What is 50 degrees f in kelvin

Answer:A sound wave is a pressure disturbance that travels through a medium by means of particle-to-particle interaction.As one particle becomes disturbed,it exerts a force on the next adjacent particle, disturbing that particle from rest and transporting the energy through the medium.Like any wave,the speed of a sound wave refers to how fast the disturbance is passed from particle to particle.While frequency refers to the number of vibrations that an individual particle makes per unit of time, speed refers to the distance that the disturbance travels per unit of time.

Since the speed of a wave is defined as the distance that a point on a wave (such as a compression or a rarefaction)travels per unit of time,it is often expressed in units of meters/second (abbreviated m/s). In equation form, this is speed = distance/time

The faster a sound wave travels,the more distance it will cover in the same period of time.If a sound wave were observed to travel a distance of 700 meters in 2 seconds,then the speed of the wave would be 350 m/s. A slower wave would cover less distance - perhaps 660 meters - in the same time period of 2 seconds and thus have a speed of 330 m/s.Faster waves cover more distance in the same period of time.

The speed of any wave depends upon the properties of the medium through which the wave is traveling.Typically there are two essential types of properties that affect wave speed - inertial properties and elastic properties.Elastic properties are those properties related to the tendency of a material to maintain its shape and not deform whenever a force or stress is applied to it.A material such as steel will experience a very small deformation of shape and dimension when a stress is applied to it.Steel is a rigid material with a high elasticity.On the other hand,a material such as a rubber band is highly flexible;when a force is applied to stretch the rubber band,it deforms or changes its shape readily.A small stress on the rubber band causes a large deformation.Steel is considered to be a stiff or rigid material,whereas a rubber band is considered a flexible material. At the particle level,a stiff or rigid material is characterized by atoms and/or molecules with strong attractions for each other.The phase of matter has a tremendous impact upon the elastic properties of the medium.For this reason,longitudinal sound waves travel faster in solids than they do in liquids than they do in gases.Even though the inertial factor may favor gases,the elastic factor has a greater influence on the speed (v) of a wave,thus yielding this general pattern:solids > liquids > gases The density of a medium is an example of an inertial property.The greater the inertia (i.e.mass density) of individual particles of the medium,the less responsive they will be to the interactions between neighboring particles and the slower that the wave will be. However,within a single phase of matter,the inertial property of density tends to be the property that has a greatest impact upon the speed of sound.Like any liquid,water has a tendency to evaporate.As it does,particles of gaseous water become mixed in the air.The temperature will affect the strength of the particle interactions an elastic property.At normal atmospheric pressure,the temperature dependence of the speed of a sound wave through dry air is approximated by the following equation:

v = 331 m/s + (0.6 m/s/C)•T

where T is the temperature of the air in degrees Celsius.Using this equation to determine the speed of a sound wave in air at a temperature of 20 degrees Celsius yields the following solution.

v = 343 m/s

(The equation itself does not have any theoretical basis;it is simply the result of inspecting temperature-speed data for this temperature range.Other equations do exist that are based upon theoretical reasoning and provide accurate data for all temperatures.The speed of light as it travels through air and space is much faster than that of sound;it travels at 300 million meters per second or 273,400 miles per hour.Visible light can also travel through other things besides through air and through space.The speed of light in water is approximately 2.26×108 2.26 × 10 8 meters per second.

Answer:

a = 5 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}=v_{o}+a*t[/tex]

where:

Vf = final velocity = 20 [m/s]

Vo = initial velocity = 10 [m/s]

t = time = 2 [s]

a = acceleration [m/s²]

Now replacing:

[tex]20 =10 +a*2\\10=2*a\\a=5[m/s^{2} ][/tex]

Answer:

Momentum, p = 23250 kg m/s

Explanation:

Given that

Mass of a car, m = 1550 kg

Speed pf car, v = 15 m/s

We need to find the momentum of the car. The formula for the momentum of an object is given by :

p = mv

Substituting all the values in the above formula

p = 1550 kg × 15 m/s

p = 23250 kg m/s

So, the momentum of the car is 23250 kg m/s.

Answer:

??

Explanation:

not completely sure hold on

Answer:

-43J

Explanation:

Answer:

c

Explanation:

Answer:

this answer you question

Answer:

Explanation:

A(n) generator changes mechanical energy into electrical. A(n) motor changes electric energy into mechanical. A(n) transformer changes the voltage of an alternating current. A(n) step-down transformer has more loops in the primary coil than in the secondary coil. A(n) step-up transformer has fewer loops in the primary coil than in the secondary coil.​

Hope it's helpful!

Answer:

12) I = 800 kg m/ s ,  13) Δv = 31.25 m / s, 14)  F = -3600 N , 15)  Δv = 4.44 m/s

Explanation:

In this strange exercise you are asked to answer a series of questions

12) force F = 800N applied mass m = 80 kg has a speed change of DV = 10 m / s, calculate the momentum

           I = Δp

           I = m Δv

           I = 80 10

           I = 800 kg m / s

13) a mass of m = 0.80 kg, has an impulse of 25 N s, determines the change in speed

          I = m Δv

          Δv = I / m

          Δv = 25 / 0.8

          Δv = 31.25 m / s

14) a mass m + 1200 kg is carried from 25 m / s to 10 m / s in a period of 5.0 s, determine the force

          I = m ([tex]v_{f}[/tex] -v₀)

the proemd force for this impulse

          I = F t

we substitute

          F t = m (v_{f} -v₀)

          F = m (v_{f} -v₀ / t

          F = 1200 (10-25) / 5

          F = -3600 N

the negative sign indicates that the force is in the opposite direction of the movement

15) a mass = 90 kg with velocity v = 9.0 m has a momentum of I = 400N s, determines the change in velocity

           I = m Δv

           Δv = I / m

           Δv = 400/90

            Δv = 4.44 m / s

if they asked for the final speed it would be.

            I = m (v_{f} -v₀)

            v_{f} = v₀ + I / m

            v_{f} = 9 + 400/90

            v_{f} = 13.4 m / s

Answer:

40 cm

hope it's help you but you can choose if your ans. is -40 cm

Answer:

A: -10 kg•m/s

Explanation:

6•5= 30

-2•20=-40

-40+30= -10

-10 kg•m/s

Answer:

Center

Explanation:

The center is the tallest player on each team, playing near the basket. On offense, the center tries to score on close shots and rebound. But on defense, the center tries to block opponents' shots and rebound their misses.

Answer:

C

Explanation:

Explanation:

For balanced forces, the severity of the 2 factors is equal, while the magnitude of the 2 factors is unequal in the situation of unbalanced forces. The three separate forces operate in opposing ways in balanced forces. In unbalanced forces, on the other hand, independent forces either behave in the same or reverse direction.

An electric switch is a device that interrupts the electron flow in a circuit. Switches are primarily binary devices: either fully on or off and light switches have a simple design. When the switch is turned off, the circuit breaks and the power flow is interrupted. Circuits consist of a source of power and load.

Given :

Initial speed of car A is 15 m/s and initial speed of car B is zero.

Final speed of car A is zero and final speed of car B is 10 m/s.

To Find :

What fraction of the initial kinetic energy is lost in the collision.

Solution :

Initial kinetic energy is :

[tex]K.E_i = \dfrac{15^2m}{2} + 0\\\\K.E_i = \dfrac{225 m}{2}[/tex]

Final kinetic energy is :

[tex]K.E_f = \dfrac{10^2m}{2} + 0\\\\K.E_f = \dfrac{100m}{2}[/tex]

Now, fraction of initial kinetic energy loss is :

[tex]Loss = \dfrac{\dfrac{225m}{2}-\dfrac{100m}{2}}{\dfrac{100m}{2}}\\\\Loss = \dfrac{125}{100}\\\\Loss = 1.25[/tex]

Therefore, fraction of initial kinetic energy loss in the collision is 1.25 .

Answer:

 F_{net-x} = 12.32 N ,   F_{net-x} = -0.14 N  

Explanation:

For this case we apply Newton's second law on each axis,  see attachment

X axis

       F cos 40 - fr = m a

Y Axis  

      F sin 40 +N - W = 0

the net force is

X axis

     [tex]F_{net-x}[/tex] = F - fr

     F_{net-x} = 20 cos 40 - 3

     F_{net-x} = 12.32 N

Y Axis  

     F_{net-y} = F sin 40 + N - W

     F_{net-x} = 20 sin 40 + 7 - 20

     F_{net-x} = -0.14 N

we see that the force in this axis is approximately zero

Answer:

(1)Work done by snail is 382.5 N

(2)Work done by ELEPHANT is 25160 N

(3)Work done by HANS is 2420 N

(4)Work done on block is 433 N

Explanation:

The work done due to force F applied at an angle θ from the horizontal to the body is give by

Work done = Fscosθ where, s is distance traveled by body

Case 1: F= 255N , s= 3.00m and θ = 60.[tex]0^0[/tex]

Work done = Fscosθ = 255 x 3.00 x cos60.[tex]0^0[/tex] = 382.5N

thus work done by snail is 382.5 N

Case 2: F= 200N , s= 150m and θ = 33.[tex]0^0[/tex]

Work done = Fscosθ = 200 x 150 x cos33.[tex]0^0[/tex] = 25160N

thus work done by elephant is 25160 N

Case 3: F= 22.9N , s= 129m and θ = 35.[tex]0^0[/tex]

Work done = Fscosθ = 22.9 x 129 x cos35.[tex]0^0[/tex] = 2420N

thus work done by Hans is 2420 N

Case 4: F= 100N , s= 5m and θ = 30.[tex]0^0[/tex]

Work done = Fscosθ = 100 x 5.00 x cos30.[tex]0^0[/tex] = 433N

thus work done on block is 433 N

(1)  The work done by the sailor is 382.5 J.

(2)  The work done by elephant is 25160 J.

(3) The work done by Hans upon the backpack is 2420 J.

(4)  The required work done on block is 433 J.

Let us solve these questions in parts. All these questions are based on the work done. The work done due to force F applied at an angle θ from the horizontal to the body is give by,

[tex]W =F \times s \times cos \theta[/tex]

Here, s is the distance covered by the body.

(1)

Given data:

F= 255N , s= 3.00m and θ = 60.

The work done is calculated as,

W = Fscosθ

W= 255 x 3.00 x cos60 = 382.5 J.

Thus, the work done by the sailor is 382.5 J.

(2)

Given data:

F= 200N , s= 150m and θ = 33.

The work done by the elephant is calculated as,

W = Fscosθ

W= 200 x 150 x cos33. = 25160 J

Thus, the work done by elephant is 25160 J.

(3)

Given data:

F= 22.9N , s= 129m and θ = 35.

Then the work done upon the backpack is calculated as,

W= Fscosθ

W= 22.9 x 129 x cos35. = 2420 J

Thus, the work done by Hans upon the backpack is 2420 J.

(4)

Given data:

F= 100N , s= 5m and θ = 30.

The work done is calculated as,

W = Fscosθ

W= 100 x 5.00 x cos30. = 433 J

Thus, the required work done on block is 433 J.

Learn more about the work done here:

https://brainly.com/question/13662169

Answer:

Yayyyyyy thank you ≥﹏≤.!!!!!!!!!!!!!

Answer:

hope this will help

Explanation:

if your title doesn't have enough information, make a list of the key words ... If you are not sure what should be included in each summary sentence, use ... Often you can present the hypothesis and the supporting reasoning in one paragraph. ... Describe specific parts of the procedure or data that contributed to your learning.  

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/191502-7how-do-the-data-support-your-claim-above-explain-your-statement.html

Answer:

mesosystem

Explanation:

The mesosystem involves relations between microsystems or connections between contexts.

Explanation:

The compass needle moved when the wire was connected to the battery. The important point here is that the needle is affected by the wire only when both ends of the wire are connected to the battery because only at this time is current flowing through the circuit.

Answer:

u will need 1/2 cells

Explanation:

Answer:

5m

Explanation:

khan academy

Vertical displacement of the circus performer is 5 m.

Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.

A circus performer walked up and to the right for a total displacement of 10 m, start to end along a diagonal tightrope angled 30° degree above the ground.

Vertical displacement = 10 sin 30° = 5 m

Vertical displacement of the circus performer is 5 m.

To learn more about displacement refer to the link:

brainly.com/question/11934397

#SPJ2

Answer:

a, 22 kg and 22 kg

b, 215.8 N and 440 N

Explanation:

a

The mass of the ball remains constant and unchanged irrespective of where it has been to, need to go or is going. So, basically the mass of the ball on earth is as the same mass of the ball on the said planet, 22 kg

b

The weight of any object factors in the acceleration due to gravity of the said area(or planet).

W = mg, with m being the mass and g being the acceleration due to gravity.

On earth

W = 22 * 9.81 = 215.8 N

On the said planet,

W = 22 * 20 = 440 N

Do therefore, the weight is 215.8 N on earth and 440 N on the planet

Answer:

hjg567 A 567

Explanation:

Answer:

[tex]from \: newton \: law \: of \: gravitation \\ F = \frac{GMm}{ {r}^{2} } \\ G = 6.67 \times {10}^{ - 11} \\ M = 0.5 \: kg \\ m = 0.33 \: kg \\ r = 0.002 \: m \\ substitute \\ F = \frac{(6.67 \times {10}^{ - 11}) \times (0.5) \times (0.33)) }{ {(0.002)}^{2} } \\ = 2.75 \times {10}^{ - 6} N[/tex]

Answer:

The unknown force will be 18.116 lb.

Explanation:

Given that,

Three forces act on a flange as shown in figure.

The net force acting on the flange is a minimum.

[tex]\dfrac{dF_{net}}{df}=0[/tex]

We need to calculate the unknown force

Using formula of net force

[tex]\vec{F_{net}}=\vec{F_{x}}+\vec{F_{y}}[/tex]

Put the value into the formula

[tex]\vec{F_{net}}=(F\cos45+70\cos30-40)\hat{i}+(70\sin30-F\sin45)\hat{j}[/tex]

[tex]\vec{F_{net}}=(F\cos45+70\times\dfrac{\sqrt{3}}{2})\hat{i}+(70\times\dfrac{1}{2}-F\sin45)\hat{j}[/tex]

The magnitude of net force,

[tex]F_{net}=\sqrt{F_{x}^2+F_{y}^2}[/tex]

[tex]F_{net}=\sqrt{(F\times\dfrac{1}{\sqrt{2}}+60.62)^2+(35-F\times\dfrac{1}{\sqrt{2}})^2}[/tex]

[tex]F_{net}=\sqrt{F^2+(60.62)^2+121.24\times\dfrac{F}{\sqrt{2}}+(35)^2-70\times\dfrac{F}{\sqrt{2}}}[/tex]

[tex]F_{net}=\sqrt{F^2+4899.78+36.232F}[/tex]

On differentiating w.r.to F

[tex](\dfrac{dF_{net}}{dF})^2=2F+36.232[/tex]

[tex]0=2F+36.232[/tex]

[tex]F=-\dfrac{36.232}{2}[/tex]

[tex]F=-18.116\ lb[/tex]

Negative sign shows the direction of force which is downward.

Hence, The unknown force will be 18.116 lb.

Following are the solution to the given question:

Calculating the Net force on flange:

[tex]\overrightarrow{F_{net}} = ( F \cos 45^{\circ} + 70 \cos 30^{\circ} -40 ) \hat{i}+(70 \sin 30^{\circ} - F \sin 45^{\circ} )\hat{y} \\\\ \overrightarrow{F_{net}} = ( F \cos 45^{\circ} + 20.62 ) \hat{i}+(35 -F\sin 45^{\circ})\hat{y} \\\\ [/tex]

Calculating the magnitude:

[tex]= \sqrt{f_{X}^2 +f_{y}^{2}}\\\\ = \sqt{( F \cos 45^{\circ} + 20.62 )^2+(35 -F\sin 45^{\circ})^2} \\\\ = \sqt{( F^2+20.62^2+ 35^2+ 41.24 F \cos 45^{\circ} -70 F\sin 45^{\circ})}\\\\ = \sqt{( F^2+20.33F +1650.1844)} \\\\[/tex]

Differentiate the value

[tex]\to \frac{F_{net}}{df}=0 [/tex]

[tex]\to 2F-20.33=0\\\\ \to 2F=20.33\\\\ \to F=\frac{20.33}{2}\\\\ \to F= 10.165\ lb [/tex]

Learn more:

brainly.com/question/15323099

Answer:

1.7x10^-10 N

Explanation:

F = G [(m_1)(m_2)]/(r^2)

F = force

G = Gravitational constant 6.67433x10^-11 (N*m^2)/kg^2

m_1 = mass first object

m_2 = mass second object

r = radius between the 2 objects

F = G[(2 kg*2 kg)/(1.25 m)^2]

F = 1.7x10^-10 N

Answer:

how the universe began

Explanation:

time never stops or starts, we only think it starts when we start recording it

Answer:

60n left

Explanation:

Do

Answer:

Use equation 1/2 * m * v²

Explanation:

where m = mass in kg

and v = velocity in m/s

plug accordingly.