Write net ionic equations for the reaction that occurs when aqueous solutions of Lithium hydroxide, LiOH, with hydrobromic acid, HBr, undergo a neutralization reaction that produces salt and water.

Answers

Answer 1

Answer:

OH⁻(aq) + H⁺(aq) ⇒ H₂O(l)

Explanation:

Let's consider the molecular equation that occurs when aqueous solutions of lithium hydroxide and hydrobromic acid undergo a neutralization reaction.

LiOH(aq) + HBr(aq) ⇒ LiBr(aq) + H₂O(l)

The complete ionic equation includes all the ions and the molecular species.

Li⁺(aq) + OH⁻(aq) + H⁺(aq) + Br⁻(aq) ⇒ Li⁺(aq) + Br⁻(aq) + H₂O(l)

The net ionic equation includes only the ions that participate in the reaction and the molecular species.

OH⁻(aq) + H⁺(aq) ⇒ H₂O(l)


Related Questions

Anyone have a nursing major

Answers

Answer:

i maybe have one

Explanation:

Examine the chemical reaction and lab scenario.

2Fe2S3+9O2→2Fe2O3+6SO2

3.17 g of iron(III) sulfide (Fe2S3) reacts with an excess amount of oxygen at standard temperature and pressure. The theoretical yield of sulfur dioxide (SO2) is 3.81 g. However, during a lab, only 3.37 g are produced.

What is the percent yield of sulfur dioxide?

94.41% SO2

81.36% SO2

44.00% SO2

88.45% SO2

Answers

Explanation:

Percentage Yield

= (3.37g/3.81g) * 100% = 88.45%.

Therefore 88.45% SO2 is the percentage yield.

A plant takes root in a small crevice of rock, as the plant grows, its roots push on the edges of the rock, breaking it is a form of weathering?

1. True

2. False

Answers

Answer:
True

Step-by-step explanation:

Roots grow into cracks in the rocks, as the roots grow, they press on the sides of the crack, making it wider until it breaks apart (example - tree roots breaking up the sidewalk. Mechanical weathering is the process of breaking big rocks into little ones. This process usually happens near the surface of the planet. Temperature also affects the land. The cool nights and hot days always cause things to expand and contract. That movement can cause rocks to crack and break apart.

1) A 10g sample of H2(g) reacts with a 22g sample of O2(g) according to

the equation: _H2(3)+ -_02(3)→ _H,0(1)

Which reactant is limiting? Which is in excess?

Answers

Answer:

H₂ is excess reactant and O₂ the limiting reactant

Explanation:

Based on the chemical reaction:

2H₂(g) + O₂(g) → 2H₂O

2 moles of H₂ react per mole of O₂

To find limiting reactant we need to convert the mass of each reactant to moles:

Moles H₂ -Molar mass: 2.016g/mol-:

10g H₂ * (1mol / 2.016g) = 4.96 moles

Moles O₂ -Molar mass: 32g/mol-:

22g O₂ * (1mol / 32g) = 0.69 moles

For a complete reaction of 0.69 moles of O₂ are needed:

0.69mol O₂ * (2mol H₂ / 1mol O₂) = 1.38 moles of H₂

As there are 4.96 moles,

H₂ is excess reactant and O₂ the limiting reactant

please help. calculate the partial pressure of oxygen gas Po2 at STP.

Answers

Answer:

0.21 atm

Explanation:

From the question given above, the following data were obtained:

Partial pressure of N₂ (P₁) = 0.78 atm

Partial pressure of Ar (P₂) = 0.01 atm

Partial pressure of O₂ (P₃) =?

Since the system is at standard temperature and pressure (STP), the total pressure of the system is 1 atm.

Finally, we shall determine the partial pressure of O₂. This can be obtained as follow:

Partial pressure of N₂ (P₁) = 0.78 atm

Partial pressure of Ar (P₂) = 0.01 atm

Total pressure (Pₜ) = 1 atm

Partial pressure of O₂ (P₃) =?

Pₜ = P₁ + P₂ + P₃

1 = 0.78 + 0.01 + P₃

1 = 0.79 + P₃

Collect like terms

1 – 0.79 = P₃

P₃ = 0.21 atm

Therefore, the partial pressure of O₂ is 0.21 atm.

A 23.9 g sample of an unknown metal is heated from 41.2C to 68.9C. During the process the
metal absorbs 1110 Joules. Calculate the specific heat of the metal.

Answers

Answer:

1.677 J/gºC

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 23.9 g

Initial temperature (T₁) = 41.2 °C

Final temperature (T₂) = 68.9 °C

Heat (Q) absorbed = 1110 J

Specific heat capacity (C) of metal =?

Next, we shall determine the change in the temperature of the metal. This can be obtained as follow:

Initial temperature (T₁) = 41.2 °C

Final temperature (T₂) = 68.9 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 68.9 – 41.2

ΔT = 27.7 °C

Finally, we shall determine the specific heat capacity of the metal as follow:

Mass (M) = 23.9 g

Heat (Q) absorbed = 1110 J

Change in temperature (ΔT) = 27.7 °C

Specific heat capacity (C) of metal =?

Q = MCΔT

1110 = 23.9 × C × 27.7

1110 = 662.03 × C

Divide both side by 662.03

C = 1110 / 662.03

C = 1.677 J/gºC

Therefore, the specific heat capacity of the metal is 1.677 J/gºC

Which of the following is not a product of the reaction of zinc metal with nitric acid?
A. H2O
B. Zn2+
C. H2
D. NH4+
E. All of the above species are products.

Answers

Answer:

A. H2O

Explanation:

The balanced ionic equation for the reaction is:

[tex]Zn^{2+} + 2H^{+} NO_{3} ^{-1}[/tex] → [tex]Zn^{2+} (NO_{3} )^{-1} _{2} + H^{2+} _{2}[/tex]

This implies that the products of the reaction are zinc nitrate and hydrogen gas only.

Therefore, the outlier from the options is water (H2O)

Let me know if you have any other questions.

Changes in temperature can often cause a change in the state of matter of objects. A decreasein temperature causes which of the following to happen?

A liquids will boil. B Water will freeze. C Wax will melt. D Solids will turn to gas.
PLS give meh answer

Answers

Answer:

B. Water will freeze

because the latent heat of vapourization decreases.

kinetic energy, elastic potential energy, and gravitational potential energy are all forms of

a. nuclear energy

b. chemical energy

c. mechanical energy

d. internal energy

Answers

Explanation:

the answer is internal energy..much like rubbing hands 2gether to make them warmer..

In a sample of air at STP, the partial pressure of nitrogen gas is PN, = 0.78 atm and the partial
pressure of argon gas is Par = 0:01 atm. Calculate the partial pressure of oxygen gas Po, at STP.
Ignore units and use the proper amount of significant figures.

Answers

Answer:

0.21 atm

Explanation:

Step 1: Given data

Pressure of air (P): 1 atm (standard pressure)Partial pressure of nitrogen (pN₂): 0.78 atmPartial pressure of argon (pAr): 0.01 atm

Step 2: Calculate the partial pressure of oxygen

The air is a gaseous mixture formed mainly by nitrogen, oxygen and argon. The total pressure is equal to the sum of the partial pressures of the gases.

P = pN₂ + pAr + pO₂

pO₂ = P - pN₂ - pAr

pO₂ = 1 atm - 0.78 atm - 0.01 atm

pO₂ = 0.21 atm

Find the number of grams in 3.45 x 10^21 molecules NiO

Answers

Answer:

Mass = 0.43 g

Explanation:

Given data:

Mass in gram = ?

Number of molecules of NiO = 3.45×10²¹

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

3.45×10²¹ molecules × 1 mol / 6.022 × 10²³ molecules

0.57×10⁻² mol

0.0057 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.0057 mol × 74.69 g/mol

Mass = 0.43 g

1. A gas expands and does p-v work on the surroundings equal to
279j. At the same time it absorbs, 216j of heat from the surroundings. What
is the change in energy of the system?


Please answer if yk

Answers

The change in energy of the system : -63 J

Further explanation

Given

279 J work

216 J heat

Required

The change in energy

Solution

Laws of thermodynamics 1

ΔU=Q+W

Rules :

receives heat, Q +  releases heat, Q -  work is done by a system, W -  work is done on a system, W +  

a gas work on the surrounding : W =-279 J

a gas absorb heat from surrounding : Q = +216 J

Internal energy :

= -279+216

= -63 J

Is the following equation balanced?...
Al + O2 --> 2Al2O3

Answers

Answer:

no

Explanation:

Compare and contrast the thermal capacity and transfer of solids, liquids, and gases

Answers

Answer:

किसी पदार्थ की ऊष्मीय चालकता को प्रति इकाई तापमान अंतर के प्रति इकाई क्षेत्र की सामग्री की एक इकाई मोटाई के माध्यम से गर्मी हस्तांतरण की दर के रूप में परिभाषित किया गया है। किसी पदार्थ की ऊष्मीय चालकता इस बात का माप है कि उस पदार्थ में कितनी तीव्र ऊष्मा प्रवाहित होगी। थर्मल चालकता के लिए एक बड़ा मूल्य इंगित करता है कि सामग्री एक अच्छा गर्मी कंडक्टर है, और एक कम मूल्य इंगित करता है कि सामग्री एक खराब गर्मी कंडक्टर या इन्सुलेटर है। कमरे के तापमान पर शुद्ध तांबे की तापीय चालकता 401 W / m है। K, जो इंगित करता है कि एक 1m मोटी तांबे की दीवार 401 W / m 2 की दर से गर्मी का संचालन करेगीप्रति दीवार के क्षेत्र का अंतर दीवार के पार तापमान अंतर। चित्रा 2.3 सामान्य तापमान और दबाव में पदार्थ के विभिन्न राज्यों के लिए तापीय चालकता की सीमा को दर्शाता है। एक ठोस की ऊष्मीय चालकता, गैस की तुलना में चार गुना अधिक परिमाण की हो सकती है। यह प्रवृत्ति काफी हद तक दोनों राज्यों के बीच अंतर-संबंधी अंतर के कारण है।

ठोस राज्य

सामग्रियों के आधुनिक दृष्टिकोण में, एक ठोस में मुक्त इलेक्ट्रॉनों और एक आवधिक व्यवस्था में बाध्य परमाणुओं का समावेश हो सकता है जिसे जाली कहा जाता है। तदनुसार, थर्मल ऊर्जा का परिवहन दो प्रभावों के कारण होता है: मुक्त इलेक्ट्रॉनों का पलायन और जाली कंपन तरंगें। ये प्रभाव योगात्मक हैं, जैसे कि तापीय चालकता k , इलेक्ट्रॉनिक घटक k e और समरूप घटक k l का योग है

k = k e + k l

(2.7)

सामान्य तापमान और दबाव में विभिन्न राज्यों के लिए थर्मल चालकता की 2.3 रेंज चित्रा

k e विद्युत प्रतिरोधकता के व्युत्क्रमानुपाती होता है । शुद्ध धातुओं के लिए, जो कम के हैं , k e , k l की तुलना में बहुत बड़ा है । इसके विपरीत, मिश्र धातुओं के लिए, जो कि काफी बड़े होते हैं , k l से k का योगदान अब नगण्य नहीं है। गैर-धात्विक ठोस के लिए, k को मुख्य रूप से k l द्वारा निर्धारित किया जाता है , जो कि जाली के परमाणुओं के बीच परस्पर क्रिया की आवृत्ति पर निर्भर करता है। जाली व्यवस्था की नियमितता का k l पर महत्वपूर्ण प्रभाव पड़ता है , क्रिस्टलीय (सुव्यवस्थित) सामग्री की तरह, क्वार्ट्ज जैसी सामग्री में कांच जैसी अनाकार सामग्री की तुलना में अधिक ऊष्मीय चालकता होती है। वास्तव में, क्रिस्टलीय के लिए, गैर-धात्विक ठोस जैसे कि हीरा और बेरिलियम ऑक्साइड, k l काफी बड़े हो सकते हैं, जो कि अच्छे कंडक्टरों से जुड़े k के मूल्यों से अधिक होते हैं , जैसे कि एल्यूमीनियम।

इन्सुलेशन सिस्टम

थर्मल इंसुलेशन में कम तापीय चालकता वाली सामग्री शामिल होती है, जो एक कम प्रणाली वाली तापीय चालकता को प्राप्त करने के लिए संयुक्त होती है। फाइबर-, पाउडर-, फ्लेक-टाइप इंसुलेशन में, ठोस पदार्थ को पूरी तरह से एक एयर स्पेस में फैलाया जाता है। ऐसी प्रणालियों को एक प्रभावी तापीय चालकता की विशेषता होती है , जो ठोस पदार्थ की तापीय चालकता और सतह विकिरणकारी गुणों पर निर्भर करती है, साथ ही साथ हवा या शून्य स्थान की प्रकृति और मात्रात्मक अंश। प्रणाली का एक विशेष पैरामीटर इसकी थोक घनत्व (ठोस द्रव्यमान / कुल मात्रा) है, जो उस तरीके पर दृढ़ता से निर्भर करता है जिसमें ठोस सामग्री परस्पर जुड़ी हुई है।

द्रवित अवस्था

चूंकि इंटरमॉलिक्युलर स्पेसिंग बहुत बड़ी होती है और अणु की गति ठोस अवस्था की तुलना में द्रव अवस्था के लिए अधिक यादृच्छिक होती है, इसलिए थर्मल एनर्जी ट्रांसपोर्ट कम प्रभावी होता है। इसलिए गैसों और तरल पदार्थों की तापीय चालकता ठोस पदार्थों की तुलना में छोटी होती है।

ऊष्मीय विसरणशीलता

गर्मी हस्तांतरण समस्याओं के हमारे विश्लेषण में, पदार्थ के कई गुणों का उपयोग करना आवश्यक होगा। इन गुणों को आम तौर पर थर्मोफिजिकल गुणों के रूप में संदर्भित किया जाता है और इसमें दो अलग-अलग श्रेणियां, परिवहन और थर्मोडायनामिक गुण शामिल होते हैं। परिवहन गुणों में प्रसार दर गुणांक जैसे कि के, थर्मल चालकता (गर्मी हस्तांतरण के लिए), और , गतिज चिपचिपापन (गति हस्तांतरण के लिए) शामिल हैं। दूसरी ओर, थर्मोडायनामिक गुण, एक प्रणाली के संतुलन की स्थिति से संबंधित हैं। घनत्व ( ) और विशिष्ट ऊष्मा ( C p ) दो ऐसे गुण हैं जिनका उपयोग थर्मोडायनामिक विश्लेषण में बड़े पैमाने पर किया जाता है। उत्पाद सी पीआम तौर पर वॉल्यूमेट्रिक ताप क्षमता को कहा जाता है , जो थर्मल ऊर्जा को स्टोर करने के लिए एक सामग्री की क्षमता को मापता है। क्योंकि बड़े घनत्व के पदार्थों को आमतौर पर छोटे विशिष्ट हीट्स, कई ठोस और तरल पदार्थों की विशेषता होती है, जो कि बहुत अच्छा ऊर्जा भंडारण मीडिया है, इसमें तुलनीय ताप क्षमता होती है। हालांकि उनकी बहुत छोटी घनत्व के कारण, गैसें थर्मल ऊर्जा भंडारण के लिए खराब अनुकूल हैं।

ऊष्मा अंतरण विश्लेषण में, ऊष्मा चालकता के लिए तापीय चालकता का अनुपात एक महत्वपूर्ण गुण है जिसे तापीय विवर्तनशीलता कहा जाता है , जिसमें m 2 / s की इकाइयाँ होती हैं ।

(2.8)

यह तापीय ऊर्जा को संग्रहीत करने की क्षमता के सापेक्ष तापीय ऊर्जा का संचालन करने के लिए एक सामग्री की क्षमता को मापता है। बड़ी की सामग्री उनके थर्मल वातावरण में बदलाव के लिए जल्दी से प्रतिक्रिया देगी, जबकि छोटे की सामग्री अधिक सुस्त प्रतिक्रिया देगी, एक नई संतुलन स्थिति तक पहुंचने में अधिक समय लेगी।

describe how atomic emission Spectra give us information about the energy levels of electrons in atoms ​

Answers

Answer:

Energy of atom is in lowest. The energy of electrons are given energy. The electrons absorb energy. Its converted to higher level of energy.

When excited electrons return to their ground state, atomic emission spectra are produced. When electrons return to a lower energy level, they emit light energy.

What is atomic emission Spectra?

The emission spectrum of a chemical element or chemical compound is the spectrum of electromagnetic radiation frequencies emitted as a result of an electron transitioning from a high energy state to a lower energy state.

The emitted photon's photon energy equals the energy difference between the two states.

Atomic emission spectra provided further evidence of light's quantized nature, leading to the development of a new model of the atom based on quantum theory.

When excited electrons return to their ground state, atomic emission spectra are produced. The light emitted corresponds to the energies of the specific electrons.

Thus, this way atomic emission Spectra give us information about the energy levels of electrons in atoms .

For more details regarding atomic emission spectra, visit:

https://brainly.com/question/14231399

#SPJ2

Q2. Which of the following molecules may show.
Infra-red absorption
absorption Spectra, CH3CH3,
CH₃Cl3, N2.​

Answers

Answer:

I think is answer

CH3cl3

Why is the atomic model the foundation for chemistry?
A. because all matter is made of atoms
B. because no particle is smaller than the atom
O c. because atoms are the invisible particles that make up light
O D. because atoms are the small forces of energy that hold together all matter

Answers

Answer:

A.

Explanation:

How many atoms are found in the chemical formula below?*
Al2(SiO3)2

Answers

Answer:

10 atoms

Explanation:

To find out the number of atoms: MULTIPLY all the SUBSCRIPTS in the molecule by the COEFFICIENT.

what happens when copper sulphate reacts with hydrogen
sulphide?​

Answers

Answer:

When hydrogen sulphide gas is passed through a blue solution of copper sulphate, a black precipitate of copper sulphide is obtained and the sulphuric acid so formed remains in the solution. In this reaction, cupric ions (from copper sulphate) combine with sulphide ions (from hydrogen sulfide) to form cupric sulphide.

Answer:

When hydrogen sulphide gas is passed through a blue solution of copper sulphate, a black precipitate of copper sulphide is obtained and the sulphuric acid so formed remains in the solution. In this reaction, cupric ions (from copper sulphate) combine with sulphide ions (from hydrogen sulfide) to form cupric sulphide.

Explanation:

why is water a polar covalent molecule.

Answers

Water is a Polar Covalent Molecule

The unequal sharing of electrons between the atoms and the unsymmetrical shape of the molecule means that a water molecule has two poles - a positive charge on the hydrogen pole (side) and a negative charge on the oxygen pole (side).

thank me and mark me as brainliest

how do you separate amixture by using fractional distillation​

Answers

Answer:Fractional distillation is a method for separating a liquid from a mixture of two or more liquids. For example, liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. This method works because the liquids in the mixture have different boiling points.

Explanation:

How many moles are in 75.0 grams of nitrogen gas, N2?

Answers

Given:                                                                                                                      

Mass of Nitrogen (N₂) gas = 75 grams

Finding the number of moles of N₂:                                                                    

We know that the molar mass of N₂ is 28 grams/mole

Number of moles = Given mass / Molar mass

Number of moles = 75 / 28

Number of moles = 2.68 moles

Hence, there are 2.68 moles in 75 grams of Nitrogen Gas

Which of the following atoms is smallest: nitrogen, phosphorus, or arsenic?

Answers

Answer:

arsenic

Explanation:

nitrogen=155pm

phosphorus=195pm

arsenic =between 38 μm and 25 mm

How many grams of ammonia(NH3) are produced from 6 moles of nitrogen. (Show all work)

Answers

Answer:

Mass = 204 g

Explanation:

Given data:

Mass of ammonia produced = ?

Number of moles of nitrogen = 6 moles

Solution:

Chemical equation;

N₂ + 3H₂    →    2NH₃

now we will compare the moles of nitrogen and ammonia.

               N₂        :          NH₃

                1          :            2

               6          :          2/1×6 = 12

Mass of ammonia;

Mass = number of moles × molar mass

Mass = 12 mol × 17 g/mol

Mass = 204 g

i need help with this

Answers

I highly believe it would be D
Because yes it does happen above water but it’s not just that, and the other two don’t seem correct. So sorry it’s not correct but I believe it is D

30 POINTS HELPP PLEASE

Answers

1: selective breeding

2:traits

3: crop species

4: domestic

5: diverse

6: artificial

7: uniform

in your opinion if the answer is correct please like n mark MI s brain list

Lee rode a skateboard to school. His velocity changed from 2 m/s east to 5
m/s east in 6 seconds. What was the change in Lee's velocity?
A. 5 m/s east
B. 3 m/s east
C. -3 m/s east
D. 2 m/s east

Answers

Answer:

Option B. 3 m/s east

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 2 m/s east

Final velocity (v) = 5 m/s east

Time (t) = 6 s

Change in velocity =?

We can obtain the change in Lee's velocity as illustrated below:

Initial velocity (u) = 2 m/s east

Final velocity (v) = 5 m/s east

Change in velocity =?

Change in velocity = Final velocity (v) – Initial velocity (u)

Change in velocity = v – u

Change in velocity = 5 – 2

Change in velocity = 3 m/s east

Thus, the change in Lee's velocity is 3 m/s east

Answer:

Option (B.) 3 m/s east

Explanation:

Have a good day hope it helps

Question:
What is protecting us from the solar wind?

Answers

Answer:

The magnetic field

Explanation:

What does it take in order for plates to move?

Answers

Answer:

Earth's thin outer shell is broken into big pieces called tectonic plates. These plates fit together like a puzzle, but they're not stuck in one place. They are floating on Earth's mantle, a really thick layer of hot flowing rock. The flow of the mantle causes tectonic plates to move in different directions.

Explanation:

Draw a Lewis structure for HCCl3 . Include all hydrogen atoms and show all unshared pairs and the formal charges, if any. Assume that bonding follows the octet rule.

Answers

Answer:

See answer below

Explanation:

First, let's explain what a Lewis structure is.

A lewis structure in short words is a draw of an atom or molecule showing how the electrons bond with another electrons of atoms, and also shows the unshared pair of electrons, which are the electrons that do not bond in the molecule. In the case of an atom, it shows all the available electrons it has to be shared and bonded with another atom to form a molecule.

With this said, in order to draw the lewis structure we need to know how many electrons the atoms involved have. To know this, we need to write the electronic configuration of the atoms, based on it's atomic number.

In the case of Hydrogen (Z = 1), Carbon (Z = 6) and Cl (Z = 17):

[H] = 1s¹     1 electron available.

[C] = 1s² 2s² 2p²   In this case, we have 4 electrons.

[Cl] = 1s² 2s² 2p⁶ 3s² 3p⁵  In this case, 7 electrons.

Now that we have the configuration, and the available electrons, we need to draw the atoms. The Carbon is the more electronegative atom of them, so, the bonding will be formed based on this atom as the central. So the other atoms will just bond and shared a pair of electron with the carbon. The HCCl₃ can be treated as CH₄, with a tetrahedrical form.

The picture below shows the lewis structure.

Hope this helps

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