Answer:
C
X=6
Step-by-step explanation:
7+5x-15=22
5x-8=22
5x=22+8
5x=30
X=30/5
X=6
Select the correct answer. This graph represents a quadratic function. What is the value of a in this function’s equation? A)-1 B)2 C)1 D)-2
Answer:
Step-by-step explanation:
We will use the work form of a quadratic to determine what a is...in fact we will write the equation for the whole thing in the process, because it's part of solving for a.
y = ±|a|(x - h)² + k
where x and y are from a coordinate point on the graph, h and k are the coordinates of the vertex, the absolute value of a indicates how steep or flat the graph is compared to the parent graph, and the ± is because a positive parabola opens up and a negative one opens upside down.
The vertex is (0, 9) and the coordinate point I chose to use is (3, 0). Filling those in and solving for a:
0 = ±|a|(3 - 0)² + 9 and
0 = ±|a|(3)² + 9 and
-9 = ±|a|9 and
-1 = ±|a| so a = 1. Because this is an upside down parabola the negative is out front, but a is independent of it. The correct choice is C. The quadratic function is
[tex]y=-x^2+9[/tex] or in more detailed form:
[tex]y=-(x-0)^2+9[/tex]
Answer:
-2
Step-by-step explanation:
Given: 3x < -6. Choose the solution set.
A. {x | x < -2}
B. {x | x > -2}
C. {x | x < 2}
D. {x | x > 2}
Answer:
When we divide the inequality by 3 we get x < -2 so the answer is A.
[tex]R = \sqrt{ \frac{ax - P}{Q + bx} } [/tex]
solve for x. Please can someone help me ASAP. I need to hand it on today.
Step-by-step explanation:
[tex]r = \sqrt{ \frac{ax - p}{q + bx} } \\ {r}^{2} = \frac{ax - p}{q + bx} [/tex]
r² (q + bx) = ax - p
qr² + bxr² = ax - p
qr² + p = ax - bxr²
qr² + p = x (a - br²)
[tex]x = \frac{q {r}^{2} + p}{a - b {r}^{2} } [/tex]
Answer:
[tex]\displaystyle x=\frac{-P-\math{R}^2Q}{\math{R}^2b-a}[/tex]
Step-by-step explanation:
[tex]R=\sqrt{\frac{ax-P}{Q+bx}}[/tex]
[tex]\mathrm{Square\:both\:sides}[/tex]
[tex]R^2=\left(\sqrt{\frac{ax-P}{Q+bx}}\right)^2[/tex]
[tex]R^2=\frac{ax-P}{Q+bx}[/tex]
[tex]\mathrm{Multiply\:both\:sides\:by\:}Q+bx[/tex]
[tex]\math{R}^2\left(Q+bx\right)=\frac{ax-P}{Q+bx}\left(Q+bx\right)[/tex]
[tex]\math{R}^2\left(Q+bx\right)=ax-P[/tex]
[tex]\math{R}^2Q+\math{R}^2bx=ax-P[/tex]
[tex]\mathrm{Subtract\:}\math{R}^2Q\mathrm{\:from\:both\:sides}[/tex]
[tex]\math{R}^2Q+\math{R}^2bx-\math{R}^2Q=ax-P-\math{R}^2Q[/tex]
[tex]\math{R}^2bx=ax-P-\math{R}^2Q[/tex]
[tex]\mathrm{Subtract\:}ax\mathrm{\:from\:both\:sides}[/tex]
[tex]\math{R}^2bx-ax=ax-P-\math{R}^2Q-ax[/tex]
[tex]\math{R}^2bx-ax=-P-\math{R}^2Q[/tex]
[tex]\mathrm{Factor}\:\math{R}^2bx-ax[/tex]
[tex]x\left(\math{R}^2b-a\right)=-P-\math{R}^2Q[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}\math{R}^2b-a[/tex]
[tex]\frac{x\left(\math{R}^2b-a\right)}{\math{R}^2b-a}=-\frac{P}{\math{R}^2b-a}-\frac{\math{R}^2Q}{\math{R}^2b-a}[/tex]
[tex]x=\frac{-P-\math{R}^2Q}{\math{R}^2b-a}[/tex]
solve tan x - cot x = -2cos 2x cosec 2x
Answer:
Step-by-step explanation:
tan x-cot x
[tex]=\frac{sin~x}{cos~x} -\frac{cos~x}{sin ~x} \\=\frac{sin^2x-cos^2 x}{sin ~x~cos~x} \\=\frac{-2(cos^2x-sin^2x)}{2 sin ~x~cos~x} \\=\frac{-2 cos~2x}{sin~2x} \\=-2 cos ~2x~cosec~2x[/tex]
If a polynomial function f(x) has roots 0, 4, and 3+ sqrt 11, what must also be a root of f(x)?
a. 3+i sqrt 11
b. -3+i sqrt 11
c. 3- sqrt 11
d. -3- sqrt 11
Answer:
The answer is C 3- sqrt 11
Step-by-step explanation:
simplify (a+b)^3 + (a-b)^3 + 6a(a^2-b^2)
Answer:
8a^3.
Step-by-step explanation:
(a+b)^3=a^3+b^3+3a^2b+3ab^2
(a-b)^3=a^3-b^3-3a^2b+3ab^2
(a+b)^3+(a-b)^3=2a^3+6ab^2
According to the question
(a+b)^3+(a-b)^3+6a(a^2-b^2)
Put in the value
=2a^3+6ab^2 +6a^3–6ab^2
=8a^3
In the simplest form expression (a + b)³ + (a - b)³ + 6a(a² - b²) can be written as, 8a³
What are algebraic identities?Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.
Given that,
A algebraic identity,
(a + b)³ + (a - b)³ + 6a(a² - b²)
It is known that,
(a + b)³ = a³ + b³ + 3ab(a + b)
(a - b)³ = a³ - b³ - 3ab(a - b)
So, now we can substitute expressions
(a + b)³ + (a - b)³ + 6a(a² - b²)
a³ + b³ + 3ab(a + b) + a³ - b³ - 3ab(a - b) + 6a(a² - b²)
a³ + b³ + 3a²b + 3ab² + a³ - b³ -3a²b + 3ab² + 6a³ - 6ab²
8a³
Hence, the simplest form is 8a³
To know more about algebraic expressions check:
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Which expressions have a positive product? *
–(5)(–0.2)(–1.9)(9)
–(2.14)(1.6)(14)
(6.3)(–8.7)(0.7)
(8.5)(–0.4)(–2.7)
Answer:
The fourth choice is the correct one.
Step-by-step explanation:
If the count of negative signs is even, the product is even (positive).
This does not apply to the first choice; this expression is odd.
Same for the second choice.
Same for the third choice. The expression is odd.
The fourth choice is POSITIVE because there are an even number (2) of negative signs.
Solve the inequality.
2(4+2x)>5x+5
O x5-2
O X2-2
x33
O X23
Step-by-step explanation:
8 + 4x > 5x + 5
8 - 5 > 5x - 4x
3 > x
The solution to the system of equation is x < 3
Inequality expressionGiven the inequality expression 2(4+2x)>5x+5
Expand the inequality
2(4+2x)>5x+5
8 + 4x > 5x + 5
Collect the like terms
4x - 5x > 5 -8
-x > -3
x < 3
Hence the solution to the system of equation is x < 3
Learn more on inequality here: https://brainly.com/question/24372553
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Answer:
12 square units
Step-by-step explanation:
formula= a+b/2×h
a=2
b=6
h=3
the answer will be = 2+6/2×3
=8/2×3
=4×3
=12
Answer:
17 square units i think
(PLZ NEED HELP) The doubling time of a bacterial population is 10 minutes. After 80 minutes, the bacterial population was 80000. _____
Using your rounded answer for the initial population above (do not round your growth rate), find the size of the bacterial population after 5 hours.____
Answer:
Initial population = 313
Population after 5 hours = [tex]3.36 \times 10^{11}[/tex]
Step-by-step explanation:
Let initial population = [tex]x[/tex]
It is given that population gets doubled every 10 minutes.
Population after 10 minutes = [tex]2x[/tex]
Population after 20 minutes = [tex]2^{2} x[/tex]
:
:
Population after 80 minutes = [tex]2^{8} x[/tex] and it is given as 80000.
[tex]\Rightarrow 2^{8} x = 80000\\\Rightarrow x = \dfrac{80000}{256}\\\Rightarrow x = 313[/tex]
So, initial population is 312.5 = ~313
To find, population after 5 hours i.e. 5 [tex]\times[/tex] 60 = 300 minutes
Population after 300 minutes =
[tex]2^{30} x\\\Rightarrow 2^{30} \times 313\\\Rightarrow 3.36 \times 10^{11}[/tex]
So, the answers are:
Initial population = 313
Population after 5 hours = [tex]3.36 \times 10^{11}[/tex]
Simplify problem: ∛-27n^27
Answer:
-3n⁹
Step-by-step explanation:
= [tex]\sqrt[3]{-27n^(27)}[/tex]
= [tex]\sqrt[3]{-27} * \sqrt[3]{n^{27}}[/tex]
= (-3) × n⁹
= -3n⁹
Find the mean of the following data set: (Round to the nearest 10th) 2,3,10,15,20,24,30
Answer:
2+3+10+15+20+2+30=82
82/8=10.25
Step-by-step explanation:+10.25
Answer:
The answer is 14.9
Step-by-step explanation:
First I added 2,3,10,15,20,24,30 then divided it by 7.
Help please!
How does the function f(x)=x^2−4x−21 illustrate the Fundamental Theorem of Algebra?
Fill in the blanks. (Hint: Your answers are numbers.)
The degree of f(x) is _____. The Fundamental Theorem of Algebra guarantees that a polynomial equation has the same number of complex roots as its degree. This means that f(x) has exactly _____ zeros. Those zeros are 7 and _____.
f(x)=x²−4x−21
The degree is the biggest power of x. That's a polynomial of degree 2, also called a quadratic function. Let's find its zeros.
0 = x²−4x−21 = (x - 7)(x+3)
x=7 or x=-3
The fundamental theorem guarantees every non-constant polynomial with complex coefficients has a complex zero, let's call it r. If we divide the polynomial by x-r there won't be any remainder and we'll get a new polynomial, one degree less. The fundamental theorem again applies and (if it's not a constant polynomial) we are assured of another zero, s. We divide by x-s and get a new polynomial of degree one less. We repeat all this until we get a constant polynomial (degree zero). So we get a zero for every degree. They're not necessarily all different.
Answer:
The degree of f(x) is 2. The Fundamental Theorem of Algebra guarantees that a polynomial equation has the same number of complex roots as its degree. This means that f(x) has exactly 2 zeros. Those zeros are 7 and -3.
Let f(x) = .............
Answer:
4
Step-by-step explanation:
g(3) = -2(3)^2 -4 = 2(9) -4 = 18-4 = 14
|f(2)| = | 2^2 -3| = | 4-3| = 1
(g(3) +2) = (14+2) = 16
4* |f(2)| = 4*1 = 4
16/4 = 4
Find the slope of the line that passes through (5, 9) and (2, 2). will mark brain
Simplify your answer and write it as a proper fraction, improper fraction, or integer.
The right answer is 7/3
please see the attached picture for full solution
hope it helps..
Good luck on your assignment
Answer:
[tex]slope = \frac{7}{3} [/tex]
Step-by-step explanation:
[tex](5 \: \: , \: \: 9) = > (x1 \: \: \:, \: y1) \\ (2 \: \: , \: \: 2) = > (x2 \: \: \:, \: \: y2)[/tex]
[tex] slope \\ = \frac{y1 - y2}{x1 - x2} \\ = \frac{9 - 2}{5 - 2} \\ = \frac{7}{3} [/tex]
hope this helps
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good luck! have a nice day!
A coordinate plane showing Nina's run. The x-axis shows Time in seconds and the y-axis shows Distance in meters. Four points plotted and labeled. The points are (4, 32), (6, 48), (8, 64), (10, 80). A two column table with four rows. The first column, Time in seconds, has the entries, 4, 6, 8. The second column, Distance in meters, has the entries, 35, 47.5, 60. Nina and Ryan each ran at a constant speed for a 100-meter race. Each runner’s distance for the same section of the race is displayed on the left. Who had a head start, and how big was the head start? had a head start of meters
Answer:
Ryan had a head start of 10 meters
Answer:
Ryan had a head start of 10 meters.
Have a great day!
Step-by-step explanation:
Please mark me brainliest!
A car travels 0.75 miles every minute.explain how you could use proportional reasoning too find how far the car travels in a hour
Answer:
The car travels 45 miles in one hour.
Step-by-step explanation:
Knowing that one hour is 60 minutes and that the car travels 0.75 miles every minute, you can multiply 60 and 0.75 which gives you 45 miles per hour meaning in one hour the car travels 45 miles.
Solve the following equation 4×6x−7=1 x= log8log6 x= log2log6 x= log6log8 x= log6log2
Answer:
The value of x is [tex]x=\frac{\log(2)}{\log(6)}[/tex].
Step-by-step explanation:
Solve the equation as follows:
[tex]4\times 6^{x}-7=1[/tex]
[tex]4\times 6^{x}=7+1[/tex]
[tex]6^{x}=\frac{8}{4}[/tex]
[tex]6^{x}=2[/tex]
Take log on both sides.
[tex]\log(6^{x})=\log(2)[/tex]
[tex]x\log (6)=\log(2)[/tex]
[tex]x=\frac{\log(2)}{\log(6)}[/tex]
Thus, the value of x is [tex]x=\frac{\log(2)}{\log(6)}[/tex].
the cost to rent skis at a local sporting goods store is $15 plus $20 per day. which equation models the relationship between the total cost to rent, c, and the length of the rental in days, d ?
Answer:
c = 20d + 15
Step-by-step explanation:
answer choices may help if the answer is not one of the choices; but here is the answer that it should be:
20 dollars per day is 20 times the length of rental.
15 is a cost that is added and does not change.
c = the total cost therefore:
c = 20d + 15
I need help please!! Identify the solution for the system of equations graphed here.
A. (1,1)
B. (-1,1)
C. (1,-1)
D. (-1,-1)
Answer:
C. (1,-1)
Step-by-step explanation:
Lines are intersecting each other at point (1, - 1).
Hence, the system of equations graphed here would be (1, - 1)
In the diagram of circle O, what is the measure of ? 27° 54° 108° 120°
Answer:
Option (2).
Step-by-step explanation:
This question is incomplete; here is the complete question and find the figure attached.
In the diagram of a circle O, what is the measure of ∠ABC?
27°
54°
108°
120°
m(minor arc [tex]\widehat {AC}[/tex]) = 126°
m(major arc [tex]\widehat {AC}[/tex]) = 234°
By the intersecting tangents theorem,
If the two tangents of a circle intersect each other outside the circle, measure of angle formed between them is half the difference of the measures of the intercepted arcs.
m∠ABC = [tex]\frac{1}{2}[m(\text {major arc{AC})}-m(\text{minor arc} {AC})][/tex]
= [tex]\frac{1}{2}(234-126)[/tex]
= 54°
Therefore, Option (2) will be the answer.
Answer:
B.
Step-by-step explanation:
(3x+8) (4x+10) what is the length
If you expand and simplify. -(y+2)(y-8)
Answer:
[tex]-y^2+6y+16[/tex]
Step-by-step explanation:
[tex]-(y+2)(y-8)[/tex]
[tex]-1(y+2) \times (y-8)[/tex]
[tex](-y-2)\times (y-8)[/tex]
[tex]-y(y-8)-2(y-8)[/tex]
[tex]-y^2+8y-2y+16[/tex]
[tex]-y^2+6y+16[/tex]
2/3 - 4x + 7/2 = -9x + 5/6 apply the properties.. step by step
Answer:
x=5/13
Step-by-step explanation:
2/3+7/2=9x+5/6+4x
2/3+7/2-5/6=9x+4x
lcm of 2,3,6=6
2/3=4/6 7/2=21/6 5/6=5/6
4/6+21/6-5/6=9x+4x
30/6=13x
5=13x
x=5/13
Steps:
Step 1: Simplify both sides of the equation.
2/3−4x+7/2=−9x+5/6
2/3+−4x+7/2=−9x+5/6
(−4x)+( 2/3 + 7/2 )=−9x+ 5/6 (Combine Like Terms)
−4x+25/6=−9x+5/6
−4x+25/6=−9x+5/6
Step 2: Add 9x to both sides.
−4x+25/6+9x=−9x+5/6+9x
5x+25/6=5/6
Step 3: Subtract 25/6 from both sides.
5x+25/6−25/6=5/6−25/6
5x=−10/3
Step 4: Divide both sides by 5.
5x/5=−10/3/5
= x=-2/3
Answer: x=-2/3
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Hope this helps.
Please help with thisssss
Answer:a
Step-by-step explanation:
Answer:
The answer is A.
Step-by-step explanation:
Pythagorean theorem.
a^2+b^2=c^2.
2^2+3^2=d^2
To eliminate the y-terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before
adding the equations together?
First Equation: 5x - 4y = 28
Second equation: 3x - 3y = 30
The first equation should be multiplied by 3 and the second equation by 5.
The first equation should be multiplied by 3 and the Second equation by -5.
The first equation should be multiplied by 9 and the second equation by 4
The first equation should be multiplied by 9 and the second equation by -4.
Mark this and retum
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Answer:
To eliminate y- terms
Multiply equ(1) by 3 and equ(2) by -4
To eliminate y- terms
Multiply (1) by 3 and (2) by -5
Step-by-step explanation:
5x - 4y = 28 (1)
3x - 3y = 30 (2)
To eliminate y- terms
Multiply equ(1) by 3 and equ(2) by -4
15x-12y=84
-12x+12y= -120
Add equ (3) and (4)
3x=84-120
3x=-36
x=-36/3
= -12
x=-12
To eliminate x- terms
5x-4y=28
3x-3y=30
Multiply (1) by 3 and (2) by -5
15x-12y=84
-15x+15y=-150
Add the new equation
3y= -66
y= -22
How many solutions does the equation - 4x + 6 = 6x - 2 have?
Answer:
There is one solution
Step-by-step explanation:
4x + 6 = 6x - 2
Subtract 4x from each side
4x-4x + 6 = 6x-4x - 2
6 = 2x-2
Add 2
6+2 = 2x
8 = 2x
Divide by 2
8/2 = 2x/2
4=x
The diameter of a sphere is 4 centimeters. Which represents the volume of the sphere? StartFraction 32 Over 3 EndFractionπ cm3 8π cm3 StartFraction 64 Over 3 EndFractionπ cm3 16π cm3
Answer:
The volume of the sphere is 32 π /3 cm^3
Step-by-step explanation:
Mathematically, the volume of a sphere can be calculated using the formula below;
V = 4/3 * pi * r^3
Now since we have the radius and diameter = 2 * radius
radius = diameter/2 = 4/2 = 2
Substituting this value into the volume equation;
V = 4/3 * pi * 2^3 = 32pi/3
Answer:
The correct answer is A
Step-by-step explanation:
Need help ASAP! Need help ASAP will mark you as brainiest!
Answer:
[tex]r=\frac{44}{\pi }[/tex]
Step-by-step explanation:
[tex]88=2\pi r[/tex]
[tex]\mathrm{Switch\:sides}\\2\pi r=88\\\frac{2\pi r}{2\pi }=\frac{88}{2\pi }\\r=\frac{44}{\pi }\\or\\r=14.00563[/tex]
Answer:
2 metres
Step-by-step explanation:
Circumference = 2 × π × r
→ Substitute in the values
88 = 2 × [tex]\frac{22}{7}[/tex] × r
→ Divide both sides by 2 to isolate [tex]\frac{22}{7}[/tex] and r
44 = [tex]\frac{22}{7}[/tex] × r
→ Multiply everything by 7 to get rid of the fraction
308 = 22 × 7r
→ Divide the equation by 22 to isolate 7r
14 = 7r
→ Divide the equation by 7 to isolate r
2 = r
The radius of the circle with a circumference of 88 meters is 2 metres
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Answer:
18 square meters
Step-by-step explanation:
Answer:
7.5 square meterssolution,
The given figure if a Trapezium whose parallel sides are of 3 m and 2 m respectively.
Distance between the parallels sides
i.e. height is 3 m
Now,
[tex]area = \frac{1}{2} \times sum \: of \: parallel \: sides \times height \\ = \frac{1}{2} \times (3 + 2) \times 3 \\ = \frac{1}{2} \times 5 \times 3 \\ = \frac{15}{2} \\ = 7.5 \: {m}^{2} [/tex]
Hope this helps...
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