What translation was used to ABCD to produce A’ B’C’D’

Answer:

[tex]a^{\frac{9}{2}}[/tex]

Step-by-step explanation:

[tex]\left(a^{\frac{3}{2}}\right)^3[/tex]

[tex]=a^{\frac{3}{2}\cdot \:3}[/tex]

[tex]=a^{\frac{3}{2}\cdot \frac{3}{1}}[/tex]

[tex]=a^{\frac{9}{2}}[/tex]

Answer: The answer is choice 3

Step-by-step explanation:

i think the answer is c

Step-by-step explanation:

i don't think u would want a whole explanation

Answer:

1.7%

Step-by-step explanation:

We have to calculate the probability that the salesperson will make four or more sales if six sales calls are made on a given day, that is:

P (x => 4)

Therefore, we must calculate when x = 4, when x = 5, and when x = 6 and add. p = 0.2, n = 6

P (x = r) = nCr * p ^ r * (1 - p) ^ (n-r)

Also, nCr = n! / (r! * (n-r) !, now replacing:

P (x = 4) = 6! / (4! * (6-4)! * 0.20 ^ 4 * 0.80 ^ (6-4)

P (x = 4) = 15 * 0.001024 = 0.01536

P (x = 5) = 6! / (5! * (6-5)! * 0.20 ^ 5 * 0.80 ^ (6-5)

P (x = 5) = 6 * 0.000256 = 0.001536

P (x = 6) = 6! / (6! * (6-6)! * 0.20 ^ 6 * 0.80 ^ (6-6)

P (x = 6) = 1 * 0.000064 = 0.000064

now,

P (x => 4)  = P (x = 4) + P (x = 5) + P (x = 6)

P (x => 4)  = 0.01536) + 0.001536 + 0.000064

P (x => 4) = 0.01696 = 0.017

It means that the probability is 1.7%

Answer: 114

Step-by-step explanation: You have 43 new catfish then you catch 88 but 17 of them have already been marked so you do not want to count those in the estimated population again because they have already been counted so you take 88 minus 17 and you get 71 new fish. So then you add the first new sample of fish 43 and then you add the second new sample of fish 71 and then you get 114

Answer: 41

Step-by-step explanation:

a^2 + b^2 = c^2

40^2 + 9^2 = c^2

c = √1681 = 41

Answer:

D: 41

Step-by-step explanation:

Using Pythagorean Theorem

c² = a² + b²

Where c is hypotenuse, x

a is the base, 9

b is the perpendicular, 40

Putting in the formula

x² = (40)²+(9)²

x² = 1600 + 81

x² = 1681

Taking square root on both sides

x = 41

Answer:

Radius = 13 m

Step-by-step explanation:

Formula for area of circle is given as:

[tex]A = \pi {r}^{2} \\ \\ \therefore \: 169\pi \: = \pi {r}^{2} \\ \\ \therefore \: {r}^{2} = \frac{169\pi }{\pi} \\ \\ \therefore \: {r}^{2} = 169 \\ \\ \therefore \: {r} = \pm \sqrt{169} \\ \\\therefore \: r = \pm \: 13 \: m \\ \\ \because \: radius \: of \: a \: circle \: can \: not \: be \: a \: negative \: \\quantity \\ \\ \huge \red{ \boxed{\therefore \: r = 13 \: m }}[/tex]

Answer:

4/13

Step-by-step explanation:

There are 13 diamonds in a deck and 3 fours that aren't diamond

13+3=16

16/52 = 4/13

Answer:

-1.75

Step-by-step explanation:

Answer:

Look at the money bags below!!! (but I'll give you the answer)

Step-by-step explanation:

John F: 7 full bags - 1 half

Juan A: 9 full bags

Jason A: 3 full bags

Nick J: 3 full bags- 1 half

Alfonso S: 8 full bags

Hope this helped and wasn't confusing!!! xx - Asia

Answer:

El resto es 9.

Step-by-step explanation:

En una división el cociente es el resultado que se obtiene, el divisor es el número por el que se divide otro número, el dividendo es el número que va a dividirse entre otro y el resto es lo que queda cuando un número no puede dividirse exactamente entre otro. De acuerdo a esto, la división planteada se encuentra en la imagen adjunta donde al resolverla se encuentra que el número que queda es 9 y este es el resto.

Answer:

b = 4.6 ft

h = 2.3 ft

Step-by-step explanation:

The volume of the tank is given by:

[tex]b^2*h=49[/tex]

Where 'b' is the length of the each side of the square base, and 'h' is the height of the tank.

The surface area can be written as:

[tex]A=b^2+4bh\\A=b^2+4b*({\frac{49}{b^2}})\\A=b^2+\frac{196}{b}[/tex]

The value of b for which the derivate of the expression above is zero is the value that yields the minimum surface area:

[tex]\frac{dA}{db} =0=2b-\frac{196}{b^2}\\2b^3=196\\b=4.61\ ft[/tex]

The value of h is then:

[tex]h=\frac{49}{4.61^2}\\h=2.31\ ft[/tex]

Rounded to the nearest tenth, the dimensions are b = 4.6 ft and h = 2.3 ft.

Answer:

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

[tex]C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex]   we can conclude that the  function is an increasing function.

Step-by-step explanation:

Given that:

[tex]\dfrac{dC}{dt}= r-kC[/tex]

[tex]\dfrac{dC}{r-kC}= dt[/tex]

By taking integration on both sides ;

[tex]\int\limits\dfrac{dC}{r-kC}= \int\limits \ dt[/tex]

[tex]- \dfrac{1}{k}In (r-kC)= t +D[/tex]

[tex]In(r-kC) = -kt - kD \\ \\ r- kC = e^{-kt - kD} \\ \\ r- kC = e^{-kt} e^{ - kD} \\ \\r- kC = Ae^{-kt} \\ \\ kC = r - Ae^{-kt} \\ \\ C = \dfrac{r}{k} - \dfrac{A}{k}e ^{-kt} \\ \\[/tex]

[tex]C(t) =\frac{ r}{k} - \frac{A}{k}e^{ -kt}[/tex]

where;

A is an integration constant

In order to determine A, we have C(0) = C0

[tex]C(0) =\frac{ r}{k} - \frac{A}{k}e^{0}[/tex]

[tex]C_0 =\frac{r}{k}- \frac{A}{k}[/tex]

[tex]C_{0} =\frac{ r-A}{k}[/tex]

[tex]kC_{0} =r-A[/tex]

[tex]A =r-kC_{0}[/tex]

Thus:

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

b ) Assuming that C0 < r/k, find lim t→[infinity] C(t) and interpret your answer

[tex]C_{0} < \lim_{t \to \infty }C(t)[/tex]

[tex]C_0 < \dfrac{r}{k}[/tex]

[tex]kC_0 <r[/tex]

The equation for C(t) can therefore be re-written as :

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

[tex]C(t) =\dfrac{ r}{k} - \left (+ve \right )e^{ -kt} \\ \\C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex]

Thus; we can conclude that the above function is an increasing function.

Answer:0,1

Step-by-step explanation:

It’s on edge

Answer:

4.......................

Answer:

y = x+2

y =-x+2  shows 0

We want to show 1 both sides

2y = x+2  shows 2

y = x+2 shows 0 as explained below.

Step-by-step explanation:

3y−x=6

Solve for y.

y=2+x3

Rewrite in slope-intercept form.

y=13x+2.

Use the slope-intercept form to find the slope and y-intercept.

Slope: 13 y-intercept: 2

Any line can be graphed using two points. Select two

x values, and plug them into the equation to find the corresponding y values.

xy 02, 33

Graph the line using the slope and the y-intercept, or the points.

Slope:

13y-intercept: 2x y (0,2) (3,3)

Answer:

The difference between the games won and lost = 21 - 6 =15

Step-by-step explanation:

According to the question In a football season a team gets 3 points for a win, 1 point for a draw and 0 points for a loss.

A particular season a team played 34 games and lost 6 games . Finding the difference between game won and game lost simply means we have to know the number of game lost and game won.

The team played a total of 34 games.

Total games played = 34

Out of the 34 games played they lost 6 games. That means the remaining games is either win or draw. Therefore,

34 - 6 = 28 games was won or draw

Let

the number of games won = x

the number of game drew = y

3x + y = 70.............(i)

x  + y = 28................(ii)

x = 28 - y

insert the value of x in equation(i)

3(28 - y) + y = 70

84 - 3y + y = 70

84 - 70 = 3y -y

14 = 2y

divide both sides by 2

y = 14/2

y = 7

insert the value of y in equation(ii)

x + y = 28

x = 28 - 7

x = 21

The team won 21 games , drew 7 games and lost 6 games.

The difference between the games won and lost = 21 - 6 =15

Answer:

The highest you could reach with this ladder is 30 feet or 9.14 meters.

Answer:

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

11*11=4

(1+1)*(1+1)=4

2 * 2 = 4

22*22=16

(2+2)*(2+2)=16

4 * 4 = 16

33*33=?

(3+3)*(3+3)=?

6 * 6 = 36

So the answer is 36

Series: 4, 16, 36

Answer: The answer is 36 :)

hope that helped

Answer:

2 rays that meet at an endpoint

Step-by-step explanation: A ray starts with a dot, or point and continues on forever with an arrow. There are two rays in that drawing that start at the same endpoint.

Answer:

2 rays that meet at an endpoint.

Step-by-step explanation:

A ray is straight but has one endpoint and the other end go on infinitely.

A line is straight and goes on infinitely.

A line segment is straight and has two endpoints.

The picture shows two rays meeting at an endpoint.

Answer:

A.

Step-by-step explanation:

A quadrilateral inscribed in a circle has its opposite angles adding up to 180°

So

<NOP + <M = 180

4x+8x-24 = 180

12x = 180+24

12x = 204

Dividing both sides by 12

x = 17

<NOP = 4(17)

= 68°

Answer:

(a) The correct option is (A).

(b) The correct option is (B).

Step-by-step explanation:

Nam collected the data for the distance traveled by all the cars in his car lot.

(a)

A histogram is a bar graph representing the distribution of a random variable. The height of the bars of the histogram represents the frequency for a specific interval.

If Nam wants to know how many vehicles had driven more than 200,000 km, the histogram would be the best display of this data. This is because the histogram shows the frequency for various interval values.

The correct option is (A).

(b)

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

So, if Nam wants to find whether the median distance was approximately 140,000 km, a box plot would be a better choice. This is because the box plot represents the median of the data by a line within the box.

The correct option is (B).

Answer: For the first one is A second one is B

Step-by-step explanation: I took the khan test. UwU♡

Answer:

There is a probability of 76% of not selling the package if there are actually three dead batteries in the package.

Step-by-step explanation:

With a 10-units package of batteries with 3 dead batteries, the sampling can be modeled as a binomial random variable with:

The probability of having k dead batteries in the sample is:

[tex]P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}[/tex]

Then, the probability of having one or more dead batteries in the sample (k≥1) is:

[tex]P(x\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{4}{0} p^{0}q^{4}=1*1*0.7^4=0.2401\\\\\\P(x\geq1)=1-0.2401=0.7599\approx0.76[/tex]

Answer:

13

Step-by-step explanation:

I think

[tex]1. \: (x - y) {2} \\ = {x}^{2} - 2xy + {y}^{2} \\ 2. \: (a + b) ^{2} \\ = {a}^{2} + 2ab + {b}^{2} \\ 3. \: (2x + 3y) ^{2} \\ = {(2x)}^{2} + 2.2x.3y + (3y) ^{2} \\ = {4x}^{2} + 12xy + {9y}^{2} \\ 4.(3x - 2y) ^{2} \\ = (3x) ^{2} - 2.3x.2y + (2y) ^{2} \\ = {9x}^{2} - 12xy + {4y}^{2} \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment[/tex]

Answer:

a) x^2−2xy+y^2

b) a^2 -ab+b^2

c)4x^2+12xy+9y^2

d)9x^2 -12xy+4y^2

Step-by-step explanation:

a) x^2−2xy+y^2

b) a^2 -ab+b^2

c)4x^2+12xy+9y^2

d)9x^2 -12xy+4y^2

We rewrite (x-y)^2 as (x-y) (x-y) to show and always see + sign at start for question a ) and question b)

a) x*x+x(−y)−yx−y(−y) = x^2−2xy+y^2

b) a^2 becomes a^2 -ab as a^2 -ab+b^2

c) As shown in notes attached and this will help you most.

d) the reasons we keep +4y is because -2y becomes -2y-2y and creates a plus.

Answer:

The quantity of salt at time t is [tex]m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })[/tex], where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

[tex]\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}[/tex]

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

[tex](0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}[/tex]

Where:

[tex]c[/tex] - The salt concentration in the tank, as well at the exit of the tank, measured in [tex]\frac{pd}{gal}[/tex].

[tex]\frac{dc}{dt}[/tex] - Concentration rate of change in the tank, measured in [tex]\frac{pd}{min}[/tex].

[tex]V[/tex] - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

[tex]V \cdot \frac{dc}{dt} + 6\cdot c = 3[/tex]

[tex]60\cdot \frac{dc}{dt} + 6\cdot c = 3[/tex]

[tex]\frac{dc}{dt} + \frac{1}{10}\cdot c = 3[/tex]

This equation is solved as follows:

[tex]e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }[/tex]

[tex]\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }[/tex]

[tex]e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt[/tex]

[tex]e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C[/tex]

[tex]c = 30 + C\cdot e^{-\frac{t}{10} }[/tex]

The initial concentration in the tank is:

[tex]c_{o} = \frac{10\,pd}{60\,gal}[/tex]

[tex]c_{o} = 0.167\,\frac{pd}{gal}[/tex]

Now, the integration constant is:

[tex]0.167 = 30 + C[/tex]

[tex]C = -29.833[/tex]

The solution of the differential equation is:

[tex]c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }[/tex]

Now, the quantity of salt at time t is:

[tex]m_{salt} = V_{tank}\cdot c(t)[/tex]

[tex]m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })[/tex]

Where t is measured in minutes.

Answer:

A) The sampling distribution for a sample size n=50 has a mean of 18.5 weeks and a standard deviation of 0.849.

B) P = 0.7616

C) P = 0.4441

Step-by-step explanation:

We assume that for the population of all unemployed individuals the population mean length of unemployment is 18.5 weeks and that the population standard deviation is 6 weeks.

A) We take a sample of size n=50.

The mean of the sampling distribution is equal to the population mean:

[tex]\mu_s=\mu=18.5[/tex]

The standard deviation of the sampling distribution is:

[tex]\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{50}}=0.849[/tex]

B) We have to calculate the probability that the sampling distribution gives a value between one week from the mean. That is between 17.5 and 19.5 weeks.

We can calculate this with the z-scores:

[tex]z_1=\dfrac{X_1-\mu}{\sigma/\sqrt{n}}=\dfrac{17.5-18.5}{6/\sqrt{50}}=\dfrac{-1}{0.8485}=-1.179\\\\\\z_2=\dfrac{X_2-\mu}{\sigma/\sqrt{n}}=\dfrac{19.5-18.5}{6/\sqrt{50}}=\dfrac{1}{0.8485}=1.179[/tex]

The probability it then:

[tex]P(|X_s-\mu_s|<1)=P(|z|<1.179)=0.7616[/tex]

C) For half a week (between 18 and 19 weeks), we recalculate the z-scores and the probabilities:

[tex]z=\dfrac{X-\mu}{\sigma/\sqrt{n}}=\dfrac{18-18.5}{6/\sqrt{50}}=\dfrac{-0.5}{0.8485}=-0.589[/tex]

[tex]P(|X_s-\mu_s|<0.5)=P(|z|<0.589)=0.4441[/tex]

Answer:

f

Step-by-step explanation: