Answer:
Waves interact with matter in several ways. The interactions occur when waves pass from one medium to another. The types of interactions are reflection, refraction, and diffraction. Each type of interaction is described in detail below.
i hang a 15 cm length spring in the classroom. the spring has a spring constant of 99 N/m. i the. attach a mass of 439 g to the spring. based on the information provided, use hookes law to predict the new length of the spring. (answer in cm)
Answer: 0.19 m
Explanation:
Spring constant (k) = 99 N/m
Length of spring hung = 15cm = 0.15m
Mass attached to the spring = 498g
The new length of spring :
F = kdx
F = mass (m) * acceleration due to gravity (g)
g = 9.8 m/s²
dx = L2 - L1 (Change in length)
m = 439 / 1000 = 0.439kg
L2 = new length
L1 = initial length
mg = k(L2 - L1)
0.439 * 9.8 = 99(L2 - 0.15)
4.3022 = 99(L2 - 0.15)
4.3022 = 99L2 - 14.85
4.3022 + 14.85 = 99L2
19.1522 = 99L2
L2 = 19.1522 / 99
L2 = 0.1934565
L2 = 0.19 m
New length of spring = 0.19 m
2. Because it can take one year to form just a few centimeters of new soil, 3 points
it is important to protect Earth's soil. *
True
False
Answer:
False.
Explanation:
What are the forces like in a collision?
Answer:
The forces are a convergent
Explanation:
According to O*NET, what are common skills needed by Emergency Medical Technicians? Check all that apply.
critical thinking
installation
technology design
active listening
service orientation
equipment maintenance
Career Explorations wasn't an options for subjects so I chose Physics. And the answer is 1, 4, and 5: critical thinking, active listening, and service orientation. It said on a website that equipment maintenance was an answer too but on the question on edg 2020 it said it wasn't
Answer:
Its just 1 4 an 5
Explanation:
i got it right
El sargento Conejero toma el sol en su colchoneta, de 2 m2 de superficie, flotando en el agua de la piscina (d = 1 g/cm3 ). Si observamos que ésta se hunde 2,7 cm, ¿cuál es el peso del sargento? (Desprecia el peso de la colchoneta).
Answer:
W = 529.2 N
Explanation:
We can solve this problem using the translational equilibrium equation, where the forces are the weight of the sergeant and the thrust of the water given by Archimedes' principle
B - W = 0
where the thrust is
B = ρ g V_liquid
The volume of the displaced liquid is
V = A h
we substitute
ρ g A h = W
We reduce the magnitudes to the SI system
h = 2.7 cm = 0.027 m
ρ = 1 g / cm3 = 1000 kg / m³
let's calculate
W = 1000 9.8 2 0.027
W = 529.2 N
In which application is a magnet used to store information?
A. The needle on a compass
B. A recycling-center separator
C. The clasp on a necklace
D. The disk in a computer hard drive
Answer:
d the disk in a computer hard drive
Explanation:
because hard drive use magnetic memory tostore giga- and terabytes of data in computer.
The disk in a computer hard drive is an application that uses magnets to store information.
What are magnets?Magnets are materials which are produce magnetic properties and make use of magnetic fields.
Magnets are used on various appliances such as speakers, microphones, computer hard disks, electromagnets, etc.
Hard disks make use of the magnetic properties of magnets to store information.
Therefore, the disk in a computer hard drive is an application that uses magnets to store information.
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Identify two factors that increase the electric force between objects
Answer: The distance between particles, and the amount of electric charge they carry.
Explanation:
Charles Coulomb wanted to figure out the strength of the force between two objects and these were the two most independent factors.
7. A 25 N block is lowered 1.2 m by a 20 N force.
a. Draw a free-body diagram of the forces acting on the block.
b. How much work does the force of gravity do on the box? Is this work positive or negative?
c. How much work does the applied force do on the box? Is this work positive or negative?
Answer:
this answer your question
The free-body diagram of the forces acting on the block is attached.
Work done by the force of gravity = 30 Joule (positive).
Work done by the applied force = 24 Joule (negative).
What is work done?A force must be applied in order for work to be completed, and there must also be motion or displacement in the force's direction.
The amount of force multiplied by the distance moved in the force's direction is known as the work done by a force acting on an item. Work has no direction and only magnitude. Work is a scalar quantity as a result.
Given parameters:
Weight of the block acting downwards; W = 25 N.
Force applied on the block in upward direction; F = 20 N.
Displacement of the block in downwards; s = 1.2 m.
So, work done by the force of gravity on the box W = F·s = Fscos0° = Fs = 25×1.2 Joule = = 30 Joule.
And, work done by the applied force the box W = F·s = Fscos180° = -Fs = -20×1.2 Joule = = - 24 Joule
Hence, the force of gravity do positive work of magnitude 30 joule on the box and the applied force do negative work of magnitude 24 Joule on the box.
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Through which gas in the table do sound waves travel at the slowest speed?
Air (dry)/Ammonia/Methane/Nitrous oxide
Speed of sound (m/s) 346/ 415/ 450/ 263
A. Ammonia
B. Nitrous oxide
C. Air
D. Methane
Answer: the answer would be methane if the problem is asking for the fastest
Explanation:
Methane (CH₄) is a chemical compound and a primary component of natural gas. The gas in the table through which sound waves travel at the slowest speed is D. Methane. According to the given speeds of sound in the table, methane has the lowest speed of sound at 263 m/s.
Methane is formed through various natural processes, including the decay of organic matter in anaerobic (oxygen-deprived) environments such as wetlands, landfills, and the digestive systems of animals.
The speed of sound in a gas depends on factors such as the density and elastic properties of the gas. The molecular composition and temperature of the gas can also affect the speed of sound. In this case, the properties of methane result in a slower speed of sound compared to the other gases mentioned.
Therefore, the gas in the table through which sound waves travel at the slowest speed is D. Methane. According to the given speeds of sound in the table, methane has the lowest speed of sound at 263 m/s.
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The action of large, massive sections of a glacier break off and falling into the ocean is called ____________.
Group of answer choices
an iceberg
an ice sheet
calving
How much thermal energy is
needed to change 3.00 x 102 g of ice at -30.0°C
to water vapor at 130.0°C?
Answer:
Qt = 940500 [J]
Explanation:
In order to solve this problem and understand it well, we must analyze that the ice melts or changes phase at a temperature of 0 [°c], then the water at a temperature of 100 [°C] evaporates or changes phase. That is, we have 5 different stages of water (initially in the form of ice), which are:
-) From -30 [°C] to 0 [°C] = Sensible change of temperature
-) At 0 [°C] = Latent heat of melting ice = 334 x 10³ [J/kg]
-) From 0 [°C] to 100 [°C] = Sensible change of temperature
-) At 100 [°C] = Latent heat of fusion for water = 2260 x 10³ [J/kg]
-) From 100 [°C] to 130 [°C] = Sensible change of temperature (superheating)
We can calculate the sensible heat of any process with the following expression:
[tex]Q=m*C_{p}*(T_{f}-T_{i})[/tex]
where:
Q = heat or thermal energy [J]
m = mass of the body or substance = 300 [g]
Cpw = specific heat of the water = 4180 [J/kg*°C]
Cpi = specific heat of the ice = 2090 [J/kg*°C]
Tfinal = final temperature of the process [°C]
Tinicial = initial temperature of the process [°C]
And for some latent heat process, we can calculate the thermal energy using the following expression:
[tex]Q_{lat}=m*Dh_{fus/eva}[/tex]
where:
Dhfus/eva = Fusion heat or latent heat [J/kg]
So, we need to calculate the fice processes.
[tex]Q_{1}=0.3*2090*(0-(-30))\\Q_{1}=18810 [J]\\Q_{2}=0.3*334*10^{3} \\Q_{2}=100200[J]\\Q_{3}=0.3*4180*(100-0)\\Q_{3}=125400[J]\\Q_{4}=0.3*2260*10^{3}\\Q_{4}=678000[J]\\Q_{5}=0.3*2010*(130-100)\\Q_{5}=18090[J][/tex]
And the final step is the sum of all the five heat processes.
[tex]Q_{t}=Q_{1}+Q_{2}+Q_{3}+Q_{4}+Q_{5}\\Q_{t}=18810+100200+125400+678000+18090\\Q_{t}=940500[J][/tex]
9)A 64 kg parent and a 16 kg child meet at the center of an ice rink. They place their hands together and push. (A) Is the
force experienced by the child more than, less than, or the same as the force experienced by the parent? (B) is the
acceleration of the child more than, less than, or the same as the acceleration of the parent? Explain. (C) If the
acceleration of the child is 2.5 m/s^2 in magnitude, what is the magnitude of the parent's acceleration?
Answer:
(A) The same
(B) More
(C) The magnitude of the parent's acceleration is 0.625 m/s²
Explanation:
The given parameters are;
The mass of the parent, m₁ = 64 kg
The mass of the child, m₂ = 16 kg
(A) By Newton's third law of motion, action and reaction are equal and opposite
Therefore, the action of the parent on the child is equal to the reaction of the child on the parent and vice versa
Therefore, the force experienced by the child is the same as the force experienced by the parent
(B) Newton's second law states that an objects acceleration is directly proportional to the applied force and inversely proportional to the mass of the object
Therefore, the parent and the child both experience the same force but the mass of the child is less than the mass of the parent and therefore, by Newton's second law, the acceleration of the child will be more than the acceleration of the parent for the same given force
(C) The acceleration of the child, a₂ = 2.5 m/s²
Let F₁ represent the force experienced by the parent, let F₂ represent the force experienced by the child and let a₁ represent the magnitude of the parent's acceleration
By Newton's third law, we have;
F₁ = F₂
Force, F = Mass, m × Acceleration, a
We can write, F = m × a
Therefore;
F₁ = m₁ × a₁ and F₂ = m₂ × a₂
∴ F₁ = F₂ gives;
m₁ × a₁ = m₂ × a₂
a₁ = (m₂ × a₂)/m₁ = (16 × 2.5)/64 = 0.625
∴ The magnitude of the parent's acceleration = a₁ = 0.625 m/s²
How many meters are in 45 centimeters?
Explanation:
100 CM = 1 m
45 CM = 45 / 100 = 0.45 m
hope it helps:)
Answer:
0.45 meters ar three in 45 centimeters
consequences and application of expansion in physics
Answer:
When solid material expands in response to an increase in temperature (thermal expansion), it can increase in length in a process known as linear expansion. for an example application of expansion and contraction. ... Strain, a material's response to stress, can cause it to deform.
When solid material expands in response to an increase in temperature (thermal expansion), it can increase in length in a process known as linear expansion.
What are Application in physics?Application of expansion and contraction. Strain, a material's response to stress, can cause it to deform. The study of matter, its nature, and qualities is the subject of physics, which also examines heat, mechanics, light, electricity, magnetism, the structure of atoms, and sound.
In the science of physics, fundamental questions about life are asked, and through observation and investigation, solutions are discovered.
The fundamental problems of life are addressed by physicists using just observational and investigative techniques.
Therefore, When solid material expands in response to an increase in temperature (thermal expansion), it can increase in length in a process known as linear expansion.
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A sailboat started its journey at 6:30am and reached the destination at 6:30pm. If the distance of the journey was 144 miles, what was the sailboats average speed?___mph
Answer:
The sailboats average speed was 13 mph.
Explanation:
To calculate the speed of the boat first calculate the total ammountof hours it took the boat to get to its destination. Then divide 144 by that number which comes out to 13.
The average speed of the sailboat is determined as 12 miles per hours.
What is average speed?
The average speed of an object in motion is obtained by dividing the total distance traveled by the object with the time spent in the entire journey.
v = total distance/total time
where;
total distance = 144 milestotal time = from 6:30am to 6:30pm = 12 hoursv = 144/12
v = 12 mph
Thus, the average speed of the sailboat is determined as 12 miles per hours.
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2. A 50.0 kg shell was fired from a cannon at earth's surface to a
maximum height of 400. m.
a. What is the potential energy at maximum height?
b. It then fell to a height of 100. m. What was the loss of PE as
it fell?
Answer: a) 196000 Joules
b) 147000 Joules
Explanation:
a. Potential energy is the energy possessed by an object by virtue of its position.
[tex]P.E=m\times g\times h[/tex]
m= mass of object = 50.0 kg
g = acceleration due to gravity = [tex]9.8ms^{-2} [/tex]
h = height of an object = 400 m
Putting in the values we get:
[tex] P.E=50kg\times 9.8ms^{-2}\times 400m=196000kgm^2s^{-2}=196000Joules[/tex] [tex](1kgm^2s^{-2}=1Joule )[/tex]
Thus the potential energy at maximum height is 196000Joules.
b. [tex] P.E=50kg\times 9.8ms^{-2}\times 100m=49000kgm^2s^{-2}=49000Joules[/tex] [tex](1kgm^2s^{-2}=1Joule )[/tex]
Thus loss in P.E = (196000Joules-49000Joules) = 147000 Joules
please answer this question
Answer:
11.a) Car B is faster than Car A. This is because Car B covers more distance in less time, whereas Car A covers less distance in more time. Now, as we know that distance is directly proportional and time is inversely proportional to speed. In Car B, a larger distance and less time and a smaller distance and more time in Car A, indicates that the speed of Car B is more than the speed of Car A.
b) Car B accelerates faster than Car A. We know that, the acceleration is directly proportional to the change in linear velocity and inversely proportional to time taken. Here, The overall journey of Car B is short, whereas for Car A, it's longer. Also, as previously mentioned that the final speeds of Car B is more than Car A [remembering that both Cars start from the origin(rest)]. Hence, the change of velocity in Car B is more than Car A. Hence so.
Gravitational force depends on __________ and __________.
a.
mass, distance
c.
distance, strength
b.
mass, strength
d.
strength, speed
Please select the best answer from the choices provided
A
B
C
D
Answer: pretty sure it’s A
Explanation:
Using the acceleration value you calculated in part A what is the final velocity of the box when immediately before it hits the bottom of the ramp.
3pts. Create and fill in a data table for all five of the known and unknown kinematics values.
2pts. Select and apply the correct kinematics equation based on the kinematics data you are trying to solve for and the data you know.
1pt. Solve
Answer:
final velocity= gt= 9.8t
where t is time taken by the box to strike ramp
You drive 20 meters forward and then 10 meters backwards in 30 seconds. What is your average speed?
Answer:
10
Explanation:
a.s = D÷T
= (20+10=30)30÷30
=10
1 m/s is my average speed.
What is average speed?Average speed is the total distance travelled by an object to the total time taken.
i.e.
Average speed = Total distance travelled /Total time taken
[tex]\overline{v}[/tex] = Δx/Δt
According to the question.
Total distance travelled by me = 20m +10m = 30m
Total time taken by me = 30 sec
By using the formula of average speed
[tex]\overline{v}[/tex] = Δx/Δt
= [tex]\frac{30m}{30s}[/tex]
=1 m/s
Hence,1 m/s is my average speed.
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Willing to give out Brainliest: 3.00 m^3 of water is at 20.0°C If you raise its temperature to 60.0°C, by how much will its volume expand ?
Answer:
The answer is below
Explanation:
Charlee's law states that the volume of a gas is directly proportion to the temperature of the gas at constant pressure. That is:
V = kT, where V = volume and T = temperature, k = constant. Therefore:
V / T = k
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
Given that: [tex]V_1=3\ m^3, T_1=20^oC=(20 + 273)K=293\ k,T_2=60^oC=(60 + 273)K=333\ k.\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{3}{293}=\frac{V_2}{333} \\\\V_2=\frac{3}{293}*333\\\\V_2=3.41\ m^3\\[/tex]
The new volume is 3.41 m³. That is it expands by 0.41 m³
Answer:
0.02484
Explanation:
Trust me bro
If you drop a watermelon and a penny off the roof of the school, which one
would hit the ground first?
Answer:
watermelon?
Explanation:
its heavier so the weight would make it drop faster
im not sure if this is a trick question so
Answer:
Watermelon because the weight of it is heavy and it would push itself on the ground
HELP PLS !!!!!!!!!!!!!!!!!!!!]
A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)
Answer:
0.25
Explanation:
According to newtons law of motion
\sum F_x = ma
F_f = ma
nR = ma
nmg = ma
ng = a
n = a/g
g is the acceleration due to gravity
Given
a = 2.42m/s²
g = 9.8m/s²
Substitute into the formula;
n = 2.42/9.8
n = 0.25
Hence the coefficient of kinetic friction is 0.25
Question.
what is a crystal?
A crystal or is a solid material whose constituents are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions
hope this helps
In an experiment, an object is heated.
The data from the experiment is shown.
The energy transferred to the object is 3.0 kJ.
The mass of the object is 2.0 kg.
The rise in temperature of the object is 10°C.
The specific heat capacity of the object is 150 J/(kg°C).
What is the thermal capacity of the object?
A 30J/°C
B 300 J/°C
C 3000J/°C D 9000 J/°C
Answer:
B) 300 J/°C
Explanation:
Q = 3kJ = 3000J
ΔT = 10°C
3000J/10°C = 300J/°C
To calculate heat capacity, use the formula: heat capacity = E / T, where E is the amount of heat energy supplied and T is the change in temperature.
E = 3kJ = 3000J
ΔT = 10°C
Heat capacity = E / T,
3000J/10°C = 300J/°C
What is heat capacity ?
"Heat capacity or thermal capacity is a physical property of matter, defined as the amount of heat to be supplied to an object to produce a unit change in its temperature." The SI unit of heat capacity is joule per kelvin. Heat capacity is an extensive property.
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a body is thrown vertically upward from the earth's surface and it took 8 seconds to return to its original position . find out the initial velocity with which it was thrown up
Answer:
The initial velocity with which the body was thrown up is 39.2 m/s
Explanation:
The given parameters for the body are;
The time it takes the body to return back to its initial position = 8 seconds
To answer the question, we make use of the kinematic equation of motion, v = u - g·t
Where
v = The final velocity of the body = 0 m/s at the maximum height
u = The initial velocity
g = The acceleration due to gravity = 9.8 m/s²
t = The time in which the body spends in the air
Therefore, at maximum height, we have;
v = 0 = u - g·t
u = g·t
t = u/g
From h = 1/2gt², which gives t = √(2·h/g), the time the body takes to maximum height = The time the body takes to return to its original position from maximum height.
Therefore, the total time in which the body is in the air = 2 × t = 2× u/g
∴
The total time in which the body is in the air = The time it takes the body to return back to its initial position after being thrown = 2 × t = 8 seconds
∴ 2 × t = 8 s = 2 × u/g
8 s = 2 × u/g
u = (8 s × g)/2
∴ u = (8 s × 9.8 m/s²)/2 = 39.2 m/s
The initial velocity with which the body was thrown up = u = 39.2 m/s.
Write a hypothesis about the use of an object’s physical characteristics to determine its density. Use the format "if . . . then . . . because . . .” and be sure to answer the lesson question "How can the density of an object be determined?” BE ORIGINAL AND SIMPLE
Answer:
If an object has a high density then the molicules making up that object are closly packed togeather. Because of this, objects with a higher density will have more mass than objects of the same size that have a lesser density.
Answer:
If an object has a high density then the molicules making up that object are closly packed togeather. Because of this, objects with a higher density will have more mass than objects of the same size that have a lesser density.
Explanation:
Why is more energy required to vaporise 1kg of water than to melt 1kg of ice?
(Please help, this is urgent)
Answer: The temperature change occurs from heat transfer if the ice melts and becomes liquid water. Similarly, energy is needed to vaporize a liquid, because the molecules in a liquid interact with each other via attractive forces.
Explanation:
Скільки тепла отримає цинкове тіло масою 2 кг, якщо воно підвищить свою температуру з 10 ° C до 60 ° C.
Answer:
39000 Дж теплової енергії поглинається тілом цинку.
Explanation:
З наведеного вище питання із запитання були отримані наступні дані:
Маса (М) = 2 кг
Початкова температура (T₁) = 10 ° C
Кінцева температура (T₂) = 60 ° C
Тепло (Q) =?
Далі ми перетворимо 2 кг у грами (g). Це можна отримати наступним чином:
1 кг = 1000 г.
Отже,
2 кг = 2 кг × 1000 г / 1 кг
2 кг = 2000 г.
Таким чином, 2 кг еквівалентно 2000 г.
Нарешті, ми визначимо тепло, що поглинається тілом цинку, як показано нижче:
Маса (М) = 2000 г.
Початкова температура (T₁) = 10 ° C
Кінцева температура (T₂) = 60 ° C
Питома теплоємність (С) цинку = 0,39 Дж / гºС
Тепло (Q) =?
Q = MC (T₂ - T₁)
Q = 2000 × 0,39 (60-10)
Q = 780 × 50
Q = 39000 Дж
Отже, 39000 Дж теплової енергії поглинається тілом цинку.
A railroad car undergoes an acceleration of 2.00 m/s2 when a net force of 40,000. N acts upon it. What is the mass of the railroad car?
Answer:
The mass of the railroad car is 20,000 kg
Explanation:
Mechanical Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = ma
Where:
a = acceleration of the object.
m = mass.
F = Net force
The railroad car undergoes an acceleration of [tex]a=2\ m/s^2[/tex] when a net force of F=40,000 N acts upon it.
It's required to find the mass of the railroad car, which can be done by solving the formula for m as follows:
[tex]\displaystyle m=\frac{F}{a}[/tex]
Substituting:
[tex]\displaystyle m=\frac{40,000}{2}=20,000[/tex]
The mass of the railroad car is 20,000 kg