What is the equation of the line that passes through the point (2,−4) and has a slope of 2?​

slope-intercept form: y = mx + c, where m is the gradient and c is the y-intercept!!!

x - 26y = 52

-26y = -x + 52

y = x/26 - 2

Answer:

damm thats really good

Step-by-step explanation:

Answer:

ooooooo me :)

Answer:

[tex] = 4(32) + (2) \\ = 128 + 2 \\ = 130[/tex]

HOPE THIS HELPS

Answer: The answer is 30 or B

.

Step-by-step explanation:

Answer: B. 30 ft

Step-by-step explanation: we know that 3 is corresponding to 15 and 6 to x. 3 was multiplied by 5 to get to 15, so the same must be done to 6 to get the value for x. 6 * 5 = 30.

Answer:

[tex]\dfrac{dy}{dx}=\dfrac{4y-2xy\ln y}{3y^3+x^2}[/tex]

Step-by-step explanation:

[tex]y^3+x^2\ln y=4x+2[/tex]

Diferenciando con respecto a [tex]x[/tex]

[tex]3y^2\dfrac{dy}{dx}+2x\ln y+\dfrac{x^2}{y}\dfrac{dy}{dx}=4\\\Rightarrow (3y^2+\dfrac{x^2}{y})\dfrac{dy}{dx}=4-2x\ln y\\\Rightarrow (\dfrac{3y^3+x^2}{y})\dfrac{dy}{dx}=4-2x\ln y\\\Rightarrow \dfrac{dy}{dx}=\dfrac{4y-2xy\ln y}{3y^3+x^2}[/tex]

La derivada de la función dada es [tex]\dfrac{4y-2xy\ln y}{3y^3+x^2}[/tex].

Answer: 23

Step-by-step explanation:

When p =1 and q=7

Substitute the numbers for the alphabets accordingly and answer the equation

Answer:

The name of line of reflection for the pair of figures is, line (r).

Step-by-step explanation:

Line of reflection : It is a line that divide a figure in two half similar or identical figures.

Or we can say that, a line of reflection is a line that divide a figure into two mirror images of the figure.

In mathematical terms we can say that, a line of reflection is a line where each point present in a shape appears at equal distance on the opposite side.

From this we conclude that,

The line 'r' represent the line of reflection.

The line 'q' represent the line of symmetry.

The line 'p' represent the line of asymmetry.

Hence, the name of line of reflection for the pair of figures is, line (r).

Answer:

24 years

Step-by-step explanation:

Total = start*(1 + interest rate / amount of times compounded per month)^(years*amount of compounds per year)

6000 = 3000*(1+0.03/4)^(4x)

6000 = 3000* ((403/400)^4)^x

2 = ((403/400)^4)^x

x = log base-((403/400)^4) of 2 = x

x = 23.19

rounding down 23 years (but you probably want a year over that to get at least 6000, so 24)

Answer:

b

c

Step-by-step explanation:

First question: x - 6 means there is a shift to the right.

Second Question: substitute the given values into the original equation for appropriate transformations.

Answer: 3 |x-4| + 2, because vertical stretch multiplies x, horizontal shifts are subtracted or added to x, and vertical shifts are added or subtracted to the entire function.

The movement of the curve in the graph is shifting of the curve in vertical or the horizontal direction.For the first function the graph horizontal shift of 6 units right and for the second function when it is  vertical stretch of 3, a horizontal shift to the right 4 units, and a vertical shift up 2 units the transformation function is,

[tex]g(x)=3|x-4|+2[/tex]

The equation of the graph given in the problem is,

[tex]f(x)=\sqrt{x} [/tex]

The movement of the curve in the graph is shifting of the curve in vertical or the horizontal direction.

          [tex]g(x)=\sqrt{x-6} [/tex]

There is no change with the constant value. Thus the graph will not move in vertical direction. The change in variable of a unit result in the graph shift in horizontal direction.

As it shift -6 thus graph horizontal shift of 6 units right.

[tex]f(x)=|x|[/tex]

Vertical stretch of 3 means multiply the function with unit 3.

[tex]g(x)=3|x|[/tex]

Horizontal shift to the right 4 units means the difference of 4 units in the variable,

[tex]g(x)=3|x-4|[/tex]

Vertical shifts up with 2 units means the addition of the constant 2.

[tex]g(x)=3|x-4|+2[/tex]

Hence, for the first function the graph horizontal shift of 6 units right and for the second function when it is  vertical stretch of 3, a horizontal shift to the right 4 units, and a vertical shift up 2 units the transformation function is,

[tex]g(x)=3|x-4|+2[/tex]

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Answer:

97.43cm³

Step-by-step explanation:

h = 22cm

d = 10cm

r = d/2

= 10/2

= 5

dh = 2(0.4)

= 0.8

dr = 0.05

V = πr²h

dV = d(πr²h)

Such that

πd(r²h)

= π[(r²dh + hd(r²)]

dV = π[(r²dh + 2rhdr]------(1)

When we put the values above in this equation 1 above:

dV = π[(5)²*0.8 + 2*5*22*0.05]

= π(25*0.8+11)

= π31cm³

Multiply the value of pi with 31cm³

= 97.43cm³

Step-by-step explanation:

the price charged for 100 students reflects the cost per student that applies to the order as a whole.

100 * 6 = $600, so the fixed cost is 750-600 = 150.

...

We can check this by substituting in the other equation.

Does 150*6 + 150 = 1050?

150*6=900

900+150 = 1050.

Yes, it does

...

We can express this relationship by the equation:

y = mx + b

where

y = total cost

m = $6 per student

x = number of students

b = fixed costs = 150

y = 6x + 150

The caterer’s fixed cost and the rate per student served is $6 and $150

This method is actually called method of elimination to solve a system of linear equations.

We make one specific variable's coefficients of equal magnitude so that we can subtract or add the equations and eliminate that variable to make it easy to get the value of the other variable which will then help in getting the value of the first variable (if working in dual variable system).

If we have equations:

[tex]a_1x + b_1y = c_1\\a_2x + b_2y = c_2[/tex]

then, if we want to eliminate variable x, then we have to multiply equation 1 with

[tex]-\dfrac{a_2}{a_1}[/tex]

which will make coefficient of x in first equation as

[tex]a_1 \times - \dfrac{a_2}{a_1} = -a_1[/tex]

Then adding both equation will eliminate the variable x.

Given;

Cost of 100 students= $750

Cost of 150 students= %1050

Let the fixed cost of caterer be x

and the cost per student be y

x+100y=750...(1)

x+150y=1050...(2)

solving the above equations;

50y=300

y=6

x=750-600=150

The fixed cost is $150, while the per-student cost is $6.

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[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: f(x)= {6}^{x} [/tex]

we need to find f'(2) = ??

[tex]\qquad \sf  \dashrightarrow \: f {}^{ \prime} (x) = \displaystyle \sf \lim_{h \to0} \: \: \dfrac{f(x + h) - f(x)}{h} [/tex]

[tex]\qquad \sf  \dashrightarrow \: f {}^{ \prime} (x) = \displaystyle \sf \lim_{h \to0} \: \: \dfrac{6 {}^{x + h} - 6 {}^{x} }{h} [/tex]

[tex]\qquad \sf  \dashrightarrow \: f {}^{ \prime} (x) = \displaystyle \sf \lim_{h \to0} \: \: \dfrac{6 {}^{x + h} - 6 {}^{x} }{h} [/tex]

[tex]\qquad \sf  \dashrightarrow \: f {}^{ \prime} (x) = \displaystyle \sf \lim_{h \to0} \: \: \dfrac{6 {}^{x }( 6 {}^{h} - 1)}{h} [/tex]

[tex]\qquad \sf  \dashrightarrow \: f {}^{ \prime} (x) =\: 6 {}^{x} \: log_{e}(6) [/tex]

Now, plug in 2 for x ~

[tex]\qquad \sf  \dashrightarrow \: f {}^{ \prime} (2) =\: 6 {}^{2} \sdot log_{e}(6) [/tex]

[tex]\qquad \sf  \dashrightarrow \: f {}^{ \prime} (2) =\: 36 \sdot (1.79)[/tex]

[tex]\qquad \sf  \dashrightarrow \: f {}^{ \prime} (2) =64.44[/tex]

Answer: 9/1

Step-by-step explanation:

Answer:

B 244

Step-by-step explanation:

You can split up the polygon into two separate rectangles, one smaller one on top and one bigger one below.

Area of smaller rectangle = 6 × (14-8)

                                          = 36

Area of bigger rectangle = 26 × 8

                                         = 208

Total area of polygon = 36 + 208

                                    = 244

Answer:

c

Step-by-step explanation:

Answer:

34 laps

Step-by-step explanation:

the specific answer is 33.3 but u have to round the whole number

Answer:

15% off $30

Step-by-step explanation:

Answer:

x=9

Step-by-step explanation:

subtract 22 from both sides, simplify 3x = 10x-63, subtract 10x from both sides of the equation, simplify -7x = -63, divide both sides of the equation by the same factor -7x/-7 = -63/-7, then simplify

The value of the variable 'x' is 9. Then the length of the side QR will be 49 units.

The polygonal shape of a triangle has a number of sides and three independent variables. Angles in the triangle add up to 180 °.

The ratio of the matching sides will remain constant if two triangles are comparable to one another.

The triangles ΔQPR and ΔQRS are congruent triangles. Then the corresponding sides will be equal. Then the equation is given as,

PQ = QR

3x + 22 = 10x - 41

Simplify the equation, then we have

10x - 41 = 3x + 22

10x - 3x = 22 + 41

7x = 63

x = 63 / 7

x = 9

The length of the side QR is given as,

QP = 10 (9) - 41

QP = 90 - 41

QP = 49

The value of the variable 'x' is 9. Then the length of the side QR will be 49 units.

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Selah needs to save 35.7% of her weekly pay she will need to save if she wants to sign her lease in 8 weeks.

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Starting from the bottom in 8 weeks Selah will earn $(8×650).

= $5200.

The cost of renting the property for 2 months is $(2×825).

= $1650.

And 25% of one month's rent as a security deposit is,

= (25/100)×825.

= $206.25.

So, The total amount she needs to sign is $(1650 + 206.25).

= $1856.25.

Therefore, The percentage of her weekly pay she will need to save is,

= (1856.25/5200)×100.

= 35.69% or 35.7%

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Answer:  the expression would be

6000-p over 24

Step-by-step explanation:since we have given that

amount that liam has=250

amount that he and his classmates had=p

student $p will split=24

Answer:

250-p/24

Step-by-step explanation:

Khan

The distance between the points where the points are given as (2.4, -5.4) and (9.2-5.4) is 6.8 units

The points are given as

(2.4, -5.4) and (9.2, -5.4)

The distance between the points is calculated as

d  = √(x2 - x1)^2 + (y2 - y1)^2

Substitute the known values in the above equation

So, we have

d  = √(9.2 - 2.4)^2 + (-5.4 + 5.4)^2

Evaluate the sum in the above equation

So, we have

d  = √(9.2 - 2.4)^2 + (0)^2

Evaluate the difference  in the above equation

So, we have

d  = √(6.8)^2 + (0)^2

Evaluate the exponents in the above equation

So, we have

d  = √46.24 + 0

Evaluate the sum in the above equation

So, we have

d  = √46.24

Evaluate the exponents in the above equation

So, we have

d  = 6.8

Hence, the distance between the points where the points are given as (2.4, -5.4) and (9.2-5.4) is 6.8 units

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Answer:

0

Step-by-step explanation:

Without solving anything, we can tell that the line that crosses these points is a horizontal line because both of the y-coordinates are the same. This tells us that the slope of the line is 0.

To prove this, we can find the slope of the line by plugging the two points,[tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex],  into the equation [tex]\frac{y_2-y_1}{x_2-x_1}[/tex].

[tex]\frac{y_2-y_1}{x_2-x_1}\\\frac{5-5}{-17-(-9)}\\= \frac{0}{-17+9)}\\= \frac{0}{-8}\\= 0[/tex]

Therefore, the slope of the line that passes through the points (-9,5) and (-17,5) is 0.

I hope this helps!

Answer:

She would need 42 cups of flour

Step-by-step explanation:

Answer:

  (-3/2, 0)

Step-by-step explanation:

You want the midpoint of line segment AB with end points A(-5, 5) and B(2, -5).

The midpoint of a line segment has coordinates that are the average of the end point coordinates.

  M = (A +B)/2

  M = ((-5, 5) +(2, -5))/2 = (-5+2, 5-5)/2 = (-3, 0)/2

  M = (-3/2, 0)

The midpoint of the line segment is (-3/2, 0).

Using trigonometric ratios we calculate the value of the variables as approximately x and y are 5.1 units and 3.1 units respectively .

Trigonometry is the branch of mathematics that is used for solving a right angled triangle if only one data is given.

Let us consider a triangle ABC right angled at B. BC is the base of the triangle and AC is the hypotenuse , therefore AB is the perpendicular.

The various trigonometric ratios used for solving a triangle are :

sin C = AB ÷ AC

cos C = BC ÷ AC

tan C = AB ÷ BC

Now in the given figure we can see that :

In ΔABC , using the trigonometric ratio of sin

sin ∠A = BC ÷ AB

or , sin 51° × AB = BC

or, BC = 10.102...

or, BC ≈ 10.1

Again in Δ BCD ,  using the trigonometric ratio of cos

cos ∠D = CD ÷ BD

or, CD ≈ 5.1

In ΔABC , using the trigonometric ratio of tan

tan ∠A = BC ÷ AC

or, tan 51° = 10.1 ÷ AC

or, AC = 8.178...

or, AC ≈ 8.2

Therefore the value of y is AC-DC = 8.2 - 5.1 = 3.1 units

The values of x and y are 5.1 units and 3.1 units respectively .

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Answer:

<AED = 65

Step-by-step explanation:

1. Find the value of "x"

Remember, verticle angles are congruent. A verticle angle is formed when two lines intersect, the verticle angles are the angles that are opposite from eachother.

This means that;

<AEB = <CED

Substitue int he values;

5x - 10 = 3x + 40

Inverse operations;

5x - 10 = 3x + 40

-3x         -3x

2x - 10 = 40

    +10     + 10

2x = 50

/2    /2

x = 25

2. Find the measure of <AEB

Subsitute in the value for "x" that was found;

<AEB = 5x - 10

5 (25) - 10

125 - 10

115

3. Find the measure of <AED

Use a linear pair, a linear pair is two angles whose sum is 180 degrees. If one can put two angles together, and they form a straight line, then it is a linear pair.

<AEB and <AED are make a linear pair because together they form line BD.

This means that;

<AEB + <AED = 180

Substitute in the values;

115 + <AED = 180

<AED = 65

Answer:

Step-by-step explanation:

Options:

A. AC≅AC, Reflexive Property of Congruence

B. ∠ACB≅∠CAD, Alternate Interior Angles Theorem

C. ∠BAC≅∠DCA, Alternate Interior Angles Theorem

D. △ABC≅△CDA, SAS Triangle Congruence Theorem

Answer:

A and B and C

theres another answer right here that explains why

Answer: 1 7/11

please mark as brainliest

Answer:

1 7/11

Step-by-step explanation: