Answer:
121
Step-by-step explanation:121 ! just got it right.
Answer:
D)
Step-by-step explanation:
on edge
Solve the system of equations.
2.5y+ 3x = 27
5x-2.5y = 5
What equation is the result of adding the two equations?
What is the solution to the system?
Answer:
The asnwer to the system of equation
x=4 y=6
Step-by-step explanation:
Answer: 1) 8x=32 2) (4,6)
Step-by-step explanation:
Hope this helps!
Mark me brainliest!
Pls and ty!
Find the value of x.
(a)
(10.7)" = 2
3x92x1 = 27*
(b)
Step-by-step explanation:
where is x in the question
Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.
sin(2sec^-1 u/10)
Answer:
[tex]\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0[/tex]
Step-by-step explanation:
We want to write the trignometric expression:
[tex]\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0[/tex]
As an algebraic equation.
First, we can focus on the inner expression. Let θ equal the expression:
[tex]\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)[/tex]
Take the secant of both sides:
[tex]\displaystyle \sec(\theta)=\frac{u}{10}[/tex]
Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:
[tex]\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}[/tex]
By substitutition:
[tex]\displaystyle= \sin(2\theta)[/tex]
Using an double-angle identity:
[tex]=2\sin(\theta)\cos(\theta)[/tex]
We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:
[tex]\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)[/tex]
Simplify. Therefore:
[tex]\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0[/tex]
how do i solve for the inequality, p=3.4?
Answer:
Step-by-step explanation:
This is already solved, and this would not be considered a inequality since it has only a equal sign.
PLEASE HELP ASAP!!! URGENT
Verify the identity. Sinx/1-cosx = cscx+cotx
Please use the answers shown in the image !! Thank you !!
Answer:
1) [tex]\frac{\sin x}{1-\cos x} = \csc x + \cot x[/tex]
2) [tex]\frac{\sin x}{1-\cos x} = \frac{1}{\sin x} + \frac{\cos x}{\sin x}[/tex]
3) [tex]\frac{\sin x}{1-\cos x} = \frac{1+\cos x}{\sin x}[/tex]
4) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x \cdot (1+\cos x)}{\sin^{2}x}[/tex]
5) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{1-\cos^{2}x}[/tex]
6) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{(1+\cos x)\cdot (1-\cos x)}[/tex]
7) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x}{1-\cos x}[/tex]
Step-by-step explanation:
Now we proceed to show all steps needed to demonstrate the trigonometric identity:
1) [tex]\frac{\sin x}{1-\cos x} = \csc x + \cot x[/tex] Given.
2) [tex]\frac{\sin x}{1-\cos x} = \frac{1}{\sin x} + \frac{\cos x}{\sin x}[/tex] Identities for cosecant and cotangent functions.
3) [tex]\frac{\sin x}{1-\cos x} = \frac{1+\cos x}{\sin x}[/tex] [tex]\frac{a}{b}+\frac{c}{b} = \frac{a+c}{b}[/tex]
4) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x \cdot (1+\cos x)}{\sin^{2}x}[/tex] Existence of additive inverse/Modulative property.
5) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{1-\cos^{2}x}[/tex] Fundamental trigonometric identity.
6) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{(1+\cos x)\cdot (1-\cos x)}[/tex] Factorization.
7) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x}{1-\cos x}[/tex] Existence of additive inverse/Modulative property/Result.
Question 20 A retired couple invested $6000 in bonds. At the end of one year, they received an interest payment of $402. What was the simple interest rate of the bonds?
Answer: interest rate was 6.7 %
Step-by-step explanation: 402/6000 = 0.067 = 6.7%
Only 3 more questions to go
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each division expression with the correct quotient. (These are the answers)
18x^(2)+39x+15 over 3x+5 -----> 6x+3
35x^(2)-5x-30 over 5x-5 -------> 7x+6
15x^(2)-44x+21 over 5x-3 ------> 3x-7
Answer:
18x^(2)+39x+15 over 3x+5 -----> 6x+3
35x^(2)-5x-30 over 5x-5 -------> 7x+6
15x^(2)-44x+21 over 5x-3 ------> 3x-7
Step-by-step explanation:
Plato Gang
What probability statement would you add to P(blue) = 1 10 to make a complete probability model for the event choosing a foam ball at random from the box?
Answer:
The chances of landing on blue are 1 in 4, or one fourth. The chances of landing on red are 1 in 4, or one fourth. This problem asked us to find some probabilities involving a spinner.
Find cos(B) in the triangle.
Choose 1 answer:
What is the image of the point (4,1) after a rotation of 270° counterclockwise about
the origin?
Will give brainliest
Answer:
1,-4
Step-by-step explanation:
formula for rotation of 270 is (x,y) to (y,-x)
The function f is defined by f(x) = 57. What is the value of f(3)?
O 15
O 25
O 53
O 125
Answer:
53
Step-by-step explanation:
Because
Find the mean for the following group of data item 1, 7, 5, 4, 9, 6, 7, 4
Answer:
5.375
Step-by-step explanation:
2. 48 degrees 17 x
(solve for x. round to the nearest tenth)
Answer:
67
Step-by-step explanation:
you divide the 48/17 yo get 67
Help please question in picture
Answer:
220
Step-by-step explanation:
Area of square=8*20=160
Area of triangle=(6*20)/2=60
160+60
Answer:
220 units²
I'm sure this is the answer!
A stationery store wants to estimate the mean retail value of greeting cards that it has in its inventory. A random sample of 15 greeting cards indicates an average value of $3.00 and a s of $0.40. The critical value for a 99% confidence interval is
Answer:
The critical value for a 99% confidence interval is T = 2.9768
Step-by-step explanation:
We have the standard deviation of the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 15 - 1 = 14
Critical value
Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.9768
The critical value for a 99% confidence interval is T = 2.9768
I just need help finding out the missing sides
GUYS HELP ME PLS. Tina is standing at the bottom of a hill. Matt is standing on the hill so that when Tina's line of sight is
perpendicular to her body, she is looking at Matt's shoes.
a. If Tina's eyes are 5 feet from the ground and 14.5 feet from Matt's shoes, what is the angle of elevation of
the hill to the nearest degree?
Answer:
71°
Step-by-step explanation:
The angle of elevation of the hill can be obtiaed using trigonometry :
Given
the opposite length = 14.5 feets
Adjacent = 5 feets
The angle of elevation vabnbe obtained using :
Tan θ = opposite / Adjacent
Where θ = angle of elevation
Tan θ = 14.5 / 5
Tan θ = 2.9
θ = tan^-1(2.9)
θ = 70.97 = 71°
The difference between the squares of two numbers is 35. Twice the square of
the first number increased by the square of the second number is 73. Find the
numbers.
Answer:
Los números son
7 y 8
Explicación paso a paso:
Si el número menor es "x" , el mayor es "x + 1"
entonces
( x + 1 )² - x² = 15
x² + 2x + 1 -x² = 15
2x + 1 = 15
2x = 15 - 1
2x = 14
x = 14/2
x = 7 ( número menor )
x + 1 = 7 + 1
x + 1 = 8 ( número mayor )
Help Broo i'm lost il give brainiest
Answer: here is your answer
Step-by-step explanation:
A= 16
B= -8
C= 6
D= -16
E= -4
Solve each equation by taking square roots : NEED THIS ASAP WILL GIVE BRAINLIEST
Answer:
1.) M=9,-9 2.) x=10,-10 3.) n=3,-3 4.) x=2,-2
Step-by-step explanation:
An introductory psychology class has 9 freshman males, 15 freshman females, 8 sophomore males, and 12 sophomore females. A random sample of n = 2 students is selected from the class. If the first student in the sample is a male, what is the probability that the second student will also be a male?
Answer
16/43
Step-by-step explanation:
17 Male + 27 female = 44 students
now n= 2 so first student was male so one male student was taken out of the equation so 16 male left. now left male students by remaining students so now total left students = 43
so, prob = remaining males/remaining students=16/43
(see picture) Find the measures of the numbered angles in each isosceles trapezoid.
find the least common multiple of 16,30,36 no links or file
9514 1404 393
Answer:
720
Step-by-step explanation:
The LCM of these numbers will have every factor that is part of these numbers.
16 = 2^4
30 = 2 × 3 × 5
36 = 2^2 × 3^2
So, the LCM will have factors of 2^4, 3^2, and 5:
LCM(16, 30, 36) = 2^4 × 3^2 × 5 = 720
720 = 16×45 = 30×24 = 36×20
The least common multiple is 720.
QUICK PLEASE I NEED HELP ON THIS
Answer:
Some
Step-by-step explanation:
the mean absolute deviation would intersect and would there for be some but at far enough apart to not be a lot
help aced and expert giving 20 points
Which fraction is equivalent to 2/-6
Answer:
-1/3
Step-by-step explanation:
xsquare-8x+15 please help me answer it thank you
Step-by-step explanation:
[tex] {x}^{2} - 8x + 15 = 0 \\ (x - 3)(x - 5) = 0 \\ x = 3 \: or \: x = 5[/tex]
POSSIBLE POINTS: 6
Solve each equation and match the solution.
e+8=31
t−25=54
32=y −21
14=b−12
x+8.95=21.95
n +21 =32
Answers,
1. 23
2. 79
3. 53
4. 26
5. 13
6. 11
How I did this,
What I did was subtract 8 from 31 to get ( e ) by itself.
This subject will get harder so I reccomend you focus on school and learn how to do this.
A racing car driver is investigating whether the type of fuel he uses in his car affects his overall speed. He uses three different types of fuel. The driver runs an experiment where he fills his car with each type of fuel 20 times, and each time records the time taken to drive one lap of a track. A one-way ANOVA test is conducted to test the null hypothesis that type of fuel is not a significant factor in determining speed. The result of the test is that the null hypothesis is not rejected.
The conclusion that follows from this test is that: __________
a. it has been proven that the type of fuel is a significant factor in determining speed
b. it cannot be ruled out that the type of fuel is an insignificant factor in determining speed
c. it has been proven that the type of fuel is an insignificant factor in determining speed
d. it has been proven that the type of fuel can sometimes be a significant factor in determining speed
Answer:
b. it cannot be ruled out that the type of fuel is an insignificant factor in determining speed.
Step-by-step explanation:
From the question :
Let the speed of each fuel be represented as ;
u1, u2, u3
The null hypothesis, H0 ;
H0 : u1 = u2 = u3
H0 is of the notion that fuel type is not a significant factor in determining speed
The alternative hypothesis, H1;
H1 : u1 ≠ u2 ≠ u3
The alternative is the opposite of the null, fuel type is a significant factor in determining speed
If after conducting the statistical test, the null hypothesis cannot be rejected ;
Then the conclusion will be ;
There is no significant evidence to conclude that the fuel type is a significant factor in determining speed ;
Hence, fuel fuel type remains an insignificant factor in determining speed.