Answer:
24
Step-by-step explanation:
That would be:
(3/8)(30)
---------------
(15/16)(1/2)
This can be reduced in various ways. First, divide that 30 by 15, obtaining:
6/8
-----------
1/32
Now invert the divisor (1/32) and multiply:
(6/8)(32/1)
This reduces to 6*4, or 24.
What is the part to part ratio for gender in a daycare of children in which 16 of them are male
Answer:
16:0
Step-by-step explanation:
6x – 2y = 10 2x + 3y = 51 Solving the first equation above for y gives: y = x – 5
Answer:
x =6y =13Step-by-step explanation:
This is the method I am familiar with.
I Hope It helps :)
[tex]METHOD- 1 : Elimination\\6x - 2y=10------(1)\\2x+3y =51------(2)\\Multiply -eq-(1)- by -the-coefficient-of-x-in-equation (2)\\Multiply-eq-(2) -by -the-coefficient-of-x-in-equation (1)\\6x - 2y=10------(1) *2\\2x+3y =51------(2)*6\\\\12x-4y=20 ------(3)\\12x+18y=306 ------(4)\\Subtract -eq- (4)- from- eq -(3)\\-22y =-286\\\frac{-22y}{-22} =\frac{-286}{-22} \\y =13\\[/tex]
[tex]Substitute- 13- for y -in-equation -(1)-or-(2)\\6x - 2y=10------(1)\\6x -2(13)=10\\6x -26=10\\6x =10+26\\6x =36\\\frac{6x}{6} =\frac{36}{6} \\x =6[/tex]
Answer:
Correct answers is
Step-by-step explanation:
1. 3
2. B
3. 6
4. (6,13)
which is a correct first step in solving the inequality-4(2x-1)>5-3x
Step-by-step explanation:
-8x + 4 > 5 - 3x
-8x + 3x > 5 - 4
-5x > 1
x > 1 / - 5
Grandmother bought enough cat food for her four cats to last for 12 days. On her way home she brought back two stray cats. If she gives each cat the same amount of food every day, how many days will the cat food last
Answer:
The number of days the cat food will last is 8 days.
Step-by-step explanation:
In this case, it it provided that Grandmother bought enough cat food for her four cats to last for 12 days.
Assume that each cat consumes x portions of food each day.
Then the four cats will consume, 4x portions of food each day.
Then in 12 days the amount of food consumed by the 4 cats will be:
Total amount of cat food = 12 × 4x
= 48x.
Now, it is provided that she on her way home she brought back two stray cats.
Then the six cats will consume, 6x portions of food each day.
Compute the number of days the cat food will last as follows:
[tex]\text{Number of days the cat food will last}=\frac{\text{Total amount of cat food}}{\text{Amount of food consumed each day}}[/tex]
[tex]=\frac{48x}{6x}\\\\=\frac{48}{6}\\\\=8[/tex]
Thus, the number of days the cat food will last is 8 days.
Please help!! Which of the following is equal to the rational expression when x ≠ 2 or -4? 5(x-2)/(x-2)(x+4)
Answer:
5 / (x+4) x ≠2 x≠-4
Step-by-step explanation:
5(x-2)/(x-2)(x+4)
The denominator cannot be zero so x ≠2 x≠-4
Cancel like terms in the numerator and denominator
5 / (x+4) x ≠2 x≠-4
1.82 /6 pls answer with rounding to the nearest cent plzzzz I'll mark the 1st answer brainlist
Answer:
.30
Step-by-step explanation:
the answer is .30333 (with the 3 repeating) and since 3 is less than 5 you leave the second number as is.
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 4 students' scores on the exam after completing the course: 12,7,13,11 Using these data, construct a 80% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Step 3 of 4 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Answer:
The 80% confidence interval for the average net change is (8.596, 12.904).
Critical value t=1.638.
Step-by-step explanation:
First, we calculate the mean and standard deviation of the sample:
[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{4}(12+7+13+11)\\\\\\M=\dfrac{43}{4}\\\\\\M=10.75\\\\\\s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2\\\\\\s=\dfrac{1}{3}((12-10.75)^2+(7-10.75)^2+(13-10.75)^2+(11-10.75)^2)\\\\\\s=\dfrac{20.75}{3}\\\\\\s=6.92\\\\\\[/tex]
We have to calculate a 80% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=10.75.
The sample size is N=4.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.63}{\sqrt{4}}=\dfrac{2.63}{2}=1.315[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=4-1=3[/tex]
The t-value for a 80% confidence interval and 3 degrees of freedom is t=1.638.
The margin of error (MOE) can be calculated as:
[tex]MOE=t\cdot s_M=1.638 \cdot 1.315=2.154[/tex]
Then, the lower and upper bounds of the confidence interval are:
[tex]LL=M-t \cdot s_M = 10.75-2.154=8.596\\\\UL=M+t \cdot s_M = 10.75+2.154=12.904[/tex]
The 80% confidence interval for the average net change is (8.596, 12.904).
30 pontos de graça
Quanto é 100X4=?
Answer:
me marca como melhor resposta ☺️❤️
Step-by-step explanation:
.....
Answer:
400
brigadaaaaaaaaaaaaaa
during a basketball practice, mai attemoted 40 free throws and was successful on 25% of them how many successful free throws did she make?
Answer:
10 successful throws
Step-by-step explanation:
40 free throws
25% (25)
40 x 0.25 = 10
Suppose that y = 5 x plus 4 and it is required that y be within 0.005 units of 8. For what values of x will this be true?
Answer:
so we have an inequality for y -
7.995<y<8.005
Then now we need in inequality for x
(y-4)/5 = x
so that means that so if we have (7.995-4)/5 we get 3.995/5 = 7.99
so we have our first 7.99<x<b
Now we solve for b
So that means that 5.005/5 = 1.001
since we are changing it we switch our signs
from 7.99<x<1.001
we do 7.99>x>1.001
therefore
1.001<x<7.99
Answer:
0.795 [tex]\leq[/tex] y [tex]\leq[/tex] 0.805
Step-by-step explanation:
8 = 5x + 4
5x = 4
x = 4/5 or 0.800
therefore 0.800 + .005 and 0.800 - .005 =
0.795 [tex]\leq[/tex] y [tex]\leq[/tex] 0.805
A company produces product with a mean weight of 10 and a standard deviation of 0.200. A new process supposedly will produce products with the same mean and a smaller standard deviation. A sample of 20 products produced by the new method has a sample standard deviation of 0.126. At a significance level of 10%, is it appropriate to conclude that the new process is less variable than the old?
Answer:
[tex]F=\frac{s^2_1}{s^2_2}=\frac{0.2^2}{0.126^2}=2.520[/tex]
Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have [tex]n_1 -1 =10-1=9[/tex] and for the denominator we have [tex]n_2 -1 =20-1=19[/tex] and the F statistic have 9 degrees of freedom for the numerator and 19 for the denominator. And the P value is given by:
Now we can calculate the p value with this probability:
[tex]p_v =P(F_{9,19}>2.520)=0.043[/tex]
Using a significance level of 5% we see that the p value is lower than this value and we have enough evidence to reject the null hypothesis and we can conclude that the variation for the new process is lower than the new one.
Step-by-step explanation:
Information given
[tex]n_1 = 10 [/tex] represent the sampe size old
[tex]n_2 =20[/tex] represent the sample size new
[tex]s_1 = 0.2[/tex] represent the sample deviation for old
[tex]s_2 = 0.126[/tex] represent the sample deviation for new
The statistic is given by:
[tex]F=\frac{s^2_1}{s^2_2}[/tex]
Hypothesis to test
We want to test if the new process is less variable than the old, so the system of hypothesis are:
H0: [tex] \sigma^2_1 \leq \sigma^2_2[/tex]
H1: [tex] \sigma^2_1 >\sigma^2_2[/tex]
The statistic is given by:
[tex]F=\frac{s^2_1}{s^2_2}=\frac{0.2^2}{0.126^2}=2.520[/tex]
Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have [tex]n_1 -1 =10-1=9[/tex] and for the denominator we have [tex]n_2 -1 =20-1=19[/tex] and the F statistic have 9 degrees of freedom for the numerator and 19 for the denominator. And the P value is given by:
Now we can calculate the p value with this probability:
[tex]p_v =P(F_{9,19}>2.520)=0.043[/tex]
Using a significance level of 5% we see that the p value is lower than this value and we have enough evidence to reject the null hypothesis and we can conclude that the variation for the new process is lower than the new one.
Of the mathematics degrees awarded in recent years, 76% were bachelor’s degrees, 21% were master’s degrees and the remaining 3% were doctorates. Moreover, women earned 52% of bachelors, 40% of masters and 22% of doctorates. What is the probability that a randomly chosen mathematics degree was a master's degree given that it was awarded to a woman? Give your answer to 4 decimal places.
Answer:
0.1729 = 17.29% probability that a randomly chosen mathematics degree was a master's degree given that it was awarded to a woman
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
[tex]P(B|A) = \frac{P(B)*P(A|B)}{P(A)}[/tex]
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Given to a woman.
Event B: Masters degree.
21% were master’s degrees
This means that [tex]P(B) = 0.21[/tex]
Women earned 40% of masters
This means that [tex]P(A|B) = 0.4[/tex]
Probability of the degree being given to a women:
52% of 76%, 40% of 21% and 22% of 3%. So
[tex]P(A) = 0.52*0.76 + 0.4*0.21 + 0.22*0.03 = 0.4858[/tex]
What is the probability that a randomly chosen mathematics degree was a master's degree given that it was awarded to a woman?
[tex]P(B|A) = \frac{0.21*0.4}{0.4858} = 0.1729[/tex]
0.1729 = 17.29% probability that a randomly chosen mathematics degree was a master's degree given that it was awarded to a woman
What are the factors of this quadratic function?
Answer:
A. x-1 and x-5
Step-by-step explanation:
zeros are 1 and 5
so the factors are:
x-1 and x-5
Option A is correct
If your answer is in decimal form, round to 2 decimal places. For example, if your answer is .412, enter it into the fill-in-the-blank as .41, or if your answer is 1.415, enter it into the fill-in-the-blank as 1.42. If there are no decimals in your answer, you will simply enter the number; so if your answer is 2, enter 2 with no decimals. Do not enter any extra spaces, do not enter commas or $ or % symbols.
Answer:
If there is no decimal just put number and if the number is higher than 5 you round up example 1.46 you would put 1.5
Step-by-step explanation:
HOPE IT HELPS
find the area enclosed by the curve y^2=x^2-x^4
Answer: 4/3
Step-by-step explanation:
As you know this graph is a lemniscate
[tex]4\int\limits^1_0 {x\sqrt{1-x^{2} } \, dx =\frac{4}{3} =1.33$[/tex]
I WILL GIVE BRAINLIEST ANSWER ASAP
Answer: B
Step-by-step explanation:
For this problem, to solve for x, you want to move all like terms to one side.
[tex]\frac{1}{4}x-\frac{1}{2}x=\frac{7}{8} +\frac{1}{8}[/tex]
Now that you have moved like terms to one side, you can directly add and subtract to combine like terms.
[tex]-\frac{1}{4} x=1[/tex]
x=-4
Answer:
[tex]x = - 4[/tex]
Second answer is correct
Step-by-step explanation:
[tex] \frac{1}{4} x - \frac{1}{8} = \frac{7}{8} + \frac{1}{2} x \\ \frac{1}{4} x - \frac{1}{2} x = \frac{1}{8} + \frac{7}{8} \\ \frac{1x - 2x}{4} = \frac{8}{8} \\ - \frac{1}{4} x = 1 \\ - 1x = 1 \times 4 \\ - 1x = 4 \\ x = - 4[/tex]
hope this helps you
If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's rule to compute the limit of the sequence given by
bn=(n)^(5.6/n).
Answer:
Step-by-step explanation:
If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's rule to compute the limit of the sequence given by
bn=(n)^(5.6/n).
a)
[tex]L = \lim_{n \to \infty} b_n \\\\\\L= \lim_{n \to \infty} n^{\frac{5.6}{n} }[/tex]
Log on both sides
[tex]In (L) = \lim_{n \to \infty} In (n)^{\frac{5.6}{n} }\\\\= \lim_{n \to \infty} \frac{5.6}{n} In(n)[/tex]
[tex]=5.6 \lim_{n \to \infty} \frac{d}{dn} In(n)/\frac{d}{dn} (n)\\\\=5.6 \lim_{n \to \infty} \frac{1}{n} /1 \\\\=5.6 \lim_{n \to \infty} \frac{1}{n} \\\\=5.6 \times 0\\\\In(L) =0\\\\L=e^0\\\\L=1[/tex]
[tex]\therefore \lim_{n \to \infty} (n)^{\frac{5.6}{n} =1[/tex]
The limit value of given sequece is 1.
To understand more, check below explanation.
Limit of function:The given sequence is,
[tex]b_{n}=n^{5.6/n}[/tex]
We have to find limit of above sequence.
[tex]L=\lim_{n \to \infty} b_n \\\\L=\lim_{n \to \infty}n^{5.6/n} \\\\ln(L)=\lim_{n \to \infty}\frac{5.6}{n}ln(n) \\\\ln(L)=5.6\lim_{n \to \infty}\frac{ln(n)}{n} \\\\ln(L)=5.6\lim_{n \to \infty}\frac{1/n}{1} \\\\ln(L)=5.6*0=0\\\\L=e^{0}=1[/tex]
Therefore, the limit value of given sequece is 1.
Learn more about the limit of function here:
https://brainly.com/question/2166212
What is the measure of
55°
The sum or measures of interior angle in a triangle is 180°.
Angle A, 35° + Angle C, 90° =125°
Angle B= 180°-125°=55°[angle B]
The diameter of a circle is 5 ft. Find its area to the nearest tenth.
Answer:
A = 19.6 ft²
Step-by-step explanation:
A = πr² Use this equation to find the area of the circle
A = π(2.5)² Multiply
A = π(6.25) Multiply
A = 19.6 ft²
1. If the ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and
the sum of the ages of all 3 is 147 years, what is the age difference between oldest the
youngest?
Answer:
37 years difference.
Step-by-step explanation:
K = Kissi
k = Age of Kissi
E = Esinam
e = Age of Esinam
L = Lariba
l = Age of Lariba
k + e + l = 147
K : E
3 : 5 → (×3) → 12 : 15
E : L
3 : 5 → (×5) → 15 : 25
K : E : L
12 : 15 : 25
12 + 15 + 25 = 52
147/52 = 2.8269...
K is the young since out of the three part ratio, 12 is the smallest and likewise, L is the oldest.
k = 12 × 2.8269... = 33.923... → 34 y/o
e = 15 × 2.8269... = 42.40... → 42 y/o
l = 25 × 2.8269... = 70.673... → 71 y/o
∴ The difference between the youngest and oldest is:
71 - 34 = 37
Jana ran 7 days last week. She ran the same number of miles every day, and she ran 28 miles in all. What is Janas rate?
Answer:
Janas rate is of 4 miles per day.
Step-by-step explanation:
Her rate is the number of miles she ran per day.
We can solve this using a rule of three.
In 7 days, she ran 28 miles. How many miles she ran a day, that is, in one day?
1 day - x miles
7 days - 28 miles
[tex]7x = 28[/tex]
[tex]x = \frac{28}{7}[/tex]
[tex]x = 4[/tex]
Janas rate is of 4 miles per day.
Select all of the following statements that are true:
A. Random samples only generate unbiased estimates of long-run proportions, not long-run means.
B. You shouldnt take a random sample of more than 5% of the population size.
C. There is no way that a random sample of 100 people can be representative of all adults living in the United States.
D. If this question is voted out, the alternate option is "larger samples are always better than smaller samples, regardless of how the sample was collected."
E. Nonrandom samples are always poor representations of the population
Answer:
B. You shouldnt take a random sample of more than 5% of the population size.
Step-by-step explanation:
B. You shouldnt take a random sample of more than 5% of the population size. This is True, so as to avoid the research analysis to be more complex to interpret and analyzed
However, the following are not true statements:
A. Random samples only generate unbiased estimates of long-run proportions, not long-run means. This is False, as there may be sampling error, when picking the sample, which will lead to bias estimates in the long run proportions
C. There is no way that a random sample of 100 people can be representative of all adults living in the United States. This is False, as using the right factors such as gender, age, income, etc, in selecting the sample, 100 people is enough to use as sample of adults living in the United States
D. If this question is voted out, the alternate option is "larger samples are always better than smaller samples, regardless of how the sample was collected." This is False, larger samples are not always better than smaller samples. In fact, they are often difficult to analyze and interpret.
E. Nonrandom samples are always poor representations of the population: This is False, depending on the expected outcome of the research study. Some research studies required the research to use Nonrandom samples to reach verifiable conclusion.
what is -10 3/10,000 as a decimal number
Answer: 0.0003
Step-by-step explanation: Solution for fraction 3/10000 to decimal conversion
In the given, we want to convert 3 / 10000 to decimal form, we can compute this by dividing numerator 3 by denominator 10000
3/10000 = 0.0003
Hope this helps ❤4x-2 im confused because i havent done one like this in ages
Answer:
2
Step-by-step explanation:
1. Divide by four
2. two of the fours will cancel out leaving you to divide 4 by - 2 which is 2
2x + 3=-7?what is this even mean
Answer:
2 times some thing and plus 3 equals -7
Step-by-step explanation:
x = -5
Fuel Efficiency of Cars and Trucks Since 1975 the average fuel efficiency of U.S. cars and light trucks (SUVs) has increased from 13.5 to 25.8 mpg, an increase of over 90%! A random sample of 40 cars from a large community got a mean mileage of 28.1 mpg per vehicle. The population standard deviation is 4.7 mpg. Estimate the true mean gas mileage with 95% confidence.
Answer:
[tex]28.1-1.96\frac{4.7}{\sqrt{40}}=26.64[/tex]
[tex]28.1+ 1.96\frac{4.7}{\sqrt{40}}=29.56[/tex]
We are confident at 95% of confidence that the true mean for the mpg is between 26.64 and 29.56. And since the lower limit from the confidence interval is highert than 25.8 then we can conclude that we have a significant increase from 1975
Step-by-step explanation:
Information given
[tex]\bar X= 28.1[/tex] represent the sample mean
[tex]\mu[/tex] population mean
[tex]\sigma =4.7[/tex] represent the population standard deviation
n=40 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex] (1)
The Confidence level is is 0.95 or 95%, the significance would be [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and we can calculate the critical value using the normal standard distribution and we got [tex]z_{\alpha/2}=1.96[/tex]
And replacing we got:
[tex]28.1-1.96\frac{4.7}{\sqrt{40}}=26.64[/tex]
[tex]28.1+ 1.96\frac{4.7}{\sqrt{40}}=29.56[/tex]
We are confident at 95% of confidence that the true mean for the mpg is between 26.64 and 29.56. And since the lower limit from the confidence interval is highert than 25.8 then we can conclude that we have a significant increase from 1975
1.solve for x 3x - 2 = 3 - 4x
Answer:
[tex]x=\frac{5}{7}[/tex]
Step-by-step explanation:
[tex]3x - 2 = 3 - 4x[/tex]
Add [tex]2[/tex] and [tex]4x[/tex] on both sides of the equation.
[tex]3x - 2 +2+4x= 3 - 4x+2+4x[/tex]
[tex]3x+4x=-4x+5+4x[/tex]
[tex]7x=5[/tex]
Divide [tex]7[/tex] on both sides of the equation.
[tex]\frac{7x}{7}=\frac{5}{7}[/tex]
[tex]x=\frac{5}{7}[/tex]
Please answer this correctly
Answer:
20 total
Shelves 3 shelves /20 total=0.15=15%
Signs 2/20=0.10=10%
Benches 6/20=0.30=30%
Tablet Holders 9/20=0.45=45%
Step-by-step explanation:
Answer:
Shelves: 15%
Signs: 10%
Benches: 30%
Tablet Holders: 45%
Step-by-step explanation:
Shelves: [tex]\frac{3}{3+2+6+9} =\frac{3}{20} =\frac{15}{100} =[/tex] 15%
Signs: [tex]\frac{2}{3+2+6+9} =\frac{2}{20} =\frac{10}{100} =[/tex] 10%
Benches: [tex]\frac{6}{3+2+6+9} =\frac{6}{20} =\frac{30}{100}=[/tex] 30%
Tablet Holders: [tex]\frac{9}{3+2+6+9} =\frac{9}{20} =\frac{45}{100} =[/tex] 45%
An item has a listed price of 90$. If the sales tax rate is 6% how much is the sales tax (in dollars)?
Answer:
five dollars and forty cents
5.40$
Step-by-step explanation:
90+6%= 95.40
16. Model with Math What must be the sum of
the two remaining numbers, x and y? Write an
equation to show how to find this sum.
Answer:
The sum of the two remaining numbers, x and y = 60
Question:
The question isn't clear enough as some information have been omitted. Let's consider the following:
Model with Math. The average of six numbers is 18. If the average of four numbers is 12. What must be the sum of the two remaining numbers, x and y?
Write an equation to show how to find this sum.
Step-by-step explanation:
Mathematical models are applied to represent things in the real world in order to solve problems.
The formula we would use to solve this problem is an example of a mathematical model.
Types of mathematical model we can use include equations and graphs.
Using equations:
Average of six numbers = 18
Average of four of the numbers = 12
Total sum of the four numbers = 4×12 = 48
the two unknown numbers are x and y
Average of six numbers = (Sum of all 6 numbers)/6
=(Total sum of four numbers + x + y)/6
(48 + x + y)/6 = 18
The equation that shows how to find the sum:
(1/6)(48 + x + y) = 18
48 + x + y = 18×6
48 + x + y = 108
x + y = 108-48
x+y = 60
The sum of the two remaining numbers, x and y = 60