which equation represents a line perpendicular to the line shown on the graph​

Which Equation Represents A Line Perpendicular To The Line Shown On The Graph

Answers

Answer 1

Answer:

y = 1/4x + (any number)

Step-by-step explanation:

m = -8/2 = -4, the equation shown is y = -4x + 8

perpendicular is  y = 1/4x + (any number), you didn't say where the line was perpendicular.


Related Questions

intext:"A shipment of 50 inexpensive digital​ watches, including 6 that are​ defective, is sent to a department store. The receiving department selects 10 at random for testing and rejects the whole shipment if 1 or more in the sample are found defective. What is the probability that the shipment will be​ rejected?"

Answers

Answer:

0.7125

Step-by-step explanation:

The binomial distribution with parameters n and p is the discrete probability distribution of the number of successes (with probability p) in a sequence of n independent events.

The probability of getting exactly x successes in n independent Bernoulli trials =  [tex]n_{C_{x}}(p)^x(1-p)^{n-x}[/tex]

Total number of watches in the shipment = 50

Number of defective watches = 6

Number of selected watches = 10

Let X denotes the number of defective digital watches such that the random variable X follows a binomial distribution with parameters n and p.

So,

Probability of defective watches = [tex]\frac{X}{n}=\frac{6}{50}=0.12[/tex]

Take n = 10 and p = 0.12

Probability that the shipment will be rejected = [tex]P(X\geq 1)=1-P(X=0)[/tex]

[tex]=1-n_{C_{x}}(p)^x(1-p)^{n-x}\\=1-10_{C_{0}}(0.12)^0(1-0.12)^{10-0}[/tex]

Use [tex]n_{C_{x}}=\frac{n!}{x!(n-x)!}[/tex]

So,

Probability that the shipment will be rejected = [tex]=1-\left ( \frac{10!}{0!(10-0)!} \right )(0.88)^{10}[/tex]

[tex]=1-(0.88)^{10}\\=1-0.2785\\=0.7125[/tex]

What’s the correct answer for this?

Answers

Answer:

C.

Step-by-step explanation:

Density = Mass / Volume

2.7 = 54 / V

V = 54 / 2.7

V = 20 cubic cm

Andrei wants to fill a glass tank with marbles, and then fill the remaining space with water. WWW represents the volume of water Andrei uses (in liters) if he uses nnn marbles. W=32-0.05nW=32−0.05nW, equals, 32, minus, 0, point, 05, n What is the glass tank's volume?

Answers

Before Andrei adds the marbles to the glass tank, the glass tank was empty. This means that the volume of the empty tank is when n = 0 and the volume is 32 liters.

Given that:

[tex]W = 32 - 0.05n[/tex]

A linear function is represented as:

[tex]y = b + mx[/tex]

Where

[tex]b \to[/tex] y intercept

Literally, the y intercept is the initial value of the function.

In this function, the y intercept means the initial volume of the glass tank before filling it with marbles.

Compare [tex]y = b + mx[/tex] and [tex]W = 32 - 0.05n[/tex]

[tex]b = 32[/tex]

This means that the volume of the glass tank is 32 liters.

Read more about linear functions at:

https://brainly.com/question/21107621

Answer:

0.05

Step-by-step explanation:

To convert a measurement, Pete must move the decimal point to the left 4 places. This is a shortcut for an operation. Which operation is he using? Which power of 10 is involved? iLL GIVE 50 POINTS PLEASE IM TIMED IM PANICKING

Answers

Answer: The moving of decimal to the left is a shortcut to the operation of multiplying number by decimal numbers

Step-by-step explanation:

the power of 10 that is involved in converting the measurements of pete is -4, so he needs to multiply the measurement by 10^-4 to convert it.

Answer:

Sample Response: Because he moved the decimal 4 places to the left, Pete is dividing by 10 to the 4th power, or 10,000. Pete moved the decimal place 4 places to the left. Pete is dividing by 10 to the 4th power, or 10,000.

Step-by-step explanation:

it was on edg

                                                      hope it helps :b

f(x)= 2x^3- x^2 +x+ 1 is divided by 2x +1.

Answers

Answer:

Step-by-step explanation:

               x^2

           --------------------------------------------------

2x + 1  /  2x^3     -     x^2    +      x      +    1

               2x^3    +    x^2

              -----------------------

                                    0 + x + 1

                                        x + 1

The quotient is  x^2 + ------------

                                       2x + 1

Use slope-intercept form to write the equation of a line
that has a slope of -3 and passes through the point
(1,-5).
Use the drop-down menus to select the proper value
for each variable that is substituted into the slope-
intercept equation
y =
X
DPM
m =

Answers

Answer:

y=-3x-2

Step-by-step explanation:

There is enough information to make a point-slope form equation that which we can convert into slope-intercept form.

Point-slope form is: [tex]y-y_1=m(x-x_1)[/tex]

We are given the slope of -3 and the point of (1,-5).

[tex]y-y_1=m(x-x_1)\rightarrow y+5=-3(x-1)[/tex]

Convert into Slope-Intercept Form:

[tex]y+5=-3(x-1)\\y+5-5=-3(x-1)-5\\\boxed{y=-3x-2}[/tex]

An engineering consulting firm wantedto evaluate a rivet process by measuring the formed diameter. The following data represent the diameters (in hundredths of an inch) for a random sample of 24 rivet heads:
6.81 - 6.79 - 6.69 - 6.59 - 6.65 - 6.60 - 6.74 - 6.70 - 6.76
6.84 - 6.81 - 6.71 - 6.66 - 6.76 - 6.76 - 6.77 - 6.72 - 6.68
7.71 - 6.79 - 6.72 - 6.72 - 6.72 - 6.79 - 6.83
a) Set up a 95% confidence interval estimate of the average diameter of rivet heads (in hundredths of an inch).
b) Set up a 95% confidence interval estimate of the standard deviation of the diameter of rivet heads (in hundredths of an inch)

Answers

Answer:

Step-by-step explanation:

6.81 - 6.79 - 6.69 - 6.59 - 6.65 - 6.60 - 6.74 - 6.70 - 6.76

6.84 - 6.81 - 6.71 - 6.66 - 6.76 - 6.76 - 6.77 - 6.72 - 6.68

7.71 - 6.79 - 6.72 - 6.72 - 6.72 - 6.79 - 6.83

[tex]\bar x =6.77[/tex]

S.D = 0.21

[tex]I=6.77\pmt\times\frac{s}{\sqrt{n} }[/tex]

df = 24

α = 0.05

t = 2.064

[tex]I=6.77\pm2.064\times\frac{0.21}{\sqrt{25} } \\\\=6.77\pm0.087\\\\=[6.683,6.857][/tex]

b)

[tex]\sqrt{\frac{(1-n)s^2}{X^2_{\alpha /2} } < \mu <\sqrt{\frac{(1-n)s^2}{X^2_{1-\alpha/2} } }[/tex]

[tex]\sqrt{\frac{24 \times 0.21^2}{39.364} } < \mu <\sqrt{\frac{24 \times 0.21^2}{12.401} } \\\\=0.1640<\mu<0.2921[/tex]

The amount of coffee that people drink per day is normally distributed with a mean of 17 ounces and a standard deviation of 4 ounces. 15 randomly selected people are surveyed. Round all answers to 4 decimal places where possible.
a) What is the distribution of XX? XX ~ N(,)
b) What is the distribution of ¯xx¯? ¯xx¯ ~ N(,)
c) What is the probability that one randomly selected person drinks between 15.5 and 18 ounces of coffee per day?
d) For the 15 people, find the probability that the average coffee consumption is between 15.5 and 18 ounces of coffee per day.
e) For part d), is the assumption that the distribution is normal necessary? YesNo
f) Find the IQR for the average of 15 coffee drinkers.
Q1 = ounces
Q3 = ounces
IQR: ounces

Answers

Answer:

Step-by-step explanation:

(a)

The distribution of X is Normal Distribution with mean [tex]= \mu =17[/tex] and Variance [tex]= \sigma^{2} = 16 \ i.e., X \sim N (17, 16),[/tex]

(b)

The distribution of [tex]\bar{x}[/tex] is Normal Distribution with mean [tex]= \mu =17[/tex] and Variance = [tex]\sigma^{2}/n = 16/15= 1.0667[/tex].i.e., [tex]\bar{x}\sim N(17,1.0667)[/tex]

c)

To find P(15.5 < X < 18):

Case 1: For X from 15.5 to mid value:

Z = (15.5 - 17)/4 = - 0.375

Table of Area Under Standard Normal Curve gives area = 0.1480

Case 2: For X from mid value to 18:

Z = (18 - 17)/4 = 0.25

Table of Area Under Standard Normal Curve gives area = 0.0987

So,

P(15.5 < X< 18) = 0.1480 +0.0987 = 0.2467

So,

Answer is:

0.2467

(d)

[tex]SE = \sigma/\sqrt{n}\\\\= 4/\sqrt{15}[/tex]

= 1.0328

To find [tex]P(15.5 < \bar{x}< 18):[/tex]

Case 1: For [tex]\bar{x}[/tex] from 15.5 to mid value:

Z = (15.5 - 17)/1.0328 = - 1.4524

Table of Area Under Standard Normal Curve gives area = 0.4265

Case 2: For X from mid value to 18:

Z = (18 - 17)/1.0328 = 0.9682

Table of Area Under Standard Normal Curve gives area = 0.3340

So,

[tex]P(15.5 < \bar{x}< 18) = 0.4265 + 0.3340 = 0.7605[/tex]

So,

Answer is:

0.7605

(e)

Correct option:

No

because Population SD is provided.

(f)

(i)

Q1 is given by:

[tex]- 0.6745 = (\bar{x} - 17)/1.0328[/tex]

So,

X = 17 - (0.6745 * 1.0328) = 17 - 0.6966 = 16.3034

So,

Q1 = 16.3034

(ii)

Q3 is given by:

[tex]0.6745 = (\bar{x} - 17)/1.0328[/tex]

So,

X = 17 + (0.6745 * 1.0328) = 17 + 0.6966 = 17.6966

So,

Q3= 17.6966

(iii)

IQR = Q3 - Q1 = 17.6966 - 16.3034 = 1.3932

So

Answers are:

Q1 = 16.3034 ounces

Q3 = 17.6966 Ounces

IQR = 1.3932 Ounces

One angle of a right triangle measures 51 degrees. What is the measure of the other small angle?

Answers

Answer:

39 degrees

Step-by-step explanation:

Given

triangle is right angled i.e one angle is 90 degrees

other angle is 51 degrees.

let the third angle be x degrees

we know that sum of angles of any triangle is 180 degrees

thus,

90 + 51+ x = 180

=> 141 + x = 180

=> x = 180 - 141 = 39.

Thus, measure of other small angle is 39 degrees.

Answer:

Step-by-step explanation:

m∠A+m∠B+m∠C = 180

90+51+x1= 180

41+x=180

x=39

A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A quality control consultant is to select 4 of these workers for in-depth interviews. Suppose the selection is made in such a way that any particular group of 4 workers has the same chance of being selected as does any other group (drawing 4 slips without replacement from among 24).
(a) How many selections result in all 4 workers coming from the day shift? What is the probability that all 4 selected workers will be from the day shift? (Round your answer to four decimal places.)
(b) What is the probability that all 4 selected workers will be from the same shift? (Round your answer to four decimal places.)
(c) What is the probability that at least two different shifts will be represented among the selected workers? (Round your answer to four decimal places.)
(d) What is the probability that at least one of the shifts will be unrepresented in the sample of workers? (Round your answer to four decimal places.)

Answers

The probability that all 4 selected workers will be from the day shift is, = 0.0198

The probability that all 4  selected workers will be from the same shift is = 0.0278

The probability that at least two different shifts will be represented among the selected workers is = 0.9722

The probability that at least one of the shifts will be unrepresented in the sample of workers is P(A∪B∪C) = 0.5257

To solve this question properly, we will need to make use of the concept of combination along with set theory.

What is Combination?

In mathematical concept, Combination is the grouping of subsets from a set without taking the order of selection into consideration.  

The formula for calculating combination can be expressed as:

[tex]\mathbf{(^n _r) =\dfrac{n!}{r!(n-r)! }}[/tex]

From the parameters given:

Workers employed on the day shift = 10Workers on swing shift = 8Workers on graveyard shift = 6

A quality control consultant is to select 4 of these workers for in-depth interviews:

Using the expression for calculating combination:

(a)

The number of selections results in all 4 workers coming from the day shift is :

[tex]\mathbf{(^n _r) = (^{10} _4)}[/tex]

[tex]\mathbf{=\dfrac{(10!)}{4!(10-4)!}}[/tex]

= 210

The probability that all 5 selected workers will be from the day shift is,

[tex]\begin{array}{c}\\P\left( {{\rm{all \ 4 \ selected \ workers\ will \ be \ from \ the \ day \ shift}}} \right) = \dfrac{{\left( \begin{array}{l}\\10\\\\4\\\end{array} \right)}}{{\left( \begin{array}{l}\\24\\\\4\\\end{array} \right)}}\\\end{array}[/tex]

[tex]\mathbf{= \dfrac{210}{10626}} \\ \\ \\ \mathbf{= 0.0198}[/tex]

(b) The probability that all 4 selected workers will be from the same shift is calculated as follows:

P( all 4 selected workers will be) [tex]\mathbf{= \dfrac{ \Big(^{10}_4\Big) }{\Big(^{24}_4\Big)}+\dfrac{ \Big(^{8}_4\Big) }{\Big(^{24}_4\Big)} + \dfrac{ \Big(^{6}_4\Big) }{\Big(^{24}_4\Big)}}[/tex]

where;

[tex]\mathbf{\Big(^{8}_4\Big) = \dfrac{8!}{4!(8-4)!} = 70}[/tex]

[tex]\mathbf{\Big(^{6}_4\Big) = \dfrac{6!}{4!(6-4)!} = 15}[/tex]

P( all 4 selected workers is:)

[tex]\mathbf{=\dfrac{210+70+15}{10626}}[/tex]

The probability that all 4 selected workers will be from the same shift is = 0.0278

(c)

The probability that at least two different shifts will be represented among the selected workers can be computed as:

 [tex]= 1-\dfrac{ (^{10}_4) }{(^{24}_4)}+\dfrac{ (^{8}_4) }{(^{24}_4)} + \dfrac{ (^{6}_4) }{(^{24}_4)}[/tex]

[tex]=1 - \dfrac{210+70+15}{10626}[/tex]

= 1 - 0.0278

=  0.9722

The probability that at least two different shifts will be represented among the selected workers is = 0.9722

(d)

The probability that at least one of the shifts will be unrepresented in the sample of workers is:

[tex]P(AUBUC) = \dfrac{(^{6+8}_4)}{(^{24}_4)}+ \dfrac{(^{10+6}_4)}{(^{24}_4)}+ \dfrac{(^{10+8}_4)}{(^{24}_4)}- \dfrac{(^{6}_4)}{(^{24}_4)}-\dfrac{(^{8}_4)}{(^{24}_4)}-\dfrac{(^{10}_4)}{(^{24}_4)}+0[/tex]

[tex]P(AUBUC) = \dfrac{(^{14}_4)}{(^{24}_4)}+ \dfrac{(^{16}_4)}{(^{24}_4)}+ \dfrac{(^{18}_4)}{(^{24}_4)}- \dfrac{(^{6}_4)}{(^{24}_4)}-\dfrac{(^{8}_4)}{(^{24}_4)}-\dfrac{(^{10}_4)}{(^{24}_4)}+0[/tex]

[tex]P(AUBUC) = \dfrac{1001}{10626}+ \dfrac{1820}{10626}+ \dfrac{3060}{10626}-\dfrac{15}{10626}-\dfrac{70}{10626}-\dfrac{210}{10626} +0[/tex]

The probability that at least one of the shifts will be unrepresented in the sample of workers is P(A∪B∪C) = 0.5257

Learn more about combination and probability here:

https://brainly.com/question/9465501

https://brainly.com/question/25870256

which answer shows 9 x 10 ^ -5 written in standard form ?

A -0.000009
B -0.00009
C 0.0009
D 0.00009

Answers

Answer:

  D  0.00009

Step-by-step explanation:

9 × 10^-5 = 9 × 1/10^5 = 9 × 1/100,000

  = 9 × 0.00001

  = 0.00009

_____

Comment on place value

The exponent of 10 associated with the place value in a decimal number increases from 0 to the left of the decimal point, and decreases from -1 to the right of the decimal point:

  100. = 10²

  10. = 10¹

  1. = 10⁰

  0.1 = 10⁻¹

  0.01 = 10⁻²

  0.001 = 10⁻³

  0.0001 = 10⁻⁴

  0.00001 = 10⁻⁵

This simple realization can help you immensely with scientific notation.

Hello! I'm stuck on this problem. Can someone help me? Thanks!



The model below represents an equation.


2 long x tiles and 3 square 1 tiles = 3 long x tiles


Which represent like terms in the model of the equation?


2 long x tiles and 3 square 1 tiles

2 long x tiles and 3 long x tiles

3 long x tiles and 3 square 1 tiles

1 long x tile and 1 square 1 tile

Answers

Answer:

Answer is B

Step-by-step explanation:

This is because you can combine both the green tiles. With the other options, you can't combine them.

(also I did the test )

Answer:

The answer is in ur head lololol

Step-by-step explanation:

Its b

Skyler is out shopping and sees that striped shirts are on sale for
$19.00 each, and plaid pants are on sale for $19.50 each. He
buys 8 shirts and 6 pairs of pants. What is the total of his
purchase?

The total was $_______​

Answers

Answer:

His total is $269

Step-by-step explanation:

8x19 = 152

6x19.50 = 117

152+117 = 269

Can someone help me please

Answers

Answer:

the triangles are not similar.

the price of a CD that sells for 21% more than
the amount (m) needed to manufacture the CD

Answers

Answer:

I need more explanation is there more to the question?

not an answer but is this what your doing?

Simon makes 30 cakes he gives 1/5 of the cakes to sali he gives 10 percent of the 30 cakes to jane what fraction of the 30 cakes does he have left

Answers

Answer:

7/10 or 70% left

Step-by-step explanation:

total cakes=  30

Gave to Sali

30*1/5= 6 cakes

Gave to Jane

30*1/10= 3 cakes

Cakes left:

30- (6-3)=21

Cakes left fraction:

21/30= 7/10 or 70 %

Answer:

7/10

Step-by-step explanation:

Cakes Simon gave to Sali = 30*1/5

= 6

Cakes Simon Gave to Jane = 30 * 1/10

= 3

Cakes left = 30 - (6-3)

= 21

21 cakes were left, so in terms of a fraction, it'd be 21/30, which can be reduced to 7/10

Hope this helps!

what is the value of x?​

Answers

Answer:

x = 5

Step-by-step explanation:

52 = y since they are the base angles of an isosceles triangle and the base angles are equal

The sum of the angles of a triangle are 180

52+y+14x+6 =180

Substitute for y

52+52+14x+6 = 180

Combine like terms

110 + 14x = 180

Subtract 110 from each side

110+14x-110 = 180-110

14x =70

Divide by 14

14x/14 = 70/14

x =5

What are the next two numbers in the pattern of numbers;
45, 15, 44, 17, 40, 20, 31, 25, …

Answers

Answer:

Next two numbers are 15 and 32 respectively.

Step-by-step explanation:

The given pattern is  

45, 15, 44, 17, 40, 20, 31, 25, …

Here, we have two patterns.

Odd places : 45, 44, 40, 31,...

Even places : 15, 17, 20, 25,...

In series of odd places, we need to subtract square of integers.

[tex]45-(1)^2=45-1=44[/tex]

[tex]44-(2)^2=44-4=40[/tex]

[tex]40-(3)^2=40-9=31[/tex]

So, 9th term of given pattern is  

[tex]31-(4)^2=31-16=15[/tex]

In series of even places, we need to add prime numbers.

[tex]15-2=17[/tex]

[tex]17+3=20[/tex]

[tex]20+5=25[/tex]

So, 10th term of given pattern is  

[tex]25+7=32[/tex]

Therefore, the next two numbers in the pattern of numbers are 15 and 32 respectively.

What percentage of the total number of microstates are in one of the three most likely macro states of 100 coins being tossed (49 heads and 51 tails, 50 heads and 50 tails, or 51 heads and 49 tails)

Answers

Answer:

Step-by-step explanation:

Idk

A certain car can travel on a highway for 350 miles on 15 gallons of gas and in a city for 280 miles on 18 gallons of gas. If the car uses twice as many gallons for city driving as for highway driving, what is the car's average number of miles per gallon? Express your answer to the nearest whole number.

Answers

Answer:

The car's average 18 number of miles per gallon

Step-by-step explanation:

The car has different efficiencies depending if its used on highway or city streets.

The efficiency on a highway is:

[tex]E_h=\dfrac{350}{15}\;\text{miles/gal}=23.33\;\text{miles/gal}[/tex]

The efficiency for city driving is:

[tex]E_c=\dfrac{280}{18}\;\text{miles/gal}=15.56\;\text{miles/gal}[/tex]

We now that the car uses twice as many gallons for city driving as for highway driving. This means that, for every gallon consumed, 2/3 are for city driving and 1/3 are for highway driving.

Then, we can calculate how many miles makes the car on average as:

[tex]E=\dfrac{1}{3}E_h+\dfrac{2}{3}E_c\\\\\\E=\dfrac{1}{3}\cdot 23.33+\dfrac{2}{3}\cdot15.56=7.78+10.37=18.15\;\text{miles/gal}[/tex]

g Suppose you have $100 of endowment, and you are offered a chance to buy a lottery which costs $36. The lottery has 18% of chance to win a prize of $G, or you just lose and get nothing. Suppose your utility function on wealth is U(w)=\sqrt{w}. What is the least prize size G that you will be willing to buy the lottery?

Answers

Answer:

$301.23

Step-by-step explanation:

We have that the function of wealth is U (w) = w ^ (1/2)

So, since what you have at the start is 100, we replace:

U (w) = 100 ^ (1/2)

U = 10

Now we have two cases:

the first one we win, then the winnings would be 100 minus the cost of the lottery, that is 36 and to that add G of the prize:

100 - 36 + G = 64 + G

In the second case, where we lose, the subtraction of 100 that we have minus the cost of the lottery would be equal 36

100 - 36 = 64

Therefore, we have to win with an 18% probability, therefore losing would be 82% (100% - 18%)

0.18 * (64 + G) ^ (1/2) + 0.82 * 64 ^ (1/2)

solving:

0.18 * (64 + G) ^ (1/2) + 6.56

Now this is equal to U which is equal to 10:

10 = 0.18 * (64 + G) ^ (1/2) + 6.56

(10 - 6.56) /0.18 = (64 + G) ^ (1/2)

(64 + G) ^ (1/2) = 19.11

(64 + G) = 365.23

G = 365.23 - 64

G = 301.23

Therefore, the smallest G prize size that the lottery will be willing to buy is $ 301.23

In monitoring lead in the air after the explosion at the battery factory, it is found that the amounts of lead over a 6 day period had a standard error of 1.93. Find the margin of error that corresponds to a 95% confidence interval. (Round to 2 decimal places) 4.56

Answers

Answer:

1.54

Margin of error M.E = 1.54

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

x+/-M.E

Where M.E = margin of error

M.E = zr/√n

Given that

Standard deviation r = 1.93

Number of samples n = 6

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

M.E = (1.96×1.93/√6) = 1.544321633166

M.E = 1.54 (to 2 decimal place)

Margin of error M.E = 1.54

A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work properly. Assume the probability of one part working does not depend on the functionality of any of the other parts. Also assume that the probabilities of the individual parts working are P(A) = P(B) = 0.93, P(C) = 0.95, and P(D) = 0.92. Find the probability that the machine works properly.A) 0.8128B) 0.2441C) 0.8217D) 0.7559

Answers

Answer:

D) 0.7559

Step-by-step explanation:

Independent events:

If two events, A and B are independent:

[tex]P(A \cap B) = P(A)*P(B)[/tex]

In this question:

Four independent events, A, B, C and D.

So

[tex]P(A \cap B \cap C \cap D) = P(A)*P(B)*P(C)*P(D)[/tex]

Find the probability that the machine works properly.

This is the probability that all components work properly.

[tex]P(A \cap B \cap C \cap D) = P(A)*P(B)*P(C)*P(D) = 0.93*0.93*0.95*0.92 = 0.7559[/tex]

So the correct answer is:

D) 0.7559

if a polynomial is divided by (x-a) and the remainder equals zero, then (x-a) is a factor of the polynomial

Answers

Answer:

True.

Step-by-step explanation:

This is the basis for polynomial division/remainder theorem.

Given a polynomial p(x) and a divisor (x - a), if p(a) = 0, then the expression factors in perfectly.

Likewise, if the remainder in p(x)/(x-a) = 0, then the expression factors in perfectly.

I hope this helps!

Answer:

True

Step-by-step explanation:

a p e x

what is the value of x?​

Answers

Answer:

solution

Step-by-step explanation:

x=5

y=4

The answer is the value of x is 5

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (9-1(3)?

Answers

Answer:

( g − f ) ( 3 ) = 23

Step-by-step explanation:

(g-f)(x)=g(x)-f(x)

=6x-(4-X(2))

=x(2)+6x-4

to evaluate (g-f) (#) substitute x=3 into (g-f)(x)

(g-f)=(9)+(6 x 3) -4=23

Zia is building a plastic model rocket that has the combined shape of a cone and a cylinder as shown. additionally, the cylinder has a hemisphere hollowed out of its bottom. the plastic for the cone weighs 1.4 grams per cubic centimeter and the plastic for the cylinder weights only 0.8 grams per cubic centimeter.
(a) the volume of plastic that remains in the cylinder after it has been hollowed out to the nearest cubic centimeter.
(b) what has a greater total weight, the plastic that makes up the cone or the plastic that makes up the cylinder after it has been hollowed out?

Answers

Answer:

226 cm^3

The mass of plastic used to make cylinder is greater

Step-by-step explanation:

Given:-

- The density of cone material, ρc = 1.4 g / cm^3

- The density of cylinder material, ρl = 0.8 g / cm^3

Solution:-

- To determine the volume of plastic that remains in the cylinder after gouging out a hemispherical amount of material.

- We will first consider a solid cylinder with length ( L = 10 cm ) and diameter ( d = 6 cm ). The volume of a cylinder is expressed as follows:

                                  [tex]V_L =\pi \frac{d^2}{4} * L[/tex]

- Determine the volume of complete cylindrical body as follows:

   

                                 [tex]V_L = \pi \frac{(6)^2}{4} * 10\\\\V_L = 90\pi cm^3\\[/tex]

- Where the volume of hemisphere with diameter ( d = 6 cm ) is given by:

                                 [tex]V_h = \frac{\pi }{12}*d^3[/tex]

- Determine the volume of hemisphere gouged out as follows:

                                 [tex]V_h = \frac{\pi }{12}*6^3\\\\V_h = 18\pi cm^3[/tex]

- Apply the principle of super-position and subtract the volume of hemisphere from the cylinder as follows to the nearest ( cm^3 ):

                               [tex]V = V_L - V_h\\\\V = 90\pi - 18\pi \\\\V = 226 cm^3[/tex]

Answer: The amount of volume that remains in the cylinder is 226 cm^3

- The volume of cone with base diameter ( d = 6 cm ) and height ( h = 5 cm ) is expressed as follows:

   

                               [tex]V_c = \frac{\pi }{12} *d^2 * h[/tex]

- Determine the volume of cone:

                              [tex]V_c = \frac{\pi }{12} *6^2 * 5\\\\V_c = 15\pi cm^3[/tex]

- The mass of plastic for the cylinder and the cone can be evaluated using their respective densities and volumes as follows:

                             [tex]m_i = p_i * V_i[/tex]

- The mass of plastic used to make the cylinder ( after removing hemispherical amount ) is:

                           [tex]m_L = p_L * V\\\\m_L = 0.8 * 226\\\\m_L = 180.8 g[/tex]

- Similarly the mass of plastic used to make the cone would be:

                           [tex]m_c = p_c * V_c\\\\m_c = 1.4 * 15\pi \\\\m_c = 65.973 g[/tex]

Answer: The total weight of the cylinder ( m_l = 180.8 g ) is greater than the total weight of the cone ( m_c = 66 g ).

                             

The volume of the remaining plastic in the cylinder is large, which

makes the weight much larger than the weight of the cone.

Responses:

(a) Volume of the remaining plastic in the cylinder is 226 cm³(b) The weight of the cylinder is greater than the weight of the cone.

How can the weight and volume be evaluated?

Density of the plastic for the cone = 1.4 g/cm³

Density of the plastic used for the cylinder = 0.8 g/cm³

From a similar question, we have;

Height of the cylinder = 10 cm

Diameter of the cylinder = 6 cm

Height of the cone = 5 cm

(a) Radius of the cylinder, r = 6 cm ÷ 2 = 3 cm

Volume of a cylinder = π·r²·h

Volume of a hemisphere = [tex]\mathbf{\frac{2}{3}}[/tex] × π×  r³

Volume of the cylinder after it has been hollowed out, V, is therefore;

[tex]V = \mathbf{\pi \times r^2 \times h - \frac{2}{3} \times \pi \times r^3}[/tex]

Which gives;

[tex]V = \pi \times 3^2 \times 10 - \frac{2}{3} \times \pi \times 3^3 \approx \mathbf{ 226}[/tex]

Volume of the cylinder after it has been hollowed out, V ≈ 226 cm³

(b) Volume of the cone = [tex]\mathbf{\frac{1}{3}}[/tex] × π × 3² × 5 47.1

Mass of the cone = 47.1 cm³ × 1.4 g/cm³ ≈ 66 g

Mass of the hollowed cylinder ≈ 226 cm³ × 0.8 g/cm³ = 180.8 g

The mass and therefore, the weight of the plastic that makes up the hollowed cylinder is greater than the weight of the plastic that makes up the cone.

Learn more about volume and density of solids here:

https://brainly.com/question/4773953

Any help would be appreciated

Answers

Answer:

increase 40

% increase is 40 %

Step-by-step explanation:

Take the new amount and subtract the original amount

140-100 = 40

Divide by the original amount

40/100

.40

Multiply by 100 %

40%

The percent increase is 40%

The answer is 40%

1. Divide 40/100 and you will get 0.40
2. multiply 0.40 times 100 because of the 100%

Therefore, ur answer is 40%

A stone is thrown vertically into the air at an initial velocity of 79 ​ft/s. On a different​ planet, the height s​ (in feet) of the stone above the ground after t seconds is sequals79tminus3t squared and on Earth it is sequals79tminus16t squared. How much higher will the stone travel on the other planet than on​ Earth?

Answers

Answer:

[tex]13t^2[/tex] feet higher the stone will travel on the other plant than on Earth.

Step-by-step explanation:

Initial velocity of the stone thrown vertically = 79 ft/s

It is given that:

Height attained on a different planet with time [tex]t[/tex]:

[tex]s_p = 79t -3t^2[/tex]

Height attained on Earth with time [tex]t[/tex]:

[tex]s_e = 79t -16t^2[/tex]

If we have a look at the values of [tex]s_p\text{ and }s_e[/tex], it can be clearly seen that the part [tex]79t[/tex] is common in both of them and some values are subtracted from it.

The values subtracted are [tex]3t^2\text{ and } 16t^2[/tex] respectively.

[tex]t^2[/tex] can never be negative because it is time value.

So, coefficient of [tex]t^2[/tex] will decide which is larger value that is subtracted from the common part i.e. [tex]79t[/tex].

Clearly, [tex]3t^2\text{ and } 16t^2[/tex] have [tex]16t^2[/tex] are the larger value, hence [tex]s_e < s_p[/tex].

So, difference between the height obtained:

[tex]s_p - s_e = 79t - 3t^2 - (79t - 16t^2)\\\Rightarrow 79t -3t^2 - 79t + 16t^2\\\Rightarrow 13t^2[/tex]

So, [tex]13t^2[/tex] feet higher the stone will travel on the other plant than on Earth.

What is the approximate length of minor arc LM? Round to
the nearest tenth of a centimeter.
12.4 centimeters
15.7 centimeters
31.4 centimeters
36.7 centimeters

Answers

Answer:its 15.7

Step-by-step explanation:

Answer:

15.7

Step-by-step explanation:

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