what is nuclear energy​

Answer:

Explanation:

D

Answer: For those who test is different .. the answer is “ An Iron nail, not near a magnet”

Explanation:

The given statement is TRUE

Iconic compounds are highly conductive when dissolved in water because the compounds hydrate ions after dissolving them in water.

Ionic compounds are a combination of metals and nonmetals, and as we know, metals are good conductors of electricity.

An ionic compound consists of two oppositely charged ions.

Water, on the other hand, is a polar solvent; the electronegativity difference between oxygen and hydrogen is high, therefore water has a positive H pole and a negative O pole (water is H2O).

And therefore when the ionic compound is dissolved in water, the opposite ions from the compound gets attracted to the poles of water and forms a unique arrangement called hydration, and therefore the iconic compounds are highly conductive when dissolved in water

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The torque required, in n∙m per meter of rod length, to hold the inner rod fixed is 0.535N.m/rod length

Angular velocity, ω = 160rev/min

ω (rad/s) =  (2π×160)/(60) = 16.74rad/s

Tangential velocity,

(V) = ωr

r is radius  = 14/2 = 7cm = 0.07m

Tangential velocity of the sleeve

(V)= ωr

V = 16.74  rad/s×0.07m

V  = 1.171m/s

Distance between the cylinders,

h= (14-12)/2 = 1cm

h = 0.01 m

Shear stress on glycerin is given by

τ = μ×V/h

μ is the dynamic viscosity of glycerin  at 20°C = 1.49 kg/m.s

∴ τ = (1.49 ×1.171 )/(0.01)

  τ = 174.4 N/m²

Shearing force (F) = shear stress × area

F = τ × A

F = τ * 2πrL          [A=2πrL (area of cylinder )]

F/L = (17.4×2π×0.07)

F/L =  7.649N/m

To hold the inner rod fixed

the opposite torque by inner rod must be equal to torque produced by the shearing force.

Torque/length (N.m/length) = [force/length (N/m) * radius]

τ /L = 7.649 ×0.07 =  0.535N.m/rod length

The torque required, in n∙m per meter of rod length, to hold the inner rod fixed is 0.535N.m/rod length

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Answer:If kinetic energy increases, so does the thermal energy, and vice versa.

Please brainliest!

The capacitance of two square parallel plates will be 1.777 farads.

The body's capacity to hold electric charge is constrained by capacitance. There is a capacitance for each capacitor. Two metallic sheets of area A, spaced by d, make up the standard parallel-plate capacitor.

The parallel plate capacitor formula is given by:

C = ε Ad

Two square parallel plates 6.7 cm on a side are separated by 1.8 mm of paraffin. The dielectric constant of paraffin is 2.2. Then the capacitance of two square parallel plates will be given as,

C = ε Ad

C = 2.2 x 0.67 x 0.67 x 1.8

C = 1.777 farad

Two parallel square plates will have a capacitance of 1.777 farads.

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Answer:

there yah go that's the answer

This question would be a piece o' cake, except that we don't know your observations, your data, or your conclusions.

We also don't know the first method, the second method, the accuracy of either method, the displacement method, or what you found out from this investigation.

Otherwise, like I said, this is really no problem.

The focal length of the mirror, when the object is moved towards it and a virtual image is formed is calculated to be -4u/3.

We know that,

magnification, m =      height of image, v        

                                 height of the object, u

given in the question, m = 4

as the mirror is concave, thus:

v= -4u

Now, by using the mirror formula:

1/(-f) = 1/ v + 1/u    

(as the image formed is virtual, the focal length of the mirror will be negative)

1/(-f) = 1/(-4u) + 1/u

-1/f = 3/4u

f= -4u/3

Concave mirrors create both physical and virtual images. When the concave mirror is put very close to the object, a virtual and enlarged image is generated; as the distance between the item and the mirror increases, the size of the image decreases, and genuine images are formed. These real-world photographs can be displayed on a screen. The concave mirror's focal point and center of curvature are located in front of the mirror.

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Answer:

Point A

Explanation:

There are 3 states of equilibrium, which are as follows:

1. Stable Equilibrium

2. Unstable Equilibrium

3. Neutral Equilibrium

1. Stable Equilibrium:

A body is said to be in stable equilibrium, if it comes back to its original position, when it is slightly  displaced. In this case the center of mass of the body is raised up as compared to the initial position.

Example: A book lying on a table, a map hanging on the wall, a stone suspended by a spring.

2. Unstable Equilibrium:

A body is said to be in unstable equilibrium if it does not come back to its original position when it is  slightly displaced. In this case the center of mass of the body is lowered, as compared to the initial position.

Example: A vertical standing pencil, a stick balanced on finger, a funnel resting on its pointed end.

3. Neutral Equilibrium:

A body is said to be in neutral equilibrium, if on being slightly displaced it does not come back to its  original position but occupies a new position similar to its original position. In this case the center of mass of the body remains at same height.

Example: A spherical ball on floor, a cone resting in horizontal position.

So, it is clear from the figure that when we will remove displacement the bus will come back to its original position. Therefore, this is the case of stable equilibrium.

So, the center of mass must have raised up. The original center of mass of the bus must be in the center. So, now the center of mass should have moved above center of bus, vertically.

Therefore, the center of mass of the bus is at point A  

Answer:

Explanation:

A. Encouragement

Answer:

Stars create new elements in their cores bu squeezing elements together in a process called unclear fusion. First stars fuse hydrogen atoms into heluim. Helium atorm then fuse to create berylluim and so on until fusion in the star’s core has created every element up to icon.

Answer:

1. The force of friction [tex]F_f =0.72 \times F_n[/tex]

2. The total travel time is approximately 0.884 seconds

The range is approximately 2.209 m

The maximum height reached is approximately 0.383 m

3. The time it will take the cyclist to stop is approximately 25.806 seconds

4. The time it will take the ball to reach the ground is approximately 2.020 seconds

Explanation:

1. Given that the coefficient of static friction, μ = 0.72, we have;

[tex]F_f = \mu \cdot F_n = 0.72 \times F_n[/tex]

2. The given parameters are;

The initial velocity of the car, v = 5 m/s

The direction of the vehicle = 60° to the horizontal

Therefore, we have;

The vertical component of the velocity, [tex]v_y[/tex] = 5 × sin(60°) = 2.5×√3

[tex]v_y[/tex] = 2.5×√3 m/s

The total travel time, t = 2·u·sin(θ)/g = 2 × 5 × sin(60°)/9.8 ≈ 0.884

The total travel time, t ≈ 0.884 seconds

The range, R = (u²·sin(2·θ))/g = 5² × sin(120°)/9.8 ≈ 2.209

The maximum height is given from the v² = [tex]u_y[/tex]² - 2·g·h

Where;

v = The final velocity = 0 m/s at maximum height

h = [tex]h_{(max)}[/tex] = The maximum height

[tex]u_y[/tex] = The initial vertical velocity = 2.5·√3

∴ 0² = 2.5·√3² - 2 × 9.8 × [tex]h_{(max)}[/tex]

2.5·√3² = 2 × 9.8 × [tex]h_{(max)}[/tex]

[tex]h_{(max)}[/tex] = 2.5·√3²/(2 × 9.8) ≈ 0.383

The maximum height = [tex]h_{(max)}[/tex] = 0.383 m

3. The given parameters are;

The initial velocity of the cyclist, v₀ = 16 m/s

The deceleration of the cyclist, a = -0.62 m/s²

At the point the cyclist stops, the final velocity, [tex]v_f[/tex] = 0

Therefore, from the given kinematic equations, we have;

[tex]v_f[/tex] = v₀ + a·t

Where t, is the time it will take the cyclist to stop

∴ t = ([tex]v_f[/tex] - v₀)/a = (0 - 16)/(-0.62) ≈ 25.806

Therefore, the time it will take the cyclist to stop = t ≈ 25.806 seconds

4. The time, t, it will take the ball to reach the ground, from a height, h = 20 meters is given by the equation of free fall as follows;

h = 1/2·g·t²

Where;

g = The acceleration due to gravity = 9.8 m/s²

Therefore, we have;

t² = h/(1/2·g)

t = √(h/(1/2·g)) = √(20/(1/2 × 9.8)) = 2.0203050891 ≈ 2.02

The time it will take the ball to reach the ground, t ≈ 2.020 seconds.

Explanation:

#31 = crest

#32 = Trough

#33 = Wavelength

#34 = Amplitude

-TheUnknownScientist

Answer:

vaat hachi upar vada ni.

Answer:

25 Kg

Explanation:

M=F/A

Answer:

Hope it helps!

Meander : A curve in a river, Delta: Mouth of the river, Tributary : A stream that flows into a river.

A river or other watercourse's channel may contain several regular, sinuous curves called meanders. It is created when a watercourse deposits sediments on an inner, convex bank, which is often a point bar and erodes the sediments of an outer, concave bank (cut bank). The channel migrates back and forth across the axis of a floodplain as a result of this combined erosion and sedimentation, forming a sinuous flow.

A freshwater stream that flows into a bigger stream or river is called a tributary. The mainstream of a river refers to its parent, or bigger, river. The confluence is the location where a tributary joins the main stem.

Tributaries, often known as effluents, do not enter the ocean directly.

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Magnetic field does the cable crew ate at points outside the cable will be zero .

Mathematically, Ampere's law circuital law is given by

 ∫B.dl = u₀I   ......(2)  where u₀ is the permitivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex]  and I is the total current threading in the loop .

It is given that coaxial cable carries current 2.00 A in one direct tin, and the sheath around it carries current 2.00A in the opposite direction.

Hence the total current in the loop will be

  [tex]I=2+(-2)=0[/tex]

Putting this value of current in equation (2) , we get

[tex]B=0[/tex]

As the total current is zero , so the magnetic field will be zero .

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Magnetic field does the cable crew ate at points outside the cable will be zero .

Mathematically, Ampere's law circuital law is given by

 ∫B.dl = u₀I   ......(2)  where u₀ is the permitivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex]  and I is the total current threading in the loop .

It is given that coaxial cable carries current 2.00 A in one direct tin, and the sheath around it carries current 2.00A in the opposite direction.

Hence the total current in the loop will be

  [tex]I=2+(-2)=0[/tex]

Putting this value of current in equation (2) , we get

[tex]B=0[/tex]

As the total current is zero , so the magnetic field will be zero .

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Magnetic field does the cable crew ate at points outside the cable will be zero .

Mathematically, Ampere's law circuital law is given by

 ∫B.dl = u₀I   ......(2)  where u₀ is the permitivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex]  and I is the total current threading in the loop .

It is given that coaxial cable carries current 2.00 A in one direct tin, and the sheath around it carries current 2.00A in the opposite direction.

Hence the total current in the loop will be

  [tex]I=2+(-2)=0[/tex]

Putting this value of current in equation (2) , we get

[tex]B=0[/tex]

As the total current is zero , so the magnetic field will be zero .

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Answer for the first one is 2. The answer for the 3rd one is 8

Plastics degrade when exposed to ultraviolet (UV) light from the sun. UV exposure can make a chemical reaction in the plastic, resulting in the scission, or severing, of those large polymer molecules if exposed long enough.

Plastics degrade when exposed to ultraviolet (UV) light from the sun. UV light can cause a chemical reaction in the plastic, resulting in the scission, or severing, of those large polymer molecules if exposed long enough.

When exposed to ultraviolet (UV) light from the sun, plastics degrade. If exposed to UV light for an extended period of time, it can cause a chemical reaction in the plastic, resulting in the scission, or severing, of those large polymer molecules.

Thus, light can cause the plastic to melt.

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The electric flux through the hole is [tex]56.45\ webber[/tex] .

It is given , hollow sphere of radius 10.0cm surrounds a 10.0-μC charge.

The whole surface of hollow sphere [tex]= 4\pi r^2[/tex]

                                                            [tex]= 4\times 3.14\times (10 \times 10^{-2})^2 \\\\= 12.56\times 10^{-2} m^2[/tex]

Area of the hole ( both side ) [tex]= 2\times \pi r^2[/tex]

                                               [tex]= 2\times 3.14 \times (10^-^3)^2\\= 6.28 \times 10^-^6 m^2[/tex]

According to Gauss's theorem, the flow from a particular charge in the center is given by

 [tex]\phi= \frac{10\times10^-^6}{8.85\times 10^-^1^2}\\\\\phi=1.13\times10^6[/tex]

This flux flows through the surface of the sphere, so the flux  per unit area which is given by

[tex]= \frac{ 1.13\times 10^6 }{ 12.56\times 10^-^2} \\\\= 8.99 \times 10^6 \ weber / m^2[/tex]

Flux through area of hole is given by :

[tex]= 8.99\times10^6 \times6.28 \times 10^-^6\\ = 56.45 \ weber[/tex]

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Answer:

Explanation:

Force of gravity is equal to mass times g

Fg=150 N

Fg=mg

150=m(9.81)

m=150/9.81 kg

FnetX=20-10=10 N

Fnetx=ma

10=150/9.81(a)

a=0.654 ms^-2

Note acceleration might need significant figures so it a=0.7 ms^-2

For the normal force, if the object isn't moving up or down. Then you can assume it's equal to the gravitational force which is 150 N.

If the object is accelerating up or down. I don't know how you would find normal force because not enough information.

Answer:

nope never

Explanation:

Answer:

never ever they dont

Answer:

A. the time of fire is 15 seconds, and the angle of fire is approximately 23.794° above the horizontal

B. The angle of fire is increased to approximately 35.4126° above the horizontal

Explanation:

A. The height of the bridge, h = 70 m

The speed with of the shell, v₀ = 100 m/s

The location of the speedboat = 3000 m

The direction of the speedboat = 26 m/s

The acceleration of the speedboat, a = 11 m/s²

Let t represent the time of firing the shells, and let x represent the distance of the speedboat from the bridge, and let θ, represent the angle to fire with, we have;

For the speedboat, t = x/(100 × cos(θ))

We note that the time the shell can travel the 3,000 m = 30 seconds

Therefore an adequate time to fire is, t = 15 seconds

The distance the speedboat covers in 15 seconds is given as follows;

s = u·t + 1/2·a·t²

s = 26 × 15 + 1/2 × 11 × 15² = 1627.5 m

At the point the speedboat had traveled 1,627.5 m, the distance of the speedboat, x is then 3000 - 1,627.5 = 1,372.5 m from the bridge, the angle of fire is given from the following formula;

t = x/(100 × cos(θ))

15 = 1,372.5/(100 × cos(θ))

cos(θ) = 1,372.5/(15 × 100) = 0.915

θ = cos⁻¹(0.915) ≈ 23.794°

The angle of fire, θ ≈ 23.794° above the horizontal in the direction of the speedboat

B. Given that a 10 m/s wind is blowing towards East, we have;

The horizontal velocity towards East = 10 + v₀ × cos(θ)

The angle of firing is therefore, given as follows;

15 = 1,3725.5/(10 + 100 × cos(θ))

(10 + 100 × cos(θ)) = 1,3725.5/15

100 × cos(θ) = 1,372.5/15 - 10

cos(θ) = (1,372.5/15 - 10)/100 = 0.815

θ = cos⁻¹(0.815) ≈ 35.4126°

Therefore, the angle of fire, θ, will be increased to approximately 35.4126° above the horizontal in the remote controlled speedboat direction.

Answer:

b. The Constitutional Convention

Explanation:

The given events in its chronological order :

1. Declaration of Independence  ---- 4th July, 1776.

2. Articles of Confederation ---------- 15th November, 1777

3. The Constitutional Convention ---- 25th May, 1787

4. U.S. Constitution ------------------------ 17 September, 1787

The U.S. Constitutional Convection took place in the year 1787 from 25th May to 17th September. It took place at the Pennsylvania State House situated in Philadelphia. The Constitutional Convection of the United States was chaired by George Washington.

Answer:

The velocity of the cross-wind was 375 km/hr South

Explanation:

The given speed of the airplane, v₀ = 500.0 km/hr W

The direction the airplane is headed = West

The direction of the wind encountered = Southbound wind

The final velocity of the airplane, R = 625 km/hr

The final direction of the airplane = South West SW

Let vₐ represent the velocity of the cross-wind

Therefore, we have the given velocities in vector form as follows;

R = -500.0·i - vₐ·j

Also, we have;

[tex]\left | R \right | = 625 = \sqrt{v_0^2 + v_a^2} = \sqrt{(-500)^2 + (-v_a)^2}[/tex]

625² = (-500)² + (-vₐ)²

(-vₐ)² = 625² - (-500)² = 140625

-vₐ = 375

vₐ = -375 km/hr North = 375 km/hr South

The velocity of the cross-wind = vₐ = 375 km/hr South

These are Some climates

Tropical.

Dry.

Temperate.

Continental.

Polar.

And these are some biomes

aquatic, grassland, forest, desert, and tundra,

In order to qualify for the finals in a racing event the race car wit an average speed of 250 km/h on a track with a total length of 1600 m must finish  the track in a time of: 23.04 seg

The formula and procedure we will use to solve this exercise is:

t = x/v

Where:

Information about the problem:

By converting the distance units from (m) to (km) we have:

x=1600 m * 1 km/1000 m

x = 1.6 km

Applying the time formula we have that:

t = x/v

t = 1.6 km / 250 km/h

t = 6.4 *10^-3 h

By converting the time units from (h) to (seg) we have:

t = 6.4 *10^-3 h * 3600 seg/1 h

t= 23.04 seg

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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Answer:

Newton, symbol N

Explanation:

newton, symbol N

Answer: Ptolemy or Kepler or Tycho Brache

1.plants,most algae and cyanobacteria

2.during photosynthesis cells use carbon dioxide and energy from the sun to make sugar molecules and oxygen

3.carbon dioxide+water---Glucose+oxygen

4.chloryphil

5.it absorbs blue and red good and absorbs green poorly

6 In plants, photosynthesis takes place in chloroplasts, which contain the chlorophyll. Chloroplasts are surrounded by a double membrane and contain a third inner membrane, called the thylakoid membrane, that forms long folds within the organelle