Answer:
0.50v
Explanation:
Now EMF is induced when there is motion of a conductor in an electric field. Michael Faraday in the annals of scientific history discovered this.
This is expressed mathematically as;
E = Magnetic field / t
but t = d/ v; d- distance, v-velocity, time
Hence E = magnetic field/ d/v
= Magnetic field× v/ d
= 0.02×30/ 1.2= 0.5
A lonely child is swinging on a rusty old swing set, as seen in the image provided. If friction does 145 J of work slowing the swing, what is the maximum speed she can reach?
Answer:
2.331
Explanation:
It just the change of Energy from potential (PE) to kinetic (KE)
PE on A = PE on B + KE on B + friction works (Wf)
mg(ha) = mg(hb) + ½mv² + Wf
35 * 9.8 * 1.5 = 35 * 9.8 * 0.8 + ½ * 35 * v² + 145
514.5 = 274.4 + 17.5v² + 145
514.5 - 274.4 - 145 = 17.5v²
17v² = 95.1
v² = 5.434
v =√5.434 = 2.331 m/s
Heat is supplied to convert 1.26 kg of water at 100°C to steam at 100°C? Latent heat of vaporization of water is
2.26 x 106 J/kg.
a
What is latent heat, and how does it affect the temperature of a substance?
Given that,
Mass of water = 1.26 kg
Latent heat of vaporization of water [tex]L=2.26\times10^{6}\ J/kg[/tex]
We need to calculate the latent heat
Using formula of latent heat
[tex]Q=mL[/tex]
Where, Q = energy
m = mass
L = latent heat of vaporization
Put the value into the formula
[tex]Q=1.26\times2.26\times10^{6}[/tex]
[tex]Q=2847600\ J[/tex]
[tex]Q=2.84\times10^{6}\ J[/tex]
The temperature changes liquid to steam.
So, The temperature will be increases.
Hence, The latent heat is [tex]2.84\times10^{6}\ J[/tex] and temperature increases.
Answer:
latent heat = 2.84 x 10^6
and the temperature increase
Explanation:
Calcula el trabajo que realiza la fuerza de fregamiento sobre un cuerpo de 13kg que es desplaza una distáncia de 46 m si el coeficiente de fregamiento entre las superficies es de 0,45
Answer:
Los datos que tienes son:
m = 13 kg
d = 46 m
∪ = 0,45
g = 9,8 m/s²
Fr = ?
w = ?
Lo primero que haremos que calcular Fr
Fr = ∪mg
Fr = (0,45) (13 kg) (9,8 m/s²)
Fr = 57,33 N
Calculamos el trabajo realizado.
w = Fd
w = (57,33 N) (46 m)
w = 2637,18 Joules
Respuesta.
El trabajo realizado es 2637,18 Joules
Explanation:
A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4u2) N, where u is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revol
A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4θ²) N, where θ is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revolutions. The disc has an initial angular velocity [tex]\omega _o = 1 \ rad/s[/tex] and radius from the center of the disc = 300 mm
Answer:
the angular acceleration = 205.706 rad/sec²
Explanation:
GIVEN THAT:
The disc mass = 8 kg
Force = [tex]\dfrac{1}{4} \ \ \theta ^2* N[/tex]
We are told that the given θ is in radians; Therefore; the when it has turned 5 revolutions; we have the θ to be:
[tex]\theta = 5 rev * (\dfrac{2 \ \pi * rad}{1 rev}) \\ \\ \theta = 10 \ \pi \ rad[/tex]
Also;
the initial angular velocity [tex]\omega _o = 1 \ rad/s[/tex]
radius from the center of the disc = 300 mm = 0.3 m
Thus; the mass moment about the Inertia can be determined via the following expression;
[tex]I_o = \dfrac{1}{2}*m*r^2[/tex]
[tex]I_o = \dfrac{1}{2}*8*0.3^2[/tex]
[tex]I_o = 0.36 \ kg/m^3[/tex]
Now to calculate the angular acceleration; we equate the sum of the moments acting on the Inertia;
SO:
[tex]\sum M_o = I_o \alpha[/tex]
[tex]F*0.3 = 0.36* \alpha[/tex]
[tex]\dfrac{1}{2}* \theta^2 *0.3 = 0.36* \alpha[/tex]
[tex]\alpha = 0.20836 \ \theta^2 \ rad/sec^2[/tex]
[tex]\alpha = 0.20836 \ (10 \ \pi )^2 \ rad/sec^2[/tex]
[tex]\alpha = 205.706 \ rad/sec^2[/tex]
Hence; the angular acceleration = 205.706 rad/sec²
This is a physics question about acceleration, I'm a Sophmore btw
"Determine the amount of time it takes for a car to accelerate forward at a rate of 7.00 m/s^2 if it starts from rest and reaches a final speed of 30.0 m/s."
I was having trouble figuring out the time if anyone can help that'd be lovely!!
Answer:
4.29 s
Explanation:
Given:
v₀ = 0 m/s
v = 30.0 m/s
a = 7.00 m/s²
Find: t
v = at + v₀
30.0 m/s = (7.00 m/s²) t + 0 m/s
t = 4.29 s
If there are a boys pulling a rubber
with the same amount of force what will happen?
Answer:
The rubber will expand to its maximum and then tear in the middle.
Explanation:
Answer:
Hey!
Well if they continue to pull the rubber band, it would eventually rip apart right in the middle as the force could not be contained by the elastic fibres and had reached its maximum extension!
Explanation:
HOPE THIS HELPS!!
would iron and carbon form metallic bonds
Answer:
NO.
Explanation:
METALLIC BOND IS ONLY IN METALS.
Since iron is a metal and carbon a non- metal, they cannot form a metallic bond.
In the equation for elastic potential energy below, what is represented by the symbol k? Ee = ½ × k × e²
Answer:
K is the spring/elastic constant measured in Newton per metre square (N/m²)
Explanation:
E = ½Ke²
In the equation above,
E is the energy in Joules (J)
K is the elastic/spring constant in Newton per metre square (N/m²)
e is the extension in metre (m)
Answer:
In the equation Ee = ½ × k × e², "k" = spring constant
Explanation:
Which quantity Has the same unit as potential difference
Answer:
Voltage.
Explanation:
i reallllly need someone to answer this quick. it's fine if you can't though
Answer:
The correct order of answers goes:
[tex]\left[\begin{array}{ccc}Ionic\\Electronegativity\\Metallic\\Cation\end{array}\right][/tex]
Explanation:
Ionic - Ionic bonds are formed between a metal and a nonmetal (typically). Nonmetals are typically more electronegative elements because they are seeking to gain electrons to achieve atomic stability while metals want to give up electrons to those elements to become atomically stable. Therefore, the nonmetals are much more electronegative in comparison to the metals.
Electronegativity - Electronegativity is used mathematically to predict the type of bond that will occur between elements. The larger electronegativity has the smaller electronegativity subtracted from it to give us a number that we then apply to ranges within a table and try to decipher what kind of bond will be formed.
Metallic - This plays into both explanations already given. Metallic bonds will form between metals, meaning their electronegativities will be much lower. Higher differences between electronegativities (anything above 1.7) is considered ionic, while anything from 0.1 to 1.69 is considered covalent (these split to make polar and nonpolar covalence).
Cation - Cation is the term for a positively charged ion. It comes from cathode (a scientist completed an experiment with the cathode ray tube where they accelerated positively charged particles throughout it).
A water distiller which is used to purify water. The distiller boils water and then condenses most of the water vapour back to water. (a) The water distiller is filled with 5.0 kg of water at 20 °C The specific heat capacity of water = 4 200 J/Kg °C Calculate the energy needed to raise the temperature of the water to 100 °C ___________________________________________________________________
Answer:
Energy needed 1680kJExplanation:
The quantity of heat required to raise the temperature of water to 100 degrees is expressed as
[tex]Q= mc(T2-T1)[/tex]
Given data
mass of water = 5kg
initial temperature T1= 20 °C
final temperature T2= 100 °C
Specific heat capacity of water= 4 200 J/Kg °C
[tex]Q= 5* 4 200(100-20)\\Q= 21000(80)\\Q= 1680000\\Q= 1680kJ[/tex]
In a 30cm by 25cm rectangle, a quadrant of a circle of radius 7cm has been cut away from each corner. What is the perimeter of the part left?
Answer: 98cm
Explanation:
Dimension of rectangle = 30cm by 25cm
Length(l) = 30cm
Width(w) = 25cm
Perimeter of a rectangle = 2(l + w)
Quadrant of circle cut away of each side of the rectangle :
Radius = 7 cm =
That is, the dimension of the triangle reduces by 2 * 7 = 14cm
New length = 30 - 14 = 16cm
New width = 25 - 14 = 11cm
The four corners =( 4 × 2πr ) / 4
2πr = 2 × 22/7 × 7 = 44cm
Perimeter = 2(16cm + 11cm)
= 2(27cm)
Perimeter = 54cm + 44 = 98cm
Which of the following has more inertia: (a) a rubber ball and a stone of the same size? (b) a bicycle and a train? (c) a five-rupees coin and a one-rupee coin?
Inertia is the same thing as mass, more or less. Inertia is the tendency of the object to want to stay in place if at rest, or the object's tendency to stay in motion if a force is applied to it. A train's inertia is massive because it takes a lot of force to move such a large mass, or to slow it down. This is in comparison to the other objects (rubber ball, stone, bike, and the coins).
Answer:
Inertia is the measure of the mass of the body. The greater is the mass of the body; the
greater is its inertia and vice-versa.
(a) Mass of a stone is more than the mass of a rubber ball for the same size. Hence, inertia of
the stone is greater than that of a rubber ball.
(b) Mass of a train is more than the mass of a bicycle. Hence, inertia of the train is greater
than that of the bicycle.
(c) Mass of a five rupee coin is more than that of a one-rupee coin. Hence, inertia of the five
rupee coin is greater than that of the one-rupee coin.
Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement
Answer:
The net displacement is
[tex]R= \sqrt{A^2+B^2+2AB \cos \theta}[/tex]
[tex]=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m[/tex]
Explanation:
Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement
Given data
A = 15 m
B = 25 m
Angle between the vectors A and B is θ = 30°
The net displacement is
[tex]R= \sqrt{A^2+B^2+2AB \cos \theta}[/tex]
[tex]=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m[/tex]
The velocity and acceleration of a body are 90km/hr and 2m/s^2 respectively. find the distance travelled by it in half minute.
Answer:
1,650 meters
Explanation:
Start by converting the velocity to m/s. There are 3600 seconds in a minute and 1000 meters in a kilometer, so 90km/hr=25m/s. Half a minute is 30 seconds, so:
[tex]d=v_ot+\dfrac{1}{2}at^2 \\\\d=(25)(30)+\dfrac{1}{2}(2)(30)^2 \\\\d=750+900=1650m[/tex]
Hope this helps!
4. ____________ occurs when one object slides over another.
a. Sliding friction
b. Static friction
c. Rolling friction
d. Net force
Answer:
A. Sliding friction
Explanation:
Sliding friction is weaker than static friction
Answer:
Rolling Friction
Explanation:
I know this because the definition of rolling friction is : type of friction that happens when one body rolls over another
A force acting on a body of mass 200g displace it through 200cm in 5s. Find the magnitude of the force if the initial velocity of is Zero
Answer:
F = 0.32 N
Explanation:
GIVEN:
Mass = m = 200 g = 0.2 kg
Distance = S = 200 cm = 2 m
Time = t = 5 s
Initial velocity = U = 0 m/s
REQUIRED
Force = F = ?
SOLUTION
Using Second Equation of Motion,
S = Ut + 1/2 at²
2 = (0)(5) + 1/2 a(5)²
2 = 25/2 a
a = 4/25
a = 0.16 m/s²
So,
Acceleration = a = 0.16 m/s²
Now Using Equation from Newtons Second Law of Motion
F = ma
F = (2)(0.16)
F = 0.32 N
1. Calculate the total binding energy of 12
6 C.
Answer in units of MeV.
2. Calculate the average binding energy per nucleon of 24
12Mg.
Answer in units of MeV/nucleon.
3. Calculate the average binding energy per nucleon of 85
37Rb.
Answer in units of MeV/nucleon.
4. Find the binding energy per nucleon of 238
92U.
Answer in units of MeV/nucleon.
5. Calculate the total binding energy of 20
10Ne.
Answer in units of MeV.
6. Calculate the total binding energy of 40
20Ca.
Answer in units of MeV.
Answer:
1. B = 79.12 MeV
2. B = -4.39 MeV/nucleon
3. B = 2.40 MeV/nucleon
4. B = 7.48 MeV/nucleon
5. B = -18.72 MeV
6. B = 225.23 MeV
Explanation:
The binding energy can be calculated using the followng equation:
[tex] B = (Zm_{p} + Nm_{n} - M)*931 MeV/C^{2} [/tex]
Where:
Z: is the number of protons
[tex]m_{p}[/tex]: is the proton's mass = 1.00730 u
N: is the number of neutrons
[tex]m_{n}[/tex]: is the neutron's mass = 1.00869 u
M: is the mass of the nucleus
1. The total binding energy of [tex]^{12}_{6}C[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (6*1.00730 + 6*1.00869 - 12.011)*931.49 MeV/u = 79.12 MeV [/tex]
2. The average binding energy per nucleon of [tex]^{24}_{12}Mg[/tex] is:
[tex] B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u [/tex]
Where: A = Z + N
[tex] B = \frac{(12*1.00730 + 12*1.00869 - 24.305)}{(12 + 12)}*931.49 MeV/u = -4.39 MeV/nucleon [/tex]
3. The average binding energy per nucleon of [tex]^{85}_{37}Rb[/tex] is:
[tex] B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u [/tex]
[tex] B = \frac{(37*1.00730 + 48*1.00869 - 85.468)}{85}*931.49 MeV/u = 2.40 MeV/nucleon [/tex]
4. The binding energy per nucleon of [tex]^{238}_{92}U[/tex] is:
[tex] B = \frac{(92*1.00730 + 146*1.00869 - 238.03)}{238}*931.49 MeV/u = 7.48 MeV/nucleon [/tex]
5. The total binding energy of [tex]^{20}_{10}Ne[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (10*1.00730 + 10*1.00869 - 20.180)*931.49 MeV/u = -18.72 MeV [/tex]
6. The total binding energy of [tex]^{40}_{20}Ca[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (20*1.00730 + 20*1.00869 - 40.078)*931.49 MeV/u = 225.23 MeV [/tex]
I hope it helps you!
Is a 5kg ball is rolling to the right and has a velocity of 4 m/s what is the momentum of the ball
Answer:
∆p = 20 kg * m/s
Explanation:
The change in momentum is the mass of the body multiplied by the change in its velocity.
In formula form ∆p = m * ( ∆v ).
with m = 5 kg and ∆v = 4 m/s
∆p = 5 kg * 4 m/s
∆p = 20 kg * m/s
What happens when a sound wave passes from water into air
Answer:
Explanation:
Sounds travel faster in object having high density proportion or matter. This is because particles vibrates and causing the other particle near to as well vibrate. Hence, when sound is moving from a higher dense medium like Water, the rate of traveling is high compare to it moving in air with less dense.
At which point does the pendulum have the highest velocity
The pendulum has the greatest speed as it passes through the lowest position, straight down, where it was hanging limply before you started it swinging.
Question 1 of 25
2 Points
What is the kinetic energy of a 5-kg cat chasing a mouse across the yard at 2
m/s?
A. 98 J
B. 10 J
C. 2J
D. 20 J
SUBMIT
Explanation:
K = 5kg[tex](2 m/s)^{2}[/tex]/2 = 10 J
A cork weigh 2.5 gf in air. When tied to a sinker , the total weight is 20 gf in water. If the sinker alone weighs 25gf in water, find the density of the cork
Answer:
0.333
Explanation:
Weight of the sinker in water = 25gf
Weight of cork in air and sinker in water = 25gf + 2.5gf
= 27.5gf
Weight of the cork and sinker in water = 20gf
Loss of weight of cork in water = 27.5- 20 = 7.5gf
Rd of cork = weight of cork in air/ loss of weight of cork in water
= 2.5/7.5
= 1/3
= 0.333
Hence the Relative density of the cork is 0.333
plzz help! i need it now!!!!
be 100% sure of the answer plzzz
Answer:
Equal effort force
Explanation:
A class 1 lever has the support between the load and the effort hence the load tilts the plain at one end containing the support we would require an effort equal and opposite to the load to ensure movement .
what is light rays ?
Answer:
A light ray is a line (straight or curved) that is perpendicular to the light's wavefronts
Explanation:
Have a great day.
please answer this question first one to answer the right answer will be marked brainiest
Answer: Force per unit area. Explanation: P = 25/20. P = 5/4 Pascal or 1.25 Pascal
Explanation: is this what you were looking for
what is a depletion layer
Jess wants to make her house more energy efficient. She has two options, A or B. Option A is double-glazing her patio doors, which will cost £350 and save £15 per year. Option B is insulating her loft, which will cost £460 and save £25 per year. Is option A or option B the better long-term option?
Jess wants to make her house more energy efficient. Insulating her loft, which will cost £460 and save £25 per year, is better long-term option. Therefore, option B is correct.
What is energy ?In order to accomplish work and to produce heat and light, energy must be transferred to a body or to a physical system. Energy is the quantitative attribute that does this. Energy is a preserved resource; according to the rule of conservation of energy, energy can only be transformed from one form to another and cannot be created or destroyed.
Computers, vehicles, communications, state-of-the-art medical technology, and many other things are all powered by energy. The demand for dependable and economical energy is especially pressing for emerging countries. It may enhance things or perhaps save lives.
A turbine generator set transforms mechanical energy into electrical energy to produce electricity. Natural gas, coal, nuclear fission, biomass, petroleum, geothermal, and solar thermal are examples of energy sources where the heat generated is used to produce steam.
Thus, option B is correct.
To learn more about energy, follow the link;
https://brainly.com/question/1932868
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why does a balloon filled with hydrogen rises up only to a certain height
Answer: they will rise up because hydrogen is lighter in density and it's weight is lower when it's in the air
Explanation:
Answer:
hydrogen is less dense and its weight is also less than the air.
Explanation:
the cylinder of gravity of cylinder is where
Explanation:
In uniform gravity it is the same as the centre of mass. For regular shaped bodies it lies at the centre of the that particular body. Hence for a cylinder centre of gravity lies at the midpoint of the axis of the cylinder.
Explanation:
We developed a spherical harmonic series that represents the gravitational potential and its gravity field due to a buried right vertical cylinder. This series can be used at far- and intermediate-regions, and is fast and accurate, using only a few terms. We compared the values of the fields acquired by this new spherical harmonic series, with ones computed by direct numerical integrations, using a fine-mesh structure for a vertical cylinder. Results of the calculations are shown and performances of the two different methods are compared. Faithfulness of the spherical harmonic series is tested with an inversion example.