What’s the correct answer for this question?

Answer:

y = -x + 2

Step-by-step explanation:

The slope intercept form equation of this line can be written like this :

y = my + p ; where m is the slope and p is the y intercept.

[tex]m = \frac{-1-4}{3-(-2)} = \frac{-5}{5} =-1[/tex]

then the equation becomes y = -x + p

(-2,4) is a point of the line means 4 = -(-2) + p

then p = 4 - 2 = 2

finally, y = -x + 2

Answer: 400

Step-by-step explanation:

500 x 0.80 = 400

Answer:

400

Step-by-step explanation:

Of means multiply

80% * 500

Change to fraction form

80/100 * 500

Rewriting to reduce

80 * 500/100

80 * 5

400

Answer:

[tex]47\frac{5}{8}[/tex]

Step-by-step explanation:

Weight from before + Weight gained

[tex]46\frac{3}{8} +1\frac{1}{4}[/tex]

Convert to improper fractions.

[tex]371/8 + 5/4[/tex]

Find the common denominator.

[tex]371/8 + 10/8[/tex]

Add.

[tex]381/8[/tex]

Convert to a mixed fraction.

[tex]47\frac{5}{8}[/tex]

Answer:

47 5/8 kg

Step-by-step explanation:

Ealier weight + gained weight = Monday's weight

46 3/8 + 1 1/4

= 371/8 + 5/4

= 371/8 + 10/8

= 381/8

= 47 5/8 kg

Answer:

The probability that the number of free throws he makes exceeds 80 is approximately 0.50

Step-by-step explanation:

According to the given data we have the following:

P(Make a Throw) = 0.80%

n=100

Binomial distribution:

mean:   np = 0.80*100= 80

hence, standard deviation=√np(1-p)=√80*0.20=4

Therefore, to calculate the probability that the number of free throws he makes exceeds 80 we would have to make the following calculation:

P(X>80)= 1- P(X<80)

You could calculate this value via a normal distributionapproximation:

P(Z<(80-80)/4)=1-P(Z<0)=1-50=0.50

The probability that the number of free throws he makes exceeds 80 is approximately 0.50

The probability that the number of free throws he makes exceeds 80 is approximately 0.5000.

Given that,

A college basketball player makes 80% of his free throws.

Over the course of the season, he will attempt 100 free throws.

Assuming free throw attempts are independent.

We have to determine,

The probability that the number of free throws he makes exceeds 80 is.

According to the question,

P(Make a Throw) = 80% = 0.80

number of free throws n = 100

Binomial distribution:

Mean: [tex]n \times p = 0.80 \times 100 = 80[/tex]

Then, The standard deviation is determined by using the formula;

[tex]= \sqrt{np(1-p)} \\\\=\sqrt{80\times (1-0.80)}\\\\= \sqrt{80 \times 0.20 } \\\\= \sqrt{16} \\\\= 4[/tex]

Therefore,

To calculate the probability that the number of free throws he makes exceeds 80 we would have to make the following calculation:

[tex]P(X>80)= 1- P(X<80)[/tex]

To calculate this value via a normal distribution approximation:

[tex]P(Z<\dfrac{80-80}{4})=1-P(Z<0)=1-0.50=0.5000[/tex]

Hence, The probability that the number of free throws he makes exceeds 80 is approximately 0.5000.

To know more about Probability click the link given below.

https://brainly.com/question/21586810

Answer:  EF = 15

Step-by-step explanation:

The given description is that of an isosceles triangle. The base angles are congruent, therefore the sides opposite of those angles are also congruent.

The base angles are ∠E and ∠G and the vertex angle is ∠F.

The sides opposite to the base angles are EF and FG.

Thus, EF ≡ FG.

Since FG = 15 and FG = EF, then 15 = EF.

Based on the definition of an isosceles triangle, the length of EF in the triangle is: 15 units.

An isosceles triangle has two sides that are congruent. The angles opposite these congruent sides are also congruent.

ΔEFG is an isosceles triangle. The congruent sides are, FG and EF.

Therefore, EF = FG = 15 units.

Learn more about isosceles triangle on:

https://brainly.com/question/11884412

Answer:

The 7 is in the hundredths place.

The 3 is in the ones place.

3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001).

Step-by-step explanation:

Given the number 3.872, to check all the given options that are true apply to the number, let's take a look at each position occupied by each digit. In order words, let's consider their place value.

Thus,

The 3 is in the ones place and as such has a value of 3.

8 is in the tenths place having a place value of 0.8 (⁸/10)

7 is in the hundredths place having a place value of 0.07 (⁷/100)

2 is in the thousandths place having a place value of 0.002 (²/1000)

Going by these, the following statements are true :

"The 7 is in the hundredths place."

"The 3 is in the ones place."

"3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001)."

The number is pronounced as three and eight hundred seventy-two thousandths rather than the option given.

Therefore, only 3 if the options are correct

Answer: The 7 is in the hundredths place.

The 3 is in the ones place.

3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001).

Step-by-step explanation:

In the question, 3 is in the ones place. The first number after the decimal point is the tenths. In the question, the place value of 8 is 8 tenths; 7 is in the hundredths place.

3.872 = (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001)

= 3 + 0.8 + 0.07 + 0.002

= 3.872

The number is pronounced as three and eight hundred seventy-two thousandths

Answer:

The GCF is going to be 32

Answer:

32x^2

Step-by-step explanation:

B on edge

Question:

It is known that 20% of products on a production line are defective. Products are inspected until first defective is encountered. a) What is the probability that the experimenter must inspect six products to find a defective product?

Answer:

P(x = 6) = 0.0655

P(x = 6) = 6.55%

Step-by-step explanation:

It is given that 20% of products on a production line are defective.

p = 0.20

Then

q = 1 - p = 1 - 0.20 = 0.80

Which means that 80% of products on the production line are not defective.

We want to find out the probability that the experimenter must inspect six products to find a defective product.

Let x is the number of inspections to get a defective product.

P(x = 6) = ?

If out of 6 inspections 1 is defective then it means 5 are not defective

so the probability is

P(x = 6) = p¹ × q⁵

P(x = 6) = 0.20¹ × 0.80⁵

P(x = 6) = 0.20 × 0.32768

P(x = 6) = 0.0655

P(x = 6) = 6.55%

Therefore, there is 6.55% chance that the experimenter finds a defetive product in 6 inspections.

Answer:

(A)three eigenvalues, all of them real.

(D)one real eigenvalue and two complex eigenvalues.

(G)only one eigenvalue -- a real one.

Step-by-step explanation:

Given an [tex]n \times n[/tex] matrix, the characteristic polynomial of the matrix is the degree n  polynomial in one variable λ:

[tex]p(\lambda) = det(\lambda I- A)[/tex]

If such [tex]n \times n[/tex] matrix A has real entries, its complex eigenvalues  will always occur in complex conjugate pairs.

Therefore, for a [tex]3 \times 3[/tex] matrix with real entries, the following are possible:

(A)three eigenvalues, all of them real.

(D)one real eigenvalue and two complex eigenvalues.

(G)only one eigenvalue -- a real one.

A [tex]3 \times 3[/tex] matrix with real entries cannot have the following:

(B)three eigenvalues, all of them complex.

(C)two real eigenvalues and one complex eigenvalue.

(E)only two eigenvalues, both of them real.

(F)only two eigenvalues, both of them complex.

(H)only one eigenvalue -- a complex one.

Answer:

(a)[tex]\dfrac{2}{13}[/tex]

(b)[tex]\dfrac{3}{13}[/tex]

(c)[tex]\dfrac{4}{13}[/tex]

Step-by-step explanation:

In a standard deck, there are 52 cards which are divided into 4 suits.

(a)

Number of Seven Cards =4

Number of King cards =4

Probability of randomly selecting a seven or king

=P(Seven)+P(King)

[tex]=\dfrac{4}{52} +\dfrac{4}{52} \\=\dfrac{8}{52}\\=\dfrac{2}{13}[/tex]

(b)

Number of Seven Cards =4

Number of King cards =4

Number of Jack(J) cards =4

Probability of randomly selecting a seven or king

=P(Seven)+P(King)+P(Jack)

[tex]=\dfrac{4}{52} +\dfrac{4}{52}+\dfrac{4}{52} \\=\dfrac{12}{52}\\=\dfrac{3}{13}[/tex]

(c)

Number of Queen Cards =4

Number of Spade cards =13

Number of Queen and Spade cards =1

Probability of randomly selecting a seven or king

[tex]=P$(Queen)+P(Spade)-P(Queen and Spade Card)\\=\dfrac{4}{52} +\dfrac{13}{52} -\dfrac{1}{52} \\=\dfrac{16}{52} \\=\dfrac{4}{13}[/tex]

Answer:

(B)[tex]9 \pi $ units squared[/tex]

Step-by-step explanation:

In circle B, AB is one of the radii; and

AB=6

Central Angle of ABC [tex]=\dfrac{\pi}{2}$ radians[/tex]

Now, Area of a Sector  

[tex]\text{Area of a Sector}=\dfrac{\theta}{2\pi} \times \pi r^2 \\=\dfrac{\frac{\pi}{2}}{2\pi} \times \pi \times 6^2\\=\dfrac{\pi}{4\pi} \times \pi \times 6^2\\=\dfrac{36}{4} \times \pi \\= 9 \pi $ units squared[/tex]

Answer:

b

Step-by-step explanation:

answer is g(x)=|x+2|-1

[tex]answer \\ g(x) = - |x + 2| - 1\\ as \: we \: can \: see \: from \: the \: given \: graph \\ above \: that \: the \: graph \: of \: absolute \\ function \: has \: been \: reflected \: over \: the \\ x \: axis \: \: shifted \: 2 \: units \: left \: and \: 1 \: \\ units \: down. \\ due \: to \: reflection \: there \: is \: a \: negative \\ sign \: shift \: of \: 2 \: units \: left \: is \: given \\ by \: x + 2 \: and \: 1 \: units \: down \: is \: given \\ by \: - 1 \\ hope \: it \: helps[/tex]

Step-by-step explanation:

Cost of 2 pack = 0.95

Cost of 1 pack = 0.95 ÷ 2 = 0.475

Unit price = 0.475

Answer:

220

Step-by-step explanation:

If we lost 12% we still have 100 - 12 = 88% of the employees left. 88% can be written as 0.88. 0.88 * 250 = 220 employees left.

Answer:

27/(4x^6y^8)

Step-by-step explanation:

Target the variables first. (x^a)^b is the same as x^(a x b).

In the numerator, it is x^(2 x 3) , which is x^6, and y^(4 x 3), which is y^12.

Same principle on the bottom. the denominator is x^12 and y^20.

In the numerator, the number 4 is alone so don't do anything to it. Cube 3. The coefficient of the numerator is 4 x 3^3 . The coefficient of the denominator is 2^4. Cancel like terms. when you divide same terms' exponents, you subtract the exponent on top by the exponent on the bottom. Remember that you can only simplify LIKE terms. (x with x, y with y, number with number.)

Answer:

if you go around a track one time thats 400 meters but if you go around 4 times thats 1600 meters, you dont need to use 3.14 pi for this " no offense", i do track and field myself and i do the short distance, which is 100 meters and 200 meter but for for long distance runners they go around the track 4- 8 times so it is 1600 meters is ur answer. and when u go around 8 times, thats 3200 meters.

Step-by-step explanation:

Answer:

[tex] (17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745[/tex]

[tex] (17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255[/tex]

Step-by-step explanation:

For this case we have the following info given:

Treatment: 12 13 15 19 20 21 24

Control: 18 23 24 30 32 35 39

We can find the sample mean and deviations with the the following formulas:

[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]

[tex] s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}[/tex]

And repaplacing we got:

[tex] \bar X_T = 17.714[/tex] the sample mean for treatment

[tex] \bar X_C = 28.714[/tex] the sample mean for treatment

[tex] s_T= 4.461[/tex] the sample deviation for treatment

[tex] s_C= 7.387[/tex] the sample deviation for control

[tex]n_T= n_C= 7[/tex] the sample size for each sample

The degrees of freedom are given by:

[tex] df= 7+7-2= 12[/tex]

The confidence interval for the difference of means is given by:

[tex] (\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}[/tex]

The confidence is 98% so then the significance is [tex]\alpha=0.02[/tex] and [tex] \alpha/2 =0.01[/tex]. Then the critical value would be:

[tex] t_{\alpha/2}=2.681[/tex]

And replacing we got:

[tex] (17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745[/tex]

[tex] (17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255[/tex]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 16, \sigma = 2.1[/tex]

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{20 - 16}{2.1}[/tex]

[tex]Z = 1.905[/tex]

[tex]Z = 1.905[/tex] has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

Here is the full question.

The average finishing time among all high school boys in a particular track event in a certain state is 5 minutes 17 seconds. Times are normally distributed with standard deviation 12 seconds.

A.  The qualifying time in this event for participation in the state meet is to be set so that only the fastest 5% of all runners qualify. Find the qualifying time in seconds (round it to the closest second). (Hint: Convert minutes to seconds.)  

B. In the western region of the state the times of all boys running in this event are normally distributed with standard deviation 12 seconds, but with mean 5 minutes 22 seconds. Find the proportion of boys from this region who qualify to run in this event in the state meet. (Hint: normalcdf)

Answer:

a. x ≅ 337 seconds.

b. P(x > 337 )  = 0.1056

Step-by-step explanation:

A.

Given that ;

Mean [tex]\mu =[/tex] 5 minutes 17 seconds =( (60× 5)+17  ) seconds  = 317 seconds   ( since 60 seconds make 1 minute.

Standard deviation: [tex]\sigma[/tex] = 12 seconds.

Only the fastest 5% of all runners qualify

The objective is to determine the qualifying time in seconds

Let's look for the Z-score of 0.95;

The Z-score is 1.645 from the tables

[tex]x= ( \sigma * z ) + \mu[/tex]

[tex]x = ( 12 * 1.645 ) + 317 \\ \\x = 336.74[/tex]

x ≅ 337 seconds.

B. Given that the standard deviation = 12 seconds

Mean = 5 minutes 22 seconds = (5 × 60 + 22 )seconds = 322 seconds

he objective is  to find P(x > 337 )   i.e the proportion of boys from this region who qualify to run in this event in the state meet.

we are using command normalcdf   (SEE THE ATTACHED FILE BELOW FOR THE COMPUTATION)

we have  P(x > 337 )  = 0.1056

Answer: The answer is 61

Step-by-step explanation: did it on 2020 edg pls mark me brainliest

Answer:

61

Step-by-step explanation:

Answer:  The answer is C 90

Step-by-step explanation: Rotations is ¼ and the Radians is π/2

Answer:

The answer is 2

From the function when the input is 2 the output is -7. The inverse reverses the order so the input will be -7 and the output will be 2.

Answer:

For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]

Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:

[tex] z_{\alpha/2}= \pm 1.62015[/tex]

And we can use the following excel code for example:

"=NORM.INV(0.0526,0,1)"

Step-by-step explanation:

For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]

Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:

[tex] z_{\alpha/2}= \pm 1.62015[/tex]

And we can use the following excel code for example:

"=NORM.INV(0.0526,0,1)"

Answer:

(–2, 5)

Step-by-step explanation:

I know its late now but here is the answer.

Answer:

The answer is a

Step-by-step explanation:

Answer:

The answer is 8300.

Step-by-step explanation:

1) We round the number up to the nearest hundred, if the last two digits in the number are 50 or above.

2) We round the number down to the nearest 100 if the last two digits in the number are 49 or below.

3) If the last two digits are 00, then we do not have to do any rounding because it is already to the hundred.

Answer:

When we talk about precision in measurements, we need to mention the significant figures, because that determines the precision.

Specifically, the more significant figures there are, more precise will be the number.

In this case, you can observe that both numbers have the same number of significant figures, which is 3, which means both numbers are equal in precision.

Answer:

The height is about 5 inches.

Step-by-step explanation:

The volume for a cone is [tex]\frac{1}{3}[/tex] × π × r² × h

The radius of the cone is 1.5

12= [tex]\frac{1}{3}[/tex] × π × 1.5² × h

12= [tex]\frac{1}{3}[/tex] × π × 2.25 × h

12=0.75×π×h

Divide both sides by 0.75

16=π×h

Divide both sides by π

5≈h

The height is about 5 inches.

Answer:

Step-by-step explanation:

a) The %tax comes from the "Rate" column on the line "up to $9525". It is 10%.

__

b) Simply compute the difference shown:

  $38,700 -$9,525 = $29,175

__

c) 22% of $9,300 is ...

  0.22 × $9,300 = $2,046

__

d) The total from the three previous calculations is ...

  $952.50 +3,501.00 +2,046.00 = $6,499.50

Answer:

10%

$29,175

$2,046

$6,499.50

got it right on ttm.  

Step-by-step explanation:

just believe me it works

Answer:

169.5 yd²

Step-by-step explanation:

See attachment.

In situations like this, ALWAYS (!) make as sketch.

Divide the areas by adding dotted lines on sensible places, and write in the missing numbers for the correct distances.

The only possible difficult one is the triangle, which is the half of a rectangle. So you are dealing with a series of areas of rectangles. That is really easy if you understand what you are doing.

Total area =

area 1 + area 2 + area 3 + area 4

10*4 + 4*7 + 3*13 + (0.5 * 7*17)

40 + 28 + 42 + 59.5

Total area = 169.5 yd²