m\\\\\text{or}\\\\\lambda=2.34\ nm[/tex]
So, the wavelength of the wave is 2.34 nm.
The wavelength of the wave is 2.34 × 10⁻⁹ meters.
Given the data in the question;
Frequency; [tex]f = 1.28*10^{17}Hz[/tex]Wavelength; [tex]\lambda =\ ?[/tex]
To determine the wavelength of the wave, we use the expression for the relations between wavelength, frequency and speed of light.
[tex]\lambda = \frac{c}{f}[/tex]
Where [tex]\lambda[/tex] is wavelength, f is frequency and c is speed of light ( [tex]3*10^8m/s[/tex] )
We substitute our values into the equation
[tex]\lambda = \frac{3*10^8m/s}{1.28*10^{17}Hz} \\\\\lambda = \frac{3*10^8m/s}{1.28*10^{17}s^{-1}} \\\\\lambda = 2.34 * 10^{-9}m[/tex]
Therefore, the wavelength of the wave is 2.34 × 10⁻⁹ meters.
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Which of the following characterizes the particles in this diagram?
A. Two positive charges
B. One positive charge and one negative charge
C. Two negative charges
D. Two neutral charges
Answer:
B
Explanation:
One positive charger and one negative charger
conditions for equilibriam
Assume that a machine puts out 8000 joules of work when the user puts in 10,000 joules of work. What is the efficiency of the machine?
Answer:
80 Percent
Explanation:
E=energy output/energy input×100
E=8000/10000×100
E=0.8×100
E=80 percent.
Mark brianliest if my answer suit your question
If the machine put, in 8000 J, and the user puts 10,000 J of work then the efficiency of the machine will be equal to 80%.
What is Work?Work is a physics term used to describe the transfer of energy that takes place when an object changes above a distance because of an external force, at least some of which is given in the vector of the dislocation. The element of the force acting all along the path multiplied by the length of the path can be used to calculate work if the force is constant.
Mathematically, this idea is expressed as W = fd, where W is the effort and f is the force multiplied by d, the distance. Work is completed whenever the force is applied at an angle with about the displacement.
As per the data provided in the question,
Total input energy = 10,000 J
Total output energy = 8,000 J
Then, the efficiency (η) of the machine will be,
η = (output energy/input energy) × 100
η = 8000/10000 × 100
η = 80%.
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Explain how series circuits use current and voltage and Explain how parallel circuits use current and voltage
'''In a series circuit, the sum of the voltages consumed by each individual resistance is equal to the source voltage. Components connected in parallel are connected along multiple paths so that the current can split up; the same voltage is applied to each component.''
A closed-pipe resonator has a length of 1.73 m. The frequency of its second harmonic if the speed of sound is 343 m/s is: a)49,5 Hz b)99.13 Hz c)20.6 Hz d)72 Hz
Answer:
There is no answer, since a closed-pipe resonator can NOT have a second harmonic. However, if you were to plug the pipe length and the speed of sound into the closed-pipe equation anyway you would get 49.56 as your fundamental frequency, which means that 99.13 would be your "plug and play" 2nd harmonic.
Explanation:
If mass = 30kg, gravity = 10 N/kg and height is 2m of a car. Calculate the gravitational potential energy.
Answer:
P.E.=600Nm
Explanation:
m=30kg
g=10m/s²
h=2m
P.E.=?
as we know that
P.E.=mgh
P.E.=30kg×10m/s²×2m
P.E.=600Nm
Which of these would not improve accuracy?
A)Taking a bigger sample size
B)Using a bigger range of the independent variable
C)Using measuring instruments that can read to a greater number of decimal places
D)Remove anomalies
40 POINTS!!! + BRAINLIEST!!!
In your own words, explain how a pendulum demonstrates the concepts of the conservation of energy. (1 or 2 sentences long)
Answer:
I think it is better if you read and shortly write my explanation
Explanation:
simple pendulum with no friction, mechanical energy is conserved. Total mechanical energy is a combination of kinetic energy and gravitational potential energy. As the pendulum swings back and forth, there is a constant exchange between kinetic energy and gravitational potential energy.
An escalator is used to move 25 passengers every minute from the first floor of a department store to the second. The second floor is located 5.30 meters above the first floor. The average passenger's mass is 60 kg. Determine the power requirement of the escalator in order to move this number of passengers in this amount of time.
Please help me quickly!
Answer:
1298.5watt
Explanation:
Power is defined as the rate at which work is done
Expressed mathematically as;
P = F × d/ t; F = force or weight of object ;d is height or distance sustain and t is time covered
Hence for 1 person the power consumption is ;
Note weight =mass× acceleration of free fall due to gravity,g
g is known as 9.8m/S2
Time taken is 1min which is 60 sec
60 ×9.8 × 5.3/60 = 51.94 watt
Hence for 25 persons we have
25 × 51.94 =1298.5watt
1.3kilo watt( kilo is 1000)
The work done by the escalator is 3,080.4 joules and the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.
The Work Done is calculated as:
Force (F) = 60 × 9.8
Distance (d) = 5.30 meters
Work (W) = F × d
Work (W) = (60 × 9.8) × 5.30
Work (W) = 3,080.4 joules
The Power is calculated as:
Time (t) = 1 minute
Power (P) = Work / Tim (t)
Power (P) = 3,080.4 / 60
Power (P) = 51.34 watts
Therefore, the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.
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An injured monkey sits perched on a tree branch 9 m above the ground, while a wildlife veterinarian is kneeling down in the bushes 90.0 m away attempting to subdue the monkey with a tranquilizer gun. The vet knows that the moment the gun fires, the monkey will be frightened and fall down from the branch. At what angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey? Given the angle, what is minimum speed at which the tranquilizer dart must leave the gun to still hit the monkey?
Answer:
The hunter should aim directly at the perched monkey because the tranquilizer dart will fall away from the line sight at the same rate that the monkey falls from its perch.
Tan theta = 9 / 90 = .1 so theta = 5.71 deg
The time for the monkey to reach the ground is
t = (2 h / g)^1/2 = (18 / 9.8)^1/2 = 1.36 sec
So the horizontal speed of the dart must be at least
Vx = 90 m / 1.36 sec = 66.4 m/s
Vx = V cos theta
V = 66.4 m/s / cos 5.71 = 66.7 m/s
The angle of projection of the tranquilizer dart is 5.7⁰
The horizontal speed of the tranquilizer dart is 66.5 m/s
The given parameters;
vertical position of the monkey, y = 9 mhorizontal position of the veterinarian, x = 90The angle of projection of the tranquilizer dart is calculated as;
[tex]tan(\theta) = \frac{y}{x} \\\\tan(\theta) = \frac{9}{90} \\\\tan(\theta) = 0.1\\\\\theta = tan^{-1}(0.1)\\\\\theta = 5.71 ^0[/tex]
The speed of the tranquilizer dart is calculated as;
X = v₀ₓt
where;
t is the time to reach maximum height
X is the horizontal displacement = 90 m
The time to reach maximum height is calculated as;
[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 9}{9.8} } \\\\t = 1.36 \ s[/tex]
The horizontal speed of the tranquilizer dart is calculated as;
[tex]X = v_0cos(\theta) \times t\\\\90 = v_0\times cos(5.71) \times 1.36\\\\90 = 1.353 v_0\\\\v_0= \frac{90}{1.353} \\\\v_0 = 66.5 \ m/s[/tex]
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The amplitude of a particle executing simple harmonic motion is 5cm, while its angular velocity is 10 rads -1 . Calculate the magnitude of the maximum acceleration of the particle.
Answer:
a_max = 50 cm/s^2
Explanation:
To find the magnitude of the maximum acceleration of the particle, you take into account the equation of motion in a simple harmonic motion:
[tex]x=Acos(\omega t)[/tex]
ω: angular velocity = 10 rad/s
A: amplitude = 5 cm
The acceleration is given by:
[tex]a=\omega^2 x[/tex]
and the maximum acceleration is obtained when the cosine function is maximum, that is, when cos(wt) = 1. Then, you have:
[tex]a_{max}=\omega^2 x_{max}=\omega^2A[/tex]
Then, you replace the values of w and A in order to calculate a_max:
[tex]a_{max}=(10rad/s)^2(5cm)=50\frac{cm}{s^2}[/tex]
hence, the maximum acceleration is 50 cm/s^2