You prepare a standard by weighing 10.751 mg of compound X into a 100 mL volumetric flask and making to volume. You further dilute this solution 5 mL to 25 mL. This standard gives an area of 4,374. Your sample is prepared by adding 5 mL of sample solution into a 50 mL flask and making to volume. This gives an area count of 2,582. Calculate the concentration of compound X in the sample - prior to dilution.

Answers

Answer 1

Answer:

0.12693 mg/L

Explanation:

First we calculate the concentration of compound X in the standard prior to dilution:

10.751 mg / 100 mL = 0.10751 mg/mL

Then we calculate the concentration of compound X in the standard after dilution:

0.10751 mg/mL * 5 mL / 25 mL = 0.021502 mg/L

Now we calculate the concentration of compound X in the sample, using the known concentration of standard and the given areas:

2582 * 0.021502 mg/L ÷ 4374 = 0.012693 mg/L

Finally we calculate the concentration of X in the sample prior to dilution:

0.012693 mg/L * 50 mL / 5 mL = 0.12693 mg/L

Related Questions

If the rate of decomposition of ammonia, NH3, at 1150 K is 2.10 x 10-6 mol/L/s, what is the
rate of production of nitrogen and hydrogen? Given 2NH3 3H2 + N2

Answers

Answer:

3.15 × 10⁻⁶ mol H₂/L.s

1.05 × 10⁻⁶ mol N₂/L.s

Explanation:

Step 1: Write the balanced equation

2 NH₃ ⇒ 3 H₂ + N₂

Step 2: Calculate the rate of production of H₂

The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s

Step 3: Calculate the rate of production of N₂

The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s

The Answer is: 3.15 × 10⁻⁶ mol H₂/L.s; 1.05 × 10⁻⁶ mol N₂/L.s

Step 1:  When we Write the balanced equation

Then 2 NH₃ ⇒ 3 H₂ + N₂

Step 2: Calculate the rate of production of H₂

After that, The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:Now 2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s

Step 3: Calculate the rate of production of N₂

After that, The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:Now 2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s

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A reaction vessel for synthesizing ammonia by reacting nitrogen and hydrogen is charged with 5.54 kg of H2 and excess N2. A total of 25.6 kg of NH3 are produced. What is the percent yield of the reaction?

Answers

Answer:

81.5

Explanation:

smartworks

Use this picture to explain that an electrically charged object can attract an uncharged object without any contact. Your answer should be at least three sentences long. (2 points) a balloon hanging from a string with small pieces of paper stuck to the bottom of it, with a few pieces on the ground

Answers

Answer: Insufficient amount of work provided.

Explanation:

The addition, removal, or substitution of nitrogenous bases in a DNA molecule may be caused by . Synapsis C. Disjunction B. Hybridization D. Mutation

Answers

Answer:

D. Mutation

Explanation:

Mutation is any change or alteration that occurs to the nucleotide sequence of a gene induced during DNA replication or by mutation-causing substances called MUTAGENS.

Mutation can be in the form of addition, removal, or substitution of nitrogenous bases in a DNA molecule. For example, in an original DNA sequence as follows: GAT ATC TGA, the following mutation can occur:

Addition: GAT ATC CTG A

Removal: GAT ATT GA

Substitution: GAT CTC TGA

How many molecules of N204 are in 85.0 g of N2O4?

Answers

Answer:

5.56 x 10^23

Explanation:

Just convert and cancel out.

85 g N2O4 x 1 mol/92.01 g x 6.02 x 10^23 molecules /1 mol

is sublimation a chemical change or chemical property or physical change?

Answers

Answer:

Physical Change

Explanation:

Sublimation is a physical change. When a substance sublimes, it changes from a solid to a gas without going through the liquid phase.

What is one way humans can preserve biodiversity

Answers

Answer:

Reducing the amount of water you use, by having a 5-minute shower or not running the water when washing up the dishes, can help protect vital wetlands. Plant scientists are also working to help conserve by developing crop varieties that use less water.

Explanation:

Answer:

1. Most of the endangered organisms may represent a source of income.

2. The conservation or preservation may conflict with morals.

3. The role of the species or organisms might not be understood.

Explanation:

Biodiversity simply means the amount or number of living organisms that exist in the world.

The practice of protecting these existing living organisms for specific known purposes is regarded as the preservation or conservation of biodiversity.

This process or practice of preserving biodiversity is important to meet most of the human needs, such as generating income, source of food and fuel among others.

Convert 8.19 x 10-14 moles of gold to atoms.

Answers

Answer:

4.932018 × 10¹⁰ atoms

Explanation:

Recall that:

1 mole = 6.022 × 10²³ atoms

To change 8.19× 10⁻¹⁴ moles to atoms;

Then, we have:

= (8.19× 10⁻¹⁴× 6.022 × 10²³ atoms)

= 4.932018 × 10¹⁰ atoms

Which of these compounds are molecular?
CBr4
FeS
P4O6
PbF2

Answers

Answer:

I think it's answer is P4O6

I hope it's helpful for you...

Do nitrates always form precipitates?

Answers

Answer:

Nitrates compared to sulphates are much more soluble therefore won't form precipitates easily.

why are electrical wires covered with plastic coating​

Answers

Answer:

For safety.

Explanation:

Because uncovered wires are conductors, an electric current could damage someone if touched. Plastic and rubber are insulators, meaning that current cannot pass through them.

g At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H 2 (g) Br 2 (g) 2HBr (g) A mixture of 0.682 mol of H 2 and 0.440 mol of Br 2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.516 mol of H 2 present. At equilibrium, there are ________ mol of Br 2 present in the reaction vessel.

Answers

Answer: At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]

Explanation:

Moles of  [tex]H_2[/tex] = 0.682 mole

Moles of  [tex]Br_2[/tex] = 0.440 mole

Volume of solution = 2.00 L

Initial concentration of [tex]H_2[/tex] = [tex]\frac{0.682}{2.00}=0.341 M[/tex]

Initial concentration of [tex]Br_2[/tex] =  [tex]\frac{0.440}{2.00}=0.220 M[/tex]

Equilibrium concentration of [tex]H_2[/tex] = [tex]\frac{0.516}{2.00}=0.258 M[/tex]

The given balanced equilibrium reaction is,

             [tex]H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)[/tex]

Initial conc.   0.341 M    0.220 M        0 M    

At eqm. conc.   (0.341-x) M   (0.220-x) M   (2x) M

Given : (0.341-x) M = 0.258 M

x= 0.083 M

Thus equilibrium concentartion of [tex]Br_2[/tex] = (0.220-0.083) M = 0.137 M

Thus moles of [tex]Br_2[/tex] at equilibrium = [tex]0.137M\times 2.00L=0.274mol[/tex]

At equilibrium , there are 0.274 moles of [tex]Br_2[/tex]

In an experiment, 135.2 grams of a mystery metal is heated to 100.0*C. The metal is then dumped into a calorimeter with 59.0 grams of water at 26.0*C. The temperature of the water in the calorimeter increases to 35.0*C after the metal is dumped into it. What is the specific heat capacity of the metal? Express your answer to 2 past the decimal. Do NOT include units

Answers

The answer wound be 23 units I think

define the term semiconductor and give an example of a metalloid

Answers

Answer:

A metalloid is a chemical element that exhibits some properties of metals and some of nonmetals.The closer you get to the zone, the more blurred the properties become. Metalloids tend to be semiconductors; silicon is the best known example of a semiconductor. Most microchips and microprocessors are made with silicon.

Explanation:

That is what i know on the answer

To solve this we must be knowing each and every concept related to metalloid. Therefore, in above given ways semiconductor can be defined.

What is metalloid?

Metalloids are chemical elements with physical and chemical characteristics that fall between between metal and nonmetal.

A metalloid is indeed a chemical element with characteristics of both metals and nonmetals. The properties grow increasingly blurred as you move closer to the zone. The seven most well-known metalloids are boron, germanium, silicon, antimony, arsenic, tellurium, and polonium.

Metalloids are often semiconductors, with silicon being the most well-known example. Silicon is used to make the majority of microchips and microprocessors.

Therefore, in above given ways semiconductor can be defined.

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Which metals will switch in this single replacement reaction Zn + MgO -->

a. Mg and Zn

b. Zn and O

c. Mg and O

d. This is not a single replacement reaction

Answers

Answer:

D

Explanation:

Magnesium is more reactive than zinc so no reaction will take place

gases are really _______ and molecules are full of _______, bouncing around constantly

Answers

Gases are really spread out and the atoms and molecules are full of energy - , bouncing around constantly.

Answer:Gases are really spread out and the atoms and molecules are full of energy - , bouncing around constantly.

Explanation:

Is chemistry required to get into speech language pathology?​

Answers

Answer:

As of right now (4-7-2021), the physical science requirement for the SLP certificate must be met by completing coursework in the areas of either chemistry or physics.

calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of water and the normal boiling point of water the molar entropy change accompanying fussion is 22.0 and that accompanying evaporation

Answers

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is [tex]-22Jmole^-^1k^-^1[/tex]

(b) The normal boiling point of water (J·K−1·mol−1) is [tex]-109Jmole^-^1K^-^1[/tex]

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is  109J/mole

Explanation:

Lets calculate

(a) - General equation -

      [tex](\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p[/tex] = [tex]-5_m(\beta )+5_m(\alpha )[/tex] =  [tex]-\frac{\Delta H}{T}[/tex]

 [tex]\alpha ,\beta[/tex] → phases

ΔH → enthalpy of transition

T → temperature transition

 [tex](\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p[/tex] =[tex]= -\frac{\Delta_fH}{T_f}[/tex]

            = [tex]\frac{-6.008kJ/mole}{273.15K}[/tex] ( [tex]\Delta_fH[/tex] is the enthalpy of fusion of water)

           = [tex]-22Jmole^-^1k^-^1[/tex]

(b) [tex](\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}[/tex]

                                  = [tex]\frac{40.656kJ/mole}{373.15K}[/tex] ([tex]\Delta_v_a_p_o_u_rH[/tex] is the enthalpy of vaporization)

                               = [tex]-109Jmole^-^1K^-^1[/tex]

(c) [tex]\Delta\mu =\Delta\mu(l)-\Delta\mu(s)[/tex] =[tex]-S_m\DeltaT[/tex]

[tex][\mu(l-5[/tex]°[tex]C)-\mu(l,0[/tex]°[tex]C)][/tex] =  [tex][\mu(s-5[/tex]°[tex]C)-\mu(s,0[/tex]°[tex]C)][/tex][tex]=-S_m[/tex]ΔT

[tex]\mu(l,-5[/tex]°[tex]C)-\mu(s,-5[/tex]°[tex]C)=-Sm\DeltaT [\mu(l,0[/tex]

[tex]\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)[/tex]

     = 109J/mole

5. How many grams of Br is needed to make 1000.g of a 2.0ppm solution?

Answers

Answer:

2.0 × 10⁻³ g

Explanation:

Step 1: Given data

Mass of solution: 1000. g (1.000 kg)Concentration of Br₂: 2.0 ppm

Step 2: Calculate the mass of Br₂ required to prepare the solution

The concentration of Br₂ is 2.0 ppm, that is, there are 2.0 mg of Br₂ per kilogram of solution. The mass of Br₂ required to prepare 1.000 kg of solution is:

1.000 kg Solution × 2.0 mg Br₂/1 kg Solution = 2.0 mg

Step 3: Convert the mass to grams

We will use the conversion factor 1 g = 1000 mg.

2.0 mg × 1 g/1000 mg = 2.0 × 10⁻³ g

What are the products for

Answers

Answer:

[tex]ZnCO_3(s)+2KNO_3(aq)[/tex]

Explanation:

Hello there!

In this case, for the referred reactants side, we can evidence that this is a double displacement reaction whereby Zn gets bonded with CO3 and therefore K gets bonded with NO3 to yield:

[tex]Zn(NO_3)_2+K_2CO_3\rightarrow ZnCO_3+2KNO_3[/tex]

Whereas the KNO3 product is aqueous and the ZnCO3 is solid due to the corresponding solubility rules. Thereby, the answer is the third one.

Regards!

For each pair of covalently bonded atoms, choose the one expected to have the shortest bond length. (A) C-I (B) H-I ...... (A,B) fill in the blank 1 (C) H-Cl (D) H-I ...... (C,D) fill in the blank 2

Answers

Answer:

i)  B

ii) D

Explanation:

Bond length is determined by the size of the atoms involved and the bond order

A) C-I

B)  H-I

answer : H-I has the shortest bond length because H has an electronegativity value of 2.2  while C has an electronegativity value of 2.5 hence the bond between H-I is greater than C - I due the electronegativity difference between H-I is greater as well.

C) H-Cl

D) H-I

answer :  H-Cl has the shortest bond length due the electronegativity difference between H-CI is greater as well.

Atoms in the same PERIOD have the same...

A. Number of energy levels
B. Size
C. Temperature
D. Reactivity

Answers

Answer:

A. Number of energy levels

NEED HELP FOR THIS ONE

Answers

Answer:

C₆H₁₂O₆ + 6 O₂ = 6 CO₂ + 6 H₂O

2 KO₂ + H₂O = 2 KOH + 1.5 O₂

Explanation:

Let's consider the following unbalanced equation.

C₆H₁₂O₆ + O₂ = CO₂ + H₂O

We will start balancing H atoms (higher atomicity) by multiplying H₂O by 6.

C₆H₁₂O₆ + O₂ = CO₂ + 6 H₂O

Then, we will balance C atoms by multiplying CO₂ by 6.

C₆H₁₂O₆ + O₂ = 6 CO₂ + 6 H₂O

Finally, to get the balanced equation, we will multiply O₂ by 6.

C₆H₁₂O₆ + 6 O₂ = 6 CO₂ + 6 H₂O

---

Let's consider the following unbalanced equation.

KO₂ + H₂O = KOH + O₂

We will multiply KO₂ and KOH by 2 to balance K and H atoms.

2 KO₂ + H₂O = 2 KOH + O₂

Finally, to get the balanced equation, we will multiply O₂ by 1.5.

2 KO₂ + H₂O = 2 KOH + 1.5 O₂

visible light travels from place to place as a

Answers

Answer:

Light can travel in three ways from a source to another location: (1) directly from the source through empty space; (2) through various media; (3) after being reflected from a mirror.

Explanation:

Big assignment please help. Will do anything

Answers

When I try to click on the picture it doesnt let me, is it an actual picture? Or..
For trolls

1. What do you call the continuous change in position of a body relative to a pon
reference point, as measured by a particular observer in a particular frame
of reference?

Answers

Answer:

In physics, motion means a continuous change in the position of a body relative to a reference point, as measured by a particular observer in a particular frame of reference.

Explanation:

what is an example of an electrolyte solution?

Answers

Answer:

nacl with water

they are capable of conducting electricity

Which term describes something that displays all the characteristics of life?
a.homeostasis
b.organism
c.stimulus
d.unicellular

Answers

A, it says on here good luckkkkkk

The spinning of Earth on its axis is an example of its ________.

Answers

Answer:

rotation

Explanation:

Answer:

Rotation

Explanation:

Earth rotates on it's axis to give us the day and night cycle

K(+1)Cl(+5)O3(-2) → K(+1)Cl(-1) + O2(0)

Answers

Answer:

Looooolllllllllllll

Explanation:

What is the question bro

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