What is her velocity?
O 1.5 m/s
O 2 m/s
O 2.5 m/s
O 5 m/s

Answer:

The answer is B

Explanation:

It will move in the direction of johns push, to the west

Answer:

It will move in the direction of John's push, to the west.

Explanation:

Plato/Edmentum

Answer:

mass*velocity=1.5*10^4 * 15

= 22.5*10^4

astronomers have a difficult time viewing stars and galaxies millions or billions of light years away because they're just so far away. based on the number of light years they are away, that number represents how long the light from that object took, in order to reach that astronomers eyes. so in reality, they're looking at the past when studying objects that insanely far away. if a star is 1 million light years away, that means the light from that star will take 1 million years to reach your position. so considering the distance that an object is in space and relative to an astronomers position, it's quite expected for it to become harder to view. the farther an object is from sight, the harder it is to see.

i hope this helps!

Answer:

a) W = -4N,   b)  F_net = 0

Explanation:

The suspended weight of the spring ladder is subjected to two forces: the elastic force of the spring directed downwards and the gravitational force directed downwards.

             [tex]F_{e}[/tex] - W = 0

             F_{e} = W

             F_{e} = W = 4 N

a) the gravitational force is the weight of the body

             W = -4N

b) as the system is in equilibrium, the net force is zero

             F_net = 0

It is called a warm-up.

Answer:

We do warm-ups before we exercise. We do cool-downs after we exercise.

Explanation:

Warming up can help you get ready to do the actual exercise, so you are prepared.

Answer:

If I say the correct answer is B.280

Answer:

283.15

Explanation:

looked it up

there's a handy calculator

Answer: C.

283 K

Explanation: edmentum

Answer:

D

Explanation:

Edge 2021

When just gravity is operating on an object, which is said to be in free fall.

The team is unable to set up the spike because the ball is at the rear of the court and has already been hit twice. Knowing this, the team receiving the ball shouts "free ball!" to signal everyone to get ready to start their offense as soon as they get possession of it.

informal idiom to consent to assisting or collaborating with someone as indicated by them: His family wanted him cared for at residence, but the insurance provider was uncooperative.

To learn  more about: Free ball

Ref: https://brainly.com/question/16088972

#SPJ2

Answer:

The mass of Star 2 is Greater than the mass of Start 1. (This, if we suppose the masses of the planets are much smaller than the masses of the stars)

Explanation:

First of all, let's draw a free body diagram of a planet orbiting a star. (See attached picture).

From the free body diagram we can build an equation with the sum of forces between the start and the planet.

[tex]\sum F=ma[/tex]

We know that the force between two bodies due to gravity is given by the following equation:

[tex]F_{g} = G\frac{m_{1}m_{2}}{r^{2}}[/tex]

in this case we will call:

M= mass of the star

m= mass of the planet

r = distance between the star and the planet

G= constant of gravitation.

so:

[tex]F_{g} =G\frac{Mm}{r^{2}}[/tex]

Also, if the planet describes a circular orbit, the centripetal force is given by the following equation:

[tex]F_{c}=ma_{c}[/tex]

where the centripetal acceleration is given by:

[tex]a_{c}=\omega ^{2}r[/tex]

where

[tex]\omega = \frac{2\pi}{T}[/tex]

Where T is the period, and [tex]\omega[/tex] is the angular speed of the planet, so:

[tex]a_{c} = ( \frac{2\pi}{T})^{2}r[/tex]

or:

[tex]a_{c}=\frac{4\pi^{2}r}{T^{2}}[/tex]

so:

[tex]F_{c}=m(\frac{4\pi^{2}r}{T^{2}})[/tex]

so now we can do the sum of forces:

[tex]\sum F=ma[/tex]

[tex]F_{g}=ma_{c}[/tex]

[tex]G\frac{Mm}{r^{2}}=m(\frac{4\pi^{2}r}{T^{2}})[/tex]

in this case we can get rid of the mass of the planet, so we get:

[tex]G\frac{M}{r^{2}}=(\frac{4\pi^{2}r}{T^{2}})[/tex]

we can now solve this for [tex]T^{2}[/tex] so we get:

[tex]T^{2} = \frac{4\pi ^{2}r^{3}}{GM}[/tex]

We could take the square root to both sides of the equation but that would not be necessary. Now, the problem tells us that the period of planet 1 is longer than the period of planet 2, so we can build the following inequality:

[tex]T_{1}^{2}>T_{2}^{2}[/tex]

So let's see what's going on there, we'll call:

[tex]M_{1}[/tex]= mass of Star 1

[tex]M_{2}[/tex]= mass of Star 2

So:

[tex]\frac{4\pi^{2}r^{3}}{GM_{1}}>\frac{4\pi^{2}r^{3}}{GM_{2}}[/tex]

we can get rid of all the constants so we end up with:

[tex]\frac{1}{M_{1}}>\frac{1}{M_{2}}[/tex]

and let's flip the inequality, so we get:

[tex]M_{2}>M_{1}[/tex]

This means that for the period of planet 1 to be longer than the period of planet 2, we need the mass of star 2 to be greater than the mass of star 1. This makes sense because the greater the mass of the star is, the greater the force it applies on the planet is. The greater the force, the faster the planet should go so it stays in orbit. The faster the planet moves, the smaller the period is. In this case, planet 2 is moving faster, therefore it's period is shorter.

Answer:

k=6.666

Explanation:

F=kx

100=k 50-35

100=k*15

k=6.666

Answer:

B

Explanation:

Hhhhh

Explanation:

Here two internal resistances are in parallel so equivalent internal resistance r

eq

=1∣∣1=

1+1

1×1

=1/2=0.5Ω

According to maximum power theorem the power will be max when internal resistance is equal to external resistance. since, r

eq

=R=0.5Ω

Maximum current through R is I

max

=

r

eq

+R

V

=

0.5+0.5

2

=2A

Maximum power is P

max

=I

max

2

R=2

2

×0.5=2W

plz follow and thanks me

Answer:

[tex]a=4.19 m/s^{2}[/tex]

Explanation:

In order to solve this problem, we must first draw a free body diagram of the situation. (See attached picture)

from this diagram, we can do the following sum of forces:

[tex]\sum F=ma[/tex]

where m is the mass of the rocket and a is its acceleration.

[tex]F_{e}-mg=ma[/tex]

where [tex]F_{e}[/tex] is the force of exhaust. We can solve this for the acceleration, so we get:

[tex]a=\frac{F_{e}-mg}{m}[/tex]

we can find the force of exhaust by using the momentum formula:

Ft=mv

so we can solve this for the force:

[tex]F_{e}=\frac{mv}{t}[/tex]

the problem already tells us what m/t is equal to, so we can directly substitute:

[tex]F_{e}=(1.75x10^{4}kg/s)(2.40x10^3m/s)[/tex]

which yields:

[tex]F_{e}=42x10^6 N[/tex]

So we can now substitute:

[tex]a=\frac{42x10^6N-(3x10^6kg)(9.81m/s^{2})}{3x10^6kg}[/tex]

so:

[tex]a=4.19 m/s^{2}[/tex]

Answer:

it's answer is 117 N

F = Gm1m2/r^2

F = 6.67 * 10 ^-11 * 70 * 7.34 * 10 ^22/(1.71 * 10 ^6)^2

F = 117 N

hope it helps you

Answer:

I think it might be negative reinforcement.

Explanation:

Answer:

negative reinforcement

Explanation:

Answer:

energy required=-energy lost

energy lost=change in kinetic energy

EL=1/2 mv^2

Answer:

the bottom one

Explanation:

Answer:

the second object exerts an equal but opposite force

Explanation:

its right

Answer: hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats.

Explanation:

Answer:

D. Inverse square

Explanation:

According to the information you are giving me, you must be referring to Coulomb's law because the electrostatic force in proportion to the displacement of charged particles is [tex] F =\frac{kq_{1}q_{2}}{r²} [/tex].

As you can see, there is a reason as to why this is also referred to as Coulomb's inverse square law because the r² represents the displacement or distance relative to the position of the particles which is squared, and it is inverse because the force and the product of the distance squared is equal to the product of the two charges particles multiplied by coulomb's constant (k) which is approximately 8.9875517923×10⁹ kg⋅m³⋅s⁻²⋅C⁻².

The mathematical proportion that relates electrostatic force and displacement for a pair of charged particles is Inverse square. Hence, option (D) is correct.

The electrostatic force is an attractive and repulsive force caused by the electric charges of particles. The electrostatic force is the electric force that exists between two stationary charged bodies. It is also known as Coulomb's force.

Hence,  electrostatic force inversely proportional to the distance between two charges. If two charges Q and q are separated by a distance r, the magnitude of electrostatic force between them is given by:

F = kQq/r²

So, the mathematical proportion that relates electrostatic force and displacement for a pair of charged particles is Inverse square. Hence, option (D) is correct.

Learn more about electrostatic force here:

https://brainly.com/question/9774180

#SPJ2

Answer:

v= 18.5 m/s

Explanation:

       [tex]F_{cent} = F_{g} - F_{n} (1)[/tex]

       [tex]F_{cent} = m*\frac{v^{2}}{r} (2)[/tex]

       [tex]F_{n} = F_{g} - m*\frac{v^{2}}{r} (3)[/tex]      

        [tex]0.9*F_{g} = F_{g} - m*\frac{v^{2}}{r} (4)[/tex]

The velocity the occupants of the car appear to weigh 10% less than their normal weight is 18.52 m/s.

The given parameters:

Apply the principle of conservation of energy to determine the velocity the occupants of the car appear to weigh 10% less than their normal weight;

[tex]F_c = mg\\\\\frac{mv^2}{r} = mg\\\\v^2 = gr\\\\v = \sqrt{gr} \\\\v = \sqrt{0.1 \times 9.8 \times 350}\\\\v = 18.52 \ m/s[/tex]

Thus, the velocity the occupants of the car appear to weigh 10% less than their normal weight is 18.52 m/s.

Learn more about velocity of a banked road here: https://brainly.com/question/14777525

Answer:

The pressure exerted by the brick on the table is 18,933.3 N/m².

Explanation:

Given;

height of the brick, h = 0.1 m

density of the brick, ρ = 19,300 kg/m³

acceleration due to gravity, g = 9.81 m/s²

The pressure exerted by the brick on the table is calculated as;

P = ρgh

P = (19,300)(9.81)(0.1)

P = 18,933.3 N/m²

Therefore, the pressure exerted by the brick on the table is 18,933.3 N/m².

Answer:

Distance moved = 42 meters

Mag and Dir = 10 meters northward

Explanation:

Distance is total distance traveled which = 22+16+4 = 42 meters

Displacement is the amount of distance moved from the start point to the end point straight line so our equation for the magnitude is 22-16+4 = 10 meters. Then the direction is northward from the start point. This answer would also be a vector because it has a magnitude and direction.

Yes, if the mass starts at rest, the change in speed will be equal the final speed, because:

Δv = Vf - Vo

How Vo (Initial velocity) is equal zero, we simplificate:

Δv = Vf

Then, the change of the speed, if the mass starts at rest, will be equal to final velocity.

Greetings.

Answer:

answer is FALSE

Explanation:

AMPLITUDE IS THE MAXIMUM AMOUNT OF DISPLACEMENT OF A PARTICLE ON THE MEDIUM FROM ITS REST POSITION

AND WAVELENGTH can be measured as crest to crest

Amplitude of a wave is the strength of the wave. It is measured from the central line of the wave to the top of the crest or bottom of the trough. Therefore, the statement is false.

Amplitude is a parameter measuring the strength of a wave. It is the maximum displacement moved by the wave from its equilibrium position. The vibrational path will be twice that of the amplitude of the wave.

As the amplitude of the wave increases its intensity increases. Both are in direct proportion with the frequency and energy of a wave. For instance the amplification of sound waves increases the intensity of waves that we hear.

The distance between two consecutive crests or troughs is the wavelength of the wave not amplitude. Amplitude is measured from the axis line to the top of the crest thus, from exact middle of the wave crest to the top or to the bottom of trough. Thus, the statement is false.

To find more on amplitude, refer here:

https://brainly.com/question/8662436

#SPJ2