Which of the following statements about CASE is not true?CASE tools provide automated graphics facilities for producing charts.CASE tools reduce the need for end user participation in systems development.CASE tools have capabilities for validating design diagrams and specifications.CASE tools support collaboration among team members.CASE tools facilitate the creation of clear documentation

Explanation:

1. I grew up in a small community and my family owned a small business which involved manual labor. Although, having little income, my Dad sought to give us the best education he could afford from his little savings. With the small family savings I went to college where I studied Information Technology, after graduating I worked for a startup firm for two years before I decided to proceed with post graduate studies and I attained my Masters in UA. I met a friend who recommended I study in University of Cumberlands, I hesitated initially but was convinced after I researched the institution.

2. I'm particularly interested in the applications of information technology in labor intensive businesses and work because of my family background.

3. I have my own startup firm that designs work communication software for companies, however I intend to broaden my knowledge through this program into Information Technology based systems using machine learning algorithm.

4. I am committed to work and study, as some have called me a curious mind because of my passion towards learning.

5. I view obtaining a doctorate as not just a personal achievement but of lasting benefits to society as I use knowledge derived to improve the work experience of society.

I am confident that after my program I would be one the renowned contributors to the applications of information technology in labor intensive businesses.

Answer:

6

Explanation:

Answer:

4

Explanation:

It is between 3 and 13. Please answer some of my questions too! :)

Answer:

I would say cclrearner

Explanation:

This is what helped me with my computer so it may help you but try which one works for you

Explanation:

search engine because it helps to search find what you are expecting to search in the google.

The specification should be developed to help your mother buy her hardware and software on her own is hardware.

Hardware refers back to the computer's tangible additives or shipping structures that shop and run the written commands furnished through the software program. The software program is the intangible a part of the tool that shall we the consumer have interaction with the hardware and command it to carry out unique tasks.

Read more about the hardware :

https://brainly.com/question/3273029

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Answer:

The pseudocode is as given below in the explanation while the flow diagram is attached herewith

Explanation:

The pseudocode is as follows

input cust_name, num_texts  

Set Main_bill=5 $;

if the num_texts is less than or equal to 60

Excess_Charge=0;

If the num_texts is greater than 60 and less than or equal to 200

num_text60200 =num_texts-60;

Excess_Charge=0.1*(num_text60200);

else If the num_texts is greater than 60

num_texts200 =num_texts-200;

Excess_Charge=0.25*(num_texts200)+0.1*(200-60);

Display cust_Name

Total_Bill=Main_bill+Excess_Charge;

Total_Bill_after_Tax=Total_Bill*1.12;

Answer:

Numeric Addition

Explanation:

Literally, the + sign is an arithmetic operator used to perform addition operation between numeric datatypes (integer, float, decimal, double, long integer, etc...)

Its default built in function of the plus is sign is to add variables, constants and/or expressions.

The plus sign is used as follows;

a = 5;

b = 3;

c = a + b

-------------

a + b = 5 + 3 = 8

8 will be saved in variable c. This is only possible using the plus sign.

The plus sign also has other function such as string concatenation but this function is language dependent (i.e. some programming languages do not use + for string concatenation).

Conclusively, the built in function of the plus sign is for numeric addition

Answer:

Given: K(x,y) denotes statement:

"x knows y"

D denote domain of all people.

Explanation:

1. Everybody knows somebody.

Solution:

∀x∈D ∃y∈D : K(x, y)

∀ means for all. Here it is used for Everybody.

∃ means there exists some. Here it represents Somebody.

∈ means belongs to . Both x and y belongs to the domain D of all people.

2. There is somebody that no one knows.

Solution:

∀x∈D ∃y∈D : ¬K(x, y)

∀ means for all. ∃ means there exists some. ∈ means belongs to both x and y belongs to the domain D of all people.¬ this is negation sign which means not K(x,y). So the negation of everybody knows somebody can be expressed as there is somebody that no one knows.

3. There is no one who knows everybody

Solution:

This can be represented in both the ways below.

∀ y∈D ∃ x∈D : K(x, y)

∀ means for all. ∃ means there exists some. ∈ means belongs to both x and y belongs to the domain D of all people.

∀x∈D ∀y∈D : ¬K(x, y)

∀ means for all. The negation shows that there is no one who knows everybody.

Answer:

Network Operating System (NOS)

Explanation:

A network operating system (NOS) is an operating system that makes different computer devices connect to a common network in order to communicate and share resources with each other using a server. A network operating system can be used by printers, computers, file sever among others, and they are connected together using a local area network. This local area network which they are connected to works as the server.

The NOS also acts as a network security because it could be used as an access control or even user authentication.

There are two types of NOS

1) Peer to peer network operating system.

2) Client/server network operating system

A network operating system (NOS) is a server-based operating system oriented to computer networking and may include directory services, network management, network monitoring, network policies, user group management, network security, and other network-related functions.

Answer:

(a)The CPU B should be  selected for the new computer as it has a low clock cycle time which implies that it will implement the process or quicker when compared to the CPU A.

(b) The CPU B is faster because it executes the same number of instruction in a lesser time than the CPU A .

Explanation:

Solution

(a)With regards to  the MIPS performance metric the CPU B should be chosen for the new computer as it low clock cycle time which implies that it will implement the process or quicker when compared to the CPU A and when we look at the amount of process done by the system , the CPU B is faster when compared to other CPU and carries out same number of instruction in time.

The metric of response time for CPU B is lower than the CPU A and it has advantage over the other CPU and it has better amount as compared to CPU A, as CPU B is carrying out more execution is particular amount of time.

(b) The execution can be computed as follows:

Clock cycles taken for a program to finish * increased by the clock cycle time = the Clock cycles for a program * Clock cycle time

Thus

CPU A= 5*10^6 * 60*10^-9 →300*10^-3 →0.3 second (1 nano seconds =10^-9 second)

CPU B= 3 *10^6 * 75*10^-9 → 225*10^-3 → 0.225 second

Therefore,The CPU B is faster as it is executing the same number of instruction in a lesser time than the CPU A

Answer: Provided in the explanation section

Explanation:

(a). BIND is a type of DNS server used on the internet, actually it is reported to be most widely used DNS server on the internet. Also BIND is the de-facto standard on Unix like operating systems and Linux. Thus it can be used to locate computers on a network using domain names instead of their IP addresses. BIND was originally programmed at the University of California, Berkeley in the 1980s, this was made possible by a grant from US based DARPA program.

Originally, BIND stood for Berkeley Internet name daemon, but nowadays it is called Berkeley Internet name domain.

(b). In some of the clients in windows and Windows servers we will install LDP. By the LDP.exe we can test tDNS, Active directory woking , even we can add or modify. LDP is used to test and verify the Active Directory objects. We will install in windows machine then open the software, then from the menu we will select connect and type the IP adress of the Active Directory then we will select or type the objects of Active directory. For Linux system we have to openldap and can search the AD.

From Linux or Unix we can use the nmap tool which can test the network connectivity between all the computers whether it is windows or Linux. By nmap we can test by ICMP protocol to verify the network connectivity. By nmap we can scan all the port which are required to open from client to the server. We can also use nslookup to test DNS server from the client. By nslookup we can check that client can connect the server.

Using the knowledge in computational language in C++ it is possible to write a code that complete main() to read dates from input, one date per line

#include <iostream>

#include <string>

using namespace std;

int DateParser(string month) {

  int monthInt = 0;

  if (month == "January")

      monthInt = 1;

  else if (month == "February")

      monthInt = 2;

  else if (month == "March")

      monthInt = 3;

  else if (month == "April")

      monthInt = 4;

  else if (month == "May")

      monthInt = 5;

  else if (month == "June")

      monthInt = 6;

  else if (month == "July")

      monthInt = 7;

  else if (month == "August")

      monthInt = 8;

  else if (month == "September")

      monthInt = 9;

  else if (month == "October")

      monthInt = 10;

  else if (month == "November")

      monthInt = 11;

  else if (month == "December")

      monthInt = 12;

  return monthInt;

}

int main ()

{

  // TODO: Read dates from input, parse the dates to find the one

  // in the correct format, and output in m/d/yyyy format

  while(1)

  {

   //declaring the required variables

  int monthInt,dayInt,yearInt;string input;

  //receive the input string frim the user

  getline(cin,input);

  //if the input is -1 then quit

  if(input=="-1")

    break;

  //else try to process the input

  try

  {

  //find and extract the month name and parse it to monthInt

  monthInt=DateParser(input.substr(0,input.find(' ')));

  //find and extract the day and parse it to dayInt

  dayInt=stoi(input.substr(input.find(' '),input.find(", ")));

  //find and extract the year and parse it to yearInt

  yearInt=stoi(input.substr(input.find(", ")+1,input.length()));

  //display the output

  cout<<monthInt<<"/"<<dayInt<<"/"<<yearInt<<endl;

  }

  //catch if any of the exceptions happens

  catch(exception& e){}

  }

}

See more about C++ at brainly.com/question/19705654

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Answer:

Option B: Attack

Explanation:

A security attack is an act to access to a system without a legit authorization. Usually the aim is to steal confidential info from the system or control the system by manipulating the data stored in the system. Some attacks are also aimed to disable the operation of the hacked system. Nowadays, there are several common types of security attacks which include

Answer:

Explanation:

a.  

// Rewriting the given function without using any square brackets

double computeAverage(const double* scores, int nScores)

{

const double* ptr = scores;

double tot = 0;

int i;//declaring integer variable

for(i=0;i<nScores;i++)

{

//using an integer variable i to visit each double in the array

tot += *(ptr+i);

}

return tot/nScores;

}

b.

// Rewriting the given function without using any square brackets

const char* findTheChar(const char* str, char chr)

{

for(int k=0;(*(str+k))!='\0';k++)

{

if ((*(str+k)) == chr)

return (str+k);

}

return nullptr;

}

c.

//Now rewriting the function shown in part b so that it uses neither square brackets nor any integer variables

const char* findTheChar(const char* str, char chr)

{

while((*str)!='\0')

{

if ((*str) == chr)

return (str);

str++;

}

return nullptr;

}

Answer: provided in the explanation section

Explanation:

// code to copy

Car.java

public class Car {

  public void m1()

  {

  System.out.println("car 1");

}

  public void m2() {

      System.out.println("car 2");

}

  public String toString()

  {

  return "vroom";

}

}

Truck.java

public class Truck extends Car{

  public void m1()

  {

  System.out.println("truck 1");

  }

  public void m2()

  {

  super.m1();

  }

  public String toString()

  {

      return super.toString() + super.toString();

  }

}

MonsterTruck​​​​​​​.java

public class MonsterTruck extends Truck

{

  public void m1() {

System.out.println("monster 1");

}

public void m2() {

super.m1();

super.m2();

}

public String toString() {

return "monster " + super.toString();

}

public static void main(String[] args) {

  MonsterTruck mt=new MonsterTruck();

  mt.m1();

  mt.m2();

  System.out.println(mt);

}

}

cheers i hope this helped !!!

Answer:

The correct usage is a NOR gate which is indicated in the explanation.

Explanation:

The truth table for the given two signals, namely

p=unplugged signal

q=low battery signal

can  form a truth table of following form

Here p has 2 states

1 if the power supply is connected

0 otherwise

Similarly q has 2 states

0 if the battery has reached almost zero state

1 otherwise

As the condition for the Hibernate Signal is given as to only activate when the battery is low and the power supply is not connected. This indicate that the value of Hibernate signal should be 1 when both p and q are 0.

Using this condition, the truth table is formed as

unplugged signal | low battery signal |  Hibernate Signal

            0               |                 0             |             1

            0               |                 1              |             0

            1                |                 0             |             0

            1                |                 1              |             0

Now the truth table of NOR is given as

a    |     b    |  a or b   |   ~(a or b)

0    |     0    |      0      |        1

0    |     1     |      1       |        0

1     |     0    |      1       |        0

1     |     1     |      1       |        0

This indicates that the both truth tables are same thus the NOR gate is to be used for this purpose.

Answer:

Explanation:

MIPS program which increments from 0 to 15 and display results in Decimal on the console

In this program the user defined procedures print_int and print_eot were used to print the integer values and new line characters(\n) respectively.the mechanisam of the loop is explaine in the comment section of the program.

     addi $s0, $0, 0

     addi $s1, $0, 15

print_int:

              li $v0, 1                # system call to print integer

              syscall                

              jr $ra                     # return

print_eol:                      # prints "\n"

            li $v0, 4            

              la $a0, linebrk      

              syscall              

              jr $ra                  # return

main: . . .          

              li $a0, 0                # print 0

              jal print_int         # print value in $a0

loop:   move $a0, $s0           # print loop count

       jal print_int        

       jal print_eol           # print "\n" character

       addi $s0, $s0, 1        # increment loop count by 1

       ble $s1, $s0, loop      # exit if $s1<$s0

beq $s0, $0, end

end:

MIPS progam to increment from 0 to 15 and display results in Hexadecimal on the console

this program is slightly differed from the previous program in this program the system call issued in print_int is implemented with a system call that prints numbers in hex.

addi $s0, $0, 15

     addi $s1, $0, 0

print_int:

   li      $v0,34                  # syscall number for "print hex"

   syscall                         # issue the syscall

              jr $ra                     # return

print_eol:                      # prints "\n"

            li $v0, 4            

              la $a0, linebrk      

              syscall              

              jr $ra                  # return

main: . . .          

              li $a0, 0                # print 0

              jal print_int         # print value in $a0

loop:   move $a0, $s0           # print loop count

       jal print_int        

       jal print_eol           # print "\n" character

       addi $s0, $s0, 1        # increment loop count by 1

       ble $s1, $s0, loop      # exit if $s0>$s1

beq $s0, $0, end

end:

Answer:

This program is written in C++

Note that the average is calculated without the highest and the least value.

Comments are used for explanatory purpose

See attachment for .cpp file.

Program starts here

#include<iostream>

using namespace std;

int main()

{

int num;

cout<<"Enter Number of Test [0-10]: ";

//cin>>num;

while(!(cin>>num) || num > 10|| num<0)

{

cout << "That was invalid. Enter a valid digit: "<<endl;

cin.clear(); // reset the failed input

cin.ignore(123,'\n');//Discard previous input

}

//Declare scores

int scores[num];

//Accept Input

for(int i =0;i<num;i++)

{

cout<<"Enter Test Score "<<(i+1)<<": ";

cin>>scores[i];

}

           //Determine highest

           int max = scores[0];

           for (int i = 1; i < num; i++)

           {

               if (scores[i] > max)

               {

                   max = scores[i];

               }

           }

           //Determine Lowest

           int least = scores[0];

           for (int i = 1; i < num; i++)

           {

               if (scores[i] < least)

               {

                   least = scores[i];

               }

           }

           int sum = 0;

           //Calculate total

           for(int i =0; i< num;i++)

           {

               sum += scores[i];

           }

           //Subtract highest and least values

           sum = sum - least - max;

           //Calculate average

           double average = sum / (num - 2);

           //Print Average

           cout<<"Average = "<<average<<endl;

           //Print Highest

           cout<<"Highest = "<<max<<endl;

           //Print Lowest

           cout<<"Lowest = "<<least;

return 0;  

}

Answer:

presentation

Explanation:

Software like Google Slides and Microsoft Powerpoint can be utilized to present financial performances through the use of slides and charts.

Find the given attachments

Answer:

In dynamic scoping the current block is searched by the compiler and then all calling functions consecutively e.g. if a function a() calls a separately defined function b() then b() does have access to the local variables of a(). The visible variables with the name of the function in which it was defined are given below.

Explanation:

a. main calls fun1; fun1 calls fun2; fun2 calls fun3

Solution:

b. main calls fun1; fun1 calls fun3

Solution:

c. main calls fun2; fun2 calls fun3; fun3 calls fun1

Solution:

Here variables c, d and e of fun2 are not visible .

d. main calls fun1; fun1 calls fun3; fun3 calls fun2

Solution:

Answer:

The programming language is not stater; However, I'll answer this question using C++.

This program does not use comments (See explanation)

See Attachment for program file

Program starts here

#include <iostream>

using namespace std;

int main()

{

string response;

cout<<"What kind of swallow?\n";

cin>>response;

for(int i =0; i<response.length();i++)

{

 response[i]=toupper(response[i]);

}

   if(response == "AFRICAN")

   {

    cout<<"Yes, it could grip it by the husk.";

}

else if(response == "EUROPEAN")

   {

    cout<<"A five-ounce bird could not carry a one-pound coconut.";

}

else

{

 cout<<"You really are not fit to be a king.";

}

   return 0;

}

Explanation:

string response; -> A string variable to hold user input is declared

cout<<"What kind of swallow?\n"; -> prompts user for input

cin>>response; -> user input is stored here

The following iteration converts user input to uppercase; so that the program will work for inputs like African, AFRICAN, AFriCAN, etc.

for(int i =0; i<response.length();i++)

{

 response[i]=toupper(response[i]);

}

The following if statement prints "Yes, it could grip it by the husk." if user input is AFRICAN

   if(response == "AFRICAN")

   {

    cout<<"Yes, it could grip it by the husk.";

}

Otherwise, if user input is EUROPEAN, it prints; "A five-ounce bird could not carry a one-pound coconut."

else if(response == "EUROPEAN")

   {

    cout<<"A five-ounce bird could not carry a one-pound coconut.";

}

Lastly; for every inputs different from AFRICAN and EUROPEAN, the program displays "You really are not fit to be a king."

else

{

 cout<<"You really are not fit to be a king.";

}

Answer:

Explanation:

The objective of this task is to compute a program that involves the usage of Python code to save the data to MongoDB and to query  the database.

Due to the error that occur which makes me to be unable to submit this answer, I've created a word document instead and the attached file can be found below.

Thanks!

Answer:

Remote Access Domain

Explanation:

Remote access Domain allows users to enter into system network through VPN.

Answer:

This program is written in python programming language

Comments are used for explanatory purpose;

Take note of indentations(See Attachment)

Program starts here

#Initialize Sum to 0

sum = 0

#Prompt user for start value

start= int(input("Start Value: "))

#Prompt user for stop value

stop= int(input("Stop Value: "))

#Check if start is less than stop

if(start<=stop):

       #Iterate from start to stop

       for i in range(start, stop+1, 1):

              sum+=i**3

else:

print("Start must be less than or equal to Stop")

#Display Result

print("Expected Output: ",sum)

#End of Program

Answer:

Following are the code to this question:

import java.util.*; //importing package for user input

public class Main //defining class

{

public static void main(String []ar) //defining main method

{

double investment_amount,interest_rate,future_investment_value; //defining double variables

int years; //defining integer variable

Scanner obx=new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter invest value: "); //print message

investment_amount=obx.nextDouble(); //input value

System.out.print("Enter interest rate: ");//print message

interest_rate=obx.nextDouble();//input value

System.out.print("Enter number of years: ");//print message

years=obx.nextInt();//input value

future_investment_value=investment_amount*Math.pow((1+interest_rate/1200.),years*12); //calculating value by apply formula

System.out.println("you enter amount: $"+investment_amount); //print calculated value

System.out.println("annual interest rate:"+interest_rate+"%");//print calculated value

System.out.printf("Number of years: "+years+" the future investment value is :$%.2f\n",future_investment_value);//print calculated value

}

}

output:

please find the attachment.

Explanation:

Program Description:

Answer: seen below

Explanation:

There are various solution or ways to go about this actually. In the end, curtailing this is what matters in the end.

Below i have briefly highlighted a few precise way some of this problems can be solved, other options are open for deliberation.

A. Digital encoding of information with the calculation being changed occasionally, particularly after the frameworks advisors have finished their employments, and the framework is being used.

Which can also mean; The money could be withdrawn form the ATM. preventive Control is password to be changed periodically and regularly.

B. Noise on the line might be causing line blunders, which can bring about information misfortune. Reverberation checks and equality checks can assist with recognizing and right such mistakes.

C. If information is being lost, reverberation checks and equality checks ought to likewise help; notwithstanding, the issue might be that an intruder is blocking messages and altering them. Message arrangement numbering will assist with deciding whether messages are being lost, and in the event that they are maybe a solicitation reaction strategy ought to be executed that makes it hard for gatecrashers to dodge.

D. In the event that messages are being postponed, a significant client request or other data could be missed. As in thing c, message arrangement numbering and solicitation reaction methods ought to be utilized.

E. Messages modified by intruders can have an extremely negative effect on client provider relations if orders are being changed. For this situation, information encryption is important to keep the gatecrasher from perusing and changing the information. Additionally, a message succession numbering strategy is important to ensure the message isn't erased.

cheers i hope this was helpful !!

Answer:1) Parse-by-value

2) Parse-by-reference

3) Parse-by-name

Explanation: Parameter parsing refers to a communication among procedures or functions.

The values of a variable procedure are transferred to the called procedure by some mechanisms. Different techniques of parameter-parsing include; parse-by-value, parse-by-reference, parse-by-copy restore, parse-by-name.

Answer:

Given

The above lines of code

Required

Rearrange.

The code is re-arrange d as follows;.

#include<iostream>

int main()

{

int userNum;

scanf("%d", &userNum);

if (userNum > 0)

{

printf("Positive.\n");

}

else

{

printf("Non-positive, converting to 1.\n");

userNum = 1;

printf("Final: %d\n", userNum);

}

return 0;

}

When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;

One should take note of the variable declarations and usage

See attachment for .cpp file

Answer:

Sorted Array A { } = { 1, 4, 23, 32, 34, 34, 67, 78, 89, 100 }

Explanation:

Binary tree is drawn given that the binary tree do not follow both minimum heap and maximum heap property, therefore, it is not a heap.

See attached picture.