What is the density of an object with a volume of 3ml and a mass of 18 grams

Answer:

The temperature of the water decreases and so the reaction is endothermic

Explanation:

This option is correct because when the 5.0g potassium chloride (KCl) was added to the 100.0ml distilled water, the KCl made the water absorb heat coming from it which made the water decrease in temperature thereby causing an endothermic reaction.

An endothermic reaction actually takes place when the temperature of a system which is isolated decreases. The surroundings of a non-isolated system actually gains heat. While in an exothermic reaction, the temperature of a system increases due to the release or evolution of heat. This heat is released into the surroundings.

Answer:

D. AgN.

Explanation:

Hello!

In this case, since the boiling point of a solution increases are more solute remains dissolved in the liquid, as more energy is required to start the phase transition, for insoluble solids for which we know the solubility product which has the following relationship with the amount of ions in solution:

"the greater Ksp, the more ions the solution has"

In such a way, for the solid with the greatest Ksp we understand it has most of the ions in solution and therefore the highest boiling point, thus, among the choices, D. AgN is the one with the highest boiling point because it Ksp is 7.2E-11, whcih is the greatest.

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Answer:

1. Number of moles in 3.63 * 10²² atoms of K = 0.06 moles

2. Number of moles in 5.96 g of BaCO₃ = 0.03 moles

3. Number of moles of NH₃ = 0.88 moles

4. Volume of CSI = 0.50 liters

Explanation:

1. One mole of K contains 6.02 * 10²³ atoms

Number of moles in 3.63 * 10²² atoms = (3.63 * 10²² atoms/6.02 * 10²³ atoms) * 1 mole

Number of moles in 3.63 * 10²² atoms of K = 0.06 moles

2. Number of moles = mass / molar mass

Molar mass of BaCO₃ = 197.33 g/mol; mass of BaCO = 5.96 g

Number of moles = 5.96 g/ 197.33 g/mol

Number of moles in 5.96 g of BaCO₃ = 0.03 moles

3. Number of moles = mass / molar mass

Molar mass of NH₃ = 17 g/mol; mass of NH₃ = 1.50 g

Number of moles = 1.50 g/ 17 g/mol

Number of moles of NH₃ = 0.88 moles

4. Chlorosulfonyl isocyanate, ClSO2NCO, otherwise known as CSI, is a reagent used in organic synthesis. It has a density of 1.626 g/cm³.

Volume = mass/density

mass = 82.0 g; density of CSI = 1.626 g/cm³

Volume = 82.0 g / 1.626 g/cm³

Volume = 50.43 cm³

Volume = 50.43 cm³/1000 cm³ * 1 liter

Volume of CSI = 0.50 liters

Answer:

-3

Explanation:

Phosphorus becomes phosphide with a -3 charge

Answer:

true

Explanation:

Answer:

Molecular

Explanation:

Using the rules for the nomenclature for naming binary covalent (molecular) compounds, the compound SO3 is named sulfur trioxide. The prefix tri- indicates that the oxygen has a subscript of 3 and that a molecule of sulfur trioxide has three oxygen atoms.

Answer:

umm.. B. a base that generates a lot of hydroxide ions in water.

The descriptions best describes a weak base is a base that dissociates only slightly in water.

Bases are those substances which react with acids to neutralize them, generally bases are the compounds of oxides, hydroxides and carbonates of metal elements.

Bases shows dissocation in the aqueous soluition and pH of bases ranges from 7 to 14. Strong bases shows full dissociation into ions and having higher pH values and weak bases shows partial dissociation into ions & having lower pH values.

Hence, option (D) is correct.

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Answer:

The correct answer is 2.1

Explanation:

The neutralization reaction involved in the titration is between a strong acid (HCl) and a strong base (NaOH), as follows:

HCl + NaOH → NaCl + H₂O

According to this, 1 equivalent of HCl reacts with 1 equivalent of NaOH. The equivalence point is the point at which the amount of NaOH added reacted completely with the amount of HCl.

moles of acid = moles of base

moles HCl = moles NaOH

Ca x Va = Cb x Vb

Ca = (Cb x Vb)/Va = (0.16 M x 17 mL)/(350 mL) = 7.8 x 10⁻³ M

Since HCl is a strong acid, we calculate the pH of the solution directly from the concentration of acid:

[H⁺]= Ca = 7.8 x 10⁻³ M

pH = -log [H⁺] = -log (7.8 x 10⁻³ M) = 2.11

Therefore, the pH of the HCl solution is 2.1

Answer:

(a) SeF₄

(b) OF₂

(c) N₂O

(d) PCl₃

Explanation:

Write the formula for each compound.

(a) selenium tetrafluoride. According to the name, this compound has 1 atom of Se and 4 atoms of F. The resulting formula is SeF₄, in which Se has the oxidation number 4+ and F has the oxidation number 1-.

(b) oxygen difluoride. According to the name, this compound has 1 atom of O and 2 atoms of F. The resulting formula is OF₂, in which the oxidation number of O is 2+ and the oxidation number of F is 1-.

(c) dinitrogen monoxide. According to the name, this compound has 2 atoms of N and 1 atom of O. The resulting formula is N₂O, in which the oxidation number of N is 1+ and the oxidation number of O is 2-.

(d) phosphorus trichloride. According to the name, this compound has 1 atom of P and 3 atoms of Cl. The resulting formula is PCl₃, in which the oxidation number of P is 3+ and the oxidation number of Cl is 1-.

Answer:

The correct option is D

Explanation:

Firstly, let's define the periodicity of these terms and then draw  conclusion from there.

Ionization energy is the amount of energy required to remove an electron from a gaseous atom in it's ground state. This property increases across a group in the periodic table.

Electronegativity is the measure of the property/tendency of an atom to attract an electron. This property also increases across a period. Thus, elements that have high electronegativity also have a high ionization energy.

Atomic radius is however the distance between the central nucleus to the outermost electron. This property decreases across the period. Thus, as electronegativity and ionization energy increases, atomic radius decreases.

From the above, it can be deduced that the correct option is d

Answer:high,small

Explanation:

I have the same test and I got it right

Answer:

1.5 moles H₂O

General Formulas and Concepts:

Chemistry - Stoichiometry

Explanation:

Step 1: Define

RxN:   2H₂ + O₂ → 2H₂O

Given:   0.750 moles O₂

Step 2: Stoich

[tex]0.750 \ mol \ O_2(\frac{2 \ mol \ H_2O}{1 \ mol \ O_2} )[/tex] = 1.5 moles H₂O

Step 3: Check

We are given 3 sig figs.

Since our answer is 2 sig figs, we don't need to round.

Answer:

AsH(2.) CHEBI:33104

Explanation:

Molecular Weight is : 75.9296 g/mol

Answer:

3 CO₃²⁻(aq) + 2 Cr³⁺(aq) ⇒ Cr₂(CO₃)₃(s)

Explanation:

Let's consider the molecular equation that occurs when aqueous solutions of ammonium carbonate and chromium(III) nitrate are combined.

3 (NH₄)₂CO₃(aq) + 2 Cr(NO₃)₃(aq) ⇒ 6 NH₄NO₃(aq) + Cr₂(CO₃)₃(s)

The complete ionic equation includes all the ions and insoluble species.

6 NH₄⁺(aq) + 3 CO₃²⁻(aq) + 2 Cr³⁺(aq) + 6 NO₃⁻(aq) ⇒ 6 NH₄⁺(aq) + 6 NO₃⁻(aq) + Cr₂(CO₃)₃(s)

The net ionic equation includes only the ions that participate in the reaction and the insoluble species.

3 CO₃²⁻(aq) + 2 Cr³⁺(aq) ⇒ Cr₂(CO₃)₃(s)

Answer:

c. Potential decreases and kinetic increases.

Explanation:

As the boulder is rolling down the hill, potential energy decreases as kinetic energy increases.

Please Brainliest me

Answer:

I think it is A. the two forces are equal, or balanced, neither the table nor the book moves up or down.

Explanation:

Tome, the other options don’t make no sense

Answer:

75603.86473 K

Explanation:

Given that:

The 1st excited electronic energy level of He atom = 3.13 × 10⁻¹⁸  J

The objective of this question is to estimate the temperature at which the ratio of the population will be 5.0 between the first excited state to the ground state.

The formula for estimating the ratio of population in 1st excited state to the ground state can be computed as:

[tex]\dfrac{N_2}{N_1} = e ^{^{-\dfrac{(E_2-E_1)}{KT}}} = e ^{^{-\dfrac{(\Delta E)}{KT}}}[/tex]

From the above equation:

Δ E = energy difference =  3.13 × 10⁻¹⁸  J

k = Boltzmann constant = 1.38 × 10⁻²³  J/K

[tex]\dfrac{N_2}{N_1} = 0.5[/tex]

Thus:

[tex]0.05 =e^{^{ -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}[/tex]

[tex]In (0.05) = { -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}[/tex]

[tex]-3.00 = { -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}[/tex]

[tex]-3.00 = -226811.5942 \times \dfrac{1}{T}[/tex]

[tex]T = \dfrac{-226811.5942}{-3.00 }[/tex]

T = 75603.86473 K

Answer:

B) 1st C sp3 ; 2nd C sp3 ; O sp3

Explanation:

Both carbons in ethanol have an sp³ configuration of their orbitals, given that each carbon atom binds to four other atoms, as can be seen on the extended formula in the attachment.

In these carbons (1st and 2nd) one s orbital and three p orbitals are hybridized to form four hybrid orbitals sp³. These orbitals form four bonds and their bond angles are close to the tetrahedral value of 109.5º,as can be seen for methanol which also has an sp³ configuration.

The oxygen atom can also be described as having sp³ hybrid orbitals. Two of the four hybrid sp³ orbitals in oxygen are occupied by lone electron pairs, and two are used to form bonds with other atoms (in this case the oxygen is bonded to a carbon atom and a hydrogen atom).

Therefore, the three central atoms have an sp³ configuration.

Answer: B

Kinetic Energy is the energy possessed by the body due to "motion".

Answer:

B- motion

Explanation:

Correct on edge 2021

️️

Answer:  the cake rises as gas bubbles form in the cake

Explanation: Had a quizziz quiz on this

Answer: The cake rises as gas bubbles form in the baking cake.

Explanation: had a test, got it right.

Answer:

it is true bc i looked it up

Answer:

The correct answer is 4.84

Explanation:

We use the Henderson Hasselbach's equation to calculate the pH of a buffer solution:

pH = pKa = log ( [conjugate base]/[weak acid])

In this case:

conjugate base: acetate ⇒ [conjugate base] =  [acetate] = 0.0200 M

weak acid: acetic acid ⇒ [weak acid] =  [acetic acid] = 0,0200 M

pH = pKa + log ([acetate]/[acetic acid])= pKa + log (0.0200 M/0.0200 M)

When a strong base- such as NaOH- is added, the acid reacts with OH⁻ to form the conjugate base. So, the conjugate base is increased while the acid is decreased. Thus, in 1 liter of solution we have:

acetate = (0,0200 mol/L x 1 L) + (2.0 mmol x 1 mol/1000 mmol) = 0.022 mol

acetic acid= (0,0200 mol/L x 1 L) - (2.0 mmol x 1 mol/1000 mmol) = 0.018 mol

Finally, we calculate the pH:

pH = 4.75 + log (0.022 mol /0.018 mol )= 4.84

Buffer has been the solution that resists the change in the pH of the solution with the addition of acid or base. The pH of buffer with NaOH has been 4.84.

The pH has been the hydrogen ion concentration in the solution. The pH has been equivalent to pKa and can be given as:

[tex]\rm pka=log\dfrac{[base]}{[acid]}[/tex]

The base in the buffer has been the acetate, while acetic acid act as the acid.

The concentration of NaOH added to the solution has been given as:

[tex]\rm Molarity=\dfrac{moles}{volume}\\\\ NaOH=\dfrac{0.002\;mol}{1\;L}\\\\ NaOH=0.002\;M[/tex]

The addition of NaOH adds the concentration of base, and neutralization reduces the concentration of acid. Thus, the new pKa can be given as:

[tex]\rm pKa=log\dfrac{0.2+0.002}{0.2-0.002} \\pKa=log\dfrac{0.022}{0.018}[/tex]

The new pH of the solution has been the sum of the old and the new pKa value.

Thus, the pH of the new buffer has been given as:

[tex]\rm pH=4.75+log\dfrac{0.022}{0.018}\\ pH=4.84[/tex]

The pH of buffer with NaOH has been 4.84.

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Answer: d

Explanation:

On edg

A chemical reaction does not create or destroy matter, it simply moves electrons from one atom to another, but does not change the nucleus of the atoms. ... The total mass of the matter can change during a nuclear reaction, the mass loss can convert into energy, which is called the nuclear power.

Answer:

A. Chemical Energy --> Thermal Energy

D. Chemical Energy --> Electromagnetic Energy

Explanation:

I took the quiz!

Answer:

Answer:

Speeds up

Explanation:

Answer:

1. A. True

2. A. True

3. B. False

4. A. True

5. B. False

Explanation:

1. The particles are in constant motion. The collisions of the particles with the walls of the container are the cause of the pressure exerted by the gas. A. True. The pressure of an ideal gas is higher than the one that would exert a real gas.

2. The particles are assumed to exert no forces on each other; they are assumed neither to attract nor to repel each other. A. True. The intermolecular forces are negligible.

3. The particles are so small compared with the distances between them that the volume of the individual particles can be assumed to be about 1 mL. B. False. The volume of the gas particles is negligible.

4. The molecules in a real gas have finite volumes and do exert forces on each other, thus real gases do not conform to some of the assumptions of an ideal gas as stated by the kinetic molecular theory. A. True. We cannot apply ideal gas laws to real gases.

5. The average kinetic energy of a collection of gas particles is assumed to be inversely proportional to the Kelvin temperature of the gas. B. False. The average kinetic energy of a collection of gas particles is assumed to be directly proportional to the Kelvin temperature of the gas.

The given statement, "if the particles are in constant motion and there are collisions of the particles with the walls of the container, then they are the cause of the pressure exerted by the gas." is:

The given statement "The particles are assumed to exert no forces on each other; they are assumed neither to attract nor to repel each other" is:

The given statement, "The particles are so small compared with the distances between them that the volume of the individual particles can be assumed to be about 1 mL" is:

The given statement ,"The molecules in a real gas have finite volumes and do exert forces on each other, thus real gases do not conform to some of the assumptions of an ideal gas as stated by the kinetic molecular theory" is:

The given statement, "The average kinetic energy of a collection of gas particles is assumed to be inversely proportional to the Kelvin temperature of the gas" is:

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Answer:

The leftover is 15 g of oxygen rather than liquid hexane as the fuel limits the reaction.

Explanation:

Hello!

In this case, since the described combustion reaction is:

[tex]C_6H_{14}(l)+\frac{19}{2} O_2(g)\rightarrow 6CO_2(g)+7H_2O(g)[/tex]

Thus, since 5.2 g of hexane (86.2 g/mol) is reacted with 33.0 g of oxygen (32.0 g/mol) we can compute the mass of hexane that was actually consumed via stoichiometry with oxygen (1:19/2 mole ratio):

[tex]m_{C_6H_{14}}^{consumed \ by\ O_2}=33.0gO_2*\frac{1molO_2}{32.0gO_2}*\frac{1molC_6H_{14}}{\frac{19}{2}gO_2 } *\frac{86.2gC_6H_{14}}{1molC_6H_{14}} \\\\m_{C_6H_{14}}^{consumed \ by\ O_2}=9.36gC_6H_{14}[/tex]

It is proved then than the hexane won't have any leftover but oxygen does, as shown below:

[tex]m_{O_2}^{consumed \ by\ C_6H_{14}}=5.2gC_6H_{14}*\frac{1molC_6H_{14}}{86.2gC_6H_{14}} *\frac{\frac{19}{2}molO_2 }{1molC_6H_{14}} *\frac{32.0gO_2}{1molO_2} \\\\m_{O_2}^{consumed \ by\ C_6H_{14}}=18g[/tex]

It means the leftover of oxygen is:

[tex]m_{O_2}^{leftover}=33g-18g\\\\m_{O_2}^{leftover}=15g[/tex]

Regards!