What is the relationship between elastic collision and 1:1 ratio?

Answers

Answer 1

An elastic collision is an come across between two bodies wherein the overall kinetic electricity of the two bodies stays the same.

In a super, perfectly elastic collision, there's no internet conversion of kinetic strength into other kinds inclusive of heat, noise, or capacity strength.  An elastic collision is a collision wherein there is no internet loss in kinetic strength within the gadget due to the collision. each momentum and kinetic energy are conserved portions in elastic collisions.

An elastic collision is a collision wherein there is no internet loss in kinetic electricity in the gadget because of the collision.  In the elastic collision, in which the kinetic energy is conserved, the kinetic electricity in an inelastic collision isn't always conserved. In an inelastic collision, the kinetic energy among the colliding bodies is exceptional at the start and the quit of the collision.

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Related Questions

Velocity in x direction
Initial velocity in y direction

Answers

Answer: Vx= 86.6 m/s & Vy= 50 m/s

Explanation:

Vx= 100*cos30° = 86.6 m/s

Vy= 100*sin30° = 50 m/s

A: In a second contest, the three displacements given are 90.9 m , 30.0 ∘ west of north; 15.5 m straight north; and 80.9 m , 45.0 ∘ south of east. What magnitude does the winner calculate for the displacement to find the keys to the Porsche?

B: What direction does the winner calculate for the displacement to find the keys to the Porsche?

Answers

A. Magnitude that the winner calculates for the displacement to find the keys to the Porsche is 38.83m.

B. The direction that the winner calculates for the displacement to find the key to the Porsche is 72.38° East of North.

When a particle moves from position A to point B, its displacement cannot be expressed using scalars. Always represented as a vector.

If an object's beginning and final positions are the same, its displacement is zero. That is, if a person begins a voyage at one location, walks some distance, and then returns to that location, his mobility will be zero.

The distance to the item will be 0 in this situation. Furthermore, there is no direction of zero displacements.

Given,

S1 = 90.9m, 30.0° west of north

S1 = 90.9 sin 30°( - î) + cos 30° j

∴ S1 = -45.45î + 78.72j

S2 = 15.5 m straight north

S2= 15.5 j

S3 = 80.9m, 45° south of east

S3 = 80.9 cos 45° î + 80.9 sin 45° j

S3 = 57.21 î - 57.21 j

Now,

Total displacement, S = S1 + S2 + S3

S = (-45.45î + 78.72j) + ( 15.5 j) + (57.21 î - 57.21 j)

  = ( -45.45 + 57.21) î + ( 78.72 + 15.5 -57.21) j

S  = 11.76 î + 37.01 j

|S| = 38.38m

tan α = y / x

tan α = 37.01 / 11.76

tan α = 3.15

α = 72.38°   from East of North

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A student drops a ball from the top of a 37-meter tall building. The ball leaves the student's hand with a zero speed. What is the speed of the ball at the moment just before it hits the ground?

Answers

Answer:

The ball accelerates because of gravity which is constant. So we can apply one of the equations of uniformly accelerated motion to solve the problem.

[tex]Vf^2=Vo^2+2aS\\[/tex] is compatible since [tex]S, Vo, a[/tex] are given enabling us to calculate [tex]Vf[/tex] .

[tex]Vf^2=(0m/s)^2+2*10m/s^2*37m\\Vf^2=20m/s^2*37m\\Vf^2=740m^2/s^2\\Vf=\sqrt{740} m/s\\ Vf=27.202941017 m/s\\[/tex]

Consider the two vectors, A= 19.5x + 13.5y and B=3.4x - 4.5y.
What is the magnitude of the vector A - B?
What is the angle of the vector A - b, measured counterclockwise in degrees from the positive x-axis?
What is the magnitude of the vector 3A + B?
What is the angle of the vector 3A + B, measured counterclockwise in degrees from the positive x-axis?

Answers

The calculated angle is 305° and if v=a,b is the position vector, then |v|=a²+b² is the calculated magnitude.

If v=a,b is the position vector, then |v|=a²+b² will give the magnitude. Depending on the application, the direction is equal to the angle made with the x-axis or the y-axis. The formula tan=(ba)=tan1 determines the direction of a position vector (ba), We may say that the vector must be inclined in the fourth quadrant in this case because the vector's x and y components are both positive.

Consequently, the angle must be greater than 270 degrees and less than 360 degrees.

Now, in order to determine the value, we can say that

tanθ=opposite side/adjacent side

=8.6/6.1

=tan⁻¹1.41

=54.65, which indicates that it is inclined at an angle above with the X axis in the fourth quadrant (360-54.65 = 305.6°).

Consequently, the proper response will be 305° degrees if the angle is measured counterclockwise.

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A man runs at 7.5 m s-1 due east across the deck of a ship which moves at 10.0 m s-' due
north. Determine the resultant velocity of the man (his velocity relative to the water).

Answers

The resultant velocity of the man is 12.5 m/s N of E.

Velocity of the man, Vm = 7.5 m/s

Velocity of Ship, Vs= 10 m/s

Since, velocity is a vector quantity, it will have both the magnitude and the direction.

So the magnitude for the resultant vector can be calculated by using the formula

[tex]\sqrt{x^{2} +y^{2} }[/tex] ; where x is the magnitude of the x-axis component and y is the magnitude of the y-axis component

i.e.

= [tex]\sqrt{Vm^{2} +Vs^{2} }[/tex]

= [tex]\sqrt{7.5^{2} + 10^{2} }[/tex]

= [tex]\sqrt{156.25}[/tex]

= 12.5 m/s

Also the direction can be calculated by Tan[tex]\alpha[/tex]

Tan[tex]\alpha[/tex] = [tex]\frac{10}{7.5}[/tex]

= Tan⁻(1.33)

= 58.9°

The angle between the resultant velocity and the horizontal axis is 58.9°.

Therefore the resultant velocity of the man relative to the water is 12.5 m/s towards NORTH-EAST direction.

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At the beginning of a 3.0-h plane trip, you are traveling due north at 192 km/h. At the end, you are traveling 250 km/h in the northwest direction (45° west of north).

Find the magnitude of the change in velocity.


Find the change in direction of your velocity. Enter the angle in degrees where negative indicates north of west and positive indicates south of west.


What is the magnitude of your average acceleration during the trip?

Answers

The magnitude of the change in velocity is determined as 408.94 km/h.

The change in direction of the velocity is 64.4⁰ north of west.

The magnitude of the average acceleration during the trip is 0.0105 m/s².

Magnitude of change in velocity

The magnitude of change in velocity is the resultant velocity of the plane.

v² = a² + b² - 2ab cosθ

where;

θ is the angle between the two velocities = 45 + 90 = 135

v² = (192²) + (250²) - 2(192 x 250) cos(135)

v² = 167,236

v = √167,236

v = 408.94 km/h

Vertical component of the velocity

vyi = 192 km/h

vy2 = 250 x sin(45) = 176.77 km/h

vy(total) = 192 km/h + 176.77 km/h = 368.77 km/h

Horizontal component of the velocity

vxi = 0

vx2 = - 250 km/h x cos(45) = -176.77 km/h

Change in direction of the velocity

θ = arc tan (Vy/Vx)

θ = arc tan(368.77 / -176.77)

θ = -64.4 ⁰

θ = 64.4⁰ north of west.

Acceleration of the trip

a = v/t

v = 408.94 km/h = 113.6 m/s

h = 3 h = 10,800 seconds

a = (113.6 m/s) / ( 10,800 s)

a = 0.0105 m/s²

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.Which term is described as a shelf of undersea land reaching a depth of about 200 meters (656 feet) and extending out from the shoreline?

A. guyots

B. deep-sea trenches

C. abyssal plains

D. continental shelf

Answers

Option D. continental shelf

Continental shelf is a part of a continent that is submerged under an area of ​​relatively shallow water known as a shelf sea.

It is given in the question, that the shelf of undersea land reaches 200 meters and it also extends out from the shoreline. This condition is only possible when a structure is submerged, and such submerged region can only be called as continental shelf.

On the other hand guyots is a underwater volcanic mountain and deep-sea trenches are the the long narrow lowerings in the ocean floor with the depth upto 6000 meters. And abyssal plains are the underwater ocean floors which cannot be found at the depth of 200 meters.

Therefore continental shelf is used to described as a shelf of undersea land reaching a depth of about 200 meters (656 feet) and extending out from the shoreline.

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How can you categorize the hazard in the hospitality industry?

Answers

Falls and Falling Objects.
Chemical Exposure.
Fire Hazards.
Electrical Hazards.
Repetitive Motion Injury.

What does an electromagnet in an electric motor do? I need help asap

Answers

Answer:the Correct Answer is

It transforms electrical energy into mechanical energy.

Explanation:

I got the answer right

If a container, with a fixed number of molecules inside, is
reduced in volume, less molecules will hit the sides of the
container per unit time, causing less pressure.
TRUE
FALSE
Check it

Answers

Answer:

FALSE

FALSE

FALSE

FALSE

If the length of the pendulum in pendulum clock increases by 0.1 % , then the error in time per day is
a) 86.4s
b) 4.32s
c) 43.2s
d) 8.64s

JEE Mains 2022​

Answers

When the length of the pendulum in pendulum clock increases by 0.1 % , then the error in time per day is c) 43.2s

How to calculate the time?

Let the pendulum = L

The time in a day will be: = 60 × 60 × 24

When the length is increased, the new length will be:

= L + 0.001L

New time period will be:

T =✓0.001s

Now, the error in a day will be:

= ✓0.001 × 60 × 60 × 24 - 1 × 60 × 60 × 24.

= 60 × 60 × 24(✓1.001 - 1)

= 43.2 seconds.

Therefore, the correct option is C.

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Find the force exerted by a pressure of 40N/m² acting over an area of 0.0025 cm ​

Answers

Answer:

[tex]1.0*10^{-5} N[/tex]

Explanation:

To answer this question we can use the formula: [tex]P=\frac{F}{A}[/tex]

Pressure (Pascals) = Force (Newtons) divided by Area (Square Meters)

We are given pressure and area in the question and are trying to find force so we can rearrange the equation to suit our needs by multiplying both sides by Area:

[tex]P(A) = \frac{F}{A} (A)\\ \\F =PA[/tex]

The next step is to ensure all given information is in the correct units. Because we are given pressure in the units [tex]N/m^{2}[/tex], we need to convert 0.0025[tex]cm^{2}[/tex] into [tex]m^{2}[/tex].

There are 10,000 [tex]cm^{2}[/tex] in 1 [tex]m^{2}[/tex], therefore to convert between them, we need to divide 0.0025 by 10,000.

[tex]0.0025/10000 = 0.00000025m^{2}[/tex]

OR [tex]2.5*10^{-7} m^{2}[/tex]

Now we just need to multiply them together to get force:

[tex]F=PA\\F=40*2.5*10^{-7}\\F=1.0*10^{-5} N[/tex]

Hope this helped!

How many grams are in 2 kg

Answers

There are 2000g in 2kg
There are 2000g in 2kg

Soil erosion is the wearing down of soil. This map provides data on the rate of soil erosion in the united states for a given year. What trend does the mad show? A. Soil erosion rates are high across the united states B. Soil erosion rates are low across the united states C. Siol erosion rates are uniform across the united states D. Soil erosion rates vary across the united states

Answers

Soil erosion is the wearing down of soil. The trend that the map shows is that soil erosion rates vary across the united states.

Hence, option (D) is correct.

What is Soil Erosion?

The removal of the top layer of soil by the action of wind, water, or human activities is known as soil erosion.Sometimes, soil erosion is good for the environment, especially in depositing fertile soil.Soil erosion is a geological action of moving soil.The areas with the highest agricultural activities have the highest rate of erosion.

As shown on the map, soil erosion vary across the United States.

Therefore, option (D) is correct.

Soil erosion is a slow method that happens while the impact of water or wind detaches and gets rid of soil particles, inflicting the soil to go to pot. Soil deterioration and low water excellent because of erosion and surface runoff have turn out to be intense troubles international.

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needdd helppppppppp

Answers

Answer:

divide 223 by 74 and you'll get your answer

7. A tennis ball thrown horizontally from the top of a water tower lands 20.0 m from the base of the tower. If the tennis ball is initially thrown at a velocity of 10.0 m/s: (a) how long does it take the tennis ball to reach the ground? (b) how high is the water tower? (b) how far away was the golfer from the hole when he hit the ball? A championship goffer uses a nine iron to chip a shot right into the cup. If the golf ball is launched at a velocity of 20m / s at an angle of 60 deg above the horizontal: (a) how long was the ball in the air? (c) what maximum height did the ball reach?​

Answers

Time taken by the tennis ball to reach the ground is 1.23 second, if the initial velocity is  10.0 m/s.

Velocity is the time price at which an object is transferring alongside a route, even as the pace is the fee and path of an item's motion. put some other manner, velocity is a scalar price, at the same time as velocity is a vector.

Speed is the speed at which something moves in a particular direction. for instance as the rate of a car traveling north on a motorway, or the rate a rocket travels after launching. In a scalar way, absolutely the value magnitude of the velocity vector is continually the velocity of the motion.

Speed is a vector expression of the displacement that an item or particle undergoes with appreciation to time. the standard unit of speed magnitude (also known as velocity ) is the meter consistent with 2nd (m/s).

The top of a water tower lands 20.0 m

initial velocity = 10.0 m/s

time required to reach the ground  =

S = ut + 1/2 at²

20 = 10t + 5t²

t = 1.23 second

The water is at a height of 20 m.

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A curve at a racetrack has a radius of 800 m and is banked at an angle of 7.0°. On a rainy day, the coefficient of friction between the cars' tires and the track is 0.50. What is the maximum speed at which a car could go around this curve without slipping?

Answers

The maximum speed at which a car could go around this curve without slipping is6.12m/s

To solve this it is necessary to take concepts related to Centripetal Force and Friction Force.

In the case of the centripetal force,

Fc = mv²/r      ....1

Where,

m=mass

v= velocity

r= Radius

In the case of the Force of Friction we have to,

F= [tex]\mu[/tex]mg      ......1.

Where,

[tex]\mu[/tex] = Friction Constant

m= mass

g= gravity

the centripetal equal to the friction force to stay on the road, in this way

mv²/r  = [tex]\mu[/tex]mg      

v² = mgr

v = √([tex]\mu[/tex]gr)

The coefficient of friction between the cars' tires and the track

 [tex]\mu[/tex] = 0.50

radius = 800m

g = 9.8 m/s²

using above values we get

v = [tex]\sqrt[]{800*9.8*0.5}[/tex]

V = 6.12m/s

The maximum speed at which a car could go around this curve without slipping is6.12m/s

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The Universal Gravitational constant
gives the mass and value a direction
converts the ratio of mass and distance to Newtons
gives the mass and distance a value
converts the ratio of mass and distance to kilograms

Answers

According to the given question, mBg- mAg = a(mA + mB)  is the equation that will be used to determine acceleration.  

The gravitational constant, represented by the capital G, is an empirical physical constant used in the calculation of gravitational effects in both Albert Einstein's theory of general relativity and Sir Isaac Newton's law of universal gravitation.

It is the proportionality constant in Newton's law that links the gravitational force between two bodies to the sum of their respective masses and the square root of their distance. It quantifies the relationship between the energy-momentum tensor and the spacetime geometry in the Einstein field equations.

The measured value of the constant is known to four significant digits with some certainty. Its value is approximately 6.674×10−11 m3⋅kg−1⋅s−2 in SI units.

Given in the qusetion

T -  WA = mAa         --------------1

WB - T = mBa            --------------2

We know that, WA = mAg and WB = mBg

T = mAa + WA

T = mAa + mAg           --------------3

Similarly, T = WB - mBa

T = mBg- mBa            --------------4

From equation 3 and 4

mAa + mAg = mBg- mBa

mAa + mBa = mBg- mAg

a(mA + mB) =  mBg- mAg

So, mBg- mAg = a(mA + mB)  is the equation that will be used to determine the acceleration.  

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Your question is incomplete. Please check the full content below.
The Universal Gravitational constant converts the ratio of mass and distance to Newton

gives the mass and distance a value

converts the ratio of mass and distance to kilograms

gives the mass and value a direction

The following equations are for two connected objects in the axis of motion

T-WA=mAa

WB-T=mBa

Which of the following equations would be used to determine the acceleration

T+mBg-mAg=(mA+mB)a

-T+mBg-mAg=(mA+mB)a

mBg-mAg=(mA+mB)a

mBg-mAg=mAa

What is measurement ?...​

Answers

Answer:

the size, length, or amount of something, as established by measuring.

the determination of the size or magnitude of something. By comparing that unknown quantity with some standard quantity of equal nature, known as measurement unit.

To pass a vehicle inspection, your Must be heard from 200 feet away.
Ohorn
Omuffler
windshield wipers
stereo

Answers

A I think sorry if I'm wrong

Polio is a disease that can cause paralysis. Doctors treated patients with casts and braces, but the work of Elizabeth Kenny led to the use of hot baths and exercise to treat polio victims. These patients had less incidence of paralysis. Kenny’s ideas and their acceptance were due to

Answers

Kenny’s ideas and their acceptance were due to open-mindedness because she led to the use of hot baths and exercise to treat polio victims.

Who was Elizabeth Kenny?

Elizabeth Kenny was a world-renowned nurse from Australia who develop a treatment for poliomyelitis, a very serious viral disease caused by poliovirus.

Elizabeth Kenny's ideas were controversial because they may be considered to be against conventional medical treatments.

In conclusion, Kenny’s ideas and their acceptance were due to open-mindedness because she led to the use of hot baths and exercise to treat polio victims.

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What become v if we use 2 risistors of 4w in parallel

Answers

the voltage across two resistors of 4w in parallel is the same.

Britney is on the starting line to run a track race. The distance around the track is 400m.
She starts the race and runs 400m around the track. She ends up in the same place where
she started. What distance did she cover? What was her displacement?

Answers

So she started from the finish line , she ran the track 400m so she only cover 400 m so your answer is 400m

Wil-E-Coyote drops a bowling ball off a cliff to try to catch the Roadrunner. The cliff is 128 m high. How long does it take the ball to hit the ground?

Answers

The time has taken the ball to hit the ground is (t)= 5.11 Seconds.

What is time?

The best example that would help us understand and know what time are the clock and the calendar. This clock gives us the exact hour, minutes and seconds. The calendar tells us the exact day, month and year.

How can we calculate time?

To calculate the time has taken the ball to hit the ground, we are using the formula,

S=ut+(1/2)gt²

Here we are given,

u= The initial velocity of the ball= 0 m/s

g= The acceleration due to gravity is= 9.8 m/s²

S= The height of the cliff = 128m.

We have to calculate the time has taken the ball to hit the ground = t

Now, we put the known values in the above equation we get,

S=ut+(1/2)gt²

Or, 128=0*t+(1/2)*9.8*t²

Or, t= √((2*128)/9.8)

Or, t=5.11 Seconds

Thus from the above calculation we can conclude that, the time has taken the ball to hit the ground is (t)= 5.11 Seconds

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What is the mass of a block accelerating at 2 m/s2 and pushed by a 9 N force?

Answers

Answer:

1 Newton (N) 1 kg*m/s²

Acceleration is measured in m/s², so combine your starting figures in such a way as to get m/s² (you have to divide away the kg):

9N/2kg = 4.5 m/s²

Explanation:

Convert 1.54 mg/cm³ to kg/dm³.

Answers

The converted unit 1.54 (mg / (cm^3)) is :

=0.00154 kg / (dm^3.)

What does unit conversion mean?

A unit conversion is used to express the same property in a distinct unit of measurement. Minutes can be used to measure time instead of hours, and feet, kilometres, or any other measure can be used to measure distance in place of miles.

Why is conversion of units required?

Showing someone the precise amount you have will be helpful. help with a mathematical problem, especially one involving chemistry where the solution can be found by following the units. Indicate the person's preferred system of measurement (i.e. metric or standard).

Briefing:

1.54 mg/ cm³ x 1g/1000mg

Continue likewise until you have achieved kg:

1.54 mg/ cm³ x 1g/1000mg x 1 kg/ 10000g

Now, work on cm³

1.54 mg/ cm³ x 1g/1000mg x 1 kg/ 1000g x 10³ cm/1dm³  = ?

= .00154 kg/dm³

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A cheetah can run at a maximum speed
106 km/h and a gazelle can run at a maxi-
mum speed of 75.6 km/h.
If both animals are running at full speed,
with the gazelle 63.4 m ahead, how long before
the cheetah catches its prey?
Answer in units of s.

Answers

Answer:

Explanation:

We find the difference in speeds between the 2 animals

106 - 75.6 = 29.4 km/h

then we convert it to m/s by dividing it with 3.6

29.4 / 3.6 = 8.2 m/s

distance divided by speed equals time

63.4 / 8.2 = 7.7 seconds

HELP URGENT- will give brainliest if correct

Answers

Answer:

6 km is the right answer

hope it helps you

Explanation:

please mark me as brainliest

006 (part 1 of 4) 3.0 points

Both car A and car B leave school at the same time, traveling in the same direction. Car A travels at a constant speed of 74 km/h, while car B travels at a constant speed of 93 km/h. How far is Car A from school 2.7 h later? Answer in units of km.

007 (part 2 of 4) 3.0 points

How far is car B from school 2.7 h later? Answer in units of km.

008 (part 3 of 4) 3.0 points

How long does it take car A to reach a gas station a distance 189 km from the school? Answer in units of h.

009 (part 4 of 4) 3.0 points

How long does it take car B to reach the gas station? Answer in units of h.​

Answers

1. The distance of car A from the school is 199.8 Km

2. The distance of car B from the school is 251.1 Km

3. The time taken for car A to reach the station is 2.55 hours

4. The time taken for car B to reach the station is 2.03 hours

What is speed?

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

1. How to determine the distance of car A from the schoolSpeed = 74 Km/hTime = 2.7 hoursDistance of car A =?

Speed = Distance / time

Cross multiply

Distance = speed × time

Distance of car A = 74 × 2.7

Distance of car A = 199.8 Km

2. How to determine the distance of car B from the schoolSpeed = 93 Km/hTime = 2.7 hoursDistance of car B =?

Speed = Distance / time

Cross multiply

Distance = speed × time

Distance of car B = 93 × 2.7

Distance of car B = 251.1 Km

3. How to determine the time taken for car A to reach the gas stationSpeed = 74 Km/hDistance = 189 KmTime for car A =?

Speed = distance / time

74 = 189 / time

Cross multiply

74 × time = 189

Divide both side by 14

Time = 189 / 74

Time for car A = 2.55 hours

4. How to determine the time taken for car B to reach the gas stationSpeed = 93 Km/hDistance = 189 KmDistance = 189 KmTime for car B =?

Speed = distance / time

93 = 189 / time

Cross multiply

93 × time = 189

Divide both side by 93

Time = 189 / 93

Time for car B = 2.03 hours

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If a ball is thrown upward at a speed of 10 m/s, and it reaches a height of 5.1 meters, how long
will it be in the air total?

Answers

Answer:

t = 10/9.81 = 1.02s

Explanation:

the ball will be up in the air for 1.02 seconds

Other Questions
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