Answer:
which sport are you referring to?
Explanation:
A 500 kg roller coaster moving at 15 m/s suddenly comes to a stop at the end of the ride. How much work energy was needed to stop the coaster?
Answer:
energy required=-energy lost
energy lost=change in kinetic energy
EL=1/2 mv^2
The amplitude of a wave is measured from the crest of one wave to the crest of the next. Question 3 options: True False
Answer:
answer is FALSE
Explanation:
AMPLITUDE IS THE MAXIMUM AMOUNT OF DISPLACEMENT OF A PARTICLE ON THE MEDIUM FROM ITS REST POSITION
AND WAVELENGTH can be measured as crest to crest
Amplitude of a wave is the strength of the wave. It is measured from the central line of the wave to the top of the crest or bottom of the trough. Therefore, the statement is false.
What is amplitude?Amplitude is a parameter measuring the strength of a wave. It is the maximum displacement moved by the wave from its equilibrium position. The vibrational path will be twice that of the amplitude of the wave.
As the amplitude of the wave increases its intensity increases. Both are in direct proportion with the frequency and energy of a wave. For instance the amplification of sound waves increases the intensity of waves that we hear.
The distance between two consecutive crests or troughs is the wavelength of the wave not amplitude. Amplitude is measured from the axis line to the top of the crest thus, from exact middle of the wave crest to the top or to the bottom of trough. Thus, the statement is false.
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The first stage of a space vehicle consumed fuel and oxidizer at the rate of 1.75 x 104 kg/s, with an exhaust speed of 2.40 x 103 m/s. Find the acceleration (in m/s2) of the vehicle just as it lifted off the launch pad on the Earth, if the vehicle's initial mass was 3.00 x 106 kg. (Note: You must include the force of gravity to solve the problem.)
Answer:
[tex]a=4.19 m/s^{2}[/tex]
Explanation:
In order to solve this problem, we must first draw a free body diagram of the situation. (See attached picture)
from this diagram, we can do the following sum of forces:
[tex]\sum F=ma[/tex]
where m is the mass of the rocket and a is its acceleration.
[tex]F_{e}-mg=ma[/tex]
where [tex]F_{e}[/tex] is the force of exhaust. We can solve this for the acceleration, so we get:
[tex]a=\frac{F_{e}-mg}{m}[/tex]
we can find the force of exhaust by using the momentum formula:
Ft=mv
so we can solve this for the force:
[tex]F_{e}=\frac{mv}{t}[/tex]
the problem already tells us what m/t is equal to, so we can directly substitute:
[tex]F_{e}=(1.75x10^{4}kg/s)(2.40x10^3m/s)[/tex]
which yields:
[tex]F_{e}=42x10^6 N[/tex]
So we can now substitute:
[tex]a=\frac{42x10^6N-(3x10^6kg)(9.81m/s^{2})}{3x10^6kg}[/tex]
so:
[tex]a=4.19 m/s^{2}[/tex]
What is 50 degrees f in kelvin
Answer:
283.15
Explanation:
looked it up
there's a handy calculator
Answer: C.
283 K
Explanation: edmentum
In class, Kelsey stops paying attention to the lesson and begins to focus on tapping her pencil on her desk. Her teacher slowly walks to Kelsey’s desk and gently takes her pencil from her. How would behaviorist B.F. Skinner MOST likely describe this response?
Answer:
I think it might be negative reinforcement.
Explanation:
Answer:
negative reinforcement
Explanation:
Can someone please help, ty!!
(Will mark brainliest)
If a change in speed “Δv” occurs and the mass starts at rest, would the change in speed also equal the final speed of the mass?
Yes, if the mass starts at rest, the change in speed will be equal the final speed, because:
Δv = Vf - Vo
How Vo (Initial velocity) is equal zero, we simplificate:
Δv = Vf
Then, the change of the speed, if the mass starts at rest, will be equal to final velocity.
Greetings.
Describe a volcanic hazard and explain how it could become a natural disaster.
do waves change direction when they travel from one material to another.
If an element has a mass number of 200 and an atomic number of 80, how many neutrons does the element have?
A. 80
B. 280
C. 120
D. 200
Answer:
If I say the correct answer is B.280
write hydrometer uses
Answer: hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats.
Explanation:
*A car is going over the top of a hill whose curvature approximates a circle of radius 350m. At what velocity will the occupants of the car appear to weigh 10% less than their normal weight
Answer:
v= 18.5 m/s
Explanation:
When at the top of the hill, the only force that keeps the car in the circular trajectory, is the centripetal force. This force is not a new force, is just the net force aiming to the center of the circle. In this case, is just the difference between the normal force (always perpendicular to the surface, pointing upward) and the force that gravity exerts on the car (which is known as the weight), pointing downward. So, we can write the following expression:[tex]F_{cent} = F_{g} - F_{n} (1)[/tex]
It can be showed that the centripetal force is related to the speed by the following expression:[tex]F_{cent} = m*\frac{v^{2}}{r} (2)[/tex]
The normal force, it is called the apparent weight, because it would be the weight as measured by a scale. Replacing (2) in (1), and solving for Fn, we get:[tex]F_{n} = F_{g} - m*\frac{v^{2}}{r} (3)[/tex]
Now, we need to find the value of v that makes Fn, exactly 10% less than the normal weight (m*g), so we can write the following equation:[tex]0.9*F_{g} = F_{g} - m*\frac{v^{2}}{r} (4)[/tex]
Replacing Fg by its value, simplifying, and solving for v, we get:[tex]v =\sqrt{0.1*g*r} =\sqrt{0.1*9.8m/s2*350m} = 18.5 m/s (5)[/tex]The velocity the occupants of the car appear to weigh 10% less than their normal weight is 18.52 m/s.
The given parameters:
Radius of the curvature, r = 350 mApply the principle of conservation of energy to determine the velocity the occupants of the car appear to weigh 10% less than their normal weight;
[tex]F_c = mg\\\\\frac{mv^2}{r} = mg\\\\v^2 = gr\\\\v = \sqrt{gr} \\\\v = \sqrt{0.1 \times 9.8 \times 350}\\\\v = 18.52 \ m/s[/tex]
Thus, the velocity the occupants of the car appear to weigh 10% less than their normal weight is 18.52 m/s.
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A spring is 50 cm in length when not compressed. The spring is then compressed by 35 cm by a force of 100N What is the k value of this spring?
Answer:
k=6.666
Explanation:
F=kx
100=k 50-35
100=k*15
k=6.666
A brick of gold is 0.1 m wide, 0.1 m high, and 0.2 m long. The density of gold is 19,300 kg/m3. What pressure does the brick exert on the table if the brick is resting on its side?
Answer:
The pressure exerted by the brick on the table is 18,933.3 N/m².
Explanation:
Given;
height of the brick, h = 0.1 m
density of the brick, ρ = 19,300 kg/m³
acceleration due to gravity, g = 9.81 m/s²
The pressure exerted by the brick on the table is calculated as;
P = ρgh
P = (19,300)(9.81)(0.1)
P = 18,933.3 N/m²
Therefore, the pressure exerted by the brick on the table is 18,933.3 N/m².
A hockey puck moves 22 meters northward, then 16 meters southward, and finally 4 meters northward.
For this motion, what is the distance moved?
What is the magnitude and direction of the displacement?
Answer:
Distance moved = 42 meters
Mag and Dir = 10 meters northward
Explanation:
Distance is total distance traveled which = 22+16+4 = 42 meters
Displacement is the amount of distance moved from the start point to the end point straight line so our equation for the magnitude is 22-16+4 = 10 meters. Then the direction is northward from the start point. This answer would also be a vector because it has a magnitude and direction.
A LOT OF POINTS!! Best answer gets brainliest!
1) Which two of the following factors affect the momentum of an object: speed, velocity, mass, shape?
2) Can a small object can have a large momentum? Give an example.
3) How could you change the momentum of an object? What would you need to change?
4) A 5000kg truck and a 50 kg person have the same momentum. How is this possible?
newtonion mechanics defination
Planet 1 orbits Star 1 and Planet 2 orbits Star 2 in circular orbits of the same radius. However, the orbital period of Planet 1 is longer than the orbital period of Planet 2. What could explain this
Answer:
The mass of Star 2 is Greater than the mass of Start 1. (This, if we suppose the masses of the planets are much smaller than the masses of the stars)
Explanation:
First of all, let's draw a free body diagram of a planet orbiting a star. (See attached picture).
From the free body diagram we can build an equation with the sum of forces between the start and the planet.
[tex]\sum F=ma[/tex]
We know that the force between two bodies due to gravity is given by the following equation:
[tex]F_{g} = G\frac{m_{1}m_{2}}{r^{2}}[/tex]
in this case we will call:
M= mass of the star
m= mass of the planet
r = distance between the star and the planet
G= constant of gravitation.
so:
[tex]F_{g} =G\frac{Mm}{r^{2}}[/tex]
Also, if the planet describes a circular orbit, the centripetal force is given by the following equation:
[tex]F_{c}=ma_{c}[/tex]
where the centripetal acceleration is given by:
[tex]a_{c}=\omega ^{2}r[/tex]
where
[tex]\omega = \frac{2\pi}{T}[/tex]
Where T is the period, and [tex]\omega[/tex] is the angular speed of the planet, so:
[tex]a_{c} = ( \frac{2\pi}{T})^{2}r[/tex]
or:
[tex]a_{c}=\frac{4\pi^{2}r}{T^{2}}[/tex]
so:
[tex]F_{c}=m(\frac{4\pi^{2}r}{T^{2}})[/tex]
so now we can do the sum of forces:
[tex]\sum F=ma[/tex]
[tex]F_{g}=ma_{c}[/tex]
[tex]G\frac{Mm}{r^{2}}=m(\frac{4\pi^{2}r}{T^{2}})[/tex]
in this case we can get rid of the mass of the planet, so we get:
[tex]G\frac{M}{r^{2}}=(\frac{4\pi^{2}r}{T^{2}})[/tex]
we can now solve this for [tex]T^{2}[/tex] so we get:
[tex]T^{2} = \frac{4\pi ^{2}r^{3}}{GM}[/tex]
We could take the square root to both sides of the equation but that would not be necessary. Now, the problem tells us that the period of planet 1 is longer than the period of planet 2, so we can build the following inequality:
[tex]T_{1}^{2}>T_{2}^{2}[/tex]
So let's see what's going on there, we'll call:
[tex]M_{1}[/tex]= mass of Star 1
[tex]M_{2}[/tex]= mass of Star 2
So:
[tex]\frac{4\pi^{2}r^{3}}{GM_{1}}>\frac{4\pi^{2}r^{3}}{GM_{2}}[/tex]
we can get rid of all the constants so we end up with:
[tex]\frac{1}{M_{1}}>\frac{1}{M_{2}}[/tex]
and let's flip the inequality, so we get:
[tex]M_{2}>M_{1}[/tex]
This means that for the period of planet 1 to be longer than the period of planet 2, we need the mass of star 2 to be greater than the mass of star 1. This makes sense because the greater the mass of the star is, the greater the force it applies on the planet is. The greater the force, the faster the planet should go so it stays in orbit. The faster the planet moves, the smaller the period is. In this case, planet 2 is moving faster, therefore it's period is shorter.
Determine the momentum of a 15,000 kg truck traveling at 15 m/s
Answer:
mass*velocity=1.5*10^4 * 15
= 22.5*10^4
simple but not plagiarized answer for "what is forces and motion?"
1. A small metal weight is suspended from a spring
scale as shown in this illustration
Spring Scale
N
1.0
2.0
3.0
4.0- The spring is measure here at 4.0 N
5.0
6.0
7.0
8.0
9.0
10.0
• What is the gravitational force acting on the weight? Explain.
• What is the net force acting on the weight? Explain.
Answer:
a) W = -4N, b) F_net = 0
Explanation:
The suspended weight of the spring ladder is subjected to two forces: the elastic force of the spring directed downwards and the gravitational force directed downwards.
[tex]F_{e}[/tex] - W = 0
F_{e} = W
F_{e} = W = 4 N
a) the gravitational force is the weight of the body
W = -4N
b) as the system is in equilibrium, the net force is zero
F_net = 0
*please answer asap, thank u*
Light gets dimmer as you get farther away from a source according to the inverse square law (like in the previous question). Why do you think it is so challenging for astronomers to view stars and galaxies that are millions or billions of light years away from Earth?
astronomers have a difficult time viewing stars and galaxies millions or billions of light years away because they're just so far away. based on the number of light years they are away, that number represents how long the light from that object took, in order to reach that astronomers eyes. so in reality, they're looking at the past when studying objects that insanely far away. if a star is 1 million light years away, that means the light from that star will take 1 million years to reach your position. so considering the distance that an object is in space and relative to an astronomers position, it's quite expected for it to become harder to view. the farther an object is from sight, the harder it is to see.
i hope this helps!
Which object would be considered to be in free fall? one that experiences both friction and centripetal force. one that is truly weightless. one that is slowed down by air resistance. one with only gravity acting upon it
Answer:
D
Explanation:
Edge 2021
When just gravity is operating on an object, which is said to be in free fall.
In volleyball, why is it referred to as a free ball?The team is unable to set up the spike because the ball is at the rear of the court and has already been hit twice. Knowing this, the team receiving the ball shouts "free ball!" to signal everyone to get ready to start their offense as soon as they get possession of it.
In the hood, what does "play ball" mean?informal idiom to consent to assisting or collaborating with someone as indicated by them: His family wanted him cared for at residence, but the insurance provider was uncooperative.
To learn more about: Free ball
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Three are used to power a portable electronic device
identical batteries with E = 2.5 V each and negligible internal resistances,
connected in series. If inadvertently one of the batteries was
mounted with reverse polarity, what is the value of the supplied voltage
system?
Explanation:
Here two internal resistances are in parallel so equivalent internal resistance r
eq
=1∣∣1=
1+1
1×1
=1/2=0.5Ω
According to maximum power theorem the power will be max when internal resistance is equal to external resistance. since, r
eq
=R=0.5Ω
Maximum current through R is I
max
=
r
eq
+R
V
=
0.5+0.5
2
=2A
Maximum power is P
max
=I
max
2
R=2
2
×0.5=2W
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It is a general exercise that we do before practicing sports activities
worm-up or cool down
It is called a warm-up.
Answer:
We do warm-ups before we exercise. We do cool-downs after we exercise.
Explanation:
Warming up can help you get ready to do the actual exercise, so you are prepared.
Paul is pushing the wheelbarrow in his garden to the east. His friend John comes along and starts pushing it in the opposite direction, to the west, with a force that's twice as great as Paul's. What can you say about the motion of the wheelbarrow?
A. It will move faster than before, to the east.
B. It will move in the direction of johns push, to the west.
C. It will move with the same speed and in the same direction as before, to the east.
D. It will stop moving immediately.
Answer:
The answer is B
Explanation:
It will move in the direction of johns push, to the west
Answer:
It will move in the direction of John's push, to the west.
Explanation:
Plato/Edmentum
Newton's third law of motion states that if one object exerts a force on another object
O the forces on both objects will always be balanced
O both objects will accelerate in opposite directions
O the forces on both objects will always cancel out
O the second object exerts an equal but opposite force
Answer:
the bottom one
Explanation:
Answer:
the second object exerts an equal but opposite force
Explanation:
its right
If you, a physics student, weigh about 70 kg, are standing on the surface of 1
the Moon, who's mass is 7.34 x 10^22 kg what is the force of gravity acting
on the Moon and yourself? The radius of the Moon is 1.71 x 10^6 m.
25 units
400 units
117 N
200 N
Answer:
it's answer is 117 N
F = Gm1m2/r^2
F = 6.67 * 10 ^-11 * 70 * 7.34 * 10 ^22/(1.71 * 10 ^6)^2
F = 117 N
hope it helps you
Identify the mathematical proportion that relates electrostatic force and displacement for a pair of charged particles.
A. Direct linear
B. Inverse
C. Quadratic
D. Inverse square
Answer:
D. Inverse square
Explanation:
According to the information you are giving me, you must be referring to Coulomb's law because the electrostatic force in proportion to the displacement of charged particles is [tex] F =\frac{kq_{1}q_{2}}{r²} [/tex].
As you can see, there is a reason as to why this is also referred to as Coulomb's inverse square law because the r² represents the displacement or distance relative to the position of the particles which is squared, and it is inverse because the force and the product of the distance squared is equal to the product of the two charges particles multiplied by coulomb's constant (k) which is approximately 8.9875517923×10⁹ kg⋅m³⋅s⁻²⋅C⁻².
The mathematical proportion that relates electrostatic force and displacement for a pair of charged particles is Inverse square. Hence, option (D) is correct.
What is electrostatic force?The electrostatic force is an attractive and repulsive force caused by the electric charges of particles. The electrostatic force is the electric force that exists between two stationary charged bodies. It is also known as Coulomb's force.
Hence, electrostatic force inversely proportional to the distance between two charges. If two charges Q and q are separated by a distance r, the magnitude of electrostatic force between them is given by:
F = kQq/r²
So, the mathematical proportion that relates electrostatic force and displacement for a pair of charged particles is Inverse square. Hence, option (D) is correct.
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what is the average gravitational force of attraction between the earth and the sun? the earth averages a distance of about 150 million km. the earth has a mass of 5.97x10^24 kg, and the sun has a mass of about 2x10^30 kg.
Answer:
B
Explanation:
Hhhhh