Answer:
[tex]M=1.05M[/tex]
Explanation:
Hello!
In this case, since the formula for the calculation of molarity is defined in terms of moles and volume in liters as shown below:
[tex]M=\frac{n}{V}[/tex]
Whereas the moles are computed by considering the molar mass of CaCO3 (100.09 g/mol):
[tex]n=47.4g*\frac{1mol}{100.09g}=0.4736mol[/tex]
Thus, we obtain:
[tex]M=\frac{0.4736mol}{0.450L}\\\\M=1.05M[/tex]
Best regards!
the atomic number of potassium is 19. How many electrons does this element have?
Answer:
Potassium is an element that has 19 electrons
pertain to the following class, Point:
public class Point {
private double x;
private double y;
public Point() {
this (0, 0);
}
public Point(double a, double b) {
/* missing code */
}
// ... other methods not shown
}
Which of the following correctly implements the equals method?
public boolean equals(Point p) {
return (x == p.x && y == p.y );
}
public void equals(Point p) {
System.out.println(x == p.x && y == p.y);
}
public void equals(Point p) {
return (x == p.x && y == p.y );
}
public boolean equals(Point p) {
return (x == Point.x && y == Point.y);
}
public boolean equals(Point p) {
System.out.println(x == p.x && y == p.y);
}
_______________________
The default constructor sets x and y to (0, 0) by calling the second constructor. What could be used to replace /* missing code */ so that this works as intended?
a = 0;
b = 0;
this (x, y);
this(0, 0);
x = a;
y = b;
a = x;
b = y;
_____________________
Which of the following correctly implements a mutator method for Point?
public double getX() {
return x;
}
public void setCoordinates (double a, double b) {
x = a;
y = b;
}
None of the items listed.
public double getX() {
return a;
}
public void setCoordinates (double a, double b) {
Point p = new Point(a,b);
}
b = 0;
this (x, y);
this(0, 0);
x = a;
y = b;
a =x
This above solution is just according to the public boolean equals(Point p) { return (x == p.x && y == p.y ); and public void equals(Point p) { System.out.println(x == p.x && y == p.y);}
What is public void?An abstract class contains a pure virtual function. Pure virtual class cannot be instantiated but it can be subclassed and the subclass can provide an implementation of the function.
A virtual function declaration in the class is preceded by the virtual keyword. For example, virtual void print();
A pure virtual function declaration is followed by '=0;'
public: virtual void print()=0;
The main method header is written as public static void main(String[] args). A main method is something that is required in Java. You must have at least one class with a method named main. In Java, main is a static method, which means that it is part of its class but not parts of objects.
Therefore, This above solution is just according to the public boolean equals(Point p) { return (x == p.x && y == p.y ); and public void equals(Point p) { System.out.println(x == p.x && y == p.y);}
Learn more about System.out.println on:
https://brainly.com/question/19467372
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A pi bond involves: Select the correct answer below: direct orbital overlap with the electron density concentrated along the internuclear axis. side-by-side, or lateral orbital overlap with the electron density concentrated on opposite sides of the internuclear axis. side-by-side, or lateral orbital overlap with the electron density concentrated along the internuclear axis. none of the above
Answer:
side-by-side, or lateral orbital overlap with the electron density concentrated on opposite sides of the internuclear axis.
Explanation:
Pi bond is a type of covalent bond in which the internuclear axis has regions of orbital overlap below and above it i.e on opposite sides. As a result of the orbital overlap, a node is created along the internuclear axis.
This ultimately implies that, a pi bond is formed due to the lateral (side-by-side) overlap of the unhybridized P-orbital comprising of at least a node along the internuclear axis.
Hence, a pi bond involves side-by-side, or lateral orbital overlap with the electron density concentrated on opposite sides of the internuclear axis.
Additionally, a node is typically formed where an electron cannot be found.
Write the molecular equation for the reaction that occurs, if any, when solutions of the following substances are mixed: nitric acid and potassium carbonate. Make sure that you have properly identified all of the phases in your answer.
Answer:
The balanced molecular equation for the reaction is:
[tex]2HNO_{3_{(aq)} }[/tex] + [tex]K_{2} CO_{3} _{(s)}[/tex] → [tex]2KNO_{3} _{(s)}[/tex] + [tex]H_{2} O_{(l)[/tex] + [tex]CO_{2} _{(g)}[/tex]↑
Explanation:
The weak nitric acid reacts with the strong potassium base to produce salt, water and carbon dioxide which is given off.
Molecular ratio of reactants is 2 : 1.
All phases are represented in the equation: aq for aqueous, l for liquid and g for gas (notice how they are written in subscript).
I hope this was helpful.
PLEASE HURRY ILL GIVE 95 POINTS!
A student dissolved 5g of table salt in 100 mL of water in a beaker. When you compare the total mass of the salt and water before mixing to the mass of the solution after mixing, which is true?
A. The total mass of the solution after mixing, Will increase by a large amount
B. The total mass of the solution after mixing, Will increase by a small amount
C. The total mass of the solution after mixing will neither increase nor decrease
D. The total mass of the solution after mixing, Will decrease by a small amount
Answer:
B.
Explanation:
Answer:
B is the correct answer
Explanation:
Choose the correct statement regarding the behavior of water.Group of answer choicesThe heat capacity of liquid water is greater than the heat capacity of solid ice.The water phase with the smallest temperature increase when adding 10 kcal of heat is solid ice.Ice has a higher density than liquid water and therefore sinks.The water phase with the smallest temperature increase when adding 10 kcal of heat is gas vapor.The heat capacity of gas vapor is greater than the heat capacity of liquid water.
Answer:
The water phase with the smallest temperature increase when adding 10 kcal of heat is solid ice.
Explanation:
The rest of the statements are incorrect. The density of ice is lower than the density of water. The heat capacity of solid ice is greater almost twice the heat capacity of the liquid water. The heat capacity of vapors is less than heat capacity of liquid.
What is the concentration of lithium ions in 0.400 M Li₂HPO₄?
Answer: 0.800 M
Basically, the ratio is 2:1, so when you have 1 M of Li2HPO4 it means you have 2 M in the concentration of lithium ions. So knowing the ratio, we know we just need to multiply 0.400 x 2.
I'm bad at explaining it, but got it right on chem101 sooo
The concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄ is 0.8 M.
The concentration of a substance is simply the amount of the substance in 1 L of water.
To obtain the concentration of lithium ion, Li⁺ in Li₂HPO₄, we'll begin by writing the dissociation equation of Li₂HPO₄. This is illustrated below:
Li₂HPO₄ (aq) <=> 2Li⁺(aq) + HPO₄²¯(aq)From the balanced equation above,
1 mole of Li₂HPO₄ produced 2 moles of Li²⁺.
Finally, we shall determine the concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄. This can be obtained as follow:
From the balanced equation above,
1 mole of Li₂HPO₄ produced 2 mole of Li⁺.
Therefore, 0.4 M Li₂HPO₄ will produce = 2 × 0.4 = 0.8M Li²⁺
Thus, 0.8 M lithium ion, Li⁺ is present in the solution.
Learn more: https://brainly.com/question/19536817
How many moles are in 3.01 x 10^23 atoms of zinc?
Answer:
What is ^ for?
Explanation:
Did i answer these right??
Draw the major organic product in the reaction scheme. Be sure to clearly show stereochemistry (if applicable).The starting material is an alkyne where carbon 1 is bonded to cyclopentane and carbon 2 is bonded to H. Step 1 is N a N H 2. Step 2 is C H 3 I. Step 3 is sodium in liquid ammonia.
Answer:
See explanation below
Explanation:
According to what you state in the problem, we have an ethyne bonded to a cyclopentane.
So, in the 1st step reacts with NaNH₂. In this step, the base which is very strong will substract the hydrogen from carbon 2, forming an anion in there. In the second step, this anion will react with CH₃I, and form a larger chain, the methyl group is attached to the alkyne.
Finally in the last step reacts with sodium in ammonia, this is to reduct the triple bond to just a single bond and leave an alkane only. The picture below shows these steps.
Hope this helps.
What is the name of the sugar that is created
through photosynthesis?
Nopetose
Glucose
Sucrose
Blooptose
:D
Answer:
Glucose!!
Explanation:
Also keep in mind that the actual sugar produced from photosynthesis is C6H12O6, which is the basis for glucose as well as other complex molecules
Answer:
Glucose
Explanation:
photosynthesis uses the energy from the light to convert carbon dioxide molecules which makes glucose
Calculate the pH of a solution that is prepared by dissolving 0.23 mol of hydrofluoric acid (HF) and 0.57 mol of hypochlorous acid (HClO) in water and diluting to 3.60 L. Also, calculate the equilibrium concentrations of HF, F2, HClO, and ClO2. (Hint: The pH will be determined by the stronger acid of this pair.)
Answer:
The equilibrium concentrations of HF = 0.058 , F2 = 0.006M , HClO =0.16M , and ClO2 = 7.7 × 10⁻⁷M.
Explanation:
The Ka values for HClO₃ and HF are given as 2.9 × 10⁻⁸ and 6.6 × 10⁻⁴ respectively. The molar concentration for HF = 0.23/ 3.60L = 0.064 M and 0.57/ 3.60 = 0.16 M.
When HF is reacted with water, it ionizes to form H₃O⁺ and F⁻. The concentration of H₃O⁺ and F⁻ can be calculated below:
HF(aq) <------------------------> H30^+ + F^-.
Ka = [H^+] [F^-]/[HF] .
6.6× 10^-4 = [x][x]/ ( 0.064- x).
x = 0.0060 M.
The concentration of H₃O⁺ and F⁻ = 0.0060 M respectively.
The pH = - log [ H₃O⁺ ] = -log [0.0060] = 2.22.
When HClO is reacted with water, it ionizes to form H₃O⁺ and F⁻. The concentration of H₃O⁺ and ClO⁻ can be calculated below:
HClO(aq) <------------------------> H30^+ + ClO^-.
Ka = [H^+] [ClO^-]/[HClO] .
6.6× 10^-4 = [0.006 + x] [x]/ ( 0.16 - x).
x = 7.7 × 10^-7M.
[ClO^-] = 7.7 × 10^-7 M.
[HClO] = 0.16 - 7.7 × 10^-7 = 0.16M.
[F^-] = 0.006 M.
[HF] = 0.064 - 0.006 = 0.058 M.
(1) Solution A and B are separated by a membrane that is permeable to Mg2 and impermeable to Cl-. Solution A contains 0.1 mM MgCl2, solution B contains 100 mM MgCl2. Mg2 will be at electrochemical equilibrium when solution A is around ____________ mV. 180 mV - 180 mV 90 mV - 90 mV 60 mV - 60 mV
Answer:
90 mV
Explanation:
Faraday constant, F = 96487
Gas constant, R = 8.314
Number of mole of electron transferred, Z = 2
MgCl in solution A, = 0.1 mm
MgCl in solution A, = 100 mm
Using the relation :
E=(RT/ZF) In(Mg out/Mgin)
E = (8.314*298) / (2*96485) * In(100/0.1)
E = (2477.572 / 192970) * 6.9077552
E = 0.0128391 * 6.9077552
E = 0.0886897 V
E = 88.68 mV (approximately 90 mV)
The image shown here is a good illustration of which law?
Answer:
3rd law
Explanation:
His third laws states that every action has an equal and opposite reaction. because you are putting force on your wall, the wall is giving the force of wall on your finger.
Help solve please, it’s due in less than an hour or so.
sorry i can only figure out 1 but the answer is
------------------------------------------------------------------
124
hope you do good on your test :D
ANSWER ASAP
2. The figure shows the first three rows, or periods, of the periodic table. Suppose the fourth period is added. How many orbits will the Bohr models in the fourth period have? How many electrons will an atom in Group 1 in the fourth period have?
Answer:
19 electrons in first group of 4th period element that is potassium K
Explanation:
Calculate what will be the volume of 10.0 grams of
gaseous ammonia at STP?
Answer:
13.22 L
Explanation:
Given data:
Volume of ammonia = ?
Mass of ammonia = 10.0 g
Temperature = standard = 273.15 K
Pressure = standard = standard = 1 atm
Solution:
First of all we will calculate the number of moles of ammonia.
Number of moles = mass/molar mass
Number of moles = 10.0 g/ 17 g/mol
Number of moles = 0.59 mol
one mole of any substance at standard temperature and pressure occupy 22.41 L . Thus, 0.59 moles of ammonia will occupy,
0.59 mol × 22.4 L / 1 mol
13.22 L
Answer: 12.4L
Explanation:
mw NH3 18
1 mole = 22.4L
10g = 10/18 moles
WHOEVER ANSWERS GETS BRAINLIEST!! (im not lying its facts)
A student placed four drops of water on a fresh slice of bread. Next the wet bread was placed inside a plastic bag and sealed up tight. After that, the student placed the sealed bag of wet bread on a balance. The mass is recorded as 20 grams. After 10 days, the student observed many types of mold growing on the bread and inside the sealed bag. The pictures show the student’s experiment.
Set up: A bread plus four drops of water plus a plastic bag equals to 20 grams.
Result: Bread in side the plastic bag equals to: ____ grams.
Predict the mass of the sealed bag of moldy bread.
A. 15 grams
B. 20 grams
C. 22 grams
D. 25 grams
Answer:
The answer to your question is D. 25 grams.
Answer
22 grams hope this helps
14.86 ml + 15.0 ml + 14.980 ml =
Answer:
44.84 ml
Explanation:
14.86
+
15.0
+
14.980
_______
44.84
What is the name of the process happening in the picture? How do you know it’s that process? Explain your answer in 2 to 3 sentences complete help please
Answer:
The name of the process happening in the picture is explained below in details.
Explanation:
The process in the picture is photosynthesis. The plant is taking CO2 and H2O and using light to form glucose which would be the sugars and creating a byproduct of oxygen that is being released into the atmosphere. How did you know this is photosynthesis? A big thing clearly is the plant and how it’s taking H2O and CO2 and making glucose so it isn’t cellular respiration (if you don’t know what that is don’t worry, if you are learning about this you are bound to come across that later) and it’s releasing oxygen into the atmosphere and light has a function in this process according to the image.
Which of these describes the essential conclusion of the Rutherford experiment? The atom contains a very small nucleus that contains most of its mass. The proton is positively charged and the neutron has no charge? Atoms are solid spheres with electrons suspended in them like chocolate chips in a cookie. Mass is neither made nor consumed in a chemical reaction.
Answer:
The atom contains a vey small small nucleus that contains most of its mass.
Explanation:
The Rutherford gold leaf experiment concluded that most (99%) of all the mass of an atom is in the nucleus of the atom, that the nucleus is very small (105 times small than the size of the atom) and that is is positively charged.
Calculate the solubility at of in pure water and in a solution. You'll find data in the ALEKS Data tab lead chromate.
Answer:
1.34 * 10^-7 M
Explanation:
The Ksp of lead II chromate is 1.8 x 10^-14
So, we have that;
PbCrO4(s) -----> Pb^2+(aq) + CrO4^2-(aq)
s s
Where s = molar concentration of Pb^2+(aq) and CrO4^2-(aq)
and;
[Pb^2+] = [CrO4^2-]
This implies that Ksp = s^2
s = √Ksp
s = √1.8 x 10^-14
s = 1.34 * 10^-7 M
Consider a hypothetical metal that has a density of 11.6 g/cm3, an atomic weight of 157.6 g/mol, and an atomic radius of 0.127 nm. Compute the atomic packing factor if the unit cell has tetragonal symmetry; values for the and lattice parameters are 0.523 nm and 0.330 nm, respectively.
Answer:
[tex]APF(atomic packing factor)=0.31736[/tex]
Explanation:
From the question we are told that
Density of metal [tex]\rho=11.6 g/cm3[/tex]
Atomic weight of [tex]W=157.6 g/mol[/tex]
Atomic radius of [tex]r= 0.127 nm[/tex]
Lattice parameters=>[tex]x=0.523nm[/tex] and [tex]y=0.330 nm[/tex]
Generally the equation for atomic packing factor is mathematically given as
[tex]APF(atomic packing factor)=\frac{Spere's\ volume}{unit\ cell\ volume}[/tex]
[tex]APF(atomic packing factor)=\frac{N*VN}{VC}[/tex]
Generally the equation for number of atoms N is mathematically given as
[tex]N=\frac{\rho }{atomic raduis*Avacados constant}[/tex]
[tex]N=\frac{11.6 }{0.127*10^{-9}*6.02214086*10^{23} mol-1}[/tex]
[tex]N=4[/tex]
Therefore APF(atomic packing factor)
[tex]APF(atomic packing factor)=\frac{N*VN}{VC}[/tex]
[tex]APF(atomic packing factor)=\frac{4*\frac{4}{3} \pi (0.127)^3}{(0.523)^2 *0.330}[/tex]
[tex]APF(atomic packing factor)=0.31736[/tex]
PLEASE HELP it’s due in 30 minutes
Answer:
1-6
3 1 3 3 2 2
Explanation:
How many molecules are in 84.0 g of C5H5N
a golf ball is hit at a distance of 300 yards in 10 seconds what is the speed of the golf ball
Answer:
30 yard per second
Explanation:
300/10 = 30
What is the percent by weight (w/w%) of sugar in soda? Assume the average mass of sugar in soda is 23.0 g and the total mass is 370.0 g.
The percent by weight (w/w%) of sugar in soda : 6.216%
Further explanationGiven
mass of sugar = 23 g
total mass = 370 g
Required
the percent weight
Solution
%weight = (mass of solute : mass of solution) x 100%
solute = sugar
solution = solvent + solute = water + sugar
percent weight of sugar in soda :
= (23 : 370) x 100%
= 6.216 %
A gas stream contains 18.0 mole% hexane and the remainder nitrogen. The stream flows to a condenser, where its temperature is reduced and some of the hexane is liquefied. The hexane mole fraction in the gas stream leaving the condenser is 0.0500. Liquid hexane condensate is recovered at a rate of 1.50 L/min. N2 C6H14(v) (5.00 mole%) N2 C6H14(v) (18.0 mole%) Liquid condensate 1.50 L C6H14 (l)/min CONDENSER (a) What is the flow rate of the gas stream leaving the condenser in mol/min
Answer:
the flow rate of the gas stream leaving the condenser is 71.9 moles/min
Explanation:
Given the data in the question and the figure below;
N2 BALANCE
(100% - 18%) × ( mole rate in ) = ( 100% - 5%) × ( mole rate out)
0.82 × ( mole rate in ) = 0.95 × ( mole rate out)
mole rate in = 0.95 × ( mole rate out) / 0.82
mole rate in = 1.1585365853 × ( mole rate out)
now;
HEXANE BALANCE
0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate --- equ 1
but condensate = 1.5 L/min × ( density of hexane ) × 1/molar mass of hexane
we know that;
density of hexane is 0.6548 g/mL
and molar mass of hexane is 86.18 g/mol
so,
condensate = 1.5 L/min × ( 0.6548 g/mL × 1000 mL/L ) × ( 1/86.18 g/mol)
condensate = 11.3970758876
now lets substitute into equation 1
0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate
⇒ 0.18 × ( 1.1585365853 × ( mole rate out) ) = 0.0500 × ( mole rate out) + 11.3970758876
⇒ 0.208536585354(mole rate out) = 0.0500( mole rate out) + 11.3970758876
⇒ 0.208536585354(mole rate out) - 0.0500( mole rate out) = 11.3970758876
⇒ 0.158536585354(mole rate out) = 11.3970758876
mole rate out = 11.3970758876 / 0.158536585354
mole rate out = 71.889247 ≈ 71.9 moles/min
Therefore, the flow rate of the gas stream leaving the condenser is 71.9 moles/min
How to Balance __MgF2 + __Li2CO3 + __ LiF
5.6 g of Iron reacts with excess fluorine gas.
The mass of iron fluoride produced is 11.3 g
What is the formula of the iron fluoride?
Answer: FeF3 Iron(III) fluoride
Explanation: 5.6 g = 1/10 mole Fe
11.3-5.6g F = 5.7 = 3/10 mole F