When writing expressions for complex numbers, what does i represent?

Answer:

Step-by-step explanation:

A=πr^2

But A=88/63

88/63=πr^2

88/63π=r^2

√88/63π=r

Answer:

The age difference between the youngest and the oldest is 48

Answer:

[tex] p =\frac{7}{51}= 0.1372[/tex]

And then the probability that is NOT from sport temas using the complement rule is given by:

[tex] q = 1-p =1- \frac{7}{51}= 0.8627[/tex]

And if we convert that into % we got:

[tex] 0.8627 *100= 86.27\%[/tex]

Approximately 86.27% of the floats were NOT sports teams

Step-by-step explanation:

For this case we can begin finding the % of floats that were from sport tems using the Laplace definition of probability given by:

[tex]p = \frac{Possible}{Total}[/tex]

And replacing we got:

[tex] p =\frac{7}{51}= 0.1372[/tex]

And then the probability that is NOT from sport temas using the complement rule is given by:

[tex] q = 1-p =1- \frac{7}{51}= 0.8627[/tex]

And if we convert that into % we got:

[tex] 0.8627 *100= 86.27\%[/tex]

Approximately 86.27% of the floats were NOT sports teams

Answer:

299.97 is the actual answer

Step-by-step explanation:

I took the test.

Answer:

Camera 2nd has to cover the maximum angle, i.e. [tex]78.70^\circ[/tex].

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle [tex]\triangle ABC[/tex] with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles [tex]\angle A, \angle B, \angle C[/tex]

As per Law of cosine:

[tex]cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}[/tex]

Putting the values of a,b and c to find out angles [tex]\angle A, \angle B, \angle C[/tex].

[tex]cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ[/tex]

[tex]cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ[/tex]

[tex]cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ[/tex]

Camera 2nd has to cover the maximum angle, i.e. [tex]78.70^\circ[/tex].

Answer:

[tex]100(0.5)^{x}[/tex]

Step-by-step explanation:

According to the graph, the y int is at 100

so that is the starting point

Then at 1 it is at 50

[tex]\frac{100}{50}[/tex] is 2 so that means it is reduced by half

Just to make sure, [tex]\frac{50}{25}[/tex] is also /2 so that means it is the slope

Since it is a decay, the slope has to be less than one so you get the reciprecol of 2 to get....

[tex]\frac{1}{2}[/tex]

Answer:f(x)=100(2^x)

Step-by-step explanation:

Answer:

Option D

Step-by-step explanation:

If these lines are parallel, they should have the same slope. How so? Well slope is the change in axis, y / x more specifically. If the lines are parallel they should change at a similar rate so that they don't intersect, and hence are, by definition, ║;

[tex]Green Line's Slope = Red Line's Slope,\\8 = Red Line's Slope,\\Red Line's Slope = 8 units\\\\Solution - Option D[/tex]

Hope that helps!

Answer:

Step-by-step explanation:

Let x be the random variable representing the SAT scores for the students at a local high school. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

From the information given,

µ = 1527

σ = 291

the probability to be determined is expressed as P(x > 1207)

P(x > 1207) = 1 - P(x ≤ 1207)

For x < 1208

z = (1207 - 1527)/291 = - 1.1

Looking at the normal distribution table, the probability corresponding to the z score is 0.16

P(x > 1207) = 1 - 0.16 = 0.84

Therefore, the percentage of students from this school earn scores that satisfy the admission requirement is

0.84 × 100 = 84%

Answer:

Due to the higher z-score, Norma should be offered the job

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

Whoever has the higher z-score should get the job.

Norma:

Norma got a score of 84.2; this version has a mean of 67.4 and a standard deviation of 14.

This means that [tex]X = 84.2 \mu = 67.4, \sigma = 14[/tex]

So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{84.2 - 67.4}{14}[/tex]

[tex]Z = 1.2[/tex]

Pierce:

Pierce got a score of 276.8; this version has a mean of 264 and a standard deviation of 16.

This means that [tex]X = 276.8, \mu = 264, \sigma = 16[/tex]

So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{276.8 - 264}{16}[/tex]

[tex]Z = 0.8[/tex]

Reyna:

Reyna got a score of 7.62; this version has a mean of 7.3 and a standard deviation of 0.8.

This means that [tex]X = 7.62, \mu = 7.3, \sigma = 0.8[/tex]

So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{7.62 - 7.3}{0.8}[/tex]

[tex]Z = 0.4[/tex]

Due to the higher z-score, Norma should be offered the job

Answer:

9, 1

Step-by-step explanation:

Counting numbers are numbers that can be used for counting purposes. This group of numbers does not include negative numbers, fractions, zero, decimal numbers etc. They are positively directed whole numbers.

From the question, given the condition not to simplify, then the counting numbers are:

                     9, 1

others numbers can not be referred to as counting numbers.

Answer:

65!

65! = 8. 2547650592 * 10^ 90 approximately

Step-by-step explanation:

A random number generator randomly generates a number from 1 to 65.

Once a specific number is generated, the generator will not select that number again until it is reset.

The number of ways it can be used is = 65!

65! = 8. 25476505* 10^ 90 approximately

Answer:

-4, -6

Step-by-step explanation:

3x+6= 1x-2

2x+6= -2

2x= -8  

x= -4

Now that you have your x variable, you can go back and plug it in to your original equations:

y= 3(-4)+6,

      y= (-12)+6 therefore y= -6

y=1(-4) -2,

        y= (-4) -2 therefore y = -6

Answer:

  a.  235°

  b. 146.03 km

  c. 105 km

  d. 193 km

Step-by-step explanation:

a. The bearing of E from A is given as 55°. The bearing in the opposite direction, from E to A, is this angle with 180° added:

  bearing of A from E = 55° +180° = 235°

__

b. The internal angle at E is the difference between the external angle at C and the internal angle at A:

  ∠E = 134° -55° = 79°

The law of sines tells you ...

  CE/sin(∠A) = CA/sin(∠E)

  CE = CA(sin(∠A)/sin(∠E)) = (175 km)·sin(55°)/sin(79°) ≈ 146.03 km

  CE ≈ 146 km

__

c. The internal angle at C is the supplement of the external angle, so is ...

  ∠C = 180° -134° = 46°

The distance PE is opposite that angle, and CE is the hypotenuse of the right triangle CPE. The sine trig relation is helpful here:

  Sin = Opposite/Hypotenuse

  sin(46°) = PE/CE

  PE = CE·sin(46°) = 146.03 km·sin(46°) ≈ 105.05 km

  PE ≈ 105 km

__

d. DE can be found from the law of cosines:

  DE² = DC² +CE² -2·DC·CE·cos(134°)

  DE² = 60² +146.03² -2(60)(146.03)cos(134°) ≈ 37099.43

  DE = √37099.43 ≈ 192.6 . . . km

  DE is about 193 km

Answer:

  1) h = -1/2t^2 +10t

  2) h = -1/2(t -10)^2 +72

  3) domain: [0, 20]; range: [0, 50]

Step-by-step explanation:

1.) I find it easiest to start with the vertex form when the vertex is given. The equation of the presumed parabolic path for Firework 1 is ...

  h = a(t -10)^2 +50

To find the value of "a", we must use another point on the graph. (0, 0) works nicely:

  0 = a(0 -10)^2 +50

  -100a = 50 . . . . . . subtract 100a

  a = -1/2 . . . . . . . . . divide by -100

Then the standard-form equation is ...

  h = (-1/2)(t^2 -20t +100) +50

  h = -1/2t^2 +10t

__

2.) The path of Firework 2 is translated upward by 22 units from that of Firework 1.

  h = -1/2(t -10)^2 +72

__

3.) The horizontal extent of the graph for Firework 1 is ...

  domain: 0 ≤ t ≤ 20

The vertical extent of the graph for Firework 1 is ...

  range: 0 ≤ h ≤ 50

Answer:

Step-by-step explanation:

draw it out and use trig function to solve for the angle. Keep in mind, after getting trig, need to do inverse

Answer:

$120.52

Margin of error M.E = $120.52

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

x+/-M.E

Where M.E = margin of error

M.E = zr/√n

Given that;

Mean x = $1,873

Standard deviation r = $550

Number of samples n = 80

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

M.E = (1.96 × $550/√80) = 120.5240639872

M.E = $120.52

Margin of error M.E = $120.52

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from T (Kano Airport) to point U in the diagram.

Distance = Speed X Time

Therefore: Distance from T to U =50km/hr X 2 hr =100 km

It moves from Point U at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, UA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

[tex]\angle U=110^\circ[/tex]

(a)First, we calculate the distance traveled, TA by plane Y.

Using Cosine rule

[tex]u^2=t^2+a^2-2ta\cos U\\u^2=100^2+125^2-2(100)(125)\cos 110^\circ\\u^2=34175.50\\u=184.87$ km[/tex]

Plane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

[tex]=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)[/tex]

b)Flight Direction of Y

Using Law of Sines

[tex]\dfrac{t}{\sin T} =\dfrac{u}{\sin U}\\\dfrac{125}{\sin T} =\dfrac{184.87}{\sin 110}\\123 \times \sin T=125 \times \sin 110\\\sin T=(125 \times \sin 110) \div 184.87\\T=\arcsin [(125 \times \sin 110) \div 184.87]\\T=39^\circ $ (to the nearest degree)[/tex]

The direction of flight Y to the nearest degree is 39 degrees.

Answer:

10-19 ⇒ 4

40-49 ⇒ 3

Answer:

10-19: 4 numbers

40-49: 3 numbers

Step-by-step explanation:

10-19: 11, 13, 17, 18 (4 numbers)

40-49: 41, 44, 47 (3 numbers)

Answer:

70 pounds

Step-by-step explanation:

3 boxes= 105 pounds

2boxes= x pounds

Cross Multiply

3*x=105 *2

3x=210

3x/3=210/3

x=70 pounds

Answer:

70

Step-by-step explanation:

105/3=35

35x2=70

So 70 is the answer

Answer:

Step-by-step explanation:

The associative property lets you move parentheses in a sum or product. That is, it doesn't matter which sum or product you compute first.

The commutative property lets you swap the order of operands in a sum or product.

The identity property says the operation using the identity element gives the original value, unchanged.

Answer:

Step-by-step explanation:

Answer:

x=7

Step-by-step explanation:

Do the equation 8x+5 + 3x+8 = 90 and do the math to come out with 7

Hope this helps :)

Answer:

7*

Step-by-step explanation:

8x + 3x + 8 * + 5*=11x+13*

90*-13*=77*

77*= 11x

x= 77*/11=7*

* = degree

Answer:

C:

Step-by-step explanation:

Both angles add up to 180°

<BCG + <BFG = 180°

2x+146+4x+238=180

6x+384 = 180°

6x = 180-384

6x = -204

Dividing both sides by 6

x = -34

Answer:

The total repair cost was around $300 .

Step-by-step explanation:

I wasn't sure when you were saying to round, so here are two options.

(For rounding at the end) :

82+157+58 = 297

Rounds to 300.

(For rounding as he's adding everything up) :

80+160+60= 300.

So either way it's 300!

Hope this helped!

Answer:

0.3182 = 32.81% probability that a randomly selected acre has between 32647 and 43559 ants.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 42000, \sigma = 12275[/tex]

Find the probability that a randomly selectd acre has between 32647 and 43559 ants.

This is the pvalue of Z when X = 43559 subtracted by the pvalue of Z when X = 32647. So

X = 43559:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{43559 - 42000}{12275}[/tex]

[tex]Z = 0.13[/tex]

[tex]Z = 0.13[/tex] has a pvalue of 0.5517.

X = 32647:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{32647 - 42000}{12275}[/tex]

[tex]Z = -0.76[/tex]

[tex]Z = -0.76[/tex] has a pvalue of 0.2236

0.5517 - 0.2236 = 0.3281

0.3182 = 32.81% probability that a randomly selected acre has between 32647 and 43559 ants.

Answer:

She needs to have approximately $6950 on that account.

Step-by-step explanation:

Since the account has an interest rate of 9% annually, then it's compounded and the earnings can be found by the following expression:

[tex]M = C*(1 + r)^t[/tex]

Where M is the final amount, C is the initial amount, r is the interest rate and t is the time elapsed in years.

She needs the money in 3 years, therefore t = 3. Applying this to the problem we have:

[tex]9000 = C*(1 + 0.09)^3\\9000 = C*(1.09)^3\\C*1.295 = 9000\\C = \frac{9000}{1.295}\\C = 6949.81[/tex]

She needs to have approximately $6950 on that account.

Answer:

the dimension of the poster = 90 cm length and 60 cm  width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = [tex]\dfrac{2400 \ cm^2}{p}[/tex]

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be [tex]\dfrac{2400 \ cm^2}{p} + 20[/tex]

The area of the printed material can now be:  [tex]A = (p+30)(\dfrac{2400 }{p} + 20)[/tex]

=[tex]2400 +20 p +\dfrac{72000}{p}+600[/tex]

Let differentiate with respect to p; we have

[tex]\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}[/tex]

Also;

[tex]\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}[/tex]

For the smallest area [tex]\dfrac{dA}{dp }=0[/tex]

[tex]20 - \dfrac{72000}{p^2}=0[/tex]

[tex]p^2 = \dfrac{72000}{20}[/tex]

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression  q = [tex]\dfrac{2400 \ cm^2}{p}[/tex]   to solve for q;

q = [tex]\dfrac{2400 \ cm^2}{p}[/tex]

q = [tex]\dfrac{2400 \ cm^2}{60}[/tex]

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = [tex]\dfrac{2400 \ cm^2}{p} + 20[/tex] = [tex]\dfrac{2400 \ cm^2}{60} + 20[/tex]  = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm  width i.e 90 cm by 60 cm.

Answer:

Answer:

The total is: $ 1345.5

Step-by-step explanation:

It is given that:

I would like to purchase 20 products at a cost 65.00 per product.

This means that the cost of 20 products will be:

Also, there is a sales tax of 3.5%

This means that a person has to pay a extra 3.5% on the total cost of the items he purchased.

i.e. he need to pay 3/5% on $ 1300

This means that the amount of tax he need to pay is: 3.5% of 1300

                                                                             =  3.5%×1300

                                                                            = 0.035×1300

                                                                           = $ 45.5.

Hence, the total cost is: $ 1300+$ 45.5

This means that the total cost is: $ 134.5

Answer:

a) [tex]x = \log_{2} 9,000,000[/tex], b) [tex]x \approx 23.101\,days[/tex]

Step-by-step explanation:

The number of readers as a function of time is:

[tex]n = 2^{x}[/tex]

Where:

[tex]x[/tex] - Time, measured in days.

[tex]n[/tex] - Number of readers, dimensionless.

a) The time when the number of readers reaches 9 million is:

[tex]x = \log_{2} n[/tex]

[tex]x = \log_{2} 9,000,000[/tex]

b) The approximate solution rounded to the nearest thousandth is:

[tex]x \approx 23.101\,days[/tex]

Answer:

Translate point J 12 units down and 6 units right.

Answer:person up top is right it’s B

Step-by-step explanation: on edg 2020

Answer:

The answer is B

Step-by-step explanation:

lol yw guys