38. You are fishing and catch a fish with a mass of
6kg. If the fishing line can withstand a maximum
tension of 30 N, what is the maximum acceleration
you can give the fish as you reel it in?..*
(10 Points)
Enter your answer​

Answer:

c. speed

Explanation:

Speedometer is a device used to measure the speed of a vehicle. I am pretty sure this is the correct option.

Answer:

Explanation:

These are the laws of Newton

Answer:

the first law, an object will not change its motion unless a force acts upon it. the 2nd one, the force of an object is equal to its mass times it acceleration. the 3rd one is when 2 objects interact, they apply forces to each other of equal magnitude and opposite direction.

Answer:

Explanation:

Step one:

given data

acceleration a=4m/s^2

final velocity v=35m/s

time t=5 seconds

Step two:

Required

initial velocity u=?

Applying the first equation of motion

v=u+at

substituting we have

35=u+4*5

35=u+20

u=35-20

u=15 m/s

The initial velocity is 15m/s

Answer:

C. a liter of salt water.

Explanation:

Defination of Solution =>

a liquid mixture in which the minor component (the solute) is uniformly distributed within the major component (the solvent).

Answer:

+ 14

Explanation:

18 protons make a positive 18 charge (+18)

4 electrons make a negative 4 charge (-4)

both combined give + 18 - 4 = + 14

The four neutrons don't carry net charge, so the addition of the electrons doesn' affect the net charge found above which still gives + 14.

Answer:

F = 1.63 x 10⁻⁹ N

Explanation:

Complete question is as follows:

The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers. Find the magnitude of Gravitational Force?

Answer:

The gravitational force is given by Newton's Gravitational Law as follows:

F = Gm₁m₂/r²

where,

F = Gravitational Force = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = m₂ = mass of each ball = 7 kg

r = distance between balls = 2 m

Therefore,

F = (6.67 x 10⁻¹¹ N.m²/kg²)(7 kg)(7 kg)/(2 m)²

F = 1.63 x 10⁻⁹ N

Answer:

hinata

Explanation:

unlike sakura she has not change at all

In my opinion, Sakura looks prettier and she developed way more than Hinata. Personally, I dislike the both of them because of their Tsundere side, but there's no doubt Sakura developed way more than Hinata. In the original Naruto series, Sakura was honestly a burden. There were some missions where Team 7 had to rescue Sakura. However, after the training with Tsunade, she gained monster strength and healing abilities. Additionally, throughout Naruto Shippuden she learned new jutsu like Yin Seal: Release.    

     However with Hinata, it's a bit more different. In the original Naruto series, I feel believe she was stronger than Sakura. She relied on her infamous visual prowess--the Byakugan. However in Naruto Shippuden, she improved slightly compared to Sakura. In my opinion, she would have been the most useless shinobi out of the eleven characters (YES, more useless than Tenten) if it weren't for her visual prowess. She's fortunate that she was born into the Hyuga clan. Every jutsu that's in her arsenal relies heavily on the Byakugan. And if Sakura and Hinata were to battle each other, it's most likely that Sakura would win. It's true that Hinata can block Sakura's chakra points, but I think she could dodge her attacks. And even if her chakra points are blocked, Sakura can rely on Taijutsu and raw strength to win.

Though both kunoichi are honorable, I believe Sakura is more prettier and stronger than Hinata.

Answer:

The power factor of the circuit is 0.99

Explanation:

Given;

resistance of the resistor, R = 65.2 ohms

capacitance of the capacitor, C = 2.26 μF = 2.26 x 10⁻⁶ F

inductance, L = 2.08 mH = 2.08 x 10⁻³ H

frequency of the AC, f = 2400 Hz

The angular frequency is given by;

ω = 2πf

ω = 2π(2400) = 15081.6 rad/s

The inductive reactance is given by;

XL = ωL

XL = (15081.6 x 2.08 x 10⁻³)

XL = 31.37 ohms

The capacitive reactance is given by;

[tex]X_c = \frac{1}{\omega C} \\\\X_c = \frac{1}{(15081.6)(2.26*10^{-6} )}\\\\X_c = 29.34 \ ohms[/tex]

The phase difference is given by;

[tex]tan\phi = \frac{X_l - X_c}{R}\\\\ tan\phi =\frac{31.37-29.34}{65.2} \\\\tan\phi = 0.0311 \\\\\phi = tan^{-1} (0.0311)\\\\\phi = 1.78^0[/tex]

The power factor is given by;

CosФ = Cos(1.78) = 0.99

Therefore, the power factor of the circuit is 0.99

Answer:

The height risen by the ball is 39.8 m.

Explanation:

Given;

total time spent in air by the ball, t = 5.7 s

time to rise to maximum height, t = 5.7 /2 = 2.85 s

The initial velocity of the ball is given by;

v = u - gt

where;

v is the final velocity at maximum height = 0

u is the initial velocity of the ball

0 = u - gt

u = gt

u = (9.8 x 2.85)

u = 27.93 m/s

The vertical height traveled by the ball is given by;

v² = u² - 2gh

where;

v is the final velocity of the ball at maximum height = 0

g is acceleration due to gravity = 9.8 m/s²

0 = u² - 2gh

2gh = u²

h = u² / 2g

h = (27.93)² / ( 2 x 9.8)

h = 39.8 m

Therefore, the height risen by the ball is 39.8 m.

Answer:

D

Explanation:

Hydrogen, oxygen, and water are pure substances that each have different properties.

Although the 3 of them are pure substances, but they nonetheless have different properties. These properties could either be their physical properties, or their chemical properties. This is particularly so because since Oxygen and Hydrogen the major components in water have different properties, it is only right if their product, water, has different properties also.

Answer:

D

Explanation:

got it right on study island

Explanation:

yooooooooo

Answer:

Explanation:

Impulse is the change of momentum of an object when the object is acted upon by a force for an interval of time.

the expression is Ft=mv

where F= force

 m= mass

t= time

v= velocity

Step one:

given data

mass m= 110g= 0.11kg

velocity v= 6.5m/s

time t= 0.19seconds

Step two:

we also know that the force on impulse is given as

Ft=mv

F=0.11*6.5/0.19

F=0.715/0.19

F=3.76N

The magnitude of the average force on the wall if the duration of the collision is 0.19 is 14N

Answer:

a. by moving the book without acceleration and keeping the height of the book constant

Explanation:

FOR CONSTANT KINETIC ENERGY:

The kinetic energy of a body depends upon its speed according to its formula:

ΔK.E = (1/2)mΔv²

So, for Δv = 0 m/s

ΔK.E = 0 J

So, for keeping kinetic energy constant, the books must be moved at constant speed without acceleration.

FOR CONSTANT POTENTIAL ENERGY:

The potential energy of a body depends upon its height according to its formula:

ΔP.E = mgΔh

So, for Δh = 0 m/s

ΔP.E = 0 J

So, for keeping potential energy constant, the books must be moved at constant height.

So, the correct option is:

a. by moving the book without acceleration and keeping the height of the book constant

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 976 × 2.5

We have the final answer as

Hope this helps you

Answer:

67500

Explanation:

F=ma

F = 1500 × 45

F = 67500

Answer:

The energy stored is [tex]E_s = 0.0064 \ J[/tex]

Explanation:

From the question we are told that  

   The capacitance  is  [tex]C = 8 \ \mu F = 8*10^{-6} \ F[/tex]

    The resistance is  R = 3.00-Ω

    The emf is  [tex]E_t = 70.0 V[/tex]

      The power  is  P = 300 W

Generally the total  emf is mathematically represented as

   [tex]E_t = E_c + E_r[/tex]

Here  [tex]E_c[/tex] is the emf across that capacitor which is mathematically represented as

      [tex]E_c = \frac{q}{C}[/tex]

and [tex]E_r[/tex] is the emf across the resistor which is mathematically represented as

       [tex]E_r = \sqrt{P R}[/tex]

So  

       [tex]E_t = \sqrt{PR} + \frac{q}{C}[/tex]

=>    [tex]q = C[E_t - \sqrt{PR} ][/tex]

Generally the energy stored in a capacitor is mathematically represented as

          [tex]E_s = \frac{q^2}{2C}[/tex]

=>      [tex]E_s = \frac{[C [ E_t - \sqrt{PR} ]]^2}{2C}[/tex]

=>      [tex]E_s = \frac{[8.0*10^{-6} [ 70 - \sqrt{300 * 3}}{2 *(8.0*10^{-6})}[/tex]

=>      [tex]E_s = 0.0064 \ J[/tex]

The energy that has been stored in the capacitor will be 0.0064 J. The stored energy is utilized in the different electrical works.

A capacitor is a device that can store electrical energy. It is a two-conductor configuration separated by an insulating medium that carries charges of equal size and opposite sign.

An electric insulator or vacuum, such as glass, paper, air, or a semi-conductor termed a dielectric, can be used as the non-conductive zone.

The given data in the problem is;

C is the capacitance = 8.00-μF = 8.00 ×10 ⁻⁶

R is the resistance =  3.00-Ω

E is  the emf  = 70.0 V

P is the power  = 300 W

The total emf is the sum of the emf due to the capacitor and emf due to the resistor;

[tex]\rm E_t = E_C + E_R[/tex]

The emf generated by the capacitor is;

[tex]\rm E_C = \frac{q}{C}[/tex]

[tex]\RM E_R = \sqrt{PR}[/tex]

[tex]\rm E_t = \frac{q}{C} + \sqrt{PR} \\\\ \rm q= C [ E_t-\sqrt{PR} ]\\\\[/tex]

Generally, the energy stored in the capacitor is;

[tex]\rm E_S= \frac{q^2}{2C} \\\\ \rm E_S= \frac{\rm C [ E_t-\sqrt{PR} ]\\\\^2}{2C} \\\\ \rm E_S= \frac{\rm 8.0 \times 10^{-6}[ 70-\sqrt{300\times 3} ]\\\\^2}{2 \times (8.0 \times 10^{-6}} \\\\ \rm E_S= 0.0064 \ J[/tex]

Hence the energy that has been stored in the capacitor will be 0.0064 J.

To learn more about the capacitor refer to the link;

https://brainly.com/question/14048432

Answer:

D. [tex]\vec F_{B} = -20\,\hat{i}-15\,\hat{j}\,\,\,[N][/tex]

Explanation:

The statement is not correctly written, the correct form is now described:

A particle with charge [tex]q = -1\,C[/tex] is moving in the positive z-direction at 5 meters per second. The magnetic field at its position is [tex]\vec B = 3\,\hat{i}-4\,\hat{j}\,\,\,[T][/tex]. What is the magnetic force on the particle?

From classic theory on Magnetism, we remember that the magnetic force  exerted on a particle ([tex]\vec F_{B}[/tex]), measured in newtons, is determined by the following vectorial formula:

[tex]\vec F_{B} = q\cdot \vec v \,\times \,\vec B[/tex] (1)

Where:

[tex]q[/tex] - Electric charge, measured in coulombs.

[tex]\vec v[/tex] - Velocity of the particle, measured in meters per second.

[tex]\vec B[/tex] - Magnetic field, measured in teslas.

If we know that [tex]q = -1\,C[/tex], [tex]\vec v = 5\,\hat{k}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\vec B = 3\,\hat{i}-4\,\hat{j}\,\,\,[T][/tex], then the magnetic force on the particle is:

[tex]\vec F_{B} = \left|\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\0\,\frac{C\cdot m}{s}&0\,\frac{C\cdot m}{s} &(-1\,C)\cdot (5\,\frac{m}{s} ) \\3\,T&-4\,T&0\,T\end{array}\right|[/tex]

[tex]\vec F_{B} = -(-4\,T)\cdot (-1\,C)\cdot \left(5\,\frac{m}{s} \right)\,\hat{i}+(-1\,C)\cdot\left(5\,\frac{m}{s} \right)\cdot (3\,T)\,\hat{j}[/tex]

[tex]\vec F_{B} = -20\,\hat{i}-15\,\hat{j}\,\,\,[N][/tex]

Which corresponds to option D.

Answer:

A. -5.5 N

Explanation:

I can confirm that the answer is A.

Answer:

Explanation:

Step one:

given data

initial velocity u= 0m/s since the ball is at rest

time of contact t= 0.3s

final velocity v=15m/s

Required

acceleration a

from the first law of motion

v=u+at

substitute our given data

15=0+a*0.3

15=0.3a

divide both sides by 0.3

a=15/0.3

a=50m/s

The average acceleration is 50m/s^2

The time taken by the car to achieve the final speed is 6.25 seconds.

The equations of motion can be defined as the equation that represents the relationship between the time, velocity, acceleration, and displacement of a moving object.

The mathematical expressions for the equations of motions can be written as:

[tex]v= u+at\\S=ut+(1/2)at^2\\v^2-u^2=2aS[/tex]

Given, the initial speed of the car, u = 15 m/s

The final speed of the given car, v = 25m/s

The distance covered by car, S = 125 m

From the third equation of motion: v² = u²+ 2aS

(25)² = (15)² + 2×a× 125

a = 1.6 m/s²

From the first equation of motion we can find the time to achieve the final speed:

v = u+ at

25 = 15 + (1.6) × t

t = 6.25 sec

Therefore, 6.25 seconds will be taken by the car to catch the final speed.

Learn more about the equation of motion, here:

brainly.com/question/16982759

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Answer:

B. Sound waves will not be transformed into electrical signals.

Explanation:

edge2021

Sound waves will not be transformed into electrical signals is the reason that microphone on an AM radio is not working properly.

It is a type of mechanical wave composed of the disturbance caused by the movements of the energy. A sound wave travels through compression and rarefaction in an elastic medium such as air.

The microphone on an AM radio is not working properly means sound waves are not transforming into electrical signals.

Learn more about sound waves

brainly.com/question/11797560

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Answer:

Umm sorry just came for the points.

Answer:

17. NADH has a molar extinction coefficient of 6200 M2 cm at 340 nm. Calculate the molar concentration of NADH required to obtain an absorbance of 0.1 at 340 nm in a 1-cm path length cuvette. 18. A sample with a path length of 1 cm absorbs 99.0% of the incident light at a wavelength of 274 nm, measured with respect to an appropriate solvent blank. Tyrosine is known to be the only chromophore present in the sample that has significant absorption at 274 nm. Calculate the molar concentration of tyrosine in the sample.

Explanation: