What is the change in momentum of a 50. kg
woman goes from running at 8.0 m/s to 0.0
m/s?

Answers

Answer 1

Answer:

400 kg-m/s

Explanation:

Given that,

Mass of the woman, m = 50 kg

Initial velocity, u = 8 m/s

Final velocity, v = 0 m/s

We need to find the change in momentum of the woman. It can be given by :

[tex]\Delta p=m(v-u)\\\\=50\times (8-0)\\\\=400\ kg-m/s[/tex]

So, the change in momentum is 400 kg-m/s.


Related Questions

Pls help I think it's pretty easy
Electromagnetic waves transfer energy and are produced by _____.

Answers

the transfer of energy by electromagnetic waves is called electromagnetic radiation. ... This causes a vibrating electric field, which in turn creates a vibrating magnetic field.

A rocket travels 200,000 meters in a time of 4.40 seconds . what of the speed of the rocket ?

Answers

Answer:

the speed of the rocket is 45454.5455

Explanation: Because the speed formula is basically just distance/ divided by time all you need to do is divide 200,000 meters by 4.40 seconds. And then thus you will get the speed.

Answer:

45454.55 m/s

Explanation:

[tex]S=\frac{d}{t}[/tex]

= [tex]\\S=\frac{200000}{4.40}[/tex]

=45454.55 m/s

8 A small smooth object slides from rest down a smooth inclined plane inclined at
30° to the horizontal. What is (i) the acceleration down the plane, (ii) the time
to reach the bottom if the plane is 5 m long?
The object is now thrown up the plane with an initial velocity of 15 ms -1.
(iii) How long does the object take to come to rest? (iv) How far up the plane has
the object then travelled?​

Answers

Answer:

(i) The acceleration of the object down the plane is approximately 4.9 m/s²

(ii) The time it takes for the object to reach the bottom is approximately [tex]1.\overline{428571}[/tex] seconds

(iii) The time it takes the object to come to rest is approximately 1.030636 seconds

(iv) The object has travelled past the top of the plane by time it comes to rest

Explanation:

(i) The given parameter for the objects motion are;

The angle of inclination of the plane with the horizontal, θ = 30°

The length of the plane, s = 5 m

Let "a" represent the acceleration down an inclined plane, due to the acceleration under gravity "g" we have;

a = g × sin(θ)

Where;

g = The acceleration due to gravity ≈ 9.8 m/s²

∴ a ≈ 9.8 m/s² × sin(30°) = 9.8 m/s² × 0.5 = 4.9 m/s²

The acceleration of the object down the plane, a ≈ 4.9 m/s²

(ii) The time it takes for the object to reach the bottom, can be found from the following kinematic equation of motion;

s = u·t + 1/2·a·t²

Where;

s = The length of the inclined plane = 5 m

u = The initial velocity of the object = 0 m/s

t = The time of motion of the object (Here the time to reach the bottom of the plane)

a = The acceleration of the object = 4.9 m/s²

Therefore, we have;

5 = 0 × t + 1/2 × 4.9 × t² = 2.45·t²

t² = 5/2.45 = 100/49

t = √(100/49) = 10/7 = [tex]1.\overline{428571}[/tex]

The time to reach the bottom of the plane = t = [tex]1.\overline{428571}[/tex] seconds

(iii) When the object is thrown up the plane with an initial velocity of 15 m/s, the time, "t", it takes the object to come to rest is found by the following kinematic equation of motion;

v² = u² - 2·a·s

Therefore, we have;

v² = 15² - 2 × 4.9 × 5 = 176

v = √176 = 4·√11

The velocity of the object at the top of the plane = v = 4·√11 m/s

The time it takes the object to come to rest after reaching the top of the plane = The time it takes the object (projectile) to reach maximum height

[tex]t_m = \dfrac{v_i \cdot sin(\theta _i )}{g}[/tex]

Where;

[tex]t_m[/tex] = The time it takes the object to reach maximum height

[tex]v_i[/tex] = The initial velocity of the object at the top of the inclined plane = 4·√11 m/s

[tex]\theta _i[/tex] = The initial angle of inclination of the path of the object with the horizontal = 30°

Therefore, we have;

[tex]t_m = \dfrac{4 \times \sqrt{11} \times sin(30^{\circ} )}{9.8} = \dfrac{10 \cdot \sqrt{11} }{49} \approx 0.67686[/tex]

The time it takes the object to come to rest after reaching the top of the plane = The time it takes the object to reach maximum height = [tex]t_m[/tex] ≈ 0.67686 seconds

The time it takes the object to reach the top of the plane, [tex]t_{top}[/tex], is given from the kinematic equation of motion, v = u - a·t, as follows

v = u - a·t

∴ t = (u - v)/a

[tex]t_{top}[/tex] = (15 - 4·√11)/4.9 ≈ 0.353776

The time it takes the object to reach the top of the plane = [tex]t_{top}[/tex] ≈ 0.353776 s

The total time it takes the object to come to rest, ∑t = [tex]t_m[/tex] + [tex]t_{top}[/tex]

∴ ∑t ≈ 0.67686 + 0.353776 = 1.030636

The time it takes the object to come to rest = ∑t ≈ 1.030636 seconds

(iv) The distance up the plane the object reaches, "s", is given by the following kinematic equation;

s = u·t - 1/2·a·t²

Therefore, we have;

s = 15 × 15/4.9 - 1/2 × 4.9 × (15/4.9)² ≈ 22.959 m

However, the plane is 5 meters long, therefore, the object goes further than the top of the plane.

Adjetivo utilizado para calificar la componente de la aceleración en la dirección del movimiento de un punto que se mueve según una circunferencia.

10 letras

Answers

Answer:

Tangencial.

Explanation:

El adjetivo empleado es tangencial, cuya longitud es diez caracteres. La aceleración tangencial es el componente del vector aceleración que es paralelo a la dirección del vector velocidad de un punto que se mueve sobre una circunferencia.

La aceleración tangencial tiene la función de cambiar la magnitud del vector aceleración.

I feel death among us

Answers

same but who knows how 2021 might go

Answer:

same....

Explanation:

Wanna be friends?

An inclined plane is set at an angle of 29 degrees above horizontalWhat is the acceleration of a 420 g block of ice sliding down the inclined plane? Assume no friction

Answers

The net force parallel to the plane is

F = m g sin(29°) = m a

where

m = mass of the block

g = magnitude of the acceleration due to gravity, 9.8 m/s²

a = mag. of acceleration of the block

where we take the direction of the block's sliding down the plane to be positive. Then

a = g sin(29°) ≈ 4.8 m/s²

How would the gravitational force between the earth and the moon change if the moon had half the mass?

Answers

The moon's gravity, combined with the waltz of Earth and the moon around their center of mass, forces the oceans into an oval shape, with two simultaneous high tides. ... If the moon were half its mass, then the ocean tides would have been correspondingly smaller and imparted less energy to it.

Write a sentence on how these words are used in real life situations

1. Average Velocity
2. Instantaneous Velocity
3. Acceleration

Answers

Answer:

Explanation:

You can approach an expression for the instantaneous velocity at any point on the path by taking the limit as the time interval gets smaller and smaller. Such a limiting process is called a derivative and the instantaneous velocity can be defined as.#3

For the special case of straight line motion in the x direction, the average velocity takes the form: If the beginning and ending velocities for this motion are known, and the acceleration is constant, the average velocity can also be expressed as For this special case, these expressions give the same result. Example for non-constant acceleration#1

When you walk into a dark room and turn the light on, do the electrons travel all the way from the switch to the light?

Answers

Answer:

Yes

Explanation:

This is because for the light to come on, electric current has to flow through it which is due to electron motion. As the electrons move through the light, it turns electrical energy to light energy, so the light comes on.

Distance is a __________ quantity, as it has no direction, only magnitude

Answers

Answer:

-scalar

Explanation:

-A scalar is any quantity that has a magnitude, but no direction

-quantities with no specified direction.

hope it helps:)

How would the gravitational force between the earth and the moon change if the moon had twice the mass?

Answers

Explanation: The moon's gravity, combined with the waltz of Earth and the moon around their center of mass, forces the oceans into an oval shape, with two simultaneous high tides. ... If the moon were half its mass, then the ocean tides would have been correspondingly smaller and imparted less energy to it.

When a wave strikes and object and bounces off . ( example echo)
A. Medium
B. Refraction
C.Reflection
D. Interference

Answers

Answer:

C. reflection

Explanation:

reflection occurs when a wave strikes an object and bounces off of it

When a wave strikes an object and bounces off, it is called reflection.

Hence, the correct option is C.

This is similar to what happens when sound waves strike a surface and bounce back, resulting in an echo.

Reflection occurs when a wave encounters a boundary or an obstacle and changes direction, returning back into the medium it came from.

The angle of incidence (the angle at which the wave strikes the surface) is equal to the angle of reflection (the angle at which the wave bounces off the surface).

Therefore, When a wave strikes an object and bounces off, it is called reflection.

Hence, the correct option is C.

To know more about reflection here

https://brainly.com/question/15487308

#SPJ6

An angle of refraction is the angle between the refracted ray and the
o incident ray.
o normal.
O medium.
O boundary

Answers

Answer:

b) normal

Explanation:

The angle of refraction (transmission) Θt is the angle between the refracted ray and the normal N'. 2. When a light ray hits a surface normally, the angle between the incident ray and the normal is 0, so Θi = 0. Since the angle of reflection equals the angle of incidence, Θr= 0.

The angle of refraction is the angle between the refracted ray and the normal, which is option B.

What is the angle of refraction?

When light travels from one medium to another medium with a different refractive index, it changes direction.

The angle of refraction is the angle between the refracted ray and the normal, which is an imaginary line perpendicular to the boundary between the two media at the point of incidence. The incident ray is the incoming ray of light that strikes the boundary between the two media.

The medium refers to the substance through which light is passing, and the boundary is the surface separating the two media.

However, the angle of refraction is not related to the incident ray or the boundary, but rather the norm.

Thus, the correct answer would be an option (B) normal.

To learn more about the angle of refraction click here:

https://brainly.com/question/2660868

#SPJ6

terms involved in s=ut+1/2at^2​

Answers

Explanation:

The terms involved in S = ut + 1/2at²

S = displacement

u = initial velocity

a = acceleration

t = time.

Hope it will help :)

Answer:

the distance traveled or displacement (s) of an object using its initial velocity (u), acceleration (a), and time (t) traveled.

3. Electrons are the only part of an atom that can be transferred between materials. True or
False?

Answers

Answer:

True

Explanation:

Electrons can be transferred between materials as in chemical reactions solid substances lose electrons while other elements gain electrons to balance the electrons in reaction.It occurs by conduction,polarization and friction.

Question 2 (2 points)
Which of the following is a true statement about mass and weight? (2 points)
a
Mass is a measure of how much matter an object has, while weight is a measure of
how much space the object takes up.
Mass will not change based on location, while weight will change based on
gravitational pull
b
Mass is a measure of a gravitational pull on an object, while weight is a measure of
how much matter is an object has,
Mass is proportional to the force of gravity, while weight is proportional to the
amount of mass,
d

Answers

Answer:

B. Mass will not change based on location, while weight will change based on gravitational pull.

Answer:

B

Explanation:

took the test

Two positive charges 12×10^-6C and 8×10^-6 are 10cm apart. Find the workdone in bringing them 4cm together

Answers

Answer:

W = 5.76 J

Explanation:

Given that,

Charge 1, [tex]q_1=12\times 10^{-6}\ C[/tex]

Charge 2, [tex]q_2=8\times 10^{-6}\ C[/tex]

The distance between charges is 10 cm.

Initial distance = 10 cm = 0.1 m

Final distance = 10 cm - 4 cm = 6 cm = 0.06 m

We need to find the work done in bringing the 4 cm together.

We know that,

Work done = change in kinetic energy

[tex]W=kq_1q_2(\dfrac{1}{r_2}-\dfrac{1}{r_1})\\\\\text{Put all the values}\\\\W=9\times 10^9\times 12\times 10^{-6}\times 8\times 10^{-6}(\dfrac{1}{0.06}-\dfrac{1}{0.1})\\\\W=5.76\ J[/tex]

So, the required work done is 5.76 J.

Which of the following best explains why the noble gases are less likely to chemically
bond with other elements?
A They are all non-metals. |
B They are all rare elements.
C They all have a full outer shell of electrons.
D They have the highest atomic number in the row.

Answers

Answer:

a

Explanation:

If a missile is launched from the equator toward an object in the Northern Hemisphere, should it be aimed to the left, to the right, or directly at its target? Why?

Answers

Answer:

Must be aimed to the left

Explanation:

Coriolis effect deflects wind or any moving item which has no contact with earth and has substantial distance to cover and moving at a substantial altitude. Coriolis effect deflectd the object to the right in the northern hemisphere. Therefore, missile must be aimed to the left, to nullify the coriollis effect.

Will anyone please help me solve this physics Problem?​

Answers

Answer:

I. Clockwise moment = 150 Nm

II. Anticlockwise moment = 400 Nm

III. 200 N

III. The anticlockwise moment.

Explanation:

From the question given above, we can obtain the answers to the questions as follow:

I. Determination of the clockwise moment.

Distance (d) = 1.5 m

Force (F) = 100 N

Clockwise Moment =?

Moment = Force × distance.

Clockwise moment = 100 × 1.5

Clockwise moment = 150 Nm

II. Determination of the anticlockwise moment.

Distance (d) = 2 m

Force (F) = 200 N

Anticlockwise Moment =?

Moment = Force × distance.

Anticlockwise moment = 200 × 2

Anticlockwise moment = 400 Nm

III. Determination of who will turn the sea saw.

Clockwise moment = 150 Nm

Anticlockwise moment = 400 Nm

Since the anticlockwise moment is greater than the clockwise moment, it therefore means that the anticlockwise moment will turn the sea saw.

All sound waves need a(n) _______________________________________ to travel through. 4. _____________________ and ___________________ can be used to describe a sound wave.

Answers

Answer:

Material medium

compressions and rarefactions

Explanation:

A sound wave is an example of a mechanical wave. All mechanical waves require a material medium for propagation. The medium for the propagation of sound is air. This is the reason why, if you cover your mouth, it will be difficult for another person to hear whatever you are saying.

Sound is also a longitudinal wave. Longitudinal waves are described in terms of compressions and rarefactions. Compressions refer to areas where air molecules crowd together while rarefactions refer to areas where the air molecules spread out.

A test pilot flies with an acceleration of 5 g. What is his acceleration in meters
per second squared?
A. 5 m/s2
B. 9.8 m/s2
C. 49 m/s2
D. 14.8 m/s2

Answers

Answer:

C. 49 m/s^2

Explanation:

1 G = 9.81 m/s^2

so 5 * 9.81 = 49.05

or C. 49 m/s^2

A tea pilotflies with an acceleration of 5g. What is his acceleration in meters per second squared? In the picture it shows that the answer is C. 49 m/s2

find the factor of the number 1.30​

Answers

1 3/10  because 130 is greater than 100 we have simplified this fraction even further to a mixed fraction.

Please provide positive integer to calculate.



How many newtons is the force of gravity g , acting on an apple with mass m = 200 g?​

Answers

Answer:

Mass of the apple is 200g or 0.2 kg

Force acting on it will be,

Force= Mass× acceleration due to gravity

Force= 0.2×9.8 Newton= 1.96 Newton

Answer:

2 N

Explanation:

The question requires you to express the weight of the apple into Newton

1 kg = 10 N

200g = 200/1000 = 0.2 kg

1 kg = 10 N

0.2 kg = ?

0.2 * 10 = 2 N

A boy pushed horizontally a 3.5 kg plastic chair across the slippery floor. If
the acceleration of the plastic chair is 2.2 m/s2 to the left, what is the net force
exerted on the plastic chair?

Answers

Answer:

7.7 N to left or -7.7 N

Explanation:

slippery floor means no frictional force

Equation for force

F = m * a , where F is force, m is mass in kg, and a is acceleration in m/s²

F = 3.5 * -2.2 m/s² = -7.7 N

a 20 of of ice at 0c is dropped into water at boiling point, specific heat capacity of water =4200 J/kg•c, sepesific latent heat of fusion (Lf) =3.3x10^(5) J/kg calculate the amount of heat energy needed to complete the previous conversion​

Answers

Answer:

15 KJ

Explanation:

The quantity of heat (Q) required is given as:

Q = mcΔθ + mL

where m is the mass of ice, c is its specific heat capacity, L is its specific latent heat andΔθ is the change in temperature.

Given: m = 20g, temperature of ice = 0[tex]^{o} C[/tex], specific heat capacity of water = 4200 J/kg[tex]^{o} C[/tex], latent heat of fusion of ice = 3.3 x 10^(5) J/kg, temperature of water = 100[tex]^{o} C[/tex].

Q = m (cΔθ + L)

   = 0.02(4200 x (100) + 330000)

   = 0.02(420000 + 330000)

  = 0.02 (750000)

Q = 15000

Q = 15000 Joules

Q = 15KJ

The quantity of heat needed to complete the conversion is 15 KJ.

Tom skis at an average speed of 5 m/s. How many mins does it take for Tom to ski 4050 m.

Answers

It takes him 810 minutes to ski 4050m

Divide 4050 by 5 to get 810

During a goal-line stand, a 112-kg fullback moving eastward with a speed of 6 m/s
collides head-on with a 120-kg lineman moving westward with a speed of 8 m/s.
The two players collide and stick together, moving at the same velocity after the
collision. Determine the post-collision velocity of the two players.

Answers

Answer:

-1.24 m/s

Explanation:

Total momentum before collision = total momentum after collision

Total momentum before collision = (mass of full back * velocity of fullback) + (mass of lineman * velocity of line man).

Mass of full back = 112 kg, mass of line bag = 120 kg, velocity of full back  6 m/s (east), velocity of line back = -8 m/s (west). Hence:

Total momentum before collision = (112 * 6) + (120 * -8) = 672 - 960 = -288 kgm/s

The total momentum after collision = (mass of full back + mass of line back) * velocity after collision.

Let velocity after collision be v, hence:

The total momentum after collision = (112 + 120)v = 232v

Total momentum before collision = total momentum after collision

-288 = 232v

v = -288 / 232

v = -1.24 m/s

Therefore after collision, the two players would move at a velocity 1.24 m/s west (the same direction as the lineman).

Help plz!! I’ll give brainlist!! I need it fast plz

Answers

Answer:

1.A

2.E

3.C

4.i think A

Explanation:

1. A
2. E
3. B
4. D

the horizontal is on the left.
vertical is on the right.

for number one it says where was the speed zero? look at the line, A is at the bottom and horizontal is there.
same applies to the vertical which you get the answer E

You drop a bowling ball and it falls with an acceleration of 10 m/s2. The ball has a mass of 5 kg. How much force is causing the ball to fall?

Answers

Explanation:

Given

acceleration (a) = 10 m/s²

mass (m) = 5 kg

Force (F) = ?

We know

F = m * a

= 5 * 10

= 50 Newton

The force is 50 N

Hope it will help :)

Answer:

[tex]\boxed {\boxed {\sf 50 \ Newtons }}[/tex]

Explanation:

Force can be found using the following formula.

[tex]F=m*a[/tex]

where F is the force, m is the mass, and a is the acceleration.

1. Define Values

We know the acceleration of the bowling ball is 10 m/s² and the mass is 5 kilograms.

[tex]a= 10 \ m/s^2 \\m= 5 \ kg[/tex]

2. Calculate Force

Substitute the values into the formula.

[tex]F= 5 \ kg * 10 \ m/s^2[/tex]

Multiply.

[tex]F= 50 \ kg*m/s^2[/tex]

1 kilogram meter per square second is equal to 1 Newton. Our answer of 50 kg*m/s² is equal to 50 N

[tex]F=50 \ N[/tex]

The force causing the ball to fall is 50 Newtons

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