What determines the placement of an element on the Periodic table

Answer:

You need to convert 27.8 miles to km and gallon to liters, then

(km/L) x #L = ?

27.8×112

=?

?×1gal

=?

?×1mi

=?

=?×?×?

answer

Answer:

) B

Explanation:

Answer:

is it c

Explanation:

Answer:

A =8

B =8

C = O oxygen

D =26

E =30

F = Fe iron

Explanation:

No of protons = atomic number

No of protons + number of neutrons = atomic mass

Answer:

Using the periodic table, complete the table to describe each atom. Type in your answers.

A     ⇒ 20

B     ⇒ 40

C      ⇒ Ca

D     ⇒ 10

E      ⇒ 9

F      ⇒ F

Explanation:

yes

Answer:1.8 moles Fe and 2.7 moles CO2

Explanation:

Answer:

1.8 moles Fe and 2.7 moles CO2

Answer:

The sun

Explanation:

I did it and got it correct :-)

Answer:

independent varible

Explanation:

Answer : The mass in grams of calcium sulfate is 0.16 grams.

Explanation :

Molarity : It is defined as the number of moles of solute present in one litre of solution.

Formula used :

[tex]Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution}}[/tex]

Solute is, [tex]CaSO_4[/tex]

Given:

Molarity of [tex]CaSO_4[/tex] = 0.0025 mol/L

Molar mass of [tex]CaSO_4[/tex] = 136 g/mole

Volume of solution = 485 mL

Now put all the given values in the above formula, we get:

[tex]0.0025=\frac{\text{Mass of }CaSO_4\times 1000}{136\times 485}[/tex]

[tex]\text{Mass of }CaSO_4=0.16g[/tex]

Thus, the mass in grams of calcium sulfate is 0.16 grams.

Answer

Two different elements have similar chemical properties when they have the same number of valence electrons in their outermost energy level. ... Elements in the same column of the Periodic Table have the same number of valence electrons – that's why they have similar chemical properties.

Statement that can be considered true as regards periodic table is : A: Elements in the same column share similar properties.

Therefore, option A is correct.

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Answer:

264.28 L of CO₂

Explanation:

We'll begin by calculating the number of moles present in 275 g of NO₃¯. This can be obtained as follow:

Mass of NO₃¯ = 275 g

Molar mass of NO₃¯ = 14 + (16×3) = 14 + 48 = 62 g/mol

Mole of NO₃¯ =?

Mole = mass / molar mass

Mole of NO₃¯ = 275 / 62

Mole of NO₃¯ = 4.44 moles

Next, we shall determine the number of mole of CO₂ produced from the reaction. This can be obtained as follow:

2NO₃¯ + 5CO + 2H⁺ —> N₂ + H₂O + 5CO₂

From the balanced equation above,

2 moles of NO₃¯ reacted to produced 5 moles of CO₂.

Therefore, 4.44 moles of NO₃¯ will react to produce = (4.44 × 5) / 2 = 11.1 moles of CO₂.

Thus, 11.1 moles of CO₂ were produced from the reaction.

Finally, we shall determine the volume of CO₂ produced each day. This can be obtained as follow:

Temperature (T) = 17 °C = 17 °C + 273 = 290 K

Pressure (P) = 1 atm

Number of mole (n) of CO₂ = 11.1 moles

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) of CO₂ =?

PV = nRT

1 × V = 11.1 × 0.0821 × 290

V = 264.28 L

Thus, 264.28 L of CO₂ would be produced each day.

The volume of [tex]\rm CO_2[/tex] produced has been 264.28 L.

The volume of the carbon dioxide gas produced can be calculated with the ideal gas equation.

The moles of [tex]\rm NO_3^-[/tex] has been:

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of 275 g  [tex]\rm NO_3^-[/tex] has been:

Moles = [tex]\rm \dfrac{275}{62}[/tex]

Moles of  [tex]\rm NO_3^-[/tex] = 4.44 moles

The balanced equation gives that with the reaction of 2 moles [tex]\rm NO_3^-[/tex] , 5 moles carbon dioxide has been formed.

Moles of carbon dioxide formed with 4.44 mol [tex]\rm NO_3^-[/tex] has been:

2 moles [tex]\rm NO_3^-[/tex] = 5 moles [tex]\rm CO_2[/tex]

4.44 moles [tex]\rm NO_3^-[/tex]  = 11.1 moles [tex]\rm CO_2[/tex].

The volume of the [tex]\rm CO_2[/tex] can be calculated as:

Pressure [tex]\times[/tex] Volume = moles [tex]\times[/tex] Rydberg constant [tex]\times[/tex] temperature

For the [tex]\rm CO_2[/tex] produced:

1 atm [tex]\times[/tex] Volume = 11.1 mol [tex]\times[/tex] 0.0821 atm.L/K.mol [tex]\times[/tex] 290 K

Volume = 264.28 L.

The volume of [tex]\rm CO_2[/tex] produced has been 264.28 L.

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Answer:

per day means - and if means + and of means × lmk if u need help

Answer:

mass = 6.9 kg = 6900 g

volune= 722 cm3

density= mass/volume

density= 6900/722

= 9.55 g/ cm3

Answer:

[tex]\boxed {\boxed {\sf d \approx 9.56 \ g/cm^3}}[/tex]

Explanation:

We want to find the density of the plastic in grams per cubic centimeter.

Density is found by dividing the mass by the volume.

[tex]d=\frac {m}{v}[/tex]

We know the mass is 6.9 kilograms and the volume is 722 cubic centimeters We must convert kilograms to grams.

Now we know the mass and volume. Substitute the values into the density formula.  

[tex]d=\frac{ 6900 \ g }{722 \ cm^3}[/tex]

[tex]d= 9.5567867 \ g/cm^3[/tex]

Let's round to the nearest hundredth. The 6 in the thousandth place tells us to round the 5 to a 6.

[tex]d \approx 9.56 \ g/cm^3[/tex]

The density of the plastic is about 9.56 grams per cubic centimeter

Answer:

False

Explanation:

Water is said to have a higher heat capacity than soil and stones, so the ocean takes much longer to heat and to cool than the land. 2. Coastal areas have more moderate temperatures than landlocked areas because of the heat capacity of the ocean and hence the answer is false.

Answer:

False.

Explanation:

Answer:

D. -1882J

Explanation:

We can solve the energy released in a chemical reaction in an aqueous medium using the equation:

Q = -m*C*ΔT

Where Q is energy (In J),

m is mass of water (45.00g)

C is specific heat of water (4.184J/g°C)

And ΔT is change in temperature (25.00°C - 15.00°C = 10.00°C)

Replacing:

Q = -45.00*4.184J/g°C*10.00°C

Q = -1882J

Right answer is:

Answer:

B

Explanation:

No explanation needed for it i got 100% on it

Lifting the remains is the last step in the excavation of the skeletal remains. Therefore, option E is correct.

In archaeology, excavation can be described as the exposure, processing, and recording of archaeological remains. An excavation site or "dig" can be the area being studied. These locations are from one to various areas at a time while a project can be conducted over weeks to several years.

Excavation involves the recovery of various types of data from a site. This data includes ecofacts, artifacts, features, and archaeological context. Before excavating, the presence of remains can often be suggested by remote sensings, such as ground-penetrating radar.

During excavation, stratigraphic excavation removes phases of the site one layer at a time and keeps the timeline of the material remains consistent. This is done through mechanical means and the soil is processed via methods like mechanical sieving or water flotation.

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Answer:

100 POINTS! (50 split up) PLSSSSSSSSSS HELP!!! I REALLY NEED IT SO MUCH :( I PROMICE TO GIVE BRAINLIEST AND FIVE STARS AND A THANKS! 6TH GRADE SCIENCE! i used all my points for this!

You measure the mass of an apple using a balance. You get these three measurements:

Trial 1: 167.0 g

Trial 2: 166.9 g

Trial 3: 167.2 g

You know that the true mass of the apple is 172 g. Describe your results in terms of precision and accuracy. Explain your answer in a paragraph for the best grade.

Explanation:

Answer:Metallic and covalent bonds are strongly attractive; hydrogen

bonding and Van der Waals forces are weakly attractive.

Answer:

Metallic and covalent bonds are strongly attractive; hydrogen bonding and Van der Waals forces are weakly attractive..

trust me i just did it

Explanation:

Answer:

the gravity

Explanation:

i hope you help this answer

Answer:

the ocean

Explanation:

Answer:

ΔE =  -22 KJ

Explanation:

Given data:

Work done = 13 KJ

Heat lose = 9 KJ (exothermic process)

ΔE = ?

Solution:

Formula:

ΔE = q + w

ΔE = - 9KJ + (-13 KJ)   (work is done by the system on surrounding that's why we add negative sign)

ΔE =  -22 KJ

Answer:

0.140 Liter

Explanation:

M1V1 = M2V2

M1 = 1.61 M

V1 = 87 ml

M2 = 1.00 M

V2 = ?

V2 = M1V1/M2

V2 = 1.61×87/1

V2 = 140.07 ml

V2= 0.140 L

Answer: There are [tex]1.08 \times 10^{-14}[/tex] moles [tex]N_{2}O_{4}[/tex] present in [tex]6.49 \times 10^9[/tex] particles.

Explanation:

According to the mole concept, 1 mole of a substance contains [tex]6.022 \times 10^{23}[/tex] particles.

Hence, number of moles present in [tex]6.49 \times 10^9[/tex] particles are calculated as follows.

No. of moles = [tex]\frac{6.49 \times 10^9}{6.022 \times 10^{23}}[/tex] mol

                      = [tex]1.08 \times 10^{-14}[/tex] mol

Thus, there are [tex]1.08 \times 10^{-14}[/tex] moles [tex]N_{2}O_{4}[/tex] present in [tex]6.49 \times 10^9[/tex] particles.

Answer:

1.08 × 10⁻¹⁴ moles of N2O4

Explanation:

Given data:

Moles of dinitrogen tetroxide = ?

Number of particles = 6.49×10⁹

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions , particles and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole contain 6.022 × 10²³ particles.

6.49×10⁹ particles × 1 mole / 6.022 × 10²³ particles

1.08 × 10⁻¹⁴ mol

Answer:

1/16

Explanation:

We have the half life of ²⁰O = 15 seconds

This half life means that the reactant 8s going to be half at this time

Now we have 60 seconds = 1 minute

Then in 60 seconds we are going to have 4 half life.

Then ²⁰O will be 1/2⁴

1/2⁴ = 1/16

This is the answer to this question.

Thank you!

1/16 fraction of a sample of pure ²⁰O remains after 1.0 minute

Given:

The half life of ²⁰O = 15 seconds

This half life means that the reactant 8s going to be half at this time

Now, we have 60 seconds = 1 minute

Then in 60 seconds we are going to have 4 half life.

Then ²⁰O will be 1/2⁴

1/2⁴ = 1/16

Thus, the fraction of a sample of pure ²⁰O remains after 1.0 minute is 1/16.

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Answer:

0.92^n

Explanation:

Given that :

Initial amount of vinegar = 1 Litre

Number of litres removed repeatedly = 0.08 Litre

Since the amount removed each time is constant, then ;

Initial % = 100% = 100/100 = 1

. Using the relation :

Amount of vinegar in mixture :

Initial * (1 - amount removed / initial amount)^n

n = number of times repeated

1 * (1 - 0.08/1)^n

1 * (1 - 0.08)^n

1 * 0.92^n

Hence,

For nth removal,

Concentration will be :

0.92^n ; for n ≥ 1

Molar concentration of acetic acid = 1 M

Given

acetic acid in 6% solution (d=1 g/ml)

Required

molar concentration

Solution

mass of acetic acid in solution

mass = density x %mass

mass = 1 g/ml x 6%

mass = 0.06 g/ml ⇒ 60 g/L

MW acetic acid = 60 g/mol

molarity acetic acid = mass : MW

molarity = 60 g/L : 60 g/mol

molarity = 1 mol / L = 1 M

Answer:

When the solar wind gets past the magnetic field and travels towards the Earth, it runs into the atmosphere .As the protons and electrons from the solar wind hit the particles in the Earth's atmosphere, they release energy – and this is what causes the northern lights.

Explanation:

Answer:

Compounds

Explanation:

It is a compound when they are separated by chemical bonds.

Compound are substances composed of two or more kinds of atoms that are joined together in a definite grouping.

The properties of a compound are distinct and different from those of the individual elements that are combined in its make-up.

Within a compound there are chemical bonds.