Which triangle congruence postulate can be used to prove that FEH=HGF?


SAS
HL
ASA
SSS

Answer:

1, 3, 5, 6

Step-by-step explanation:

Your solution has to be less than the number they are giving you for example if you have -3 one solution could be -16

The numbers that are solutions to the inequality are as follows: 20%, 17%, 29.5%, 1.5%.

The solution of an inequality is the set of all possible values that could serve as the result of the expression. So, for the given problem, the set of values that would correspond to the likelihood of snow is 20%, 17%, 29.5%, and 1.5%.

In other words, these percentages are less than 30% and can be rightly represented by the variable s.

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Answer:

79.91% of loaves are between 26.94 and 32.18 centimeters

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 30, \sigma = 2[/tex]

What percentage of loaves are between 26.94 and 32.18 centimeters

This is the pvalue of Z when X = 32.18 subtracted by the pvalue of Z when X = 26.94.

X = 32.18:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{32.18 - 30}{2}[/tex]

[tex]Z = 1.09[/tex]

[tex]Z = 1.09[/tex] has a pvalue of 0.8621

X = 26.94:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{26.94 - 30}{2}[/tex]

[tex]Z = -1.53[/tex]

[tex]Z = -1.53[/tex] has a pvalue of 0.0630

0.8621 - 0.0630 = 0.7991

79.91% of loaves are between 26.94 and 32.18 centimeters

Answer:

h = p - l - w

Step-by-step explanation:

p = 4l + 4w + 4h       Divide l, w, and h by 4

p = l + w + h              Set the equation equal to h

h = p - l - w

Answer:

A just did it on edge<3

Answer:

Step-by-step explanation:

) Do you expect the distribution of number of friends made online to be symmetric, skewed to the right, or skewed to the left?

Skewed to the left.

Symmetric

Skewed to the right.

(b) Two measures of center for this distribution are 1 friend and 5.3 friends. Which is most likely to be the mean and which is most likely to be the median?

Mean=

Median=

a)

as proportion of people with 0 friends is 43% whcih is on left side and maximum ; and % decrease with increasing number of friends

skewed to the right

b)

as it is skewed to the right ; therefore mean is greater than median

mean=5.3

median=1

[since for skwewed to the right distribution :mean is always greater than median, therefore higher value should be mean which is 5.3 and lower value is median which is 1]

Part(a): Skewed to the right

Part(b) The required values are,

mean=5.3

median=1

a)

As a proportion of people with 0 friends are 43% which is on the left side and maximum; and % decrease with an increasing number of friends

skewed to the right

b)

As it is skewed to the right; therefore mean is greater than the median

mean=5.3

median=1

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Answer:

Step-by-step explanation:

|x-1|=8

if (x-1) >= 0 meaning x >= 1

then |x-1| = x-1

and then the solution of the equation is

x-1=8

<=> x = 9

if (x-1) <= 0 meaning x <= 1

then |x-1| = -(x-1) = -x+1

so the solution of the equation is

-x+1=8

<=> -x = 7

<=> x = -7

so the solutions are -7 and 9

answer C

do no hesitate if you need further explanation

thank you

Answer:

4

Step-by-step explanation:

T(n) = n² + 3

T(1) = 1² + 3 = 1 + 3 = 4

Answer:

The angles measured between the shadow and the wall trim and the shadow and the top or bottom of the picture should be equal if the picture is level

Step-by-step explanation:

Whereby the picture is 12 inches above the wall trim and the Sun is casting a shadow on the wall, therefore, the edges of the shadow of a straight edged object is straight

If the picture is level, the shadow cast by the sun is transversal to the wall trim and the line formed by extending the bottom or top of the picture in the direction of the shadow. That is, if the picture is parallel, the shadow cast by the Sun on the wall is transversal to the picture and the wall trim if or when the shadow eventually crosses the picture

With the protractor, the angle between the shadow and the wall trim and the shadow and the top or bottom is measured

The angles measured should be the same if the picture is level.

Answer:

3.216×[tex]10^{11}[/tex]

Step-by-step explanation:

I'm assuming 104 is [tex]10^{4}[/tex] and 106 is [tex]10^{6}[/tex].

6.7×[tex]10^{4}[/tex]×4.8×[tex]10^{6}[/tex]=

32.16×[tex]10^{10}[/tex]=

3.216×[tex]10^{11}[/tex]

Our answer is 3.216×[tex]10^{11}[/tex].

Answer:

Step-by-step explanation:

4x+5x=27

9x=27

x=27/9

x=3

4x3=12

5x3=15

The total number of cats were 12.

Based on the ratio of dogs to cats in the shelter, we know that out of 27 animals, there are 12 cats.

The ratio of cats to dogs is 4:5 which means that there are 5 dogs for every 4 cats.

This means that out of 9 animals, 4 would be cats and 5 would be dogs. If there was 27 animals therefore:

= 4 / 9 x 27

= 108 / 9

= 12 cats

In conclusion, there are 12 cats.

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Answer:

Laniece had 60 magazines

Step-by-step explanation:

Given: In the  first week, Tamia sold 30% more than Laniece. In the second  week, Tamia sold 12 magazines, but Laniece did not sell any. Tamia sold 50% more than Laniece by the end of the second  week

To find: Number of magazines sold by Laniece

Solution:

Let number of magazines sold by Laniece in the first week be x.

Number of magazines sold by Tamia in the first week = [tex]x+\frac{30}{100} x=\frac{130x}{100} =\frac{13x}{10}[/tex]

Number of magazines sold by Tamia in the second week = 12

Total number of magazines sold by Tamia at the end of the second week = [tex]\frac{13x}{10}+12[/tex]

Total number of magazines sold by Laniece at the end of the second week = x

According to question,

[tex]\frac{13x}{10}+12=x+\frac{50x}{100}=x+\frac{x}{2}\\\frac{13x}{10}+12=\frac{3x}{2}\\\frac{3x}{2}-\frac{13x}{10} =12\\\frac{15x-13x}{10}=12\\\frac{2x}{10}=12\\\frac{x}{5}=12\\x=60[/tex]

Answer: What what my you explain shorter please

Step-by-step explanation:

Answer:

96

Step-by-step explanation:

60% * 160 = 0.6 * 160 = 96.

Answer:

None

Step-by-step explanation:

There is no Forest Green iPhone XR's only the 11 Pros have that color.

There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

Answer:

C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

[tex]\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3[/tex]

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

[tex]H_0 :[/tex]  The quarterly growth rate in the number of contracts is not  significantly different from 0% (? = 0.05)

[tex]H_a:[/tex]  The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the   t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

Answer:

a) Probability the fatality resulted from a fall = 0.1422

b) Probability the fatality resulted from a transportation incident = 0.3958

c(i) The cause of fatality that is least likely to occur is fatality due to fires and explosions with the lowest number of fatalities, 113.

c(ii) Probability that the fatality resulted from fires and explosions = 0.0249

Step-by-step explanation:

Data on U.S, Work-Related fatalities by cause follow (The World Almanac, 2012)

Cause of Fatality | Number of Fatalities Transportation Incidents | 1795

Assaults and violent acts | 837

Contacts with objects and equipment | 741

Falls | 645

Exposure to harmful substances | 404

Fires and explosions | 113

Total number of fatalities = 1795+837+741+645+404+113 = 4,535

Assume that a fatality will be randomly chosen from this population.

a. What is the probability the fatality resulted from a fall?

The probabilty of an event is given mathematically as the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

Probability the fatality resulted from a fall = (645/4535) = 0.14223 = 0.1422

b. What is the probability the fatality resulted from a transportation incident?

Probability the fatality resulted from a transportation incident = (1795/4535) = 0.39581 = 0.3958

c(i) What cause of fatality is least likely to occur?

The cause of fatality that is least likely to occur is the cause of fatality with the lowest frequency or number of fatalities. And this is fatality due to fires and explosions with the lowest fatalities of 113

c(ii). What is the probability the fatality resulted from this cause?

This is the probability that the fatality resulted from fires and explosions.

Probability that the fatality resulted from fires and explosions = (113/4535) = 0.02492 = 0.0249

Hope this Helps!!!

Answer:

[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

So first calculate what fraction of the circumference the arc is.

[tex]\frac{20}{360}=\frac{1}{18}[/tex]

Now the circumference is 6, so one eighteenth of that is [tex]\frac{1}{3}[/tex]

Answer:

The answer is "[tex]\sqrt{12}[/tex] is not a perfect square".

Step-by-step explanation:

12 is not a perfect square because it is the natural number, and no other natural number would square the number 12, that's why it is not a perfect square.

If we calculate the square root of [tex]\sqrt{12}[/tex]. so, it is will give [tex]2\sqrt{3}[/tex] that is not a perfect square root which can be described as follows:

[tex]\Rightarrow \sqrt{12}= \sqrt{2\times 2\times 3}[/tex]

            [tex]= \sqrt{2^2\times 3}\\\\= 2\sqrt{3}\\\\[/tex]

[tex]\bold{\sqrt{12}}[/tex] is not a perfect square root.

Answer:

Here's a picture

Step-by-step explanation:

Answer:

D. Pilot error isPilot error is the most serious threat to aviation safety. Pilots could be better trained.

Step-by-step explanation:

We can construct the relative frequency distribution dividing the amount of incidents for each category by the total amount of incidents.

This amount is:

[tex]\sum x_i=627+64+113+382+481=1667[/tex]

Then, the relative frequency for each category is:

[tex]\text{Pilot error}=627/1667=0.38\\\\\text{Human error}=64/1667=0.04\\\\\text{Weather}=113/1667=0.07\\\\\text{Mechanical problems}=382/1667=0.23\\\\\text{Sabotage}=481/1667=0.29\\\\[/tex]

As the pilot error has the largest relative frequency, we can conclude that pilot error is the most serious threat to aviation safety.

Answer:

a. 2 groups of 2 is 4

b. 3 groups of 2 is 6

c. 4 groups of 2 is 8

d. 5 groups of 2 is 10

e. 6 groups of 2 is 12

Answer:

a - 2

b- 3

c- 4 groups of 2 is 8

d- 5 groups of 2 is 10

e- 6 groups of 2 is 12

Answer:

Are there any choices?..

The correct statement the describes the equation is The lines intersect at (1, 0) and the lines are parallel.

x - y = 1.............equation 1

y - x = 1.............equation 2

Add equations (1) and (2):

(x - y) + (y - x) = 1 + 1

Simplifying

0 = 2

Since 0 = 2, the system is inconsistent, meaning there is no solution. The lines represented by the equations are parallel and will never intersect.

The system of equations has no solution, as the lines represented by the equations are parallel and will never intersect.

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The complete question is- Which statement describes the graph of the system of equations?

[x-y=1

Ly- X= 1

The lines are parallel.

The lines are coinciding.

The lines intersect at(1, 0).

The lines intersect at (-1,0).

Answer:

a) P(X < 30) = 0.0392.

b) P(28 < X < 32) = 0.2760

c) P(X > 35) = 0.1190

d) P(X > 31) = 0.8810

e) At least 35.7965 mpg

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 33, \sigma = 1.7[/tex]

a. P(X<30)

This is the pvalue of Z when X = 30. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{30 - 33}{1.7}[/tex]

[tex]Z = -1.76[/tex]

[tex]Z = -1.76[/tex] has a pvalue of 0.0392.

Then

P(X < 30) = 0.0392.

b) P(28 < X < 32)

This is the pvalue of Z when X = 32 subtracted by the pvalue of Z when X = 28. So

X = 32

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{32 - 33}{1.7}[/tex]

[tex]Z = -0.59[/tex]

[tex]Z = -0.59[/tex] has a pvalue of 0.2776.

X = 28

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{28 - 33}{1.7}[/tex]

[tex]Z = -2.94[/tex]

[tex]Z = -2.94[/tex] has a pvalue of 0.0016.

0.2776 - 0.0016 = 0.2760.

So

P(28 < X < 32) = 0.2760

c) P(X>35)

This is 1 subtracted by the pvalue of Z when X = 35. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{35 - 33}{1.7}[/tex]

[tex]Z = 1.18[/tex]

[tex]Z = 1.18[/tex] has a pvalue of 0.8810.

1 - 0.8810 = 0.1190

So

P(X > 35) = 0.1190

d. P(X>31)

This is 1 subtracted by the pvalue of Z when X = 31. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{31 - 33}{1.7}[/tex]

[tex]Z = -1.18[/tex]

[tex]Z = -1.18[/tex] has a pvalue of 0.1190.

1 - 0.1190 = 0.8810

So

P(X > 31) = 0.8810

e. the mileage rating that the upper 5% of cars achieve.

At least the 95th percentile.

The 95th percentile is X when Z has a pvalue of 0.95. So it is X when Z = 1.645. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.645 = \frac{X - 33}{1.7}[/tex]

[tex]X - 33 = 1.645*1.7[/tex]

[tex]X = 35.7965[/tex]

At least 35.7965 mpg

The upper 5% of cars have a mileage rating of 35.805 mpg

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean) / standard deviation

Given;  mean of 33 mpg and a standard deviation of 1.7

a) For < 30:

z = (30 - 33)/1.7 = -1.76

P(x < 30) = P(z < -1.76) = 1 - 0.8413 = 0.0392

b) For < 28:

z = (28 - 33)/1.7 = -2.94

P(x < 28) = P(z < -2.94) = 0.0016

c) For > 35:

z = (35 - 33)/1.7 = 1.18

P(x > 35) = P(z > 1.18) = 1 - P(z < 1.18) = 1 - 0.8810 = 0.119

d) For > 31:

z = (31 - 33)/1.7 = -1.18

P(x > 31) = P(z > -1.18) = 1 - P(z < -1.18) = 0.8810

e) The  upper 5% of cars achieve have a z score of 1.65, hence:

1.65 = (x - 33)/1.7

x = 35.805 mpg

The upper 5% of cars have a mileage rating of 35.805 mpg

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The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

A sports physician conducts an observational study to learn the average amount of time that 3,000 swimmers in the town can hold their breath underwater. He uses 150 sampling of 60 people. The average of the means of all the samplings is 72.7, and the standard deviation is 0.92. This is a histogram of the sampling distribution of the sample mean. Based on this data, with a 95% confidence interval the researchers can determine that the actual average amount of time the entire population can hold their breath under water is?

Given Information:

sample mean time = 72.7

sample standard deviation = 0.92

Sampling size = n = 150

Confidence level = 95%

Required Information:

95% confidence interval = ?  

Answer:

[tex]\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 72.7 \pm 0.14836\\\\\text {confidence interval} = 72.7 - 0.14836, \: 72.7 + 0.14836\\\\\text {confidence interval} = (72.552, \: 72.848)\\\\[/tex]

Step-by-step explanation:

The confidence interval is given by

[tex]\text {confidence interval} = \bar{x} \pm MoE\\\\[/tex]

Where [tex]\bar{x}[/tex] is the sample mean time and Margin of error is given by

[tex]$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\[/tex]

Where n is the sampling size, s is the sample standard deviation, and [tex]t_{\alpha/2}[/tex] is the t-score corresponding to 95% confidence level.

The t-score corresponding to 95% confidence level is

Significance level = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 150 - 1 = 149

From the t-table at α = 0.025 and DoF = 149

t-score = 1.975

[tex]MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 1.975\cdot \frac{0.92}{\sqrt{150} } \\\\MoE = 1.96\cdot 0.07512\\\\MoE = 0.14836\\\\[/tex]

So the required 95% confidence interval is

[tex]\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 72.7 \pm 0.14836\\\\\text {confidence interval} = 72.7 - 0.14836, \: 72.7 + 0.14836\\\\\text {confidence interval} = (72.552, \: 72.848)\\\\[/tex]

Therefore, we are 95% confident that actual average amount of time the entire population can hold their breath under water is within the range of (72.552, 72.848)

Answer:

Step-by-step explanation:

Given that:

68.87, 78.25, 70.44, 84.67, 79.79, 86.33, 100.24, 98.26

we calculate sample mean and standard deviation from given data

Sample Mean

[tex]\bar x = \frac{\sum (x)}{n} =\frac{666.85}{8} \\\\=83.35625[/tex]

Sample Variance

[tex]s^2= \frac{\sum (x- \bar x )^2}{n-1} \\\\=\frac{933.224787}{7} =133.317827[/tex]

sample standard deviation

[tex]s=\sqrt{s^2} \\=\sqrt{133.317827} \\ =11.546334[/tex]

95% CI for [tex]\mu[/tex] using t - dist

Sample mean = 83.35625

Sample standard deviation = 11.546334

Sample size = n = 8

Significance level = α = 1 - 0.95 = 0.05

Degrees of freedom for t - distribution

d-f = n - 1 = 7

Critical value

[tex]t_{\alpha 12, df}= t_{0.025, df=7}=2.365[/tex] ( from t - table , two tails, d.f =7)

Margin of Error

[tex]E = t_{\alpha 12, df}\times \frac{s_x}{\sqrt{n} } \\\\=2.365 \times \frac{11.546334}{\sqrt{8} } \\\\=2.365 \times 4.082246\\\\E=9.654512[/tex]

Limits of 95% Confidence Interval are given by:

Lower limit

[tex]\bar x - E = 83.35625-9.654512\\\\=73.701738\approx 73.702[/tex]

Upper Limit

[tex]= \bar x + E\\=83.35625+ 9.654512\\=93.010762 \approx 93.011[/tex]

95% Confidence interval is

[tex]\bar x \pm E = 83.35625 \pm 9.654512\\\\=(73.701738,93.010762)[/tex]

95% CI using t - dist (73.70 < μ < 93.01)

D. The lower bound is $ and the upper bound is One can be [95]% confident that the mean travel tax for all cities is between these values.

c.What would you recommend to a researcher who wants to increase the precision of the interval, but does not have access to additional data?

A. The researcher could decrease the level of confidence.

Answer: 95 degrees

Step-by-step explanation:

We can infer than angles 1, 4, 5, 8 are all equal and angles 2, 3, 6, 7 are also equal to eachother. These two sets of angles are supplementary(you’d get 180 by adding them)

So 3x+10=4x-15

if you rearrange you'll get

x=25

therefore angle 1 equals

3*25+10=85

angle 1 and 7 are supplementary

thus angle 7 equals

180-85=95

Answer:

Step-by-step explanation:

F(x) results in a parabola with vertex (0,0) wich mean there is only one x-int at that point. g(x) has been shifted the grapgh of f(x) to the right by to units and down by three unites. Now our vertex lies in the point (2,-3) and since the graph was move dow i=of the x-axis we now have two different x-intercepts.

Answer:

-The value of [tex]y[/tex]:

[tex]y = 1[/tex]

Step-by-step explanation:

-Find the value of [tex]y[/tex]:

[tex]11- 9y = -6y + 8[/tex]

-Add both sides by [tex]6y[/tex] and combine [tex]9y[/tex] and [tex]6y[/tex] together:

[tex]11- 9y + 6y = -6y + 6y+ 8[/tex]

[tex]11 - 3y = 8[/tex]

-Subtract both sides by [tex]11[/tex]:

[tex]11 - 11 - 3y = 8 -11[/tex]

[tex]-3y = -3[/tex]

-Divide both sides by [tex]-3[/tex]:

[tex]\frac{-3y}{-3} = \frac{-3}{-3}[/tex]

[tex]y = 1[/tex]

So the final answer is [tex]y = 1[/tex] .

Answer:

Step-by-step explanation:

In a survey of 1,000 adults living in a big city, 540 participants said that they prefer to get news from the Internet, 330 prefer to watch news on TV, and 130 are rarely interested in the current news. We want to test if the proportion of people getting the news from the Internet is more than 50%. By generating the randomization distribution, we find that the p-value is 0.0057. Choose the correct statement interpreting the p-value.

A.If the proportion of people getting the news from the Internet is not equal to 0.5 then there is a 0.0057 chance of seeing the sample proportion as extreme as the survey results.

B. If the proportion of people getting the news from the Internet is not equal to 0.54 then there is a 0.0057 chance of seeing the sample proportion as extreme as the survey results.

C. If the proportion of people getting the news from the Internet is equal to 0.54 then there is a 0.0057 chance of seeing the sample proportion less extreme compared to the survey results. р

D. If the proportion of people getting the news from the Internet is equal to 0.54 then there is a 0.0057 chance of seeing the sample proportion as extreme as the survey results.

E. If the proportion of people getting the news from the Internet is equal to 0.5 then there is a 0.0057 chance of seeing the sample proportion as extreme as the survey results.

The correct interpretation of P value will be:

if the proportion of people getting the news from internet is equal to 0.5 then there is a 0.0057 chance of seeing the sample proportion as extreme as survey results.

Answer:

c. results in either of two directions can lead to rejection of the null hypothesis.

Step-by-step explanation:

A two tailed test is performed when we want to test if there is statistically significant difference from the null state. That means that if the statistic value is significantly higher or significantly lower, we will reject the null hypothesis. Both tails have rejection areas.

Answer:

A.

Step-by-step explanation:

Add 4:

-5x ≤ 10

Divide by -5:

x ≥ -2